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  • Convert JSON query parameters to objects with JAX-RS

    - by deamon
    I have a JAX-RS resource, which gets its paramaters as a JSON string like this: http://some.test/aresource?query={"paramA":"value1", "paramB":"value2"} The reason to use JSON here, is that the query object can be quite complex in real use cases. I'd like to convert the JSON string to a Java object, dto in the example: @GET @Produces("text/plain") public String getIt(@QueryParam("query") DataTransferObject dto ) { ... } Does JAX-RS support such a conversion from JSON passed as a query param to Java objects?

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  • Zend_Nav in zend framework issue getting menu to show up

    - by Kalle Johansson
    Hi ! First time of here, so please bare with me. I have to following problem, using zend framework, specifically zend_nav to create a reusable menu to be passed in via the layout/layout.phtml page. These are the code fragments in their respective files. first of in application/configs/navigation.xml, <configdata> <nav> <label>Home</label> <controller>index</controller> <action>index</action> <pages> <add> <label>Add</label> <controller>post</controller> <action>add</action> </add> <login> <label>Admin</label> <controller>login</controller> <action>login</action> </login> </pages> </nav> </configdata> this is then passed into an object in the Bootstrap.php file(only showing that specific method) protected function __initNavigation(){ $this->bootstrap('layout'); $layout = $this->getResource('layout'); $view = $layout->getView(); $config = new Zend_Config_Xml(APPLICATION .'/config/navigation.xml', 'nav'); $container = new Zend_Navigation($config); $view->navigation($container); } and then finally in the view layout.phtml, the object should return the menu <!-- application/layouts/scripts/layout.phtml --> <?php echo $this->doctype() ?> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title>Zend Blog !</title> <?php echo $this->headLink()->appendStylesheet('/css/global.css')?> </head> <body> <div id="header"> <div id="header-logo"> <b>Blog Me !</b> </div> </div> <div id="menu"> <?php echo $this->navigation()->menu() ?> </div> <div id="content"> <?php echo $this->layout()->content ?> </div> </body> </html> The menu does however not show up when i start up my app in the browser, any ideas as to might have gone wrong, is humbly received. Thanks in advance Kalle Johansson

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  • Opening an SQL CE file at runtime with Entity Framework 4

    - by David Veeneman
    I am getting started with Entity Framework 4, and I an creating a demo app as a learning exercise. The app is a simple documentation builder, and it uses a SQL CE store. Each documentation project has its own SQL CE data file, and the user opens one of these files to work on a project. The EDM is very simple. A documentation project is comprised of a list of subjects, each of which has a title, a description, and zero or more notes. So, my entities are Subject, which contains Title and Text properties, and Note, which has Title and Text properties. There is a one-to-many association from Subject to Note. I am trying to figure out how to open an SQL CE data file. A data file must match the schema of the SQL CE database created by EF4's Create Database Wizard, and I will implement a New File use case elsewhere in the app to implement that requirement. Right now, I am just trying to get an existing data file open in the app. I have reproduced my existing 'Open File' code below. I have set it up as a static service class called File Services. The code isn't working quite yet, but there is enough to show what I am trying to do. I am trying to hold the ObjectContext open for entity object updates, disposing it when the file is closed. So, here is my question: Am I on the right track? What do I need to change to make this code work with EF4? Is there an example of how to do this properly? Thanks for your help. My existing code: public static class FileServices { #region Private Fields // Member variables private static EntityConnection m_EntityConnection; private static ObjectContext m_ObjectContext; #endregion #region Service Methods /// <summary> /// Opens an SQL CE database file. /// </summary> /// <param name="filePath">The path to the SQL CE file to open.</param> /// <param name="viewModel">The main window view model.</param> public static void OpenSqlCeFile(string filePath, MainWindowViewModel viewModel) { // Configure an SQL CE connection string var sqlCeConnectionString = string.Format("Data Source={0}", filePath); // Configure an EDM connection string var builder = new EntityConnectionStringBuilder(); builder.Metadata = "res://*/EF4Model.csdl|res://*/EF4Model.ssdl|res://*/EF4Model.msl"; builder.Provider = "System.Data.SqlServerCe"; builder.ProviderConnectionString = sqlCeConnectionString; var entityConnectionString = builder.ToString(); // Connect to the model m_EntityConnection = new EntityConnection(entityConnectionString); m_EntityConnection.Open(); // Create an object context m_ObjectContext = new Model1Container(); // Get all Subject data IQueryable<Subject> subjects = from s in Subjects orderby s.Title select s; // Set view model data property viewModel.Subjects = new ObservableCollection<Subject>(subjects); } /// <summary> /// Closes an SQL CE database file. /// </summary> public static void CloseSqlCeFile() { m_EntityConnection.Close(); m_ObjectContext.Dispose(); } #endregion }

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  • Ant error when trying to build file, can't find tools.jar ??

    - by Derek
    When I run ant it says: Unable to locate tools.jar. Expected to find it in C:\Program Files\Java\jre6\lib\tools.jar Buildfile: build.xml does not exist! Build failed What package can I use to download the file required C:\Program Files\Java\jre6\lib\tools.jar I just downloaded this one: jre-6u19-windows-i586-s.exe but unfortunately it appears that it was not on it...

