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  • Selecting dictionary items by key efficiently in Python

    - by user248237
    suppose I have a dictionary whose keys are strings. How can I efficiently make a new dictionary from that which contains only the keys present in some list? for example: # a dictionary mapping strings to stuff mydict = {'quux': ..., 'bar': ..., 'foo': ...} # list of keys to be selected from mydict keys_to_select = ['foo', 'bar', ...] The way I came up with is: filtered_mydict = [mydict[k] for k in mydict.keys() \ if k in keys_to_select] but I think this is highly inefficient because: (1) it requires enumerating the keys with keys(), (2) it requires looking up k in keys_to_select each time. at least one of these can be avoided, I would think. any ideas? I can use scipy/numpy too if needed.

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  • python and regular expression with unicode

    - by bsn
    I need to delete some unicode symbols from the string '?????? ??????? ???????????? ??????????' I know they exist here for sure. I try: re.sub('([\u064B-\u0652\u06D4\u0670\u0674\u06D5-\u06ED]+)', '', '?????? ??????? ???????????? ??????????') but it doesn't work. String stays the same. ant suggestion what i do wrong?

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  • How can i optimize this python code

    - by RandomVector
    def maxVote(nLabels): count = {} maxList = [] maxCount = 0 for nLabel in nLabels: if nLabel in count: count[nLabel] += 1 else: count[nLabel] = 1 #Check if the count is max if count[nLabel] > maxCount: maxCount = count[nLabel] maxList = [nLabel,] elif count[nLabel]==maxCount: maxList.append(nLabel) return random.choice(maxList) nLabels contains a list of integers. The above function returns the integer with highest frequency, if more than one have same frequency then a randomly selected integer from them is returned. E.g. maxVote([1,3,4,5,5,5,3,12,11]) is 5

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  • Search inside dynamic array in python

    - by user2091683
    I want to implement a code that loops inside an array that its size is set by the user that means that the size isn't constant. for example: A=[1,2,3,4,5] then I want the output to be like this: [1],[2],[3],[4],[5] [1,2],[1,3],[1,4],[1,5] [2,3],[2,4],[2,5] [3,4],[3,5] [4,5] [1,2,3],[1,2,4],[1,2,5] [1,3,4],[1,3,5] and so on [1,2,3,4],[1,2,3,5] [2,3,4,5] [1,2,3,4,5] Can you help me implement this code?

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  • Noob Python Question: List Confusion

    - by potatocubed
    I'm trying to transfer the contents of one list to another, but it's not working and I don't know why not. My code looks like this: list1 = [1, 2, 3, 4, 5, 6] list2 = [] for item in list1: list2.append(item) list1.remove(item) But if I run it my output looks like this: >>> list1 [2, 4, 6] >>> list2 [1, 3, 5] My question is threefold, I guess: Why is this happening, how do I make it work, and am I overlooking an incredibly simple solution like a 'move' statement or something?

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  • Python point lookup (coordinate binning?)

    - by Rince
    Greetings, I am trying to bin an array of points (x, y) into an array of boxes [(x0, y0), (x1, y0), (x0, y1), (x1, y1)] (tuples are the corner points) So far I have the following routine: def isInside(self, point, x0, x1, y0, y1): pr1 = getProduct(point, (x0, y0), (x1, y0)) if pr1 >= 0: pr2 = getProduct(point, (x1, y0), (x1, y1)) if pr2 >= 0: pr3 = getProduct(point, (x1, y1), (x0, y1)) if pr3 >= 0: pr4 = getProduct(point, (x0, y1), (x0, y0)) if pr4 >= 0: return True return False def getProduct(origin, pointA, pointB): product = (pointA[0] - origin[0])*(pointB[1] - origin[1]) - (pointB[0] - origin[0])*(pointA[1] - origin[1]) return product Is there any better way then point-by-point lookup? Maybe some not-obvious numpy routine? Thank you!

