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• Android canceling all alarm set

  - by spagi

  Hi all. I am making an event application and user can set a reminder for events he wants. So i use the alarmManager to create alarms. I would like to put a cancel all option to my main activity so that i could cancel all the alarms created by my application. The usual method for canceling the alarm with the same intent doesnt really help cause i set tha alarms on a different activity than the one I want to cancel them in. So is there a way to cancel all the alarms created by my application? Thanks!

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• using android alarmclock

  - by user316341

  is it possible to use the com.androird.alarmclock so that I can use it to kick off alarm features in my application. if it is how can i do it?

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• Android how to create notification that resumes activity

  - by Adam Praiswater

  I a have a notification in a receiver that fires off fine, but it restarts the activity (thus clearing the edittexts and resetting the toggle button) How can i set it so that when its tapped on it resumes the activity rather that clearing and resetting everything? My current code doesnt work. Current Code String currentDateTimeString = DateFormat.getDateTimeInstance().format(new Date()); Intent intenti= new Intent(context, Locator.class); intenti.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK | Intent.FLAG_ACTIVITY_SINGLE_TOP); PendingIntent contentIntent = PendingIntent.getActivity(context, 0, intenti, 0); NotificationCompat.Builder mBuilder = new NotificationCompat.Builder(context) .setSmallIcon(R.drawable.xxxxxxnotifyicon) .setContentTitle("xxxxxxx Link") .setContentText("Auto Check In Complete at " + currentDateTimeString); mBuilder.setContentIntent(contentIntent); mBuilder.setDefaults(Notification.DEFAULT_SOUND); mBuilder.setAutoCancel(true); NotificationManager mNotificationManager = (NotificationManager) context.getSystemService(Context.NOTIFICATION_SERVICE); mNotificationManager.notify(1, mBuilder.build());

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• Select option in iPhone and Android browsers.

  - by alex

  I'd like a select box that will alert the value when the user selects the option. (in iPhone) <select> <option> 1 </option> <option> 2 </option> <option> 3 </option> </select> In my web browser on the desktop, I can do: onclick, but on the phone, onclick doesn't work.

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• Android: Problems downloading images and converting to bitmaps

  - by Mike

  Hi all, I am working on an application that downloads images from a url. The problem is that only some images are being correctly downloaded and others are not. First off, here is the problem code: public Bitmap downloadImage(String url) { HttpClient client = new DefaultHttpClient(); HttpResponse response = null; try { response = client.execute(new HttpGet(url)); } catch (ClientProtocolException cpe) { Log.i(LOG_FILE, "client protocol exception"); return null; } catch (IOException ioe) { Log.i(LOG_FILE, "IOE downloading image"); return null; } catch (Exception e) { Log.i(LOG_FILE, "Other exception downloading image"); return null; } // Convert images from stream to bitmap object try { Bitmap image = BitmapFactory.decodeStream(response.getEntity().getContent()); if(image==null) Log.i(LOG_FILE, "image conversion failed"); return image; } catch (Exception e) { Log.i(LOG_FILE, "Other exception while converting image"); return null; } } So what I have is a method that takes the url as a string argument and then downloads the image, converts the HttpResponse stream to a bitmap by means of the BitmapFactory.decodeStream method, and returns it. The problem is that when I am on a slow network connection (almost always 3G rather than Wi-Fi) some images are converted to null--not all of them, only some of them. Using a Wi-Fi connection works perfectly; all the images are downloaded and converted properly. Does anyone know why this is happening? Or better, how can I fix this? How would I even go about testing to determine the problem? Any help is awesome; thank you!

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• How to check if EditText has a value in Android / Java

  - by Allen Gingrich

  This should be simple, but I have tried if statements checking for null values and also ones checking the .length of it: EditText marketValLow = (EditText) findViewById(R.id.marketValLow); EditText marketValHigh = (EditText) findViewById(R.id.marketValHigh); if (marketValLow.getText().length() != 0 && marketValHigh.getText().length() != 0) { Intent intent = new Intent(); intent.setClass(v.getContext(), CurrentlyOwe.class); startActivity(intent); } else { Toast.makeText(CurrentMarketValue.this, "You need to enter a high AND low.", Toast.LENGTH_SHORT); } But it doesn't detect nothing was entered. Any ideas? Thanks!

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• Rich image scroll and zooming on android

  - by F0RR

  I'm looking for a way to implement image zoom and scrolling the way it is implemented in Droid Comic Viewer. Is there any quick way to do that? If not, then could you please give some advices at least on implementing kinetic scrolling.

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• draw is being constantly called in my android map overlay

  - by Itsik

  I'm trying to draw a route onto my MapView. I've extended Overlay and implemented the draw() method. The route is displayed properly, although while debugging, I added a breakpoint on draw(), and noticed it is being called constantly. I only want it to be re-drawn if someone moves the map or zooms (the draw take into account these changes when drawing the route) What can cause this ?

