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  • Viewing large XML files in eclipse?

    - by Paul Wicks
    I'm working on a project involving some large XML files (from 50MB to over 1GB) and it would be nice if I could view them in eclipse (simple text view is fine) without Java running out of heap space. I've tried tweaking the amount of memory available to the jvm in eclipse.ini but haven't had much success. Any ideas?

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  • XML Import how would you do it?

    - by Rico
    XML is used as one of our main integration points. it comes over by many clients at a time but too many clients importing at the same time can slow down our database to a crawl. Someone has to have solved a problem like this. I am basically using VB to parse through the data and import what i want and don't want. Is there a better way?

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  • How to merge 2 XML streams in Java by XSLT

    - by user327933
    I'd like to merge 2 XML streams (strings) in Java, necessarily by XSLT (that I could change the transformation), but the problem is that the XMLs come as a string. There are many examples, but through the files. Can this be done without saving them in files? Thanks.

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  • programming language xml reader

    - by matt
    Indentify a suitable programming language that will read the XML document and insert its contents into the database. i need help with this question i am getting really confused can some one show me and guide me thorught how to do this

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  • WP7 Return the last 7 days of data from an xml web service

    - by cvandal
    Hello, I'm trying to return the last 7 days of data from an xml web service but with no luck. Could someone please explain me to how I would accomplish this? The XML is as follows: <node> <api> <usagelist> <usage day="2011-01-01"> <traffic name="total" unit="bytes">23579797</traffic> </usage> <usage day="2011-01-02"> <traffic name="total" unit="bytes">23579797</traffic> </usage> <usage day="2011-01-03"> <traffic name="total" unit="bytes">23579797</traffic> </usage> <usage day="2011-01-04"> <traffic name="total" unit="bytes">23579797</traffic> </usage> </usagelist> </api> </node> EDIT The data I want to retrieve will be used to populate a line graph. Specificly I require the day attribute value and the traffic element value for the past 7 days. At the moment, I have the code below in place, howevewr it's only showing the first day 7 times and traffic for the first day 7 times. XDocument xDocument = XDocument.Parse(e.Result); var values = from query in xDocument.Descendants("usagelist") select new History { day = query.Element("usage").Attribute("day").Value, traffic = query.Element("usage").Element("traffic").Value }; foreach (History history in values) { ObservableCollection<LineGraphItem> Data = new ObservableCollection<LineGraphItem>() { new LineGraphItem() { yyyymmdd = history.day, value = double.Parse(history.traffic) }, new LineGraphItem() { yyyymmdd = history.day, value = double.Parse(history.traffic) }, new LineGraphItem() { yyyymmdd = history.day, value = double.Parse(history.traffic) }, new LineGraphItem() { yyyymmdd = history.day, value = double.Parse(history.traffic) }, new LineGraphItem() { yyyymmdd = history.day, value = double.Parse(history.traffic) }, new LineGraphItem() { yyyymmdd = history.day, value = double.Parse(history.traffic) }, new LineGraphItem() { yyyymmdd = history.day, value = double.Parse(history.traffic) }, }; lineGraph1.DataSource = Data; }

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  • Passing input value thru XML loop and return value

