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  • MAC OS X: How to determine if filesystem is case sensitive?

    - by trojanfoe
    I have used the statfs(2) system call to get many characteristics of a Mac OS X filesystem, but it doesn't tell me if the filesystem is case-sensitive or not. I need this information as the application I am developing will be moving many files around and I want to detect potential loss of data due to files being moved from a case-sensitive filesystem to a case-insensitive filesystem. Can anyone suggest a way of detecting this?

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  • How can I get the behavior of GNU's readlink -f on a Mac?

    - by troelskn
    On Linux, the readlink utility accepts an option -f that follows additional links. This doesn't seem to work on Mac and possibly BSD based systems. What would the equivalent be? Here's some debug information: $ which readlink; readlink -f /usr/bin/readlink readlink: illegal option -f usage: readlink [-n] [file ...]

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  • Wirenet : découverte du premier trojan Linux/Mac OS X interplateforme de vol de mot de passe

    Wirenet : le premier trojan Linux/Mac OS X interplateforme De vol de mot de passe Doctor Web, l'éditeur russe d'antivirus, a annoncé l'émergence du premier Trojan Linux/OSX interplateforme de vol de mot de passe. Par l'utilisation d'un backdoor, le malware au nom de code BackDoor.Wirenet.1 arrive à transporter les données de l'utilisateur vers un serveur de contrôle situé à l'adresse 212.7.208.65. Les données récoltées comportent les touches de claviers tapées à l'image d'un keylogger et les mots de passe des utilisateurs enregistrés dans les navigateurs Opera, Firefox, Chrome et Chromium et dans les applications Thunderbird, SeaMonkey et Pidgin. L'AES (Advanced Encryption...

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  • I erased osx when i installed ubuntu, how do i set up dual boot

    - by mandy
    I have a macbook pro 8,1 running ubuntu 11.10 on it. Before I wiped osx clean off it, i was running osx lion. This computer was shipped with snow leopard on it so i know it will work on it, but when i try to run the install disk (Even before ubuntu while on lion) i got all kinds of kernel panic and it told me to restart my computer. i just want a dual boot set up so how do i make a partition in ubuntu and put mac on it?

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  • How to view files from host? (running inside VMWare Fusion)

    - by Dave Long
    I have just finished moving my development server into a Ubuntu 10.04 Server VM in VMWare Fusion 3. I have all of my mysql and tomcat stuff running and am now trying to connect to my actual site files which are stored on my mac under /{User Root}/Workspace/ColdFusion/. I know that normally you should be able to setup a shared folder in VMWare and find it under /mnt/hgfs/{Share Name}, but I can't find it. I am not sure if I have to manually mount it or what.

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  • Is this Java 7 security thread an issue if you have Java 7 installed but not as the default?

    - by user1361315
    I have a MBP with osx mountain lion installed, and I believe from what I read Mac's only ship with Java 6 by default. I'm not at my computer at the moment, but I am pretty sure I have installed Java 7 but it isn't my default java version (I think I installed it and I have to explicitly reference it to use it). Does this mean I am safe from this particular thread? Reference: http://www.pcworld.com/businesscenter/article/261748/researchers_find_critical_vulnerability_in_java_7_patch_hours_after_release.html

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  • Help reinstalling Ubuntu on macbook pro

    - by pipsqueaker117
    Ok. I recently installed ubuntu on my macbook pro. Unfortunately, while trying to install the nvidia graphics drivers the system wouldn't reboot, the screen grey for hours. I concluded that I had broken ubuntu, and proceeded to boot into osx and remove the ubuntu partitions. After I had done that, after a reboot, I noticed that "boot linux from hd" was still listed in the bootloader (i'm using rEFIT). I dismissed it. Now, I'm trying to reinstall ubuntu, using the same USB that I successfully installed with earlier. Now, however, when the ubuntu installer is on the "copying files" part this error (more or less) pops up. ERRNO 5: We're sorry, the installer crashed. This error frequently is caused by faulty installation media, the hard disk being too hot... and so on and so forth. I'm not sure what's causing the problem, but I have a hunch that whatever's the reason that's causing linux to show up in rEFIT is the root reason. If anyone could respond, that would be great. PS, and unfortunately no, i do not have a time machine backup.

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  • Does anyone really understand how HFSC scheduling in Linux/BSD works?

