Search Results

Search found 16764 results on 671 pages for 'provider model'.

Page 209/671 | < Previous Page | 205 206 207 208 209 210 211 212 213 214 215 216  | Next Page >

  • Name that blog entry - Modelling changes over time with two db columns only.

    - by disown
    I vaguely remember reading a blog entry (written by a well-known blogger I think) about how to model price changes over time, and that you could model most changes by saving two dates only (two columns in a db). The blog talked about prices on a website changing over time and how you could figure out the right price to charge knowing only when the purchase had been made. Very vague, I know, but my google-fu is failing me, everyone at IRC are busy talking about other stuff and I don't know what to do! :)

    Read the article

  • Inconsistent accessibility

    - by user1312412
    I am getting the following error Inconsistent accessibility: parameter type 'Db.Form1.ConnectionString' is less accessible than method 'Db.Form1.BuildConnectionString(Db.Form1.ConnectionString)' //Name spaces using System; using System.Collections.Generic; using System.ComponentModel; using System.Data; using System.Drawing; using System.Linq; using System.Text; using System.Windows.Forms; using Microsoft.VisualBasic; using System.Collections; using System.Diagnostics; using System.Data.OleDb; using System.IO; using System.Drawing.Printing; // namespace Db { public partial class Form1 : Form { public Form1() { InitializeComponent(); } public void SetBusy() { this.Cursor = Cursors.WaitCursor; Application.DoEvents(); } public void SetFree() { this.Cursor = Cursors.Default; Application.DoEvents(); } //connection string into parts struct ConnectionString { public string Provider; public string DataSource; public string UserId; public string Password; public string Database; } //Declare public string BuildConnectionString(ConnectionString connStr) ------> getting error here { string[] parts = new string[5]; parts[0] = "Provider=" + connStr.Provider; parts[1] = "Data Source=" + connStr.DataSource; parts[2] = "User Id=" + connStr.UserId; parts[3] = "Password=" + connStr.Password; parts[4] = "Initial Catalog=" + connStr.Database; return string.Join(";", parts); } // settings public bool IsValidConnectionForPrinting() { SetBusy(); ConnectionString connStr = new ConnectionString(); connStr.Provider = cboProvider.Text; connStr.DataSource = cboDataSource.Text; connStr.UserId = txtUserId.Text; connStr.Password = txtPassword.Text; connStr.Database = cboDatabase.Text; //connection string to database string connectionString = BuildConnectionString(connStr); OleDbConnection conn = new OleDbConnection(connectionString); try { conn.Open(); OleDbCommand cmd = conn.CreateCommand; cmd.CommandType = CommandType.TableDirect; cmd.CommandText = "vw_pr_DL"; cmd.ExecuteScalar(); cmd.CommandText = "vw_pr_VR"; cmd.ExecuteScalar(); //cmd.CommandText = "vw_pr_VR" //cmd.ExecuteScalar() conn.Close(); } //Exception messages catch (Exception ex) { SetFree(); if (ex.Message.StartsWith("Invalid object name")) { MessageBox.Show(ex.Message.Replace("Invalid object name", "Table or view not found"), "Connection Test"); } else { MessageBox.Show(ex.GetBaseException().Message, "Connection Test"); } return false; } SetFree(); return true; } // when user click testbutton private void btnConnTest_Click(object sender, EventArgs e) { if (IsValidConnectionForPrinting()) { MessageBox.Show("Connection succeeded", "Connection Test"); } }

    Read the article

  • Calling overridden method from within overriding method in OO PHP

    - by paddymcc
    Working in a symfony model, I want to override a function and call the overridden function from within the overriding one, along the lines of class MyClass extends BaseMyClass { function setMyProperty($p) { parent::setMyProperty($p); //do some other stuff } } This is resulting in a segmentation fault. I don't want to alter the parent class - it's been generated by symfony, and may feasibly be overwritten in the future if the model is rebuilt. This seems like something that should be straightforward, but I'm struggling to find the solution. Thanks for any advice

    Read the article

  • How can one check for a binary in the GAC in a WiX installer?

    - by Billy ONeal
    I have an application which depends on the Team Foundation Server "Object Model", and looks for such binaries in the GAC. This means that clients of the app need to install Visual Studio, or the standalone TFS object model in order to use the application. I would like the installer to detect that the TFS bits aren't installed, and fail to install appropriately if they are not. Is such a thing possible?

