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  • mySQL - query to combine two tables

    - by W.Gerick
    Hi there, I have two tables. The first one holds information about cities: Locations: locID | locationID | locationName | countryCode | 1 | 2922239 | Berlin | de | 2 | 291074 | Paris | fr | 3 | 295522 | Orlando | us | 3 | 292345 | Tokyo | jp | There is a second table, which holds alternative names for locations. There might be NO alternative name for a location in the Locations table: AlternateNames: altNameID | locationID | alternateName | 1 | 2922239 | Berlino | 2 | 2922239 | Berlina | 3 | 291074 | Parisa | 4 | 291074 | Pariso | 5 | 295522 | Orlandola | 6 | 295522 | Orlandolo | What I would like to get is the locationID, name and the countryCode of a location for a location name search like "Berlin", or "Ber": | locationID | name | countryCode | | 2922239 | Berlin | de | However, if the user searches for "Berlino", I would like to get the alternateName back: | locationID | name | countryCode | | 2922239 | Berlino | de | The "locationName" has a higher priority than the alternateName, if the searchterm matches both. I can't figure out how to build a query to do that. Since the name can come from one of the two tables, it seems quite difficult to me. Any help is really appreciated!

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  • Select query 2-3 times faster than view

    - by Richard Knop
    This query run alone: SELECT -- lots of columns FROM (((((((((((`table1` `t1` LEFT JOIN `table2` `t2` ON(( `t2`.`userid` = `t1`.`userid` ))) LEFT JOIN `table3` `t3` ON(( `t1`.`orderid` = `t3`.`orderid` ))) LEFT JOIN `table4` `t4` ON(( `t4`.`orderitemlicenseid` = `t3`.`orderitemlicenseid` ))) LEFT JOIN `table5` `t5` ON(( `t1`.`orderid` = `t5`.`orderid` ))) LEFT JOIN `table6` `t6` ON(( `t5`.`transactionid` = `t6`.`transactionid` ))) LEFT JOIN `table7` `t7` ON(( `t7`.`transactionid` = `t5`.`transactionid` ))) LEFT JOIN `table8` `t8` ON(( `t8`.`voucherid` = `t7`.`voucherid` ))) LEFT JOIN `table9` `t9` ON(( `t8`.`voucherid` = `t9`.`voucherid` ))) LEFT JOIN `table10` `t10` ON(( ( `t10`.`vouchergroupid` = `t9`.`vouchergroupid` ) AND ( `t2`.`territoryid` = `t10`.`territoryid` ) ))) LEFT JOIN `table11` `t11` ON(( `t11`.`voucherid` = `t8`.`voucherid` ))) LEFT JOIN `table12` `t12` ON(( `t12`.`orderid` = `t1`.`orderid` ))) GROUP BY `t5`.`transactionid` Takes about 2.5 seconds to finish. When I save it to a view and run it as: SELECT * FROM viewName; It takes 7 seconds to finish. What is the reason and how can I make the view faster?

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  • SQL - re-arrange a table via query

    - by abelenky
    I have a poorly designed table that I inherited. It looks like: User Field Value ------------------- 1 name Aaron 1 email [email protected] 1 phone 800-555-4545 2 name Mike 2 email [email protected] 2 phone 777-123-4567 (etc, etc) I would love to extract this data via a query in the more sensible format: User Name Email Phone ------------------------------------------- 1 Aaron [email protected] 800-555-4545 2 Mike [email protected] 777-123-4567 I'm a SQL novice, but have tried several queries with variations of Group By, all without anything even close to success. Is there a SQL technique to make this easy?

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  • MYSQL - Group by limit

    - by jono2010
    Hello Is there a simple way to LIMIT the GROUP BY results to the top 2. The following query returns all the results. Using 'LIMIT 2' reduces the overall list to the top 2 entries only. select distinct(rating_name), id_markets, sum(rating_good) 'good', sum(rating_neutral)'neutral', sum(rating_bad) 'bad' from ratings where rating_year=year(curdate()) and rating_week= week(curdate(),1) group by rating_name,id_markets order by rating_name, sum(rating_good) desc Results in the following :- poland 78 48 24 12 <- keep poland 1 15 5 0 <- keep poland 23 12 6 3 poland 2 5 0 0 poland 3 0 5 0 poland 4 0 0 5 ireland 1 9 3 0 <- keep ireland 2 3 0 0 <- keep ireland 3 0 3 0 ireland 4 0 0 3 france 12 24 12 6 <- keep france 1 3 1 0 <- keep france 231 1 0 0 france 2 1 0 0 france 4 0 0 1 france 3 0 1 0 Thanks Jon