    - by Mike Dyer
    "X" is reading the form value, but it is still passing and older "var thisMarket" value. The objective is to take a zip code via HTML form: <form id="market" name="market" onSubmit="return validateZIP(this.zip.value);" method="get" action=""> <input type="text" name="zip" id="zip" value="zipcode" onfocus="if(!this._haschanged){this.value=''};this._haschanged=true;" style="float:left; width:100px; margin-top:5px;"> <input type="image" style="float:left; margin-top:5px; border: 0pt none ; width: 22px; height:17px;" src="images/nav/bottom/linkbar/btn_search_btn.gif" onClick="findLda();"> </form> The script being passed thru is: function findLda(x){ marketName = new Array(); marketURL = new Array(); zip = new Array(); zip_temp = new Array(); zipMatch = false; var shareZip = "Shared Zips"; var thisMarket = "Market value"; xmlDoc=loadXML("/_includes/market.xml"); var Offer,node; document.getElementById('market').innerHTML=''; for(var j=0; j<xmlDoc.getElementsByTagName('market').length; j++){ node = xmlDoc.getElementsByTagName('market')[j]; marketName.push(node.childNodes[3].textContent); marketURL.push(node.childNodes[5].textContent); for(var k=0; k<node.getElementsByTagName('zip').length; k++){ if(node.getElementsByTagName('zip')[k].textContent!=null){ zip_temp.push(node.getElementsByTagName('zip')[k].textContent); } } zip.push(zip_temp); zip_temp = new Array(); } //loop the zip Array to find a match for the query Zip. for(k=0; k<zip.length; k++){ for(m=0; m<zip[k].length; m++){ if(x == zip[k][m].toString()){ zipMatch=true; thisMarket=marketName[k].toString(); } } } alert(thisMarket); } The objective naturally is to take field input (A), pass it thru market.xml - initialize a loop and match a zip (B), alert the result (C). Looking for any direction with what is existing or a completely new direction. Thanks!

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  • AS3 XML problem

    - by dd
    My Flash project is made of several .swf files, one of them loads XML gallery. everything works fine on my machine, but when I upload it to the testing server gallery content doesn't load. All my paths are relative to Main swf file. I can't make them absolute URLs, b/c I have to deliver zip package. What could be wrong?

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  • Help with XML path views

    - by xmlpath
    Hi all, is there any tool that will give me a view for XML fields like so. I want something that will show me the a view like so, if i select element1 Service/Body/element1 Is there any tool for eclipse for doing the above. Thanks.

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  • c# update xml file

    - by Pila
    I want to replace a xml node that is not a child of the root element. how can I do it - not in .Net 3.5? I don't know the exact path to the node I want to replace, I get the node by XPath query like : XmlElement root = doc.DocumentElement; oldItem = root.SelectSingleNode("//Node1[@name='aaa']//Node2[Item='bbb']/Value"); how can I replace this olditem?

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  • xml schema construction

    - by amanrahahla
    in xml can any concept inhert the attribute of the main concept as an example: book( -author -title -isbn -price) and textbook as a subconcept from book can textbook take the same attribute of book and how?

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  • One log4j.xml - many scripts

    - by psed
    One of my utility jar files is used by different nix scripts, located in different categories. Problem: unable to initialize log4j framework (unable to find log4j.xml). Solution, that allows to configure logger correctly while launching jar classes by different scripts - usage of env vars and force configuring using DOMConfigurtor.configure(pathToConfXml) method. is it possible to avoid path hardcoding and configure logger inside of a script? Appreciate all your help. Thanks.

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  • update XML file

    - by Pila
    I want to replace an XML node that is not a child of the root element. How can I do it - not in .NET 3.5? I don't know the exact path to the node I want to replace, I get the node by XPath query like: XmlElement root = doc.DocumentElement; oldItem = root.SelectSingleNode("//Node1[@name='aaa']//Node2[Item='bbb']/Value"); How can I replace this old item?

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  • PHP: Proper way of using a PDO database connection in a class

