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  • Am I making the right choice in choosing Yii as my PHP Framework?

    - by Bara
    I am about to begin development of a new website and have been doing research on PHP Frameworks. I'm not an advanced PHP developer, but I have been developing web sites and apps (in asp.net) for a few years now. My website will primarily be AJAX-based (using jQuery) and making lots of calls to web services. After some research, here's what I came up with: CakePHP: Originally started developing in this, but found it too complex. The fact that it forces you to use and learn all this new stuff just to use it was a bit daunting, so I put it aside for the time being. Zend: The performance of the framework leaves me a bit skeptical, but I heard it has great support for creating web services. I also heard it was a bit complex. CodeIgniter: No real reason for not using this one. Based on what I've read CodeIgniter and Yii are very similar, but Yii is a bit faster and doesn't have un-needed code for PHP4 (since I plan on developing exclusively in PHP5). As far as Yii, the only things that scare me about it are that it is newer than the other frameworks so it has a smaller community. It also doesn't seem to have a ton of web service support (only SOAP, from my understanding) as opposed to Zend. So my questions come down to: Should these things worry me? (not as big of a community, poor web service support) Is there anything else I should look into? Is my choice of Yii over the other frameworks ok for a primarily AJAX-based web app? Bara

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  • How can I read the value of a radio button in JavaScript?

    - by Corey
    <html> <head> <title>Tip Calculator</title> <script type="text/javascript"><!-- function calculateBill(){ var check = document.getElementById("check").value; /* I try to get the value selected */ var tipPercent = document.getElementById("tipPercent").value; /* But it always returns the value 15 */ var tip = check * (tipPercent / 100) var bill = 1 * check + tip; document.getElementById('bill').innerHTML = bill; } --></script> </head> <body> <h1 style="text-align:center">Tip Calculator</h1> <form id="f1" name="f1"> Average Service: 15% <input type="radio" id="tipPercent" name="tipPercent" value="15" /> <br /> Excellent Service: 20% <input type="radio" id="tipPercent" name="tipPercent" value="20" /> <br /><br /> <label>Check Amount</label> <input type="text" id="check" size="10" /> <input type="button" onclick="calculateBill()" value="Calculate" /> </form> <br /> Total Bill: <p id="bill"></p> </body> </html> I try to get the value selected with document.getElementById("tipPercent").value, but it always returns the value 15.

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  • what's the right way to bind sqldatasource to asp:label in asp.net 4.0?

    - by cskilbeck
    Is it possible using Eval? If so, can someone post a short fragment to illustrate? My SqlDataSource returns 1 record with 3 fields, I'd like to Format these into a string. eg: Record Field 'Name' = 'Jack' Field 'Amount' = 100 Field 'Date' = 12.02.2010 asp:Label text should end up being: Welcome Jack, last payment was 100 on 12.02.2010 if another control than asp:Label is appropriate, that would be good to know also.

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  • Declaring pointers; asterisk on the left or right of the space between the type and name?

    - by GenTiradentes
    I've seen mixed versions of this in a lot of code. (This applies to C and C++, by the way.) People seem to declare pointers in one of two ways, and I have no idea which one is correct, of if it even matters. The first way it to put the asterisk adjacent the type name, like so: someType* somePtr; The second way is to put the asterisk adjacent the name of the variable, like so: someType *somePtr; This has been driving me nuts for some time now. Is there any standard way of declaring pointers? Does it even matter how pointers are declared? I've used both declarations before, and I know that the compiler doesn't care which way it is. However, the fact that I've seen pointers declared in two different ways leads me to believe that there's a reason behind it. I'm curious if either method is more readable or logical in some way that I'm missing.

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  • How to use JQuery Validate to create a popup with all form error when the submit button is clicked?

    - by Larry
    I am using the JQuery Validation plugin for client side form validation. In addition to the colorful styling on invalid form fields, my client requires that a popup message be shown. I only want to show this message when the submit button is click because it would drive the user crazy otherwise. I tried the following code, but errorList is always empty. Anyone know the correct way to do something similar. function popupFormErrors(formId) { var validator = $(formId).validate(); var message = ''; for (var i = 0; i < validator.errorList.length - 1; i++) { message += validator.errorList[i].message + '\n'; } if (message.length > 0) { alert(message); } } $('#btn-form-submit').click(function(){ $('#form-register').submit(); popupFormErrors('#btn-form-submit'); return false; }); $('#form-register').validate({ errorPlacement: function(error, element) {/* no room on page */}, highlight: function(element) { $(element).addClass('invalid-input'); }, unhighlight: function(element) { $(element).removeClass('invalid-input'); }, ... }); Update From the info in the accepted answer I came up with this. var submitClicked = false; $('#btn-form-submit').click(function() { submitClicked = true; $('#form-register').submit(); return false; }); $('#form-register').validate({ errorPlacement: function(error, element) {/* no room on page */}, highlight: function(element) { $(element).addClass('invalid-input'); }, unhighlight: function(element) { $(element).removeClass('invalid-input'); }, showErrors: function(errorsObj) { this.defaultShowErrors(); if (submitClicked) { submitClicked = false; ... create popup from errorsObj... } } ... });

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  • What is the right software to build a directory?