    - by Mecki
    I read the original SIGCOMM '97 PostScript paper about HFSC, it is very technically, but I understand the basic concept. Instead of giving a linear service curve (as with pretty much every other scheduling algorithm), you can specify a convex or concave service curve and thus it is possible to decouple bandwidth and delay. However, even though this paper mentions to kind of scheduling algorithms being used (real-time and link-share), it always only mentions ONE curve per scheduling class (the decoupling is done by specifying this curve, only one curve is needed for that). Now HFSC has been implemented for BSD (OpenBSD, FreeBSD, etc.) using the ALTQ scheduling framework and it has been implemented Linux using the TC scheduling framework (part of iproute2). Both implementations added two additional service curves, that were NOT in the original paper! A real-time service curve and an upper-limit service curve. Again, please note that the original paper mentions two scheduling algorithms (real-time and link-share), but in that paper both work with one single service curve. There never have been two independent service curves for either one as you currently find in BSD and Linux. Even worse, some version of ALTQ seems to add an additional queue priority to HSFC (there is no such thing as priority in the original paper either). I found several BSD HowTo's mentioning this priority setting (even though the man page of the latest ALTQ release knows no such parameter for HSFC, so officially it does not even exist). This all makes the HFSC scheduling even more complex than the algorithm described in the original paper and there are tons of tutorials on the Internet that often contradict each other, one claiming the opposite of the other one. This is probably the main reason why nobody really seems to understand how HFSC scheduling really works. Before I can ask my questions, we need a sample setup of some kind. I'll use a very simple one as seen in the image below: Here are some questions I cannot answer because the tutorials contradict each other: What for do I need a real-time curve at all? Assuming A1, A2, B1, B2 are all 128 kbit/s link-share (no real-time curve for either one), then each of those will get 128 kbit/s if the root has 512 kbit/s to distribute (and A and B are both 256 kbit/s of course), right? Why would I additionally give A1 and B1 a real-time curve with 128 kbit/s? What would this be good for? To give those two a higher priority? According to original paper I can give them a higher priority by using a curve, that's what HFSC is all about after all. By giving both classes a curve of [256kbit/s 20ms 128kbit/s] both have twice the priority than A2 and B2 automatically (still only getting 128 kbit/s on average) Does the real-time bandwidth count towards the link-share bandwidth? E.g. if A1 and B1 both only have 64kbit/s real-time and 64kbit/s link-share bandwidth, does that mean once they are served 64kbit/s via real-time, their link-share requirement is satisfied as well (they might get excess bandwidth, but lets ignore that for a second) or does that mean they get another 64 kbit/s via link-share? So does each class has a bandwidth "requirement" of real-time plus link-share? Or does a class only have a higher requirement than the real-time curve if the link-share curve is higher than the real-time curve (current link-share requirement equals specified link-share requirement minus real-time bandwidth already provided to this class)? Is upper limit curve applied to real-time as well, only to link-share, or maybe to both? Some tutorials say one way, some say the other way. Some even claim upper-limit is the maximum for real-time bandwidth + link-share bandwidth? What is the truth? Assuming A2 and B2 are both 128 kbit/s, does it make any difference if A1 and B1 are 128 kbit/s link-share only, or 64 kbit/s real-time and 128 kbit/s link-share, and if so, what difference? If I use the seperate real-time curve to increase priorities of classes, why would I need "curves" at all? Why is not real-time a flat value and link-share also a flat value? Why are both curves? The need for curves is clear in the original paper, because there is only one attribute of that kind per class. But now, having three attributes (real-time, link-share, and upper-limit) what for do I still need curves on each one? Why would I want the curves shape (not average bandwidth, but their slopes) to be different for real-time and link-share traffic? According to the little documentation available, real-time curve values are totally ignored for inner classes (class A and B), they are only applied to leaf classes (A1, A2, B1, B2). If that is true, why does the ALTQ HFSC sample configuration (search for 3.3 Sample configuration) set real-time curves on inner classes and claims that those set the guaranteed rate of those inner classes? Isn't that completely pointless? (note: pshare sets the link-share curve in ALTQ and grate the real-time curve; you can see this in the paragraph above the sample configuration). Some tutorials say the sum of all real-time curves may not be higher than 80% of the line speed, others say it must not be higher than 70% of the line speed. Which one is right or are they maybe both wrong? One tutorial said you shall forget all the theory. No matter how things really work (schedulers and bandwidth distribution), imagine the three curves according to the following "simplified mind model": real-time is the guaranteed bandwidth that this class will always get. link-share is the bandwidth that this class wants to become fully satisfied, but satisfaction cannot be guaranteed. In case there is excess bandwidth, the class might even get offered more bandwidth than necessary to become satisfied, but it may never use more than upper-limit says. For all this to work, the sum of all real-time bandwidths may not be above xx% of the line speed (see question above, the percentage varies). Question: Is this more or less accurate or a total misunderstanding of HSFC? And if assumption above is really accurate, where is prioritization in that model? E.g. every class might have a real-time bandwidth (guaranteed), a link-share bandwidth (not guaranteed) and an maybe an upper-limit, but still some classes have higher priority needs than other classes. In that case I must still prioritize somehow, even among real-time traffic of those classes. Would I prioritize by the slope of the curves? And if so, which curve? The real-time curve? The link-share curve? The upper-limit curve? All of them? Would I give all of them the same slope or each a different one and how to find out the right slope? I still haven't lost hope that there exists at least a hand full of people in this world that really understood HFSC and are able to answer all these questions accurately. And doing so without contradicting each other in the answers would be really nice ;-)