    Read the article

  • Django - Can you use property as the field in an aggregation function?

    - by orokusaki
    I know the short answer because I tried it. Is there any way to accomplish this though (even if only on account of a hack)? class Ticket(models.Model): account = modelfields.AccountField() uuid = models.CharField(max_length=36, unique=True) created = models.DateTimeField(auto_now_add=True) class Meta: ordering = ['created'] @property def repair_cost(self): # cost is a @property of LineItem(models.Model) return self.lineitem_set.aggregate(models.Sum('cost'))

    Read the article

  • getting Cannot identify image file when trying to create thumbnail in django

    - by Mo J. Mughrabi
    Am trying to create a thumbnail in django, am trying to build a custom class specifically to be used for generating thumbnails. As following from StringIO import StringIO from PIL import Image class Thumbnail(object): source = '' size = (50, 50) output = '' def __init__(self): pass @staticmethod def load(src): self = Thumbnail() self.source = src return self def generate(self, size=(50, 50)): if not isinstance(size, tuple): raise Exception('Thumbnail class: The size parameter must be an instance of a tuple.') self.size = size # resize properties box = self.size factor = 1 fit = True image = Image.open(self.source) # Convert to RGB if necessary if image.mode not in ('L', 'RGB'): image = image.convert('RGB') while image.size[0]/factor > 2*box[0] and image.size[1]*2/factor > 2*box[1]: factor *=2 if factor > 1: image.thumbnail((image.size[0]/factor, image.size[1]/factor), Image.NEAREST) #calculate the cropping box and get the cropped part if fit: x1 = y1 = 0 x2, y2 = image.size wRatio = 1.0 * x2/box[0] hRatio = 1.0 * y2/box[1] if hRatio > wRatio: y1 = int(y2/2-box[1]*wRatio/2) y2 = int(y2/2+box[1]*wRatio/2) else: x1 = int(x2/2-box[0]*hRatio/2) x2 = int(x2/2+box[0]*hRatio/2) image = image.crop((x1,y1,x2,y2)) #Resize the image with best quality algorithm ANTI-ALIAS image.thumbnail(box, Image.ANTIALIAS) # save image to memory temp_handle = StringIO() image.save(temp_handle, 'png') temp_handle.seek(0) self.output = temp_handle return self def get_output(self): return self.output.read() the purpose of the class is so i can use it inside different locations to generate thumbnails on the fly. The class works perfectly, I've tested it directly under a view.. I've implemented the thumbnail class inside the save method of the forms to resize the original images on saving. in my design, I have two fields for thumbnails. I was able to generate one thumbnail, if I try to generate two it crashes and I've been stuck for hours not sure whats the problem. Here is my model class Image(models.Model): article = models.ForeignKey(Article) title = models.CharField(max_length=100, null=True, blank=True) src = models.ImageField(upload_to='publication/image/') r128 = models.ImageField(upload_to='publication/image/128/', blank=True, null=True) r200 = models.ImageField(upload_to='publication/image/200/', blank=True, null=True) uploaded_at = models.DateTimeField(auto_now=True) Here is my forms class ImageForm(models.ModelForm): """ """ class Meta: model = Image fields = ('src',) def save(self, commit=True): instance = super(ImageForm, self).save(commit=True) file = Thumbnail.load(instance.src) instance.r128 = SimpleUploadedFile( instance.src.name, file.generate((128, 128)).get_output(), content_type='image/png' ) instance.r200 = SimpleUploadedFile( instance.src.name, file.generate((200, 200)).get_output(), content_type='image/png' ) if commit: instance.save() return instance the strange part is, when i remove the line which contains instance.r200 in the form save. It works fine, and it does the thumbnail and stores it successfully. Once I add the second thumbnail it fails.. Any ideas what am doing wrong here? Thanks Update: I tried earlier doing the following but I still got the same error class ImageForm(models.ModelForm): """ """ class Meta: model = Image fields = ('src',) def save(self, commit=True): instance = super(ImageForm, self).save(commit=True) instance.r128 = SimpleUploadedFile( instance.src.name, Thumbnail.load(instance.src).generate((128, 128)).get_output(), content_type='image/png' ) instance.r200 = SimpleUploadedFile( instance.src.name, Thumbnail.load(instance.src).generate((200, 200)).get_output(), content_type='image/png' ) if commit: instance.save() return instance

