Search Results

Search found 88594 results on 3544 pages for 'vc project file'.

Page 199/3544 | < Previous Page | 195 196 197 198 199 200 201 202 203 204 205 206  | Next Page >

  • having difficulties adding new xml to my project

    - by yoavstr
    when i open a new xxx.xml file it doesnt write to the R.id my new var example when i write in xml : <__Button android:text="New Game" android:id="@+id/newGameButton" android:layout_width="wrap_content" android:layout_height="wrap_content"</Button (the _ r from this web format boundaries ) in R it should write : public static final int newGameButton=0x7f050013; note : this is a xml i added as new to my project should i make something so the eclipse tool will write automatically to the R file?

    Read the article

  • please give me a solution

    - by user327832
    here is the code i have written so far but ended up giving me error import java.io.File; import java.io.FileInputStream; import java.io.IOException; import java.io.InputStream; public class Main { public static void main(String[] args) throws Exception { File file = new File("c:\\filea.txt"); InputStream is = new FileInputStream(file); long length = file.length(); System.out.println (length); bytes[] bytes = new bytes[(int) length]; try { int offset = 0; int numRead = 0; while (numRead >= 0) { numRead = is.read(bytes); } } catch (IOException e) { System.out.println ("Could not completely read file " + file.getName()); } is.close(); Object[] see = new Object[(int) length]; see[1] = bytes; System.out.println ((String[])see[1]); } }

    Read the article

  • Best practice- How to team-split a django project while still allowing code reusal

    - by Infinity
    I know this sounds kind of vague, but please let me explain- I'm starting work on a brand new project, it will have two main components: "ACME PRODUCT" (think Gmail, Meebo, etc), and "THE SITE" (help, information, marketing stuff, promotional landing pages, etc lots of marketing-induced cruft). So basically the url /acme/* will load stuff in the uber cool ajaxy application, and every other URI will load stuff in the other site. Problem: "THE SITE" component is out of my hands, and will be handled by a consultants team that will work closely with marketing, And I and my team will work solely on the ACME PRODUCT. Question: How to set up the django project in such a way that we can have: Seperate releases. (They can push new marketing pages and functionality without having to worry about the state of our code. Maybe even separate Subversion "projects") Minimize impact (on our product) of whatever flying-unicorns-hocus-pocus the other team codes into the site. Still allow some code reusal. My main concern is that the ACME product needs to be rock solid, and therefore needs to be somewhat isolated of whatever mistakes/code bloopers the consultants make in their marketing side of the site. How have you handled this? Any ideas? Thanks!

    Read the article

  • Maven (EJB) project with client and server artifacts

    - by Cornel Masson
    Here's my variation on the "multiple artifacts from Maven build" question: I'm porting from Ant to Maven. My application is an EJB server that is packaged as an EAR, but it also exposes a client JAR for use by other client apps. This jar contains the EJB interfaces, facade class and some helpers. I know that the Maven way is to have one artifact per project (POM); however, both artifacts (server EAR and client JAR) need to be built from the same source tree - server and client share, for example, the EJB and 'home' interfaces. How do I do this in Maven? Do I have one project containing two POMs, say server-pom.xml & client-pom.xml? I was thinking I could also have a parent POM (pom.xml) that can be used to build both client and server with one foul swoop? However, the lifecycles diverge after the 'package' phase, since the server has to go through assembly (tar/gzip), while the client is done after 'package' and can simply be installed into the repository. Any advice/experience on the best way to approach this?

    Read the article

  • PHP: Fastest way possible to read contents of a file.

    - by SoLoGHoST
    Ok, I'm looking for the fastest possible way to read all of the contents of a file via php with a filepath on the server, also these files can be huge. So it's very important that it does a READ ONLY to it as fast as possible. Is reading it line by line faster than reading the entire contents? Though, I remember reading up on this some, that reading the entire contents can produce errors for huge files. Is this true?

    Read the article

  • How to retrieve the XML file which is under the project folder

    - by Vara Prasad.M
    I having an XML file and that file is under the Documents folder. If I actually give the entire path in C# then I am able to retrieve the XML values, but if I give the project path then it is not getting the values. For example: string fileNamePath=ConfigurationManager.AppSettings["XMLDocPath"].ToString() + fileName; m_xmld.Load(fileNamePath); It is throwing a runtime error.

