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  • MySQL charset issue.

    - by Shagymoe
    I'm not sure exactly why this happened, but I'm assuming it was an dump and import. The db is full of characters like — for commas and such. I've tried various solutions on the web, but nothing seems to work. I've verified that the html header specifies utf8. Any ideas on how I can get the entire db back to normal characters?

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  • Validation library for PHP/mysql

    - by Industrial
    Hi! Is there any lightweight validation library available for PHP that easily can check if a specific string or value is valid for a known database type - Something like this: if (is_MEDIUMINT($var)) { $this->db->insert($anothervar); } Thanks!

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  • how store date in mysql database?

    - by Syom
    i have date in dd/mm/yyyy format. how can i store it in databse, if i fant to do some operations on them after? for example i must find out the rows, where date > something what type i must set to date field? thanks

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  • onUpdate in MySQL means?

    - by ajsie
    i know that if you create a foreign key on a field (parent_id) in a child table that refer to a parent table's primary key (id), then if this parent table is deleted the child class will be deleted as well if you set onDelete to cascade when creating the foreign key in the child class. but what happens if i set it to onUpdate = cascade?

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  • Possibly simple PHP/MYSQL issue with retrieving and showing data

    - by envoys
    I have been racking my brains over this for a while now. Here is the data i have in the sql data base as an example: ID | TYPE | DATA 1 | TXT | TEST 2 | PHP | php 3 | JS | JAVASCRIPT That is just an example, there are multiple listing for TXT, PHP and JS throughout the table. What I want to do is retrive all the data and display it all into separate drop down/select boxes. Meaning, select box one would list all data with type TXT, select box two would list all data with type PHP and select box 3 would list all data with type JS. The only way I have came about doing this is doing individual sql queries for each different type. I know there is a way to do it all in 1 query and then display it the way I want to but I just can't seem to figure out how and I know its going to drive me nuts when someone helps and I see just how they did it. Thanks for the input.

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  • Setting MySQL column names

    - by Richard Mar.
    Say I have these tables: people(id, name), cars(person_id, car) and this query: SELECT c.car FROM people as p, cars as c WHERE c.person_id = p.id AND p.id = 3 I want the c.car column to take its name from the name field in the people table, like this (invalid SQL, just to illustrate): SELECT c.car AS(SELECT name FROM people WHERE id = 3) How do I do that?

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  • Mysql SELECT with an OR across 2 columns

    - by Haroldo
    I'm creating a 'similar items' link table. i have a 2 column table. both columns contains product ids. The table is showing that these items are similar. However ids in the left column are more valuable. Say i want to select similar items to product '125b'. i only want 3 similar items to 125b. If there are any instances of 125b in col1 I would prefer these to finding 125b in col2. so i need a select statement along the lines of SELECT * FROM similar_items WHERE col_1={$id} OR col_2={$id} ORDER BY column(?) LIMIT 3 i do not want to do 2 separate queries ( ie query 2 if count(query1) <3 )

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  • delete row from mysql through generated table with records

    - by HennySmafter
    I am using 2 pages. On one page it generates a table with the records and a delete button. After pressing delete it goes to the second page which should delete the record. But it doesn't. Below is the code that I am using. PS: The code is adapted from a tutorial I found through Google a while ago. delete_overzicht.php <?php // Load Joomla! configuration file require_once('../../../configuration.php'); // Create a JConfig object $config = new JConfig(); // Get the required codes from the configuration file $server = $config->host; $username = $config->user; $password = $config->password; $database = $config->db; // Connect to db $con = mysqli_connect($server,$username,$password,$database); if (!$con){ die('Could not connect: ' . mysqli_error($con)); } mysqli_select_db($con,$database); // Get results $result = mysqli_query($con,"SELECT * FROM cypg8_overzicht"); echo "<table border='1' id='example' class='tablesorter'><thead><tr><th>Formulier Id</th><th>Domeinnaam</th><th>Bedrijfsnaam</th><th>Datum</th><th>Periode</th><th>Subtotaal</th><th>Dealernaam</th><th>Verwijderen</th></tr></thead><tbody>"; while($row = mysqli_fetch_array($result)) { echo "<tr>"; echo "<td>" . $row['formuliernummer'] . "</td>"; echo "<td>" . $row['domeinnaam'] . "</td>"; echo "<td>" . $row['bedrijfsnaam'] . "</td>"; echo "<td>" . $row['datum'] . "</td>"; echo "<td>" . $row['periode'] . "</td>"; echo "<td> &euro; " . $row['subtotaal'] . "</td>"; echo "<td>" . $row['dealercontactpersoon'] . "</td>"; echo "<td><a href='delete.php?id=" . $row['id'] . "'>Verwijderen </a></td>"; echo "</tr>"; } echo "</tbody></table>"; mysqli_close($con); ?> delete.php <?php // Load Joomla! configuration file require_once('../../../configuration.php'); // Create a JConfig object $config = new JConfig(); // Get the required codes from the configuration file $server = $config->host; $username = $config->user; $password = $config->password; $database = $config->db; // Connect to db $con = mysqli_connect($server,$username,$password,$database); if (!$con){ die('Could not connect: ' . mysqli_error($con)); } mysqli_select_db($con,$database); // Check whether the value for id is transmitted if (isset($_GET['id'])) { // Put the value in a separate variable $id = $_GET['id']; // Query the database for the details of the chosen id $result = mysqli_query($con,"DELETE * FROM cypg8_overzicht WHERE id = $id"); } else { die("No valid id specified!"); } ?> Thanks to everyone who is willing to help!