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  • SQL Server Query solution cum Suggestion Required

    - by Nirmal
    Hello All... I have a following scenario in my SQL Server 2005 database. zipcodes table has following fields and value (just a sample): zipcode latitude longitude ------- -------- --------- 65201 123.456 456.789 65203 126.546 444.444 and place table has following fields and value : id name zip latitude longitude -- ---- --- -------- --------- 1 abc 65201 NULL NULL 2 def 65202 NULL NULL 3 ghi 65203 NULL NULL 4 jkl 65204 NULL NULL Now, my requirement is like I want to compare my zip codes of place table and update the available latitude and longitude fields from zipcode table. And there are some of the zipcodes which has no entry in zipcode table, so that should remain null. And the major issue is like I have more then 50,00,000 records in my db. So, query should support this feature. I have tried some of the solutions but unfortunately not getting proper output. Any help would be appreciated...

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  • Mysql query problem....

    - by Avinash
    I have below values in my database. been Lorem Ipsum and scrambled ever scrambledtexttextofandtooktooktypetexthastheunknownspecimenstandardsincetypesett Here is my query: SELECT nBusinessAdID, MATCH (`sHeadline`) AGAINST ("text" IN BOOLEAN MODE) AS score FROM wiki_businessads WHERE MATCH (`sHeadline`) AGAINST ("text" IN BOOLEAN MODE) AND bDeleted ="0" AND nAdStatus ="1" ORDER BY score DESC, bPrimeListing DESC, dDateCreated DESC It's not fetching first result, why? It should fetch first result because its contain text word in it. I have disabled the stopword filtering. This one is also not working SELECT nBusinessAdID, MATCH (`sHeadline`) AGAINST ('"text"' IN BOOLEAN MODE) AS score FROM wiki_businessads WHERE MATCH (`sHeadline`) AGAINST ('"text"' IN BOOLEAN MODE) AND bDeleted ="0" AND nAdStatus ="1" ORDER BY score DESC, bPrimeListing DESC, dDateCreated DESC Thanks Avinash

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  • UriBuilder incorrectly encoding Query Parameters value ?

    - by Fred
    Lets consider the following code sample where a path and single parameter are encoded... Parameter name: "param" Parameter value: "foo/bar?aaa=bbb&ccc=ddd" (happens to be a url with query parameters) String test = UriBuilder.fromPath("https://dummy.com"). queryParam("param", "foo/bar?aaa=bbb&ccc=ddd"). build().toURL().toString(); The encoded URL string returned is: "https://dummy.com?param=foo/bar?aaa%3Dbbb&ccc%3Dddd" Is this correct ? Should not the character "&" (and may be even "?") be encoded in the parameter value string ? Would not the URL produced be interpreted as follow: One first parameter, name="param", value = "ar?aaa%3Dbbb" followed by a second parameter, name="ccc%3Dddd", without value.

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  • SQL Query - Count column values separately

    - by user575535
    I have a hard time getting a Query to work right. This is the DDL for my Tables CREATE TABLE Agency ( id SERIAL not null, city VARCHAR(200) not null, PRIMARY KEY(id) ); CREATE TABLE Customer ( id SERIAL not null, fullname VARCHAR(200) not null, status VARCHAR(15) not null CHECK(status IN ('new','regular','gold')), agencyID INTEGER not null REFERENCES Agency(id), PRIMARY KEY(id) ); Sample Data from the Tables AGENCY id|'city' 1 |'London' 2 |'Moscow' 3 |'Beijing' CUSTOMER id|'fullname' |'status' |agencyid 1 |'Michael Smith' |'new' |1 2 |'John Doe' |'regular'|1 3 |'Vlad Atanasov' |'new' |2 4 |'Vasili Karasev'|'regular'|2 5 |'Elena Miskova' |'gold' |2 6 |'Kim Yin Lu' |'new' |3 7 |'Hu Jintao' |'regular'|3 8 |'Wen Jiabao' |'regular'|3 I want to produce the following output, but i need to count separately for ('new','regular','gold') 'city' |new_customers|regular_customers|gold_customers 'Moscow' |1 |1 |1 'Beijing'|1 |2 |0 'London' |1 |1 |0