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• Android Email Application:

  - by PankajV

  By looking at the link http://stackoverflow.com/questions/2001254/downloading-sent-mails-from-yahoo-gmail-and-hotmail is it possible to invoke or call Gmail and open a message programmatically

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• Android use of an string array on another method

  - by spagi

  Hi all. Im trying to make an activity that has a multiple choice dialog after you push a button. In there you select from a list of things. But these things are received from a web method before the dialog appears. So I create a string array after I receive them inside the onCreate to initialise it there with the correct size. But my dialog method then cant get the array because propably its out of its scope. My code looks like this @Override protected Dialog onCreateDialog(int id) //Here is where the array is loaded to the multiple select dialog etc @Override public void onCreate(Bundle savedInstanceState) //Here is where i initialise the array and get its contents etc I cant initialise my array when the class starts because I dont know its size yet. This has to do something with the scopes of my variables and I am pretty confused

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• options menu in android application

  - by sam

  hey … i want to open up options menu by clicking upon my own created button … is it possible ? if so, please help me out … thanks in advance

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• Connecting GPS coordinates taken from a database in Android using Overlay

  - by LordSnoutimus

  I am currently building an application that allows users to track where their phone has been on a Google Map. At the moment, when the onLocationChanged() method is called, the application stores the current GPS longitude and latitude in a database and calls the animateTo() method to the current position. Using SDK 1.5, how would I go about connecting these points with a coloured line drawn on the MapView using an Overlay?.

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• [Android] XML Parser

  - by lemon

  I'm trying to extract n0Y7ezLlIYA8R0K54rEmHaTOraBQVSPDjQaGlQxlGso4jdVN1kRxtcfskEs= using w3c dom <html> <div id='token' style='display:none;'> n0Y7ezLlIYA8R0K54rEmHaTOraBQVSPDjQaGlQxlGso4jdVN1kRxtcfskEs= </div> </html> but I seem to be stuck DocumentBuilder builder = DocumentBuilderFactory.newInstance().newDocumentBuilder(); Document doc = builder.parse(con.getInputStream()); NodeList list = doc.getElementsByTagName("div"); Can someone please point me to some basic tutorials that would help me solve my dilemma. Thanks.

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• How can I write my own context menu for copy & paste?

  - by skysign

  I'm writing an application with EditText driven widget. and I'd like to create my own copy & paste menu. To replace android default menu on EditText, what should I do? Just overriding long click? or is there another way to implement? Thanks in advance.

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• Adapter Methods in Android?

  - by Praveen Chandrasekaran

  i have go through the three methods in Adapters classes. getView() newView() bindView() what are the difference between those methods? please share some tutorial, sample code or logics to understand this. Thanks. i have to create a listview with the progressive icons. which adapter you suggest me to do that?

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• Android game logic problem

  - by semajhan

  I'm currently creating a game and have a problem which I think I know why it is occurring but not entirely sure and even if I knew, don't know how to solve. I have a 2D array 10 x 10 and have a "player" class that takes up a tile. Now, I have created 2 instances of the player and move them around via swiping. Around the edges I have put "walls" that the player cannot walk through and everything works fine, until I remove a wall. Once I remove a wall and move the character/player to the edge of the screen, the player cannot go any further. The problem occurs here, where the second instance of the player is not at the edge of the screen but say 2 tiles from the first instance of "player" who is at the edge. If I try moving them further into the direction of the edge, I understand that the first instance of player wouldn't move or do anything but the second instance of player should still move, but it won't. This is the code that executed when the user swipes: if (player.getArrayX() - 1 != player2.getArrayX()) { player.moveLeft(); } else if (player.getArrayX() - 1 == player2.getArrayX() && player.getArrayY() != player2.getArrayY()) { player.moveLeft(); } if (player2.getArrayX() - 1 != player.getArrayX()) { player2.moveLeft(); } else if (player2.getArrayX() - 1 == player.getArrayX() && player2.getArrayY() != player.getArrayY()) { player2.moveLeft(); } In the player class I have: public void moveLeft() { if (alive) { switch (levelMaster.getLevel1(getArrayX() - 1, getArrayY())) { case 0: break; case 1: subX(); // basically moves player left setArrayX(getArrayX() - 1); // shifts x coord of player 1 within tilemap Log.d("semajhan", "x: " + getArrayX()); break; case 9: subX(); setArrayX(getArrayX() - 1); setAlive(false); break; } } } Any help on the matter or further insight would be greatly appreciated, thanks.

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• android, find the nearest location without going through all the locations

  - by Marwan

  I am building a taxi dispatching app first: I need the passenger app to show the nearest taxis, now I know how to do that in code but in my way I have to go through all the taxis locations(in database on server) and calculate the distance from the passenger location and get the lowest ones - I don't want to do this because there will be a lot of taxis and going through all of them and making some math is kind of pain on the server- is there a way to get the nearest ones without going through all of them? second: what the best database to use - first, should it be sql or non-sql - I need a very robust database, because there will be a lot of updates (I mean the passengers locations added then deleted when arriving to destination && the taxis location changes frequently) finally: I will use RubyOnRails to do the server side and json as data transfer format, do you have a recommendation to me on something better? Thanks

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• Android different resolutions problem

  - by user346665

  Hi, I have 9 (vertical) radio buttons and they are all showing in default resolution (320x480) without problems . But when I'm trying in resolution for Htc Tattoo (240x320) the last radio button is hidden - there isn't space to be shown. How to make uniformly size ?

