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  • How do I make a class whose interface matches double, but upon which templates can be specialized?

    - by Neil G
    How do I make a class whose interface matches double, but whose templated types do not dynamic cast to double? The reason is that I have a run-time type system, and I want to be able to have a type that works just like double: template<int min_value, int max_value> class BoundedDouble: public double {}; And then inherit use template specialization to get run-time information about that type: template<typename T> class Type { etc. } template<int min_value, int max_value> class Type<BoundedDouble<min_value, max_value>> { int min() const { return min_value; } etc. } But, you can't inherit from double...

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  • How do I assign by "reference" to a class field in c#?

    - by Jamie
    I am trying to understand how to assign by "reference" to a class field in c#. I have the follwing example to consider: public class X { public X() { string example = "X"; new Y( ref example ); new Z( ref example ); System.Diagnostics.Debug.WriteLine( example ); } } public class Y { public Y( ref string example ) { example += " (Updated By Y)"; } } public class Z { private string _Example; public Z( ref string example ) { this._Example = example; this._Example += " (Updated By Z)"; } } var x = new X(); When running the above code the output is: X (Updated By Y) And not: X (Updated By Y) (Updated By Z) As I had hoped. It seems that assigning a "ref parameter" to a field loses the reference. Is there any way to keep hold of the reference when assigning to a field? Thanks.

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  • C++ Why am I unable to use an enum declared globally outside of the class it was declared in?

    - by VGambit
    Right now, my project has two classes and a main. Since the two classes inherit from each other, they are both using forward declarations. In the first object, right underneath the #include statement, I initialize two enums, before the class definition. I can use both enums just fine inside that class. However, if I try to use those enums in the other class, which inherits from the first one, I get an error saying the enum has not been declared. If I try to redefine the enum in the second class, I get a redefinition error. I have even tried using a trick I just read about, and putting each enum in its own namespace; that didn't change anything.

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  • Can I change class types in a setter with an object-oriented language?

    - by user214626
    Hello, Here is the problem statement : Calling a setter on the object should result in the object to change to an object of a different class, which language can support this ? Ex. I have a class called "Man" (Parent Class), and two children namely "Toddler" and "Old Man", they are its children because they override a behaviour in Man called as walk.( i.e Toddler sometimes walks using both his hands and legs kneeled down and the Old man uses a stick to support himself). The Man class has a attribute called age, I have a setter on Man,say it is called setAge(int ageValue). I have 3 objects, 2 toddlers, 1 old-Man. (The system is up and running,i guess when we say objects it is obvious) .I will make this call, toddler.setAge(80), I expect the toddler to change to an object of type Old Man. Is this possible.Please suggest. Thanks,

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  • jQuery: Adding class to the li element after the link is clicked, and deselecting all other classes

    - by Oleg Tarasenko
    Hi, I am generating menu with such tags: <div class="animatedtabs"> <ul> {% for item in menu_items %} <li><a href="{{ item.url }}" title="{{ item.name }}"><span>{{ item.name }}</span></a></li> {% endfor %} </ul> </div> What I want to do, I want to add class="selected" to li, after the link is clicked, and to remove all other class="selected" on other li's... Also I wonder, how to show menu in the way, so the first item is selected by default... But then when another linked is clicked, then class="selected" is toggled

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  • C# - Custom Attributes - Setting an attribute property to the type of the decorated class.

    - by cmaduro
    Is it possible to get the decorated class' type inside of the custom attribute's class? For example: [MetadataAttribute] [AttributeUsage(AttributeTargets.Class | AttributeTargets.Property, AllowMultiple = false)] public class ViewAttribute : ExportAttribute { public object TargetRegion { get; set; } public Type ViewModel { get; set; } public Type Module { get; set; } public ViewAttribute() : base(typeof(UserControl)) { Module = GetDecoratedClassType(); //I need this method } } In the following example GetDecoratedClassType() would return HomeView [View] HomeView MyHomeView { get; set; }

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  • Should enumerations be placed in a separate file or within another class?

    - by Icono123
    I currently have a class file with the following enumeration: using System; namespace Helper { public enum ProcessType { Word = 0, Adobe = 1, } } Or should I include the enumeration in the class where it's being used? I noticed Microsoft creates a new class file for DockStyle: using System; using System.ComponentModel; using System.Drawing.Design; namespace System.Windows.Forms { public enum DockStyle { None = 0, Top = 1, Bottom = 2, Left = 3, Right = 4,. Fill = 5, } }

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  • How can i encrypt a function or its contents in a php class?