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  • Is alcheMo available?

    - by cable729
    Is it possible to develop iphone apps with java? I'd prefer to use alchemo over xmlvm because of the superior features that it offers. Can I do that? Is anyone else doing that? I've looked all over their site for the download link, but can't find it! Is it available? If so, where? http://www.innaworks.com/alchemo-for-iphone-java-me-j2me-to-iphone-porting/

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  • Getting code-first Entity Framework to build tables on SQL Azure

    - by NER1808
    I am new the code-first Entity Framework. I have tried a few things now, but can't get EF to construct any tables in the my SQL Azure database. Can anyone advise of some steps and settings I should check. The membership provider has no problems create it's tables. I have added the PersistSecurityInfo=True in the connection string. The connection string is using the main user account for the server. When I implement the tables in the database using sql everything works fine. I have the following in the WebRole.cs //Initialize the database Database.SetInitializer<ReykerSCPContext>(new DbInitializer()); My DbInitializer (which does not get run before I get a "Invalid object name 'dbo.ClientAccountIFAs'." when I try to access the table for the first time. Sometime after startup. public class DbInitializer:DropCreateDatabaseIfModelChanges<ReykerSCPContext> { protected override void Seed(ReykerSCPContext context) { using (context) { //Add Doc Types context.DocTypes.Add(new DocType() { DocTypeId = 1, Description = "Statement" }); context.DocTypes.Add(new DocType() { DocTypeId = 2, Description = "Contract note" }); context.DocTypes.Add(new DocType() { DocTypeId = 3, Description = "Notification" }); context.DocTypes.Add(new DocType() { DocTypeId = 4, Description = "Invoice" }); context.DocTypes.Add(new DocType() { DocTypeId = 5, Description = "Document" }); context.DocTypes.Add(new DocType() { DocTypeId = 6, Description = "Newsletter" }); context.DocTypes.Add(new DocType() { DocTypeId = 7, Description = "Terms and Conditions" }); //Add ReykerAccounttypes context.ReykerAccountTypes.Add(new ReykerAccountType() { ReykerAccountTypeID = 1, Description = "ISA" }); context.ReykerAccountTypes.Add(new ReykerAccountType() { ReykerAccountTypeID = 2, Description = "Trading" }); context.ReykerAccountTypes.Add(new ReykerAccountType() { ReykerAccountTypeID = 3, Description = "SIPP" }); context.ReykerAccountTypes.Add(new ReykerAccountType() { ReykerAccountTypeID = 4, Description = "CTF" }); context.ReykerAccountTypes.Add(new ReykerAccountType() { ReykerAccountTypeID = 5, Description = "JISA" }); context.ReykerAccountTypes.Add(new ReykerAccountType() { ReykerAccountTypeID = 6, Description = "Direct" }); context.ReykerAccountTypes.Add(new ReykerAccountType() { ReykerAccountTypeID = 7, Description = "ISA & Direct" }); //Save the changes context.SaveChanges(); } and my DBContext class looks like public class ReykerSCPContext : DbContext { //set the connection explicitly public ReykerSCPContext():base("ReykerSCPContext"){} //define tables public DbSet<ClientAccountIFA> ClientAccountIFAs { get; set; } public DbSet<Document> Documents { get; set; } public DbSet<DocType> DocTypes { get; set; } public DbSet<ReykerAccountType> ReykerAccountTypes { get; set; } protected override void OnModelCreating(DbModelBuilder modelBuilder) { //Runs when creating the model. Can use to define special relationships, such as many-to-many. } The code used to access the is public List<ClientAccountIFA> GetAllClientAccountIFAs() { using (DataContext) { var caiCollection = from c in DataContext.ClientAccountIFAs select c; return caiCollection.ToList(); } } and it errors on the last line. Help!

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  • How can I link two Java serialised objects back together?

    - by Kidburla
    Sometimes (quite a lot, actually) we get a situation in Java where two objects are pointing to the same thing. Now if we serialise these separately it is quite appropriate that the serialised forms have separate copies of the object as it should be possible to open one without the other. However if we now deserialise them both, we find that they are still separated. Is there any way to link them back together? Example follows. public class Example { private static class ContainerClass implements java.io.Serializable { private ReferencedClass obj; public ReferencedClass get() { return obj; } public void set(ReferencedClass obj) { this.obj = obj; } } private static class ReferencedClass implements java.io.Serializable { private int i = 0; public int get() { return i; } public void set(int i) { this.i = i; } } public static void main(String[] args) throws Exception { //Initialise the classes ContainerClass test1 = new ContainerClass(); ContainerClass test2 = new ContainerClass(); ReferencedClass ref = new ReferencedClass(); //Make both container class point to the same reference test1.set(ref); test2.set(ref); //This does what we expect: setting the integer in one (way of accessing the) referenced class sets it in the other one test1.get().set(1234); System.out.println(Integer.toString(test2.get().get())); //Now serialise the container classes java.io.ObjectOutputStream os = new java.io.ObjectOutputStream(new java.io.FileOutputStream("C:\\Users\\Public\\test1.ser")); os.writeObject(test1); os.close(); os = new java.io.ObjectOutputStream(new java.io.FileOutputStream("C:\\Users\\Public\\test2.ser")); os.writeObject(test2); os.close(); //And deserialise them java.io.ObjectInputStream is = new java.io.ObjectInputStream(new java.io.FileInputStream("C:\\Users\\Public\\test1.ser")); ContainerClass test3 = (ContainerClass)is.readObject(); is.close(); is = new java.io.ObjectInputStream(new java.io.FileInputStream("C:\\Users\\Public\\test2.ser")); ContainerClass test4 = (ContainerClass)is.readObject(); is.close(); //We expect the same thing as before, and would expect a result of 4321, but this doesn't happen as the referenced objects are now separate instances test3.get().set(4321); System.out.println(Integer.toString(test4.get().get())); } }

