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  • Adding a UINavigationController as a subview of UIView

    - by eagle
    I'm trying to display a UILabel on top of a UINavigationController. The problem is that when I add the UILabel as a subview of UIWindow it will not automatically rotate since it is not a subview of UIViewController (UIViewController automatically handles updating subviews during rotations). This is the hierarchy I was using: UIWindow UILabel UINavigationController So I was thinking I could use the following hierarchy: UIWindow UIViewController UIView UILabel UINavigationController This way the label could be displayed on top of the UINavigationController's bar while also automatically being rotated since it is a subview of UIViewController. The problem is that when I try adding a UINavigationController as a subview of a view: [myViewController.view addSubview:myNavigationController.view]; it will appear 20 pixels downwards. Which I'm guessing is because it thinks it needs to make room for the status bar. But, since the UINavigationController is being placed inside a UIView which does not overlay on top of the status bar, it is incorrectly adding an additional 20 pixels. In other words, the top of the UINavigationBar is at the screen's 40 pixel mark instead of at 20 pixels. Is there any easy way to just shift the UINavigationController and all of its elements (e.g. navigation bar, tool bar, root view controller) up 20 pixels? Or to let it know that it shouldn't compensate for a status bar? If not, I guess I would need to use my first hierarchy mentioned above and figure out how to rotate the label so it is consistent with the navigation bar's rotation. Where can I find more information on how to do this? Note: by "displaying a label on top of the navigation bar", I mean it should overlay on top of the navigation bar... it can't simply be wrapped in a bar button item and placed as one of the items of the navigation bar.

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  • UIScrollView with pages enabled and device rotation/orientation changes (MADNESS)

    - by jbrennan
    I'm having a hard time getting this right. I've got a UIScrollView, with paging enabled. It is managed by a view controller (MainViewController) and each page is managed by a PageViewController, its view added as a subview of the scrollView at the proper offset. Scrolling is left-right, for standard orientation iPhone app. Works well. Basically exactly like the sample provided by Apple and also like the Weather app provided with the iPhone. However, when I try to support other orientations, things don't work very well. I've supported every orientation in both MainViewController and PageViewController with this method: - (BOOL)shouldAutorotateToInterfaceOrientation:(UIInterfaceOrientation)interfaceOrientation { return YES; } However, when I rotate the device, my pages become quite skewed, and there are lots of drawing glitches, especially if only some of the pages have been loaded, then I rotate, then scroll more, etc... Very messy. I've told my views to support auto-resizing with theView.autoresizingMask = UIViewAutoresizingFlexibleWidth | UIViewAutoresizingFlexibleHeight; But to no avail. It seems to just stretch and distort my views. In my MainViewController, I added this line in an attempt to resize all my pages' views: - (void)didRotateFromInterfaceOrientation:(UIInterfaceOrientation)fromInterfaceOrientation { self.scrollView.contentSize = CGSizeMake(self.scrollView.frame.size.width * ([self.viewControllers count]), self.scrollView.frame.size.height); for (int i = 0; i < [self.viewControllers count]; i++) { PageViewController *controller = [self.viewControllers objectAtIndex:i]; if ((NSNull *)controller == [NSNull null]) continue; NSLog(@"Changing frame: %d", i); CGRect frame = self.scrollView.frame; frame.origin.x = frame.size.width * i; frame.origin.y = 0; controller.view.frame = frame; } } But it didn't help too much (because I lazily load the views, so not all of them are necessarily loaded when this executes). Is there any way to solve this problem?

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  • UIWebView rotation and memory problem

    - by Fer
    Hi. I have an UIWebView that loads a embedded XHTML like this: body = [[UIWebView alloc] initWithFrame:CGRectMake(0, 0, self.view.frame.size.width, self.view.frame.size.height)]; body.scalesPageToFit = YES; body.backgroundColor = [UIColor scrollViewTexturedBackgroundColor]; body.autoresizingMask = UIViewAutoresizingFlexibleBottomMargin | UIViewAutoresizingFlexibleWidth | UIViewAutoresizingFlexibleLeftMargin | UIViewAutoresizingFlexibleRightMargin; [self.view addSubview:body]; [body loadRequest:[NSURLRequest requestWithURL:[NSURL fileURLWithPath:[[NSBundle mainBundle] pathForResource:@"article16" ofType:@"xhtml"]isDirectory:NO]]]; This XHTML have a lot of images, and when I rotate the device I got some memory warnings, and sometimes the app crashes. If I remove the autoresizing mask, specifically the UIViewAutoresizingFlexibleWidth (I have tryed with only UIViewAutoresizingFlexibleLeftMargin and UIViewAutoresizingFlexibleRightMargin with no problems), the memory warning stops, and the app does not crash anymore. If I remove all autoresizing mask, and set the new webView frame in didRotate or willRotate, I got the same warnings as using the UIViewAutoresizingFlexibleWidth. There's a app, called Atomic Web that could open the same XHTML and rotate with no memory warnings, and safari can open it as well, but if I create a project with only that UIWebView, the app sometimes crashes. Someone knows what this may be? Can I set the webview frame in other way? Why can't I use the autoresizing mask? Thanks for your attention.

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  • Should I use OpenGL for chess with animations?

    - by fhucho
    At the moment I am experimenting with SurfaceView for my chess game with animations. I am getting only about 8 FPS in the emulator. I draw a chess board and 32 chess pieces and rotate everything (to see how smooth it is), I am using antialiasing. On the Droid I'm getting about 20FPS, so it's not very smooth. Is it possible to implement a game with very scarce and simple animations without having to use OpenGL? This is what I do every frame: // scale and rotate matrix.setScale(scale, scale); rotation += 3; matrix.postRotate(rotation, 152, 152); canvas = surfaceHolder.lockCanvas(); canvas.setDrawFilter(new PaintFlagsDrawFilter(0, Paint.FILTER_BITMAP_FLAG)); canvas.setMatrix(matrix); canvas.drawARGB(255, 255, 255, 255); // fill the canvas with white for (int i = 0; i < sprites.size(); i++) { sprites.get(i).draw(canvas); // draws chessboard and chess pieces }

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  • Ubuntu 9.10 and Squid 2.7 Transparent Proxy TCP_DENIED

