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  • JavaScript - How to change a dom node back to an existing Google Map?

    - by David Robertson
    I set a div to a class which shows a spinning animated when the map is loading some data, the question is, how can I set the div back to the map (I don't want to load a new map, but load the existing one, which is assigned to a var 'map')? //map is assigned originally like this: map = new google.maps.Map(document.getElementById('map3'),options); //animated graphic is assigned to map div on load of data: document.getElementById('map3').className = "loading"; but how to get the map back? Thanks for any tips! David

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  • How do you access the DOM node in jquery inside of a javascript variable?

    - by KallDrexx
    I have the following html <div id="list_item_template"><li><a href="#">Text</a></li></div> and javascript: var item = $("#list_item_template").clone(); What I want to do is access the inner <a> tag of the cloned copy and add an attribute. Without cloning I would just do: $("#list_item_template a").attr("onclick", "SomeFunction()"); However, I need to perform that operation on the cloned copy, not on the html currently on the page. How would I do this?

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  • Basic File upload in GWT

    - by Maksim
    I'm trying to figure out how to upload one file using GWTs FileUpload widget. I'm using GWT and Google AppEngine with Java but I would like to upload file to my own Linux server. I have the following code already but now I can't figure out how to submit my file to the Google AppServer server and save it to another server: public class FileUploader{ private ControlPanel cp; private FormPanel form = new FormPanel(); private FileUpload fu = new FileUpload(); public FileUploader(ControlPanel cp) { this.cp = cp; this.cp.setPrimaryArea(getFileUploaderWidget()); } @SuppressWarnings("deprecation") public Widget getFileUploaderWidget() { form.setEncoding(FormPanel.ENCODING_MULTIPART); form.setMethod(FormPanel.METHOD_POST); // form.setAction(/* WHAT SHOULD I PUT HERE */); VerticalPanel holder = new VerticalPanel(); fu.setName("upload"); holder.add(fu); holder.add(new Button("Submit", new ClickHandler() { public void onClick(ClickEvent event) { GWT.log("You selected: " + fu.getFilename(), null); form.submit(); } })); form.addSubmitHandler(new FormPanel.SubmitHandler() { public void onSubmit(SubmitEvent event) { if (!"".equalsIgnoreCase(fu.getFilename())) { GWT.log("UPLOADING FILE????", null); // NOW WHAT???? } else{ event.cancel(); // cancel the event } } }); form.addSubmitCompleteHandler(new FormPanel.SubmitCompleteHandler() { public void onSubmitComplete(SubmitCompleteEvent event) { Window.alert(event.getResults()); } }); form.add(holder); return form; } } Now, what do I need to do next? What do i need to put in web.xml and how do I write my servlet so i can store file and return url of that object (if possible)

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  • Double Linked List Insertion Sorting Bug

    - by house
    Hello, I have implemented an insertion sort in a double link list (highest to lowest) from a file of 10,000 ints, and output to file in reverse order. To my knowledge I have implemented such a program, however I noticed in the ouput file, a single number is out of place. Every other number is in correct order. The number out of place is a repeated number, but the other repeats of this number are in correct order. Its just strange how this number is incorrectly placed. Also the unsorted number is only 6 places out of sync. I have looked through my program for days now with no idea where the problem lies, so I turn to you for help. Below is the code in question, (side note: can my question be deleted by myself? rather my colleges dont thieve my code, if not how can it be deleted?) void DLLIntStorage::insertBefore(int inValue, node *nodeB) { node *newNode; newNode = new node(); newNode->prev = nodeB->prev; newNode->next = nodeB; newNode->value = inValue; if(nodeB->prev==NULL) { this->front = newNode; } else { nodeB->prev->next = newNode; } nodeB->prev = newNode; } void DLLIntStorage::insertAfter(int inValue, node *nodeB) { node *newNode; newNode = new node(); newNode->next = nodeB->next; newNode->prev = nodeB; newNode->value = inValue; if(nodeB->next == NULL) { this->back = newNode; } else { nodeB->next->prev = newNode; } nodeB->next = newNode; } void DLLIntStorage::insertFront(int inValue) { node *newNode; if(this->front == NULL) { newNode = new node(); this->front = newNode; this->back = newNode; newNode->prev = NULL; newNode->next = NULL; newNode->value = inValue; } else { insertBefore(inValue, this->front); } } void DLLIntStorage::insertBack(int inValue) { if(this->back == NULL) { insertFront(inValue); } else { insertAfter(inValue, this->back); } } ifstream& operator>> (ifstream &in, DLLIntStorage &obj) { int readInt, counter = 0; while(!in.eof()) { if(counter==dataLength) //stops at 10,000 { break; } in >> readInt; if(obj.front != NULL ) { obj.insertion(readInt); } else { obj.insertBack(readInt); } counter++; } return in; } void DLLIntStorage::insertion(int inValue) { node* temp; temp = this->front; if(temp->value >= inValue) { insertFront(inValue); return; } else { while(temp->next!=NULL && temp!=this->back) { if(temp->value >= inValue) { insertBefore(inValue, temp); return; } temp = temp->next; } } if(temp == this->back) { insertBack(inValue); } } Thankyou for your time.