    - by Cenk
    I'm trying to build a wedding-stuff related directory. I basically have a whole load of links that are sorted by 2 categories: ZIP code and type of link. Also I need the users to have the ability to rate links and leave comments. What is the best software solution to build this?

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  • jquery: adding class on to list-items only on mouseover-remove on mouse-out?

    - by user239831
    hey guys, what's the best way to do that: i have a list <ul> <li>hello</li> <li>good bye</li> <li>arrivederci</li> <li class="selected">dude</li> <li>whatever</li> </ul> Initially one item already has a class of .selected applied. When i hover over one of the list-items i want this one to have the .selected class. So every item should only have the class applied when im over, as soon as i leave the item the class get's removed and the next one has the class.

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  • how I can overcome this error C2679: binary '>>' : no operator found which takes a right-hand oper

    - by hussein abdullah
    #include <iostream> using std::cout; using std::cin; using std::endl; #include <cstring> void initialize(char[],int*); void input(const char[] ,int&); void print ( const char*,const int); void growOlder (const char [], int* ); bool comparePeople(const char* ,const int*,const char*,const int*); int main(){ char name1[25]; char name2[25]; int age1; int age2; initialize (name1,&age1); initialize (name2,&age2); print(name1,age1); print(name2,age2); input(name1,age1); input(name2,age2); print(name1,age1); print(name2,age2); growOlder(name2,&age2); if(comparePeople(name1,&age1,name2,&age2)) cout<<"Both People have the same name and age "<<endl; return 0; } void input(const char name[],int &age) { cout<<"Enter a name :"; cin>>name ; cout<<"Enter an age:"; cin>>age; cout<<endl; } void initialize ( char name[],int *age) { name[0]='\0'; *age=0; } void print ( const char name[],const int age ) { cout<<"The Value stored in variable name is :" <<name<<endl <<"The Value stored in variable age is :" <<age<<endl<<endl; } void growOlder(const char name[],int *age) { cout<< name <<" has grown one year older\n\n"; *age++; } bool comparePeople (const char *name1,const int *age1, const char *name2,const int *age2) { return(*age1==*age2 && !strcmp(name1,name2)); }

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  • How to detect a gamepad button press on OSX 10.5 and higher?

    - by Steph Thirion
    How do I detect a button press on a USB gamepad on OSX 10.5 and higher? I can't wrap my head around the ridiculously complex HID Manager (even though apparently it was simplified with 10.5), and the code samples at Apple have thousands of lines of code that would take days to understand and isolate what I need, so I'd appreciate if someone posts a simple, and fully coded solution for this isolated problem. EDIT: so far all answers are links to source code or semi obscure libraries for all kinds of HID devices, which will require more research time than what I'd like to invest on this. I am starting a bounty to get an actual snippet of code that solves this simple problem (using an external library or not). EDIT POS BOUNTY: thanks to all for you help; but unfortunately the answer that has been automatically selected by the system is not working for me, can't figure out why; and the author has not yet replied to my comments. Any insight would be appreciated, but until a fix is found, anyone looking for resources on this topic should take this answer with a pinch of salt.

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  • how do i use MySql ENUM type? (and is it right for a news feed)

    - by Haroldo
    I'm creating a table called news_feed, this will log all the actions a user performs. Lets say I want to store user1234 deleted article412 at midday I then need a table like so timestamp | user_id | subject_type | subject_id | method . there would be 5 potential methods to log, methods = add/edit/delete/update/report and lets say 2 possible subject_type subjects = article/comment I know i could make my own key where 0=add, 1=delete etc etc but this would make my queries cumbersome to use/write as i'd need to keep consulting the key. Is there a MySql type which can read lots of identially values quickly? is this ENUM? how do i use it?!!

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  • What's the right tool for this job in Google Spreadsheets?

    - by Daniel Harvey
    Is it possible to nest simple programs within a Google doc spreadsheet, similar to how you would w/Basic in Excel? Or alternatively a simple = syntax using regex, if there is a way to do that in google docs? I want to take a list of multiple names(name1, name2, name3) in a single cell from across multiple identical sheets and transpose them to another sheet within the same spreadsheet, check for duplicates and ignore capitals, etc. Is there a way to do this?

