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  • Need help with a Linq XML conditional grouping query

    - by FiveTools
    I have the following xml fragment: <BANNER ID="Banner 2" ROW_WIDTH="200"> <BANNER_TEXTS ID="BANNER_TEXTS"> <BANNER_TEXT UNDERLINE="false" SPAN_COL="1" WIDTHT="78px"></BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="3" WIDTHT="234px">Years In Practice</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="3" WIDTHT="234px">Internet Usage</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="4" WIDTHT="312px">Sales Reps Seen / Week</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="3" WIDTHT="234px">Prescription Volume</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="3" WIDTHT="222px">Patient Load</BANNER_TEXT> </BANNER_TEXTS> <BANNER_TEXTS ID="COLUMN_TEXTS"> <BANNER_TEXT UNDERLINE="true" SPAN_COL="1" WIDTHT="78px">Total</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="1" WIDTHT="78px">&#60; 11 years</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="1" WIDTHT="78px">11-20 years</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="1" WIDTHT="78px">21-30 years</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="1" WIDTHT="78px">Light 1-5 hrs</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="1" WIDTHT="78px">Medium 6-10 hrs</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="1" WIDTHT="78px">Heavy &#62;10 hrs</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="1" WIDTHT="78px">0</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="1" WIDTHT="78px">1-2</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="1" WIDTHT="78px">3-5</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="1" WIDTHT="78px">&#62;5</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="1" WIDTHT="78px">1-100</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="1" WIDTHT="78px">101-150</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="1" WIDTHT="78px">&#62;150</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="1" WIDTHT="74px">1-100</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="1" WIDTHT="74px">101-200</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="1" WIDTHT="74px">&#62;200</BANNER_TEXT> </BANNER_TEXTS> <BANNER_TEXTS ID="COLUMN_TEXTS"> <COLUMN_TEXT UNDERLINE="false" SPAN_COL="1">(A)</COLUMN_TEXT> <COLUMN_TEXT UNDERLINE="false" SPAN_COL="1">(B)</COLUMN_TEXT> <COLUMN_TEXT UNDERLINE="false" SPAN_COL="1">(C)</COLUMN_TEXT> <COLUMN_TEXT UNDERLINE="false" SPAN_COL="1">(D)</COLUMN_TEXT> <COLUMN_TEXT UNDERLINE="false" SPAN_COL="1">(E)</COLUMN_TEXT> <COLUMN_TEXT UNDERLINE="false" SPAN_COL="1">(F)</COLUMN_TEXT> <COLUMN_TEXT UNDERLINE="false" SPAN_COL="1">(G)</COLUMN_TEXT> <COLUMN_TEXT UNDERLINE="false" SPAN_COL="1">(H)</COLUMN_TEXT> <COLUMN_TEXT UNDERLINE="false" SPAN_COL="1">(I)</COLUMN_TEXT> <COLUMN_TEXT UNDERLINE="false" SPAN_COL="1">(J)</COLUMN_TEXT> <COLUMN_TEXT UNDERLINE="false" SPAN_COL="1">(K)</COLUMN_TEXT> <COLUMN_TEXT UNDERLINE="false" SPAN_COL="1">(L)</COLUMN_TEXT> <COLUMN_TEXT UNDERLINE="false" SPAN_COL="1">(M)</COLUMN_TEXT> <COLUMN_TEXT UNDERLINE="false" SPAN_COL="1">(N)</COLUMN_TEXT> <COLUMN_TEXT UNDERLINE="false" SPAN_COL="1">(O)</COLUMN_TEXT> <COLUMN_TEXT UNDERLINE="false" SPAN_COL="1">(P)</COLUMN_TEXT> <COLUMN_TEXT UNDERLINE="false" SPAN_COL="1">(Q)</COLUMN_TEXT> </BANNER_TEXTS> </BANNER> I would like to group all the 'BANNER_TEXT' in the second sequence using the first sequence 'BANNER_TEXT' as the key (only include elements where string is not null or empty). The span_col attribute in the first 'BANNER_TEXT' sequence indicates which elements by position in the 2nd sequence are related. An example: 'Years in Practice' would be the first key and the attribute SPAN_COL=3 for that element indicates it would contain '< 11 years', '11-20 years', '21-30 years' (the first grouping of string.empty = Total would be skipped).

