Search Results

Search found 68715 results on 2749 pages for 'mysql data'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 209/2749 | < Previous Page | 205 206 207 208 209 210 211 212 213 214 215 216  | Next Page >

  • Finding easily parseable chemical element data

    - by nickname
    I am writing an application that needs simple data found (mostly) on the periodic table of elements, such as atomic mass, atomic number, state, etc. However, I would prefer not to manually enter this data. I managed to find the NIST website (http://www.nist.gov/pml/data/edi.cfm) with all of the data I need, but not in a downloadable format. Where can I find this data? Preferably, it would be in an XML/YAML/JSON/other documented format, however, any format would be helpful.

    Read the article

  • Using a comma seperated data in MYSQL "IN" clause

    - by Sashi Kant
    I have a column in one of my table where I store multiple ids seperated by comma's. Is there a way in which I can use this column's value in the "IN" clause of a query. The column(city) has values like 6,7,8,16,21,2 I need to use as Select * from table where e_ID in (Select city from locations where e_Id=?) I am satisfied with Crozin's answer, but I am open to suggestions, views and options. Feel free to share your views.

    Read the article

  • MySQL Removing Some Foreign keys

    - by Drew
    I have a table whose primary key is used in several other tables and has several foreign keys to other tables. CREATE TABLE location ( locationID INT NOT NULL AUTO_INCREMENT PRIMARY KEY ... ) ENGINE = InnoDB; CREATE TABLE assignment ( assignmentID INT NOT NULL AUTO_INCREMENT PRIMARY KEY, locationID INT NOT NULL, FOREIGN KEY locationIDX (locationID) REFERENCES location (locationID) ... ) ENGINE = InnoDB; CREATE TABLE assignmentStuff ( ... assignmentID INT NOT NULL, FOREIGN KEY assignmentIDX (assignmentID) REFERENCES assignment (assignmentID) ) ENGINE = InnoDB; The problem is that when I'm trying to drop one of the foreign key columns (ie locationIDX) it gives me an "ERROR 1025 (HY000): Error on rename" error. How can I drop the column in the assignment table above without getting this error?

    Read the article

  • Help with MySQL date operation

    - by jartaud
    Hello i have two columns: duration (int) and dateCol (date) in a table. How should i proceed if i want to know when CURDATE() - dateCol will iqual to duration. ie: CURDATE() - dateCol (2010-05-08) = duration (14 days), and then send an e-amil?

    Read the article

  • mysql and indexes with more than one column

    - by clarkk
    How to use indexes with more than one column The original index has an index on block_id, but is it necesarry when it's already in the unique index with two column? Indexes with more than one column (a,b,c) you can search for a, b and c you can search for a and b you can search for a you can not search for a and c Does this apply to unique indexes too? table id block_id account_id name indexes origin PRIMARY KEY (`id`) UNIQUE KEY `block_id` (`block_id`,`account_id`) KEY `block_id` (`block_id`), KEY `account_id` (`account_id`), indexes alternative PRIMARY KEY (`id`) UNIQUE KEY `block_id` (`block_id`,`account_id`) KEY `account_id` (`account_id`),

    Read the article

  • MYSQL Query with 2 columns in Table A related to 1 column in Table B

    - by CYREX
    I have 2 Tables, User and Mail. In User Table i have 2 columns that i will use, the ID column which makes the relation with the Mail Table and it is the Index of User Table and the Name column. In Mail Table i have Receiver Column and Sender Column. Both columns, Receiver and Sender have a number that relates to the ID Column in the User Table. In the User Table is where the name columns resides and i want to make a query that shows me the Receiver and Sender Columns but with the name of the user, not the ID. Up to this point i have this: SELECT name AS Send, name AS Receive FROM mail,user WHERE sender=guid; I know there is still a part of the query missing but i can not figure out what else to put to tell it to show in the SEND output column the name of the sender and in the RECEIVE output column the name of the receiver.

    Read the article

  • Display rows from MySQL where a datetime is within the next hour

    - by alex
    I always have trouble with complicated SQL queries. This is what I have $query = ' SELECT id, name, info, date_time FROM acms_events WHERE date_time = DATE_SUB(NOW(), INTERVAL 1 HOUR) AND active = 1 ORDER BY date_time ASC LIMIT 6 '; I want to get up to 6 rows that are upcoming within the hour. Is my query wrong? It does not seem to get events that are upcoming within the next hour when I test it. What is the correct syntax for this? Thanks

    Read the article

  • mySQL: Joining three tables - how?