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  • Why does right shift in PHP return a negative number?

    - by Legend
    I am trying to query a bittorrent tracker and am using unpack to get the list of IPs from the response. So, something like this: $ip = unpack("N", $peers); $ip_add = ($ip[1]>>24) . "." . (($ip[1]&0x00FF0000)>>16) . "." . (($ip[1]&0x0000FF00)>>8) . "." . ($ip[1]&0x000000FF); But, for some reason, I am getting the following IP addresses when I print $ip_add: 117.254.136.66 121.219.20.250 -43.7.52.163 Does anyone know what could be going wrong?

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  • How to make a jQuery plugin (the right way)?

    - by macek
    I know there are jQuery cookie plugins out there, but I wanted to write one for the sake of better learning the jQuery plugin pattern. I like the separation of "work" in small, manageable functions, but I feel like I'm passing name, value, and options arguments around too much. Is there a way this can be refactored? I'm looking for snippets of code to help illustrate examples provided with in answers. Any help is appreciated. Thanks :) example usage $.cookie('foo', 'bar', {expires:7}); $.cookie('foo'); //=> bar $.cookie('foo', null); $.cookie('foo'); //=> undefined Edit: I did a little bit of work on this. You can view the revision history to see where this has come from. It still feels like more refactoring can be done to optimize the flow a bit. Any ideas? the plugin (function($){ $.cookie = function(name, value, options) { if (typeof value == 'undefined') { return get(name); } else { options = $.extend({}, $.cookie.defaults, options || {}); return (value != null) ? set(name, value, options) : unset(name, options); } }; $.cookie.defaults = { expires: null, path: '/', domain: null, secure: false }; var set = function(name, value, options){ console.log(options); return document.cookie = options_string(name, value, options); }; var get = function(name){ var cookies = {}; $.map(document.cookie.split(';'), function(pair){ var c = $.trim(pair).split('='); cookies[c[0]] = c[1]; }); return decodeURIComponent(cookies[name]); }; var unset = function(name, options){ value = ''; options.expires = -1; set(name, value, options); }; var options_string = function(name, value, options){ var pairs = [param.name(name, value)]; $.each(options, function(k,v){ pairs.push(param[k](v)); }); return $.map(pairs, function(p){ return p === null ? null : p; }).join(';'); }; var param = { name: function(name, value){ return name + "=" + encodeURIComponent(value); }, expires: function(value){ // no expiry if(value === null){ return null; } // number of days else if(typeof value == "number"){ d = new Date(); d.setTime(d.getTime() + (value * 24 * 60 * 60 * 1000)); } // date object else if(typeof value == "object" && value instanceof "Date") { d = value; } return "expires=" + d.toUTCString(); }, path: function(value){ return "path="+value; }, domain: function(value){ return value === null ? null : "domain=" + value; }, secure: function(bool){ return bool ? "secure" : null; } }; })(jQuery);

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  • Can I package my Eclipse extension so the right version is automatically installed?

    - by James
    Is there a way to build an Eclipse Update Site so that Eclipse 3.3 will install one version of my plug-in while Eclipse 3.4 will install another version? Background: I've become responsible for an Eclipse extension that has half a dozen plug-ins which depend on a "support" plug-in, and the support plug-in needs to be one version for Eclipse 3.3 and a different version for Eclipse 3.4/3.5. I currently have two separate features, "extension for 3.3" and "extension for 3.4+" but I'd like to not bother my users with this detail.

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  • Two Problems I'm having with UIButton and UIView.

    - by Andy
    Hi all, I haven't been programming on the iPhone for very long, but I'm picking it up slowly by googling problems I get. Unfortunately I haven't been able to find an answer for these. I have started a new View-based application in Xcode 3.2.2 and immediately added the following files: myUIView.m and myUIView.h, which are subclasses of UIView. In Interface Builder, I set the subclass of the default UIView to be myUIView. I made a button in the drawRect method. Problem one: The title of the button only appears AFTER I click the screen, why? Problem two: I want the button to produce the modalview - is this possible? The code is as follow: #import "myUIView.h" @implementation myUIView - (void)drawRect:(CGRect)rect { // Drawing code button = [UIButton buttonWithType:UIButtonTypeRoundedRect]; button.frame = CGRectMake(0,0,100,100); [button setTitle:@"butty" forState:UIControlStateNormal]; [button addTarget:self action:@selector(buttonPressed:) forControlEvents:UIControlEventTouchUpInside]; [self addSubview:button]; } -(void)buttonPressed:(id)sender{ NSLog(@"Button pressed"); //present modal view somehow..? } I can't see how to post attachments, but if anyone thinks it will help I can upload the source. Many thanks, Andy

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