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  • Retrieving only the first record or record at a certain index in LINQ

    - by vik20000in
    While working with data it’s not always required that we fetch all the records. Many a times we only need to fetch the first record, or some records in some index, in the record set. With LINQ we can get the desired record very easily with the help of the provided element operators. Simple get the first record. If you want only the first record in record set we can use the first method [Note that this can also be done easily done with the help of the take method by providing the value as one].     List<Product> products = GetProductList();      Product product12 = (         from prod in products         where prod.ProductID == 12         select prod)         .First();   We can also very easily put some condition on which first record to be fetched.     string[] strings = { "zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine" };     string startsWithO = strings.First(s => s[0] == 'o');  In the above example the result would be “one” because that is the first record starting with “o”.  Also the fact that there will be chances that there are no value returned in the result set. When we know such possibilities we can use the FirstorDefault() method to return the first record or incase there are no records get the default value.        int[] numbers = {};     int firstNumOrDefault = numbers.FirstOrDefault();  In case we do not want the first record but the second or the third or any other later record then we can use the ElementAt() method. In the ElementAt() method we need to pass the index number for which we want the record and we will receive the result for that element.      int[] numbers = { 5, 4, 1, 3, 9, 8, 6, 7, 2, 0 };      int fourthLowNum = (         from num in numbers         where num > 5         select num )         .ElementAt(1); Vikram

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  • Best approach to convert XML to RDF/XML using an ontology

    - by krisvandenbergh
    I have an XML which uses the XPDL standard (which has an XML schema). What I'm trying to do now is to convert its content to RDF format (serialized in XML), in terms of a certain ontology. Clearly, there needs to be some sort of mapping here. I would like to do this using PHP. The thing is, I have no idea how to do this best. I know how to read an XML file, but how would the mappings occur? What would be a good approach?

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  • How to generate XML with attributes in c#.

    - by user292815
    I have that code: ... request data = new request(); data.username = formNick; xml = data.Serialize(); ... [System.Serializable] public class request { public string username; public string password; static XmlSerializer serializer = new XmlSerializer(typeof(request)); public string Serialize() { StringBuilder builder = new StringBuilder(); XmlWriterSettings settings = new XmlWriterSettings(); settings.OmitXmlDeclaration = true; settings.Encoding = Encoding.UTF8; serializer.Serialize( System.Xml.XmlWriter.Create(builder, settings ), this); return builder.ToString(); } public static request Deserialize(string serializedData) { return serializer.Deserialize(new StringReader(serializedData)) as request; } } I want to add attributes to some nodes and create some sub-nodes. Also how to parse xml like that: <answer> <player id="2"> <coordinate axis="x"></coordinate> <coordinate axis="y"></coordinate> <coordinate axis="z"></coordinate> <action name="nothing"></action> </player> <player id="3"> <coordinate axis="x"></coordinate> <coordinate axis="y"></coordinate> <coordinate axis="z"></coordinate> <action name="boom"> <1>1</1> <2>2</2> </action> </player> </answer> p.s. it is not a xml file, it's answer from http server.

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  • How to generate XML with attributes in .NET?

    - by user292815
    I have that code: ... request data = new request(); data.username = formNick; xml = data.Serialize(); ... [System.Serializable] public class request { public string username; public string password; static XmlSerializer serializer = new XmlSerializer(typeof(request)); public string Serialize() { StringBuilder builder = new StringBuilder(); XmlWriterSettings settings = new XmlWriterSettings(); settings.OmitXmlDeclaration = true; settings.Encoding = Encoding.UTF8; serializer.Serialize( System.Xml.XmlWriter.Create(builder, settings ), this); return builder.ToString(); } public static request Deserialize(string serializedData) { return serializer.Deserialize(new StringReader(serializedData)) as request; } } I want to add attributes to some nodes and create some sub-nodes. Also how to parse xml like that: <answer> <player id="2"> <coordinate axis="x"></coordinate> <coordinate axis="y"></coordinate> <coordinate axis="z"></coordinate> <action name="nothing"></action> </player> <player id="3"> <coordinate axis="x"></coordinate> <coordinate axis="y"></coordinate> <coordinate axis="z"></coordinate> <action name="boom"> <1>1</1> <2>2</2> </action> </player> </answer> p.s. it is not a xml file, it's answer from http server.