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  • Configuring a Jetty web application on a different port

    - by sHz
    Hi folks, I'm brand new to Jetty. I'd like to ask if its possible to have Jetty listening on port 8080, however where specified, serve a specific web application under say /var/jetty/webapps/<appname> (default on CentOS) served on say port 10000 instead of http://localhost:8080/<appname> i.e. http://localhost:10000/ = http://localhost:8080/<appname&gt; ? If so, what configuration changes would be required to make this work without an additional proxy server? I've googled away, but haven't found a solution (perhaps I've missed something obvious?).

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  • Java applet class never found

    - by Andrew
    I am having a problem with the java plugins of all three major browsers: chromium, firefox and Internet Explorer. The issue is that applets will always fail to load and yield errors no matter what website or what applet I am trying to use. I can not see any of the example applets on oracle's website; I can not launch the minecraft browser applet; nor can I launch any applet across the web using any browser. I always receive a "class not found:AppletClassHere.class" error. I know that my browser plugin must be working correctly because I can launch the Cisco Nac applet each time I connect to my network and I can launch my own simple applets offline. I am connecting to the internet through a vpn in case that is important. It also seems like a lot of other people I know are having this issue. Re-installing the plugin does not appear to fix the issue. I am asking this question to find out the cause of this problem, and any possible solutions. Thank you.

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  • How to Upload a file from client to server using OFBIZ?

