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  • Access VBA sub with form as parameter doesn't alter the form

    - by Ski
    I have a Microsoft Access 2003 file with various tables of data. Each table also has a duplicate of it, with the name '[original table name]_working'. Depending on the user's choices in the switchboard, the form the user choose to view must switch its recordsource table to the working table. I refactored the relevant code to do such a thing into the following function today: Public Sub SetFormToWorking(ByRef frm As Form) With frm .RecordSource = rst![Argument] & "_working" .Requery Dim itm As Variant For Each itm In .Controls If TypeOf itm Is subForm Then With Item Dim childFields As Variant, masterFields As Variant childFields = .LinkChildFields masterFields = .LinkMasterFields .Form.RecordSource = .Form.RecordSource & "_working" .LinkChildFields = childFields .LinkMasterFields = masterFields .Form.Requery End With End If Next End With End Sub The lines of code that call the function look like this: SetFormToWorking Forms(rst![Argument]) and SetFormToWorking Forms(cmbTblList) For some reason, the above function doesn't change the recordsource for the form. I added the 'ByRef' keyword to the parameter just to be certain that it was passing by reference, but no dice. Hopefully someone here can tell me what I've done wrong?

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  • Submit Form Equivalent To WML

    - by Nathan Campos
    I'm playing a little bit with WML with PHP, then I want to know what is the equivalent of this on WML: <form action="upload_file.php" method="post"enctype="multipart/form-data"> <label for="file">File:</label><br /> <input type="file" name="file" id="file" /><br /> <input type="submit" name="submit" value="Submit" /> </form>

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  • how to check if the enddate is after the startdate in a zend form

    - by murze
    I have a zend form with a start- and an endate. $form = new Zend_Form(); $form->setName($this->formName) ->setMethod('post'); $feStartdate = new Zend_Form_Element_Text('startdate'); $feEnddate = new Zend_Form_Element_Text('enddate'); $form->addElement($feStartDate) ->addElement($feEndDate) ->addElement('submit', 'submit', array('label' => 'Save')); I assume I must write a custom validator for to check this. How would this custom validator look like and how can I call it? I assume something like $feEnddate->addValidator('dateComesAfter', $feStartDate)

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  • Zend_Form : Adding fields in sub-forms on user's click

    - by anu iyer
    I'm having a zend form - comprised of a number of zend - sub forms, where the user is creating a new question (its a content management system). In one of the subforms, the user can click on a button to add more textfields, like this: [----------] [----------] [click to add more] which should give [----------] [----------] [----------] [click to add more] I'm trying to set a flag in the sub form in question - or set a count on how many times the button has been clicked, to add that many total fields to the subform - but its simply not working. I tried using a static count variable - but the value doesnt get incremented at all. Any thoughts on how to do this in a Zend-subform within a zend form? I'll definitely update if I hit a solution. Thanks!

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  • Form Validation Options

    The steps involved in transmitting form data from the client to the Web server User loads web form. User enters data in to web form fields User clicks submit On submit page validates fields using JavaScript. If validation errors are found then the validation script stops the browser from canceling posting the data to the web server and displays error messages as needed. If the form passes the data validation process then the browser will URL encode the values of every field and post it to the server.  The server reads the posted data from the query string and then again validates the data just to ensure data consistency and to prevent any non-validated data because JavaScript was turned off on the clients browser from being inserted in to a database or passed on to other process. If the data passes the second validation check then the server side code will continue with the requested processes. In my opinion, it is mandatory to validate data using client side and server side validation as a fail over process. The client side validation allows users to correct any error before they are sent to the web server for processing, and this allows for an immediate response back to the user regarding data that is not correct or in the proper format that is desired. In addition, this prevents unnecessary interaction between the user and the web server and will free up the server over time compared to doing only server side validation. Server validation is the last line of defense when it comes to validation because you can check to ensure the user’s data is correct before it is used in a business process or stored to a database. Honestly, I cannot foresee a scenario where I would only want to use one form of validation over another especially with the current cost of creating and maintaining data. In my opinion, the redundant validation is well worth the overhead.

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  • Bypass django form validation on new form instance

    - by Thomas Schultz
    Hello! I have a situation where we are trying to autofill some form data on the second page of a signup and I was wondering if there's a way to bypass the entire form validation when we pass in only a couple of fields? so we have something like form = NewForm(request.POST) Where request.POST only contains some of the fields in NewForm(). So the page loads and there is feedback about how some fields are not filled in yet. This all happens from the GET request of the second page. Is there a way to do something like... form = NewForm(request.POST, validate=False)

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  • how to submit a form without loosing values already selected at the same form

    - by kawtousse
    Hi everyone, I am using jstl with dropdown lists. When i click submit button i success the specification but values int dropdownlists are reinitialized. So I want to submit form without loosing the values already selected in the form because I need to stay always at the same level in the form.To be more clear, user choose a value from ddl and click edit button to show other options and fill them at the same form without loosing what he has selected. I have tried to deal like that: but it doesn't work. think you for your help.

