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• Php regular expression to match a div

  - by Thoman

  Hello This is mycode <?php /** * @author Joomlacoders * @copyright 2010 */ $url="http://urlchecker.net/html/demo.html"; $innerHtml=file_get_contents($url); //echo $innerHtml; preg_match_all("{\<div id='news-id-.*d'\>(.*)\</div\>}",$innerHtml,$matches); //<div id='news-id-160346'> var_dump($matches); ?> I want find all content in div id='news-id-160346'. Please help me

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• Drupal - Generating forms from the database.

  - by YsoL8

  Hello I'm trying to teach myself Drupal and I've found something I can't find any tutorials for. I am trying to generate a form, with a dynamic number of text fields, to populate and edit the contents of my custom table. In regular PHP I would achieve this with: $count = '0'; while ($row = mysql_fetch_array ($result) { echo "<input type='text' name='title_row".$count."' value='".$row['title']."'>" $count = $count +1; } Can someone point me to something that'll show me how to do that in Drupal (and processing the submited data)? Thanks

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• Can I use string concatenation to define a class CONST in PHP?

  - by selfsimilar

  I know that you can create global constants in terms of each other using string concatenation: define('FOO', 'foo'); define('BAR', FOO.'bar'); echo BAR; will print 'foobar'. However, I'm getting an error trying to do the same using class constants. class foobar { const foo = 'foo'; const foo2 = self::foo; const bar = self::foo.'bar'; } foo2 is defined without issue, but declaring const bar will error out Parse error: syntax error, unexpected '.', expecting ',' or ';' I've also tried using functions like sprintf() but it doesn't like the left paren any more than the string concatenator '.'. So is there any way to create class constants in terms of each other in anything more than a trivial set case like foo2?

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• Centering images php

  - by peak

  I'm trying to center an image in php. I'm currently using this line of code echo '<img src="newimage.jpg" width="110" height="120" class="centre">'; However, this seems to have no effect. I've also tried using something like this, img.center { display: block; margin-left: auto; margin-right: auto; } <img src="newimage.jpg" alt="Suni" class="center" /> but this merely gives me a syntax error, how do I go about fixing this? Thanks

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• Login with Google OAuth api and return url with variable

  - by user2833721

  I am using the Google API for login in my site and I appending my variable with URL and I want that variable in the return URL of OAuth API because of update purpose can I return back that variable For example: <a href="<?php echo($authUrl); ?>&kicker"> I append the kicker in $authUrl and when I return back from Oauth api print $me['displayName']; print $user['email']; print $me['gender']; print $me['id']; with this output I also want my variable "kicker" how can I get it

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• show count of only configurable products of current category

  - by hs19

  hello, i want to show count of only configurable products of current category on category page. for that I have written following code... <?php $cate = Mage::registry('current_category')->getName(); $total=0; $category = Mage::registry('current_category'); $products = $category->getProductCollection(); foreach ( $products as $_product ) if ($_product->isConfigurable()) { $total++; } echo $cate."(".$total.")"; ?> my problem is the code is showing the total count of configurable products of all child categories... can anyone help me with this?

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• system() not working in php using windows server 2003

  - by jazzy

  hi i have to extract the cabfile(.cab) on the server. i am Finding such script which extract cab file but i didn't get it yet. So now i am try to extract using cabarc.exe. But i face the problem that when i run command throuw commandline its work fine but when i give same command to system() or exec() function in php it is not work. code is as follow: $command = "c:\\exe\\cabarc X c:\\cab\\data.cab c:\\data\\"; if(($output = system($command,$return) != false) { echo "$return"; } it is not working when i use same string in commandline it works fine. please any body help me to why it not working what to do tomake it work is ther any rights issue. I had give the execute permission to the site. thanks

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• How to get the required value displayed from the given array?

