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  • PHP/MySQL Problem

    - by Scott
    Why does this only print the sites specific content under the first site, and doesn't do it for the other 2? <?php echo 'NPSIN Data will be here soon!'; // connect to DB $dbhost = 'localhost'; $dbuser = 'root'; $dbpass = 'root'; $conn = mysql_connect($dbhost, $dbuser, $dbpass) or die ('Error connecting to DB'); $dbname = 'npsin'; mysql_select_db($dbname); // get number of sites $query = 'select count(*) from sites'; $result = mysql_query($query) or die ('Query failed: ' . mysql_error()); $resultArray = mysql_fetch_array($result); $numSites = $resultArray[0]; echo "<br><br>"; // get all sites $query = 'select site_name from sites'; $result = mysql_query($query); // get site content $query2 = 'select content_name, site_id from content'; $result2 = mysql_query($query2); // get site files // print info $count = 1; while ($row = mysql_fetch_array($result, MYSQL_NUM)) { echo "Site $count: "; echo "$row[0]"; echo "<br>"; $contentCount = 1; while ($row2 = mysql_fetch_array($result2, MYSQL_NUM)) { $id = $row2[1]; if ($id == ($count - 1)) { echo "Content $contentCount: "; echo "$row2[0]"; echo "<br>"; } $contentCount++; } $count++; } ?>

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  • Mysql SELECT with an OR across 2 columns

    - by Haroldo
    I'm creating a 'similar items' link table. i have a 2 column table. both columns contains product ids. The table is showing that these items are similar. However ids in the left column are more valuable. Say i want to select similar items to product '125b'. i only want 3 similar items to 125b. If there are any instances of 125b in col1 I would prefer these to finding 125b in col2. so i need a select statement along the lines of SELECT * FROM similar_items WHERE col_1={$id} OR col_2={$id} ORDER BY column(?) LIMIT 3 i do not want to do 2 separate queries ( ie query 2 if count(query1) <3 )

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  • Ways to prevent multiple email notification with php&mysql

    - by Louis Loudog Trottier
    My 1st post, but i got many great answers and tips from stackoverflow so far. This one was a close call- How does facebook, gmail send the real time notification? but not exactly, so let brainstorm this together. I have CMS system with mail notification when a change is made on the site. Everything wotk very well but i want to prevent multiple notification if somene make another quick change to, let say, fix a typo. Using php mail(), obviously. I've tough of 2 ways, one simple, and one.... let just say, pretty heavy... cough. the 3rd one was inspired by Implementing Email Notification but really doesn't look appealing to me to send bunch of email at once. Use a timestamp to check if another change was made in the 'let say' last 5 minutes. Record the last change, and compare it to the new one. Could be usefull for backup at the same time since i'll have to save the change somewhere, but text can be long and making an sql search would be painfull. Wouldn't it? Use cron to send changes every x minutes... convince me if you ythink it is a suitable solution. Any ideas, comment or suggestion of your own? Looking forward for your inputs, and since i now registered, i'll do my best to help around. Cheers, all llt

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  • mysql_num_rows(): supplied argument is not a valid MySQL result resource

    - by php-b-grader
    I am getting this error when I pass an invalid SQL string... I spent the last hour trying to find the problem assuming - It's not my SQL it must be the db handle... ANyway, I've now figured out that it was bad SQL... What I want to do is test the result of the mysql_query() for a valid resultset. I am simply using empty($result)... Is this the most effective test? Is there a more widely accepted method of testing a resultset for a valid result?

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  • mysql codeigniter active record m:m deletion

    - by sea_1987
    Hi There, I have a table 2 tables that have a m:m relationship, what I can wanting is that when I delete a row from one of the tables I want the row in the joining table to be deleted as well, my sql is as follow, Table 1 CREATE TABLE IF NOT EXISTS `job_feed` ( `id` int(11) NOT NULL AUTO_INCREMENT, `body` text NOT NULL, `date_posted` int(10) NOT NULL, PRIMARY KEY (`id`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=3 ; Table 2 CREATE TABLE IF NOT EXISTS `job_feed_has_employer_details` ( `job_feed_id` int(11) NOT NULL, `employer_details_id` int(11) NOT NULL, PRIMARY KEY (`job_feed_id`,`employer_details_id`), KEY `fk_job_feed_has_employer_details_job_feed1` (`job_feed_id`), KEY `fk_job_feed_has_employer_details_employer_details1` (`employer_details_id`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1; So what I am wanting to do is, if the a row is deleted from table1 and has an id of 1 I want the row in table to that also has that idea as part of the relationship also. I want to do this in keeping with codeigniters active record class I currently have this, public function deleteJobFeed($feed_id) { $this->db->where('id', $feed_id) ->delete('job_feed'); return $feed_id; }

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  • mysql query trouble

    - by Bharanikumar
    Hi , in my database i have phone numbers with country code , which look somthing like 0044-123456 0044-123456 0014-123456 0014-123456 0024-123456 0024-123456 0034-123456 0044-123456 0044-123456 0024-123456 0034-123456 084-123456 084-123456 i want to total up the numbers by country, something like this output 0044 (2) 0024 (2) 0034 (1) 084 (2) 064 (5) Is it possible to do this with a SQL query?