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  • Passing variables to a Custom Zend Form Element

    - by user322003
    Hi, I'm trying to create a custom form element which extends Zend_Form_Element_Text with a validator (so I don't have to keep setting up the validator when I use certain elements). Anyway, I'm having trouble passing $maxChars variable to it when I instantiate it in my Main form. I've provided my shortened code below This is my custom element below class My_Form_Custom_Element extends Zend_Form_Element_Text { public $maxChars public function init() { $this->addValidator('StringLength', true, array(0, $this->maxChars)) } public function setProperties($maxChars) { $this->maxChars= $maxChars; } } This is where I instantiate my custom form element. class My_Form_Abc extends Zend_Form { public function __construct($options = null) { parent::__construct($options); $this->setName('abc'); $customElement = new My_Form_Custom_Element('myCustomElement'); $customElement->setProperties(100); //**<----This is where i set the $maxChars** $submit = new Zend_Form_Element_Submit('submit'); $submit -> setAttrib('id', 'submitbutton'); $this->addElements(array($customElement ,$submit)); } } When I try to pass '100' using $customElement-setProperties(100) in my Form, it doesnt get passed properly to my StringLength validator. I assume it's because the validator is getting called in Init? How can I fix this?

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  • Display small form while main form is "locked"

    - by daemonsvk
    Hi there, i'm thinking about writing a WPF program that would require login and password at the app startup. I thought about small form with two textboxes as a login form. User will have to fill in his details and then the main form of the application will be unlocked. How will you solve this? Thanks for your answers, daemonsvk

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  • Creating form object for variable kind of form.

    - by Bunny Rabbit
    i want to create a form for users to submit questions in django ..so far the models i have created are class Question(models.Model): statement=models.CharField(max_length=100) class Choice(models.Model): statement=models.CharField(max_length=100) value=models.IntegerField() question=models.ForeignKey(Question) Now i want to write a Form class for creating a above form but the problem is the number of choices are variable,a user can decide how many choices a question must have .How do i do that in django?

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  • Handling form from different view and passing form validation through session in django

    - by Mo J. Mughrabi
    I have a requirement here to build a comment-like app in my django project, the app has a view to receive a submitted form process it and return the errors to where ever it came from. I finally managed to get it to work, but I have doubt for the way am using it might be wrong since am passing the entire validated form in the session. below is the code comment/templatetags/comment.py @register.inclusion_tag('comment/form.html', takes_context=True) def comment_form(context, model, object_id, next): """ comment_form() is responsible for rendering the comment form """ # clear sessions from variable incase it was found content_type = ContentType.objects.get_for_model(model) try: request = context['request'] if request.session.get('comment_form', False): form = CommentForm(request.session['comment_form']) form.fields['content_type'].initial = 15 form.fields['object_id'].initial = 2 form.fields['next'].initial = next else: form = CommentForm(initial={ 'content_type' : content_type.id, 'object_id' : object_id, 'next' : next }) except Exception as e: logging.error(str(e)) form = None return { 'form' : form } comment/view.py def save_comment(request): """ save_comment: """ if request.method == 'POST': # clear sessions from variable incase it was found if request.session.get('comment_form', False): del request.session['comment_form'] form = CommentForm(request.POST) if form.is_valid(): obj = form.save(commit=False) if request.user.is_authenticated(): obj.created_by = request.user obj.save() messages.info(request, _('Your comment has been posted.')) return redirect(form.data.get('next')) else: request.session['comment_form'] = request.POST return redirect(form.data.get('next')) else: raise Http404 the usage is by loading the template tag and firing {% comment_form article article.id article.get_absolute_url %} my doubt is if am doing the correct approach or not by passing the validated form to the session. Would that be a problem? security risk? performance issues? Please advise Update In response to Pol question. The reason why I went with this approach is because comment form is handled in a separate app. In my scenario, I render objects such as article and all I do is invoke the templatetag to render the form. What would be an alternative approach for my case? You also shared with me the django comment app, which am aware of but the client am working with requires a lot of complex work to be done in the comment app thats why am working on a new one.

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  • Do You Want "Normal?" Good luck!