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  • how to remove mysql root password

    - by nectar
    I want to remove password for user root in localhost how can I do that?by mistake I have set the password of root user thats why phpmyadmin is giving error- #1045 - Access denied for user 'root'@'localhost' (using password: NO)

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  • Problem with MySQL query

    - by Psyche
    This time my setup looks like this: one table with galleries names (gallery_id, gallery_name) and another table with galleries photos (photo_id, photo_gallery_id, photo_name). What I need is to get all the galleries with one random picture for each gallery. Is it possible to do this with a single query?

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  • mysql database design: threads and replies

    - by ajsie
    in my forum i have threads and replies. one thread has multiple replies. but then, a reply can be a reply of an reply (like google wave). because of that a reply has to have a column "reply_id" so it can point to the parent reply. but then, the "top-level" replies (the replies directly under the thread) will have no parent reply. so how can i fix this? how should the columns be in the reply table (and thread table). at the moment it looks like this: threads: id title body replies: id thread_id (all replies will belong to a thread) reply_id (here lies the problem. the top-level replies wont have a parent reply) body what could a smart design look like to enable reply a reply?

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  • MYSQL UPDATE with IN and Subquery

    - by Johal
    Hi i have tables like this : table entry : id | total_comments ___________ 1 | 0 2 | 0 3 | 0 4 | 0 table comments : id | eid | comment ___________ 1 | 1 | comment sdfd 2 | 1 | testing testing 3 | 1 | comment text 4 | 2 | dummy comment 5 | 2 | sample comment 6 | 1 | fg fgh dfh Query i write : UPDATE entry SET total_comments = total_comments + 1 WHERE id IN ( SELECT eid FROM comments WHERE id IN (1,2,3,4,5,6)) Results i get is : table entry : id | total_comments ___________ 1 | 1 2 | 1 3 | 0 4 | 0 Expected results : table entry : id | total_comments ___________ 1 | 4 2 | 2 3 | 0 4 | 0 Any help will be appreciated.

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  • Duplication in mysql/php

    - by user1334095
    I have a problem in the code.i have two tables 'sms' and 'bd_paid_bribe'.sms table has a column 'Message' and bd_paid_bribe table has a column 'c_addi_info'.when i execute the code first time all the values of Message column are inserted into c_addi_info column.when i enter a record for the second time instead of inserting the new record, all the records of Message column are inserted into bd_paid_bribe column.can u modify the code and provide a solution to avoid duplication and to insert only the newly added record. <?php $con=mysql_connect('localhost','root',''); if(!$con) { die("couldn't connect"); } mysql_select_db("ipab2",$con); $rs2=mysql_query(" select max(sms_index) from tab3"); do { $rs=mysql_query("insert into tab3(sms_index)select max(sms_index) from sms"); $rs3=mysql_query("SELECT max(sms_index) FROM sms"); $rs1=mysql_query("insert into bd_paid_bribe(c_addi_info) select Message from sms "); }while($rs2>$rs3); ?>

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  • Export data from mysql table row into an array format

    - by user1804952
    I am trying to output data from table : artists row : artist into this format. Artist Names can have special characters and there are over 16k of them. It needs to be written to a file. called anything artist.php for example $Artist = array( "Name from database", "Name from database", "Name from database", "Name from database", "Name from database" ); ok sorry for not explaining. do this for ajax auto complete.. so i need to create a file with this array in it. here is the exact script http://www.brandspankingnew.net/specials/ajax_autosuggest/ajax_autosuggest_autocomplete.html

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  • Check if the current date is between two dates + mysql select query

    - by kj7
    I have following table : id dateStart dateEnd active 1 2012-11-12 2012-12-31 0 2 2012-11-12 2012-12-31 0 I want to compare todays date in between dateStart and dateEnd. Following is my query for this : $todaysDate="2012-26-11"; $db = Zend_Registry::get("db"); $result = $db->fetchAll("SELECT * FROM `table` WHERE active=0 AND {$todaysDate} between dateStart and dateEnd"); return $result; But its not working. Any solution. Thanks in advance.

