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  • Copying files to Truecrypt file container hangs

    - by Wagner Maestrelli
    I have a dual boot installation with Windows 7 Ultimate (32-bits, NTFS file sytem) and Ubuntu 10.10 (32-bits, ext4 file system). I have installed the version 7.0a of Truecrypt in both Operating Systems. Located in the Windows 7 HDD I have a 150 GB encrypted file container. It is a standard and dynamic file container, which means it's not hidden and uses a sparse file. This file was created using the Windows version of the Truecrypt program. When I logon in Windows the container is mounted as the drive E: and everything works fine! In Ubuntu the Windows's NTFS file system is automaticaly mounted after I logon. I've configured that using the ntfs-config package. In my ~/.profile I have this line to mount the truecrypt's file container: truecrypt /media/7EDEBCFADEBCABB1/Users/Wagner/hd/hd.tc /media/truecrypt1 The file container is mounted after the logon without any problem. I can access it, copy files to/from it, etc. But when I try do copy relatively large amounts of data (~50 MB) to it via nautilus or cp -R, it starts the copy, copies some data until certain point and then it just hangs! The progress bar does not move anymore and nothing happens. There is no error, it just hangs and that's it. I have to kill the process myself. This problem does not happen in Windows: I can copy very large amounts of data to the container and it works great. But in Ubuntu the problem always happens! I mean, whenever I try to copy a bunch of files together the copy process hangs. Does anyone ever faced this problem? Can anyone help? Thanks!

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  • What is a widely accepted term for a string variable that would probably contain a file path and file name?

    - by Peter Turner
    For functions that need to index files in a directory and rename them FileName0001, FileName0002, etc... I often need to write a function that splits the file name from the file path and rename the file. When I put the file name and file path back together, I don't have a very good name for the variable that contains both of them and I usually just wind up concatenating them every time I want to use them (usually using them as parameters for functions labeled either filename or filepath) so I never really know what I'm doing until I notice a lot of files being written in the same directory as my binaries. Anyway, what do I call a file name and a file path? I don't want to call it File, because that usually means the binary information behind the file. I don't want to call it URI because that usually means I've got some sort of protocol, which I don't. I just want a good way to denote "c:\somedir\somedir\somedir\somefile.txt" so as to deconfuse this mess I've just realized I'm in. Please don't just list your personal preference. I think an excellent answer should "'site its sources". (as in, provide a link to a repository with a good example of the code being used as I described)

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  • Windows + Django + mod_wsgi = "DLL load failed"

    - by Kyle MacFarlane
    For a long time I was using Python 2.5 to do all this fine but recently upgraded to 2.7 since building stuff for 2.5 is a real pain. I also updated mod_wsgi to 3.3 for Python 2.7. Everything is working fine with Apache + mod_wsgi on CentOS and also in the Django runserver on both Windows and CentOS, but not with Apache + mod_wsgi on Windows. Whenever I try to access a page in my Django app I get the following (note that Apache starts fine): ImportError at / DLL load failed: The specified module could not be found. Which is caused by things like: from Crypto.Cipher import AES Etree and others cause the exact same error and it is not limited to any specific packages. Anything with pyd files fails. Googling around suggests reinstalling Python "for all users", but the installer doesn't give you that option anymore anyway. For good measure I've tried reinstalling Python 2.7 as an administrator and also told it to register itself as the default version of Python but neither helped. I think the solution might have something to do with: The fact that I have 2.5, 2.6 and 2.7 installed on this machine and mod_wsgi might be loading the DLLs for 2.5 instead of 2.7. Something to do with WSGIPythonPath, which I usually don't need to set.

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  • How do I prevent Excel from locking files by default?

    - by Andrzej Doyle
    When I double-click on a CSV file on a network share, the file is opened in Microsoft Excel (which is what I want). However, Excel assumes that I'm going to modify the file, and that everyone else is too, and so puts a lock on it. In practice I very rarely actually want to modify these files, merely read from them. And if I have the file open in an Excel window in the background, it stops anyone else from opening the same file. I am aware that I can manually open a file as read-only from the File - Open dialog within Excel. However I almost always open files by double-clicking on them in Explorer (or Outlook, for attachments). Is it possible to change the file association so that the default handler for CSV files is "Excel in read-only mode"? Is there a command-line argument that I can use in the Open With... dialog to achieve this? Or more bluntly - when I am looking at a CSV file in Windows Explorer, is there an easier way to open it read-only than starting up Excel myself, selecting File - Open, choosing "read only" from the dropdown, manually navigating to the same folder in the hierarchy, and then opening the file? (I am happy to have to jump through hoops on the rare occasions that I want to modify and save a file.)

