Is it possible to supply template parameters when calling operator()?
- by Paul
I'd like to use a template operator() but am not sure if it's possible. Here is a simple test case that won't compile. Is there something wrong with my syntax, or is this simply not possible?
struct A {
template<typename T> void f() { }
template<typename T> void operator()() { }
};
int main() {
A a;
a.f<int>(); // This compiles.
a.operator()<int>(); // This compiles.
a<int>(); // This won't compile.
return 0;
}