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  • Does anyone really understand how HFSC scheduling in Linux/BSD works?

    - by Mecki
    I read the original SIGCOMM '97 PostScript paper about HFSC, it is very technically, but I understand the basic concept. Instead of giving a linear service curve (as with pretty much every other scheduling algorithm), you can specify a convex or concave service curve and thus it is possible to decouple bandwidth and delay. However, even though this paper mentions to kind of scheduling algorithms being used (real-time and link-share), it always only mentions ONE curve per scheduling class (the decoupling is done by specifying this curve, only one curve is needed for that). Now HFSC has been implemented for BSD (OpenBSD, FreeBSD, etc.) using the ALTQ scheduling framework and it has been implemented Linux using the TC scheduling framework (part of iproute2). Both implementations added two additional service curves, that were NOT in the original paper! A real-time service curve and an upper-limit service curve. Again, please note that the original paper mentions two scheduling algorithms (real-time and link-share), but in that paper both work with one single service curve. There never have been two independent service curves for either one as you currently find in BSD and Linux. Even worse, some version of ALTQ seems to add an additional queue priority to HSFC (there is no such thing as priority in the original paper either). I found several BSD HowTo's mentioning this priority setting (even though the man page of the latest ALTQ release knows no such parameter for HSFC, so officially it does not even exist). This all makes the HFSC scheduling even more complex than the algorithm described in the original paper and there are tons of tutorials on the Internet that often contradict each other, one claiming the opposite of the other one. This is probably the main reason why nobody really seems to understand how HFSC scheduling really works. Before I can ask my questions, we need a sample setup of some kind. I'll use a very simple one as seen in the image below: Here are some questions I cannot answer because the tutorials contradict each other: What for do I need a real-time curve at all? Assuming A1, A2, B1, B2 are all 128 kbit/s link-share (no real-time curve for either one), then each of those will get 128 kbit/s if the root has 512 kbit/s to distribute (and A and B are both 256 kbit/s of course), right? Why would I additionally give A1 and B1 a real-time curve with 128 kbit/s? What would this be good for? To give those two a higher priority? According to original paper I can give them a higher priority by using a curve, that's what HFSC is all about after all. By giving both classes a curve of [256kbit/s 20ms 128kbit/s] both have twice the priority than A2 and B2 automatically (still only getting 128 kbit/s on average) Does the real-time bandwidth count towards the link-share bandwidth? E.g. if A1 and B1 both only have 64kbit/s real-time and 64kbit/s link-share bandwidth, does that mean once they are served 64kbit/s via real-time, their link-share requirement is satisfied as well (they might get excess bandwidth, but lets ignore that for a second) or does that mean they get another 64 kbit/s via link-share? So does each class has a bandwidth "requirement" of real-time plus link-share? Or does a class only have a higher requirement than the real-time curve if the link-share curve is higher than the real-time curve (current link-share requirement equals specified link-share requirement minus real-time bandwidth already provided to this class)? Is upper limit curve applied to real-time as well, only to link-share, or maybe to both? Some tutorials say one way, some say the other way. Some even claim upper-limit is the maximum for real-time bandwidth + link-share bandwidth? What is the truth? Assuming A2 and B2 are both 128 kbit/s, does it make any difference if A1 and B1 are 128 kbit/s link-share only, or 64 kbit/s real-time and 128 kbit/s link-share, and if so, what difference? If I use the seperate real-time curve to increase priorities of classes, why would I need "curves" at all? Why is not real-time a flat value and link-share also a flat value? Why are both curves? The need for curves is clear in the original paper, because there is only one attribute of that kind per class. But now, having three attributes (real-time, link-share, and upper-limit) what for do I still need curves on each one? Why would I want the curves shape (not average bandwidth, but their slopes) to be different for real-time and link-share traffic? According to the little documentation available, real-time curve values are totally ignored for inner classes (class A and B), they are only applied to leaf classes (A1, A2, B1, B2). If that is true, why does the ALTQ HFSC sample configuration (search for 3.3 Sample configuration) set real-time curves on inner classes and claims that those set the guaranteed rate of those inner classes? Isn't that completely pointless? (note: pshare sets the link-share curve in ALTQ and grate the real-time curve; you can see this in the paragraph above the sample configuration). Some tutorials say the sum of all real-time curves may not be higher than 80% of the line speed, others say it must not be higher than 70% of the line speed. Which one is right or are they maybe both wrong? One tutorial said you shall forget all the theory. No matter how things really work (schedulers and bandwidth distribution), imagine the three curves according to the following "simplified mind model": real-time is the guaranteed bandwidth that this class will always get. link-share is the bandwidth that this class wants to become fully satisfied, but satisfaction cannot be guaranteed. In case there is excess bandwidth, the class might even get offered more bandwidth than necessary to become satisfied, but it may never use more than upper-limit says. For all this to work, the sum of all real-time bandwidths may not be above xx% of the line speed (see question above, the percentage varies). Question: Is this more or less accurate or a total misunderstanding of HSFC? And if assumption above is really accurate, where is prioritization in that model? E.g. every class might have a real-time bandwidth (guaranteed), a link-share bandwidth (not guaranteed) and an maybe an upper-limit, but still some classes have higher priority needs than other classes. In that case I must still prioritize somehow, even among real-time traffic of those classes. Would I prioritize by the slope of the curves? And if so, which curve? The real-time curve? The link-share curve? The upper-limit curve? All of them? Would I give all of them the same slope or each a different one and how to find out the right slope? I still haven't lost hope that there exists at least a hand full of people in this world that really understood HFSC and are able to answer all these questions accurately. And doing so without contradicting each other in the answers would be really nice ;-)

