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  • Find records produced in the last hour

    - by justSteve
    I have a smalldatetime field named myTime recording when the record was created. I need the syntax that selects records created within the last hour. thought it would be: and DATEDIFF("hh", datePart(hh, myTime), DatePart(hh, GETDATE()) < 1 where datediff 1) looks for hours; 2) looks at the hours portion of the data in myTime as starting; 3) looks at the hours portion of now for ending 3) produces an int that gets compared to '1' the results i'm getting are clearly way, way off base cuz umm...clearly...i don't know what i'm doing. help? thx

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  • Stopping users posting more than once

    - by user342391
    Before posting my form I am checking the database to see if there are any previous posts from the user. If there are previous posts then the script will kick back a message saying you have already posted. The problem is that what I am trying to achieve isn't working it all goes wrong after my else statement. It is also probable that there is an sql injection vulnerability too. Can you help??4 <?php include '../login/dbc.php'; page_protect(); $customerid = $_SESSION['user_id']; $checkid = "SELECT customerid FROM content WHERE customerid = $customerid"; if ($checkid = $customerid) {echo 'You cannot post any more entries, you have already created one';} else $sql="INSERT INTO content (customerid, weburl, title, description) VALUES ('$_POST[customerid]','$_POST[webaddress]','$_POST[pagetitle]','$_POST[pagedescription]')"; if (!mysql_query($sql)) { die('Error: ' . mysql_error()); } echo "1 record added"; ?>

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  • Next Identity Key LINQ + SQL Server

    - by user569347
    To represent our course tree structure in our Linq Dataclasses we have 2 columns that could potentially be the same as the PK. My problem is that if I want to Insert a new record and populate 2 other columns with the PK that was generated there is no way I can get the next identity and stop conflict with other administrators who might be doing the same insert at the same time. Case: A Leaf node has right_id and left_id = itself (prereq_id) **dbo.pre_req:** prereq_id left_id right_id op_id course_id is_head is_coreq is_enforced parent_course_id and I basically want to do this: pre_req rec = new pre_req { left_id = prereq_id, right_id = prereq_id, op_id = 3, course_id = query.course_id, is_head = true, is_coreq = false, parent_course_id = curCourse.course_id }; db.courses.InsertOnSubmit(rec); try { db.SubmitChanges(); } Any way to solve my dilemma? Thanks!

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  • Rails: validate presence of parent_id in has_many association

    - by deb
    I have a projects resource that has many tasks. I want to ensure that every task has a project_id by adding validates_presence_of :project_id to the tasks model. However, when creating a new project with tasks, the project_id won't be available until the record saves, therefore I can't use validates_presence_of :project_id. So my question is, how do I validate presence of project_id in the task model? I want to ensure every task has a parent. ... class Project < ActiveRecord::Base has_many :tasks, :dependent => :destroy accepts_nested_attributes_for :tasks, :allow_destroy => true ... class Task < ActiveRecord::Base belongs_to :project validates_presence_of :project_id

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  • Client to server data upload

    - by RickBowden
    I'm trying to design a system similar to the traditional server monitoring systems like MOM, Tivoli, Open View, where an agent will record data and then upload it to a central database once a day, but them also be able to send immediate alerts back to the server. I'm not sure what the best methodology might be for this. I've started looking at Microsoft sync services but I'm not sure if it will fit my needs. I'm using VS2008 and C#. Does anyone have any experience or ideas about how I should go about this task?

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  • SQL Server 2008 database timeout after delete

    - by stephenbayer
    I'm running the following statement, it is working locally with SQL Server 2008, however, there is SQL Server 2008 Express on the development server, and after the sql statement runs, I am unable to do SELECT statements on the table in which I deleted the record. Both databases were created with the same table creation scripts. "DELETE FROM [dbo].[tblMiddayMover] WITH (ROWLOCK) WHERE [idMiddayMover] = @IdMiddayMover" What reasons would this statement ever cause the database to hang. After executing that statement, the following SELECT statement causes an error. "SELECT * FROM [dbo].[tblMiddayMover] WHERE [fldActive] = 1" I get the following error: Timeout expired. The timeout period elapsed prior to completion of the operation or the server is not responding. I can do select statements on any other table with no issues.

