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  • MySQL - generate numbers for a group of results

    - by FreeIX
    I need a query to return this result: +---------+-----+-------+ | ref_nid | nid | delta | +---------+-----+-------+ | AA | 97 | 1 | | BB | 97 | 2 | | CC | 97 | 3 | | DD | 98 | 1 | | EE | 98 | 2 | | FF | 98 | 3 | +---------+-----+-------+ However, I do not have the delta column. I need to generate it for each nid group. In other words, I need an auto incremented number for each group of the result.

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  • getting rows which including a value with mysql

    - by sundowatch
    I have a mysq query which gets including some vars like that: messages TABLE receiver cols user1 rows : 1,3,5 user2 rows : 2,3 user3 rows : 1,4 I want to get rows which includes '3' value. So I will get 'user1' and 'user2'. I tried that but naturally it doesn't work. mysql_query("SELECT * FROM messages WHERE receiver='3'"); How can I do this?

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  • PHP & MySQL query value question.

    - by space
    How can I use the first query's id value $row['id'] again after I run a second query inside the while loop statement? To show you what I mean here is a sample code below of what I'm trying to do. I hope I explained it right. Here is the code. $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT users.* FROM users WHERE user_id = 4"); if (!$dbc) { // There was an error...do something about it here... print mysqli_error($mysqli); } while($row = mysqli_fetch_assoc($dbc)) { echo '<div>User: ' . $row['id'] . '</div>'; echo '<div>Link To User' . $row['id'] . '</div>'; $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc2 = mysqli_query($mysqli,"SELECT COUNT(cid) as num FROM comments WHERE comments_id = $row[id]"); if (!$dbc2) { // There was an error...do something about it here... print mysqli_error($mysqli); } else { while($row = mysqli_fetch_array($dbc2)){ $num = $row['num']; } } echo '<div>User ' . $row['id'] . ' Comments# ' . $num . '</div>'; }

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  • MySQL: Query Cacheing (How do I use memcache?)

    - by Rachel
    I have an query like: SELECT id as OfferId FROM offers WHERE concat(partycode, connectioncode) = ? AND CURDATE() BETWEEN offer_start_date AND offer_end_date AND id IN ("121211, 123341,151512,5145626 "); Now I want to cache the results of this query using memcache and so my question is How can I cache an query using memcache. I am currently using CURDATE() which cannot be used if we want to implement caching and so how can I get current date functionality without using CURDATE() function ?

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  • MySQL select column length in php

    - by Patrick
    Hello! How do i get the actual max length of a specified column in php? For instance, this table: id - int(11) name - string(20) I want in php to select the maximum number of characters that a field can have, like SELECT length(name) from table1 and it should then return 20 (since its the maximum number of characters for that field).

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  • Problem with multi-table MySQL query

    - by mahle
    I have 3 tables. Here is the relevant information needed for each. items prod_id order_id item_qty orders order_id order_date order_status acct_id accounts acct_id is_wholesale items is linked to order by the order_id and orders is linked to accounts via acct_id I need to sum item_qty for all items where prod_id=464 and the order stats is not 5 and where the is_wholesale is 0 and the order_date is between two dates. Im struggling with this and would appreciate any help. Here is what I have but it's not working correctly: SELECT SUM(items.item_qty) as qty FROM items LEFT JOIN orders ON orders.order_id = items.order_id LEFT JOIN accounts on orders.acct_id = accounts.acct_id WHERE items.prod_id =451 AND orders.order_date >= '$from_date' AND orders.order_date <= '$to_date' AND orders.order_status <>5 AND accounts.is_wholesale=0; Again, any help would be greatly appreciated!

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  • Install mySQL data using ftp?

    - by Jane
    I am trying to install magento (open source e-commerce platform) sample data on my webhost. I have uploaded the file magento_sample_data.sql via ftp, and setup a new database and have assigned it to a user. How do I get the sample data into my empty database?

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  • Mysql - Join matches and non-matches

    - by jwzk
    This is related to my other question: http://stackoverflow.com/questions/2579249/managing-foreign-keys I am trying to join the table of matches and non-matches. So I have a list of interests, a list of users, and a list of user interests. I want the query to return all interests, whether the user has the interest or not (should be null in that case), only where the user = x. Every time I get the query working its only matching interests that the user specifically has, instead of all interests whether they have it or not.