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  • SQL SERVER – Windows File/Folder and Share Permissions – Notes from the Field #029

    - by Pinal Dave
    [Note from Pinal]: This is a 29th episode of Notes from the Field series. Security is the task which we should give it to the experts. If there is a small overlook or misstep, there are good chances that security of the organization is compromised. This is very true, but there are always devils’s advocates who believe everyone should know the security. As a DBA and Administrator, I often see people not taking interest in the Windows Security hiding behind the reason of not expert of Windows Server. We all often miss the important mission statement for the success of any organization – Teamwork. In this blog post Brian tells the story in very interesting lucid language. Read On! In this episode of the Notes from the Field series database expert Brian Kelley explains a very crucial issue DBAs and Developer faces on their production server. Linchpin People are database coaches and wellness experts for a data driven world. Read the experience of Brian in his own words. When I talk security among database professionals, I find that most have at least a working knowledge of how to apply security within a database. When I talk with DBAs in particular, I find that most have at least a working knowledge of security at the server level if we’re speaking of SQL Server. One area I see continually that is weak is in the area of Windows file/folder (NTFS) and share permissions. The typical response is, “I’m a database developer and the Windows system administrator is responsible for that.” That may very well be true – the system administrator may have the primary responsibility and accountability for file/folder and share security for the server. However, if you’re involved in the typical activities surrounding databases and moving data around, you should know these permissions, too. Otherwise, you could be setting yourself up where someone is able to get to data he or she shouldn’t, or you could be opening the door where human error puts bad data in your production system. File/Folder Permission Basics: I wrote about file/folder permissions a few years ago to give the basic permissions that are most often seen. Here’s what you must know as a minimum at the file/folder level: Read - Allows you to read the contents of the file or folder. Having read permissions allows you to copy the file or folder. Write  – Again, as the name implies, it allows you to write to the file or folder. This doesn’t include the ability to delete, however, nothing stops a person with this access from writing an empty file. Delete - Allows the file/folder to be deleted. If you overwrite files, you may need this permission. Modify - Allows read, write, and delete. Full Control - Same as modify + the ability to assign permissions. File/Folder permissions aggregate, unless there is a DENY (where it trumps, just like within SQL Server), meaning if a person is in one group that gives Read and antoher group that gives Write, that person has both Read and Write permissions. As you might expect me to say, always apply the Principle of Least Privilege. This likely means that any additional permission you might add does not need Full Control. Share Permission Basics: At the share level, here are the permissions. Read - Allows you to read the contents on the share. Change - Allows you to read, write, and delete contents on the share. Full control - Change + the ability to modify permissions. Like with file/folder permissions, these permissions aggregate, and DENY trumps. So What Access Does a Person / Process Have? Figuring out what someone or some process has depends on how the location is being accessed: Access comes through the share (\\ServerName\Share) – a combination of permissions is considered. Access is through a drive letter (C:\, E:\, S:\, etc.) – only the file/folder permissions are considered. The only complicated one here is access through the share. Here’s what Windows does: Figures out what the aggregated permissions are at the file/folder level. Figures out what the aggregated permissions are at the share level. Takes the most restrictive of the two sets of permissions. You can test this by granting Full Control over a folder (this is likely already in place for the Users local group) and then setting up a share. Give only Read access through the share, and that includes to Administrators (if you’re creating a share, likely you have membership in the Administrators group). Try to read a file through the share. Now try to modify it. The most restrictive permission is the Share level permissions. It’s set to only allow Read. Therefore, if you come through the share, it’s the most restrictive. Does This Knowledge Really Help Me? In my experience, it does. I’ve seen cases where sensitive files were accessible by every authenticated user through a share. Auditors, as you might expect, have a real problem with that. I’ve also seen cases where files to be imported as part of the nightly processing were overwritten by files intended from development. And I’ve seen cases where a process can’t get to the files it needs for a process because someone changed the permissions. If you know file/folder and share permissions, you can spot and correct these types of security flaws. Given that there are a lot of database professionals that don’t understand these permissions, if you know it, you set yourself apart. And if you’re able to help on critical processes, you begin to set yourself up as a linchpin (link to .pdf) for your organization. If you want to get started with performance tuning and database security with the help of experts, read more over at Fix Your SQL Server. Reference: Pinal Dave (http://blog.sqlauthority.com)Filed under: Notes from the Field, PostADay, SQL, SQL Authority, SQL Query, SQL Security, SQL Server, SQL Tips and Tricks, T SQL