    - by user298814
    Hi, We've spent the last two days trying to get squid 2.7 to work with ubuntu 9.10. The computer running ubuntu has two network interfaces: eth0 and eth1 with dhcp running on eth1. Both interfaces have static ip's, eth0 is connected to the Internet and eth1 is connected to our LAN. We have followed literally dozens of different tutorials with no success. The tutorial here was the last one we did that actually got us some sort of results: http://www.basicconfig.com/linuxnetwork/setup_ubuntu_squid_proxy_server_beginner_guide. When we try to access a site like seriouswheels.com from the LAN we get the following message on the client machine: ERROR The requested URL could not be retrieved Invalid Request error was encountered while trying to process the request: GET / HTTP/1.1 Host: www.seriouswheels.com Connection: keep-alive User-Agent: Mozilla/5.0 (X11; U; Linux x86_64; en-US) AppleWebKit/532.9 (KHTML, like Gecko) Chrome/5.0.307.11 Safari/532.9 Cache-Control: max-age=0 Accept: application/xml,application/xhtml+xml,text/html;q=0.9,text/plain;q=0.8,image/png,/;q=0.5 Accept-Encoding: gzip,deflate,sdch Cookie: __utmz=88947353.1269218405.1.1.utmccn=(direct)|utmcsr=(direct)|utmcmd=(none); __qca=P0-1052556952-1269218405250; __utma=88947353.1027590811.1269218405.1269218405.1269218405.1; __qseg=Q_D Accept-Language: en-US,en;q=0.8 Accept-Charset: ISO-8859-1,utf-8;q=0.7,*;q=0.3 Some possible problems are: Missing or unknown request method. Missing URL. Missing HTTP Identifier (HTTP/1.0). Request is too large. Content-Length missing for POST or PUT requests. Illegal character in hostname; underscores are not allowed. Your cache administrator is webmaster. Below are all the configuration files: /etc/squid/squid.conf, /etc/network/if-up.d/00-firewall, /etc/network/interfaces, /var/log/squid/access.log. Something somewhere is wrong but we cannot figure out where. Our end goal for all of this is the superimpose content onto every page that a client requests on the LAN. We've been told that squid is the way to do this but at this point in the game we are just trying to get squid setup correctly as our proxy. Thanks in advance. squid.conf acl all src all acl manager proto cache_object acl localhost src 127.0.0.1/32 acl to_localhost dst 127.0.0.0/8 acl localnet src 192.168.0.0/24 acl SSL_ports port 443 # https acl SSL_ports port 563 # snews acl SSL_ports port 873 # rsync acl Safe_ports port 80 # http acl Safe_ports port 21 # ftp acl Safe_ports port 443 # https acl Safe_ports port 70 # gopher acl Safe_ports port 210 # wais acl Safe_ports port 1025-65535 # unregistered ports acl Safe_ports port 280 # http-mgmt acl Safe_ports port 488 # gss-http acl Safe_ports port 591 # filemaker acl Safe_ports port 777 # multiling http acl Safe_ports port 631 # cups acl Safe_ports port 873 # rsync acl Safe_ports port 901 # SWAT acl purge method PURGE acl CONNECT method CONNECT http_access allow manager localhost http_access deny manager http_access allow purge localhost http_access deny purge http_access deny !Safe_ports http_access deny CONNECT !SSL_ports http_access allow localhost http_access allow localnet http_access deny all icp_access allow localnet icp_access deny all http_port 3128 hierarchy_stoplist cgi-bin ? cache_dir ufs /var/spool/squid/cache1 1000 16 256 access_log /var/log/squid/access.log squid refresh_pattern ^ftp: 1440 20% 10080 refresh_pattern ^gopher: 1440 0% 1440 refresh_pattern -i (/cgi-bin/|\?) 0 0% 0 refresh_pattern (Release|Package(.gz)*)$ 0 20% 2880 refresh_pattern . 0 20% 4320 acl shoutcast rep_header X-HTTP09-First-Line ^ICY.[0-9] upgrade_http0.9 deny shoutcast acl apache rep_header Server ^Apache broken_vary_encoding allow apache extension_methods REPORT MERGE MKACTIVITY CHECKOUT cache_mgr webmaster cache_effective_user proxy cache_effective_group proxy hosts_file /etc/hosts coredump_dir /var/spool/squid access.log 1269243042.740 0 192.168.1.11 TCP_DENIED/400 2576 GET NONE:// - NONE/- text/html 00-firewall iptables -F iptables -t nat -F iptables -t mangle -F iptables -X echo 1 | tee /proc/sys/net/ipv4/ip_forward iptables -t nat -A POSTROUTING -j MASQUERADE iptables -t nat -A PREROUTING -p tcp --dport 80 -j REDIRECT --to-port 3128 networking auto lo iface lo inet loopback auto eth0 iface eth0 inet static address 142.104.109.179 netmask 255.255.224.0 gateway 142.104.127.254 auto eth1 iface eth1 inet static address 192.168.1.100 netmask 255.255.255.0

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  • Rotating an Image in Silverlight without cropping

    - by Tim Saunders
    I am currently working on a simple Silverlight app that will allow people to upload an image, crop, resize and rotate it and then load it via a webservice to a CMS. Cropping and resizing is done, however rotation is causing some problems. The image gets cropped and is off centre after the rotation. WriteableBitmap wb = new WriteableBitmap(destWidth, destHeight); RotateTransform rt = new RotateTransform(); rt.Angle = 90; rt.CenterX = width/2; rt.CenterY = height/2; //Draw to the Writeable Bitmap Image tempImage2 = new Image(); tempImage2.Width = width; tempImage2.Height = height; tempImage2.Source = rawImage; wb.Render(tempImage2,rt); wb.Invalidate(); rawImage = wb; message.Text = "h:" + rawImage.PixelHeight.ToString(); message.Text += ":w:" + rawImage.PixelWidth.ToString(); //Finally set the Image back MyImage.Source = wb; MyImage.Width = destWidth; MyImage.Height = destHeight; The code above only needs to rotate by 90° at this time so I'm just setting destWidth and destHeight to the height and width of the original image.

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  • iPhone Safari does not auto scale back down on portrait->landscape->portrait

    - by Tom
    Hi, I have a very simple HTML page with this META tag for the iPhone: <meta name="viewport" content="height=device-height,width=device-width,initial-scale=1.0,user-scalable=no" /> When the page loads in portrait mode it looks fine and the width fits the screen. When I rotate the iPhone to landscape mode the web page is auto resized to fit the landscape width. Good, this is what I want. But when I rotate back to landscape, the page is not resized back to fit the portrait width like it was before. It remains in the landscape width. I want the iPhone to set it back to the right width automatically, just like it did for the landscape mode. I don't think this should involve orientation listeners because it is all done automatically and I don't have any special styling for the different modes. Why doesn't the iPhone resize the web page back in portrait mode? How do I fix this? Thanks! Tom.

