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  • Creating a menu to switch languages on site

    - by user342391
    I have a dropdown menu on my site that I want to use to switch between the different languages: <select onChange="if(this.selectedIndex!=0) self.location=this.options[this.selectedIndex].value" name="userLanguage" id="userLanguage"> <option value="http://demo.com/?lang=en"> English (International)</option> <option value="http://demo.com/?lang=es"> Español (European)</option> </select> How can I get the above menu to display which language is currently showing. Is there someway of showing an active state. Site is using php. Thanks in advance.

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  • CSS/Jquery How can I display a div directly under button?

    - by user342391
    I have a button that when hovered displays a div. How can I postion this div to appear directly under the button when displayed??? <script type="text/javascript"> $(document).ready(function(){ $(".plans").hover(function() { $("#planssubnav").show("slow"); }, function(){ $("#planssubnav").hide("slow"); }); }); </script> <a href="/plans" style="font-size:14px;" class="plans fg-button fg-button-icon-right ui-state-default ui-corner-all"><span class="ui-icon ui-icon-circle-triangle-s"></span>Plans</a> <div id="planssubnav" style="display:none"> <h1> content</h1> </div>

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  • Pass data via ajax to dialog Jquery

    - by user342391
    I am trying to post data from my form to a jquery dialog that loads external content. I am serializing the form data which works (appears in the url) but the dialog won't open: $("#wavajax button").click(function() { $.post({url: 'player/index.php', data: $("#wavajax").serialize(), success: function (data) { $("#recordingdialog").load("player/index.php", [], function(){ $("#recordingdialog").dialog("open"); } }); return false; }); What am I doing wrong, am I going about it the right way???

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  • PHP pass variable after form is submitted

    - by user342391
    I have a form that posts to process.php. Process.php send all the data to mysql then returns back to the page using: <?php header("Location: /campaigns"); ?> On the page it returns to I want to display a message saying form submitted. Can I post a variable to the Location: /campaigns. And use the variable to display the message (or modal box)? and if so what would be the best way to do it?

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  • User Inactivity Logout PHP

    - by user342391
    I want my users to be logged out automatically after X minutes of inactivity. I also want to have all sessions destroyed. How can this be done? How can I check for inactivity then perform a function to log them out???

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  • Jquery show div on hover then when user hovers out of div hide it help?

    - by user342391
    I have a menu and when I hover one of the links a div shows. I want the user to be able to hover over this div but when the user hovers out of the div (mouseout i think its called) I want it to hide. Imagine a dropdown menu in css, the user hovers over the link and the sub nav is shown, when the user hovers out or away from the link and sub nav the sub nav dissapears. How can this be done with jquery??? this is what I have: $(document).ready(function(){ //when user hovers over plans the mainnavbottom is shown $(".plans").hover( function() { $(".mainnavbottom").show("fast"); }, function(){ $(".mainnavbottom").mouseout.hide("slow"); }); });

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  • Stopping users posting more than once

    - by user342391
    Before posting my form I am checking the database to see if there are any previous posts from the user. If there are previous posts then the script will kick back a message saying you have already posted. The problem is that what I am trying to achieve isn't working it all goes wrong after my else statement. It is also probable that there is an sql injection vulnerability too. Can you help??4 <?php include '../login/dbc.php'; page_protect(); $customerid = $_SESSION['user_id']; $checkid = "SELECT customerid FROM content WHERE customerid = $customerid"; if ($checkid = $customerid) {echo 'You cannot post any more entries, you have already created one';} else $sql="INSERT INTO content (customerid, weburl, title, description) VALUES ('$_POST[customerid]','$_POST[webaddress]','$_POST[pagetitle]','$_POST[pagedescription]')"; if (!mysql_query($sql)) { die('Error: ' . mysql_error()); } echo "1 record added"; ?>

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  • $this.attr() stops Jquery dialog from opening

    - by user342391
    I am using the following code to post my form data to player/index.php and open it in a dialog. Because I have multiple of these forms in my table I need to use $(this). But now it doesn't open in a dialog. New code (doesn't open dialog but display data in url): $("#recordingdialog").dialog({ //other options, width, height, etc... modal: true, bgiframe: true, autoOpen: false, height: 200, width: 350, draggable: true, resizeable: true, title: "Play Recording",}); $(this).click(function() { $.post('player/index.php', $(this).attr('form').serialize(), function (data) { $("#recordingdialog").html(data).dialog("open"); }); return false; }); Old code (only works on one form): $("#recordingdialog").dialog({ //other options, width, height, etc... modal: true, bgiframe: true, autoOpen: false, height: 550, width: 550, draggable: true, resizeable: true, title: "Play Recording",}); $("#wavajax button").click(function() { $.post('player/index.php', $("#wavajax").serialize(), function (data) { $("#recordingdialog").html(data).dialog("open"); }); return false; });

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  • How to get value of href in Jquery

    - by user342391
    I am trying to grab the value of my href in jquery how is it done'? This is what I have done: $('#playbackbutton').click( function() { $("#playbackdiv").load("$('a:href').val();", [], function(){ $("#playbackdiv").dialog("open"); } ); return false; } I need to get the value of the href in my a tag. here is the html: <a href="/record/123.wav">play</a>

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  • How do stop form posting to mysql if database contains a specific ID?

    - by user342391
    I have a form that I am using to post data to mysql. Before submitting the form I want to check the database and see if there are any fields in the column 'customerid' that equal 'userid' and if so not to post the form. Basically, I am trying to limit my users from posting more than once. Users will be able to login to my system and make ONE post. They will be able to delete and modify their post but are only limited to one post. How would I do this??? Code so far: <?php include '../login/dbc.php'; page_protect(); $userid = $_SESSION['user_id']; $sql="INSERT INTO content (customerid, weburl, title, description) VALUES ('$_POST[userid]','$_POST[webaddress]','$_POST[pagetitle]','$_POST[pagedescription]')"; if (!mysql_query($sql)) { die('Error: ' . mysql_error()); } echo "1 record added"; ?>

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  • php help hiding navigation with cookie

    - by user342391
    I have these tabs on my navigation: <li<?php if ($thisPage=="Customers") echo " class=\"current\""; ?>><a href="/customers/">Customers</a></li> <li<?php if ($thisPage=="Trunks") echo " class=\"current\""; ?>><a href="/trunks/">Trunks</a></li> <li<?php if ($thisPage=="Settings") echo " class=\"current\""; ?>><a href="/settings/">Settings</a></li> and I only want to show them when admin is logged in: if ($_COOKIE['custid'] == "admin") { echo "Customers"; echo "Trunks"; echo "Settings"; } How can I combine the two of these scripts???

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