    - by divya.malik
    By Steve Diamond Much has been written about "The New Normal." One thing is for sure: whatever THAT is, economically speaking we won't be experiencing it anytime soon. Sure, we're well beyond the "no floor" perception of 18 months ago--which is certainly comforting, but ask any senior executive and they'll tell you of the constant rigor necessary to continually adapt to an ever-changing macro environment. This brings me to a suggestion that you tune in to a Deloitte Webinar titled, "The New Normal: Embrace Complexity or Seek to Simplify." It features the perspectives on this very topic of Jessica Blume, a principal at Deloitte; and Kirk Mosher, VP of CRM Marketing at Oracle.

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  • Do You Want "Normal?" Good luck!

    - by steve.diamond
    Much has been written about "The New Normal." One thing is for sure: whatever THAT is, economically speaking we won't be experiencing it anytime soon. Sure, we're well beyond the "no floor" perception of 18 months ago--which is certainly comforting, but ask any senior executive and they'll tell you of the constant rigor necessary to continually adapt to an ever-changing macro environment. This brings me to a suggestion that you tune in to a Deloitte Webinar titled, "The New Normal: Embrace Complexity or Seek to Simplify." It features the perspectives on this very topic of Jessica Blume, a principal at Deloitte; and Kirk Mosher, VP of CRM Marketing at Oracle.

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  • CSS Hidden DIV Form Submit

    - by Michael
    Using CSS, when a link is clicked it brings up a hidden DIV that contains a form. The user will then enter information and then submit the form. I'd like the hidden DIV to remain visisble, and a 'success message' to be displayed after submission. Then the user will have the option of closing the DIV. I can't get it to work without reloading the page, which causes the DIV to become hidden again. Any ideas? <body> <a href="javascript:showDiv()" style="color: #fff;">Click Me</a> <!--POPUP--> <div id="hideshow" style="visibility:hidden;"> <div id="fade"></div> <div class="popup_block"> <div class="popup"> <a href="javascript:hideDiv()"> <img src="images/icon_close.png" class="cntrl" title="Close" /> </a> <h3>Remove Camper</h3> <form method="post" onsubmit="email.php"> <p><input name="Name" type="text" /></p> <p><input name="Submit" type="submit" value="submit" /></p> </form> <div id="status" style="display:none;">success</div> </div> </div> </div> <!--END POPUP--> <script language=javascript type='text/javascript'> function hideDiv() { if (document.getElementById) { // DOM3 = IE5, NS6 document.getElementById('hideshow').style.visibility = 'hidden'; } else { if (document.layers) { // Netscape 4 document.hideshow.visibility = 'hidden'; } else { // IE 4 document.all.hideshow.style.visibility = 'hidden'; } } } function showDiv() { if (document.getElementById) { // DOM3 = IE5, NS6 document.getElementById('hideshow').style.visibility = 'visible'; } else { if (document.layers) { // Netscape 4 document.hideshow.visibility = 'visible'; } else { // IE 4 document.all.hideshow.style.visibility = 'visible'; } } } </script> </body>

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  • Form graphics not set when form loads

    - by Jimmy
    My form has a group box which contains two overlapping rectangles. The form's other controls are two sets of four numeric up down controls to set the rectangles' colors. (nudF1,2,3 and 4 set the rectangle that's in front, and nudB1,2,3 and 4 set the rectangle that's behind.) Everything works fine, except that the rectangles do not display the colors set in the numeric up downs when the form first loads. The numeric up down controls' ChangeValue events all call the ShowColors() method. The form's Load event calls the csColorsForm_Load() method. Any suggestions? namespace csColors { public partial class csColorsForm : Form { public csColorsForm() { InitializeComponent(); } private void csColorsForm_Load(object sender, EventArgs e) { this.BackColor = System.Drawing.Color.DarkBlue; SetColors(sender, e); } private void SetColors(object sender, EventArgs e) { Control control = (Control)sender; String ctrlName = control.Name; Graphics objGraphics; Rectangle rect1, rect2; int colorBack, colorFore; objGraphics = this.grpColor.CreateGraphics(); // If calling control is not a forecolor control, paint backcolor rectangle if (ctrlName.Substring(0,4)!="nudF") { colorBack = int.Parse(SetColorsB("nudB"), NumberStyles.HexNumber); SolidBrush BrushB = new SolidBrush(Color.FromArgb(colorBack)); rect1 = new Rectangle(this.grpColor.Left, this.grpColor.Top, this.grpColor.Width, this.grpColor.Height); objGraphics.FillRectangle(BrushB, rect1); } // Always paint forecolor rectangle colorFore = int.Parse(SetColorsB("nudF"), NumberStyles.HexNumber); SolidBrush BrushF = new SolidBrush(Color.FromArgb(colorFore)); rect2 = new Rectangle(this.grpColor.Left, this.grpColor.Top, this.grpColor.Width, this.grpColor.Height); objGraphics.FillRectangle(BrushF, rect2); objGraphics.Dispose(); } private string SetColorsB(string nam) { string txt=""; for (int n = 1; n <= 4; ++n) { var ud = Controls[nam + n] as NumericUpDown; int hex = (int)ud.Value; txt += hex.ToString("X2"); } return txt; } private void btnClose_Click(object sender, EventArgs e) { this.Close(); } } }