    - by jane
    How can i encrypt a function or its contents in a php class ? e.g. Take a look at below class, i would like to encrypt the function test1() so the code inside will never be revealed but executes as normal class test { var $x; var $y; function test1() { return $this->x; } function test2() { return $this->y; } } Thanks in advance

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  • Why do I have to specify pure virtual functions in the declaration of a derived class in Visual C++?

    - by neuviemeporte
    Given the base class A and the derived class B: class A { public: virtual void f() = 0; }; class B : public A { public: void g(); }; void B::g() { cout << "Yay!"; } void B::f() { cout << "Argh!"; } I get errors saying that f() is not declared in B while trying do define void B::f(). Do I have to declare f() explicitly in B? I think that if the interface changes I shouldn't have to correct the declarations in every single class deriving from it. Is there no way for B to get all the virtual functions' declarations from A automatically? EDIT: I found an article that says the inheritance of pure virtual functions is dependent on the compiler: http://www.objectmentor.com/resources/articles/abcpvf.pdf I'm using VC++2008, wonder if there's an option for this.

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  • What's the Difference Between These Two Ruby Class Initialization Definitions?

    - by michaelmichael
    I'm working through a book on Ruby, and the author used a slightly different form for writing a class initialization definition than he has in previous sections of the book. It looks like this: class Ticket attr_accessor :venue, :date def initialize(venue, date) self.venue = venue self.date = date end end In previous sections of the book, it would've been defined like this: class Ticket attr_accessor :venue, :date def initialize(venue, date) @venue = venue @date = date end end Is there any functional difference between using the setter method, as in the first example, vs. using the instance variable as in the second? They both seem to work. Even mixing them up works: class Ticket attr_accessor :venue, :date def initialize(venue, date) @venue = venue self.date = date end end

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  • Resharper: how to force introducing new private fields at the bottom of the class?

    - by Igor Brejc
    Resharper offers a very useful introduce and initialize field xxx action when you specify a new parameter in a constructor like: Constructor (int parameter) The only (minor) nuisance is that it puts the new field at the beginning of the class - and I'm a fan of putting private parts as far away as possible from the prying eyes of strangers ;). If, however, you already have some private fields in the class, Resharper will put the new field "correctly" (note the quotes, I don't want to start a flame war over this issue) next to those, even if they are at the end of the class. Is there a way to force Resharper to always put new fields at the end of the class? UPDATE: OK, I forgot to mention I know about the "Type Members Layout in Options" feature, but some concrete help on how to modify the template to achieve fields placement would be nice.

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  • What's the Difference Between These Two Ruby Class Initialaztion Definitions?

    - by michaelmichael
    I'm working through a book on Ruby, and the author used a slightly different form for writing a class initialization definition than he has in previous sections of the book. It looks like this: class Ticket attr_accessor :venue, :date def initialize(venue, date) self.venue = venue self.date = date end end In previous sections of the book, it would've been defined like this: class Ticket attr_accessor :venue, :date def initialize(venue, date) @venue = venue @date = date end end Is there any functional difference between using the setter method, as in the first example vs. using the instance variable in the second? They both seem to work. Even mixing them up seems to work: class Ticket attr_accessor :venue, :date def initialize(venue, date) @venue = venue self.date = date end end

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  • Can a custom MFC window/dialog be a class template instantiation?

    - by John
    There's a bunch of special macros that MFC uses when creating dialogs, and in my quick tests I'm getting weird errors trying to compile a template dialog class. Is this likely to be a big pain to achieve? Here's what I tried: MyDlg.h template <class W> class CMyDlg : public CDialog { typedef CDialog super; DECLARE_DYNAMIC(CMyDlg <W>) public: CMyDlg (CWnd* pParent); // standard constructor virtual ~CMyDlg (); // Dialog Data enum { IDD = IDD_MYDLG }; protected: virtual void DoDataExchange(CDataExchange* pDX); // DDX/DDV support DECLARE_MESSAGE_MAP() private: W *m_pWidget; //W will always be a CDialog }; IMPLEMENT_DYNAMIC(CMyDlg<W>, super) <------------------- template <class W> CMyDlg<W>::CMyDlg(CWnd* pParent) : super(CMyDlg::IDD, pParent) { m_pWidget = new W(this); } I get a whole bunch of errors but main one appears to be: error C2955: 'CMyDlg' : use of class template requires template argument list I tried using some specialised template versions of macros but it doesn't help much, other errors change but this one remains. Note my code is all in one file, since C++ templates don't like .h/.cpp like normal. I'm assuming someone must have done this in the past, possibly creating custom versions of macros, but I can't find it by searching, since 'template' has other meanings.