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  • [AS3] BitmapData cut-off

    - by Fristi
    Hello, I am writing a MovieClip rasterizer which rasterizes all the frames in the specified movieclip. Here's the code for rasterizing: for ( var i:int = start; i <= end; i++ ) { //goto the next frame clip.gotoAndStop( i ); //get the bounds bounds = clip.getBounds(clip); //create a new bitmapdata container bitmapData = new BitmapData( transformer.width == -1 ? bounds.width : transformer.width, transformer.height == -1 ? bounds.height : transformer.height, transformer.transparent, transformer.color ); //rotate the clip if (clip.rotation != 0) transformer.rotate( clip.rotation * (Math.PI / 180) ); //scale the clip if (clip.scaleX != 1 || clip.scaleY != 1) transformer.scale( clip.scaleX, clip.scaleY ); //translate the movieclip to its zero point if (transformer.matrix.tx == 0 && transformer.matrix.ty == 0) transformer.translateToZero( bounds ); //draw the bitmap data with the transformers bitmapData.draw( this._source, transformer.matrix, transformer.colorTransform, transformer.blendMode, transformer.clipRect, //new Rectangle(0, 0, bounds.width, bounds.height), transformer.smoothing ); //push the data on the array frames.push( bitmapData ); } Now the result is different - http://i42.tinypic.com/lfv52.jpg - (note the head and left shoe). Anyone knows what the problem is? I've seen people adding 'extra' pixels to their boundary box at the BitmapData constructor, but thats nasty imo.

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  • Automatically Sizing UIView after Adding to Window

    - by Kristopher Johnson
    I have an iPad app that switches between different views in its main window. The view-switching code looks like this: - (void)switchToViewController:(UIViewController*)viewController { if (currentViewController != viewController) { [currentViewController.view removeFromSuperview]; currentViewController = viewController; [window addSubview:viewController.view]; } } The problem is that when the new view (a UISplitView) appears in landscape orientation, it is not sized to fill the entire window. There is an empty black space on the right. If I rotate the device and then rotate back, the view sizes itself properly. If the device is in portrait orientation, everything works fine. The UISplitView also gets sized properly if it is the first view I show. The problem only occurs if I switch to it after another view has been shown, in landscape. So, is there some way to force iPhone OS to resize the view after it has been added to the window? I've tried calling sizeToFit, but it didn't work. I've also tried setting the view's bounds to the window's bounds, and I've tried setting the frame.

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  • Generating all unique combinations for "drive ya nuts" puzzle

    - by Yuval A
    A while back I wrote a simple python program to brute-force the single solution for the drive ya nuts puzzle. The puzzle consists of 7 hexagons with the numbers 1-6 on them, and all pieces must be aligned so that each number is adjacent to the same number on the next piece. The puzzle has ~1.4G non-unique possibilities: you have 7! options to sort the pieces by order (for example, center=0, top=1, continuing in clockwise order...). After you sorted the pieces, you can rotate each piece in 6 ways (each piece is a hexagon), so you get 6**7 possible rotations for a given permutation of the 7 pieces. Totalling: 7!*(6**7)=~1.4G possibilities. The following python code generates these possible solutions: def rotations(p): for i in range(len(p)): yield p[i:] + p[:i] def permutations(l): if len(l)<=1: yield l else: for perm in permutations(l[1:]): for i in range(len(perm)+1): yield perm[:i] + l[0:1] + perm[i:] def constructs(l): for p in permutations(l): for c in product(*(rotations(x) for x in p)): yield c However, note that the puzzle has only ~0.2G unique possible solutions, as you must divide the total number of possibilities by 6 since each possible solution is equivalent to 5 other solutions (simply rotate the entire puzzle by 1/6 a turn). Is there a better way to generate only the unique possibilities for this puzzle?

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  • Cocos2D: Problem Rotating a CCMenu

    - by srikanth rongali
    If I try to do actions over menuItems but the actions are not running as expected. I think code below should make the menuItem rotate by 90 degrees but when I run it, the menuItem translates from its coordinates to another coordinate then returns to its original coordinate. The complete translation takes 3 seconds. What I need is for the menuItem to rotate by 90 degrees in place within a 3 seconds duration. Please explain where I have done wrong? CCMenuItemImage *targetE;//Globally declared CCMenu *menu;//Globally declared -(id)init { if( (self = [super init]) ) { isTouchEnabled = YES; CGSize windowSize = [[CCDirector sharedDirector] winSize]; targetE = [CCMenuItemImage itemFromNormalImage:@"grossinis_sister1.png" selectedImage:@"grossinis_sister1.png" target:self selector:@selector(touch:)]; menu = [CCMenu menuWithItems:targetE,nil]; id action4 = [CCRotateBy actionWithDuration:3.0 angle:90]; [menu runAction: [CCSequence actions: action4, nil]]; menu.position = ccp(windowSize.width/2 + 200, windowSize.height/2); [self addChild: menu z:10]; } return self; } @end Thank You.

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  • 2D Ball Collisions with Corners

    - by Aaron
    I'm trying to write a 2D simulation of a ball that bounces off of fixed vertical and horizontal walls. Simulating collisions with the faces of the walls was pretty simple--just negate the X-velocity for a vertical wall or the Y-velocity for a horizontal wall. The problem is that the ball can also collide with the corners of the walls, where a horizontal wall meets with a vertical wall. I have already figured out how to detect when a collision with a corner is occurring. My question is how the ball should react to this collision--that is, how its X and Y velocities will change as a result. Here's a list of what I already know or know how to find: *The X and Y coordinates of the ball's center during the frame when a collision is detected *The X and Y components of the ball's velocity *The X and Y coordinates of the corner *The angle between the ball's center and the corner *The angle in which the ball is traveling just before the collision *The amount that the ball is overlapping the corner when the collision is detected I'm guessing that it's best to pretend that the corner is an infinitely small circle, so I can treat a collision between the ball and that circle as if the ball were colliding with a wall that runs tangent to the circles at the point of collision. It seems to me that all I need to do is rotate the coordinate system to line up with this imaginary wall, reverse the X component of the ball's velocity under this system, and rotate the coordinates back to the original system. The problem is that I have no idea how to program this. By the way, this is an ideal simulation. I'm not taking anything like friction or the ball's rotation into account. I'm using Objective-C, but I'd really just like a general algorithm or some advice. Many thanks if anyone can help!