    - by SIVAKUMAR.J
    Hi all, Im new to ofbiz.So is my question is have any mistake forgive me for my mistakes.Im new to ofbiz so i did not know some terminologies in ofbiz.Sometimes my question is not clear because of lack of knowledge in ofbiz.So try to understand my question and give me a good solution with respect to my level.Because some solutions are in very high level cannot able to understand for me.So please give the solution with good examples. My problem is i created a project inside the ofbiz/hot-deploy folder namely "productionmgntSystem".Inside the folder "ofbiz\hot-deploy\productionmgntSystem\webapp\productionmgntSystem" i created a .ftl file namely "app_details_1.ftl" .The following are the coding of this file <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1"> <title>Insert title here</title> <script TYPE="TEXT/JAVASCRIPT" language=""JAVASCRIPT"> function uploadFile() { //alert("Before calling upload.jsp"); window.location='<@ofbizUrl>testing_service1</@ofbizUrl>' } </script> </head> <!-- <form action="<@ofbizUrl>testing_service1</@ofbizUrl>" enctype="multipart/form-data" name="app_details_frm"> --> <form action="<@ofbizUrl>logout1</@ofbizUrl>" enctype="multipart/form-data" name="app_details_frm"> <center style="height: 299px; "> <table border="0" style="height: 177px; width: 788px"> <tr style="height: 115px; "> <td style="width: 103px; "> <td style="width: 413px; "><h1>APPLICATION DETAILS</h1> <td style="width: 55px; "> </tr> <tr> <td style="width: 125px; ">Application name : </td> <td> <input name="app_name_txt" id="txt_1" value=" " /> </td> </tr> <tr> <td style="width: 125px; ">Excell sheet &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;: </td> <td> <input type="file" name="filename"/> </td> </tr> <tr> <td> <!-- <input type="button" name="logout1_cmd" value="Logout" onclick="logout1()"/> --> <input type="submit" name="logout_cmd" value="logout"/> </td> <td> <!-- <input type="submit" name="upload_cmd" value="Submit" /> --> <input type="button" name="upload1_cmd" value="Upload" onclick="uploadFile()"/> </td> </tr> </table> </center> </form> </html> the following coding is present in the file "ofbiz\hot-deploy\productionmgntSystem\webapp\productionmgntSystem\WEB-INF\controller.xml" ...... ....... ........ <request-map uri="testing_service1"> <security https="true" auth="true"/> <event type="java" path="org.ofbiz.productionmgntSystem.web_app_req.WebServices1" invoke="testingService"/> <response name="ok" type="view" value="ok_view"/> <response name="exception" type="view" value="exception_view"/> </request-map> .......... ............ .......... <view-map name="ok_view" type="ftl" page="ok_view.ftl"/> <view-map name="exception_view" type="ftl" page="exception_view.ftl"/> ................ ............. ............. The following are the coding present in the file "ofbiz\hot-deploy\productionmgntSystem\src\org\ofbiz\productionmgntSystem\web_app_req\WebServices1.java" package org.ofbiz.productionmgntSystem.web_app_req; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import java.io.DataInputStream; import java.io.FileOutputStream; import java.io.IOException; public class WebServices1 { public static String testingService(HttpServletRequest request, HttpServletResponse response) { //int i=0; String result="ok"; System.out.println("\n\n\t*************************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response)- Start"); String contentType=request.getContentType(); System.out.println("\n\n\t*************************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response)- contentType : "+contentType); String str=new String(); // response.setContentType("text/html"); //PrintWriter writer; if ((contentType != null) && (contentType.indexOf("multipart/form-data") >= 0)) { System.out.println("\n\n\t**********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) after if (contentType != null)"); try { // writer=response.getWriter(); System.out.println("\n\n\t**********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) - try Start"); DataInputStream in = new DataInputStream(request.getInputStream()); int formDataLength = request.getContentLength(); byte dataBytes[] = new byte[formDataLength]; int byteRead = 0; int totalBytesRead = 0; //this loop converting the uploaded file into byte code while (totalBytesRead < formDataLength) { byteRead = in.read(dataBytes, totalBytesRead,formDataLength); totalBytesRead += byteRead; } String file = new String(dataBytes); //for saving the file name String saveFile = file.substring(file.indexOf("filename=\"") + 10); saveFile = saveFile.substring(0, saveFile.indexOf("\n")); saveFile = saveFile.substring(saveFile.lastIndexOf("\\")+ 1,saveFile.indexOf("\"")); int lastIndex = contentType.lastIndexOf("="); String boundary = contentType.substring(lastIndex + 1,contentType.length()); int pos; //extracting the index of file pos = file.indexOf("filename=\""); pos = file.indexOf("\n", pos) + 1; pos = file.indexOf("\n", pos) + 1; pos = file.indexOf("\n", pos) + 1; int boundaryLocation = file.indexOf(boundary, pos) - 4; int startPos = ((file.substring(0, pos)).getBytes()).length; int endPos = ((file.substring(0, boundaryLocation)).getBytes()).length; //creating a new file with the same name and writing the content in new file FileOutputStream fileOut = new FileOutputStream("/"+saveFile); fileOut.write(dataBytes, startPos, (endPos - startPos)); fileOut.flush(); fileOut.close(); System.out.println("\n\n\t**********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) - try End"); } catch(IOException ioe) { System.out.println("\n\n\t*********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) - Catch IOException"); //ioe.printStackTrace(); return("exception"); } catch(Exception ex) { System.out.println("\n\n\t*********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) - Catch Exception"); return("exception"); } } else { System.out.println("\n\n\t********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) else part"); result="exception"; } System.out.println("\n\n\t*************************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response)- End"); return(result); } } I want to upload a file to the server.The file is get from user "<input type="file"..> tag in the "app_details_1.ftl" file & it is updated into the server by using the method "testingService(HttpServletRequest request, HttpServletResponse response)" in the class "WebServices1".But the file is not uploaded. Give me a good solution for uploading a file to the server. Thanks & Regards, Sivakumar.J

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  • KVM and JBoss Java Application Server

    - by Jason
    We have a large Xen deployment running on both RHEL and CentOS and have recently started looking at KVM since this is where it looks like the future of VM's are on Linux. We can load the server and get everything running without an issue. However when we load up a new one with JBoss (4.2 Community edition, Sun JDK 6) and load a large EAR the server goes a little crazy. The %sy will jump to 80-99% and just hang for large periods of time we see a similar jump in %us on the host machine. We though at first this might be I/O as it seems to happen at start of JBoss but then would "cool down" after everything got loaded. We did some tests by extracting some large tar.gz files and using jar -xvf on the ear but could not re-create. Then we starting thinking this might be some type of memory access issues. We loaded a c-program that would generate a lot of memory activity and sure enough we saw the spikes again. Not as high mind you but we did see it jump. We then wrote a small java program to do the same thing and sure enough we saw it jump again. Any thoughts on what might be causing this? Is this just the way KVM works? As a side note we do NOT see this behavior on any other setup. Xen, VMWare and/or native iron. The system does seem a bit slower than our Xen / VMware ones.

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  • Sun Java keytool importing EV certificates into a single keystore

    - by ss0
    At my current job we are using tomcat, customers have custom web portals setup on their own local machines. EV certs are new to me, they have 2 part intermediary and a primary certificate. For our product to work it appears I need to get all three parts installed under a single keystore entry. How can I roll all three parts into a single x.509 compliant file for import? They syntax I am using is as follows: /blah/system/j2sdk/bin/keytool -import -alias foo -keystore /zix/system/jdk1.5.0_06/jre/lib/security/cacerts -file certname.pem -trustcacerts where foo = the keystore name and certname.pem is the main cert. I have tried importing the intermediate certs under their own names into the keystore and I don't know if it's just the product I have to work with (not vanilla tomcat) or what but it doesn't see those. I have seen a working system and all three certs were under the single keystore alias. Anyone have any ideas?