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• How to justify text on a TextView made easy- Android

  - by Juan

  I'm looking for a simple way to forget that I'm using a WebView to have justified text in my TextView. Has someone made a custom view for this? I'm well aware that I can do something like this: WebView view = new WebView(this); view.loadData("my html with text justification","text/html","utf-8"); But it gets ugly when you want to set the size, the color or other common properties of the TextView, there must be a more convenient way of doing it.

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• Consume a JSON webservice and process data in Android

  - by user1783391

  I am trying to consume a the webservice below http://62.253.195.179/disaster/webservices/login.php?message=[{"email":"[email protected]","password":"welcome"}] This returns a JSON array [{"companyuserId":"2","name":"ben stein","superiorname":"Leon","departmentId":"26","departmentname":"Development","companyId":"23","UDID":"12345","isActive":"1","devicetoken":"12345","email":"[email protected]","phone":"5456465465654","userrole":"1","chngpwdStatus":"1"}] My code is below try{ String weblink = URLEncoder.encode("http://62.253.195.179/disaster/webservices/login.php?message=[{\"email\":\"[email protected]\",\"password\":\"welcome\"}]"); HttpParams httpParameters = new BasicHttpParams(); int timeoutConnection = 7500; HttpConnectionParams.setConnectionTimeout(httpParameters, timeoutConnection); int timeoutSocket = 7500; HttpConnectionParams.setSoTimeout(httpParameters, timeoutSocket); HttpClient client = new DefaultHttpClient(httpParameters); HttpGet request = new HttpGet(); URI link = new URI(weblink); request.setURI(link); HttpResponse response = client.execute(request); BufferedReader rd = new BufferedReader(new InputStreamReader( response.getEntity().getContent())); result = rd.readLine(); JSONObject myData = new JSONObject(result); JSONArray jArray = myData.getJSONArray(""); JSONObject steps = jArray.getJSONObject(0); String name = steps.getString("name"); } catch (JSONException e) { e.printStackTrace(); } But its not working and I am not 100% sure this is the best way to do it. 11-10 10:49:55.489: E/AndroidRuntime(392): java.lang.IllegalStateException: Target host must not be null, or set in parameters.

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• Android: ScoreNinja is only displaying 1 highscore....

  - by Dave B

  Hi All, I am trying to implement ScoreNinja into one of my apps. It all seems to work, but when I submit a score it replaces the current #1 score with any that I supply, even it is lower. This means that only one score is ever displayed. Anyone got any idea what I'm doing wrong? I have e-mailed the dev but he/they haven't responded. Thanks in advance for any info on this, most appreciated! Dave B

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• Android - show webview in same tab containing a list

  - by Taz

  I am using a TabWidget that contains a List in one tab. What I want to do is when a user selects an item, a webview is shown in that tab. If the user then wants to go back to the list, they would click on the list tab. I can get the webview up that replaces the whole tabwidget but don't know how to leave the tabs and show a webview. Any help greatly appreciated

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• how to send image to remote server using web services in android

  - by Aswan

  get image from sdcard and store that image to remote server. i am getting the image from sdcard and i converterd that image to bytearray by using bitmap .but what's the problem if i oberver byte array it is showing some different values it is not matching with .net image byte array conversion. can u pl help if you have any solution it is very urgent to me following is the code i am using can u pl suggest me FileInputStream fin = new FileInputStream(new File("/sdcard/pictures/1.jpg")); BufferedInputStream bis = new BufferedInputStream(fin,3000); byte[] data = new byte[bis.available()]; bis.read(data, 0, data.length); byte[] data1=new byte[data.length]; for (int i = 0; i < data.length; i++) { System.out.print(data[i]); data1[i]=data[i]; } System.out.println("5..................."+data1); Bitmap bitmap = BitmapFactory.decodeByteArray(data1,0,data1.length); System.out.println("6..................."+data1.length); Log.v("hgfjohfjghjdfhgj",""+bitmap); if(bitmap!=null) image.setImageBitmap(bitmap); else Log.e("Bitmap "," Not Created");

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• Android: heavy traffic on server causes app to force close

  - by user522559

  I have developed an app to communicate with my own server and published it. However, sometimes the app force closes. I know there is no bug in the code because the app works properly most of the time, but sometimes it is waiting for an answer from the server forever. I think this is due to the fact that so many people are using the app, and the app refreshes every 1 second or so, so this heavy traffic causes the server to take a large amount of time to respond. So how do you take care of such a use case? should I have a use case where if the server does not respond after some time you just stop the app and throw a message saying that the server is not responding or something like that?

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• Make a String text Bold in Java Android

  - by meskh

  I want to make Habit Number: bold , I tried the HTML tag but it didn't work. I did some research but couldn't find any. Hope someone is able to help me. Thanks! String habitnumber = "Habit Number: " + String.valueOf(habitcounter); String Title = habit.getTitle(); String description = habit.getDescription(); //Set text for the row tv.setText(habitnumber+ "\n" + Title + " \n" + description + "\n --------------------");

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