    Read the article

  • [NSData dataWithContentsOfFile:path] doesn't work

    - by Felics
    Hello, when I have the fallowing code to read a binary file: NSString* file = [NSString stringWithUTF8String:fileName]; NSString* filePath = resource ? [[NSBundle mainBundle] pathForResource:file ofType:nil] : [[NSSearchPathForDirectoriesInDomains(NSDocumentDirectory, NSUserDomainMask, YES) objectAtIndex:0] stringByAppendingPathComponent: file]; NSData* fileData = [NSData dataWithContentsOfFile:filePath]; Where "fileName" and resource are load function parameters. "resource" is used to know if the file is located in application bundle or in Documents. Sometimes this code works well and sometimes it doesn't. As far I saw this problem is random. I can run the code 10 times in a row and it works fine and after that it gives me nil data without any modification. Does anybody knows what could be the problem? Could it be related with file extension or file name? Thank you. PS: I use this code on iPhone Simulator and the file exists in application bundle.

    Read the article

  • Anyone know any good backend user online file manager?

    - by skyhigh
    Hi I'm looking for a backend system where your clients can login and upload files to your server, download files from the server and you can delete the users, create users, etc. I do not know the proper name for this kind of software. Maybe its called online file manager? Any recommendations? My server supports PHP, apache and mysq. Thanks

    Read the article

  • time on files differ by 1 sec. FAIL Robocopy sync

    - by csmba
    I am trying to use Robocopy to sync (/IMG) a folder on my PC and a shared network drive. The problem is that the file attributes differ by 1 sec on both locations (creation,modified and access). So every time I run robocopy, it syncs the file again... BTW, problem is the same if I delete the target file and robocopy it from new... still, new file has 1 sec different properties. Env Details: Source: Win 7 64 bit Target: WD My Book World Edition NAS 1TB which takes its time from online NTP pool.ntp.org (I don't know if file system is FAT or not)

    Read the article

  • Is there a way to efficiently yield every file in a directory containing millions of files?

    - by Josh Smeaton
    I'm aware of os.listdir, but as far as I can gather, that gets all the filenames in a directory into memory, and then returns the list. What I want, is a way to yield a filename, work on it, and then yield the next one, without reading them all into memory. Is there any way to do this? I worry about the case where filenames change, new files are added, and files are deleted using such a method. Some iterators prevent you from modifying the collection during iteration, essentially by taking a snapshot of the state of the collection at the beginning, and comparing that state on each move operation. If there is an iterator capable of yielding filenames from a path, does it raise an error if there are filesystem changes (add, remove, rename files within the iterated directory) which modify the collection? There could potentially be a few cases that could cause the iterator to fail, and it all depends on how the iterator maintains state. Using S.Lotts example: filea.txt fileb.txt filec.txt Iterator yields filea.txt. During processing, filea.txt is renamed to filey.txt and fileb.txt is renamed to filez.txt. When the iterator attempts to get the next file, if it were to use the filename filea.txt to find it's current position in order to find the next file and filea.txt is not there, what would happen? It may not be able to recover it's position in the collection. Similarly, if the iterator were to fetch fileb.txt when yielding filea.txt, it could look up the position of fileb.txt, fail, and produce an error. If the iterator instead was able to somehow maintain an index dir.get_file(0), then maintaining positional state would not be affected, but some files could be missed, as their indexes could be moved to an index 'behind' the iterator. This is all theoretical of course, since there appears to be no built-in (python) way of iterating over the files in a directory. There are some great answers below, however, that solve the problem by using queues and notifications. Edit: The OS of concern is Redhat. My use case is this: Process A is continuously writing files to a storage location. Process B (the one I'm writing), will be iterating over these files, doing some processing based on the filename, and moving the files to another location. Edit: Definition of valid: Adjective 1. Well grounded or justifiable, pertinent. (Sorry S.Lott, I couldn't resist). I've edited the paragraph in question above.

    Read the article

  • How to launch a .bat file in a C# windows Service project

    - by freedark
    I create a C# Windows servive project, then I want to run a .bat file, but I find that it does not run Process pInfo = new Process(); pInfo.StartInfo.UseShellExecute=false; pInfo.StartInfo.CreateNoWindow=true; pInfo.StartInfo.FileName =bat file name ; pInfo.StartInfo.RedirectStandardOutput = true; pInfo.Start(); Could anyone help me ?

    Read the article

  • Referencing java resource files for cold fusion

    - by Chimeara
    I am using a .Jar file containing a .properties file in my CF code, however it seems unable to find the .properties file when run from CF. My java code is: String key =""; String value =""; try { File file = new File("src/test.properties"); FileInputStream fileInput = new FileInputStream(file); Properties properties = new Properties(); properties.load(fileInput); fileInput.close(); Enumeration enuKeys = properties.keys(); while (enuKeys.hasMoreElements()) { key = (String) enuKeys.nextElement(); value = properties.getProperty(key); //System.out.println(key + ": " + value); } } catch (FileNotFoundException e) { e.printStackTrace(); key ="error"; } catch (IOException e) { e.printStackTrace(); key ="error"; } return(key + ": " + value); I have my test.properties file in the project src folder, and make sure it is selected when compiling, when run from eclipse it gives the expected key and value, however when run from CF I get the caught errors. My CF code is simply: propTest = CreateObject("java","package.class"); testResults = propTest.main2(); Is there a special way to reference the .properties file so CF can access it, or do I need to include the file outside the .jar somewhere?

