Search Results

Search found 14956 results on 599 pages for 'mysql dba'.

Page 192/599 | < Previous Page | 188 189 190 191 192 193 194 195 196 197 198 199  | Next Page >

  • mysql date format with changing string value

    - by hacket
    I have a field called Timestamp, that stores its values as text as opposed to an actual Timestamp. The logging application is unchangeable, unfortunately. So table.Timestamp -> text field with format -> "Wed Mar 02 13:28:59 CDT 2011" I have been developing a query to purge all but the most recent row using this as my Timestamp selector, which is also converting the string into a date - MAX( STR_To_DATE( table.Timestamp , '%a %b %d %H:%i:%s CDT %Y' ) My query works perfectly... However, what I've found is that the string value - 'CDT' - changes between 'CDT' and 'CST' depending on whether the current time is daylight savings time or not. During daylight savings time, it logs as 'CDT', and vice versa. So all the rows that contain 'CST' get ignored when I run this - MAX( STR_To_DATE( table.Timestamp , '%a %b %d %H:%i:%s CDT %Y' ) and all the rows that contain 'CDT' get ignored when I run this - MAX( STR_To_DATE( table.Timestamp , '%a %b %d %H:%i:%s CST %Y' ) Is there a way to make it run against both string formats?

    Read the article

  • counting sub rows in mysql

    - by moustafa
    i have 2 table ok catgories and artilces i have this structure catgories web > design > photoshop > layers web > design > photoshop > effects and each one is a catgory and layers catgories has 100 article and effects catgories has 50 article now i want when count the articles 'web' catgory it show 150 article how i can do this give me an example

    Read the article

  • Find MySQL entries with same set of column B values for their common column A value

    - by nnsd44g
    I have: +----+------+------+ | id | A | B | +----+------+------+ | 1 | 1 | 1 | < | 2 | 1 | 2 | < | 3 | 2 | 2 | | 4 | 2 | 3 | | 5 | 3 | 1 | < | 6 | 3 | 2 | < | 7 | 4 | 4 | | 8 | 4 | 5 | +----+------+------+ I need to select the entries that have the same set of B values for their common A value. So, in this case, I need ids 1, 2 and 5, 6 because in those cases the sequence of B values is 1, 2. Is this possible? Thanks!

    Read the article

  • How to query multiple tables with multiple selects MySQL

    - by brybam
    I'm trying to write a php function that gets all the basic food data(this part works fine in my code) Then grabs all the ingredients related to the ids of the selected items from the query before. Anyone have have any idea why my second array keeps coming back as false? I should be getting 1 array with the list of foods (this works) Then, the second one should be an array with all the ingredients for all the foods that were previously selected...then in my code im planning to work with the array and sort them with the proper foods based on the ids. function getFood($start, $limit) { $one = mysql_query("SELECT a.id, a.name, a.type, AVG(b.r) AS fra, COUNT(b.id) as tvotes FROM `foods` a LEFT JOIN `foods_ratings` b ON a.id = b.id GROUP BY a.id ORDER BY fra DESC, tvotes DESC LIMIT $start, $limit;"); $row = mysql_fetch_array($one); $qry = ""; foreach ($row as &$value) { $fid = $value['id']; $qry = $qry . "SELECT ing, amount FROM foods_ing WHERE fid='$fid';"; } $two = mysql_query($qry); return array ($one, $two); }

    Read the article

  • MySQL COUNT() multiple columns

    - by liam
    Hello, I'm trying to fetch the most popular tags from all videos in my database (ignoring blank tags). I also need the 'flv' for each tag. I have this working as I want if each video has one tag: SELECT tag_1, flv, COUNT(tag_1) AS tagcount FROM videos WHERE NOT tag_1='' GROUP BY tag_1 ORDER BY tagcount DESC LIMIT 0, 10 However in my database, each video is allowed three tags - tag_1, tag_2 and tag_3. Is there a way to get the most popular tags reading from multiple columns? The record structure is: +-----------------+--------------+------+-----+---------+----------------+ | Field | Type | Null | Key | Default | Extra | +-----------------+--------------+------+-----+---------+----------------+ | id | int(11) | NO | PRI | NULL | auto_increment | | flv | varchar(150) | YES | | NULL | | | tag_1 | varchar(75) | YES | | NULL | | | tag_2 | varchar(75) | YES | | NULL | | | tag_3 | varchar(75) | YES | | NULL | | +-----------------+--------------+------+-----+---------+----------------+