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  • jquery Uncaught SyntaxError: Unexpected token )

    - by js00831
    I am getting a jquery error in my code... can you guys tell me whats the reason for this when you click the united states red color button in this link you will see this error http://jsfiddle.net/SSMX4/88/embedded/result/ function checkCookie(){ var cookie_locale = readCookie('desired-locale'); var show_blip_count = readCookie('show_blip_count'); var tesla_locale = 'en_US'; //default to US var path = window.location.pathname; // debug.log("path = " + path); var parsed_url = parseURL(window.location.href); var path_array = parsed_url.segments; var path_length = path_array.length var locale_path_index = -1; var locale_in_path = false; var locales = ['en_AT', 'en_AU', 'en_BE', 'en_CA', 'en_CH', 'de_DE', 'en_DK', 'en_GB', 'en_HK', 'en_EU', 'jp', 'nl_NL', 'en_US', 'it_IT', 'fr_FR', 'no_NO'] // see if we are on a locale path $.each(locales, function(index, value){ locale_path_index = $.inArray(value, path_array); if (locale_path_index != -1) { tesla_locale = value == 'jp' ? 'ja_JP':value; locale_in_path = true; } }); // debug.log('tesla_locale = ' + tesla_locale); cookie_locale = (cookie_locale == null || cookie_locale == 'null') ? false:cookie_locale; // Only do the js redirect on the static homepage. if ((path_length == 1) && (locale_in_path || path == '/')) { debug.log("path in redirect section = " + path); if (cookie_locale && (cookie_locale != tesla_locale)) { // debug.log('Redirecting to cookie_locale...'); var path_base = ''; switch (cookie_locale){ case 'en_US': path_base = path_length > 1 ? path_base:'/'; break; case 'ja_JP': path_base = '/jp' break; default: path_base = '/' + cookie_locale; } path_array = locale_in_path != -1 ? path_array.slice(locale_in_path):path_array; path_array.unshift(path_base); window.location.href = path_array.join('/'); } } // only do the ajax call if we don't have a cookie if (!cookie_locale) { // debug.log('doing the cookie check for locale...') cookie_locale = 'null'; var get_data = {cookie:cookie_locale, page:path, t_locale:tesla_locale}; var query_country_string = parsed_url.query != '' ? parsed_url.query.split('='):false; var query_country = query_country_string ? (query_country_string.slice(0,1) == '?country' ? query_country_string.slice(-1):false):false; if (query_country) { get_data.query_country = query_country; } $.ajax({ url:'/check_locale', data:get_data, cache: false, dataType: "json", success: function(data){ var ip_locale = data.locale; var market = data.market; var new_locale_link = $('#locale_pop #locale_link'); if (data.show_blip && show_blip_count < 3) { setTimeout(function(){ $('#locale_msg').text(data.locale_msg); $('#locale_welcome').text(data.locale_welcome); new_locale_link[0].href = data.new_path; new_locale_link.text(data.locale_link); new_locale_link.attr('rel', data.locale); if (!new_locale_link.hasClass(data.locale)) { new_locale_link.addClass(data.locale); } $('#locale_pop').slideDown('slow', function(){ var hide_blip = setTimeout(function(){ $('#locale_pop').slideUp('slow', function(){ var show_blip_count = readCookie('show_blip_count'); if (!show_blip_count) { createCookie('show_blip_count',1,360); } else if (show_blip_count < 3 ) { var b_count = show_blip_count; b_count ++; eraseCookie('show_blip_count'); createCookie('show_blip_count',b_count,360); } }); },10000); $('#locale_pop').hover(function(){ clearTimeout(hide_blip); },function(){ setTimeout(function(){$('#locale_pop').slideUp();},10000); }); }); },1000); } } }); } }

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  • How to Find Intersections with Ellipses in PGF/TikZ

    - by infblnpf
    Hello, I am trying to display a sphere in PGF/TikZ to illustrate the idea of great circles. The code for my current result is: \begin{tikzpicture} \tikzfading[name=fade right, left color=transparent!20, right color=transparent!90] \tikzfading[name=fade out, inner color=transparent!100, outer color=transparent!10] \tikzfading[name=fade right gc, left color=transparent!0, right color=transparent!70] \draw [<->, dashed] (0,-5) -- (0,5); % y-axis \draw [->, dashed] (0, 0) -- (20:5); % x-axis \draw [->, dashed] (0, 0) -- (200:5); % x-axis \draw [->, dashed] (0, 0) -- (340:5); % z-axis \draw [->, dashed] (0, 0) -- (160:5); % z-axis \fill [color=cyan, opacity=0.15, path fading=fade out] (0,0) circle (4cm); % bounding circle \fill [color=cyan, opacity=0.25, path fading=fade right, fading angle=90] (0,0) ellipse (4cm and 1cm); % x-y-axis area % great circle 1 \draw [rotate=-40, color=red, path fading=fade right gc, fading angle=40] (0,0) ellipse (4cm and 1cm); % great circle 2 \draw[rotate=5, color=red, path fading=fade right gc, fading angle=5] (0,0) ellipse (1.5cm and 4cm); \end{tikzpicture} How do I find the two points of intersection of the two red ellipses (commented as great circle 1 and 2), find the point of intersection of a line (originating at the center (0,0)) with a ellipse, and place a little circle or rectangle there? Placing a little circle or rectangle there is not an issue. Thank you very much!

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  • Autorotation and multiple view controllers

    - by alku83
    I'm creating an iPad application which should only work in portrait and portait upsidedown modes. For performance reasons in my applicationDidFinishLaunching method I'm creating several viewControllers, and adding them to my main window as subviews. I then hide the ones I don't want to see straight away. There is no tab bar or navigation controller. My problem is that only the first viewController seems to be receiving the rotate calls. I have verified this by swapping around the order in which I add the subviews to the main window and NSLog's. Is there some way I can force all the controllers to receive the calls? Some of my views are designed to lay over the top of another view, but this behind view will not always be the same one - so it seems to make sense to have the overlay view in a separate view controller. Am I doing something fundamentally wrong, and that's why it's not behaving as I would expect? EDIT: The accepted answer for this question seems to indicate the exact problem I'm facing: http://stackoverflow.com/questions/548142/uiviewcontroller-rotate-methods

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  • GLSL Error: failed to preprocess the source. How can I troubleshoot this?