    - by Cortopasta
    Trying to organize all my code into classes, and I can't get the database queries to work inside a class. I tested it without the class wrapper, and it worked fine. Inside the class = no dice. What about my classes is messing this up? class ac { public function dbConnect() { global $dbcon; $dbInfo['server'] = "localhost"; $dbInfo['database'] = "sn"; $dbInfo['username'] = "sn"; $dbInfo['password'] = "password"; $con = "mysql:host=" . $dbInfo['server'] . "; dbname=" . $dbInfo['database']; $dbcon = new PDO($con, $dbInfo['username'], $dbInfo['password']); $dbcon->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); $error = $dbcon->errorInfo(); if($error[0] != "") { print "<p>DATABASE CONNECTION ERROR:</p>"; print_r($error); } } public function authentication() { global $dbcon; $plain_username = $_POST['username']; $md5_password = md5($_POST['password']); $ac = new ac(); if (is_int($ac->check_credentials($plain_username, $md5_password))) { ?> <p>Welcome!</p> <!--go to account manager here--> <?php } else { ?> <p>Not a valid username and/or password. Please try again.</p> <?php unset($_POST['username']); unset($_POST['password']); $ui = new ui(); $ui->start(); } } private function check_credentials($plain_username, $md5_password) { global $dbcon; $userid = $dbcon->prepare('SELECT id FROM users WHERE username = :username AND password = :password LIMIT 1'); $userid->bindParam(':username', $plain_username); $userid->bindParam(':password', $md5_password); $userid->execute(); print_r($dbcon->errorInfo()); $id = $userid->fetch(); Return $id; } } And if it's any help, here's the class that's calling it: require_once("ac/acclass.php"); $ac = new ac(); $ac->dbconnect(); class ui { public function start() { if ((!isset($_POST['username'])) && (!isset($_POST['password']))) { $ui = new ui(); $ui->loginform(); } else { $ac = new ac(); $ac->authentication(); } } private function loginform() { ?> <form id="userlogin" action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post"> User:<input type="text" name="username"/><br/> Password:<input type="password" name="password"/><br/> <input type="submit" value="submit"/> </form> <?php } }

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  • HTML and PHP simple contact form.

    - by user317128
    I tried to make a simple contact form via HTML and PHP but the form doesnt seem to submit. it stays on the HTML page and doesnt post to the php form. would love someone to look over the code, thanks in advanced. simple_form.html cdoe <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Simple Feedback Form</title> </head> <body> <form action="send_simpleform.php" method="post"> <p>Your name<br /> <input name="sender_name" type="text" size="30" /></p> <p>Email<br /> <input name="sender_email" type="text" size="30" /></p> <p>Message<br /> <textarea name="message" cols="30" rows="5"></textarea></p> <input name="submit" type="button" value="Send This Form" /> </form> </body> </html> send_simpleform.php code <? if (($_POST[sender_name] == "") || ($_POST[sender_email] == "") || ($_POST[message] == "") { header("Location: simple_form.php"); exit; } $msg = "Email sent from wwwsite\n"; $msg .= "Sender's Name:\t $_POST[senders_name]\n"; $msg .= "Sender's E-mail:\t $_POST[senders_email]\n"; $msg .= "Sender's Message:\t $_POST[message]\n"; $to = "[email protected]"; $subject = "Website feedback message"; $mailheaders = "From: My web site <www.testwebsite.com>\n"; $mailherders .= "Reply to: $_POST[sender_email]\n"; $mail($to, $subject, $msg, $mailheaders); ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Simple Feedback Form Sent</title> </head> <body> <h1>The following email has been sent</h1> <p>Your Name:<br /> <? echo "$_POST[sender_name]"; ?> <p>Your Email Adress:<br /> <? echo "$_POST[sender_email]"; ?> <p>Message:<br /> <? echo "$_POST[message]"; ?> </p> </body> </html>

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  • Is this PHP/MySQL login script secure?