    Read the article

  • MySQL: Selecting One Record When Others Have Same Data

    - by LoganFrederick
    I have a table of cities that all share the same area code: 367 01451 Harvard Worcester Massachusetts MA 978 Eastern 368 01452 Hubbardston Worcester Massachusetts MA 978 Eastern 369 01453 Leominster Worcester Massachusetts MA 978 Eastern The table has multiple area codes, all with multiple cities. What I'd like to do is only select one city from each area code and delete any extra cities from duplicate area codes. What would be the best query to accomplish this? I believe: http://stackoverflow.com/questions/596629/mysql4-sql-for-selecting-one-or-zero-record Is coming close to what I need but didn't quite get what/how those answers were working. Note The "978" row is the "area_code" row, table name is "zip_code".

    Read the article

  • mysql join 3 tables and count

    - by air
    Please look at this image here is 3 tables , and out i want is uid from table1 industry from table 3 of same uid count of fid from table 2 of same uid like in the sample example output will be 2 records Thanks

    Read the article

  • Associating multiple MySQL queries w/ PHP?

    - by anon
    I am trying to create a simple inventory request system. A user can enter multiple SKU's that will query the inventory database. My problem is I am trying to do is associate these multiple queries into a type of list. This list can later be retrieved and contains all queries that were submitted simultaneously. When the list is filled it can then be deleted. Is this possible? I am just looking to be pointed in the right direction. Thanks

    Read the article

  • MySQL: Use CASE/ELSE value as join parameter

    - by DRJ
    I'm trying to join the NAME and PHOTO from USERS table to the TRANSACTIONS table based on who is the payer or payee. It keeps telling me can't find the table this -- What am I doing wrong? SELECT name,photo,amount,comment, ( CASE payer_id WHEN 72823 THEN payee_id ELSE payer_id END ) AS this FROM transactions RIGHT JOIN users ON (users.id=this) WHERE payee_id=72823 OR payer_id=72823

    Read the article

  • mysql rollback when auto commit is on

    - by devang
    hi, by mistake i fired a update query and all the records in the table in dat field got updated nd also cannot rollback as auto_commit is on..is der ny other way in which i can retreive the records.plz help its urgent.. Thanks in advance

    Read the article

  • How to insert form data into MySQL database table

    - by Richard
    So I have this registration script: The HTML: <form action="register.php" method="POST"> <label>Username:</label> <input type="text" name="username" /><br /> <label>Password:</label> <input type="text" name="password" /><br /> <label>Gender:</label> <select name="gender"> <optgroup label="genderset"> <option value="Male">Male</option> <option value="Female">Female</option> <option value="Hermaphrodite">Hermaphrodite</option> <option value="Not Sure!!!">Not Sure!!!</option> </optgroup> </select><br /> <input type="submit" value="Register" /> </form> The PHP/SQL: <?php $username = $_POST['username']; $password = $_POST['password']; $gender = $_POST['gender']; mysql_query("INSERT INTO registration_info (username, password, gender) VALUES ('$username', '$password', '$gender') ") ?> The problem is, the username and password gets inserted into the "registration_info" table just fine. But the Gender input from the select drop down menu doesn't. Can some one tell me how to fix this, thanks.