    - by Brent Parker
    I'm trying to learn to play with OpenGL GLSL shaders. I've written a very simple program to simply create a shader and compile it. However, whenever I get to the compile step, I get the error: Error: Preprocessor error Error: failed to preprocess the source. Here's my very simple code: #include <GL/gl.h> #include <GL/glu.h> #include <GL/glut.h> #include <GL/glext.h> #include <time.h> #include <stdio.h> #include <iostream> #include <stdlib.h> using namespace std; const int screenWidth = 640; const int screenHeight = 480; const GLchar* gravity_shader[] = { "#version 140" "uniform float t;" "uniform mat4 MVP;" "in vec4 pos;" "in vec4 vel;" "const vec4 g = vec4(0.0, 0.0, -9.80, 0.0);" "void main() {" " vec4 position = pos;" " position += t*vel + t*t*g;" " gl_Position = MVP * position;" "}" }; double pointX = (double)screenWidth/2.0; double pointY = (double)screenWidth/2.0; void initShader() { GLuint shader = glCreateShader(GL_VERTEX_SHADER); glShaderSource(shader, 1, gravity_shader, NULL); glCompileShader(shader); GLint compiled = true; glGetShaderiv(shader, GL_COMPILE_STATUS, &compiled); if(!compiled) { GLint length; GLchar* log; glGetShaderiv(shader, GL_INFO_LOG_LENGTH, &length); log = (GLchar*)malloc(length); glGetShaderInfoLog(shader, length, &length, log); std::cout << log <<std::endl; free(log); } exit(0); } bool myInit() { initShader(); glClearColor(1.0f, 1.0f, 1.0f, 0.0f); glColor3f(0.0f, 0.0f, 0.0f); glPointSize(1.0); glLineWidth(1.0f); glMatrixMode(GL_PROJECTION); glLoadIdentity(); gluOrtho2D(0.0, (GLdouble) screenWidth, 0.0, (GLdouble) screenHeight); glEnable(GL_DEPTH_TEST); return true; } int main(int argc, char** argv) { glutInit(&argc, argv); glutInitDisplayMode(GLUT_DOUBLE | GLUT_RGB); glutInitWindowSize(screenWidth, screenHeight); glutInitWindowPosition(100, 150); glutCreateWindow("Mouse Interaction Display"); myInit(); glutMainLoop(); return 0; } Where am I going wrong? If it helps, I am trying to do this on a Acer Aspire One with an atom processor and integrated Intel video running the latest Ubuntu. It's not very powerful, but then again, this is a very simple shader. Thanks a lot for taking a look!

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  • Injection of an EJB into a web java class under JBoss 7.1.1

    - by Dobbo
    I am trying to build a website using JBoss 7.1.1 and RESTeasy. I have managed to constructed and deploy and EAR with a both a WAR and an EJB-JAR contained within: voyager-app.ear META-INF/MANIFEST.MF META-INF/application.xml META-INF/jboss-app.xml lib/voyager-lib.jar voyager-adm.war voyager-ejb.jar voyager-web.war So far things are very simple. voyager-adm.war & voyager-lib.jar are empty (just the manifest file) but I know that I'm going to have code for them shortly. There is just one Stateful EJB - HarbourMasterBean (with just a local interface) and a few Database Entity Beans in the EJB jar file: voyager-ejb.jar META-INF/MANIFEST.MF META-INF/persistence.xml com/nutrastat/voyager/db/HarbourMasterBean.class com/nutrastat/voyager/db/HarbourMasterLocal.class com/nutrastat/voyager/db/PortEntity.class com/nutrastat/voyager/db/ShipEntity.class As far as I can tell the EJBs deploy correctly because the database units are created and the log shows that the publication of some HarbourMaster references: java:global/voyager-app/voyager-ejb/harbour-master!com.nutrastat.voyager.db.HarbourMasterLocal java:app/voyager-ejb/harbour-master!com.nutrastat.voyager.db.HarbourMasterLocal java:module/harbour-master!com.nutrastat.voyager.db.HarbourMasterLocal java:global/voyager-app/voyager-ejb/harbour-master java:app/voyager-ejb/harbour-master java:module/harbour-master The problem lies in getting the HarbourMaster EJB injected into my web bean. The reference to it is alway NULL no matter what I try. voyager-web.war META-INF/MANIFEST.MF WEB-INF/web.xml WEB-INF/classes/com/nutrastat/voyager/web/ WEB-INF/classes/com/nutrastat/voyager/web/Ships.class WEB-INF/classes/com/nutrastat/voyager/web/VoyagerApplication.class Ships.java: @Path("fleet") public class Ships { protected transient final Logger log; @EJB private HarbourMasterLocal harbourMaster; public Ships() { log = LoggerFactory.getLogger(getClass()); } @GET @Path("ships") @Produces({"text/plain"}) public String listShips() { if (log.isDebugEnabled()) log.debug("Harbour master value: " + harbourMaster); return "Harbour Master: " + harbourMaster; } } &lt;web-app xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" version="3.0" &gt; <display-name>Voyager Web Application</display-name> <listener> <listener-class> org.jboss.resteasy.plugins.server.servlet.ResteasyBootstrap </listener-class> </listener> <servlet> <servlet-name>Resteasy</servlet-name> <servlet-class> org.jboss.resteasy.plugins.server.servlet.HttpServletDispatcher </servlet-class> <init-param> <param-name> javax.ws.rs.Application </param-name> <param-value> com.nutrastat.voyager.web.VoyagerApplication </param-value> </init-param> </servlet> <servlet-mapping> <servlet-name>Resteasy</servlet-name> <url-pattern>/*</url-pattern> </servlet-mapping> &lt;/web-app&gt; I have been searching the web for an answer and read a number of places, both on StackOverflow and elsewhere that suggests is can be done, and that the problems lies with configuration. But they post only snippets and I'm never sure if I'm doing things correctly. Many thanks for any help you can provide. Dobbo

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  • Faster method for Matrix vector product for large matrix in C or C++ for use in GMRES

