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  • How to use the Zend_Log instance that was created using the Zend_Application_Resource_Log in a model

    - by Alex
    Our Zend_Log is initialized by only adding the following lines to application.ini resources.log.stream.writerName = "Stream" resources.log.stream.writerParams.mode = "a" So Zend_Application_Resource_Log will create the instance for us. We are already able to access this instance in controllers via the following: public function getLog() { $bootstrap = $this->getInvokeArg('bootstrap'); //if (is_null($bootstrap)) return false; if (!$bootstrap->hasPluginResource('Log')) { return false; } $log = $bootstrap->getResource('Log'); return $log; } So far, so good. Now we want to use the same log instance in model classes, where we can not access the bootstrap. Our first idea was to register the very same Log instance in Zend_Registry to be able to use Zend_Registry::get('Zend_Log') everywhere we want: in our Bootstrap class: protected function _initLog() { if (!$this->hasPluginResource('Log')) { throw new Zend_Exception('Log not enabled'); } $log = $this->getResource('Log'); assert( $log != null); Zend_Registry::set('Zend_Log', $log); } Unfortunately this assertion fails == $log IS NULL --- but why?? It is clear that we could just initialize the Zend_Log manually during bootstrapping without using the automatism of Zend_Application_Resource_Log, so this kind of answers will not be accepted.

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  • symfony 2.0 stable enough to use?

    - by fayer
    i wonder if symfony 2.0 is stable enough to use? cause i never used symfony before. it seems that symfony 2 is much more better than the previous version and i dont want to relearn/recode everything some months from now. when do you think symfony 2.0 will be released? will it be a wise choice to use 2.0 now?

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  • how to use multiple $_name using extends Zend_Db_Table_Abstract in zend frame work.

    - by karthik
    we tried to do like this,but it is showing some errors.Our table names are users and messages. <?php class Application_Model_childconnect1 extends Zend_Db_Table_Abstract { protected $_name = 'users'; public function loginvalidation($username,$pwd) { $row = $this->fetchRow('UserName = \'' . $username . '\'and UserPW = \''. $pwd . '\''); if (!$row) { $msg="invalid"; return $msg; } else { return $row->toArray(); } } protected $_name = 'messages'; public function replymessage($message) { $data=array( 'MessageText'=>$message ); $this->insert($data); } }

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  • [WM 6.5 / C#] Send SMS AND copy them into the "sent messages" folder

    - by netblognet
    Hello, I'm developing an application for windows mobile 6.5. Im writing the code in c#.net and want to send sms due to my app. I checked out the POOM and sms sending worked fine. Code: SmsMessage msg = new SmsMessage(); msg.To.Add(receiver); msg.Body = messageText; msg.Send(); But there's one problem. I want that the messages will be saved/copied to the "send messages" folder, after my program has sent them. How can I realize that. Is it possible with the POOM, oder should I work with MAPI and generate a converted copy of the msg-Object in the "send messages"-folder? greets, raffi

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  • zend one controller many views

    - by Sherif
    hi there when i build my web site it was handling only one interface but now i need to handle many interface i can detect which site to communicate and isolate it from other sites but i stuck with this : all the sites have the same views ... is there are a way so i can rander from the same controller different views .. something like application application controller model site_1_view site_2_view is this possible ??!!

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  • how to add multiple modules to a single page in digitalus

    - by jspeshu
    when i do some thing like this i can see the module <div id='search' class="module"> <digitalusControl type='moduleSelector' id='module' label="searchM" group='mods' /> </div> but i want to have two modules so i make something like this <div id='search' class="module"> <digitalusControl type='moduleSelector' id='modulesearch' label="searchM" group='mods' /> </div> <div id='search' class="module"> <digitalusControl type='moduleSelector' id='modulenews' label="newsM" group='mods' /> </div> plz help how can i create multiple modules since i can't create another element "digitalusControl" with id "module" i really need this plz help EDIT: even worse a template with only one module, this single line is not working for me

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  • ETA on Smart Device Projects for Visual Studio 2010

    - by Vaccano
    I really want to upgrade to Visual Studio 2010. But since I do a lot of development for the Pocket PC version of Windows Mobile I cannot. (I develop for a Symbol device that does not support Windows Phone 7, so that is not a option.) Does any one know any kind of time frame of when Microsoft plans to add support for Smart Device Projects into Visual Studio 2010

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  • Using Google's Contacts API's, how can I get the user's name and gmail address?

    - by chris
    I know how to get the entire contacts list using Google Contacts API (I get a session token and use Google's Zend package for PHP). But how can I get the person's name and email address? Currently, the Contacts API just seems to give all of the contacts. I'm not sure how to distinguish which email and name out of that list corresponds to the user's account. Is there an easy way to get the user's full name and email address? Any help would be useful. Thanks!

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  • Not enough storage is available to complete this operation - Program or Storage memory?

    - by Grant Crofton
    I've been given a Windows Mobile app written in .Net CF 3.5 to fix, and one of the problems is to do with storage. The message 'Not enough storage is available to complete this operation' has appeared a few times - it's logged in the SQL CE database, and always happens during data access (but not the same bit of data access). The thing I'm slightly confused about is whether this refers to Program Memory (e.g. RAM) or Storage Memory (e..g permanent storage). It would appear to be storage memory, but the devices seem to have plenty free. While there are some OutOfMemoryExceptions, these appear totally unrelated to this problem (in that that happen at a different time due to an image-related issue). We're using SQL CE 3.5 with a single connection, which is stored along with the app on the device (as opposed to the storage card). The device is a Motorola MC75 running Windows Mobile 6.1. Any thoughts?