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  • Problem retrieving values from Zend_Form_SubForms - no values returned

    - by anu iyer
    I have a Zend_Form that has 4 or more subforms. /** Code Snippet **/ $bigForm = new Zend_Form(); $littleForm1 = new Form_LittleForm1(); $littleForm1->setMethod('post'); $littleForm2 = new Form_LittleForm2(); $littleForm2->setMethod('post'); $bigForm->addSubForm($littleForm1,'littleForm1',0); $bigForm->addSubForm($littleForm2,'littleForm2',0); On clicking the 'submit' button, I'm trying to print out the values entered into the forms, like so: /** Code snippet, currently not validating, just printing **/ if($this-_request-getPost()){ $formData = array(); foreach($bigForm->getSubForms() as $subForm){ $formData = array_merge($formData, $subForm->getValues()); } /* Testing */ echo "<pre>"; print_r($formData); echo "</pre>"; } The end result is that - all the elements in the form do get printed, but the values entered before posting the form don't get printed. Any thoughts are appreciated...I have run around circles working on this! Thanks in advance!

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  • adding Form Validation Javacript of jquery???

    - by user634599
    How can I add inline Validation to make sure a choice of radio input must be selected <script type="text/javascript"> function choosePage() { if(document.getElementById('weightloss').form1_option1.checked) { window.location.replace( "http://google.com/" ); } if(document.getElementById('weightloss').form1_option2.checked) { window.location.replace( "http://yahoo.com/" ); } } </script> <form id="weightloss"> <input type="radio" id="form1_option1" name="weight-loss" value="5_day" class="plan"> <label for="form1_option1"> 5 Day - All Inclusive Price</label><br> <input type="radio" id="form1_option2" name="weight-loss" value="7_day"> <label for="form1_option2"> 7 Day - All Inclusive Price</label><br> <input type="button" value="Place Order" alt="Submit button" class="orange_btn" onclick="choosePage()"> </form>

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  • HTML Form Upload PDF with other form contents using PHP

    - by Sev
    I have a HTML form with fields such as name, address, notes, etc. I also have a field to upload a PDF. The uploaded PDF get's stored on the file system. How can I accomplish this if possibly the PDF files are larger than 2 MBs? Also, for some reason, the uploading of the PDF (< 2 MBs) works fine in Chrome, but not in IE. In IE, the upload doesn't even begin, but in Chrome, it completes fine. Form header looks like: method='post' ENCTYPE='multipart/formdata' edit: the ini setting didn't help The HTML <input type='text' name='user' /> <input type='file' name='userfile' /> The basic PHP ( I do some preg matching above, that I haven't included) $uploaddir = 'uploads/'; $uploadfile = $uploaddir . basename($_FILES['userfile']['name']); if (move_uploaded_file($_FILES['userfile']['tmp_name'], $uploadfile)) { echo "File is valid, and was successfully uploaded.\n"; } else { echo "File uploading failed.\n"; }

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  • Spring Framework 3 and session attributes

    - by newbie
    I have form object that I set to request in GET request handler in my Spring controller. First time user enters to page, a new form object should be made and set to request. If user sends form, then form object is populated from request and now form object has all user givern attributes. Then form is validated and if validation is ok, then form is saved to database. If form is not validated, I want to save form object to session and then redirect to GET request handling page. When request is redirected to GET handler, then it should check if session contains form object. I have figured out that there is @SessionAttributes("form") annotation in Spring, but for some reason following doesnt work, because at first time, session attribute form is null and it gives error: org.springframework.web.HttpSessionRequiredException: Session attribute 'form' required - not found in session Here is my controller: @RequestMapping(value="form", method=RequestMethod.GET) public ModelAndView viewForm(@ModelAttribute("form") Form form) { ModelAndView mav = new ModelAndView("form"); if(form == null) form = new Form(); mav.addObject("form", form); return mav; } @RequestMapping(value="form", method=RequestMethod.POST) @Transactional(readOnly = true) public ModelAndView saveForm(@ModelAttribute("form") Form form) { FormUtils.populate(form, request); if(form.validate()) { formDao.save(); } else { return viewForm(form); } return null; }

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