    - by Industrial
    Hi everybody, I have the following query in my application. It works well, but I need it to also contain the number of products that are associated with each manufacturer. The current query: SELECT * FROM (`manufacturers`) JOIN `languages` ON `manufacturers`.`lang` = `languages`.`id` ORDER BY `languages`.`id` asc, `id` asc My products table looks like this: id | name | manufacturerid 0 | Product1 | 0

    Read the article

  • insert a date in mysql database

    - by kawtousse
    I use a jquery datepicker then i read it in my servlet like that: String dateimput=request.getParameter("datepicker");//1 then parse it like that: System.out.println("datepicker:" +dateimput); DateFormat df = new SimpleDateFormat("MM/dd/yyyy"); java.util.Date dt = null; try { dt = df.parse(dateimput); System.out.println("date imput parssé1 est:" +dt); System.out.println("date imput parsée2 est:" +df.format(dt)); } catch (ParseException e) { e.printStackTrace(); } and insert query like that: String query = "Insert into dailytimesheet(trackingDate,activity,projectCode) values ("+df.format(dt)+", \""+activity+"\" ,\""+projet+"\")"; it pass successfully untill now but if i check the record inserted i found the date: 01/01/0001 00:00:00 l've tried to fix it but it still a mess for me.

    Read the article

  • MySQL : incrementing text id in DB

    - by BarsMonster
    I need to have text IDs in my application. For example, we have acceptable charset azAZ09, and allowed range of IDs [aaa] - [cZ9]. First generated id would be aaa, then aab, aac, aad e.t.c. How one can return ID & increment lower bound in transaction-fashion? (provided that there are hundreds of concurrent requests and all should have correct result) To lower the load I guess it's possible to define say 20 separate ranges, and return id from random range - this should reduce contention, but it's not clear how to do single operation in the first place. Also, please note that number of IDs in range might exceed 2^32. Another idea is having ranges of 64-bit integers, and converting integer-char id in software code, where it could be done asyncroniously. Any ideas?

    Read the article

  • MySQL - how to retrieve columns in same row as the values returned by min/mx

    - by Gala101
    I couldn't frame the Question's title properly.. Suppose a table of weekly movie Earnings as below, MovieName MovieGross WeekofYear Year So how do I get the names of top grossers for each week of this year If I do select MovieName , Max(MovieGross) , WeekofYear from earnings where year = 2010 group by WeekofYear; Then obviously query wont run, select Max(MovieName) , Max(MovieGross) , WeekofYear from earnings where year = 2010 group by WeekofYear; would just give movies starting with lowest alphabet Is using group-concat and then substring-index the only option here? select substring_index(group_concat(MovieName order by MovieGross desc),',',1), Max(MovieGross) , WeekofYear from earnings where year = 2010 group by WeekofYear ; Seems clumsy.. Is there any better way of acieveing this?

    Read the article

  • How to apply GROUP_CONCAT in mysql Query

    - by Query Master
    How to apply GROUP_CONCAT in this Query if you guys have any idea or any alternate solution about this please share me. Helps are definitely appreciated also (see Query or result required) Query SELECT WEEK(cpd.added_date) AS week_no,COUNT(cpd.result) AS death_count FROM cron_players_data cpd WHERE cpd.player_id = 81 AND cpd.result = 2 AND cpd.status = 1 GROUP BY WEEK(cpd.added_date); Query output result screen Result Required 23,24,25 AS week_no 2,3,1 AS death_count

    Read the article

  • Input questions mysql php html

    - by Marcelo
    (Q1)Hi I'm using textbox in my project and I can't receive the values that are typed <textarea rows="5" cols="60"> Type your suggestion </textarea> <br> <input type="submit" name="sugestao" value="Submit" /> Sorry I don't know how to 'kill' html code, that's why < is missing. All I'm getting in the column of the database from this text box is "Submit", I'd like to receive whatever is written in the text area. How can I make the value equal whaterever is typed? (Q2) How can I make sure that I'll only store the same type(int,varchar,text) that I setted,declared in the database. For example: age(int), but if someone types "abc" in the input it will be stored in my database as the value 0 . How can I forbid this, and only save the age when it's just int and all the other fields(like name, email) are filled ?. And if is still possible warn the user that he is typing something wrong, don't need to say where. Sorry for any mistake in English and Thanks for the attention.

    Read the article

  • Validate a date range within MySQL query

    - by fishcracker
    (This question may seem easy or kind of noobish, by that I pardon my ignorance.) I used PDO query to use SELECT then fetch some values, it comes to a point that I need to fetch only some entries that within its start date and end date. My database +----------+-----------------+----------------------+--------------------+ | id (INT) | title (VARCHAR) | start_date (VARCHAR) | end_date (VARCHAR) | +----------+-----------------+----------------------+--------------------+ | 1 | buddy | 2012-11-26 | 2012-11-30 | | 2 | metro | 2012-12-05 | 2012-12-20 | | 3 | justin | 2012-11-28 | 2012-12-01 | +----------+-----------------+----------------------+--------------------+ My query is as follows: $query = "SELECT title, start_date, end_date FROM debts WHERE start_date >= CURDATE() AND end_date >= CURDATE()"; What I want to achieve is whenever the start_date is today or greater but not exceeding the end_date it will be valid. This will return the row for id 1, however if I change the start_date to 2012-11-25, it will fail due to the first condition on AND. I'm really confuse on this since I am new to this, is there any built-in function to handle this kind of situation?