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  • Download - Upload is too slow on Centos

    - by Mehdi
    My download/upload in server and out of server is too slow (around 50 KB/s !) ! Did I miss some configuration ? Some information: CentOS release 6.3 uptime load average: 0.17, 0.32, 0.37 Memory free -m total used free shared buffers cached Mem: 24009 21988 2021 0 806 18098 -/+ buffers/cache: 3083 20926 Swap: 4095 28 4067 lshw -C network *-network description: Ethernet interface product: 82574L Gigabit Network Connection vendor: Intel Corporation physical id: 0 bus info: pci@0000:02:00.0 logical name: eth0 version: 00 serial: 00:25:90:70:17:4a size: 100MB/s capacity: 1GB/s width: 32 bits clock: 33MHz capabilities: pm msi pciexpress msix bus_master cap_list ethernet physical tp 10bt 10bt-fd 100bt 100bt-fd 1000bt-fd autonegotiation configuration: autonegotiation=off broadcast=yes driver=e1000e driverversion=1.9.5-k duplex=full firmware=2.1-2 ip=108.175.8.123 latency=0 link=yes multicast=yes port=twisted pair speed=100MB/s resources: irq:16 memory:fb900000-fb91ffff ioport:e000(size=32) memory:fb920000-fb923fff ethtool ethtool eth0 Settings for eth0: Supported ports: [ TP ] Supported link modes: 10baseT/Half 10baseT/Full 100baseT/Half 100baseT/Full 1000baseT/Full Supports auto-negotiation: Yes Advertised link modes: Not reported Advertised pause frame use: No Advertised auto-negotiation: No Speed: 100Mb/s Duplex: Full Port: Twisted Pair PHYAD: 1 Transceiver: internal Auto-negotiation: off MDI-X: off Supports Wake-on: pumbg Wake-on: g Current message level: 0x00000001 (1) Link detected: yes dmesg |grep e1000e dmesg |grep e1000e e1000e: Intel(R) PRO/1000 Network Driver - 1.9.5-k e1000e: Copyright(c) 1999 - 2012 Intel Corporation. e1000e 0000:02:00.0: Disabling ASPM L0s e1000e 0000:02:00.0: PCI INT A -> GSI 16 (level, low) -> IRQ 16 e1000e 0000:02:00.0: setting latency timer to 64 e1000e 0000:02:00.0: irq 33 for MSI/MSI-X e1000e 0000:02:00.0: irq 34 for MSI/MSI-X e1000e 0000:02:00.0: irq 35 for MSI/MSI-X e1000e 0000:02:00.0: eth0: (PCI Express:2.5GT/s:Width x1) 00:25:90:70:17:4a e1000e 0000:02:00.0: eth0: Intel(R) PRO/1000 Network Connection e1000e 0000:02:00.0: eth0: MAC: 3, PHY: 8, PBA No: FFFFFF-0FF e1000e: eth0 NIC Link is Up 100 Mbps Full Duplex, Flow Control: None e1000e 0000:02:00.0: eth0: 10/100 speed: disabling TSO e1000e: eth0 NIC Link is Up 100 Mbps Full Duplex, Flow Control: None e1000e 0000:02:00.0: eth0: 10/100 speed: disabling TSO e1000e: eth0 NIC Link is Up 100 Mbps Full Duplex, Flow Control: None e1000e 0000:02:00.0: eth0: 10/100 speed: disabling TSO e1000e: eth0 NIC Link is Up 100 Mbps Full Duplex, Flow Control: None e1000e: eth0 NIC Link is Up 100 Mbps Full Duplex, Flow Control: None e1000e 0000:02:00.0: eth0: 10/100 speed: disabling TSO e1000e 0000:02:00.0: eth0: 10/100 speed: disabling TSO e1000e 0000:02:00.0: eth0: Unsupported Speed/Duplex configuration e1000e: eth0 NIC Link is Up 10 Mbps Full Duplex, Flow Control: None e1000e 0000:02:00.0: eth0: 10/100 speed: disabling TSO e1000e: eth0 NIC Link is Up 100 Mbps Full Duplex, Flow Control: None e1000e 0000:02:00.0: eth0: 10/100 speed: disabling TSO e1000e: eth0 NIC Link is Up 100 Mbps Full Duplex, Flow Control: None e1000e 0000:02:00.0: eth0: 10/100 speed: disabling TSO e1000e 0000:02:00.0: Disabling ASPM L1 e1000e 0000:02:00.0: eth0: changing MTU from 1500 to 9000 e1000e: eth0 NIC Link is Up 100 Mbps Full Duplex, Flow Control: None e1000e 0000:02:00.0: eth0: 10/100 speed: disabling TSO e1000e: eth0 NIC Link is Up 100 Mbps Full Duplex, Flow Control: None e1000e 0000:02:00.0: eth0: 10/100 speed: disabling TSO e1000e: eth0 NIC Link is Up 100 Mbps Full Duplex, Flow Control: None e1000e 0000:02:00.0: eth0: 10/100 speed: disabling TSO