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  • Sql query problem

    - by LiveEn
    I have the below sql query that will update the the values from a form to the database $sql="update leads set category='$Category',type='$stype',contactName='$ContactName',email='$Email',phone='$Phone',altphone='$PhoneAlt',mobile='$Mobile',fax='$Fax',address='$Address',city='$City',country='$Country',DateEdited='$today',printed='$Printed',remarks='$Remarks' where id='$id'"; $result=mysql_query($sql) or die(mysql_error()); echo '<h1>Successfully Updated!!.</h1>'; when i submit I dont get any errors and the success message is displayed but the database isnt updated . When i echo the $sql, all the values are set properly. and when i ech the $result i get the value 1. can someone please tell me what am i doing wrong here??

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  • [Newbie] How to join mysql tables

    - by Ivan
    I've an old table like this: user> id | name | address | comments And now I've to create an "alias" table to allow some users to have an alias name for some reasons. I've created a new table 'user_alias' like this: user_alias> name | user But now I have a problem due my poor SQL level... How to join both tables to generate something like this: 1 | my_name | my_address | my_comments 1 | my_alias | my_address | my_comments 2 | other_name | other_address | other_comments I mean, I want to make a "SELECT..." query that returns in the same format as the "user" table ALL users and ALL alias.. Something like this: SELECT user.* FROM user LEFT JOIN user_alias ON `user`=`id` but it doesn't work for me..

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  • MYSQL Select and group by date

    - by Gil
    I'm not sure how create a right query to get the result I'm looking for. What I have is 2 tables. first has ID, Name columns and second has date and adminID, which is referenced from table 1 column ID. Now, what I want to get is basically number of times each admin loged in per day during the month. From structure like this one I want to get per day and month data so result would be similar to 1, 2, 2 march total 5 for admin 4. ID | Date ------------------ 4 | 2010/03/01 4 | 2010/03/04 4 | 2010/03/04 4 | 2010/03/05 4 | 2010/03/05

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  • How to use MySql date_add in Nhibernate?

    - by jalchr
    This really puzzled for hours, I searched all over the internet, but got no working solution. Can someone point where the problem is ... thanks ! I created my own dialect class public class MySQLDialectExtended : MySQLDialect { public MySQLDialectExtended() { RegisterFunction("date_add_interval", new SQLFunctionTemplate(NHibernateUtil.Date, "date_add(?1, INTERVAL ?2 ?3)")); } } Then I try to use it as follows: query.Append( " ( date_add_interval(D.ApprovalDate, 1, YEAR) < current_timestamp() < date_add_interval(D.RenewalDate, -1, YEAR) )"); It fails with following exception: NHibernate.Hql.Ast.ANTLR.QuerySyntaxException : Exception of type 'Antlr.Runtime.NoViableAltException' was thrown. near line 1, column 677 where the column number is at the end of the first 'YEAR' word. Edit: here is my configuration <property name="dialect">MyCompanyName.MySQLDialectExtended, MyCompanyName</property> <property name="hbm2ddl.keywords">none</property>

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  • mysql query clarification

    - by JPro
    I have a query which I am wondering if the result I am getting is the one that I am expecting. The table structure goes like this : Table : results ID TestCase Set Analyzed Verdict StartTime Platform 1 1010101 ros2 false fail 18/04/2010 20:23:44 P1 2 1010101 ros3 false fail 19/04/2010 22:22:33 P1 3 1232323 ros2 true pass 19/04/2010 22:22:33 P1 4 1232323 ros3 false fail 29/04/2010 22:22:33 P2 Table : testcases ID TestCase type 1 1010101 NOSNOS 2 1232323 N212NS is there any way to display only the latest fails on each platform? in the above case Result shoud be : ID TestCase Set Analyzed Verdict StartTime Platform type 2 1010101 ros3 false fail 19/04/2010 22:22:33 P1 NOSNOS 4 1232323 ros3 false fail 29/04/2010 22:22:33 P2 N212NS