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  • [MySQL] Optimize Query

    - by bordeux
    Hello. I have problem with optimize this query: SET @SEARCH = "dokumentalne"; SELECT SQL_NO_CACHE `AA`.`version` AS `Version` , `AA`.`contents` AS `Contents` , `AA`.`idarticle` AS `AdressInSQL` , `AA` .`topic` AS `Topic` , MATCH (`AA`.`topic` , `AA`.`contents`) AGAINST (@SEARCH) AS `Relevance` , `IA`.`url` AS `URL` FROM `xv_article` AS `AA` INNER JOIN `xv_articleindex` AS `IA` ON ( `AA`.`idarticle` = `IA`.`adressinsql` ) INNER JOIN ( SELECT `idarticle` , MAX( `version` ) AS `version` FROM `xv_article` WHERE MATCH (`topic` , `contents`) AGAINST (@SEARCH) GROUP BY `idarticle` ) AS `MG` ON ( `AA`.`idarticle` = `MG`.`idarticle` ) WHERE `IA`.`accepted` = "yes" AND `AA`.`version` = `MG`.`version` ORDER BY `Relevance` DESC LIMIT 0 , 30 Now, this query using ^ 20 seconds. How to optimize this? EXPLAIN gives this: 1 PRIMARY AA ALL NULL NULL NULL NULL 11169 Using temporary; Using filesort 1 PRIMARY ALL NULL NULL NULL NULL 681 Using where 1 PRIMARY IA ALL accepted NULL NULL NULL 11967 Using where 2 DERIVED xv_article fulltext topic topic 0 1 Using where; Using temporary; Using filesort This is example server with my data: user: bordeux_4prog password: 4prog phpmyadmin: http://phpmyadmin.bordeux.net/ chive: http://chive.bordeux.net/

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  • Creating CFArray from MySQL Result Array

    - by Andrew
    Is there an easy way to dump an array returned from mysql_fetch_row into a CFArray? (part of the PHP implementation of CFPropertyList) I'm bummed by the lack of documentation on CFPropertyList for PHP. Iterating through each item in the array seems inefficient. I'm open to using a different mysql_fetch_... command. I'd like to just say: $NewArray = new CFArray( $ResultArray ) But that deosn't seem to work. This is my current code: $plist = new CFPropertyList(); $ResultRow = mysqli_fetch_row( $result ); $plist-add( $TableRow = new CFArray() ); foreach ( $ResultRow as $Item ){ $TableRow-add( new CFString( $Item ) ); }

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  • MYSQL sum() for distinct rows

    - by makeee
    I'm looking for help using sum() in my SQL query (not posting full query since the scenario is fairly simple). I have COUNT(DISTINCT conversions.id) in my query. I use DISTINCT because I'm doing "group by" for multiple columns and this ensures the same row is not counted more than once. Now I want to add: SUM(conversions.value) as conversion_value The problem is that the "value" for each row is counted more than once (due to the multiple group bys) I basically want to do SUM(conversions.value) for each DISTINCT conversions.id. Is that possible?

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  • MySQL: group by and IF statement

    - by notset
    By default, parent_id = 0. I want to select all records with parent_id = 0 and only the last ones with parent_id 0. I tried this, but it didn't work: SELECT * FROM `articles` IF `parent_id` > 0 THEN GROUP BY `parent_id` HAVING COUNT(`parent_id`) >= 1 END; ORDER BY `time` DESC What could be the solution?

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  • Incrementing through mysql PHP

    - by Rawdon
    I am looking at try to increment and decrement by three records through a table and present those records. Say if the id '4' is currently active. I want the to be display the ID's and category of 3.2.1 and 5.6.7 from an increment and decrement So far I have: $stmt = $db->query("SELECT id, category FROM test"); $stmt->execute(); while ($results = $stmt->fetch(PDO::FETCH_ASSOC)) { $current = $results['id']; $category = $results['category']; $next = array(array('slide_no' => $current, 'category' => $category)); } print_r($next); Now with this, I am getting back every row in the table. I'm now getting confused on how I could increment and decrement the records by 3 and make sure that the category will also increment correctly. Thank you very much.

