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  • Fit Lightbox container in window if image is larger

    - by Bobe
    I'm just looking for a simple way to set the max width and height of the Lightbox container and image based on the window size if the image is larger than the current window size. So say the image is 2000x1200 and the window is 1280x1024, then the max-height and max-width of div.lb-outerContainer and img.lb-image should be set to $(window).height() - 286, $(window).width() - 60 and $(window).height() - 306, $(window).width() - 80 respectively. I'm just having a bit of trouble determining where to go about implementing these rules. Do I do it in the lightbox.js file? If so, where? Would it be acceptable to just throw in some script on the page it's used on?

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  • Positioning an image inside an ImageView width max height and max width set

    - by andern
    I have an ImageView with max height and max width both set to 100. The figure below is clearly not a square, but you can use your imagination ;) Figure 1: +----------------------------------------------+ ¦ ImageView +--------------+ ¦ ¦ ¦ ¦ ¦ ¦ ¦ Actual image ¦ ¦ ¦ ¦ ¦ ¦ ¦ ¦ ¦ ¦ ¦ ¦ ¦ ¦ ¦ +--------------+ ¦ +----------------------------------------------+ Anyway, If I try to set a BitMap to the ImageView that does not have a ratio of 1:1, the image is positioned like pictured in Figure 1. What I want is for the picture to be placed to the left inside the ImageView like pictured in Figure 2 below. Figure 2: +----------------------------------------------+ ¦--------------+ ¦ ¦ ¦ ¦ ¦ Actual image ¦ ¦ ¦ ¦ ¦ ¦ ¦ ¦ ¦ ¦ ¦ ¦--------------+ ¦ +----------------------------------------------+ You can see my ImageView in XML below. maxHeight, maxWidth and adjustViewBounds are set during runtime. <ImageView android:id="@+id/someImage" android:layout_alignParentLeft="true" android:layout_below="@+id/textName" android:layout_height="wrap_content" android:layout_width="wrap_content" android:paddingRight="4dp" /> This is in a RelativeLayout if it makes any difference.

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  • Positioning an image inside an ImageView with max height and max width set

    - by andern
    I have an ImageView with max height and max width both set to 100. The figure below is clearly not a square, but you can use your imagination ;) Figure 1: +----------------------------------------------+ ¦ ImageView +--------------+ ¦ ¦ ¦ ¦ ¦ ¦ ¦ Actual image ¦ ¦ ¦ ¦ ¦ ¦ ¦ ¦ ¦ ¦ ¦ ¦ ¦ ¦ ¦ +--------------+ ¦ +----------------------------------------------+ Anyway, If I try to set a BitMap to the ImageView that does not have a ratio of 1:1, the image is positioned like pictured in Figure 1. What I want is for the picture to be placed to the left inside the ImageView like pictured in Figure 2 below. Figure 2: +----------------------------------------------+ ¦--------------+ ¦ ¦ ¦ ¦ ¦ Actual image ¦ ¦ ¦ ¦ ¦ ¦ ¦ ¦ ¦ ¦ ¦ ¦--------------+ ¦ +----------------------------------------------+ You can see my ImageView in XML below. maxHeight, maxWidth and adjustViewBounds are set during runtime. <ImageView android:id="@+id/someImage" android:layout_alignParentLeft="true" android:layout_below="@+id/textName" android:layout_height="wrap_content" android:layout_width="wrap_content" android:paddingRight="4dp" /> This is in a RelativeLayout if it makes any difference.

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  • django select max field from mysql when column is varchar

    - by doza
    Hi, Using Django 1.1, I am trying to select the maximum value from a varchar column (in MySQL.) The data stored in the column looks like: 9001 9002 9017 9624 10104 11823 (In reality, the numbers are much bigger than this.) This worked until the numbers incremented above 10000: Feedback.objects.filter(est__pk=est_id).aggregate(sid=Max('sid')) Now, that same line would return 9624 instead of 11823. I'm able to run a query directly in the DB that gives me what I need, but I can't figure out the best way to do this in Django. The query would be: select max(sid+0) from Feedback; Any help would be much appreciated. Thanks!

