Search Results

Search found 37 results on 2 pages for 'hammad khalid'.

Page 2/2 | < Previous Page | 1 2 

  • Calling different layers from the same class

    - by khalid
    Hi, I am here to seek some help with my code which i am facing a dead end road with. I'm trying to pass values from screen1.java using Intent to screen2.java. Passing the values is fine and I managed to get through it; however, when I check using if statement the program crash down. Here are my files, plzzzzzzzzzzz help screen1.java package test.android; import android.app.Activity; import android.content.Intent; import android.os.Bundle; import android.view.View; import android.widget.Button; public class screen1 extends Activity { static String strKey = "Hello"; static final String strValue = "Hello"; public void onCreate(Bundle icicle) { super.onCreate(icicle); setContentView(R.layout.screen1); //** button A Button A = (Button) findViewById(R.id.btnClickA); A.setOnClickListener(new View.OnClickListener() { public void onClick(View arg0) { Intent i = new Intent(screen1.this, screen2.class); strKey = "NAME"; i.setClassName("packageName", "packageName.IntentClass"); String term = "Hello"; i.putExtra("packageName.term", term); //i.putExtra(strKey, strValue); startActivity(i); } }); //** //** button B Button B = (Button) findViewById(R.id.btnClickB); B.setOnClickListener(new View.OnClickListener() { public void onClick(View arg0) { Intent i = new Intent(screen1.this, screen3.class); startActivity(i); } }); //** } } screen2.java package test.android; import android.app.Activity; import android.os.Bundle; import android.view.View; import android.widget.Button; public class screen2 extends Activity { public void onCreate(Bundle icicle) { Bundle extras = getIntent().getExtras(); String term = extras.getString("packageName.term"); System.out.println("--- Name is -->"+ term); if(term.equalsIgnoreCase("Hello") || term.equalsIgnoreCase("Name")){ super.onCreate(icicle); setContentView(R.layout.screen3); Button b = (Button) findViewById(R.id.btnClick3); b.setOnClickListener(new View.OnClickListener() { public void onClick(View arg0) { setResult(RESULT_OK); finish(); } }); } else { super.onCreate(icicle); setContentView(R.layout.screen2); Button b = (Button) findViewById(R.id.btnClick2); b.setOnClickListener(new View.OnClickListener() { public void onClick(View arg0) { setResult(RESULT_OK); finish(); } }); } // DOES NOT WORK !!!!!!!!! System.out.println("--- Name is --"+ term); } } Layouts: screen1.xml screen2.xml screen3.xml AndroidManifest.xml <activity android:name="screen1" android:label="SCREEN 1"> <intent-filter> <action android:name="android.intent.action.MAIN" /> <category android:name="android.intent.category.LAUNCHER" /> </intent-filter> </activity> <activity android:name="screen2" android:label="SCREEN 2"> </activity> <activity android:name="screen3" android:label="SCREEN 3"> </activity> ===== The error is caused by these lines of code in screen2.java: if(term.equalsIgnoreCase("Hello") || term.equalsIgnoreCase("Name")){ super.onCreate(icicle); setContentView(R.layout.screen3); Button b = (Button) findViewById(R.id.btnClick3); b.setOnClickListener(new View.OnClickListener() { public void onClick(View arg0) { setResult(RESULT_OK); finish(); } }); } else { super.onCreate(icicle); setContentView(R.layout.screen2); Button b = (Button) findViewById(R.id.btnClick2); b.setOnClickListener(new View.OnClickListener() { public void onClick(View arg0) { setResult(RESULT_OK); finish(); } }); } **notice if I get rid of the entire IF statement and go with only the ELSE the program works fine.

    Read the article

  • use Jquery load to load content in adiv?

    - by Khalid Omar
    simply i'm doing a test i have a div called test and mvc action in the client controler the view and the controler public string testout() { return DateTime.Now.ToString(); } and i'm using jquery to update the div $("#B1").live("click", function() { $("#test").load("/client/testout"); return false; }); first time a click the bottun i see the date and time in the div test second time i click the botton nothing changed

    Read the article

  • NHibernate IQueryable Collection as Property of Root

    - by Khalid Abuhakmeh
    Hello and thank you for taking the time to read this. I have a root object that has a property that is a collection. For example : I have a Shelf object that has Books. // now public class Shelf { public ICollection<Book> Books {get; set;} } // want public class Shelf { public IQueryable<Book> Books {get;set;} } What I want to accomplish is to return a collection that is IQueryable so that I can run paging and filtering off of the collection directly from the the parent. var shelf = shelfRepository.Get(1); var filtered = from book in shelf.Books where book.Name == "The Great Gatsby" select book; I want to have that query executed specifically by NHibernate and not a get all to load a whole collection and then parse it in memory (which is what currently happens when I use ICollection). The reasoning behind this is that my collection could be huge, tens of thousands of records, and a get all query could bash my database. I would like to do this implicitly so that when NHibernate sees and IQueryable on my class it knows what to do. I have looked at NHibernates Linq provider and currently I am making the decision to take large collections and split them into their own repository so that I can make explicit calls for filtering and paging. Linq To SQL offers something similar to what I'm talking about.