    - by NightMICU
    Greetings, A site I designed was compromised today, working on damage control at the moment. Two user accounts, including the primary administrator, were accessed without authorization. Please take a look at the log-in script that was in use, any insight on security holes would be appreciated. I am not sure if this was an SQL injection or possibly breach on a computer that had been used to access this area in the past. Thanks <?php //Start session session_start(); //Include DB config require_once('config.php'); //Error message array $errmsg_arr = array(); $errflag = false; //Connect to mysql server $link = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD); if(!$link) { die('Failed to connect to server: ' . mysql_error()); } //Select database $db = mysql_select_db(DB_DATABASE); if(!$db) { die("Unable to select database"); } //Function to sanitize values received from the form. Prevents SQL injection function clean($str) { $str = @trim($str); if(get_magic_quotes_gpc()) { $str = stripslashes($str); } return mysql_real_escape_string($str); } //Sanitize the POST values $login = clean($_POST['login']); $password = clean($_POST['password']); //Input Validations if($login == '') { $errmsg_arr[] = 'Login ID missing'; $errflag = true; } if($password == '') { $errmsg_arr[] = 'Password missing'; $errflag = true; } //If there are input validations, redirect back to the login form if($errflag) { $_SESSION['ERRMSG_ARR'] = $errmsg_arr; session_write_close(); header("location: http://tapp-essexvfd.org/admin/index.php"); exit(); } //Create query $qry="SELECT * FROM user_control WHERE username='$login' AND password='".md5($_POST['password'])."'"; $result=mysql_query($qry); //Check whether the query was successful or not if($result) { if(mysql_num_rows($result) == 1) { //Login Successful session_regenerate_id(); //Collect details about user and assign session details $member = mysql_fetch_assoc($result); $_SESSION['SESS_MEMBER_ID'] = $member['user_id']; $_SESSION['SESS_USERNAME'] = $member['username']; $_SESSION['SESS_FIRST_NAME'] = $member['name_f']; $_SESSION['SESS_LAST_NAME'] = $member['name_l']; $_SESSION['SESS_STATUS'] = $member['status']; $_SESSION['SESS_LEVEL'] = $member['level']; //Get Last Login $_SESSION['SESS_LAST_LOGIN'] = $member['lastLogin']; //Set Last Login info $qry = "UPDATE user_control SET lastLogin = DATE_ADD(NOW(), INTERVAL 1 HOUR) WHERE user_id = $member[user_id]"; $login = mysql_query($qry) or die(mysql_error()); session_write_close(); if ($member['level'] != "3" || $member['status'] == "Suspended") { header("location: http://members.tapp-essexvfd.org"); //CHANGE!!! } else { header("location: http://tapp-essexvfd.org/admin/admin_main.php"); } exit(); }else { //Login failed header("location: http://tapp-essexvfd.org/admin/index.php"); exit(); } }else { die("Query failed"); } ?>

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  • php slideshow sample

    - by serhio
    I try to do a simple image slideshow in php (just cycle images, no links, no other effects). after some googling I found the following in net: <HTML> <HEAD> <TITLE>Php Slideshow</TITLE> <script language="javascript"> var speed = 4000; // time picture is displayed var delay = 3; // time it takes to blend to the next picture x = new Array; var y = 0; <?php $tel=0; $tst='.jpg'; $p= "./images"; $d = dir($p); $first = NULL; while (false !== ($entry = $d->read())) { if (stristr ($entry, $tst)) { $entry = $d->path."/".$entry; print ("x[$tel]='$entry';\n"); if ($first == NULL) { $first = $entry; } $tel++; } } $d->close(); ?> function show() { document.all.pic.filters.blendTrans.Apply(); document.all.pic.src = x[y++]; document.all.pic.filters.blendTrans.Play(delay); if (y > x.length - 1) y = 0; } function timeF() { setTimeout(show, speed); } </script> </HEAD> <BODY > <!-- add html code here --> <?php print ("<IMG src='$first' id='pic' onload='timeF()' style='filter:blendTrans()' >"); ?> <!-- add html code here --> </BODY> </HTML> but it displays only the first image from the cycle. Do I something wrong? the resulting HTML page is: <HTML> <HEAD> <TITLE>Php Slideshow</TITLE> <script language="javascript"> var speed = 4000; // time picture is displayed var delay = 3; // time it takes to blend to the next picture x = new Array; var y = 0; x[0]='./images/under_construction.jpg'; x[1]='./images/BuildingBanner.jpg'; x[2]='./images/littleLift.jpg'; x[3]='./images/msfp_smbus1_01.jpg'; x[4]='./images/escalator.jpg'; function show() { document.all.pic.filters.blendTrans.Apply(); document.all.pic.src = x[y++]; document.all.pic.filters.blendTrans.Play(delay); if (y > x.length - 1) y = 0; } function timeF() { setTimeout(show, speed); } </script> </HEAD> <BODY > <!-- add html code here --> <IMG src='./images/under_construction.jpg' id='pic' onload='timeF()' style='filter:blendTrans()' ><!-- add html code here --> </BODY> </HTML>

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  • Separation of presentation and business logic in PHP