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  • SQL Max Group By Query Help

    - by Hcabnettek
    Hi All, I have a quick question. How do I select the two values I need in one query? Currently I'm doing this, which works fine, but it's obviously running two queries when one should do the trick. I tried MAX(columnA) and GROUP BY ColumnB, but that returns multiple row. I only want one row returned. DECLARE @biID bigint , @dtThreshold DateTime SELECT @biID = MAX(biID) FROM tbPricingCalculationCount WITH (NOLOCK) SELECT @dtThreshold = dtDateTime FROM tbPricingCalculationCount WITH (NOLOCK) WHERE biID = @biID I would like both those variables to be set correctly in one query. How can I do that? Thanks, ~ck

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  • How to get MAX value of a version-number (varchar) column in T-SQL

    - by Ogre Psalm33
    I have a table defined like this: Column: Version Message Type: varchar(20) varchar(100) ---------------------------------- Row 1: 2.2.6 Message 1 Row 2: 2.2.7 Message 2 Row 3: 2.2.12 Message 3 Row 4: 2.3.9 Message 4 Row 5: 2.3.15 Message 5 I want to write a T-Sql query that will get message for the MAX version number, where the "Version" column represents a software version number. I.e., 2.2.12 is greater than 2.2.7, and 2.3.15 is greater than 2.3.9, etc. Unfortunately, I can't think of an easy way to do that without using CHARINDEX or some complicated other split-like logic. Running this query: SELECT MAX(Version) FROM my_table will yield the erroneous result: 2.3.9 When it should really be 2.3.15. Any bright ideas that don't get too complex?

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  • Van Gogh’s Starry Night Rendered in Hubble Telescope Images

    - by Jason Fitzpatrick
    The process of making a large image out of mosaic of smaller image “pixels” is certainly nothing new; this rendition of Starry Night using images from the Hubble telescope, however, is a particularly fitting use of the technique. Crafted by Alex H. Parker, a researcher at the Harvard-Smithsonian Center for Astrophysics, on evenings when cloud cover prevented him from conducting his research, the image is a carefully constructed mosaic of NASA supplied photos from the Hubble telescope program. Hit up the link below to check out the full size image. Starry Night Arranged by Alex H. Parker 8 Deadly Commands You Should Never Run on Linux 14 Special Google Searches That Show Instant Answers How To Create a Customized Windows 7 Installation Disc With Integrated Updates

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  • Case Management API by Koen van Dijk

    - by JuergenKress
    Case Management is a new addition to Oracle BPM in release 11.1.1.1.7 (PS6). This new release contains the Case Management engine, see blog Léon at  http://leonsmiers.blogspot.nl/ for more details.  However, currently this release does not contain a case portal. The case management API's, just like the already existing Oracle BPM API's, help in developing a portal page with relative ease. This blog will use some real life examples from the EURent casemanagement application and portal application developed by Oracle. The Oracle BPM Case Management API is a Java Based API that enables developers to programmatically access the new Case Management functionalities. It is an elaborate API that can access all the functionalities of Oracle Case Management. I will describe two of those functionalities in this blog: retrieving case data as DOM (http://www.w3.org/DOM/) and attaching a document to a case. Libraries First of all when creating a Case Management project you will need to attach the following libraries: These contain all the classes that are in the Case Management API. Service client To do anything with the BPM CaseManagement API in general it is necessary to create a CaseManagementServiceClient Object. The Case Management service client is the central piece of the Case Management API. It can be used to retrieve two different types of services. The first is the case stream service and the case service. The case stream service contains functionality to upload and download documents to and from a case. The second one is the CaseService. This service contains all the other functionality acting upon a case including but not limited to: Read the complete article here. SOA & BPM Partner Community For regular information on Oracle SOA Suite become a member in the SOA & BPM Partner Community for registration please visit www.oracle.com/goto/emea/soa (OPN account required) If you need support with your account please contact the Oracle Partner Business Center. Blog Twitter LinkedIn Facebook Wiki Technorati Tags: ACM API,adaptive Case Management,BPM,SOA Community,Oracle SOA,Oracle BPM,Community,OPN,Jürgen Kress

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  • SQL SERVER – Find Max Worker Count using DMV – 32 Bit and 64 Bit

    - by pinaldave
    During several recent training courses, I found it very interesting that Worker Thread is not quite known to everyone despite the fact that it is a very important feature. At some point in the discussion, one of the attendees mentioned that we can double the Worker Thread if we double the CPU (add the same number of CPU that we have on current system). The same discussion has triggered this quick article. Here is the DMV which can be used to find out Max Worker Count SELECT max_workers_count FROM sys.dm_os_sys_info Let us run the above query on my system and find the results. As my system is 32 bit and I have two CPU, the Max Worker Count is displayed as 512. To address the previous discussion, adding more CPU does not necessarily double the Worker Count. In fact, the logic behind this simple principle is as follows: For x86 (32-bit) upto 4 logical processors  max worker threads = 256 For x86 (32-bit) more than 4 logical processors  max worker threads = 256 + ((# Procs – 4) * 8) For x64 (64-bit) upto 4 logical processors  max worker threads = 512 For x64 (64-bit) more than 4 logical processors  max worker threads = 512+ ((# Procs – 4) * 8) In addition to this, you can configure the Max Worker Thread by using SSMS. Go to Server Node >> Right Click and Select Property >> Select Process and modify setting under Worker Threads. According to Book On Line, the default Worker Thread settings are appropriate for most of the systems. Reference: Pinal Dave (http://blog.SQLAuthority.com) Filed under: Pinal Dave, SQL, SQL Authority, SQL Query, SQL Scripts, SQL Server, SQL System Table, SQL Tips and Tricks, T SQL, Technology Tagged: SQL DMV