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  • Adding up row number and displaying total using COUNT (PHP MySQL)

    - by Yvonne
    I'm attempting to run a query that adds up the total number of subjects in a class. A class has many subjects. There is a 'teachersclasses' table between teachers (the user table) and classes. The principles sounds pretty simple but I'm having some trouble in getting my page to display the number of subjects for each class (directly associated with the teacher) This is what I have so far, trying to make use of the COUNT with a nested SELECT: SELECT (SELECT count(*) FROM subjects WHERE subjects.classid = class.classid) AS total_subjects, class.classname, class.classid FROM class Then I am calling up 'num_subjects' to present the total within a while loop: <?php echo $row['total_subjects']?> From the above, I am receiving the total subjects for a class, but within the same table row (for one class) and my other while loop doesnt run anymore, which returns all of the classes associated with a teacher :( ... Bit of a mess now! I know to return the classes for a particular teacher, I can do an additional WHERE clause on the session of 'teacherid' but I think my query is getting too complicated for me that errors are popping up everywhere. Anyone have a quick fix for this! Thanks very much

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  • MySQL Group Results by day using timestamp

    - by Webnet
    I need to take the following query and pull the total order counts and sum of the orders grouped by day. I'm storing everything using timestamps. SELECT COUNT(id) as order_count, SUM(price + shipping_price) as order_sum, DAY(FROM_UNIXTIME(created)) as day FROM `order` WHERE '.implode(' AND ', $where).' I need to group by DAY but when I do for this past weekend's sales it takes my order_count and makes it 1 instead of 3. How can I pull the above values grouped by day? NOTE: The implode is used ONLY to define the time period (WHERE created = TIMESTAMP AND <= TIMESTAMP)

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  • mysql database design: threads and replies

    - by ajsie
    in my forum i have threads and replies. one thread has multiple replies. but then, a reply can be a reply of an reply (like google wave). because of that a reply has to have a column "reply_id" so it can point to the parent reply. but then, the "top-level" replies (the replies directly under the thread) will have no parent reply. so how can i fix this? how should the columns be in the reply table (and thread table). at the moment it looks like this: threads: id title body replies: id thread_id (all replies will belong to a thread) reply_id (here lies the problem. the top-level replies wont have a parent reply) body what could a smart design look like to enable reply a reply?

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  • MySQL - JOINS (excepts)

    - by user2529899
    I'm trying to find 2 different result via JOINS. Table look like; SELECT id,member_id,registered_year FROM records; I can listing which members registered in 2012 and also in 2013 with; SELECT member_id FROM records a INNER JOIN records b ON a.member_id=b.member_id WHERE a.registered_year='2013' AND b.registered_year='2012'; But I can't list revers of It. How can I list which members were registered in 2012 but not in 2013? Thnx in advance.

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  • MySQL -- How to do this better?

    - by Andrew
    $activeQuery = mysql_query("SELECT count(`status`) AS `active` FROM `assignments` WHERE `user` = $user_id AND `status` = 0"); $active = mysql_fetch_assoc($activeQuery); $failedQuery = mysql_query("SELECT count(`status`) AS `failed` FROM `assignments` WHERE `user` = $user_id AND `status` = 1"); $failed = mysql_fetch_assoc($failedQuery); $completedQuery = mysql_query("SELECT count(`status`) AS `completed` FROM `assignments` WHERE `user` = $user_id AND `status` = 2"); $completed = mysql_fetch_assoc($completedQuery); There has to be a better way to do that, right? I don't know how much I need to elaborate as you can see what I'm trying to do, but is there any way to do all of that in one query? I need to be able to output the active, failed, and completed assignments, preferably in one query.

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  • how to remove mysql root password

    - by nectar
    I want to remove password for user root in localhost how can I do that?by mistake I have set the password of root user thats why phpmyadmin is giving error- #1045 - Access denied for user 'root'@'localhost' (using password: NO)

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  • onUpdate in MySQL means?

    - by ajsie
    i know that if you create a foreign key on a field (parent_id) in a child table that refer to a parent table's primary key (id), then if this parent table is deleted the child class will be deleted as well if you set onDelete to cascade when creating the foreign key in the child class. but what happens if i set it to onUpdate = cascade?

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  • how store date in mysql database?

    - by Syom
    i have date in dd/mm/yyyy format. how can i store it in databse, if i fant to do some operations on them after? for example i must find out the rows, where date > something what type i must set to date field? thanks

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  • Problem with MySQL query

    - by Psyche
    This time my setup looks like this: one table with galleries names (gallery_id, gallery_name) and another table with galleries photos (photo_id, photo_gallery_id, photo_name). What I need is to get all the galleries with one random picture for each gallery. Is it possible to do this with a single query?

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