    - by user35959
    I have a large, dense matrix A, and I aim to find the solution to the linear system Ax=b using an iterative method (in MATLAB was the plan using its built in GMRES). For more than 10,000 rows, this is too much for my computer to store in memory, but I know that the entries in A are constructed by two known vectors x and y of length N and the entries satisfy: A(i,j) = .5*(x[i]-x[j])^2+([y[i]-y[j])^2 * log(x[i]-x[j])^2+([y[i]-y[j]^2). MATLAB's GMRES command accepts as input a function call that can compute the matrix vector product A*x, which allows me to handle larger matrices than I can store in memory. To write the matrix-vecotr product function, I first tried this in matlab by going row by row and using some vectorization, but I avoid spawning the entire array A (since it would be too large). This was fairly slow unfortnately in my application for GMRES. My plan was to write a mex file for MATLAB to, which is in C, and ideally should be significantly faster than the matlab code. I'm rather new to C, so this went rather poorly and my naive attempt at writing the code in C was slower than my partially vectorized attempt in Matlab. #include <math.h> #include "mex.h" void Aproduct(double *x, double *ctrs_x, double *ctrs_y, double *b, mwSize n) { mwSize i; mwSize j; double val; for (i=0; i<n; i++) { for (j=0; j<i; j++) { val = pow(ctrs_x[i]-ctrs_x[j],2)+pow(ctrs_y[i]-ctrs_y[j],2); b[i] = b[i] + .5* val * log(val) * x[j]; } for (j=i+1; j<n; j++) { val = pow(ctrs_x[i]-ctrs_x[j],2)+pow(ctrs_y[i]-ctrs_y[j],2); b[i] = b[i] + .5* val * log(val) * x[j]; } } } The above is the computational portion of the code for the matlab mex file (which is slightly modified C, if I understand correctly). Please note that I skip the case i=j, since in that case the variable val will be a 0*log(0), which should be interpreted as 0 for me, so I just skip it. Is there a more efficient or faster way to write this? When I call this C function via the mex file in matlab, it is quite slow, slower even than the matlab method I used. This surprises me since I suspected that C code should be much faster than matlab. The alternative matlab method which is partially vectorized that I am comparing it with is function Ax = Aprod(x,ctrs) n = length(x); Ax = zeros(n,1); for j=1:(n-3) v = .5*((ctrs(j,1)-ctrs(:,1)).^2+(ctrs(j,2)-ctrs(:,2)).^2).*log((ctrs(j,1)-ctrs(:,1)).^2+(ctrs(j,2)-ctrs(:,2)).^2); v(j)=0; Ax(j) = dot(v,x(1:n-3); end (the n-3 is because there is actually 3 extra components, but they are dealt with separately,so I excluded that code). This is partly vectorized and only needs one for loop, so it makes some sense that it is faster. However, I was hoping I could go even faster with C+mex file. Any suggestions or help would be greatly appreciated! Thanks! EDIT: I should be more clear. I am open to any faster method that can help me use GMRES to invert this matrix that I am interested in, which requires a faster way of doing the matrix vector product without explicitly loading the array into memory. Thanks!

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  • Code Golf: Rotating Maze

    - by trinithis
    Code Golf: Rotating Maze Make a program that takes in a file consisting of a maze. The maze has walls given by '#'. The maze must include a single ball, given by a 'o' and any number of holes given by a '@'. The maze file can either be entered via command line or read in as a line through standard input. Please specify which in your solution. Your program then does the following: 1: If the ball is not directly above a wall, drop it down to the nearest wall. 2: If the ball passes through a hole during step 1, remove the ball. 3: Display the maze. 4: If there is no ball in the maze, exit. 5: Read a line from the standard input. Given a 1, rotate the maze counterclockwise. Given a 2, rotate the maze clockwise. Rotations are done by 90 degrees. It is up to you to decide if extraneous whitespace is allowed. If the user enters other inputs, repeat this step. 6: Goto step 1. You may assume all input mazes are closed. Note, a hole effectively acts as a wall in this regard. You may assume all input mazes have no extraneous whitespace. The shortest source code by character count wins. Example mazes: ###### #o @# ###### ########### #o # # ####### # ###@ # ######### ########################### # # # # @ # # # # ## # # ####o#### # # # # # # ######### # @ ######################

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  • Checkboxes will not check in IE7 using Javascript, and yet no errors

    - by leeand00
    Okay I'm totally confused on this one. I have a script that receives a bunch of values from a JSON object and creates a bunch of checkboxes and either checks or unchecks a these checkboxes based on their values. This script treats me like a woman treats me... "If you don't know what's wrong, then I'm not going to tell you..." The script works correctly in IE8, Firefox3, etc... etc... However... In IE7 the script fails to check off the checkboxes. It displays no errors and from what I can tell, the script runs just fine. I just doesn't check any of the checkboxes, and I don't know why... shoppingCart['Update_Stock_Item_0_NRD%5FHAT2'] = { 'propeller': { 'label' : 'propeller', 'optionValues' : { 'on' : { 'selected': 'selected' }, 'off' : { 'selected': '' }, '' : new String() } }, 'sunLogo': { 'label' : 'sunLogo', 'optionValues' : { 'on' : { 'selected': 'selected' }, 'off' : { 'selected': '' }, '' : new String() } }, 'MSLogo': { 'label' : 'sunLogo', 'optionValues' : { 'on' : { 'selected': 'selected' }, 'off' : { 'selected': '' }, '' : new String() } } }; function stockInit() { alert("BEGIN: stockInit()"); // TODO: You will recieve an "on" and an "off" option, // One will have a "selected" attribute of "selected", // and the other will have a "selected" attribute of "" // // The option that has the "selected" attribute of "" // will generate a checkbox that is not checked. // // The option that has the "selected attribute of "selected" // will generate a checkbox that is checked. // // Why? You ask...because that's just the way the thing is // setup. for(var item in shoppingCart) { // // console.log("processing item: " + item); var optionContainer = document.getElementById(item + "_optionContainer"); for(var option in shoppingCart[item]) { if(option != "blank") { // // console.log("option: " + option); var currentOption = shoppingCart[item][option]['optionValues']; // // console.log("currentOption['on']['selected']: " + currentOption['on']['selected']); // // console.log("currentOption['off']['selected']: " + currentOption['off']['selected']); // Really you only have to check the one, but just to be through-o var selected = (currentOption['on']['selected'] == 'selected') ? true : false; selected = (currentOption['off']['selected'] == 'selected') ? false : true; var label = document.createElement("LABEL"); var labelText = document.createTextNode(shoppingCart[item][option]['label']); var optionInput = document.createElement("INPUT"); var hiddenInput = document.createElement("INPUT"); optionInput.setAttribute("type", "checkbox"); optionInput.checked = selected; optionInput.setAttribute("id", option); alert(optionInput.id); alert(optionInput.checked); hiddenInput.setAttribute("type", "hidden"); hiddenInput.setAttribute("name", option); hiddenInput.setAttribute("id", option + "_hiddenValue"); hiddenInput.setAttribute("value", (optionInput.checked) ? "on" : "off"); label.appendChild(optionInput); label.appendChild(labelText); label.appendChild(hiddenInput); (function(id) { optionInput.onclick = function() { var hiddenInput = document.getElementById(id + "_hiddenValue"); hiddenInput.setAttribute("value", (this.checked == true) ? "on" : "off"); alert("this.id: " + this.id); alert("this.checked: " + this.checked); } })(optionInput.id); optionContainer.appendChild(label); } } // // console.log("processing item of " + item + " complete"); } alert("END: stockInit()"); } And please don't ask why I'm doing things this way...all I can really tell you is that I don't have access to the backend code...so I get what I get...