    Read the article

  • Help with PHP MySQL join

    - by kester martinez
    Please help me to understand proper join syntax. I have table named inventory which has: trans_id trans_items items -> item_id trans_user employees -> person_id trans_date trans_comment trans_inventory As you can see above, trans_items is a foreign key in items table, and trans_user is a foreign key in employees table. Now what I want to do is to display in HTML the inventory table, but instead of displaying the item id, I want the ITEM NAME to be displayed. Here is what I have done. Please note I'm using CodeIgniter. public function getData(array $inputs) { $this->db->select('trans_items, trans_user, trans_date, trans_inventory, trans_comment'); $this->db->from('inventory'); $this->db->order_by('trans_date desc'); return $this->db->get()->result_array(); }

    Read the article

  • MySQL Query to get count of unique values?

    - by RD
    Hits Table: hid | lid | IP 1 | 1 | 123.123.123.123 2 | 1 | 123.123.123.123 3 | 2 | 123.123.123.123 4 | 2 | 123.123.123.123 5 | 2 | 123.123.123.124 6 | 2 | 123.123.123.124 7 | 3 | 123.123.123.124 8 | 3 | 123.123.123.124 9 | 3 | 123.123.123.124 As you can see, there following are the unique hits for the various lid: lid 1: 1 unique hit lid 2: 2 unique hits lid 3: 1 unique hit So basically, I need a query that will return the following: lid | uhits | 1 | 1 | 2 | 2 | 3 | 1 | Anybody know how to get that?

    Read the article

  • Filtering out unique rows in MySQL

    - by jpatokal
    So I've got a large amount of SQL data that looks basically like this: user | src | dst 1 | 1 | 1 1 | 1 | 1 1 | 1 | 2 1 | 1 | 2 2 | 1 | 1 2 | 1 | 3 I want to filter out pairs of (src,dst) that are unique to one user (even if that user has duplicates), leaving behind only those pairs belonging to more than one user: user | src | dst 1 | 1 | 1 1 | 1 | 1 2 | 1 | 1 In other words, pair (1,2) is unique to user 1 and pair (1,3) to user 2, so they're dropped, leaving behind only all instances of pair (1,1). Any ideas? The answers to the question below can find the non-unique pairs, but my SQL-fu doesn't suffice to handle the complication of requiring that they belong to multiple users as well. [SQL question] How to select non "unique" rows

    Read the article

  • Find all those columns which have only null values, in a MySQL table

    - by Robin v. G.
    The situation is as follows: I have a substantial number of tables, with each a substantial number of columns. I need to deal with this old and to-be-deprecated database for a new system, and I'm looking for a way to eliminate all columns that have - apparently - never been in use. I wanna do this by filtering out all columns that have a value on any given row, leaving me with a set of columns where the value is NULL in all rows. Of course I could manually sort every column descending, but that'd take too long as I'm dealing with loads of tables and columns. I estimate it to be 400 tables with up to 50 (!) columns per table. Is there any way I can get this information from the information_schema? EDIT: Here's an example: column_a column_b column_c column_d NULL NULL NULL 1 NULL 1 NULL 1 NULL 1 NULL NULL NULL NULL NULL NULL The output should be 'column_a' and 'column_c', for being the only columns without any filled in values.

    Read the article

  • mysql joining three specific tables

    - by sam lim
    Here what i would like to pull date from this three table. Table users i have three columns uid, username , data(text) Table users_order i have three columns uid, orders_id , users_email Table order_products i have three columns orders_id, product_id, product_name I would like to use product_id as the ref/search to pull the user info from those three tables. If product_id = 5 The query will display uid; username; users_email; orders_id; product_name; data (text) how would i right the sql query for this situation. Thanks,

    Read the article

  • MySQL Queries using Doctrine & CodeIgniter

    - by 01010011
    Hi, How do I write plane SQL queries using Doctrine connection object and display the results? For example, how do I perform: SELECT * FROM table_name WHERE column_name LIKE '%anything_similar_to_this%'; using Doctrine something like this (this example does not work) $search_key = 'search_for_this'; $conn = Doctrine_Manager::connection(); $conn->execute('SELECT * FROM table_name WHERE column_name LIKE ?)', $search_key); echo $conn;