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  • Linux HA cluster w/Xen, Heartbeat, Pacemaker. domU does not failover to secondary node

    - by Kendall
    I am having the followig problem with an OenSuSE + Heartbeat + Pacemaker + Xen HA cluster: when the node a Xen domU is running on is "dead" the Xen domU running on it is not restarted on the second node. The cluster is setup with two nodes, each running OpenSuSE-11.3, Heartbeat 3.0, and Pacemaker 1.0 in CRM mode. For storage I am using a LUN on an iSCSI SAN device; the LUN is formatted with OCFS2 and managed with LVM. The Xen domU has two logical volumes; one for root and the other for swap. I am using IPMI cards for STONITH devices, and a dedicated ethernet link for heartbeat communications. The ha.cf file is as follows: keepalive 1 deadtime 10 warntime 5 udpport 694 ucast eth1 auto_failback off node dhcp-166 node stage use_logd yes crm yes My resources look as follows: shocrm(live)configure# show node $id="5c1aa924-bba4-4f95-a367-6c9a58ac4a38" dhcp-166 node $id="cebc92eb-af24-4833-aaf0-672adf80b58e" stage primitive Xen-Util ocf:heartbeat:Xen \ meta target-role="Started" \ operations $id="Xen-Util-operations" \ op start interval="0" timeout="60" start-delay="0" \ op stop interval="0" timeout="120" \ params xmfile="/etc/xen/vm/xen-util" primitive my-stonith stonith:external/ipmi \ params hostname="dhcp-166" ipaddr="192.168.3.106" userid="ADMIN" passwd="xxx" \ op monitor interval="2m" timeout="60s" primitive my-stonith2 stonith:external/ipmi \ params hostname="stage" ipaddr="192.168.3.105" userid="ADMIN" passwd="xxx" \ op monitor interval="2m" timeout="60s" property $id="cib-bootstrap-options" \ dc-version="1.0.9-89bd754939df5150de7cd76835f98fe90851b677" \ cluster-infrastructure="Heartbeat" The Xen domU config file is as follows: name = "xen-util" bootloader = "/usr/lib/xen/boot/domUloader.py" #bootargs = "xvda1:/vmlinuz-xen,/initrd-xen" bootargs = "--entry=xvda1:/boot/vmlinuz-xen,/boot/initrd-xen" memory = 4096 disk = [ 'phy:vg_xen/xen-util-root,xvda1,w', 'phy:vg_xen/xen-util-swap,xvda2,w', ] root = "/dev/xvda1" vif = [ 'mac=00:16:3e:42:42:06' ] #vfb = [ 'type=vnc,vncunused=0,vnclisten=192.168.3.172' ] extra = "" Say domU "Xen-Util" is running on node "stage"; if "stage" goes down, "Xen-Util" does not restart on node "dhcp-166". It seems to want to try as an "xm list" will show it for a few seconds and if you "xm console xen-util" it will give a message like "copying /boot/kernel.gz from xvda1 to /var/lib/xen/tmp/kernel.a53gs for booting". However, it never gets past that, eventually gives up, and no longer appears in "xm list". Now, when node "stage" comes back online after being power cycled, it detects that "Xen-Util" isn't running, and starts it (on stage). I've tried starting "Xen-Util" on node "dhcp-166" without the cluster running, and it works fine. No problems. So, I know it works in that respect. Any ideas? Thanks!