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  • SQL - Count grouped entries and then get the max values grouped by date

    - by Marcus
    hello, I am out of any logic how to write the right sql statment. I've got a sqlite table holding every played track in a row with played date/time Now I will count the plays of all artists, grouped by day and then find the artist with the max playcount per day. I used this Query SELECT COUNT(ARTISTID) AS artistcount, ARTIST AS artistname,strftime('%Y-%m-%d', playtime) AS day_played FROM playcount GROUP BY artistname to get this result "93"|"The Skygreen Leopards"|"2010-06-16" "2" |"Arcade Fire" |"2010-06-15" "2" |"Dead Kennedys" |"2010-06-15" "2" |"Wolf People" |"2010-06-15" "3" |"16 Horsepower" |"2010-06-15" "3" |"Alela Diane" |"2010-06-15" "46"|"Motorama" |"2010-06-15" "1" |"Ariel Pink's Haunted" |"2010-06-14" I tried then to query this virtual table but I always get false results in artistname. SELECT MAX(artistcount), artistname , day_played FROM ( SELECT COUNT(ARTISTID) AS artistcount, ARTIST AS artistname,strftime('%Y-%m-%d', playtime) AS day_played FROM playcount GROUP BY artistname ) GROUP BY strftime('%Y-%m-%d',day_played) result in this "93"|"lilium" |"2010-06-16" "46"|"Wolf People"|"2010-06-15" "30"|"of Montreal"|"2010-06-14" but the artist name is false. I think through the grouping by day, it just use the last artist, or so. I tested stuff like INNER JOIN or GROUP BY ... HAVING in trial and error, I read examples of similar issues but always get lost in columnnames and stuff (I am a bit burned out) I hope someone can give me a hint. thanks m

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  • translate stored procedure - to Linq2SQL (count, max, group, orderby)

    - by Walter
    I've two tables (1:N) CREATE TABLE master (idMaster int identity (1,1) not null, TheName varchar( 100) null, constraint pk_master primary key(idMaster) clustered) and - CREATE TABLE lnk (idSlave int not null, idMaster int not null, constraint pk_lnk_master_slave(idSlave) primary key clustered) link between Master.idMaster and lnk.idMaster I've a SQL query: select max (master.idMaster) as idMaster, master.theName, count (lnk.idSlave) as freq from lnk inner join master ON lnk.idMaster = master.idMaster Group by master.theName order by freq desc, master.theName I need to translate this T-SQL query to a Linq-to-SQL statement, preferably in C#

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  • how to create a linq query using join and max

    - by geoff swartz
    I have 2 tables in my linq dbml. One is people with a uniqueid called peopleid and the other is a vertical with a foreign key for peopleid and a uniqueid called id. I need to create a type of linq query that does a left outer join on people and gets the latest record in the vertical table based off the max(id) column. Can anyone suggest what this should look like? Thanks.

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  • Using max-width = 100% and max-height = 100% on an image, calculate the display width/height

    - by NatalieMac
    I am creating a slideshow for images of various sizes to display centered vertically and horizontally within a canvas area. In my CSS, I set the width and height of the image to 100% so that each image would proportionally fill the canvas. I want the canvas to auto-size itself to fit within the viewer's screensize as the original size of the images is quite large (up to 800 pixels tall). I am using jQuery 1.4, and using the height of the image to calculate the top value for absolute positioning it to the middle of the canvas. I have tried using jQuery to get the .height(), innerHeight(), and outerHeight(), but it always gets the full size of the image. I extracted the DOM element from the jQuery object and tried using .width, .offsetWidth, and .clientWidth, but that too always seems to return the full size of the image. Firebug displays the correct dimensions, so I know there's some way of calculating the actual display height of the image, I just can't figure out what it is. How do you get the actual display height of an image if you've set max-height = 100%? I didn't want to have to calculate and set the height of each image in the js, but if I have to, I will. It just seems like I should be able to set the canvas size and have the images auto-adjust.