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  • Installing Java 6 on Ubuntu 10.04 fails on missing Java 6 JRE package

    - by David S
    I'm trying to install Java 6 on Ubuntu 10.04 and it's been harder than it should be. In another question about installing Java on Ubuntu/Linux it said that I needed to do the following: sudo add-apt-repository "deb http://archive.canonical.com/ lucid partner" However, that failed and I kept getting: sudo: add-apt-repository: command not found The solution to this, was to run: sudo apt-get install python-software-properties So, that seemed to work and the command above to "add-apt-repository" seems to complete with no errors. And I have run the following to confirm it got added. sudo vi /etc/apt/sources.list But, now when I run the following: sudo apt-get install sun-java6-jre I get: Reading package lists... Done Building dependency tree Reading state information... Done Package sun-java6-jre is not available, but is referred to by another package. This may mean that the package is missing, has been obsoleted, or is only available from another source E: Package sun-java6-jre has no installation candidate Where do I go from here?

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  • Can't install .NET framework 4.0 on Windows XP professional version 2002 SP3 (OS bug?)

    - by that guy
    .NET framework 4.0 install fails on Windows XP professional version 2002 SP3: I tried to run setup using "run as..." to make sure the admin rights are used ("protect my computer..." tick was deselected of course). I tried everything: installing using online/offline setup, windows update. install goes a little and then "rolls back" and says: Installation did not succeed .NET Framework 4 has not been installed because: Fatal error during installation. for more information about this problem, see the log file. the full log: http://pastebay.net/1433771 Any ideas? EDIT1: I have found this in the log: "BlockIf: You must install the 32-bit Windows Imaging Component (WIC) before you run Setup. Please visit the Microsoft Download Center to install WIC, and then rerun Setup...." So I found it, and launched "wic_x86_enu.exe" - but it said: WIC Setup error Newer version of update is already on the system. I have already installed: .NET framewrok 2.0 SP2 .NET framewrok 3.0 SP2 .NET framewrok 3.5 SP1 but I need 4.0 . EDIT2: another attempt and it's log. (this time better copy of log file): http://pastebin.com/gmGfbM9a (copy to notepad and save as .htm and open with internet browser). I have tried all the solutions I could find - and nothing helped. I have found something weird: when I formatted the hard drive and installed windows xp again - the .NET framework 4.0 installed ok, but when I plugged my 100Mbit internet cable - the operating system kind off "locked itself" and the bug returned - I could no longer install .NET framework 4.0 again. There was no reason for that to happen, for example I have windows server 2003 in local network, but I don't have active directory enabled on it or anything like that - the server just has some folders shared and thats all (all server's "features" are default). I had the second pc with the same problem - with XP on it too. This seems like the bug of Operating System to me. I couldn't find what was causing the problem. After many days I gave up: backuped everything, formatted HDD and installed Windows 7 professional 64bit. .NET framework 4.0 installed with no problem on it.

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  • Java process eating CPU; Why?

    - by Camran
    I have a Linux server which I have installed Java on. Sometimes, and only sometimes when a large nr of visitors visit my website, the site hangs. When I open the terminal and enter the "top" command to see whats going on, I can see that "Java" process is eating CPU! Like 400%. I have also tried ps aux command, and can see that the command is from usr/bin/java I have little experience in troubleshooting this kind of things, so I turn to you guys for help. I have a java container installed (Jetty) which I must have in order to use SOLR (search engine) which is integrated into my website. I can start and stop SOLR by: etc/init.d/solr stop But this didn't remove the java process from the "Top" command. Still java was eating 400% CPU. Is there other methods to restart java only? This has happened twice to me, and each time I have now restarted my entire servers and everithing is fine. If you need more input let me know! Thanks

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  • Why did the web win the space of remote applications and X not?

    - by Martin Josefsson
    The X Window System is 25 years old, it had it's birthday yesterday (on the 15'th). As you probably are aware of, one of it's most important features is the separation of the server side and the client side in a way that neither Microsoft's, Apples or Wayland's windowing systems have. Back in the days (sorry for the ambiguous phrasing) many believed X would dominate over other ways to make windows because of this separation of server and client, allowing the application to be ran on a server somewhere else while the user clicks and types on her own computer at home. This use obviously still exists, but is marginalized at best. When we write and use programs that run on a server we almost always use the web with it's html/css/js. Why did the web win, and X not? The technologies used for the web (said html/css/js) are a mess. Combined with all the back-end-frameworks (Rails, Django and all) it really is a jungle to navigate thru. Still the web thrives with creativity and progress, while remote X apps do not.