    Read the article

  • Is it possible to declare multiple static variable with same name in a single C file?

    - by Mohammed Khalid Kherani
    Hi Experts, Is it possible to declare multiple static variables of same name in a single C file with different scopes? I wrote a simple programme to check this and in gcc it got compiled and worked fine. code: static int sVar = 44; void myPrint2() { printf("sVar = %d\n", sVar++); } void myPrint() { static int sVar =88; printf("sVar = %d\n", sVar++); } int main(void) { static int sVar = 55; int i = 0; for (i = 0; i < 5; i++) myPrint(); printf("sVar = %d\n", sVar); myPrint2(); return(0); } Now my question is since all "static" variable will reside in same section (.data) then how we can have multiple variable with same name in one section? I used objdump to check the different section and found that all Static variables (sVar) were in .data section but with different names 0804960c l O .data 00000004 sVar 08049610 l O .data 00000004 sVar.1785 08049614 l O .data 00000004 sVar.1792 Why compiler is changing the name of variables (since C doesnt support name mangling)? Thanks in advance.

    Read the article

  • Radiobuttonlist and load page in same initial position

    - by Khalid
    Hi I have this simple code in my page, I have a long page, if the client use this button then it shall reload the page and display the page from the beginning. I wish to be reload the page and display from the last position. <asp:RadioButtonList ID="RadioButtonList5" runat="server" AutoPostBack="True" RepeatDirection="Horizontal"> <asp:ListItem Value="45">Sheet2</asp:ListItem> </asp:RadioButtonList> Any advice, apprciated. Thank you.

    Read the article

  • Salon du E-commerce et Social CRM B2B

    - by Valérie De Montvallon
    Nous participions au Salon du E-commerce et Social CRM B2B en septembre dernier et nous vous proposons la vidéo réalisée par Les décideurs de la relation client. Découvrez des avis d'experts de la Relation Client pour en savoir toujours plus sur le Social CRM BtoB. Pour le BtoB, la gestion de la Relation Client semble bien simple quand il s’agit de récolter des informations à partir d’appels téléphoniques, d’entretiens physiques ou d’emails. Toutefois, la tâche s’enhardit sur les réseaux sociaux. Ces plateformes sont-elles réellement adaptées au BtoB ? Comment procéder quand on se lance ? Quels sont les pièges à éviter ? Quels sont les éléments qui laissent à penser que le Social CRM BtoB est une vraie tendance de la Relation Client ? Autant de questions auxquelles les experts rencontrés ont apporté des éléments de réponse. Vous découvrirez l'interview de notre expert, Khalid Madarbokus, qui s'exprime sur la remontée d'informations depuis les médias sociaux au sein des départements d'une entreprise B2B (à 3:20)

    Read the article

  • Manage SQL Server Connectivity through Windows Azure Virtual Machines Remote PowerShell