    Read the article

  • aapt.exe has stopped working and R.java cannot be resolved after adding Google Play Services library to an existing project

    - by Kapil Kapri
    I'm trying to add new google-play-services_lib in my old project, due to which R.jave file is removed from the project. Also, as soon as i remove google-play-services_lib, i get my R.java file back. minimum sdk version is 11. I'm referring to following link: https://developer.android.com/google/play-services/setup.html I am following these steps to add library as a project == Right-click on My project - Properties In Android-Library section click Add select recently added project - Ok then aapt.exe has stopped working and R.jave file is removed from the project

    Read the article

  • Need to have JProgress bar to measure progress when copying directories and files

    - by user1815823
    I have the below code to copy directories and files but not sure where to measure the progress. Can someone help as to where can I measure how much has been copied and show it in the JProgress bar public static void copy(File src, File dest) throws IOException{ if(src.isDirectory()){ if(!dest.exists()){ //checking whether destination directory exisits dest.mkdir(); System.out.println("Directory copied from " + src + " to " + dest); } String files[] = src.list(); for (String file : files) { File srcFile = new File(src, file); File destFile = new File(dest, file); copyFolder(srcFile,destFile); } }else{ InputStream in = new FileInputStream(src); OutputStream out = new FileOutputStream(dest); byte[] buffer = new byte[1024]; int length; while ((length = in.read(buffer)) > 0){ out.write(buffer, 0, length); } in.close(); out.close(); System.out.println("File copied from " + src + " to " + dest); }

    Read the article

  • Best way and problems when using ajax tabs with an MVC PHP project

    - by Jonathan
    Hi, I'm building an IMDB.com like website using PHP/jQuery and a MVC approach (no OOP). I have an index.php base controller to 'rule them all' :), a controllers folder with all the controllers, a models folder and a view folder. In some pages of the website I have tabbed navigation, when the visitor clicks on one of those tabs to get more information, jQuery gets that data using the $.post or $.get method and shows it on the tab container, obviously without refreshing the page. The problem is that those pages loaded by ajax are also generated using controllers, models, and views, and the things are getting a bit complicated for someone like me ( = 'no experience'). To dynamically get the data I some times need to include a model twice, include an include in an include in an include, send information multiple times, connect with the database again, and all sort of things like that and I'm sure there is a better and prettier way to do this. I'm searching for the best approach and common methods for this. I have no experience working with a big project like this. This is a personal project so I have full control and every answer is welcome. Thanks!!!

    Read the article

  • [Python] How to create a named temporary file in memory?

    - by conradlee
    I would like to use Python's tempfile module to create a temporary file that I will use for communication between processes (use of pipes is awkward). The documentation I've linked to above shows two functions that almost do what I want: tempfile.NamedTemporaryFile # For creating named tempfiles tempfile.SpooledTemporaryFile # For creating tempfiles in memory but actually I want a tempfile that is both named AND in memory. Any ideas?

    Read the article

  • Beginner servlet question: accessing files in a .war, which path?

    - by Navigateur
    When a third-party library I'm using tries to access a file, I'm getting "Error opening ... file ... (No such file or directory)" even though I KNOW the file is in the WAR. I've tried both packaged (.war) and "exploded" (directory) deployment, and the file is definitely there. I've tried setting full permissions on it too. It's on Unix (Ubuntu). File is war/dict/index.sense and the error is "dict/index.sense (No such file or directory)". It works fine on my Windows computer when running in hosted mode as a GWT app from Eclipse, just not when I transfer it to the Unix machine for deployment. My question is: has anybody experienced this before and/or are there differences in relative path that I should consider i.e. what's the root path for relative file access in a war?

    Read the article

  • Can I use php's fwrite with 644 file permissions?

    - by filip
    I am trying to set up automated .htaccess updating. This clearly needs to be as secure as possible, however right now the best I can do file permission-wise is 666. What can I do to setup either my server or php code so that my script's fwrite() command will work with 644 or better? For instance is there a way to set my script(s) to run as owner?

    Read the article

< Previous Page | 195 196 197 198 199 200 201 202 203 204 205 206  | Next Page >