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  • How can I turn a SimpleXML object to array, then shuffle?

    - by Joshua Cody
    Crux of my problem: I've got an XML file that returns 20 results. Within these results are all the elements I need to get. Now, I need to return them in a random order, and be able to specifically work with item 1, items 2-5, and items 6-17. Idea 1: Use this script to convert the object to an array, which I can shuffle through. This is close to working, but a few of the elements I need to get are under a different namespace, and I don't seem to be able to get them. Code: /* * Convert a SimpleXML object into an array (last resort). * * @access public * @param object $xml * @param boolean $root - Should we append the root node into the array * @return array */ function xmlToArray($xml, $root = true) { if (!$xml->children()) { return (string)$xml; } $array = array(); foreach ($xml->children() as $element => $node) { $totalElement = count($xml->{$element}); if (!isset($array[$element])) { $array[$element] = ""; } // Has attributes if ($attributes = $node->attributes()) { $data = array( 'attributes' => array(), 'value' => (count($node) > 0) ? xmlToArray($node, false) : (string)$node // 'value' => (string)$node (old code) ); foreach ($attributes as $attr => $value) { $data['attributes'][$attr] = (string)$value; } if ($totalElement > 1) { $array[$element][] = $data; } else { $array[$element] = $data; } // Just a value } else { if ($totalElement > 1) { $array[$element][] = xmlToArray($node, false); } else { $array[$element] = xmlToArray($node, false); } } } if ($root) { return array($xml->getName() => $array); } else { return $array; } } $thumbfeed = simplexml_load_file('http://gdata.youtube.com/feeds/api/videos?q=skadaddlemedia&max-results=20&orderby=published&prettyprint=true'); $xmlToArray = xmlToArray($thumbfeed); $thumbArray = $xmlToArray["feed"]; for($n = 0; $n < 18; $n++){ $title = $thumbArray["entry"][$n]["title"]["value"]; $desc = $thumbArray["entry"][0]["content"]["value"]; $videoUrl = $differentNamespace; $thumbUrl = $differentNamespace; } Idea 2: Continue using my working code that is getting the information using a foreach, but store each element in an array, then use shuffle on that. I'm not precisely sure hwo to write to an array within a foreach loop and not write over one another, though. Working code: foreach($thumbfeed->entry as $entry){ $thumbmedia = $entry->children('http://search.yahoo.com/mrss/') ->group ; $thumb = $thumbmedia->thumbnail[0]->attributes()->url; $thumburl = $thumbmedia->content[0]->attributes()->url; $thumburl1 = explode("http://www.youtube.com/v/", $thumburl[0]); $thumbid = explode("?f=videos&app=youtube_gdata", $thumburl1[1]); $thumbtitle = $thumbmedia->title; $thumbyt = $thumbmedia->children('http://gdata.youtube.com/schemas/2007') ->duration ; $thumblength = $thumbyt->attributes()->seconds; } Ideas on if either of these are good solutions to my problem, and if so, how I can get over my execution humps? Thanks so much for any help you can give.