    Read the article

  • Google App Engine getting verbose_name of a property from an instance

    - by Brian M. Hunt
    Given a model likeso: from google.appengine.ext import db class X(db.Model): p = db.StringProperty(verbose_name="Like p, but more modern.") How does one access verbose_name from x=X() (an instance of X)? One might expect that x.p.verbose_name would work, or alternatively x.properties()['p'].verbose_name, but neither seems to work. Thanks! EDIT: x.name.verbose_name = x.p.verbose_name

    Read the article

  • Trouble with ASP.NET MVC auto-scaffolder template

    - by DanM
    I'm trying to write an auto-scaffolder template for Index views. I'd like to be able to pass in a collection of models or view-models (e.g., IQueryable<MyViewModel>) and get back an HTML table that uses the DisplayName attribute for the headings (th elements) and Html.Display(propertyName) for the cells (td elements). Each row should correspond to one item in the collection. Here's what I have so far: <%@ Control Language="C#" Inherits="System.Web.Mvc.ViewUserControl" %> <% var items = (IQueryable<TestProj.ViewModels.TestViewModel>)Model; // How do I make this generic? var properties = items.First().GetMetadata().Properties .Where(pm => pm.ShowForDisplay && !ViewData.TemplateInfo.Visited(pm)); %> <table> <tr> <% foreach(var property in properties) { %> <th> <%= property.DisplayName %> </th> <% } %> </tr> <% foreach(var item in items) { HtmlHelper itemHtml = ????; // What should I put in place of "????"? %> <tr> <% foreach(var property in properties) { %> <td> <%= itemHtml.Display(property.DisplayName) %> </td> <% } %> </tr> <% } %> </table> Two problems with this: I'd like it to be generic. So, I'd like to replace var items = (IQueryable<TestProj.ViewModels.TestViewModel>)Model; with var items = (IQueryable<T>)Model; or something to that effect. A property Html is automatically created for me when the view is created, but this HtmlHelper applies to the whole collection. I need to somehow create an itemHtml object that applies just to the current item in the foreach loop. I'm not sure how to do this, however, because the constructors for HtmlHelper don't take a Model object. How do I solve these two problems?

    Read the article

  • Getting below error when trying to register a generic class with a implementation using .net 2.0

    - by Gaurav Saxena
    Code: StructureMapConfiguration.BuildInstancesOf().AsSingletons().TheDefaultIsConcreteType(); Error: StructureMap Exception Code: 190 Can not create a Generic PluginFamily for PluginFamily MIGExcel.Service.IPersistenceService1[[MIGExcel.Model.Contact, WizardModel, Version=1.0.0.0, Culture=neutral, PublicKeyToken=null]]. Check that the basic type MIGExcel.Service.IPersistenceService1 is configured as a PluginFamily. These Generic types are configured within StructureMap as PluginFamily's: MIGExcel.Service.IPersistenceService`1[[MIGExcel.Model.Contact, WizardModel, Version=1.0.0.0, Culture=neutral, PublicKeyToken=null]],MIGExcel.Service;

    Read the article

  • Is it possible to route *.example.com to a single machine without registering extra domains?

    - by oligofren
    I would like to achieve something similar to what wordpress.com does - giving each user its own subdomain. user1.wordpress.com would in the VirtualHosts setup of Apache would have its DocRoot at /user/user1, for instance. Now, our hosting service provider takes a fee for creating a domain, and in our case this would mean a ridiculous number of domains with a matching price. After some googling on DNS I came over a description of a DNAME record. That seems to fit the bill precisely. Any reason why my service provider would not do this, or why I should not do this?

    Read the article

  • Migrating Identity Providers - specifying a new users password hash.

    - by Stephen Denne
    We'd like to switch Identity Provider (and Web Access Manager), and also the user directory we use, but would like to do so without users needing to change their password. We currently have the SSHA of the passwords. I'm expecting to write code to perform the migration. I don't mind how complex the code has to be, rather my concern is whether such a migration is possible at all. MS Active Directory would be our preferred user store, but I believe that it can not have new users set up in it with a particular password hash. Is that correct? What user directory stores can be populated with users already set up with a SSHA password? What Identity Provider and Access Management products work with those stores?