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  • MySQL SELECT MAX multiple tables : foreach parent return eldest son's picture

    - by Guillermo
    **Table parent** parentId | name **Table children** childId | parentId | pictureId | age **Table childrenPictures** pictureId | imgUrl no i would like to return all parent names with their eldest son's picture (only return parents that have children, and only consider children that have pictures) so i thought of something like : SELECT c.childId AS childId, p.name AS parentName, cp.imgUrl AS imgUrl, MAX(c.age) AS age FROM parent AS p RIGHT JOIN children AS c ON (p.parentId = c.parentId) RIGHT JOIN childrenPictures AS cp ON (c.pictureId = cp.pictureId)) GROUP BY p.name This query will return each parent's eldest son's age, but the childId will not correspond to the eldest sons id, so the output does not show the right sons picture. Well if anyone has a hint i'd appreciate very much Thank you very much, G

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  • max count with joins

    - by trixet
    I have 3 tables: users: Id Login 1 John 2 Bill 3 Jim computers: Id Name 1 Computer1 2 Computer2 3 Computer3 4 Computer4 5 Computer5 sessions: UserId ComputerId Minutes 1 2 47 2 1 32 1 4 15 2 5 5 1 2 7 1 1 40 2 5 31 I would like to display this resulting table: Login Total_sess Total_min Most_freq_computer Sess_on_most_freq Min_on_most_freq John 4 109 Computer2 2 54 Bill 3 68 Computer5 2 36 Jim - - - - - Myself I can only cover first 3 columns with: SELECT Login, COUNT(sessions.UserId), SUM(Minutes) FROM users LEFT JOIN sessions ON users.Id = sessions.UserId GROUP BY users.Id And some kind of other columns with: SELECT main.* FROM (SELECT UserId, ComputerId, COUNT(*) AS cnt ,SUM(Minutes) FROM sessions GROUP BY UserId, ComputerId) AS main INNER JOIN ( SELECT ComputerId, MAX(cnt) AS maxCnt FROM ( SELECT ComputerId, UserId, COUNT(*) AS cnt FROM sessions GROUP BY ComputerId, UserId ) AS Counts GROUP BY ComputerId) AS maxes ON main.ComputerId = maxes.ComputerId AND main.cnt = maxes.maxCnt But I need to get whole resulting table in one query. I feel I'm doing something completely wrong. Need help.

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  • Select *, max(date) works in phpMyAdmin but not in my code

    - by kdobrev
    OK, my statement executes well in phpMyAdmin, but not how I expect it in my php page. This is my statement: SELECT egid , group_name , limit , MAX( date ) FROM employee_groups GROUP BY egid ORDER BY egid DESC ; This is may table: CREATE TABLE employee_groups ( egid int(10) unsigned NOT NULL, date date NOT NULL, group_name varchar(50) NOT NULL, limit smallint(5) unsigned NOT NULL, PRIMARY KEY (egid,date) ) ENGINE=MyISAM DEFAULT CHARSET=cp1251; I want to extract the most recent list of groups, e.g. if a group has been changed I want to have only the last change. And I need it as a list (all groups).

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  • How to get max row from table

    - by Odette
    HI I have the following code and a massive problem: WITH CALC1 AS ( SELECT OTQUOT, OTIT01 AS ITEMS, ROUND(OQCQ01 * OVRC01,2) AS COST FROM @[email protected] WHERE OTIT01 <> '' UNION ALL SELECT OTQUOT, OTIT02 AS ITEMS, ROUND(OQCQ02 * OVRC02,2) AS COST FROM @[email protected] WHERE OTIT02 <> '' UNION ALL SELECT OTQUOT, OTIT03 AS ITEMS, ROUND(OQCQ03 * OVRC03,2) AS COST FROM @[email protected] WHERE OTIT03 <> '' UNION ALL SELECT OTQUOT, OTIT04 AS ITEMS, ROUND(OQCQ04 * OVRC04,2) AS COST FROM @[email protected] WHERE OTIT04 <> '' UNION ALL SELECT OTQUOT, OTIT05 AS ITEMS, ROUND(OQCQ05 * OVRC05,2) AS COST FROM @[email protected] WHERE OTIT05 <> '' ORDER BY OTQUOT ASC ) SELECT OTQUOT, ITEMS, MAX(COST) FROM CALC1 WHERE OTQUOT = '04886471' GROUP BY OTQUOT, ITEMS result: 04886471 FEPO5050WCGA24 13.21 04886471 GFRK1650SGL 36.21 04886471 FRA7500GA 12.6 04886471 CGIFESHAZ 11.02 04886471 CGIFESHPDPR 11.79 04886471 GFRK1350DBL 68.23 04886471 RET1.63825GP 32.55 04886471 FRSA 0.12 04886471 GFRK1350SGL 55.94 04886471 GFRK1650DBL 71.89 04886471 FEPO6565WCGA24 16.6 04886471 PCAP5050GA 0.28 04886471 FEPO6565NCPAG24 0.000000 How can I get the result of the row with the Itemcode that has the highest value? In this case I need the result: 04886471 GFRK1650DBL 71.89 but i dont know how to change my code to get that - can anybody please help me?