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  • django hidden field error

    - by dana
    hi, there, i'm building a message system for a virtual community, but i can't take the userprofile id i have in views.py def save_message(request): if request.method == 'POST': form = MessageForm(request.POST) if form.is_valid(): new_obj = form.save(commit=False) new_obj.sender = request.user u = UserProfile.objects.get(request.POST['userprofile_id']) new_obj.owner = u new_obj.save() return HttpResponseRedirect('.') else: form = MessageForm() return render_to_response('messages/messages.html', { 'form': form, }, context_instance=RequestContext(request)) and the template: {% block primary %} <form action="." method="post"> {{ form.as_p }} <p><input type="hidden" value="{{ userprofile.id }}" name = "owner" /></p> <p><input type="submit" value="Send Message!" /></p> </form> {% endblock %} forms.py: class MessageForm(ModelForm): class Meta: model = Messages fields = ['message'] models.py: class Messages(models.Model): message = models.CharField(max_length = 300) read = models.BooleanField(default=False) owner = models.ForeignKey(UserProfile) sender = models.ForeignKey(User) I don't figure out why i get this error,since i'm just trying to get the profileId of a user, using a hiddeen field. the error is: Key 'UserProfile_id' not found in <QueryDict: {u'owner': [u''], u'message': [u'fdghjkl']}> and i'm getting it after i fill out the message text field. Thanks!

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  • Upon doing a XSL Transform to XML how do I remove white space from a Node's attribute or data?

    - by Randy
    I have a part's list built out in XML and each part is labeled as such: <division> <parts> <part number="123456 " drawing="123456 " cad="y"> <attribute> <header>Header</header> <list>2</list> </attribute> </part> And I need to get the data behind the number and drawing attributes without the white space. I tried xsl:strip-space on the specific elements, and across the board, but that only strips the content in between the tags. I unfortunately have no access to the back-end that's producing the XML, so removing the spaces there doesn't look like an option.

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  • Fading out an article and dropping down a form at the same time?

    - by eveo
    I have an article: <article> Some paragraphs. </article> Below that I have my contact: <div id="contact"> stuff, this form is 600 px tall </div> contact is set to display:none;. I use jQuery to toggle it. What I'm trying to do is modify this script from http://tutsplus.com/lesson/slides-and-structure/ so that it fades out the article text and then slides in the contact form. Having some trouble. Code: <script> (function() { $('html').addClass('js'); var contactForm = { container: $('#contact'), article: $('article'), init: function() { $('<button></button>', { text: 'Contact Me' }) .insertAfter('article:first') .on('click', function() { console.log(this); this.show(); // contactForm.article.fadeToggle(300); // contactForm.container.show(); }) }, show: function() { contactForm.close.call(contactForm.container); contactForm.container.slideToggle(300); }, close: function() { console.log(this); $('<span class=close>X</span>') .prependTo(this) .on('click', function(){ contactForm.article.fadeToggle(300); contactForm.container.slideToggle(300); }) } }; contactForm.init(); })(); </script> The part that is not working is: .on('click', function() { console.log(this); this.show(); // contactForm.article.fadeToggle(300); // contactForm.container.show(); }) When I do .on('click', this.show); it works fine, when I put this.show in a function it does not work!

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  • how do I insert an hidden token in my form to prevent double posts? (PHP)

    - by jpjp
    I want to prevent users from accidentally posting a comment twice. I use the PRG (post redirect get) method, so that I insert the data on another page then redirect the user back to the page which shows the comment. This allows users to refresh as many times as they want. However this doesn't work when the user goes back and clicks submit again or when they click submit 100 times really fast. I don't want 100 of the same comments. I looked at related questions on SO and found that a token is best. But I am having trouble using it. //makerandomtoken(20) returns a random 20 length char. <form method="post" ... > <input type="text" id="comments" name="comments" class="commentbox" /><br/> <input type="hidden" name="_token" value="<?php echo $token=makerandomtoken(20); ?>" /> <input type="submit" value="submit" name="submit" /> </form> if (isset($_POST['submit']) && !empty($comments)) { $comments= mysqli_real_escape_string($dbc,trim($_POST['comments'])); //how do I make the if-statment to check if the token has been already set once? if ( ____________){ //don't insert comment because already clicked submit } else{ //insert the comment into the database } } So I have the token as a hidden value, but how do I use that to prevent multiple clicking of submit.