    Read the article

  • Netbeans code templates' modifiers

    - by hsz
    Hello ! I set a new PHP code template in Netbeans: /* @var $$${name}Table Model_${name}_Table */ $$${name}Table = Container::get('model')->get('${name}_Table'); and if I use as ${name} some value - shop - I have in output: /* @var $shopTable Model_shop_Table */ $shopTable = Container::get('model')->get('shop_Table'); Is it possible to add some modifier to the second and fourth ${name} so I will have it started with upper letter ? Shop_Table instead of shop_Table

    Read the article

  • What are MVP and MVC and what is the difference?

    - by Wolfbyte
    When looking beyond the RAD (drag-drop and configure) way of building User Interfaces that many tools encourage you are likely to come across 2 design patterns called Model-View-Controller and Model-View-Presenter. My question has two parts to it: What issues do these patterns address? How are they similar? How are they different?

    Read the article

  • How secure is cloud computing?

    - by Rhubarb
    By secure, I don't mean the machines itself and access to it from the network. I mean, and I suppose this could be applied to any kind of hosting service, when you put all your intellectual property onto a hosted provider, what happens to the hard disks as they cycle through them? Say I've invested million into my software, and the information and data that I have is valuable, how can I be sure it isn't read off old disks as they're recycled? Is there some kind of standard to look for that ensures a provider is going to use the strictest form of intellectual property protection? Is SAS70 applicable here?

    Read the article

  • Entity Framework 4 POCO with Dictionary

    - by Eric J.
    I have a POCO (Plain Old CLR Object) public Foo { public virtual int Id { get; set; } public virtual Dictionary<string, string> Stuff { get; set; } public virtual string More { get; set; } } Using the model first approach (i.e. I don't have a data model yet), how would I handle persisting Stuff (Dictionary)?

    Read the article

  • Create and Share a File (Also a mysterious error)

    - by Kirk
    My goal is to create a XML file and then send it through the share Intent. I'm able to create a XML file using this code FileOutputStream outputStream = context.openFileOutput(fileName, Context.MODE_WORLD_READABLE); PrintStream printStream = new PrintStream(outputStream); String xml = this.writeXml(); // get XML here printStream.println(xml); printStream.close(); I'm stuck trying to retrieve a Uri to the output file in order to share it. I first tried to access the file by converting the file to a Uri File outFile = context.getFileStreamPath(fileName); return Uri.fromFile(outFile); This returns file:///data/data/com.my.package/files/myfile.xml but I cannot appear to attach this to an email, upload, etc. If I manually check the file length, it's proper and shows there is a reasonable file size. Next I created a content provider and tried to reference the file and it isn't a valid handle to the file. The ContentProvider doesn't ever seem to be called a any point. Uri uri = Uri.parse("content://" + CachedFileProvider.AUTHORITY + "/" + fileName); return uri; This returns content://com.my.package.provider/myfile.xml but I check the file and it's zero length. How do I access files properly? Do I need to create the file with the content provider? If so, how? Update Here is the code I'm using to share. If I select Gmail, it does show as an attachment but when I send it gives an error Couldn't show attachment and the email that arrives has no attachment. public void onClick(View view) { Log.d(TAG, "onClick " + view.getId()); switch (view.getId()) { case R.id.share_cancel: setResult(RESULT_CANCELED, getIntent()); finish(); break; case R.id.share_share: MyXml xml = new MyXml(); Uri uri; try { uri = xml.writeXmlToFile(getApplicationContext(), "myfile.xml"); //uri is "file:///data/data/com.my.package/files/myfile.xml" Log.d(TAG, "Share URI: " + uri.toString() + " path: " + uri.getPath()); File f = new File(uri.getPath()); Log.d(TAG, "File length: " + f.length()); // shows a valid file size Intent shareIntent = new Intent(); shareIntent.setAction(Intent.ACTION_SEND); shareIntent.putExtra(Intent.EXTRA_STREAM, uri); shareIntent.setType("text/plain"); startActivity(Intent.createChooser(shareIntent, "Share")); } catch (FileNotFoundException e) { e.printStackTrace(); } break; } } I noticed that there is an Exception thrown here from inside createChooser(...), but I can't figure out why it's thrown. E/ActivityThread(572): Activity com.android.internal.app.ChooserActivity has leaked IntentReceiver com.android.internal.app.ResolverActivity$1@4148d658 that was originally registered here. Are you missing a call to unregisterReceiver()? I've researched this error and can't find anything obvious. Both of these links suggest that I need to unregister a receiver. Chooser Activity Leak - Android Why does Intent.createChooser() need a BroadcastReceiver and how to implement? I have a receiver setup, but it's for an AlarmManager that is set elsewhere and doesn't require the app to register / unregister. Code for openFile(...) In case it's needed, here is the content provider I've created. public ParcelFileDescriptor openFile(Uri uri, String mode) throws FileNotFoundException { String fileLocation = getContext().getCacheDir() + "/" + uri.getLastPathSegment(); ParcelFileDescriptor pfd = ParcelFileDescriptor.open(new File(fileLocation), ParcelFileDescriptor.MODE_READ_ONLY); return pfd; }