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  • Handling missing data

    - by soppotare
    Say I have a simple helpdesk application which logs calls made by users. I would typically have such fields in a table relating to the call e.g. CallID, Description, CustomerID etc. I Would also have a table of customers including CustomerID, Username, Password, FullName etc. Now when a user is deleted from the customers table then the inner join between the calls table and the users table to find out historically which user logged a call would produce no results. How do people usually deal with this? Have seperate customer and useraccount tables Just disable the accounts so the data is still available Record the customers name in the calls table as a seperate field. or any other methods / suggestions?

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  • question abouut string sort

    - by davit-datuashvili
    i have question from programming pearls problem is following show how to use lomuto's partitioning scheme to sort varying length bit strings in time proportional to the sum oof their length and algorithm is following each record in x[0..n-1] has an integer length and pointer to the array bit[0..length-1] code void bsort(l,u,depth){ if (l>=u) return; for (int i=l;i<u;i++) if (x[i].length<depth) swap(i,l++); m=l; if (x[i].bit[depth] ==0) swap(i,m++); bsort(l,m-1,depth+1); bsort(m,u,depth+1); please help me i need following things 1. how this algorith works 2.how implement in java?

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  • how i insert values from list of Data Grid View,current time ,EmployeeID using button click event (C

    - by Six fourty
    hi, it show me this error Incorrect syntax near the keyword 'Select' to make to clear Employee ID in this case is FK in the table (Attendance detail) and the other thing is i am using Data Grid View from another table(Employee information) to Show the list of the staff in my form. then i want to transfer each selected cell value from Data Grid View to attendance detail table. 10q private void time_in_Click(object sender, EventArgs e) { employee_InformationDataGridView.SelectedCells[0].Style.ForeColor = Color.Green; time_in.Enabled = false; time_out.Enabled = true; con = new SqlConnection(GlobalClass.conn); con.Open(); SqlCommand cmd = new SqlCommand("Insert into Attendancedetail Values(" + "Select from EmployeeInformation(EmployeeID)" + ",'" + employee_InformationDataGridView.SelectedCells[0] + "','" + DateTime.Now.ToLongDateString() + "','" + null + "','" + null + "','" + DateTime.Now.ToLongTimeString() + "'," + null + ")", con); int i = cmd.ExecuteNonQuery(); MessageBox.Show(i.ToString() + " record inserted"); }

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  • Problem using Min(field)

    - by Todd
    have these two queries: SELECT classroomid AS crid, startdate AS msd FROM unitTemplates where classroomid = 6 GROUP BY classroomid and: SELECT classroomid AS crid, Min(startdate) AS msd FROM unitTemplates where classroomid = 6 GROUP BY classroomid The second query uses the minimum function. There is only one record in my table with a classroomid of 6. The first query returns msd = 20100505, the second query returns msd = 0 (instead of the expected 20100505). If I change the "Min" to "Max" it returns the highest (and only) startdate (20100505). Why doesn't MySQL like the Min function I'm using?

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  • How do stop form posting to mysql if database contains a specific ID?

    - by user342391
    I have a form that I am using to post data to mysql. Before submitting the form I want to check the database and see if there are any fields in the column 'customerid' that equal 'userid' and if so not to post the form. Basically, I am trying to limit my users from posting more than once. Users will be able to login to my system and make ONE post. They will be able to delete and modify their post but are only limited to one post. How would I do this??? Code so far: <?php include '../login/dbc.php'; page_protect(); $userid = $_SESSION['user_id']; $sql="INSERT INTO content (customerid, weburl, title, description) VALUES ('$_POST[userid]','$_POST[webaddress]','$_POST[pagetitle]','$_POST[pagedescription]')"; if (!mysql_query($sql)) { die('Error: ' . mysql_error()); } echo "1 record added"; ?>

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  • Encrypted ID in URLs

    - by Eric
    I am trying to hash or encrypt a record's ID for URL's such that people can't view various records simply by guessing different integer ID's. Essentially, my URL's would be something like this: /plans/0AUTxwoGkOYfiZGd2 instead of /plans/304. Would the best way to do this just be to use SHA-1 to hash the plan's id and store it in a hashed_id column for plans? Then, overwrite to_param and add a finder to find by hashed_id? How do you ensure that the characters generated are 0-9, a-z, or A-Z? Thanks!