  - by Parth

  From below array i want the value of "_sql" to be displayed or we can I want to echo the "_sql" value, so what should be the syntax to display it in PHP code? JTableMenu Object ( [lft] => [rgt] => [home] => [_tbl] => #__menu [_tbl_key] => id [_db] => JDatabaseMySQL Object ( [name] => mysql [_nullDate] => 0000-00-00 00:00:00 [_nameQuote] => ` [_sql] => INSERT INTO `jos_menu` ( `id`,`menutype`,`name`,`alias`,`link`,`type`,`published`,`componentid`,`parent`,`ordering`,`checked_out`,`checked_out_time`,`brow............ [_errorNum] => 0 ) )

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• problems with inserting data in database

  - by jannes braet

  $message=$_POST['answer']; $message=nl2br($message); $message=strip_tags($message, '<p><a><b><i><strong><em><code><sub><sup><img><ul><ol><li>'); $message = mysql_real_escape_string($message); $user=$_SESSION['SESS_MEMBER_ID']; $qry="INSERT INTO forum_rules (message,author,date) VALUES ($message,$user,'".date("Y-m-d H:i:s")."')"; $result=mysql_query($qry) or die(mysql_error()); if (!$result) { echo "error inserting data into database"; } else { ... } this codes always outputs error inserting data into database and i don't see what i'm doing wrong. i hav also tried to do it without the date part but that didn't work tho. can someone please tell me what i'm doing wrong here

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• Vim: How to handle newlines when storing multiple commands in registers?

  - by UncleZeiv

  I have a file where I store snippets of vim commands. When I need a snippet, I yank it and then execute it with @". The snippets are stored as a script, one line per command, like this: :s/foo/bar/g :echo "hello" :s/1/2/g Edit: I removed normal mode commands from the example, as they were not part of the problem. Now this procedure doesn't work anymore: when executing the snippet, it just stops at the first line as if waiting for a newline. Is there an option somewhere affecting how @ is executed? I'm pretty sure it was working some time ago... Substituting the newline with a ^M character works but makes the file more difficult to handle. Additional information: Here's another symptom: when I yank a snippet, if I execute it with @" it stops at the first line as I just explained. But if I execute it with :@ it works. But the help file doesn't seem to imply any difference in how the two commands treat the register's content...

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• Windows batch file: Pipe destroys my return code

  - by murxx

  Hi, is it possible to return the errorlevel also if I pipe the output of a script into a logfile: test1.bat: call test2.bat 2>&1 | tee log.txt echo ERRORLEVEL: %ERRORLEVEL% test2.bat: exit /B 1 Output when calling test1.bat: ERRORLEVEL: 0 The errorlevel is always 0. The problem is, I want to call another script inside my script where the output should be redirected synchronously with the output shown in the command line, therefore a simple is not enough for me. I tried several ideas, but result is that the pipe always seems to destroy the given error-level... :( Can you give me any further suggestions? Thanks in advance... :)

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• Display only latest three results from PHP and MySQL

  - by nogggin1

  <?php $result = @mysql_query('SELECT Article FROM news WHERE ID = (SELECT MAX(ID) FROM News)'); if (!$result) { die('<p>Error performing query: ' . mysql_error() . '</p>'); } while ( $row = mysql_fetch_array($result) ) { echo('<p>' . $row['Article'] . '</p>'); } ?> basically i need to tweak this so that it shows the latest 3 results instead of just the latest one, also i need the order to be: newest 2nd newest 3rd newest any help would be greatly appreciated!

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• trying to get property of non object curl issue

  - by user550265

  I have a curl setup as follows to access a json object $ch = curl_init(); curl_setopt($ch, CURLOPT_URL, "http://sitename.com"); curl_setopt($ch, CURLOPT_HEADER, 0); curl_setopt($ch, CURLOPT_RETURNTRANSFER, true); curl_setopt($ch, CURLOPT_BINARYTRANSFER, true); curl_setopt($ch, CURLOPT_COOKIEJAR, 'cookiefilename.txt'); curl_setopt($ch, CURLOPT_HTTPHEADER, array('Host:sitename.com')); $output = curl_exec($ch); curl_close($ch); $output = json_decode($output); echo $output->property; I get the error 'trying to access property of non object'.