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  • UITabBarController with viewControllers utilizing different orientations?

    - by RickiG
    Hi I can see that this is something that has been troubling a lot of people:/ I have a UITabBarController that has 4 viewControllers, all of type UINavigationController. One of the navigationControllers gets a viewController pushed onto its stack, this viewController should be presented in landscape mode/orientation. The viewController is a graph, it is the absolutely only place in the app where landscape makes sense. (I hide the UITabBar when this is presented to not lead the user to believe this will work everywhere) To make a UITabBarController respond correctly to changes in orientation all its viewControllers need to return the same value from the delegate method: - (BOOL)shouldAutorotateToInterfaceOrientation:(UIInterfaceOrientation)interfaceOrientation So to accomodate this behavior I have implemented this method in all the viewControllers belonging to the UITabBarController: - (BOOL)shouldAutorotateToInterfaceOrientation:(UIInterfaceOrientation)interfaceOrientation { NSUserDefaults *defaults = [NSUserDefaults standardUserDefaults]; BOOL canRotate = [defaults boolForKey:@"can_rotate"]; return canRotate; } The "trick" is now that when my can-be-landscape viewController is pushed I do this: - (void) viewWillAppear:(BOOL)animated { NSUserDefaults *defaults = [NSUserDefaults standardUserDefaults]; [defaults setBool:YES forKey:@"can_rotate"]; [defaults synchronize]; } and when it is popped, I do this: - (void) viewWillDisappear:(BOOL)animated { NSUserDefaults *defaults = [NSUserDefaults standardUserDefaults]; [defaults setBool:NO forKey:@"can_rotate"]; [defaults synchronize]; } This works really well. When the viewController is on the stack I can rotate the device and the view follows. The problem is however, that if the user taps the "back" button on the navigationBar while in landscape mode, thus popping the viewController to the previous viewController, this "old" viewController is of course also in landscape mode. To make things worse, because I set the BOOL to NO, this "old" viewController can not rotate back when I orientate the device to portrait mode. Is there a way to update everything so that none of my other viewControllers will be in landscape mode when I pop the can-be-in-landscape mode viewController? I am a bit worried that if this could be done from landscape to portrait it should also be possible from portrait to landscape, thus making my "hack" unnecessary.. but if it can not, then I am back to square one :/ Hope I am close and that someone could help me get there, thanks:)

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  • ExtJS 4 Chart Axis Display Issue in Chrome

    - by SerEnder
    I've run into an issue while using ExtJS 4.0.7. I'm trying to display a chart with two series on a Numeric/Category Chart. The chart displays correctly in Firefox, but while using Chrome (18.0.1025.142) the x axis labels are either all stacked upon each or else (when using rotate) rendered behind the chart in the specified angle. Any ideas would be appreciated. Screen shot in Firefox: Screen Shot in Chrome: And the code that's used to generate both: Ext.require(['Ext.chart.*']); Ext.onReady(function() { var iChartWidth = 800; // Defines chart width var iChartHeight = 550; // Defines chart height Ext.define('RulesCreatedModel',{ extend:'Ext.data.Model', fields:[ {name:'sHourName', type:'string'}, {name:'User_2', type:'number'}, {name:'User_1', type:'number'}, ] }); var RulesCreatedStore = Ext.create('Ext.data.Store',{ id:'RulesCreatedStore', model:'RulesCreateModel', fields: [ 'sHourName','dayNum','hour','User_2','User_1'], data:[{ 'sHourName':'3pm', 'User_1':82, 'User_2':56 },{ 'sHourName':'4pm', 'User_1':39, 'User_2':44 },{ 'sHourName':'5pm', 'User_1':80, 'User_2':14 },{ 'sHourName':'6pm', 'User_1':55, 'User_2':0, },{ 'sHourName':'7pm', 'User_1':36, 'User_2':0, },{ 'sHourName':'8pm', 'User_1':66, 'User_2':0 },{ 'sHourName':'9pm', 'User_1':39, 'User_2':0, },{ 'sHourName':'10pm', 'User_1':0, 'User_2':0 },{ 'sHourName':'11pm', 'User_1':0, 'User_2':0 },{ 'sHourName':'12am', 'User_1':0, 'User_2':0 },{ 'sHourName':'1am', 'User_1':0, 'User_2':0 },{ 'sHourName':'2am', 'User_1':0, 'User_2':0 },{ 'sHourName':'3am', 'User_1':0, 'User_2':0 },{ 'sHourName':'4am', 'User_1':0, 'User_2':0 },{ 'sHourName':'5am', 'User_1':0, 'User_2':0 },{ 'sHourName':'6am', 'User_1':0, 'User_2':0 },{ 'sHourName':'7am', 'User_1':0, 'User_2':1 },{ 'sHourName':'8am', 'User_1':0, 'User_2':99 },{ 'sHourName':'9am', 'User_1':0, 'User_2':28 },{ 'sHourName':'10am', 'User_1':0, 'User_2':28 },{ 'sHourName':'11am', 'User_1':0, 'User_2':153 },{ 'sHourName':'12pm', 'User_1':0, 'User_2':58 },{ 'sHourName':'1pm', 'User_1':0, 'User_2':42 },{ 'sHourName':'2pm', 'User_1':20, 'User_2':10 }] }); Ext.create('Ext.chart.Chart',{ id: 'RulesWrittenChart', renderTo: 'StatCharts_Display', width: iChartWidth, height: iChartHeight, animate: true, store: RulesCreatedStore, axes: [{ type: 'Numeric', position: 'left', fields: ['User_2','User_1'], title: 'Rules Written', grid: true },{ type: 'Category', position: 'bottom', fields: ['sHourName'], title: 'Hour', grid: false, label: { rotate: { degrees: 315 } } }], series: [{ type: 'line', axis: 'left', xField: 'sHourName', yField: 'User_2', highlight: { size: 3, radius: 3 } },{ type: 'line', axis: 'left', xField: 'sHourName', yField: 'User_1', highlight: { size: 3, radius: 3 } }] }); });