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  • Can't install NPM after installing Node on EC2 Linux instance?

    - by frequent
    I'm trying my first attempt on getting a node server set up on an amazon ec2 linux instance. I think I made it quite far. First problem I ran into was when trying to make Node the connection timed out after a while, so I need three attempts until I got this: LINK(target) /home/ec2-user/node/out/Release/node: Finished touch /home/ec2-user/node/out/Release/obj.target/node_dtrace_header.stamp touch /home/ec2-user/node/out/Release/obj.target/node_dtrace_provider.stamp touch /home/ec2-user/node/out/Release/obj.target/node_dtrace_ustack.stamp touch /home/ec2-user/node/out/Release/obj.target/node_etw.stamp make[1]: Leaving directory `/home/ec2-user/node/out' ln -fs out/Release/node node Which tells me, "Node is done", although I'm not sure it is also working as it should. Following this,this and this tutorial, I'm now stuck at installing npm. I think I first cloned into the wrong folder, which always gave me error 127, but even if I'm doing this: cd ~ git clone git://github.com/isaacs/npm.git cd npm sudo -s PATH=/usr/local/bin:$PATH make install I'm still getting this: #after cloning# make[1]: Entering directory `/root/npm' node cli.js install bash: node: command not found make[1]: *** [node_modules/.bin/ronn] Error 127 make[1]: Leaving directory `/root/npm' make: *** [man/man3/start.3] Error 2 Question:: Since I'm pretty much a newby at everything I'm trying here, can someone please tell me what I'm doing wrong and how to get npm to install? Also, in case I cloned into the wrong folder, is there a way to remove the "false clone" or is this not written to disk until I call make install and I don't need to worry? Thanks for helping out!

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  • Is it possible to be a professional studying on your own?

    - by Marc Jr
    I read economics at university(nothing to see with linux, isn't it? :P). I have some basic knowledge about booting process, Linux Kernel compiling from source and stuff like that. But of course I have still much to learn sometimes some errors appears and "voila" I am lost. I had: Ubuntu, Fedora, OpenSuse, Arch.. using Gentoo now. I'd like to know what you linux users, professionals, administrators... would think it is the best way to learn linux in a professional way. Is it worth studying it and passing the LPIC test enough to work in the linux world? or do I need going to IT uni? I've heard LFS is a good way of learning about linux, is that real? I've been thinking about getting to LFS learn about more deeply about the linux process and learning scripts. It is possible to do this way? if anyone has a tip or a good way of doing, maybe someone did it. Any tip is very welcome. Words from a person in love with linux. :D The best, Marc

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  • Why am I seeing MailSlot Browse messages on unrouted ports of my Linux box?