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  • Django formset doesn't validate

    - by tsoporan
    Hello, I am trying to save a formset but it seems to be bypassing is_valid() even though there are required fields. To test this I have a simple form: class AlbumForm(forms.Form): name = forms.CharField(required=True) The view: @login_required def add_album(request, artist): artist = Artist.objects.get(slug__iexact=artist) AlbumFormSet = formset_factory(AlbumForm) if request.method == 'POST': formset = AlbumFormSet(request.POST, request.FILES) if formset.is_valid(): return HttpResponse('worked') else: formset = AlbumFormSet() return render_to_response('submissions/addalbum.html', { 'artist': artist, 'formset': formset, }, context_instance=RequestContext(request)) And the template: <form action="" method="post" enctype="multipart/form-data">{% csrf_token %} {{ formset.management_form }} {% for form in formset.forms %} <ul class="addalbumlist"> {% for field in form %} <li> {{ field.label_tag }} {{ field }} {{ field.errors }} </li> {% endfor %} </ul> {% endfor %} <div class="inpwrap"> <input type="button" value="add another"> <input type="submit" value="add"> </div> </form> What ends up happening is I hit "add" without entering a name then HttpResponse('worked') get's called seemingly assuming it's a valid form. I might be missing something here, but I can't see what's wrong. What I want to happen is, just like any other form if the field is required to spit out an error if its not filled in. Any ideas?

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  • What is the form_for syntax for nested resources?

    - by Kris
    I am trying to create a form for a nested resource. Here is my route: map.resources :websites do |website| website.resources :domains end Here are my attempts and the errors: <% form_for(@domain, :url => website_domains_path(@website)) do | form | %> <%= form.text_field :name %> # ArgumentError: wrong number of arguments (1 for 0) # form_helper.rb:290:in 'respond_to?' # form_helper.rb:290:in 'apply_form_for_options!' # form_helper.rb:277:in 'form_for' <% form_for([@website, @domain]) do | form | %> <%= form.text_field :name %> # ArgumentError: wrong number of arguments (1 for 0) # form_helper.rb:290:in 'respond_to?' # form_helper.rb:290:in 'apply_form_for_options!' # form_helper.rb:277:in 'form_for' <% form_for(:domain, @domain, :url => website_domains_path(@website)) do | form | %> <%= form.text_field :name %> # ArgumentError: wrong number of arguments (1 for 0) # wrapper.rb:14:in 'respond_to?' # wrapper.rb:14:in 'wrap' # active_record_helper.rb:174:in 'error_messages_for' <% form_for(:domain, [@website, @domain]) do | form | %> <%= form.text_field :name %> # UndefinedMethodError 'name' for #<Array:0x40fa498> I have confirmed both @website and @domain contain instances of the correct class. The routes also generate correctly is used like this for example, so I dont think their is an issue with the route or url helpers. <%= website_domains_path(1) %> <%= website_data_source_path(1, 1) %> Rails 2.3.5

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  • Problem bounding name to a class in Django

    - by martinthenext
    Hello! I've got a view function that has to decide which form to use depending on some conditions. The two forms look like that: class OpenExtraForm(forms.ModelForm): class Meta: model = Extra def __init__(self, *args, **kwargs): super(OpenExtraForm, self).__init__(*args, **kwargs) self.fields['opening_challenge'].label = "lame translation" def clean_opening_challenge(self): challenge = self.cleaned_data['opening_challenge'] if challenge is None: raise forms.ValidationError('??????? ???, ??????????? ?????? ???. ???????????') return challenge class HiddenExtraForm(forms.ModelForm): class Meta: model = Extra exclude = ('opening_challenge') def __init__(self, *args, **kwargs): super(HiddenExtraForm, self).__init__(*args, **kwargs) The view code goes like that: @login_required def manage_extra(request, extra_id=None, hidden=False): if not_admin(request.user): raise Http404 if extra_id is None: # Adding a new extra extra = Extra() if hidden: FormClass = HiddenExtraForm else: FormClass = OpenExtraForm else: # Editing an extra extra = get_object_or_404(Extra, pk=extra_id) if extra.is_hidden(): FromClass = HiddenExtraForm else: FormClass = OpenExtraForm if request.POST: form = FormClass(request.POST, instance=extra) if form.is_valid(): form.save() return HttpResponseRedirect(reverse(view_extra, args=[extra.id])) else: form = FormClass(instance=extra) return render_to_response('form.html', { 'form' : form, }, context_instance=RequestContext(request) ) The problem is somehow if extra.is_hidden() returns True, the statement FromClass = HiddenExtraForm doesn't work. I mean, in all other conditions that are used in the code it works fine: the correct Form classes are intantiated and it all works. But if extra.is_hidden(), the debugger shows that the condition is passed and it goes to the next line and does nothing! As a result I get a UnboundLocalVar error which says FormClass hasn't been asssigned at all. Any ideas on what's happening?