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  • How to access shared folders from file editors?

    - by Marchosius
    I am running a xampp server on one of my other computers, and when using the brows functionality from text editors like gedit, bluefish and Eclipse/Aptana studio I can access the shares I made for the sites running on the server. Even when I right click-edit with-application with the the file browser it does not open the file in the editor. How can get this to work without having to copy the file over from the share then edit and then upload again after I am done? Similar issue when trying to upload a file to hosting server direct from the file server I have with filezilla. with this I also need to copy the file over to my pc and then from there upload to the hosting server with filezilla. EDIT: For eclipse I found a build in functionality to do this. (new-remote system connection-Enter the access details) Nothing yet on FileZilla Hope my Question is clear

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  • Uploading a file automatically for speed test?

    - by Abhi
    I am building a Web UI for a device for internet connection and one of the requirements in it is a speed test. I know the basic concept of how speed test works. A file is downloaded for a limited time then the same file is uploaded again and the speed is tracked at regular intervals. Downloading the file is not an issue, but how am I supposed to upload the file without the client knowing that the file is getting uploaded? I've read through a lot of documentation, but I'm still not able to get the answer to how I will upload the file from clients machine without asking him to select the file.

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  • Merge two different API calls into One

    - by dhilipsiva
    I have two different apps in my django project. One is "comment" and an other one is "files". A comment might save some file attached to it. The current way of creating a comment with attachments is by making two API calls. First one creates an actual comment and replies with the comment ID which serves as foreign key for the Files. Then for each file, a new request is made with the comment ID. Please note that file is a generic app, that can be used with other apps too. What is the cleanest way of making this into one API call? I want to have this as a single API call because I am in a situation where I need to send user an email with all the files as attachment when a comment is made. I know Queueing is the ideal way to do it. But I don't have the liberty to add queing to our stack now. So this was the only way I could think of.

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  • Making file in user's homedir accessible from web/webserver

    - by evident
    Hi everybody, I have a txt-file one of my user's homedir which is regularly updated there by a script. I now want to be able to access (read) this file from the web. /home/user/folder/file.txt So what I tried now is to log in as root, go into my webservers httpdocs folder /var/www/path/to/domain/httpdocs and there I tried to create a symbolic link with ln -s /home/user/foler/file.txt /var/www/path/to/domain/httpdocs/file.txt But this didn't work... I already tried changing the chmod of the symlink (which changes the ones from the original file of course) and also a chown to the user from webserver, but no matter what I tried I cannot open the file from the web or from a php-script (which is what I want to do) Can anybody help me and tell me what I need to do? What rights do I need to give? Or is there another way of achieving this?