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  • Android programming - How to acces [to draw on] XML view in main.xml layout, using code

    - by user556248
    Ok I'm a newbie at Android programming, have a hard time with the graphics part. Understand the beauty of creating layout in XML file, but lost how to access various elements, especially a View element to draw on it. See example of my layout main.xml here; <?xml version="1.0" encoding="utf-8"?> <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:id="@+id/root" android:orientation="vertical" android:layout_width="fill_parent" android:layout_height="fill_parent"> <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:layout_width="fill_parent" android:layout_height="wrap_content"> <TextView xmlns:android="http://schemas.android.com/apk/res/android" android:id="@+id/Title" android:text="App title" android:layout_width="fill_parent" android:layout_height="wrap_content" android:textColor="#000000" android:background="#A0A0FF"/> </LinearLayout> <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:id="@+id/PaperLayout" android:layout_width="fill_parent" android:layout_height="0dp" android:layout_weight="1" android:orientation="horizontal" android:focusable="true"> <View android:id="@+id/Paper" android:layout_width="fill_parent" android:layout_height="fill_parent" /> </LinearLayout> <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:layout_width="fill_parent" android:layout_height="wrap_content"> <Button android:id="@+id/File" android:layout_width="fill_parent" android:layout_weight="1" android:layout_height="34dp" android:layout_alignParentTop="true" android:layout_centerInParent="true" android:clickable="true" android:textSize="10sp" android:text="File" /> <Button android:id="@+id/Edit" android:layout_width="fill_parent" android:layout_weight="1" android:layout_height="34dp" android:clickable="true" android:textSize="10sp" android:text="Edit" /> </LinearLayout> </LinearLayout> As you can see I have a custom app title bar, then a View filling middle, and finally two buttons in bottom. Catching button events and responding to, for example changing title bar text and changing View background color works fine, but how the heck do I access and more importantly draw on the view defined in main.xml UPDATE: That for your suggestion, however besides that I need a View, not ImageView and you are missing a parameter on canvas.drawText and an ending bracket, it does not work. Now this is most likely because you missed the fact that I am a newbie and assuming I can fill in any blanks. Now first of all I do NOT understand why in my main.xml layout file I can create a View or even a SurfaceView element, which is what I need, but according to your solution I don't even specify the View like Anyways I edited my main.xml according to your solution, and slimmed it down a bit for simplicity; <?xml version="1.0" encoding="utf-8"?> <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:id="@+id/root" android:orientation="vertical" android:layout_width="fill_parent" android:layout_height="fill_parent"> <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:layout_width="fill_parent" android:layout_height="wrap_content"> <TextView xmlns:android="http://schemas.android.com/apk/res/android" android:id="@+id/Title" android:text="App title" android:layout_width="fill_parent" android:layout_height="wrap_content" android:textColor="#000000" android:background="#A0A0FF"/> </LinearLayout> <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:id="@+id/PaperLayout" android:layout_width="fill_parent" android:layout_height="0dp" android:layout_weight="1" android:orientation="horizontal" android:focusable="true"> <com.example.MyApp.CustomView android:id="@+id/Paper" android:layout_width="fill_parent" android:layout_height="fill_parent" /> <com.example.colorbook.CustomView/> </LinearLayout> <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:layout_width="fill_parent" android:layout_height="wrap_content"> <Button android:id="@+id/File" android:layout_width="fill_parent" android:layout_weight="1" android:layout_height="34dp" android:layout_alignParentTop="true" android:layout_centerInParent="true" android:clickable="true" android:textSize="10sp" android:text="File" /> </LinearLayout> </LinearLayout> In my main java file, MyApp.java, I added this after OnCreate; public class CustomView extends ImageView { @Override protected void onDraw(Canvas canvas) { super.onDraw(canvas); canvas.drawText("Your Text", 1, 1, null); } } But I get error on the "CustomView" part; "Implicit super constructor ImageView() is undefined for default constructor.Must define an explicit constructor" Eclipse suggests 3 quick fixes about adding constructor, but none helps, well it removes error but gives error on app when running. I hope somebody can break this down for me and provide a solution, and perhaps explain why I can't just create a View element in my main.xml layotu file and draw on it in code.