    - by SQLOS Team
    Manage SQL Server Connectivity through Windows Azure Virtual Machines Remote PowerShell Blog This blog post comes from Khalid Mouss, Senior Program Manager in Microsoft SQL Server. Overview The goal of this blog is to demonstrate how we can automate through PowerShell connecting multiple SQL Server deployments in Windows Azure Virtual Machines. We would configure TCP port that we would open (and close) though Windows firewall from a remote PowerShell session to the Virtual Machine (VM). This will demonstrate how to take the advantage of the remote PowerShell support in Windows Azure Virtual Machines to automate the steps required to connect SQL Server in the same cloud service and in different cloud services.  Scenario 1: VMs connected through the same Cloud Service 2 Virtual machines configured in the same cloud service. Both VMs running different SQL Server instances on them. Both VMs configured with remote PowerShell turned on to be able to run PS and other commands directly into them remotely in order to re-configure them to allow incoming SQL connections from a remote VM or on premise machine(s). Note: RDP (Remote Desktop Protocol) is kept configured in both VMs by default to be able to remote connect to them and check the connections to SQL instances for demo purposes only; but not actually required. Step 1 – Provision VMs and Configure Ports   Provision VM1; named DemoVM1 as follows (see examples screenshots below if using the portal):   Provision VM2 (DemoVM2) with PowerShell Remoting enabled and connected to DemoVM1 above (see examples screenshots below if using the portal): After provisioning of the 2 VMs above, here is the default port configurations for example: Step2 – Verify / Confirm the TCP port used by the database Engine By the default, the port will be configured to be 1433 – this can be changed to a different port number if desired.   1. RDP to each of the VMs created below – this will also ensure the VMs complete SysPrep(ing) and complete configuration 2. Go to SQL Server Configuration Manager -> SQL Server Network Configuration -> Protocols for <SQL instance> -> TCP/IP - > IP Addresses   3. Confirm the port number used by SQL Server Engine; in this case 1433 4. Update from Windows Authentication to Mixed mode   5.       Restart SQL Server service for the change to take effect 6.       Repeat steps 3., 4., and 5. For the second VM: DemoVM2 Step 3 – Remote Powershell to DemoVM1 Enter-PSSession -ComputerName condemo.cloudapp.net -Port 61503 -Credential <username> -UseSSL -SessionOption (New-PSSessionOption -SkipCACheck -SkipCNCheck) Your will then be prompted to enter the password. Step 4 – Open 1433 port in the Windows firewall netsh advfirewall firewall add rule name="DemoVM1Port" dir=in localport=1433 protocol=TCP action=allow Output: netsh advfirewall firewall show rule name=DemoVM1Port Rule Name:                            DemoVM1Port ---------------------------------------------------------------------- Enabled:                              Yes Direction:                            In Profiles:                             Domain,Private,Public Grouping:                             LocalIP:                              Any RemoteIP:                             Any Protocol:                             TCP LocalPort:                            1433 RemotePort:                           Any Edge traversal:                       No Action:                               Allow Ok. Step 5 – Now connect from DemoVM2 to DB instance in DemoVM1 Step 6 – Close port 1433 in the Windows firewall netsh advfirewall firewall delete rule name=DemoVM1Port Output: Deleted 1 rule(s). Ok. netsh advfirewall firewall show  rule name=DemoVM1Port No rules match the specified criteria.   Step 7 – Try to connect from DemoVM2 to DB Instance in DemoVM1  Because port 1433 has been closed (in step 6) in the Windows Firewall in VM1 machine, we can longer connect from VM3 remotely to VM1. Scenario 2: VMs provisioned in different Cloud Services 2 Virtual machines configured in different cloud services. Both VMs running different SQL Server instances on them. Both VMs configured with remote PowerShell turned on to be able to run PS and other commands directly into them remotely in order to re-configure them to allow incoming SQL connections from a remote VM or on on-premise machine(s). Note: RDP (Remote Desktop Protocol) is kept configured in both VMs by default to be able to remote connect to them and check the connections to SQL instances for demo purposes only; but not actually needed. Step 1 – Provision new VM3 Provision VM3; named DemoVM3 as follows (see examples screenshots below if using the portal): After provisioning is complete, here is the default port configurations: Step 2 – Add public port to VM1 connect to from VM3’s DB instance Since VM3 and VM1 are not connected in the same cloud service, we will need to specify the full DNS address while connecting between the machines which includes the public port. We shall add a public port 57000 in this case that is linked to private port 1433 which will be used later to connect to the DB instance. Step 3 – Remote Powershell to DemoVM1 Enter-PSSession -ComputerName condemo.cloudapp.net -Port 61503 -Credential <UserName> -UseSSL -SessionOption (New-PSSessionOption -SkipCACheck -SkipCNCheck) You will then be prompted to enter the password.   Step 4 – Open 1433 port in the Windows firewall netsh advfirewall firewall add rule name="DemoVM1Port" dir=in localport=1433 protocol=TCP action=allow Output: Ok. netsh advfirewall firewall show rule name=DemoVM1Port Rule Name:                            DemoVM1Port ---------------------------------------------------------------------- Enabled:                              Yes Direction:                            In Profiles:                             Domain,Private,Public Grouping:                             LocalIP:                              Any RemoteIP:                             Any Protocol:                             TCP LocalPort:                            1433 RemotePort:                           Any Edge traversal:                       No Action:                               Allow Ok.   Step 5 – Now connect from DemoVM3 to DB instance in DemoVM1 RDP into VM3, launch SSM and Connect to VM1’s DB instance as follows. You must specify the full server name using the DNS address and public port number configured above. Step 6 – Close port 1433 in the Windows firewall netsh advfirewall firewall delete rule name=DemoVM1Port   Output: Deleted 1 rule(s). Ok. netsh advfirewall firewall show  rule name=DemoVM1Port No rules match the specified criteria.  Step 7 – Try to connect from DemoVM2 to DB Instance in DemoVM1  Because port 1433 has been closed (in step 6) in the Windows Firewall in VM1 machine, we can no longer connect from VM3 remotely to VM1. Conclusion Through the new support for remote PowerShell in Windows Azure Virtual Machines, one can script and automate many Virtual Machine and SQL management tasks. In this blog, we have demonstrated, how to start a remote PowerShell session, re-configure Virtual Machine firewall to allow (or disallow) SQL Server connections. References SQL Server in Windows Azure Virtual Machines   Originally posted at http://blogs.msdn.com/b/sqlosteam/

    Read the article

< Previous Page | 1 2