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  • PHP MYSQL SIMPLE SEARCH ISSUE

    - by Kunal
    Hi I have a table with the following structure: id int(11), name varchar(250) I have lots of records in the table but when I am trying to find a particluar record which has the following value on the name field: Lorem ipsum d\'olor sit amet The query is simply returning a blank recordset. I am not being able to figure out this weird behaviour, when my query is as simple as follows: SELECT * FROM slot_games WHERE name='Lorem ipsum d\'olor sit amet' Would appreciate your help please! Thanks in advance.

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  • Adding up row number and displaying total using COUNT (PHP MySQL)

    - by Yvonne
    I'm attempting to run a query that adds up the total number of subjects in a class. A class has many subjects. There is a 'teachersclasses' table between teachers (the user table) and classes. The principles sounds pretty simple but I'm having some trouble in getting my page to display the number of subjects for each class (directly associated with the teacher) This is what I have so far, trying to make use of the COUNT with a nested SELECT: SELECT (SELECT count(*) FROM subjects WHERE subjects.classid = class.classid) AS total_subjects, class.classname, class.classid FROM class Then I am calling up 'num_subjects' to present the total within a while loop: <?php echo $row['total_subjects']?> From the above, I am receiving the total subjects for a class, but within the same table row (for one class) and my other while loop doesnt run anymore, which returns all of the classes associated with a teacher :( ... Bit of a mess now! I know to return the classes for a particular teacher, I can do an additional WHERE clause on the session of 'teacherid' but I think my query is getting too complicated for me that errors are popping up everywhere. Anyone have a quick fix for this! Thanks very much

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  • How to optimize this MYSQL table?

    - by Lost_in_code
    This is for an upcoming project. I have two tables - first one keeps tracks of photos, and the second one keeps track of the photo's rank Photos: +-------+-----------+------------------+ | id | photo | current_rank | +-------+-----------+------------------+ | 1 | apple | 5 | | 2 | orange | 9 | +-------+-----------+------------------+ The photo rank keeps changing on a regular basis and this is the table that tracks it: Ranks: +-------+-----------+----------+-------------+ | id | photo_id | ranks | timestamp | +-------+-----------+----------+-------------+ | 1 | 1 | 8 | * | | 2 | 2 | 2 | * | | 3 | 1 | 3 | * | | 4 | 1 | 7 | * | | 5 | 1 | 5 | * | | 6 | 2 | 9 | * | +-------+-----------+----------+-------------+ * = current timestamp Every rank is tracked for reporting/analysis purpose. I talked to someone who has experience in this field and he told me that storing ranks like above is the way to go. But I'm not so sure yet. The problem here is data redundancy. There are going to be tens of thousands of photos. The photo rank changes on a hourly basis (many time within minutes) for recent photos but less frequently for older photos. At this rate the table will have millions of records within months. And since I do not have experience in working with large databases, this makes me a little nervous. I thought of this: Ranks: +-------+-----------+--------------------+ | id | photo_id | ranks | +-------+-----------+--------------------+ | 1 | 1 | 8:*,3:*,7:*,5:* | | 2 | 2 | 2:*,9:* | +-------+-----------+--------------------+ * = current timestamp That means some extra code in PHP to split the rank/time (and sorting) but that looks OK to me. Is this a correct way to optimize the table for performance? What would you recommend? Any suggestions would be great.

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  • MySQL: Insert into multiple tables in same query with BEGIN&COMMIT

    - by strc
    I want to insert into multiple tables in same query by using BEGIN and COMMIT. It seems the error occur at begin. here is my SQL command BEGIN INSERT INTO Product (pName, pBrand, pCategory, pSize, pQuantity, pPrice, pDetail) VALUES('$name', '$brand', '$category', '$size', '$quantity', '$price', '$detail') INSERT INTO Image (iName, iExt, iSize, pID) VALUES('$img_name', '$img_ext', '$img_size', LAST_INSERT_ID()); COMMIT;

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  • cant made mySQL connection

    - by Andika Evangelion Thirteenth S
    I've use following code $con = mysql_connect("localhost","root","");if (!$con) {die('Could not connect: ' . mysql_error());} It's works. but when $db_host='localhost';$db_id='root';$db_pass=''; $con = mysql_connect($db_host,$db_id,$db_pass);if (!$con) {die('Could not connect: ' . mysql_error());} it didn't works, trying to swap ("),('),and empty in mysql_connect() and in $var and vice versa. Any help would be appreciated. Thanks.

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