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  • Mysql question about UPDATE

    - by Beck
    UPDATE counter_reports SET `counter`=`counter`+1,`date`=? WHERE report_id IN( (SELECT report_id FROM counter_reports WHERE report_name="emails_sent" AND `year`=1 ORDER BY report_id DESC LIMIT 1), (SELECT report_id FROM counter_reports WHERE report_name="emails_sent" AND `month`=1 ORDER BY report_id DESC LIMIT 1), (SELECT report_id FROM counter_reports WHERE report_name="emails_sent" AND `week`=1 ORDER BY report_id DESC LIMIT 1), (SELECT report_id FROM counter_reports WHERE report_name="emails_sent" AND `day`=1 ORDER BY report_id DESC LIMIT 1) ) Is there any alternative for such sql? I need to update(increment by 1) last counter reports for day,week,month and year. If I'm adding manually, sql works fine, but with subqueries it fails to launch. Thanks. :)

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  • MySQL LEFT JOIN issue with three WHERE statements

    - by jhat
    I am building a note taking app for myself with tag filtering functions, but am having an issue when trying to grab notes with the tags. The tag filter needs to use AND not IN, because it will help better narrow down what I am looking for. My tables are configured like this: + notes note_id | note_title | note_uid + tags tag_id | tag_title + notes_tags nt_id | nt_note_id | nt_tag_id The notes_tags table keeps track of all notes' tags. I am not worried about returning any information about tags, so here is an example LEFT JOIN I am using currently to only get notes with only 1 tag. SELECT * FROM notes_tags LEFT JOIN notes ON note_id = nt_note_id WHERE note_uid IN ( 1 ) AND nt_tag_id = 10 This query runs perfect, it grabs all of the notes with that single tag. However, I am having issues "pinpointing" my notes using a query like this: SELECT * FROM notes_tags LEFT JOIN notes ON note_id = nt_note_id WHERE note_uid IN ( 1 ) AND nt_tag_id = 10 AND nt_tag_id = 11 What am I doing wrong with the syntax?

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  • mySQL JOIN wont return results with 0 count

    - by MPC
    SELECT categories.*, COUNT(categoryID) AS kritCount FROM categories AS categories LEFT JOIN krits ON categories.id = categoryID WHERE (krits.approved = '1') GROUP BY categories.id So this works great except that it does not return a category that has a 0 count of krits in the category. It will if I remove the WHERE statement but I need the WHERE to only select the krits where the field approved = 1

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  • MySQL - JOINS (excepts)

    - by user2529899
    I'm trying to find 2 different result via JOINS. Table look like; SELECT id,member_id,registered_year FROM records; I can listing which members registered in 2012 and also in 2013 with; SELECT member_id FROM records a INNER JOIN records b ON a.member_id=b.member_id WHERE a.registered_year='2013' AND b.registered_year='2012'; But I can't list revers of It. How can I list which members were registered in 2012 but not in 2013? Thnx in advance.

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  • MYSQL: COUNT with GROUP BY, LEFT JOIN and WHERE clause doesn't return zero values

    - by Paul Norman
    Hi guys, thanks in advance for any help on this topic! I'm sure this has a very simply answer, but I can't seem to find it (not sure what to search on!). A standard count / group by query may look like this: SELECT COUNT(`t2`.`name`) FROM `table_1` `t1` LEFT JOIN `table_2` `t2` ON `t1`.`key_id` = `t2`.`key_id` GROUP BY `t1`.`any_col` and this works as expected, returning 0 if no rows are found. So does: SELECT COUNT(`t2`.`name`) FROM `table_1` `t1` LEFT JOIN `table_2` `t2` ON `t1`.`key_id` = `t2`.`key_id` WHERE `t1`.`another_column` = 123 However: SELECT COUNT(`t2`.`name`) FROM `table_1` `t1` LEFT JOIN `table_2` `t2` ON `t1`.`key_id` = `t2`.`key_id` WHERE `t1`.`another_column` = 123 GROUP BY `t1`.`any_col` only works if there is at least one row in table_1 and fails miserably returning an empty result set if there are zero rows. I would really like this to return 0! Anyone enlighten me on this? Beer can be provided in exchange if you are in London ;-)

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  • please suggest mysql query for this