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  • What is a good naming convention to differentiate a class name from a property in C#?

    - by Andy Stampor
    I run into this frequently enough that I thought I'd see what others had to say about it. Using the StyleCop conventions, I find that I often have a property name that is hard to make different than the class name it is accessing. For example: public class ProjectManager { // Stuff here } public class OtherClass { private ProjectManager ProjectManager { get; set; } } It compiles and runs, but seems like it would be an easy way to confuse things, even with the use of "this".

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  • Is there a way to check if a div has the same class as an ancestor in jQuery?

    - by T.R.
    I'm looking to dynamically highlight a tab, if it represents the current page. I have: <style> #tabs li{bg-color: white;} body.Page1 #tabs .Page1, body.Page2 #tabs .Page2, body.Page3 #tabs .Page3{bg-color: orange;} </style> <body class="Page1 ADifferentClass"> <ul id="tabs"> <li class="Page1 SomeClass"> <li class="Page2 SomeOtherClass"> <li class="Page3 AnotherClass"> </ul> </body> As you can see, there needs to be CSS for each tab, so adding another page involves modifying both the HTML and the CSS. Is there a simple (DRY) way to check if two divs have the same class already built into jQuery? I ultimately went with this: <script> $(document).ready(function(){ var classRE = /Page\d+/i; var pageType = $('body').attr('className').match(classRE); $('li.'+pageType).addClass('Highlight'); }); </script> <style> #tabs li{bg-color: white;} #tabs li.Highlight{bg-color: orange;} </style>

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  • Is it possible to avoid C++ compiler error (C2757) where 2 different header files contain same symbol for namespace & class?

    - by dharmendra
    Hi, I am facing a problem when implementing some new code to an existing library. This library already references a class with a name say 'foo'. The same name is used as a namespace in the other header file which has to be included to implement the new functionality. Since both the header files are a part of legacy code libraries I cannot amend them. So here I am looking for any way so as to avoid the Compiler Error (C2757: a symbol with this name already exists and therefore this name cannot be used as a namespace name). I am not sure whether it is possible or not. Hence, Any help shall be appreciated. Thanks For clarity here is the sample code illustration for the issue: HeaderA.h class foo {} HeaderB.h namespace foo { class ABC{} } HeaderC.h #include <HeaderA.h> #include <HeaderB.h> using namespace foo; class Toimplement{ ABC a; //Throws Error C2757 }

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  • When mocking a class with Moq, how can I CallBase for just specific methods?

    - by Daryn
    I really appreciate Moq's Loose mocking behaviour that returns default values when no expectations are set. It's convenient and saves me code, and it also acts as a safety measure: dependencies won't get unintentionally called during the unit test (as long as they are virtual). However, I'm confused about how to keep these benefits when the method under test happens to be virtual. In this case I do want to call the real code for that one method, while still having the rest of the class loosely mocked. All I have found in my searching is that I could set mock.CallBase = true to ensure that the method gets called. However, that affects the whole class. I don't want to do that because it puts me in a dilemma about all the other properties and methods in the class that hide call dependencies: if CallBase is true then I have to either Setup stubs for all of the properties and methods that hide dependencies -- Even though my test doesn't think it needs to care about those dependencies, or Hope that I don't forget to Setup any stubs (and that no new dependencies get added to the code in the future) -- Risk unit tests hitting a real dependency. Q: With Moq, is there any way to test a virtual method, when I mocked the class to stub just a few dependencies? I.e. Without resorting to CallBase=true and having to stub all of the dependencies? Example code to illustrate (uses MSTest, InternalsVisibleTo DynamicProxyGenAssembly2) In the following example, TestNonVirtualMethod passes, but TestVirtualMethod fails - returns null. public class Foo { public string NonVirtualMethod() { return GetDependencyA(); } public virtual string VirtualMethod() { return GetDependencyA();} internal virtual string GetDependencyA() { return "! Hit REAL Dependency A !"; } // [... Possibly many other dependencies ...] internal virtual string GetDependencyN() { return "! Hit REAL Dependency N !"; } } [TestClass] public class UnitTest1 { [TestMethod] public void TestNonVirtualMethod() { var mockFoo = new Mock<Foo>(); mockFoo.Setup(m => m.GetDependencyA()).Returns(expectedResultString); string result = mockFoo.Object.NonVirtualMethod(); Assert.AreEqual(expectedResultString, result); } [TestMethod] public void TestVirtualMethod() // Fails { var mockFoo = new Mock<Foo>(); mockFoo.Setup(m => m.GetDependencyA()).Returns(expectedResultString); // (I don't want to setup GetDependencyB ... GetDependencyN here) string result = mockFoo.Object.VirtualMethod(); Assert.AreEqual(expectedResultString, result); } string expectedResultString = "Hit mock dependency A - OK"; }