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  • Edit 100MB+ file

    - by Majid Fouladpour
    I have captured some traffic with Wireshark and saved the result as a file. The file has 3 sections now: request headers response headers response body The response body is to become an flv file, but now everything is saved as a single file. So I need a way to delete the first two sections from the file, but the problem is that the file is very big (over a thousand mega bytes). I have tried to open it with gedit, but no matter how long I wait, gedit hangs and remains unresponsive until I kill it. What tool can I use to edit this big file easily?

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  • File Upload with HttpWebRequest doesn't post the file

    - by Sri Kumar
    Hello All, Here is my code to post the file. I use asp fileupload control to get the file stream. HttpWebRequest requestToSender = (HttpWebRequest)WebRequest.Create("http://localhost:2518/Web/CrossPage.aspx"); requestToSender.Method = "POST"; requestToSender.ContentType = "multipart/form-data"; requestToSender.KeepAlive = true; requestToSender.Credentials = System.Net.CredentialCache.DefaultCredentials; requestToSender.ContentLength = BtnUpload.PostedFile.ContentLength; BinaryReader binaryReader = new BinaryReader(BtnUpload.PostedFile.InputStream); byte[] binData = binaryReader.ReadBytes(BtnUpload.PostedFile.ContentLength); Stream requestStream = requestToSender.GetRequestStream(); requestStream.Write(binData, 0, binData.Length); requestStream.Close(); HttpWebResponse responseFromSender = (HttpWebResponse)requestToSender.GetResponse(); string fromSender = string.Empty; using (StreamReader responseReader = new StreamReader(responseFromSender.GetResponseStream())) { fromSender = responseReader.ReadToEnd(); } XMLString.Text = fromSender; In the page load of CrossPage.aspx i have the following code NameValueCollection postPageCollection = Request.Form; foreach (string name in postPageCollection.AllKeys) { Response.Write(name + " " + postPageCollection[name]); } HttpFileCollection postCollection = Request.Files; foreach (string name in postCollection.AllKeys) { HttpPostedFile aFile = postCollection[name]; aFile.SaveAs(Server.MapPath(".") + "/" + Path.GetFileName(aFile.FileName)); } string strxml = "sample"; Response.Clear(); Response.Write(strxml); I don't get the file in Request.Files. The byte array is created. What was wrong with my HttpWebRequest?

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  • Trouble converting an MP3 file to a WAV file using Naudio

    - by WebDevHobo
    Naudio Library: http://naudio.codeplex.com/ I'm trying to convert an MP3 file to a WAV file, but I've run in to a small error. I know what's going wrong, but I don't really know how to go about fixing it. Here's the piece of code I'm running: private void button1_Click(object sender, EventArgs e) { using(Mp3FileReader reader = new Mp3FileReader(@"path\to\MP3")) { using(WaveFileWriter writer = new WaveFileWriter(@"C:\test.wav", new WaveFormat())) { int counter = 0; while(reader.Read(test, counter, test.Length + counter) != 0) { writer.WriteData(test, counter, test.Length + counter); counter += 512; } } } } reader.Read() goes into the Mp3FileReader class, and the method looks like this: public override int Read(byte[] sampleBuffer, int offset, int numBytes) { if (numBytes % waveFormat.BlockAlign != 0) //throw new ApplicationException("Must read complete blocks"); numBytes -= (numBytes % waveFormat.BlockAlign); return mp3Stream.Read(sampleBuffer, offset, numBytes); } mp3Stream is an object of the Stream class. The problem is: I'm getting an ArgumentException. MSDN says that this is because the sum of offset and numBytes is greater than the length of sampleBuffer. Documentation: http://msdn.microsoft.com/en-us/library/system.io.stream.read.aspx This happens because I increase the counter every time, but the size of the byte array test remains the same. What I've been wondering is: do I need to increase the size of the array dynamically, or do I need to find out the needed size at the beginning and set it right away? And also, instead of 512, the method in Mp3FileReader returns 365 the first time. Which is the size of a whole block. But I'm writing the full 512. I'm basically just using the read to check if I'm not at the end of the file yet. Do I need to catch the return value and do something with that, or am I good here?