    - by I Like PHP
    I HAVE TWO TABLES shown below table_joining id join_id(PK) transfer_id(FK) unit_id transfer_date joining_date 1 j_1 t_1 u_1 2010-06-05 2010-03-05 2 j_2 t_2 u_3 2010-05-10 2010-03-10 3 j_3 t_3 u_6 2010-04-10 2010-01-01 4 j_5 NULL u_3 NULL 2010-06-05 5 j_6 NULL u_4 NULL 2010-05-05 table_transfer id transfer_id(PK) pastUnitId futureUnitId effective_transfer_date 1 t_1 u_3 u_1 2010-06-05 2 t_2 u_6 u_1 2010-05-10 3 t_3 u_5 u_3 2010-04-10 now i want to know total employee detalis( using join_id) which are currently working on unit u_3 . means i want only join_id j_1 (has transfered but effective_transfer_date is future date, right now in u_3) j_2 ( tansfered and right now in `u_3` bcoz effective_transfer_date has been passed) j_6 ( right now in `u_3` and never transfered) what i need to take care of below steps( as far as i know ) <1> first need to check from table_joining whether transfer_id is NULL or not <2> if transfer_id= is NULL then see unit_id=u_3 where joining_date <=CURDATE() ( means that person already joined u_3) <3> if transfer_id is NOT NULL then go to table_transfer using transfer_id (foreign key reference) <4> now see the effective_transfer_date regrading that transfer_id whether effective_transfer_date<=CURDATE() <5> if transfer date has been passed(means transfer has been done) then return futureUnitID otherwise return pastUnitID i used two separate query but don't know how to join those query?? for step <1 ans <2 SELECT unit_id FROM table_joining WHERE joining_date<=CURDATE() AND transfer_id IS NULL AND unit_id='u_3' for step<5 SELECT IF(effective_transfer_date <= CURDATE(),futureUnitId,pastUnitId) AS currentUnitID FROM table_transfer // here how do we select only those rows which have currentUnitID='u_3' ?? please guide me the process?? i m just confused with JOINS. i think using LEFT JOIN can return the data i need, or if we use subquery value to main query? but i m not getting how to implement ...please help me. Thanks for helping me alwayz

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  • MySQL -- How to do this better?

    - by Andrew
    $activeQuery = mysql_query("SELECT count(`status`) AS `active` FROM `assignments` WHERE `user` = $user_id AND `status` = 0"); $active = mysql_fetch_assoc($activeQuery); $failedQuery = mysql_query("SELECT count(`status`) AS `failed` FROM `assignments` WHERE `user` = $user_id AND `status` = 1"); $failed = mysql_fetch_assoc($failedQuery); $completedQuery = mysql_query("SELECT count(`status`) AS `completed` FROM `assignments` WHERE `user` = $user_id AND `status` = 2"); $completed = mysql_fetch_assoc($completedQuery); There has to be a better way to do that, right? I don't know how much I need to elaborate as you can see what I'm trying to do, but is there any way to do all of that in one query? I need to be able to output the active, failed, and completed assignments, preferably in one query.

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  • MySQL table with similar column info - HELP!!!

    - by George Garman
    I have a DB with a table that is named "victim". The form that dumps the info into the table has room for two victims and therefore there is vic1_fname, vic1_lname, vic2_fname, vic2_lname, etc.. (business name, person first, person last, address, city, state, zip) a "1" and "2" of each. Now I want to search the DB and locate listed victims. This is what I have so far: $result = mysql_query( "SELECT victim.* FROM victim WHERE vic1_business_name OR vic2_business_name LIKE '%$search_vic_business_name%' AND vic1_fname OR vic2_fname LIKE '%$search_vic_fname%' AND vic1_lname OR vic2_lname LIKE '%$search_vic_lname%' AND vic1_address OR vic2_address LIKE '%$search_vic_address%' AND vic1_city OR vic2_city LIKE '%$search_vic_city%' AND vic1_state OR vic2_state LIKE '%$search_vic_state%' AND vic1_dob OR vic2_dob LIKE '%$search_vic_dob%' "); <table width="960" style="border: groove;" border=".5"> <tr><th colspan=10>You search results are listed below:</th></tr> <tr> <th>Case Number</th> <th>Business Name</th> <th>First Name</th> <th>Last Name</th> <th>DOB / Age</th> <th>Address</th> <th>City</th> <th>State</th> </tr> <?php while($row = mysql_fetch_array($result)) { ?> <tr> <td align="center"><?php print $row['vic_business_name']; ?></td> <td align="center"><?php print $row['vic_fname']; ?></td> <td align="center"><?php print $row['vic_lname']; ?></td> <td align="center"><?php print $row['vic_dob']; ?></td> <td align="center"><?php print $row['vic_adress']; ?></td> <td align="center"><?php print $row['vic_city']; ?></td> <td align="center"><?php print $row['vic_state']; ?></td> </tr> <?php } ?> </table> The info did not display in the table until I changed the table to this: <tr> <td align="center"><?php print $row['vic1_business_name']; ?></td> <td align="center"><?php print $row['vic1_fname']; ?></td> <td align="center"><?php print $row['vic1_lname']; ?></td> <td align="center"><?php print $row['vic1_dob']; ?></td> <td align="center"><?php print $row['vic1_adress']; ?></td> <td align="center"><?php print $row['vic1_city']; ?></td> <td align="center"><?php print $row['vic1_state']; ?></td> </tr> <tr> <td align="center"><?php print $row['vic2_business_name']; ?></td> <td align="center"><?php print $row['vic2_fname']; ?></td> <td align="center"><?php print $row['vic2_lname']; ?></td> <td align="center"><?php print $row['vic2_dob']; ?></td> <td align="center"><?php print $row['vic2_adress']; ?></td> <td align="center"><?php print $row['vic2_city']; ?></td> <td align="center"><?php print $row['vic2_state']; ?></td> </tr> Now it displays both rows, even if its empty. It doesn't matter if the victim was listed originally as vic1 or vic2, i just want to know if they are a victim. I hope this makes sense. I can't get it to display the way I want, line-by-line, irregardless of whether you are vic1 or vic2.