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  • Duplicate / Copy records in the same MySQL table

    - by Digits
    I have been looking for a while now but I can not find an easy solution for my problem. I would like to duplicate a record in a table, but of course, the unique primary key needs to be updated. I have this query: INSERT INTO invoices SELECT * FROM invoices AS iv WHERE iv.ID=XXXXX ON DUPLICATE KEY UPDATE ID = (SELECT MAX(ID)+1 FROM invoices) the problem is that this just changes the ID of the row instead of copying the row. Does anybody know how to fix this ? Thank you verrry much, Digits //edit: I would like to do this without typing all the field names because the field names can change over time.

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  • How to select Distinct records from SQL without a primary key

    - by Satheesh
    I need to show a Notification on user login if there is any unread messages.So if multiple users send(5 messages each) while the user is in offline these messages should be shown on login.Means have to show the last messages from each user. I use joining to find records. In this scenario Message from User is not a primary key. This is my query SELECT UserMessageConversations.MessageFrom, UserMessageConversations.MessageFromUserName,UserMessages.MessageTo, UserMessageConversations.IsGroupChat, UserMessageConversations.IsLocationChat, UserMessageConversations.Message, UserMessages.UserGroupID,UserMessages.LocationID FROM UserMessageConversations LEFT OUTER JOIN UserMessages ON UserMessageConversations.UserMessageID = UserMessages.UserMessageID ![enter image description here][1]Where UserMessageConversations.MessageTo=743 AND UserMessageConversations.ReadFlag=0 This is the output obtained from above query. MessageFrom -582 appears twice. I need only one record of this User. How is it possible

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  • How to get the next element of a SortedSet?

    - by Pentium10
    I have a SortedSet holding my ordered data. I use the .first() method to return the first record, and pass it to another window. When the other window finishes I get an event called, and I want to pass the next from the SortedSet to the window, so how to move to the next element? launchWindow(this.set.first()); Then I have this: onActivityResult(...) { if (this.set.hasNext()) launchWindow(this.set.next());//hasNext/next doesn't exists in the current context for SortedSet } What options I have?

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  • Accessing data feed

    - by racket99
    I have a Java program on my desktop which displays financial data gleaned from the web. It is a 3rd party application. What I would like to do is intercept the data before it goes to the Java application and record it into a flat file for the purpose of later data analysis. Is this at all possible? I imagine the data are available and are entering my computer through some port which the Java app picks up and then displays. Help appreciated. Thanks

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  • Social statistics for a given page

    - by Trendee
    I have looked through the API's of facebook and twitter but i cannot seem to find the answer to my question. On websites like http://punchfork.com/recipe/Porkitos-Crispy-Prosciutto-Chips-Nom-Nom-Paleo On the right hand side they have the social stats page with information such as Tweets, Facebook Shares and Stumbleupons. My question is how do they record or gather these results? Is it a case of they have a button that records it in their database then sends you to the page to tweet/share/stumble? But surely that couldn't be accurate as people might not continue to fill out the action.

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  • Most efficient way to Update with Linq2Sql

    - by pranay
    can I update my employee record as given in below function or i have to make query of employee collection first and than i update data public int updateEmployee(App3_EMPLOYEE employee) { DBContextDataContext db = new DBContextDataContext(); db.App3_EMPLOYEEs.Attach(employee); db.SubmitChanges(); return employee.PKEY; } or i have to do this public int updateEmployee(App3_EMPLOYEE employee) { DBContextDataContext db = new DBContextDataContext(); App3_EMPLOYEE emp = db.App3_EMPLOYEEs.Single(e => e.PKEY == employee.PKEY); db.App3_EMPLOYEEs.Attach(employee,emp); db.SubmitChanges(); return employee.PKEY; } But i dont want to use second option is there any efficient way to update data

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  • how to get the second batch and 3rd batch in the same query result in oracle sql + yii framework?