    - by Markus Ossi
    I am programming my first real PHP website and am wondering how to make my code more readable to myself. The reference book I am using is PHP and MySQL Web Development 4th ed. The aforementioned book gives three approaches to separating logic and content: include files function or class API template system I haven't chosen any of these yet, as wrapping my brains around these concepts is taking some time. However, my code has become some hybrid of the first two as I am just copy-pasting away here and modifying as I go. On presentation side, all of my pages have these common elements: header, top navigation, sidebar navigation, content, right sidebar and footer. The function-based examples in the book suggest that I could have these display functions that handle all the presentation example. So, my page code will be like this: display_header(); display_navigation(); display_content(); display_footer(); However, I don't like this because the examples in the book have these print statements with HTML and PHP mixed up like this: echo "<tr bgcolor=\"".$color."\"><td><a href=\"".$url."\">" ... I would rather like to have HTML with some PHP in the middle, not the other way round. I am thinking of making my pages so that at the beginning of my page, I will fetch all the data from database and put it in arrays. I will also get the data for variables. If there are any errors in any of these processes, I will put them into error strings. Then, at the HTML code, I will loop through these arrays using foreach and display the content. In some cases, there will be some variables that will be shown. If there is an error variable that is set, I will display that at the proper position. (As a side note: The thing I do not understand is that in most example code, if some database query or whatnot gives an error, there is always: else echo 'Error'; This baffles me, because when the example code gives an error, it is sometimes echoed out even before the HTML has started...) For people who have used ASP.NET, I have gotten somewhat used to the code-behind files and lblError and I am trying to do something similar here. The thing I haven't figured out is how could I do this "do logic first, then presentation" thing so that I would not have to replicate for example the navigation logic and navigation presentation in all of the pages. Should I do some include files or could I use functions here but a little bit differently? Are there any good articles where these "styles" of separating presentation and logic are explained a little bit more thoroughly. The book I have only has one paragraph about this stuff. What I am thinking is that I am talking about some concepts or ways of doing PHP programming here, but I just don't know the terms for them yet. I know this isn't a straight forward question, I just need some help in organizing my thoughts.

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  • Converting PHP pagination to jQuery?

    - by ClarkSKent
    Hey, I have been trying to get this pagination class that I am using to be more ajaxy - meaning when I click on the page number like page [2] the data loads, but I want to load in the data without going to a different page (HTTP request in the background, with no page reloads). Being new to both php and jquery, I am a little unsure on how to achieve this result, especially while using a php class. This is what the main page looks like by the way: <?php $categoryId=$_GET['category']; echo $categoryId; ?> <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.1/jquery.min.js"></script> <script type="text/javascript" src="jquery_page.js"></script> <?php //Include the PS_Pagination class include('ps_pagination.php'); //Connect to mysql db $conn = mysql_connect('localhost', 'root', 'root'); mysql_select_db('ajax_demo',$conn); $sql = "select * from explore where category='$categoryId'"; //Create a PS_Pagination object $pager = new PS_Pagination($conn, $sql, 3, 11, 'param1=value1&param2=value2'); //The paginate() function returns a mysql //result set for the current page $rs = $pager->paginate(); //Loop through the result set echo "<table width='800px'>"; while($row = mysql_fetch_assoc($rs)) { echo "<tr>"; echo"<td>"; echo $row['id']; echo"</td>"; echo"<td>"; echo $row['site_description']; echo"</td>"; echo"<td>"; echo $row['site_price']; echo"</td>"; echo "</tr>"; } echo "</table>"; echo "<ul id='pagination'>"; echo "<li>"; //Display the navigation echo $pager->renderFullNav(); echo "</li>"; echo "</ul>"; ?> <div id="loading" ></div> <div id="content" ></div> Would I need to do something with this part of the class?, as seen above: $pager = new PS_Pagination($conn, $sql, 3, 11, 'param1=value1&param2=value2'); Or this?: echo $pager->renderFullNav(); I don't no much about jquery,but i guess I would start it like: $("#pagination li").click(function() { Then load something maybe... I don't no. Any help on this would be great. Thanks.

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