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  • CSS: how to set the width of form control so they all have the same width?

    - by Alessandro Vernet
    Consider the following example: <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8"/> <style type="text/css"> div { width: 15em } input, textarea, select { width: 100%; -moz-box-sizing: border-box; -webkit-box-sizing: border-box; box-sizing: border-box } </style> </head> <body> <form> <div> <input value="Input"> </div> <div> <textarea>Text area</textarea> </div> <div> <select> <option>One</option> <option>Two</option> <option>Three</option> </select> </div> </form> </body> </html> On browser that support the border-box box sizing, this is rendered as I want: On IE 6/7, however, this is rendered as: How can I get the same rendering in IE 6/7 that I get in other browsers, without resorting to setting sizes in pixels?

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  • Chrome not sending POST requests on localhost, Firefox works fine

    - by AP257
    I have copied the simple Django forms example exactly, running on localhost. The basic contact form example should submit a POST request when you click the Submit button. I'm running Chrome on Mac Snow Leopard, and whenever I submit the form, the page simply reloads with an empty form: I can see from the runserver output that it's not sending a POST - instead it's sending a GET request. If I open the same page in Firefox on Mac Snow Leopard, and submit the form, I can see it's sending a POST request (as it should be). Looking at the source in Chrome, the form definitely says method="post". <form action="/contact/" method="post"> <p><label for="id_subject">Subject:</label> <input id="id_subject" type="text" name="subject" maxlength="100" /></p> <p><label for="id_message">Message:</label> <input type="text" name="message" id="id_message" /></p> <p><label for="id_sender">Sender:</label> <input type="text" name="sender" id="id_sender" /></p> <p><label for="id_cc_myself">Cc myself:</label> <input type="checkbox" name="cc_myself" id="id_cc_myself" /></p> <input type="submit" value="Submit" /> </form> External sites with POST forms seem to work OK in Chrome. In addition, if I fill the form in incorrectly, in Chrome the page just reloads, with a GET request, as before; in Firefox the form gets validated, as it should. I've tried with other POST forms on localhost and got the same result. I know Chrome for Mac has its quirks, but what on earth is going on?

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  • Django repeating vars/cache issue?

    - by Mark
    I'm trying to build a better/more powerful form class for Django. It's working well, except for these sub-forms. Actually, it works perfectly right after I re-start apache, but after I refresh the page a few times, my HTML output starts to look like this: <input class="text" type="text" id="pickup_addr-pickup_addr-pickup_addr-id-pickup_addr-venue" value="" name="pickup_addr-pickup_addr-pickup_addr-pickup_addr-venue" /> The pickup_addr- part starts repeating many times. I was looking for loops around the prefix code that might have cause this to happen, but the output isn't even consistent when I refresh the page, so I think something is getting cached somewhere, but I can't even imagine how that's possible. The prefix car should be reset when the class is initialized, no? Unless it's somehow not initializing something? class Form(object): count = 0 def __init__(self, data={}, prefix='', action='', id=None, multiple=False): self.fields = {} self.subforms = {} self.data = {} self.action = action self.id = fnn(id, 'form%d' % Form.count) self.errors = [] self.valid = True if not empty(prefix) and prefix[-1:] not in ('-','_'): prefix += '-' for name, field in inspect.getmembers(self, lambda m: isinstance(m, Field)): if name[:2] == '__': continue field_name = fnn(field.name, name) field.label = fnn(field.label, humanize(field_name)) field.name = field.widget.name = prefix + field_name + ife(multiple, '[]') field.id = field.auto_id = field.widget.id = ife(field.id==None, 'id-') + prefix + fnn(field.id, field_name) + ife(multiple, Form.count) field.errors = [] val = fnn(field.widget.get_value(data), field.default) if isinstance(val, basestring): try: val = field.coerce(field.format(val)) except Exception, err: self.valid = False field.errors.append(escape_html(err)) field.val = self.data[name] = field.widget.val = val for rule in field.rules: rule.fields = self.fields rule.val = field.val rule.name = field.name self.fields[name] = field for name, form in inspect.getmembers(self, lambda m: ispropersubclass(m, Form)): if name[:2] == '__': continue self.subforms[name] = self.__dict__[name] = form(data=data, prefix='%s%s-' % (prefix, name)) Form.count += 1 Let me know if you need more code... I know it's a lot, but I just can't figure out what's causing this!