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  • Multiple Zend application code organisation

    - by user966936
    For the past year I have been working on a series of applications all based on the Zend framework and centered on a complex business logic that all applications must have access to even if they don't use all (easier than having multiple library folders for each application as they are all linked together with a common center). Without going into much detail about what the project is specifically about, I am looking for some input (as I am working on the project alone) on how I have "grouped" my code. I have tried to split it all up in such a way that it removes dependencies as much as possible. I'm trying to keep it as decoupled as I logically can, so in 12 months time when my time is up anyone else coming in can have no problem extending on what I have produced. Example structure: applicationStorage\ (contains all applications and associated data) applicationStorage\Applications\ (contains the applications themselves) applicationStorage\Applications\external\ (application grouping folder) (contains all external customer access applications) applicationStorage\Applications\external\site\ (main external customer access application) applicationStorage\Applications\external\site\Modules\ applicationStorage\Applications\external\site\Config\ applicationStorage\Applications\external\site\Layouts\ applicationStorage\Applications\external\site\ZendExtended\ (contains extended Zend classes specific to this application example: ZendExtended_Controller_Action extends zend_controller_Action ) applicationStorage\Applications\external\mobile\ (mobile external customer access application different workflow limited capabilities compared to full site version) applicationStorage\Applications\internal\ (application grouping folder) (contains all internal company applications) applicationStorage\Applications\internal\site\ (main internal application) applicationStorage\Applications\internal\mobile\ (mobile access has different flow and limited abilities compared to main site version) applicationStorage\Tests\ (contains PHP unit tests) applicationStorage\Library\ applicationStorage\Library\Service\ (contains all business logic, services and servicelocator; these are completely decoupled from Zend framework and rely on models' interfaces) applicationStorage\Library\Zend\ (Zend framework) applicationStorage\Library\Models\ (doesn't know services but is linked to Zend framework for DB operations; contains model interfaces and model datamappers for all business objects; examples include Iorder/IorderMapper, Iworksheet/IWorksheetMapper, Icustomer/IcustomerMapper) (Note: the Modules, Config, Layouts and ZendExtended folders are duplicated in each application folder; but i have omitted them as they are not required for my purposes.) For the library this contains all "universal" code. The Zend framework is at the heart of all applications, but I wanted my business logic to be Zend-framework-independent. All model and mapper interfaces have no public references to Zend_Db but actually wrap around it in private. So my hope is that in the future I will be able to rewrite the mappers and dbtables (containing a Models_DbTable_Abstract that extends Zend_Db_Table_Abstract) in order to decouple my business logic from the Zend framework if I want to move my business logic (services) to a non-Zend framework environment (maybe some other PHP framework). Using a serviceLocator and registering the required services within the bootstrap of each application, I can use different versions of the same service depending on the request and which application is being accessed. Example: all external applications will have a service_auth_External implementing service_auth_Interface registered. Same with internal aplications with Service_Auth_Internal implementing service_auth_Interface Service_Locator::getService('Auth'). I'm concerned I may be missing some possible problems with this. One I'm half-thinking about is a config.ini file for all externals, then a separate application config.ini overriding or adding to the global external config.ini. If anyone has any suggestions I would be greatly appreciative. I have used contextswitching for AJAX functions within the individual applications, but there is a big chance both external and internal will get web services created for them. Again, these will be separated due to authorization and different available services. \applicationstorage\Applications\internal\webservice \applicationstorage\Applications\external\webservice

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  • How to use multiple DisplayName attribute using Entity Framework and ASP.Net Mvc 2

    - by Picflight
    Depending on where I use my Class, I want to be able to show a different DisplayName. I have the following class: [MetadataType(typeof(PortalMetaData))] [System.Web.Mvc.Bind(Exclude = "PortalId")] public partial class Portal { public Portal() { this.Created = DateTime.Now; } } public class PortalMetaData { [Required(ErrorMessage = "Portal name is required")] [StringLength(50, ErrorMessage = "Portal name must be under 50 characters")] public object PortalName { get; set; } [Required(ErrorMessage = "Description is required")] public object Description { get; set; } } I have a corresponding Table in the database Portal I use the Portal table with a PortalController for the Site Admin to update the records in the Portal Table. I want another user with a different Role (AsstAdmin) to be able to update this table as well. To facilitate that I am thinking of creating a separate partial class that somehow links back to the Portal Model. This would allow me to display limited Fields for update by the AsstAdmin and I can display a different name for the Field as well. How can I accomplish this task? If I add the following class which inherits from Portal than I get an exception: Unable to cast object of type 'Project1.Mvc.Models.Portal' to type 'Prpject1.Mvc.Models.Site'. [MetadataType(typeof(SiteMetaData))] public class Site : Portal { public Site() { } } public class SiteMetaData { [Required(DisplayName = "Site Description")] public object Description { get; set; } }

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  • Restlet vs Spring MVC for Restful web service

    - by zachariahyoung
    I'm researching how best to create a Restful web service on Google app engine. My end goal is to have an Android application call a web service on GAE to post and get data. At this point I not sure what the best approach is. What I know at this point is Spring MVC 3 provide the ability to create web service but it does not provide a full implementation of JAX-RS. I also have read a few blog that talk about how Spring and Restlet can be integrated together. On the other side I have read that I could only use Restlet in GAE. I would also like provide a light web interface for users to view their posted data So my questions are the following. 1. Should I just use Restlet. 2. Should I just use Spring MVC to provide my Restful web service. 3. Should I use Spring and Restlet together. At this point I think I should invest my time in Restlet because that seems to be the best approach for calling web services in Android. I'm also debating if Spring MVC is just over kill. Any thoughts would be helpful.