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  • Using xsi:nil in XML

    - by Matt
    I am generating an XML file from a VB.NET app. The document was generating fine before I tried to add nillable elements. I am now testing putting in just one nil element as: <blah xsi:nil="true"></blah> Once this element is in place and I try to view the XML file in IE it is unable to display. I am receiving: > The XML page cannot be displayed > Cannot view XML input using XSL style > sheet. Please correct the error and > then click the Refresh button, or try > again later. > > -------------------------------------------------------------------------------- > > The operation completed successfully. > Error processing resource If I remove this one element it displays fine again. What am I missing here?

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  • Unable to load huge XML document (incorrectly suppose it's due to the XSLT processing)

    - by krisvandenbergh
    I'm trying to match certain elements using XSLT. My input document is very large and the source XML fails to load after processing the following code (consider especially the first line). <xsl:template match="XMI/XMI.content/Model_Management.Model/Foundation.Core.Namespace.ownedElement/Model_Management.Package/Foundation.Core.Namespace.ownedElement"> <rdf:RDF> <rdf:Description rdf:about=""> <xsl:for-each select="Foundation.Core.Class"> <xsl:for-each select="Foundation.Core.ModelElement.name"> <owl:Class rdf:ID="@Foundation.Core.ModelElement.name" /> </xsl:for-each> </xsl:for-each> </rdf:Description> </rdf:RDF> </xsl:template> Apparently the XSLT fails to load after "Model_Management.Model". The PHP code is as follows: if ($xml->loadXML($source_xml) == false) { die('Failed to load source XML: ' . $http_file); } It then fails to perform loadXML and immediately dies. I think there are two options now. 1) I should set a maximum executing time. Frankly, I don't know how that I do this for the built-in PHP 5 XSLT processor. 2) Think about another way to match. What would be the best way to deal with this? The input document can be found at http://krisvandenbergh.be/uml_pricing.xml Any help would be appreciated! Thanks.

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  • Python XML + Java XML interoperability.

    - by erb
    Hello. I need a recommendation for a pythonic library that can marshall python objects to XML(let it be a file). I need to be able read that XML later on with Java (JAXB) and unmarshall it. I know JAXB has some issues that makes it not play nice with .NET XML libraries so a recommendation on something that actually works would be great.

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  • What can map database tables like LINQ to SQL did?

    - by trnTash
    A good thing in LINQ to SQL was a fast and reliable way to map database tables and convert them into classes accessible from c# project. However it is no longer recommended to create projects using LINQ to SQL. What is its substitute? What kind of tool should I use in VS 2010 today if I want to have the same functionality as I had with LINQ to SQL?

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  • Read XML from an XDocument with silverlight

    - by user625310
    Hi I have managed to load an XDocument with xml data from this link http://go.yr.no/go/e/main/http://www.yr.no/place/Norway/Telemark/Sauherad/Gvarv/forecast.xml. I am using C# and .Net in Blend and producing a web app (ie some of the normal .Net functions is not included in the silverlight plugin). I have researched this a lot but can not figure out: how to put the "text" in the link node in a string variable and how to all put the "-11" from ? in a array and link it to the "time from"? I think i have to use LINQ, but the stuff on MSDN and other tutorials is confusing and to general. huge thank in advance Regards Arnt I am sorry to ask such novice questions, but i have searched a lot. Also please excuse the typos, English is not my first language. Huge thank in advance Arnt

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  • Writing to XML issue Unity3D C#