    Read the article

  • Conditional SELECT MySQL

    - by user188693
    Don't know if this is possible, but I'd like to select records based on the field value of recur_type, where the 'm' is the day of the week. If it's a weekly recurring event, I need to make sure this is a day it recurs on, otherwise, I want to return all days. however, I'm getting an empty result set: SELECT * FROM wp_fun_bec_events WHERE start_date <= '2009-10-12' AND ( end_date >= '2009-10-12' OR (recur_end > '0' AND recur_end >= '2009-10-12' ) ) AND ('m' IN ( CASE WHEN 'recur_type' = 'weekly' THEN recur_days ELSE 's/m/t/w/r/f/a' END ) ) ORDER BY start_date, start_time Any ideas??

    Read the article

  • MySQL join headaches, please help!

    - by Andrew Heath
    Ok, I've hit the wall here and need some help. Sample tables are as follows: SCENARIO_NATIONS [scenID] [side] [nation] scen001 1 Germany scen001 2 Britain scen001 2 Canada SCENARIO_NEEDUNITS [scenID] [unitID] scen001 0001 scen001 0003 scen001 0107 scen001 0258 scen001 0759 UNIT_BASIC_DATA [unitID] [nation] [name] 0001 Germany Mortars 0003 Germany Infantry 0107 Britain Lt 0258 Britain Infantry 0759 Canada Kilted Yaksmen Goal: given a scenID, pull a list of units from the database sorted by side, nation, name. I can do everything except for the side inclusion with: SELECT scenario_needunits.scenID, unit_basic_data.nation, unit_basic_data.name FROM scenario_needunits LEFT OUTER JOIN unit_basic_data ON scenario_needunits.unitID=unit_basic_data.unitID WHERE scenario_needunits.scenID='scen001' ORDER BY unit_basic_data.nation ASC, unit_basic_data.name ASC I've tried just dropping the SCENARIO_NATIONS table in as a LEFT OUTER JOIN on scenID but what ends up happening is that ALL units come back with a side of 1 because that's always the first side listed for the scenID in the SCENARIO_NATIONS table. Conceptually, what I think needs to happen is SCENARIO_NATIONS must be joined to both the scenID (to restrict it to just that scenario) and to each unit's nation but I don't have any idea how to do that and my Google-fu is inadequate. :-/

    Read the article

  • PHP Code- How to check duplicate entries in Mysql Database

    - by yash bhavnani
    Hi guys, I am working on Google checkout API notification URL. I want to apply a check in my php code which will see if transaction ID present in transaction table of my DB, it will exit not process. I am struggling into applying here. Can somebody help? I want to check if trasaction ID exists in table of DB it will exit, it will not process: *case "new-order-notification": $sql = "update transactions set remote_trans_id=\"".$_REQUEST["google-order-number"]."\", updated=now() where id=".$_REQUEST["shopping-cart_items_item-1_merchant-item-id"]." "; execute($sql, $conn); break;* Regards

    Read the article

  • mysql data being inserted twice via php

    - by Jascha
    I can't for the life of me figure out why this function is causing multiple entries into my database table... When I run the function I end up with two records stacked on top of each one second apart here is the function: function generate_signup_token(){ $connection = new DB_Connect(); // <--- my database connection class $ip = mysql_real_escape_string($_SERVER['REMOTE_ADDR']); $sign_up_token = uniqid(mt_rand(), true); $_SESSION['signup_token'] = $sign_up_token; $sign_up_token = mysql_real_escape_string($sign_up_token); $query = "INSERT INTO `token_manager` (`ip_address`, `signup_token`) VALUES ('$ip', '$sign_up_token')"; mysql_query($query); } generate_signup_token();

    Read the article

  • MySQL - Join as zero if record Not IN

    - by Zurahn
    To explain by example, take two tables, A and B Table A id foo 1 x 2 y 3 z Table B id aid bar 1 3 50 2 1 100 An example join SELECT foo, bar FROM a, b WHERE a.id = b.aid; Garners a result of foo bar z 50 x 100 What I would like to do is get all values of foo and for any instances where there isn't a corresponding bar value, return 0 for that column. My best guess was something along the lines of SELECT foo, bar AS br FROM a, b WHERE a.id = b.aid OR a.id NOT IN (SELECT aid FROM b); But that returns duplicates and non-zero values for bar. Possible?

    Read the article

  • Mysql Avg function for recent 15 records by date (order date desc) in every symbol

    - by venkatesh
    i am trying to create a statement in sql (for a table which holds stock symbols and price on specified date) with avg of 5 day price and avg of 15 days price for each symbol. table description: symbol open high close date the average price is calculated from last 5 days and last 15 days. i tried this for getting 1 symbol: SELECT avg(close), avg(`trd_qty`) FROM (select * from cashmarket WHERE symbol = \'hdil\' order by `M_day` desc limit 0,15 ) s ...but I couldn't get the desired the list for showing avg values for all symbols.

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 205 206 207 208 209 210 211 212 213 214 215 216  | Next Page >