    - by nmichaels
    I have a Linux box (Debian squeeze) with several NICs. The ones of interest are: eth3 - my main link to the network (dhcp on 10.20.30.0/24) eth0 - the first connection to my test network (static: 192.168.1.2) eth4 - the second connection to my test network (static: 192.168.1.1) My routing table looks like this: $ sudo route Kernel IP routing table Destination Gateway Genmask Flags Metric Ref Use Iface 10.20.30.0 * 255.255.255.0 U 0 0 0 eth3 default 10.20.30.254 0.0.0.0 UG 0 0 0 eth3 I have the 2 test net ports connected to each other with a crossover cable and an instance of wireshark running on each port. Every once in a while, I'll see a packet like the following show up. Who could be doing this, and how do I convince them to stop? I do have Samba running on the machine (for a cifs mount) but don't see why it would be sending packets out to unrouted ports. I had a Windows VM running in VMWare Client and thought that might be causing it, but it still happens without it. What I want is totally silent interfaces so I can run some tests with Scapy over them.

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  • Why is my filesystem being mounted read-only in linux?

    - by Tim
    I am trying to set up a small linux system based on Gentoo on a VirtualBox machine, as a step towards deploying the same system onto a low-spec Single Board Computer. For some reason, my filesystem is being mounted read-only. In my /etc/fstab, I have: /dev/sda1 / ext3 defaults 0 0 none /proc proc defaults 0 0 none /sys sysfs defaults 0 0 none /dev/shm tmpfs defaults 0 0 However, once booted /proc/mounts shows rootfs / rootfs rw 0 0 /dev/root / ext3 ro,relatime,errors=continue,barrier=0,data=writeback 0 0 proc /proc proc rw,nosuid,nodev,noexec,relatime 0 0 sysfs /sys sysfs rw,nosuid,nodev,noexec,relatime 0 0 udev /dev tmpfs rw,nosuid,relatime,size=10240k,mode=755 0 0 devpts /dev/pts devpts rw,nosuid,noexec,relatime,gid=5,mode=620 0 0 none /dev/shm tmpfs rw,relatime 0 0 usbfs /proc/bus/usb usbfs rw,nosuid,noexec,relatime,devgid=85,devmode=664 0 0 binfmt_misc /proc/sys/fs/binfmt_misc binfmt_misc rw,nosuid,nodev,noexec,relatime 0 0 (the above may contain errors: there's no practical way to copy and paste) The partition at /dev/hda1 is clearly being mounted OK, since I can read all the data, but it's not being mounted as described in fstab. How might I go about diagnosing / resolving this? Edit: I can remount with mount -o remount,rw / and it works as expected, except that /proc/mounts reports /dev/root mounted at / rather than /dev/sda1 as I'd expect. If I try to remount with mount -a I get mount: none already mounted or /sys busy mount: according to mtab, sysfs is already mounted on /sys Edit 2: I resolved the problem with mount -a (the same error was occuring during startup, it turned out) by changing the sysfs and proc lines to proc /proc proc [...] sysfs /sys sysfs [...] Now mount -a doesn't complain, but it doesn't result in a read-write root partition. mount -o remount / does cause the root partition to be remounted, however.

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  • How can I set the CD audio volume in Linux?