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  • Calculate lookat vector from position and Euler angles

    - by Jaap
    I've implemented an FPS style camera, with the camera consisting of a position vector, and Euler angles pitch and yaw (x and y rotations). After setting up the projection matrix, I then translate to camera coordinates by rotating, then translating to the inverse of the camera position: // Load projection matrix glMatrixMode(GL_PROJECTION); glLoadIdentity(); // Set perspective gluPerspective(m_fFOV, m_fWidth/m_fHeight, m_fNear, m_fFar); // Load modelview matrix glMatrixMode(GL_MODELVIEW); glLoadIdentity(); // Position camera glRotatef(m_fRotateX, 1.0, 0.0, 0.0); glRotatef(m_fRotateY, 0.0, 1.0, 0.0); glTranslatef(-m_vPosition.x, -m_vPosition.y, -m_vPosition.z); Now I've got a few viewports set up, each with its own camera, and from every camera I render the position of the other cameras (as a simple box). I'd like to also draw the view vector for these cameras, except I haven't a clue how to calculate the lookat vector from the position and Euler angles. I've tried to multiply the original camera vector (0, 0, -1) by a matrix representing the camera rotations then adding the camera position to the transformed vector, but that doesn't work at all (most probably because I'm way off base): vector v1(0, 0, -1); matrix m1 = matrix::IDENTITY; m1.rotate(m_fRotateX, 0, 0); m1.rotate(0, m_fRotateY, 0); vector v2 = v1 * m1; v2 = v2 + m_vPosition; // add camera position vector glBegin(GL_LINES); glVertex3fv(m_vPosition); glVertex3fv(v2); glEnd(); What I'd like is to draw a line segment from the camera towards the lookat direction. I've looked all over the place for examples of this, but can't seem to find anything. Thanks a lot!

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  • error in a pygame code

    - by mekasperasky
    # INTIALISATION import pygame, math, sys from pygame.locals import * screen = pygame.display.set_mode((1024, 768)) car = pygame.image.load('car.png') clock = pygame.time.Clock() k_up = k_down = k_left = k_right = 0 speed = direction = 0 position = (100, 100) TURN_SPEED = 5 ACCELERATION = 2 MAX_FORWARD_SPEED = 10 MAX_REVERSE_SPEED = ­5 BLACK = (0,0,0) while 1: # USER INPUT clock.tick(30) for event in pygame.event.get(): if not hasattr(event, 'key'): continue down = event.type == KEYDOWN # key down or up? if event.key == K_RIGHT: k_right = down * ­5 elif event.key == K_LEFT: k_left = down * 5 elif event.key == K_UP: k_up = down * 2 elif event.key == K_DOWN: k_down = down * ­2 elif event.key == K_ESCAPE: sys.exit(0) # quit the game screen.fill(BLACK) # SIMULATION # .. new speed and direction based on acceleration and turn speed += (k_up + k_down) if speed > MAX_FORWARD_SPEED: speed = MAX_FORWARD_SPEED if speed < MAX_REVERSE_SPEED: speed = MAX_REVERSE_SPEED direction += (k_right + k_left) # .. new position based on current position, speed and direction x, y = position rad = direction * math.pi / 180 x += ­speed*math.sin(rad) y += ­speed*math.cos(rad) position = (x, y) # RENDERING # .. rotate the car image for direction rotated = pygame.transform.rotate(car, direction) # .. position the car on screen rect = rotated.get_rect() rect.center = position # .. render the car to screen screen.blit(rotated, rect) pygame.display.flip() enter code here the error i get is this Non-ASCII character '\xc2' in file race1.py on line 13, but no encoding declared; see http://www.python.org/peps/pep-0263.html for details Not able to understand what the error is and how to get rid of it?

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  • Auto-rotating freshly created interface

    - by zoul
    Hello! I have trouble with auto-rotating interfaces in my iPad app. I have a class called Switcher that observes the interface rotation notifications and when it receives one, it switches the view in window, a bit like this: - (void) orientationChanged: (NSNotification*) notice { UIDeviceOrientation newIO = [[UIDevice currentDevice] orientation]; UIViewController *newCtrl = /* something based on newIO */; [currentController.view removeFromSuperview]; // remove the old view [window addSubview newCtrl.view]; [self setCurrentController:newCtrl]; } The problem is that the new view does not auto-rotate. My auto-rotation callback in the controller class looks like this: - (BOOL) shouldAutorotateToInterfaceOrientation: (UIInterfaceOrientation) io { NSString *modes[] = {@"unknown", @"portrait", @"portrait down", @"landscape left", @"landscape right"}; NSLog(@"shouldAutorotateToInterfaceOrientation: %i (%@)", io, modes[io]); return YES; } But no matter how I rotate the device, I find the following in the log: shouldAutorotateToInterfaceOrientation: 1 (portrait) shouldAutorotateToInterfaceOrientation: 1 (portrait) …and the willRotateToInterfaceOrientation:duration: does not get called at all. Now what? The orientation changing is becoming my least favourite part of the iPhone SDK… (I can’t check the code on the device yet, could it be a bug in the simulator?) PS. The subscription code looks like this: [[UIDevice currentDevice] beginGeneratingDeviceOrientationNotifications]; [[NSNotificationCenter defaultCenter] addObserver:self selector:@selector(orientationChanged:) name:UIDeviceOrientationDidChangeNotification object:nil];

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