    - by N0xus
    I'm trying to create a tool using Unity to generate an XML file for use in another project. Now, please, before someone suggests I do it in something, the reason I am using Unity is that it allows me to easily port this to an iPad or other device with next to no extra development. So please. Don't suggest to use something else. At the moment, I am using the following code to write to my XML file. public void WriteXMLFile() { string _filePath = Application.dataPath + @"/Data/HV_DarkRideSettings.xml"; XmlDocument _xmlDoc = new XmlDocument(); if (File.Exists(_filePath)) { _xmlDoc.Load(_filePath); XmlNode rootNode = _xmlDoc.CreateElement("Settings"); // _xmlDoc.AppendChild(rootNode); rootNode.RemoveAll(); XmlElement _cornerNode = _xmlDoc.CreateElement("Screen_Corners"); _xmlDoc.DocumentElement.PrependChild(_cornerNode); #region Top Left Corners XYZ Values // indent top left corner value to screen corners XmlElement _topLeftNode = _xmlDoc.CreateElement("Top_Left"); _cornerNode.AppendChild(_topLeftNode); // set the XYZ of the top left values XmlElement _topLeftXNode = _xmlDoc.CreateElement("TopLeftX"); XmlElement _topLeftYNode = _xmlDoc.CreateElement("TopLeftY"); XmlElement _topLeftZNode = _xmlDoc.CreateElement("TopLeftZ"); // indent these values to the top_left value in XML _topLeftNode.AppendChild(_topLeftXNode); _topLeftNode.AppendChild(_topLeftYNode); _topLeftNode.AppendChild(_topLeftZNode); #endregion #region Bottom Left Corners XYZ Values // indent top left corner value to screen corners XmlElement _bottomLeftNode = _xmlDoc.CreateElement("Bottom_Left"); _cornerNode.AppendChild(_bottomLeftNode); // set the XYZ of the top left values XmlElement _bottomLeftXNode = _xmlDoc.CreateElement("BottomLeftX"); XmlElement _bottomLeftYNode = _xmlDoc.CreateElement("BottomLeftY"); XmlElement _bottomLeftZNode = _xmlDoc.CreateElement("BottomLeftZ"); // indent these values to the top_left value in XML _bottomLeftNode.AppendChild(_bottomLeftXNode); _bottomLeftNode.AppendChild(_bottomLeftYNode); _bottomLeftNode.AppendChild(_bottomLeftZNode); #endregion #region Bottom Left Corners XYZ Values // indent top left corner value to screen corners XmlElement _bottomRightNode = _xmlDoc.CreateElement("Bottom_Right"); _cornerNode.AppendChild(_bottomRightNode); // set the XYZ of the top left values XmlElement _bottomRightXNode = _xmlDoc.CreateElement("BottomRightX"); XmlElement _bottomRightYNode = _xmlDoc.CreateElement("BottomRightY"); XmlElement _bottomRightZNode = _xmlDoc.CreateElement("BottomRightZ"); // indent these values to the top_left value in XML _bottomRightNode.AppendChild(_bottomRightXNode); _bottomRightNode.AppendChild(_bottomRightYNode); _bottomRightNode.AppendChild(_bottomRightZNode); #endregion _xmlDoc.Save(_filePath); } } This generates the following XML file: <Settings> <Screen_Corners> <Top_Left> <TopLeftX /> <TopLeftY /> <TopLeftZ /> </Top_Left> <Bottom_Left> <BottomLeftX /> <BottomLeftY /> <BottomLeftZ /> </Bottom_Left> <Bottom_Right> <BottomRightX /> <BottomRightY /> <BottomRightZ /> </Bottom_Right> </Screen_Corners> </Settings> Which is exactly what I want. However, each time I press the button that has the WriteXMLFile() method attached to it, it's write the entire lot again. Like so: <Settings> <Screen_Corners> <Top_Left> <TopLeftX /> <TopLeftY /> <TopLeftZ /> </Top_Left> <Bottom_Left> <BottomLeftX /> <BottomLeftY /> <BottomLeftZ /> </Bottom_Left> <Bottom_Right> <BottomRightX /> <BottomRightY /> <BottomRightZ /> </Bottom_Right> </Screen_Corners> <Screen_Corners> <Top_Left> <TopLeftX /> <TopLeftY /> <TopLeftZ /> </Top_Left> <Bottom_Left> <BottomLeftX /> <BottomLeftY /> <BottomLeftZ /> </Bottom_Left> <Bottom_Right> <BottomRightX /> <BottomRightY /> <BottomRightZ /> </Bottom_Right> </Screen_Corners> <Screen_Corners> <Top_Left> <TopLeftX /> <TopLeftY /> <TopLeftZ /> </Top_Left> <Bottom_Left> <BottomLeftX /> <BottomLeftY /> <BottomLeftZ /> </Bottom_Left> <Bottom_Right> <BottomRightX /> <BottomRightY /> <BottomRightZ /> </Bottom_Right> </Screen_Corners> </Settings> Now, I've written XML files before using winforms, and the WriteXMLFile function is exactly the same. However, in my winform, no matter how much I press the WriteXMLFile button, it doesn't write the whole lot again. Is there something that I'm doing wrong or should change to stop this from happening?