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• How do check if PDO object is connected properly inside a different class?

  - by tgun926

  I want to fetch some information from my mysql database in a class, so I'm passing in the PDO object into a __construct function, and working from there. However, what's an elegant way of checking to see if the PDO object was correctly created, and that the connection is open when the Table class is instantiated? class Table{ public function __construct(PDO $db, $week){ try{ $query = $db -> query ("SELECT * FROM `table1` where `day` = 'monday'"); } catch(PDOExeption $e){ echo 'error: '. $e->getMessage(); //die(); } } } I don't think this code does what I want.

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• Remembering Form information

  - by Pete Herbert Penito

  Hi everyone! I'm sorry if this has been asked before but I feel my situation is a little different... I have a huge form (like 50 questions involving checkboxes, drop downs, text boxes and textareas) When a user submits a form and the validation page throws an error, is there an easy way to keep the info they entered? My intitial form is on form.php and then the form action is form_posted.php, before anything is run on form_posted.php I have my validation code which sends the user back to form.php with an error number (eg. form.php?error=3) if there was a problem with any in particular. This is done with header("form.php?error=3") so on form.php do the posted variables exist? even tho the page wasn't specifically sent with any posted variables. Also if this is the case, is it completely secure to be making the value of a textbox what it was before? like <input type="text" value="php echo $_POSTED["username"] ?>">

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• Is this a correct json format....

  - by chandru_cp

  I want to get a fair idea about json format... I am using php in which i have converted my result array to json like this $result = mysql_query("select dStud_id,dMarkObtained1,dMarkObtained2, dMarkObtained3,dMarkTotal from tbl_internalmarkallot"); $JsonVar = json_encode($res); echo "<input type='text' name='json' id='json' value ='$JsonVar'>"; And the text box shows {"0":"101","dStud_id":"101","1":"60","dMarkObtained1":"60","2":"80", "dMarkObtained2":"80","3":"80","dMarkObtained3":"80","4":"220","dMarkTotal":"220"} Is this a correct json format....

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• PHP: How do I access child properties from a method in a base object?

  - by Nick

  I'd like for all of my objects to be able to return a JSON string of themselves. So I created a base class for all of my objects to extend, with an AsJSON() method: class BaseObject { public function AsJSON() { $JSON=array(); foreach ($this as $key = $value) { if(is_null($value)) continue; $JSON[$key] = $value; } return json_encode($JSON); } } And then extend my child classes from that: class Package extends BaseObject { ... } So in my code, I expect to do this: $Box = new Package; $Box-SetID('123'); $Box-SetName('12x8x6'); $Box-SetBoxX('12'); $Box-SetBoxY('8'); $Box-SetBoxZ('6'); echo $Box-AsJSON(); But the JSON string it returns only contains the BaseClass's properties, not the child properties. How do I modify my AsJSON() function so that $this refers to the child's properties, not the parent's?

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• Refreshing <div> and load data from php

  - by forgatn

  I have on my page and there is a tag where is some and values filled from mySQL DB. I need some JavaScript I think. When I select one option, I want to display in this propriate DATAs which are in DB. without refreshing whole page. Can you tell me how to do it, if you know that please?:) <div id="country1" class="tabcontent"> <label>Choose protocol</label> <SELECT name="cisloprot"> <?php $con = mysql_connect("localhost", "root", "123456"); $sql = "SELECT kod FROM prot GROUP BY kod"; $rs = mysql_query($sql,$con); while ($r = mysql_fetch_array($rs)) { echo "<OPTION VALUE=".$r['kod'].">".$r['kod']."</OPTION>"; } ?> </SELECT> </div>

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• jquery json function returning null

  - by ian

  I have a jquery script as below: $.ajax({ type: "GET", url: "http://www.site.com/v4/ajax/get_song_info.php", data: ({id : song_id }), dataType: "json", success: function(data) { alert( "Data: " + data ); } }); And the associated php page: <?php include_once '../connect.php'; $song_id = $_GET['id']; $query = mysql_query("SELECT * FROM songs WHERE id = '$song_id' LIMIT 1"); $song = mysql_fetch_row($query); $song_info = array( htmlentities($song[3]) , htmlentities($song[4]) ); header('Content-Type: application/json'); echo json_encode($song_info); ?> The php returns something like this when I call it on its own in a browser: ["Peaches","I Feel Cream (Proxy Remix)"] However when I make the jQuery call my alert shows 'Data: null'