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  • IE7 issue - cannot download streamed file when Automatic prompting for file downloads is disabled

    - by Jai ganesh K
    Hi, My application is J2EE (JSP/Servlet) based. I encounter an issue when i try to open a new window (pop-up) from JSP and call a Servlet action (e.g. Streamer.do) which streams a PDF file inside that pop-up. Problem: While IE 7 - Tools - Internet Options - Security - Custom Level - Downloads - Automatic prompting for file downloads is Disabled and while pop-up window get opened, I am unable to download the file (Save/Open prompt is not comming up). In contrast, when I enable this option, I am able to download. But this option sometimes would be disabled in some environments. While testing this in Mozilla Firefox 3.0/3/5/IE6 it is working fine without any settings change. When i check it to enable i then get the Save/Open prompt to work correctly. This should be problem with IE7. Can anybody help us with Javascript or any working settings which doesnt care whether the "Automatic prompting for downloads" option in IE7 is enabled. Any help in this would be much appreciated. Regards! Jai

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  • Pentaho - Reporting Tool - Is the .prpt file (report template file) contains datasource information

    - by Yatendra Goel
    I am new Pentaho Reporting Tool. I have the following question: When I created a report using Pentaho Report Designer, it output a report file having .prpt extension. After that I found an example on internet where the following code were used to display the report in html format:| protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { ResourceManager manager = new ResourceManager(); manager.registerDefaults(); String reportPath = "file:" + this.getServletContext().getRealPath("sampleReport.prpt"); try { Resource res = manager.createDirectly(new URL(reportPath), MasterReport.class); MasterReport report = (MasterReport) res.getResource(); HtmlReportUtil.createStreamHTML(report, response.getOutputStream()); } catch (Exception e) { e.printStackTrace(); } } And the report got printed successfully. So as we haven't specified any datasource information here, I think that the .prpt file contains that information in it. If that's true than Isn't Jasper is better Reporting tool than Pentaho because when we display Jasper reports, we have to provide datasource details also so in that way our report is flexible and is not bound to any particular database.

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  • Need a way to determine if a file is done being written to.

    - by Khorkrak
    The situation I'm in is this - there's a process that's writing to a file, sometimes the file is rather large say 400 - 500MB. I need to know when it's done writing. How can I determine this? If I look in the directory I'll see it there but it might not be done being written. Plus this needs to be done remotely - as in on the same internal LAN but not on the same computer and typically the process that wants to know when the file writing is done is running on a Linux box with a the process that's writing the file and the file itself on a windows box. No samba isn't an option. xmlrpc communication to a service on that windows box is an option as well as using snmp to check if that's viable. Ideally Works on either Linux or Windows - meaning the solution is OS independent. Works for any type of file. Good enough: Works just on windows but can be done through some library or whatever that can be accessed with Python. Works only for PDF files. Current best idea is to periodically open the file in question from some process on the windows box and look at the last bytes checking for the PDF end tag and accounting for the eol differences because the file may have been created on Linux or Windows.

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  • Deploy an hta file in an exe or msi file

    - by rjmunro
    I've written an HTA file frontend for our web app that allows the web app to run without web browser status bars etc, and allows it to access the local system for certain tasks. I need a way to deploy this to customers. I need an installer to supply an hta file, an ico file, and add a link to them in the start menu and on the users desktop. I looked at building an installer with NSIS, but I couldn't figure out how to assign the icon to the shortcuts - The icon had to be a standard HTA one. Can this be done with NSIS, or should I be using another installer? P.s. I've got no particular preference for NSIS, it's just something I once used a very long time ago. When I download stuff, I think I prefer them to be msi files that launch with windows installer (it feels more like downloading a .rpm or .deb on linux which I am used to) but I know nothing about how those are created. I'm a web/linux guy who knows very little about windows programming.