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  • How do you test a command object in a grails controller integration test?

    - by egervari
    I'm new to grails. How do I test a form command object to make sure that it's working? Here's some setup code in a test. When I try to do it, I get the following exceptions: Error occurred creating command object. org.codehaus.groovy.grails.web.servlet.mvc.exceptions.ControllerExecutionException: Error occurred creating command object. at sun.reflect.NativeConstructorAccessorImpl.newInstance0(Native Method) .... Caused by: groovy.lang.MissingPropertyException: No such property: password for class: project.user.RegistrationForm Possible solutions: password Here is my test case. As you can see, I set "password" on the params map... void testSaveWhenDataIsCorrect() { controller.params.emailAddress = "[email protected]" controller.params.password = "secret" controller.params.confirmPassword = "secret" controller.save() assertEquals "success", redirectArgs.view ... } Here's the controller action, that adds the command object as a closure parameter: def save = { RegistrationForm form -> if(form.hasErrors()) { render view: "create", model: [form: form] } else { def user = new User(form.properties) user.password = form.encryptedPassword if(user.save()) { redirect(action: "success") } else { render view: "create", model: [form: form] } } } Here's the command object itself... and note that it DOES have a "password" field... class RegistrationForm { def springSecurityService String emailAddress String password String confirmPassword String getEncryptedPassword() { springSecurityService.encodePassword(password) } static constraints = { emailAddress(blank: false, email: true) password(blank: false, size:4..10) confirmPassword(blank: false, validator: { password != confirmPassword }) } } I'm totally lost in the non-intuitive way to do controllers... Please help.

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  • Using javascript to add form fields, but what will the new name be?

    - by user1322844
    After reading this post: using javascript to add form fields.. but below, not to the side? I've made the button work! But I don't know how to receive the output. This is what I entered. var counter = 0; function addNew() { // Get the main Div in which all the other divs will be added var mainContainer = document.getElementById('mainContainer'); // Create a new div for holding text and button input elements var newDiv = document.createElement('div'); // Create a new text input var newText = document.createElement('input'); newText.type = "input"; newText.maxlength = "50"; newText.maxlimit = "50"; newText.size = "60"; newText.value = counter; // Create a new button input var newDelButton = document.createElement('input'); newDelButton.type = "button"; newDelButton.value = "Delete"; // Append new text input to the newDiv newDiv.appendChild(newText); // Append new button input to the newDiv newDiv.appendChild(newDelButton); // Append newDiv input to the mainContainer div mainContainer.appendChild(newDiv); counter++; // Add a handler to button for deleting the newDiv from the mainContainer newDelButton.onclick = function() { mainContainer.removeChild(newDiv); } } </script> With this in the form: <input type="button" size="3" cols="30" value="Add" onClick="addNew()"> So, what will the new field names be? I don't understand enough of the coding to figure out what I'm telling it to. Good thing there are other smart folks out there for me to lean on! Thanks for any answers.

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  • In .NET, how do I prevent, or handle, tampering with form data of disabled fields before submission?

    - by David
    Hi, If a disabled drop-down list is dynamically rendered to the page, it is still possible to use Firebug, or another tool, to tamper with the submitted value, and to remove the "disabled" HTML attribute. This code: protected override void OnLoad(EventArgs e) { var ddlTest = new DropDownList() {ID="ddlTest", Enabled = false}; ddlTest.Items.AddRange(new [] { new ListItem("Please select", ""), new ListItem("test 1", "1"), new ListItem("test 2", "2") }); Controls.Add(ddlTest); } results in this HTML being rendered: <select disabled="disabled" id="Properties_ddlTest" name="Properties$ddlTest"> <option value="" selected="selected">Please select</option> <option value="1">test 1</option> <option value="2">test 2</option> </select> The problem occurs when I use Firebug to remove the "disabled" attribute, and to change the selected option. On submission of the form, and re-creation of the field, the newly generated control has the correct value by the end of OnLoad, but by OnPreRender, it has assumed the identity of the submitted control and has been given the submitted form value. .NET seems to have no way of detecting the fact that the field was originally created in a disabled state and that the submitted value was faked. This is understandable, as there could be legitimate, client-side functionality that would allow the disabled attribute to be removed. Is there some way, other than a brute force approach, of detecting that this field's value should not have been changed? I see the brute force approach as being something crap, like saving the correct value somewhere while still in OnLoad, and restoring the value in the OnPreRender. As some fields have dependencies on others, that would be unacceptable to me.

