How to treat Base* pointer as Derived<T>* pointer?
- by dehmann
I would like to store pointers to a Base class in a vector, but then use them as function arguments where they act as a specific class, see here:
#include <iostream>
#include <vector>
class Base {};
template<class T>
class Derived : public Base {};
void Foo(Derived<int>* d) {
std::cerr << "Processing int" << std::endl;
}
void Foo(Derived<double>* d) {
std::cerr << "Processing double" << std::endl;
}
int main() {
std::vector<Base*> vec;
vec.push_back(new Derived<int>());
vec.push_back(new Derived<double>());
Foo(vec[0]);
Foo(vec[1]);
delete vec[0];
delete vec[1];
return 0;
}
This doesn't compile:
error: call of overloaded 'Foo(Base*&)' is ambiguous
Is it possible to make it work? I need to process the elements of the vector differently, according to their int, double, etc. types.