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  • Saving temporary file name after uploading file with uplodify

    - by mIRU
    I have this script if (!empty($_FILES)) { $tempFile = $_FILES['Filedata']['tmp_name']; $targetPath = dirname(__FILE__).$_POST['folder'] . '/'; $pathinfoFile = pathinfo($_FILES['Filedata']['name']); $targetFile = str_replace('//','/',$targetPath) .uniqid().'.'.$pathinfoFile['extension']; move_uploaded_file($tempFile,$targetFile); } this script is from uplodify , modified for saving the file with unique name , i need after user will upload the file , this unique name and original name , to save temporary , when user will submit the form , this temporary variables i will insert in database , the problem is that in firebug console , i can not see all the actions of this script , and i can not understand the way how to fix it, I tried to save in $_SESSION but i have problems , is not saving , i found why is not working with $_SESSION , http://uploadify.com/forum/viewtopic.php?f=5&t=43 , i tried the solution from forum but without result , exist a more easy way to solve this problem ? , or what is better way to do it ? . Sorry for so silly question , i ran out of ideas . Thanks a lot for helping me , and sorry again for my English

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  • Reading a binary file in perl: Bad File Descriptor

    - by Magicked
    I'm trying to read a binary file 40 bytes at a time, then check to see if all those bytes are 0x00, and if so ignore them. If not, it will write them back out to another file (basically just cutting out large blocks of null bytes). This may not be the most efficient way to do this, but I'm not worried about that. However, right now I'm getting a "Bad File Descriptor" error and I cannot figure out why. my $comp = "\x00" * 40; my $byte_count = 0; my $infile = "/home/magicked/image1"; my $outfile = "/home/magicked/image1_short"; open IN, "<$infile"; open OUT, ">$outfile"; binmode IN; binmode OUT; my ($buf, $data, $n); while (read (IN, $buf, 40)) { ### Problem is here ### $boo = 1; for ($i = 0; $i < 40; $i++) { if ($comp[$i] != $buf[$i]) { $i = 40; print OUT $buf; $byte_count += 40; } } } die "Problems! $!\n" if $!; close OUT; close IN; I marked with a comment where it is breaking. Thanks for any help!

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  • Java - Reading a csv file line by line - stuck with weird non-existent characters being read!

    - by rockit
    hello fellow java developers. I'm having a very strange issue. I'm trying to read a csv file line by line. Im at the point where Im just testing out the reading of the lines. ONly each time that I read a line, the line contains square characters between each character of text. I even saved the file as a txt file in wordpad and notepad with no change. Thus I must be doing something stupid... I have a csv file, standard csv file, yes a text file with commas in it. I try to read a line of text, but the text is all f-ed up and cannot find the phrase within the text. Any advice? code below. //open csv File filReadMe = new File(strRoot + "data2.csv"); BufferedReader brReadMe = new BufferedReader(new InputStreamReader(new FileInputStream(filReadMe))); String strLine = brReadMe.readLine(); //for all lines while (strLine != null){ //if line contains "(see also" if (strLine.toLowerCase().contains("(see also")){ //write line from "(see also" to ")" int iBegin = strLine.toLowerCase().indexOf("(see also"); String strTemp = strLine.substring(iBegin); int iLittleEnd = strTemp.indexOf(")"); System.out.println(strLine.substring(iBegin, iBegin + iLittleEnd)); } //update line strLine = brReadMe.readLine(); } //end for brReadMe.close();

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  • Short file names versus long file names in Windows

    - by normski
    I have some code which gets the short name from a file path, using GetShortNameW(), and then later retrieves the long name view GetLongNameA(). The original file is of the form "C:/ProgramData/My Folder/File.ext" However, following conversion to short, then back to long, the filename becomes "C:/Program Files/My Folder/Filename.ext". The short name is of the form "C:/PROGRA~2/MY_FOL~1/FIL~1.EXT" The short name is being incorrectly resolved. The code compiles using VS 2005 on Windows 7 (I cannot upgrade the project to VS2008) Does anybody have any idea why this might be happening? DWORD pathLengthNeeded = ::GetShortPathNameW(aRef->GetFilePath().c_str(), NULL, 0); if(pathLengthNeeded != 0) { WCHAR* shortPath = new WCHAR[pathLengthNeeded]; DWORD newPathNameLength = ::GetShortPathNameW(aRef->GetFilePath().c_str(), shortPath, pathLengthNeeded); if(newPathNameLength != 0) { UI_STRING unicodePath(shortPath); std::string asciiPath = StringFromUserString(unicodePath); pathLengthNeeded = ::GetLongPathNameA(asciiPath.c_str(),NULL, 0); if(pathLengthNeeded != 0) {// convert it back to a long path if possible. For goodness sake can't we use Unicode throughout?F char* longPath = new char[pathLengthNeeded]; DWORD newPathNameLength = ::GetLongPathNameA(asciiPath.c_str(), longPath, pathLengthNeeded); if(newPathNameLength != 0) { std::string longPathString(longPath, newPathNameLength); asciiPath = longPathString; } delete [] longPath; } SetFullPathName(asciiPath); } delete [] shortPath; }