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  • How to create multiple Repository object inside a Repository class using Unit Of Work?

    - by Santosh
    I am newbie to MVC3 application development, currently, we need following Application technologies as requirement MVC3 framework IOC framework – Autofac to manage object creation dynamically Moq – Unit testing Entity Framework Repository and Unit Of Work Pattern of Model class I have gone through many article to explore an basic idea about the above points but still I am little bit confused on the “Repository and Unit Of Work Pattern “. Basically what I understand Unit Of Work is a pattern which will be followed along with Repository Pattern in order to share the single DB Context among all Repository object, So here is my design : IUnitOfWork.cs public interface IUnitOfWork : IDisposable { IPermitRepository Permit_Repository{ get; } IRebateRepository Rebate_Repository { get; } IBuildingTypeRepository BuildingType_Repository { get; } IEEProjectRepository EEProject_Repository { get; } IRebateLookupRepository RebateLookup_Repository { get; } IEEProjectTypeRepository EEProjectType_Repository { get; } void Save(); } UnitOfWork.cs public class UnitOfWork : IUnitOfWork { #region Private Members private readonly CEEPMSEntities context = new CEEPMSEntities(); private IPermitRepository permit_Repository; private IRebateRepository rebate_Repository; private IBuildingTypeRepository buildingType_Repository; private IEEProjectRepository eeProject_Repository; private IRebateLookupRepository rebateLookup_Repository; private IEEProjectTypeRepository eeProjectType_Repository; #endregion #region IUnitOfWork Implemenation public IPermitRepository Permit_Repository { get { if (this.permit_Repository == null) { this.permit_Repository = new PermitRepository(context); } return permit_Repository; } } public IRebateRepository Rebate_Repository { get { if (this.rebate_Repository == null) { this.rebate_Repository = new RebateRepository(context); } return rebate_Repository; } } } PermitRepository .cs public class PermitRepository : IPermitRepository { #region Private Members private CEEPMSEntities objectContext = null; private IObjectSet<Permit> objectSet = null; #endregion #region Constructors public PermitRepository() { } public PermitRepository(CEEPMSEntities _objectContext) { this.objectContext = _objectContext; this.objectSet = objectContext.CreateObjectSet<Permit>(); } #endregion public IEnumerable<RebateViewModel> GetRebatesByPermitId(int _permitId) { // need to implment } } PermitController .cs public class PermitController : Controller { #region Private Members IUnitOfWork CEEPMSContext = null; #endregion #region Constructors public PermitController(IUnitOfWork _CEEPMSContext) { if (_CEEPMSContext == null) { throw new ArgumentNullException("Object can not be null"); } CEEPMSContext = _CEEPMSContext; } #endregion } So here I am wondering how to generate a new Repository for example “TestRepository.cs” using same pattern where I can create more then one Repository object like RebateRepository rebateRepo = new RebateRepository () AddressRepository addressRepo = new AddressRepository() because , what ever Repository object I want to create I need an object of UnitOfWork first as implmented in the PermitController class. So if I would follow the same in each individual Repository class that would again break the priciple of Unit Of Work and create multiple instance of object context. So any idea or suggestion will be highly appreciated. Thank you

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