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  • Reasons for sticking with TEXT, NTEXT and IMAGE instead of (N)VARCHAR(max) and VARBINARY(max)

    - by John Assymptoth
    TEXT, NTEXT and IMAGE have been deprecated a long time ago and will, eventually, be removed from SQL Server. However, they are not going to be discontinued right away, not even in the next version of SQL Server, so it's not convenient for my enterprise to transform thousands of columns right away, even if it is using SQL Server 2012. What arguments can I use to postpone this migration? I know there are some advantages in using the new types. But I'm strictly looking for reasons not to migrate my data that is already functioning pretty well in the old types.

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  • Using recursion to to trim a binary tree based on a given min and max value

    - by Justin
    As the title says, I have to trim a binary tree based on a given min and max value. Each node stores a value, and a left/right node. I may define private helper methods to solve this problem, but otherwise I may not call any other methods of the class nor create any data structures such as arrays, lists, etc. An example would look like this: overallRoot _____[50]____________________ / \ __________[38] _______________[90] / \ / _[14] [42] [54]_____ / \ \ [8] [20] [72] \ / \ [26] [61] [83] trim(52, 65); should return: overallRoot [54] \ [61] My attempted solution has three methods: public void trim(int min, int max) { rootFinder(overallRoot, min, max); } First recursive method finds the new root perfectly. private void rootFinder(IntTreeNode node, int min, int max) { if (node == null) return; if (overallRoot.data < min) { node = overallRoot = node.right; rootFinder(node, min, max); } else if (overallRoot.data > max) { node = overallRoot = node.left; rootFinder(node, min, max); } else cutter(overallRoot, min, max); } This second method should eliminate any further nodes not within the min/max, but it doesn't work as I would hope. private void cutter(IntTreeNode node, int min, int max) { if (node == null) return; if (node.data <= min) { node.left = null; } if (node.data >= max) { node.right = null; } if (node.data < min) { node = node.right; } if (node.data > max) { node = node.left; } cutter(node.left, min, max); cutter(node.right, min, max); } This returns: overallRoot [54]_____ \ [72] / [61] Any help is appreciated. Feel free to ask for further explanation as needed.

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  • Max Value of a Multiway Tree in OCaml

    - by Trigork
    I'm an IT Student and kind of a newbie to OCaml Recently, studying for an exam I found this exercise. Given: type 'a tree = Tree of 'a * 'a tree list Define a function mtree : 'a tree -'a, that returns the greatest value of all the nodes in a multiway tree, following the usual order relation in OCaml (<=) I've come to do something like this below, which, of course, is not working. let rec mtree (Tree (r, sub)) = let max_node (Tree(a, l1)) (Tree(b, l2)) = if a >= b then (Tree(a, l1)) else (Tree(b, l2)) in List.fold_left max_node r sub;; After reading an answer to this I'm posting the fixed code. let rec mtree (Tree(r,sub)) = let max_node (Tree(a, l1)) (Tree(b, l2)) = if a >= b then a else b in List.fold_left (max_node) r (List.map mtree sub);; The idea is the same, fold the list comparing the nodes making use of my local function to do so and travel through the tree by calling the function itself over the nodes lists of the consecutive levels. Is still not working, though. Now complains about max_node in the fold_left part. Error: This expression has type 'a tree -> 'a tree -> 'a but an expression was expected of type 'a tree -> 'a tree -> 'a tree And here I'm definitely lost because I can't see why does it expects to return an 'a tree

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  • SQL Server Max SmallInt Value

    - by Derek Dieter
    The maximum value for a smallint in SQL Server is: -32768 through 32767 And the byte size is: 2 bytes other maximum values: BigInt: -9223372036854775808 through 9223372036854775807 (8 bytes) Int: -2147483648 through 2147483647 (4 bytes) TinyInt: 0 through 255 (1 byte) Related Posts:»SQL Server Max TinyInt Value»SQL Server Max Int Value»SQL Server Bigint Max Value»Dynamic Numbers Table»Troubleshooting SQL Server Slowness

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