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  • Unable to recieve file contents on server during upload

    - by Khushal
    Hello, I have a JSP page in which I have a file input field from which I browse a csv file and then upload it on server. I am using method = "POST" and ENCTYPE='multipart/form-data' in the form in which this file input field is present. On the servlet side(in the application's servlet) I am making use of apache's commom file upload API-ServletFileUpload API. After getting the FileItem list from the method parseRequest(request) of this API I am unable to get the file name and its content by using the methods getName(), getString() of FileItem API. Needed to know what am I doing wrong or any modifications in my approach that will make my application to work. Any pointers regarding this will be helpful. Thanks in advance!!

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  • Unable to delete a file using bash script

    - by user3719091
    I'm having problems removing a file in a bash script. I saw the other post with the same problem but none of those solutions solved my problem. The bash script is an OP5 surveillance check and it calls an Expect process that saves a temporary file to the local drive which the bash script reads from. Once it has read the file and checked its status I would like to remove the temporary file. I'm pretty new to scripting so my script may not be as optimal as it can be. Either way it does the job except removing the file once it's done. I will post the entire code below: #!/bin/bash #GET FLAGS while getopts H:c:w: option do case "${option}" in H) HOSTADDRESS=${OPTARG};; c) CRITICAL=${OPTARG};; w) WARNING=${OPTARG};; esac done ./expect.vpn.check.sh $HOSTADDRESS #VARIABLES VPNCount=$(grep -o '[0-9]\+' $HOSTADDRESS.op5.vpn.results) # Check if the temporary results file exists if [ -f $HOSTADDRESS.op5.vpn.results ] then # If the file exist, Print "File Found" message echo Temporary results file exist. Analyze results. else # If the file does NOT exist, print "File NOT Found" message and send message to OP5 echo Temporary results file does NOT exist. Unable to analyze. # Exit with status Critical (exit code 2) exit 2 fi if [[ "$VPNCount" > $CRITICAL ]] then # If the amount of tunnels exceeds the critical threshold, echo out a warning message and current threshold and send warning to OP5 echo "The amount of VPN tunnels exceeds the critical threshold - ($VPNCount)" # Exit with status Critical (exit code 2) exit 2 elif [[ "$VPNCount" > $WARNING ]] then # If the amount of tunnels exceeds the warning threshold, echo out a warning message and current threshold and send warning to OP5 echo "The amount of VPN tunnels exceeds the warning threshold - ($VPNCount)" # Exit with status Warning (exit code 1) exit 1 else # The amount of tunnels do not exceed the warning threshold. # Print an OK message echo OK - $VPNCount # Exit with status OK exit 0 fi #Clean up temporary files. rm -f $HOSTADDRESS.op5.vpn.results I have tried the following solutions: Create a separate variable called TempFile that specifies the file. And specify that in the rm command. I tried creating another if statement similar to the one I use to verify that file exist and then rm the filename. I tried adding the complete name of the file (no variables, just plain text of the file) I can: Remove the file using the full name in both a separate script and directly in the CLI. Is there something in my script that locks the file that prevents me from removing it? I'm not sure what to try next. Thanks in advance!

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  • How to copy file preserving directory path in Linux?

    - by gasan
    I have Eclipse projects and ".project" file in them, the directory structure looks like 'myProject/.project'. I want to copy these '.project' files to another directory, but I want the enclosing directory name to be preserved. Let's say I have 'a/myProject/.project', I want to copy 'myProject/.project' to 'b', so it be 'b/myProject/.project', but 'b/myProject' doesn't exist. When I try in a: cp -r ./myProject/.project ../b it copies only '.project' file itself, without 'myProject' directory. Please advise.

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