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  • How to modify a xml file using PHP? use a node to retrieve the value of new child nodes and add them

    - by Avinash Sonee
    I have pasted the example of what I need here : http://pastie.org/1005178 I have a xml file with say the following info <state> <info> <name>hello</name> <zip>51678</zip> </info> <info> <name>world</name> <zip>54678</zip> </info> </state> Now I need to create a new xml file which has the following <state> <info> <name>hello</name> <zip>51678</zip> <lat>17.89</lat> <lon>78.90</lon> </info> <info> <name>world</name> <zip>54678</zip> <lat>16.89</lat> <lon>83.45</lon> </info> </state> So, basically I need to add lat and lon nodes to each info element. these lat and lon correspond to the zip code which are stored in a mysql file which contains 3 fields - pin, lat and lon How do i do this recursively. I have say 1000 info elements in a file Please give me a sample code because I have already tried using simplexml and read the documentation but doesn't see to understand it properly

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  • What makes good web form styling for business applications?

    - by ProfK
    Styling forms (form elements) is something that even Eric Meyer prefers to avoid. However, most business forms, and that is where styling is at issue; 'contact us' forms are easy to style, put window estate at a premium, with more 'document level' (e.g. invoice) fields, plus 'detail level' (e.g. invoice line) fields. Factors I often find at play are: At my minimum, at least two horizontally adjacent fieldsets are required. In applications vs. public web pages, fixed positioning vs fluid layout is often better. Quantity of content is important, vs. exaggerated readability. Users know the system, and cues etc. take a back seat. In light of factors like these, is there any available guidence for styling web form based applications? Are there any CSS or JavaScript frameworks that would make my quest to style these applications better than Visual Studios still pathetic 'Auto-format' (what drugs were those people on? I will never take them.)

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  • Why is Firefox prompting to download a file that is POST'd to?

    - by alex
    This is the most peculiar thing. It is from an old in house CMS. When I attempt to submit my changes, it prompts to save the file linked in the action attribute of the form. Headers Request POST /~site/edit/articles/article_save.php?id=54 HTTP/1.1 Host: example.com User-Agent: Mozilla/5.0 (Macintosh; U; Intel Mac OS X 10.6; en-US; rv:1.9.2.3) Gecko/20100401 Firefox/3.6.3 Accept: text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8 Accept-Language: en-us,en;q=0.5 Accept-Encoding: gzip,deflate Accept-Charset: ISO-8859-1,utf-8;q=0.7,*;q=0.7 Keep-Alive: 115 Connection: keep-alive Referer: http://example.com Content-Type: multipart/form-data; boundary=---------------------------10102754414578508781458777923 Content-Length: 940 -----------------------------10102754414578508781458777923 Content-Disposition: form-data; name="title" Home Content -----------------------------10102754414578508781458777923 Content-Disposition: form-data; name="catid" 18 -----------------------------10102754414578508781458777923 Content-Disposition: form-data; name="activecheck" 1 -----------------------------10102754414578508781458777923 Content-Disposition: form-data; name="image" -----------------------------10102754414578508781458777923 Content-Disposition: form-data; name="contentWidgToolbarSelectBlock" <p> -----------------------------10102754414578508781458777923 Content-Disposition: form-data; name="content" <p>Edit your article in this text box.</p> -----------------------------10102754414578508781458777923 Content-Disposition: form-data; name="contentWidgEditor" true -----------------------------10102754414578508781458777923-- Response HTTP/0.9 200 OK And then Firefox shows.... I can't determine from the response headers as to why this is prompting to open/save. It has always worked. All other PHP files on the site work fine. Anyone have a clue? Thanks Update Apparently, it just crashes Safari.

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