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  • mysql error in query for timestamp interval

    - by nik parsa
    I have voting_IP table as follow: +-----------+-------------+------+-----+---------+----------------+ | Field | Type | Null | Key | Default | Extra | +-----------+-------------+------+-----+---------+----------------+ | ip_id | int(11) | NO | PRI | NULL | auto_increment | | mes_id_fk | int(11) | YES | MUL | NULL | | | ip_add | varchar(40) | YES | | NULL | | | timestamp | datetime | YES | | NULL | | +-----------+-------------+------+-----+---------+----------------+ I want to run this query which has errors and I don't know how to correct it? $ip_sql=mysql_query("select ip_add from Voting_IP where mes_id_fk='$id' and ip_add='$ip' and timestamp > (DATE_ADD(now(), INTERVAL -1 HOUR);)"); I also tried this one: $ip_sql=mysql_query("select ip_add from Voting_IP where (mes_id_fk='$id' and ip_add='$ip' and timestamp > (DATE_ADD(now(), INTERVAL -1 HOUR);))");

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  • How to join mysql tables

    - by Ivan
    I've an old table like this: user> id | name | address | comments And now I've to create an "alias" table to allow some users to have an alias name for some reasons. I've created a new table 'user_alias' like this: user_alias> name | user But now I have a problem due my poor SQL level... How to join both tables to generate something like this: 1 | my_name | my_address | my_comments 1 | my_alias | my_address | my_comments 2 | other_name | other_address | other_comments I mean, I want to make a "SELECT..." query that returns in the same format as the "user" table ALL users and ALL alias.. Something like this: SELECT user.* FROM user LEFT JOIN user_alias ON `user`=`id` but it doesn't work for me..

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  • Insert coding query in yii

    - by nerd
    I need to auto insert the next orders_id into an Orders table in a database. orders_id is not the primary Key, and it does not auto-increment I need to query the database, find the last (highest) id value, increment 1, and insert it in Orders table in database. Actually, I have a shipping action which will provide address of shipping of orders. So as soon as the user fills address form and move to payments page, I want to simultaneously fill my Orders table by max(orders_id)+1. I have built relations between Address table and Orders table but my orders Table is not getting populated. Please detail me correct codes to implement it in my controller in Yii

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  • many-to-many query

    - by kofto4ka
    Hello, guys! I have a problem and I dont know what is better solution. Okay, I have 2 tables: posts(id, title), posts_tags(post_id, tag_id). I have next task: must select posts with tags ids for example 4, 10 and 11. Not exactly, post could have any other tags at the same time. So, how I could do it more optimized? Creating temporary table in each query? Or may be some kind of stored procedure? In the future, user could ask script to select posts with any count of tags (it could be 1 tag only or 10 at the same time) and I must be sure that method that I will choose would be the best method for my problem. Sorry for my english, thx for attention.

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  • SQL Count Query with Grouping by multiple Columns

    - by Christian
    I have a table with three filled columns named "Name", "City" and "Occupation". I want to create a new column in the same table that contains the number of people who have the same occupation. "Name" | "City" | "Occupation" ------------------------------ Amy | Berlin | Plumber Bob | Berlin | Plumber Carol | Berlin | Lawyer David | London | Plumber I want to have a table that contains: "Name" | "City" | "Occupation" | "Number" --------------------------------------- Amy | Berlin | Plumber | 2 Bob | Berlin | Plumber | 2 Carol | Berlin | Lawyer | 1 David | London | Plumber | 1 How does the SQL Query that creates the new columns have to look like? I want to actually create a new column in the database that I can access later.

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  • problems with mysql "or"

    - by Simon
    i have a problem with "and" "or" syntax!!! here is my query. . . SELECT `act1`.`name`, `act1`.`surname`, `act2`.`name`, `act2`.`surname`, `act3`.`name`, `act3`.`surname` FROM videos, actors AS act1, actors AS act2, actors AS act3 WHERE videos.ident = 'somethink' AND ( act1.id = videos.id_actor1 OR act2.id = videos.id_actor2 OR act3.id = videos.id_actor3 ) it returns me all variations of {name, surname}, but why!!! i want the name and surname of first axactly, second and thirth, if they exist!!! halp me please