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  • How to clone a Model using Entity Framework and ASP.Net Mvc 2

    - by Picflight
    I have the following class: [MetadataType(typeof(PortalMetaData))] [System.Web.Mvc.Bind(Exclude = "PortalId")] public partial class Portal { public Portal() { this.Created = DateTime.Now; } } public class PortalMetaData { [Required(ErrorMessage = "Portal name is required")] [StringLength(50, ErrorMessage = "Portal name must be under 50 characters")] public object PortalName { get; set; } [Required(ErrorMessage = "Description is required")] public object Description { get; set; } } I have a corresponding Table in the database Portal I use the Portal table with a PortalController for the Site Admin to update the records in the Portal Table. I want another user with a different Role (AsstAdmin) to be able to update this table as well. To facilitate that I am thinking of creating a separate partial class that somehow links back to the Portal Model. This would allow me to display limited Fields for update by the AsstAdmin and I can display a different name for the Field as well. How can I accomplish this task? If I add the following class which inherits from Portal than I get an exception: Unable to cast object of type 'Project1.Mvc.Models.Portal' to type 'Prpject1.Mvc.Models.Site'. [MetadataType(typeof(SiteMetaData))] public class Site : Portal { public Site() { } } public class SiteMetaData { [Required(DisplayName = "Site Description")] public object Description { get; set; } }

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  • Correct way to edit and update complex viewmodel objects using asp.net-mvc2 and entity framework

    - by jslatts
    I have a table in my database with a one to many relationship to another table: ParentObject ID Name Description ChildObject ID Name Description ParentObjectID AnotherObjectID The objects are mapped into Entity Framework and exposed through a data access class. It seemed like ViewModels are recommended when the data to be displayed greatly differs from the domain object, so I created a ViewModel as follows: public class ViewModel { public IList<ParentObject> ParentObjects { get; set; } public ParentObject selectedObject { get; set; } public IList<ChildObject> ChildObjects { get; set; } } I have a view that displays a list of ParentObjects and when clicked will allow a ChildObject to be modified saved. <% using (Html.BeginForm()) { %> <table> <% foreach (var parent in Model.ParentObjects) { %> <tr> <td> ObjectID [<%= Html.Encode(parent.ID)%>] </td> <td> <%= Html.Encode(parent.Name)%> </td> <td> <%= Html.Encode(parent.Description)%> </td> </tr> <% } %> </table> <% if (Model.ParentObject != null) { %> <div> Name:<br /> <%= Html.TextBoxFor(model => model.ParentObject.Name) %> <%= Html.ValidationMessageFor(model => model.ParentObject.Name, "*")%> </div> <div> Description:<br /> <%= Html.TextBoxFor(model => model.ParentObject.Description) %> <%= Html.ValidationMessageFor(model => model.ParentObject.Description, "*")%> </div> <div> Child Objects </div> <% for (int i = 0; i < Model.ParentObject.ChildObjects.Count(); i++) { %> <div> <%= Html.DisplayTextFor(sd => sd.ChildObjects[i].Name) %> </div> <div> <%= Html.HiddenFor(sd => sd.ChildObjects[i].ID )%> <%= Html.TextBoxFor( sd => sd.ChildObjects[i].Description) %> <%= Html.ValidationMessageFor(sd => sd.ChildObjects[i].Description, "*") %> </div> <% } } } %> This all works fine. My question is around the best way to update the EF objects and persist the changes back to the database. I initially tried: [HttpPost] public ActionResult Edit(ViewModel viewModel) { ParentObject parent = myRepository.GetParentObjectByID(viewModel.SelectedObject.ID); if ((!ModelState.IsValid) || !TryUpdateModel(parent, "SelectedObject", new[] { "Name", "Description" })) { || !TryUpdateModel(parent.ChildObjects, "ChildObjects", new[] { "Name", "Description" })) { //Code to handle failure and return the current model snipped return View(viewModel); } myRepository.Save(); return RedirectToAction("Edit"); } When I try to save a change to the child object, I get this exception: Entities in 'MyEntities.ChildObject' participate in the 'FK_ChildObject_AnotherObject' relationship. 0 related 'AnotherObject' were found. 1 'AnotherObject' is expected. Investigation on StackOverflow and generally googling led me to this blog post that seems to describe my problem: TryUpdateModel() does not correctly handle nested collections. Apparently, (and stepping through the debugger confirms this) it creates a new ChildObject instead of associating with the EF objects from my instantiated context. My hacky work around is this: if (viewModel.ChildObjects.Count > 0) { foreach (ChildObject modelChildObject in viewModel.ChildObjects) { ChildObject childToUpdate = ParentObject.ChildObject.Where(a => a.ID == modelChildObject.ID).First(); childToUpdate.Name = modelChildObject.Name; } } This seems to work fine. My question to you good folks: Is there correct way to do this? I tried following the suggestion for making a custom model binder per the blog link I posted above but it didn't work (there was an issue with reflection) and I needed to get something going ASAP. PS - I tried to cleanup the code to hide specific information, so beware I may have hosed something up. I mainly just want to know if other people have solved this problem. Thanks!