    - by user1296362
    In Windows 7 Control Panel - Sound - Sound Properties window there's an slider for setting CD Audio volume: And it's pretty strange that I can't find corresponding one in generic Linux mixers: alsamixer or amixer. I connected a CD drive to try to set CD audio volume with cdcd (CD Player): $ cdcd setvol 0 Invalid volume It isn't actually an invalid volume, it is because ioctl() call fails. I found that out after searching and changing a bit the source code of this utility (in the libcdaudio): --- cdaudio.c.orig 2004-09-09 06:26:20.000000000 +0600 +++ cdaudio.c 2012-05-30 21:34:34.167915521 +0600 @@ -578,8 +578,10 @@ cdvol_data.CDVOLCTRL_BACK_RIGHT_SELECT = CDAUDIO_MAX_VOLUME; #endif - if(ioctl(cd_desc, CDAUDIO_SET_VOLUME, &cdvol) < 0) - return -1; + if(ioctl(cd_desc, CDAUDIO_SET_VOLUME, &cdvol) < 0) { + printf("*** cd_set_volume: ioctl() returned error\n"); + return -1; + } return 0; } By the way cdcd's get volume command yields rather weird output: Left Right Front 1281734864 32767 Back 0 0 Also I tried aumix: $ aumix -c 0 But all with no success. I read from this manual — http://tldp.org/HOWTO/Alsa-sound-6.html (section 6.2 The mixer) that CD channel can present in amixer output. Maybe some drivers for sound card are missing in my Ubuntu 12.04 LTS installation. Though I don't think it's the case: $ lsmod | grep snd snd_mixer_oss 22602 0 snd_hda_codec_hdmi 32474 1 snd_hda_codec_realtek 223867 1 snd_hda_intel 33773 4 snd_hda_codec 127706 3 snd_hda_codec_hdmi,snd_hda_codec_realtek,snd_hda_intel snd_hwdep 13668 1 snd_hda_codec snd_pcm 97188 3 snd_hda_codec_hdmi,snd_hda_intel,snd_hda_codec snd_seq_midi 13324 0 snd_rawmidi 30748 1 snd_seq_midi snd_seq_midi_event 14899 1 snd_seq_midi snd_seq 61896 2 snd_seq_midi,snd_seq_midi_event snd_timer 29990 2 snd_pcm,snd_seq snd_seq_device 14540 3 snd_seq_midi,snd_rawmidi,snd_seq snd 78855 19 snd_mixer_oss,snd_hda_codec_hdmi,snd_hda_codec_realtek,snd_hda_intel,snd_hda_codec,snd_hwdep ,snd_pcm,snd_rawmidi,snd_seq,snd_timer,snd_seq_device soundcore 15091 1 snd snd_page_alloc 18529 2 snd_hda_intel,snd_pcm All I need is just mute or set to 0 volume level of CD Audio channel, like I did in Windows 7, to get rid of sibilant noise in the speakers.

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  • Simple Linux program that takes any HTTP/HTTPS request and returns a single page?

    - by ultrasawblade
    I have a Linux box operating as router. There's a NIC that's connected to the internet (WAN), a NIC connected to an 8-port GbE switch (LAN), and a NIC connected to a Linksys wireless N-router (WLAN). Routing between everything is working perfectly. I have security completely disabled on the wireless router, but the WLAN NIC is firewalled such that it will only accept DNS queries and PPTP VPN connections. Currently HTTP/HTTPS traffic and everything else is blocked. I would like to run something that listens on port 80/443 of the WLAN NIC, and, for non VPN'ed connections, given any HTTP/HTTPS request it will return a single webpage saying "Unauthenticated" and explain how to sign into the VPN. A transparent proxy seems to be what I need, but my searches all seem to direct me to Squid, which is already running on my server and seems overkill for this simple task. Is there a simpler, lightweight program out there that does just this or should I just suck it up and run two instances of Squid (or figure out how to configure it)? Or, is this entire VPN thing I'm doing complete nonsense and I should just enable encryption on the wireless router?

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  • How do I set up a shared directory on Linux?

    - by JR Lawhorne
    I have a linux server I want to use to share files between users in my company. Users will access the machine with sftp or secure shell. Here is what I have: cd /home ls -l drwxrwsr-x 5 userA staff 4096 Jul 22 15:00 shared (other listings omitted) I want all users in the staff group to be able to create, modify, delete any file and/or directory in the shared folder. I don't want anyone else to have access to the folder at all. I have: Added the users to the staff group by modifying /etc/group and running grpconv to update /etc/gshadow Run chown -R userA.staff /home/shared Run chmod -R 2775 /home/shared Now, users in the staff group can create new files but they aren't allowed to open the existing files in the directory for edit. I suspect this is due to the primary group id associated with each user which is still set to be the group created when the user was created. So, the PGID of user 'userA' is 'userA'. I'd rather not change the primary group of the users to 'staff' if I can help it but if it is the easiest option, I would consider it. And, a variation on a theme, I'd like to do this same thing with another directory but also allow the apache user to read files in the directory and serve them. What's the best way to set this up?

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