    - by sasori
    let' say i have 20 results in the sql query. if am gonna use the limit in the yii active record, I'll obviously get the first four from the result, but what if i wanna get the 2nd four and then 3rd four in the same query result ? how to query that via sql ? e.g $criteria2 = new CDbCriteria(); $criteria2->select = 'USERID, ADID ,ADTYPE, ADTITLE, ADDESC, PAGEVIEW, DISPPUBLISHDATE'; $criteria2->addCondition("STATUS = 1"); $criteria2->order = '"t".PAGEVIEW DESC,"t".PUBLISHDATE DESC'; $criteria2->limit = 4; $criteria2->with = array('subcat','adimages'); $result = $this->findAll($criteria2); return $result;

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  • Running Test framework as part of application

    - by VP
    Hi, I would like to know if it is possible in rails to run some test cases through my application. I mean, i want show the test results to users. So i was thinking to be able to call my tests through a controller and put the tests output in a dialog. Imagine that i'm doing an application where before to apply a rule, i want to run some validation tests. I could write methods in my rule model to do it, but i would like to use something like shoulda or any other kind of DSL where the "fixture" would be a record itself. Any tip or idea?

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  • Duplicate records

    - by czuroski
    Hello, I am using nHibernate for db persistence. I have a one-to-many relationship defined between 2 tables. When I query and try to get data, I am getting the correct number of rows from the "many" table, but the rows are duplicates of the first row returned. table1 (one), table2 (many). I create a criteria query to get a certain record from table1. I then expect to get all associated records from table2. ie, table1 holds orders, table2 holds items. I query table1 to get an order which has 4 items. I expect to see each of those 4 items from table2, but all I am seeing is the 1st item repeated 4 times. Does anyone have any idea what might be happening?

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  • Asp.net static object behaviour

    - by Circadian
    I have the following class as part of an asp.net application. public sealed class SomeClass { private static string appId = Guid.NewGuid().ToString(); public static ReadSomethingFromDb(){} public static WriteSomethingToDb(){} } There are more than one application instances in the same application pool, and they all access the same database. I want the operations performed by the above class to be uniquely tied to the instance that performed it, hence the use of the appId. So adding a record to the database would for example contain a name, address and appId. This has been simplified for discussion purposes. Assuming that I have two instances running at mysite.a and mysite.b the above class would generate two different guids. My problem is that mysite.a sometimes produces more than one guid, which is unexpected. Thank you in advance

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  • servlet authentication and further reference to the credentials

    - by user553592
    What I got so far: It all begins with an HTML form which prompts the user for a username and password. From there it post the acquired user/pass to a servlet, GateKeeper. GateKeeper determines if the user/pass combination match any records in the MySQL database. Here is the sql I use: SELECT id FROM Users WHERE username='?' AND password=MD5('?') where the ? indicate information provided the previous HTML form. What I need now: I need some way to store the username and id of the record in the database. GateKeeper redirects the user to a control panel upon success. Therefore, I need a method to reference the username to display simple greetings, etc and also the id so it eliminates unnecessary calls to the database. The control panel may make AJAX calls to Servlets that preform some sort of task to the MySQL database.

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  • Creating a SQL lookup

    - by Scott
    I’m in the process of cleaning up a database table. Due to the way some of the data needed to be processed, now I need to go back and perform a “reverse lookup” on the data. For example, a field for one of the records is set to “car” and I need to set that record’s tranportmode field to “1” (for “car”). The lookup tables are already created. I just need to do the reverse lookup part. The cleansed tables will only have the numeric lookup value.

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  • Application start in global.asax

    - by Zerotoinfinite
    Hi experts, I am developing my application in asp.net 3.5 and sql server 2005, and I want to record the visitor info into my database, like once the visitor enter my website, I'll insert his browser details to the database. [It's not necessary that visitor login my website]. Now I am confused where to put my code, If I put insert function in every page_load then on every page it will execute and I'll not be able to get the exact number of visitor, visited my website. Shall I go with application_start in Global.asax ?? Please help.

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