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  • Extending spring based app

    - by pitr
    I have a spring-based Web Service. I now want to build a sort of plugin for it that extends it with beans. What I have now in web.xml is: <context-param> <param-name>contextConfigLocation</param-name> <param-value>/WEB-INF/classes/*-configuration.xml</param-value> </context-param> My core app has main-configuration.xml which declares its beans. My plugin app has plugin-configuration.xml which declares additional beans. Now when I deploy, my build deploys plugin.jar into /WEB-INF/lib/ and copies plugin-configuration.xml into /WEB-INF/classes/ all under main.war. This is all fine (although I think there could be a better solution), but when I develop the plugin, I don't want to have two projects in Eclipse with dependencies. I wish to have main.jar that I include as a library. However, web.xml from main.jar isn't automatically discovered. How can I do this? Bean injection? Bean discovery of some sort? Something else? Note: I expect to have multiple different plugins in production, but development of each of them will be against pure main.jar Thank you.

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  • java.lang.ClassNotFoundException: org.springframework.ui.ModelMap

    - by aelshereay
    I create a simple webapp using tomcat 6, spring 2.5.6 and maven. The problem is when I boot up tomcat, I am getting the following errors: SEVERE: StandardWrapper.Throwable java.lang.NoClassDefFoundError: org/springframework/ui/ModelMap ... Caused by: java.lang.ClassNotFoundException: org.springframework.ui.ModelMap The ModelMap class does exist in spring-2.5.6.jar and spring-context-2.5.6.jar, I also have some other spring jars. All of them are being deployed to tomcat correctly, when I check the application WEB-INF (deployed to tomcat) I found all those jars there! I have only one @Controller that has a @RequestMapping("/home.htm") showForm(ModelMap model) method. My applicationContext is quite simple: <?xml version="1.0" encoding="utf-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:aop="http://www.springframework.org/schema/aop" xmlns:context="http://www.springframework.org/schema/context" xmlns:dwr="http://www.directwebremoting.org/schema/spring-dwr" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.5.xsd http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop-2.5.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-2.5.xsd http://www.directwebremoting.org/schema/spring-dwr http://www.directwebremoting.org/schema/spring-dwr-3.0.xsd" default-autowire="byName"> <context:component-scan base-package="org.myapp"/> <bean class="org.springframework.web.servlet.mvc.annotation.DefaultAnnotationHandlerMapping"/> <bean class="org.springframework.web.servlet.mvc.annotation.AnnotationMethodHandlerAdapter"/> <bean id="viewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver"> <property name="viewClass" value="org.springframework.web.servlet.view.JstlView"></property> <property name="prefix" value="/WEB-INF/view/"></property> <property name="suffix" value=".jsp"></property> </bean> </beans>

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  • How to reference using Entity Framework and Asp.Net Mvc 2

    - by Picflight
    Tables CREATE TABLE [dbo].[Users]( [UserId] [int] IDENTITY(1,1) NOT NULL, [UserName] [varchar](50) COLLATE SQL_Latin1_General_CP1_CI_AS NULL, [Email] [varchar](255) COLLATE SQL_Latin1_General_CP1_CI_AS NULL, [BirthDate] [smalldatetime] NULL, [CountryId] [int] NULL, CONSTRAINT [PK_Users] PRIMARY KEY CLUSTERED ([UserId] ASC )WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY] ) ON [PRIMARY] CREATE TABLE [dbo].[TeamMember]( [UserId] [int] NOT NULL, [TeamMemberUserId] [int] NOT NULL, [CreateDate] [smalldatetime] NOT NULL CONSTRAINT [DF_TeamMember_CreateDate] DEFAULT (getdate()), CONSTRAINT [PK_TeamMember] PRIMARY KEY CLUSTERED ([UserId] ASC, [TeamMemberUserId] ASC )WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY] ) ON [PRIMARY] dbo.TeamMember has both UserId and TeamMemberUserId as the index key. My goal is to show a list of Users on my View. In the list I want to flag, or highlight the Users that are Team Members of the LoggedIn user. My ViewModel public class UserViewModel { public int UserId { get; private set; } public string UserName { get; private set; } public bool HighLight { get; private set; } public UserViewModel(Users users, bool highlight) { this.UserId = users.UserId; this.UserName = users.UserName; this.HighLight = highlight; } } View <%@ Page Title="" Language="C#" MasterPageFile="~/Views/Shared/Site.Master" Inherits="System.Web.Mvc.ViewPage<MvcPaging.IPagedList<MyProject.Mvc.Models.UserViewModel>>" %> <% foreach (var item in Model) { %> <%= item.UserId %> <%= item.UserName %> <%if (item.HighLight) { %> Team Member <% } else { %> Not Team Member <% } %> How do I toggle the TeamMember or Not If I add dbo.TeamMember to the EDM, there are no relationships on this table, how will I wire it to Users object? So I am comparing the LoggedIn UserId with this list(SELECT TeamMemberUserId FROM TeamMember WHERE UserId = @LoggedInUserId)

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