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  • How to get the Displayed Webpage source

    - by Shadow
    Hi, how can i get the web-page source displayed on a web-browser control, either in c# or Win32.even ATL COM also fine. i mean.. i dont want to create new "HTTPReqest" or "openURL" to get source.. i want to get the source from the control only..is it possible for windows mobile.. if so how?.. please let me know. Thank u

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  • Zend Form - How to set values on sub form elements?

    - by Zend_Sklave
    array 'subQuantity' => array 'quantity_6' => string '23' (length=2) 'quantity_16' => string '23' (length=2) 'quantity_18' => string '23' (length=2) 'update' => string 'Update' (length=6) Good day! I just created a subform from my existing zend form and procures this data when form submits. Based on posted data (the quantity_ elements), I would like to set the values to subform elements. Is it possible? Thanks in advance. cheers and happy coding!

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  • trying to show a variable in my layout

    - by user1400
    hi i have a simple question where is my code wrong ? in index controller and index action i put $this->view->username="user1"; and when i try in my layout i use echo $this->username; i got fllowing error or null value Notice: Trying to get property of non-object in D:\Zend\Apache2\htdocs\test\application\layouts\layout.phtml on line 115 thanks

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  • Zend_Dojo_Form not rendering in layout

    - by Grant Collins
    Hi, I have a quick question about adding Zend_Dojo_Form into Zend_layouts. I have a Zend_Dojo_Form that I want to display in the layout that is used for a particular controller. I can add the form to the layout without any issue however the dojo elements fail to render, as they would do if I added the form to a standard view. Is there any reason why this would be the case? Do I need to do something to the layout so that it will enable the components for this embedded form in the layout. Any other dojo enabled forms that are added in the view using this layout work fine. My form is created in the usual way: class QuickAddJobForm extends Zend_Dojo_Form{ public function init(){ $this->setName('quickaddjobfrm') ->setMethod('post') ->setAction('/addjob/start/); /*We now create the elements*/ $jobTitle = new Zend_Dojo_Form_Element_TextBox('jobtitle', array( 'trim' => true ) ); $jobTitle->setAttrib('style', 'width:200px;') ->addFilter('StripTags') ->removeDecorator('DtDdWrapper') ->removeDecorator('HtmlTag') ->removeDecorator('Label'); .... $this->addElements(array($jobTitle, ....)); In the controller I declare the layout and the form in the init function: public function init(){ $this->_helper->layout->setLayout('add-layout'); $form = new QuickAddJobForm(); $form->setDecorators(array(array('ViewScript', array('viewScript' => 'quickAddJobFormDecorator.phtml')))); $this->_helper->layout()->quickaddjob = $form; In my layout Where I want the form I have: echo $this->layout()->quickaddjob; Why would adding this form in the layout fail to render/add the Dojo elements? All that is currently being displayed are text boxes, rather than some of the other components such as ComboBoxes/FilteringSelects etc... Thanks in advance.

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  • Defining a function to a Row

    - by Siedrix
    Hi, im making an application and i need to implement diferent level of user permits. I coul have the function $this->view->users->hasPermits($this->view->user); By declaring a function on the model, an things could be easy to implement. But i would like to be able to have the next function doing the same: $this->view->user->hasPermits(); Is there a way to do this? do i need to extend the Zend_Db_Table_Row class? any ideas?

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  • Zend_Controller_Router_Route_Chain more routes - more problems

    - by epmspec
    When i use only langRoute and moduleRoute i have not any problems. But when i add pageRoute it is not work properly. I have tried many another ways do it (Regex etc) but none gives the desired result. Can anybody help me? $front = Zend_Controller_Front::getInstance(); $router = $front->getRouter(); //Route_page needs dispatcher and request $dispatcher = $front->getDispatcher(); $request = $front->getRequest(); // Add languag routes $langRoute = new Zend_Controller_Router_Route_Hostname( ':language.domain.com', array( 'language' => 'ru', ), array( 'language' => '^(ru|en)$', ) ); // Add module routes $moduleRoute = new Zend_Controller_Router_Route_Module(array(),$dispatcher,$request); // Add page routes $pageRoute = new Zend_Controller_Router_Route( ':uri\.html', array( 'controller' => 'index', 'module' => 'default', 'action' => 'index', 'uri' => 'index', ), array ('uri' => '[0-9a-z\-]+') ); // Add chain routes $chainedRoute = new Zend_Controller_Router_Route_Chain(); $chainedRoute->chain($pageRoute); $chainedRoute->chain($langRoute)->chain($moduleRoute); $router->addRoute('default', $chainedRoute);

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  • Trying to understand the Zend_Auth OpenId

    - by Will Olbrys
    I'm using a slightly modified version of the Zend_Auth_OpenId classes to get openid logins from google apps. The results are very positive, as I seem to be getting successful results from Google. I cannot get successful results passed to Zend_Auth, though. For example, Zend_Auth_Adapter_OpenId on line 241: if (!$consumer->login($id, $this->_returnTo, $this->_root, $this->_extensions, $this->_response)) { return new Zend_Auth_Result( Zend_Auth_Result::FAILURE, $id, array("Authentication failed", $consumer->getError())); } The consumer calls login() which in turn calls the private method _checkId() in Zend_OpenId_Consumer. _checkId() always ends in redirecting to the openid server. How is this ever supposed to return a valid Zend_Auth_Result object? I'm pretty close to giving up and trying to implement another OpenId library, but I'm so close to just making this work. I must be missing something so obvious! Maybe I don't understand how openid works exactly, but if someone could help me understand I would really appreciate it.

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