    Read the article

  • mysql php problem: no error message despite error_reporting(E_ALL) line

    - by herrturtur
    index.php <html> <head> <title>Josh's Online Playground</title> </head> <body> <form method="POST" action="action.php"> <table> <tr> <td>"data for stuff"</td> <td><input type="text" ?></td> </tr> <tr> <td><input type="submit"></td> </tr> </table> </form> </body> </html> action.php <?php error_reporting(E_ALL); ini_sit("display_errors", 1); $mysqli = new mysqli('localhost', 'root', 'password', 'website'); $result = $mysqli->query("insert into stuff (data) values (' .$_POST['data'] ."'); echo $mysqli->error(); if($result = $mysqli->query("select data from stuff")){ echo 'There are '.$result->num_rows.' results.'; } while ($row = $result->fetch_object()){ echo 'stuff' . $row->data; } ?> Despite the first two lines in action.php, I get no error or warning messages. Instead I get a blank page after clicking the submit button. Do I have to do something differently to insert data?

    Read the article

  • mysql update enums

    - by FFish
    I have a field with enums: 'preview','active','closed' When I query like this: $query = "UPDATE albums SET album_active = preview WHERE album_id = 3"; $result = mysql_query($query); if (!$result) die('Invalid query: ' . mysql_error()); I get : Invalid query: Unknown column 'preview' in 'field list

    Read the article

  • multiple-to-one relationship mysql, submissions

    - by Yulia
    Hello, I have the following problem. Basically I have a form with an option to submit up to 3 images. Right now, after each submission it creates 3 records for album table and 3 records for images. I need it to be one record for album and 3 for images, plus to link images to the album. I hope it all makes sense... Here is my structure. TABLE `albums` ( `id` int(11) NOT NULL auto_increment, `title` varchar(50) NOT NULL, `fullname` varchar(40) NOT NULL, `email` varchar(100) NOT NULL, `created_at` datetime NOT NULL, `theme_id` int(11) NOT NULL, `description` int(11) NOT NULL, `vote_cache` int(11) NOT NULL, PRIMARY KEY (`id`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=20 ; TABLE `images` ( `id` int(11) NOT NULL auto_increment, `album_id` int(11) NOT NULL, `name` varchar(30) NOT NULL, and my code function create_album($params) { db_connect(); $query = sprintf("INSERT INTO albums set albums.title = '%s', albums.email = '%s', albums.discuss_url = '%s', albums.theme_id = '%s', albums.fullname = '%s', albums.description = '%s', created_at = NOW()", mysql_real_escape_string($params['title']), mysql_real_escape_string($params['email']), mysql_real_escape_string($params['theme_id']), mysql_real_escape_string($params['fullname']), mysql_real_escape_string($params['description']) ); $result = mysql_query($query); if(!$result) { return false; } $album_id = mysql_insert_id(); return $album_id; } if(!is_uploaded_file($_FILES['userfile']['tmp_name'][$i])) { $warning = 'No file uploaded'; } elseif is_valid_file_size($_FILES['userfile']['size'][$i])) { $_POST['album']['theme_id'] = $theme['id']; create_album($_POST['album']); mysql_query("INSERT INTO images(name) VALUES('$newName')"); copy($_FILES['userfile']['tmp_name'][$i], './photos/'.$original_dir.'/' .$newName.'.jpg');

    Read the article

  • Display only latest three results from PHP and MySQL

    - by nogggin1
    <?php $result = @mysql_query('SELECT Article FROM news WHERE ID = (SELECT MAX(ID) FROM News)'); if (!$result) { die('<p>Error performing query: ' . mysql_error() . '</p>'); } while ( $row = mysql_fetch_array($result) ) { echo('<p>' . $row['Article'] . '</p>'); } ?> basically i need to tweak this so that it shows the latest 3 results instead of just the latest one, also i need the order to be: newest 2nd newest 3rd newest any help would be greatly appreciated!

    Read the article

< Previous Page | 188 189 190 191 192 193 194 195 196 197 198 199  | Next Page >