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  • mysql codeigniter active record m:m deletion

    - by sea_1987
    Hi There, I have a table 2 tables that have a m:m relationship, what I can wanting is that when I delete a row from one of the tables I want the row in the joining table to be deleted as well, my sql is as follow, Table 1 CREATE TABLE IF NOT EXISTS `job_feed` ( `id` int(11) NOT NULL AUTO_INCREMENT, `body` text NOT NULL, `date_posted` int(10) NOT NULL, PRIMARY KEY (`id`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=3 ; Table 2 CREATE TABLE IF NOT EXISTS `job_feed_has_employer_details` ( `job_feed_id` int(11) NOT NULL, `employer_details_id` int(11) NOT NULL, PRIMARY KEY (`job_feed_id`,`employer_details_id`), KEY `fk_job_feed_has_employer_details_job_feed1` (`job_feed_id`), KEY `fk_job_feed_has_employer_details_employer_details1` (`employer_details_id`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1; So what I am wanting to do is, if the a row is deleted from table1 and has an id of 1 I want the row in table to that also has that idea as part of the relationship also. I want to do this in keeping with codeigniters active record class I currently have this, public function deleteJobFeed($feed_id) { $this->db->where('id', $feed_id) ->delete('job_feed'); return $feed_id; }

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  • mysql extra columns with same name from two tables

    - by salmane
    Table 1 has columns : entry_id user_id ... Table 2 has columns : entry_id user_id ... the user_id entry is not always the same so I would like to extract both of them so I can later on compare them in my script SELECT * FROM table1 as t1 INNER JOIN table2 as t2 on t1.entry_id=t2.entry_id WHERE t1.user_id='%s' I would like to extract t1.user_id and t2.user_id ...the problem is the result array has only user_id thank you

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  • mysql: managing memory usage

    - by every_answer_gets_a_point
    i am doing a delete with a LIKE statement my keybuffer is 25m, the sort buffer size is 256k the delete has been taking over 2 hours should i increase memory usage? there are about 50 megs of data in the table from which i am deleting, thats about 500,000 rows is there anything else i can do on the adminsitration size to speed up this delete?

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  • Sort MySQL query result by a alphanumeric field

    - by Jason Shultz
    I'm querying a table in a db using php. one of the fields is a column called "rank" and has data like the following: none 1-bronze 2-silver 3-gold ... 10-ambassador 11-president I want to be able to sort the results based on that "rank" column. any results where the field is "none" get excluded, so those don't factor in. As you can already guess, right now the results are coming back like this: 1-bronze 10-ambassador 11-president 2-silver 3-gold Of course, I would like for it to be sorted so it is like the following: 1-bronze 2-silver 3-gold ... 10-ambassador 11-president Right now the query is being returned as an object. I've tried different sort options like natsort, sort, array_multisort but haven't got it to work the way I'm sure it can. I would prefer keeping the results in an object form if possible. I'm passing the data on to a view in the next step. although, it's perfectly acceptable to pass the object to the view and then do the work there. so it's not an issue after all. :) thank you for your help. i'm hoping I'm making sense.

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  • mysql query results sorting

    - by user329094
    I am calling the results form a query to a list on my site based on if the item is "downtown_hosted". This works fine but I would now like to sort that list DESC, but can't seem to get the syntax correct. Below is what I have: $result_events = mysql_query("SELECT * FROM events WHERE downtown='downtown_hosted' ORDER BY date DESC LIMIT 5 ");

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