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  • mySql table returning JSON that needs formatting for a iPhone UITableview

    - by Michael Robinson
    I have a php query the returns the following JSON format from a table. [{"memberid":"18", "useridFK":"30", "loginName":"Johnson", "name":"Frank", "age":"23", "place":"School", }, It needs the following format: [{"memberid":"18" { "useridFK":"30", "loginName":"Johnson", "name":"Frank", "age":"23", "place":"School",} }, I can figure out where/how to convert this, Where would I create the formatting following: (1) In the php return? (2) the JSON instructions for deserialization? or (3) Some kinb of Obj-C coding instruction? My end use is a simple Drill Down table using the NSObject, so when I select "memberid" row, I'll get the child/detail list on the next UITableview. My Data.plist will look like the following: Root: Dictionary V Rows: Array V Item 0: Dictionary Title: String 18 V Children Array V Item 0 Dictionary Title String 30 etc. Thanks in advance, this site rocks.

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  • Query Concatenated Field (using SubSonic)

    - by jwynveen
    Is there a way to query against a concatenated field using MS SQL? For instance, what I want to do is something like: Select FirstName+' '+LastName as FullName from Attendees where FullName like '%Joe Schmoe%' The above doesn't work. What I have found works is: Select * from Attendee where FirstName+' '+LastName like '%Joe Schmoe%' but I can't figure out how to do that using a SubSonic SqlQuery. I have a number of joins and OR statements added dynamically that I don't want to have to write out the sql manually. Any help/ideas?

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  • mySQL one-to-many query

    - by Stomped
    I've got 3 tables that are something like this (simplified here ofc): users user_id user_name info info_id user_id rate contacts contact_id user_id contact_data users has a one-to-one relationship with info, although info doesn't always have a related entry. users has a one-to-many relationship with contacts, although contacts doesn't always have related entries. I know I can grab the proper 'users' + 'info' with a left join, is there a way to get all the data I want at once? For example, one returned record might be: user_id: 5 user_name: tom info_id: 1 rate: 25.00 contact_id: 7 contact_data: 555-1212 contact_id: 8 contact_data: 555-1315 contact_id: 9 contact_data: 555-5511 Is this possible with a single query? Or must I use multiple?

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  • SQL Count Query with Grouping by multiple Rows

    - by Christian
    I have a table with three filled rows named "Name", "City" and "Occupation". I want to create a new row in the same table that contains the number of people who have the same occupation. "Name" | "City" | "Occupation" ------------------------------ Amy | Berlin | Plumber Bob | Berlin | Plumber Carol | Berlin | Lawyer David | London | Plumber I want to have a table that contains: "Name" | "City" | "Occupation" | "Number" --------------------------------------- Amy | Berlin | Plumber | 2 Bob | Berlin | Plumber | 2 Carol | Berlin | Lawyer | 1 David | London | Plumber | 1 How does the SQL Query that creates the new row have to look like? I want to actually create a new row in the database that I can access later.

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  • Query a range of date

    - by juniorSE
    Hello Guys, Im trying to query a sort of from - to date. e.g. 20-01-2010 to 20-02-2010. this should include the mentioned dates. i've tried the following queries but none works. select * from [tableName] where date = '20-01-2010' AND date <= '20-02-2010' the date where date is equal to 20-02-2010 does not show. i don't know why. select * from [tableName] where date between '20-01-2010' AND '20-02-2010' the mentioned dates is not included in the results. i want it to be included in the results. please help. thanks in advance! :)

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  • Update multiple rows with one query?

    - by kavoir.com
    I found something that works with updating one field at here: http://www.karlrixon.co.uk/articles/sql/update-multiple-rows-with-different-values-and-a-single-sql-query/ UPDATE person SET name = CASE id WHEN 1 THEN 'Jim' WHEN 2 THEN 'Mike' WHEN 3 THEN 'Precious' END WHERE id IN (1,2,3) My question is how to update more than one field? Such as: UPDATE person SET name = CASE, sex = CASE id WHEN 1 THEN 'Jim', 'female' WHEN 2 THEN 'Mike' 'male' WHEN 3 THEN 'Precious', 'male' END WHERE id IN (1,2,3) Which doesn't work of course. Tried a few other combination and failed. Any idea? Thanks!

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