    Read the article

  • django sort by manytomany relationship

    - by Marconi
    I have the following model: class Service(models.Model): ratings = models.ManyToManyField(User) Now if I wanna get all the service with ratings sorted in descending order I did something: services_list = Service.objects.filter(ratings__gt=0).distinct() services_list = list(services_list) services_list.sort(key=lambda service: service.ratings.all().count(), reverse=True) As you can see its a three step process and I don't feel right about this. Anybody who knows a better way to do this?

    Read the article

  • I cannot connect to database from Drupal

    - by Patrick
    hi, I've uploaded my drupal website (and related database) to my new server. The database info is: host: localhost user: user pass: pass databaseName = database_name I've set the following line in settings.php file: $db_url = 'mysqli://user:password@localhost/database_name'; but what I get is this: If you are the maintainer of this site, please check your database settings in the settings.php file and ensure that your hosting provider's database server is running. For more help, see the handbook, or contact your hosting provider. I guess the database is running, it always run and I can access with phpmyadmin so I think the problem is not there. The database and website files upload have also been succesfull.. so I dunno what to do to fix this issue. It is mysql on IIS Server thanks

    Read the article

  • Planning a requirements gathering session using Agile

    - by Dave Smith
    We are planning on introducing Agile into our development process (a shift from the waterfall we've been using so far). We are leaning towards a hybrid model in whcih the requirements gathering session is comprised of a business analyst, subject matter experts, technical person and a user interface person. The plan is to create user stories that the development team can use in their agile process with 1 month sprints. Has anyone had experience with a hybrid model? How has it worked for you so far?

    Read the article

  • jQuery MVC architecture

    - by Tomas Barbak
    Hi, what is the best way to create MVC architecture in jQuery? Should I use jQuery.extend()? jQuery.extend({ View: function(){} }); ...or jQuery Plugin? (function($) { $.fn.model = function() { return this; }; })(jQuery); ...or just objects in JavaScript? var model = {} var view = {} var controller = {} Thank you!

    Read the article

  • Which is more flexible in regards to database changes, EF 4 or Linq to SQL

    - by JBeckton
    Reading about both Linq to SQL and Entity Framework I have developed the impression that EF is more suitable for apps that get data from multiple data sources. But as I am reading about MVC2 models I see an example where EF is more loosely coupled with your data model. If I have to add or remove some columns from a table then what is involved in updating my model or DAL with each of these implementations?

    Read the article

  • how can i request a variable in my home.ctp of my cakePHP application?

    - by Simon
    I created a page using the MVC structure called 'sections' ( view is located in the app/views/sections folder, model in the model folder and the controller in the controller folder) when i request the variable $test, it works fine without any errors.. When i want to request this variable in my home.ctp, it provides me with an error, saying that the variable is undefined.. Is there any way in cakePHP to request this variable on any page you want it to? Thnx in advance!

    Read the article

  • Formtastic + nested categories

    - by astropanic
    I have an article model and an category model. Category act as tree. What is the best approch to build a select list to allow the administrator to select an category from a select list to associate it later with an article ? semantic_form_for(@article) do |f| f.input :title, :as => :string f.input :content, :as => :text f.input :category, :collection => #what should go here ? end

    Read the article

< Previous Page | 205 206 207 208 209 210 211 212 213 214 215 216  | Next Page >