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  • Python: Closing a for loop by reading stdout

    - by user1732102
    import os dictionaryfile = "/root/john.txt" pgpencryptedfile = "helloworld.txt.gpg" array = open(dictionaryfile).readlines() for x in array: x = x.rstrip('\n') newstring = "echo " + x + " | gpg --passphrase-fd 0 " + pgpencryptedfile os.popen(newstring) I need to create something inside the for loop that will read gpg's output. When gpg outputs this string gpg: WARNING: message was not integrity protected, I need the loop to close and print Success! How can I do this, and what is the reasoning behind it? Thanks Everyone!

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  • Python - Submit Information on a Website to Extract Data from Resulting Page

    - by bloodstorm17
    So I am trying to figure out how to post on a website that uses a drop down menu which is holding the values like this (based on the page source): <td valign="top" align="right"><span class="emphasis">Select Item Option : </span></td> <td align="left"> <span class="notranslate"> <select name="ItemOption1"> <option value="">Select Item Option</option> <option value="321_cba">Item Option 1</option> <option value="123_abcd">Item Option 2</option> ... Now there are two of these drop down menus on top of each other. I want to be able to select an item from drop down menu 1 and drop down menu 2 and then submit the page. Now based on the code it submits the information using the following code: <td colspan="2" align="center"> <input type="submit" value="View Result" onclick="return check()"> </td> </tr> </table> <input type="hidden" name="ItemOption1" value=""> <input type="hidden" name="ItemOption2" value=""> I have no idea how to select the items in the drop down menu and then submit the page and capture the information on the resulting page into a text file. Can someone please help me with this?

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  • Lucene boost: I need to make it work better

    - by zvikico
    I'm using Lucene to index components with names and types. Some components are more important, thus, get a bigger boost. However, I cannot get my boost to work properly. I sill get some components appear later (get worse score), even though they have a higher boost. Note that the indexing is done on one field only and I've set the boost to that field alone. I'm using Lucene in Java. I don't think it has anything to do with the field length. I've seen components with the same name (but different type) get the wrong score.

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  • Recurrent yearly date alert in Python

    - by coulix
    Hello Hackerz, Here is the idea A user can set a day alert for a birthday. (We do not care about the year of birth) He also picks if he wants to be alerted 0, 1, 2, ou 7 days (Delta) before the D day. Users have a timezone setting. I want the server to send the alerts at 8 am on the the D day - deleta +- user timezone Example: 12 jun, with "alert me 3 days before" will give 9 of Jun. My idea was to have a trigger_datetime extra field saved on the 'recurrent event' object. Like this a cron Job running every hour on my server will just check for all events matching irs current time hour, day and month and send to the alert. The problem from a year to the next the trigger_date could change ! If the alert is set on 1st of March, with a one day delay that could be either 28 or 29 of February .. Maybe i should not use the trigger date trick and use some other kind of scheme. All plans are welcome.

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  • A way to use Python which I don't know

    - by Konie
    In this quicksort function: def qsort2(list): if list == []: return [] else: pivot = list[0] # can't understand the following line lesser, equal, greater = partition(list[1:], [], [pivot], []) return qsort2(lesser) + equal + qsort2(greater) def partition(list, l, e, g): if list == []: return (l, e, g) else: head = list[0] if head < e[0]: return partition(list[1:], l + [head], e, g) elif head > e[0]: return partition(list[1:], l, e, g + [head]) else: return partition(list[1:], l, e + [head], g) I don't understand the sentence below the comment. Can someone tell me what is the meaning of this sentence here?

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  • python check value not in unicode list

    - by John
    Hi, I have a list and a value and want to check if the value is not in the list. list = [u'first record', u'second record'] value = 'first record' if value not in list: do something however this is not working and I think it has something to do with the list values having a u at the start, how can I fix this? And before someone suggests the list is returned from Django queryset so I can't just take the u out of the code :) Thanks

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  • Python how to convert this for loop into a while loop

    - by user1690198
    I have this for a for loop which I made I was wondering how I would write so it would work with a while loop. def scrollList(myList): negativeIndices=[] for i in range(0,len(myList)): if myList[i]<0: negativeIndices.append(i) return negativeIndices So far I have this def scrollList2(myList): negativeIndices=[] i= 0 length= len(myList) while i != length: if myList[i]<0: negativeIndices.append(i) i=i+1 return negativeIndices

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