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• Stopping an if clause along with the whole PHP script, but not HTML

  - by user626816

  Hello there, I've been having this problem for around an hour, and have searched the internet for answers. I've checked the PHP documentation, looked around, Googled, nothing. Anyways, my problem is that after I try to validate something (and it's wrong), if I use exit; it will also stop the HTML after. Here's what I'm talking about: if ($_POST['exampleEmail'] == "") { echo "Please enter an e-mail."; //Now I want only the PHP script to stop, however... exit; //If I use exit, then the HTML after this script (footer) doesn't show. } If anyone can help, please do. I've tried using break, but to no avail, since it's only for loops and switches. If there is a better/more correct (or simply correct if this is the wrong way), please share. I've had this problem in the past, and I just used exit then. Thanks.

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• CodeIgniter URI segments captured as variables?

  - by Zen Savona

  well, i have a function within a controller called test, and i can access it by going to http://localhost/nwk/control/test this is my function. I want to use the data given in the next segment from the "test" as a php variable. so if i put function test() { $var $this->uri->segment(3); echo $var; } according to the user guide if I enter control/test/data, my variable should be equal to 'data'? doesn't seem to be working. Am I missing something here?

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• What does $this generally mean in PHP?

  - by xczzhh

  I am really new to PHP, so I am kind of confused seeing these different operators all day. Here is some code I came across when watching a video tutorail, I'd appreciate it if some could explain a little bit: function index() { $config = Array( 'protocol' => 'smtp', 'smtp_host' => 'ssl://smtp.googlemail.com', 'smtp_port' => 465, 'smtp_user' => '[email protected]', 'smtp_pass' =>'password', ); $this->load->library('email', $config); $this->email->set_newline("\r\n"); $this->email->from('[email protected]', 'Jerry'); $this->email->to('[email protected]'); $this->email->subject('this is an email test'); $this->email->message('this is test message!'); if($this->email->send()) { echo 'Your email was sent'; } else { show_error($this->email->print_debugger()); } } ...

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• php date() stuck

  - by WAC0020

  I am getting the date from my mysql database and that date is correct but when I use the date() function the minute part is stuck a 6 minutes. My mysql is returning 2010-06-15 09:59:18 Then in php I use this code: date('M d,Y H:m A',strtotime($row[4])) ** $row[4] is from my while loop ** When I echo this out I get: Jun 15,2010 9:06 AM I also have tried converting it to unix timestamp in my sql query, does the same thing. I noticed that the hours work and the seconds work but the minutes are stuck at 6. Does anyone have any ideas on what is going on?

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• Question about a dialog form and submit errors

  - by user248959

  Hi, I have the link below that executes the action message/new which shows a form inside a jqueryui modal dialog. <div id="myDialog"> </div> echo jq_link_to_remote('Enviar mensaje', array( 'url' => 'mensaje/new?receptor='.$miembro->getId().'&tipo=0&estado=0', 'update' => 'myDialog', 'complete' => "jQuery('#myDialog').dialog({ width:375, height:220, top:123, resizable:false, modal:true, autoOpen: false }); jQuery('#myDialog').dialog('open')" )); The point: if there are submit errors the form is not showed inside the dialog form but in a empty page (mensaje/create).. Any idea? Javi

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• How to set this if isset function

  - by Danny Florian

  I have the following code that sets a background if user has uploaded to database. If user has NOT uploaded an image then the result is a blank img src='' I need to set this as an if isset function so I can plug in an alternate image if user has not uploaded anything. Here is the current code: <div id="background"><?php echo isset($background_image) && file_exists(ROOT.$background_image)?"<img src='$background_image' alt='' />":'';?></div>

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