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  • XML Signature in a Web application

    - by OpenDevSoft
    Hi, We are developing an e-Banking web application for a small bank (up to 20000 clients/users). We have to implement digital signatures with X509 certificates (issued by CA on USB tokens) for signing payment information. We tried using CAPICOM but it seems that it is not working well with Windows Vista (have not tried it with Win 7). The other problem is that core banking system can process only Xml digital signatures, so we have to sign XML documents (not just a bulk-formatted text data like with CAPICOM and Win32 Crypto API). So my questions here are: Does anyone of you have similar problem and how did they solved it? Is there a plug-in, library, component or external tool (for Internet Explorer and/or Fire Fox) that supports XML Digital Signatures in a web application? Can you please recommend some of these products and write something about your experience with them? Thank you very much.

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  • XML deserialization doesn't read in second level

    - by Andy
    Sorry if the title doesn't make much sense, but I'm not too familiar with the terminology. My question is: I have a config.xml file for a program I'm working on. I created an xsd file by 'xsd.exe config.xml'. I then took this xsd and added it to the solution in visual studio. My last step used a program called xsd2code that turned that xsd file into a class I can serialize too. The problem is it doesn't read more then a layer deep in the xml tree. By this I mean the elements in the root node get deserialized into my object, but those that are in a node inside the root node are not. I found this out by putting a breakpoint after the deserialization and looking at my object. Any Ideas? Let me know if this needs some clarification or you need a snippet of something.

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  • Element Based XML Parsing

    - by demos
    I have an XML document which reads like this: <xml> <web:Web> <web:Total>4000</web:Total> <web:Offset>0</web:Offset> </web:Web> </xml> my question is how do I access them using a library like BeautifulSoup in python? xmlDom.web["Web"].Total ? does not work?

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  • Element Based XML Parising

    - by demos
    I have an XML document which reads like this: <xml> <web:Web> <web:Total>4000</web:Total> <web:Offset>0</web:Offset> </web:Web> </xml> my question is how do I access them using a library like BeautifulSoup in python? xmlDom.web["Web"].Total ? does not work?

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  • How to modify by loading and saving the same xml file

    - by cynthia hong
    I have a problem with modifying xml file when i first load and then save it with same file path and name. Below is my code. The error is "Access to the path C:\MyApp\Web.config is denied. If i change the path of the xdoc.Save to be different from xdoc.Load, then it will be ok. What is your recommandation to solve this problem? If possible, i need to modify the existing xml file(meaning xml file for loading and saving is the same path). XmlDocument xdoc = new XmlDocument(); xdoc.Load(@"C:\\MyApp\\Web.config"); XmlNode xn = xdoc.SelectSingleNode("//configuration/MyProvider"); XmlElement el = (XmlElement)xn; el.SetAttribute("defaultProvider", "MyCustomValue"); xdoc.Save(@"C:\\MyApp\\Web.config"); Thanks in advance.

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  • Retrieving recent tweets using LINQ

    - by brian_ritchie
    There are a few different APIs for accessing Twitter from .NET.  In this example, I'll use linq2twitter.  Other APIs can be found on Twitter's development site. First off, we'll use the LINQ provider to pull in the recent tweets. .csharpcode, .csharpcode pre { font-size: small; color: black; font-family: Consolas, "Courier New", Courier, Monospace; background-color: #ffffff; /*white-space: pre;*/ } .csharpcode pre { margin: 0em; } .csharpcode .rem { color: #008000; } .csharpcode .kwrd { color: #0000ff; } .csharpcode .str { color: #006080; } .csharpcode .op { color: #0000c0; } .csharpcode .preproc { color: #cc6633; } .csharpcode .asp { background-color: #ffff00; } .csharpcode .html { color: #800000; } .csharpcode .attr { color: #ff0000; } .csharpcode .alt { background-color: #f4f4f4; width: 100%; margin: 0em; } .csharpcode .lnum { color: #606060; } 1: public static Status[] GetLatestTweets(string screenName, int numTweets) 2: { 3: try 4: { 5: var twitterCtx = new LinqToTwitter.TwitterContext(); 6: var list = from tweet in twitterCtx.Status 7: where tweet.Type == StatusType.User && 8: tweet.ScreenName == screenName 9: orderby tweet.CreatedAt descending 10: select tweet; 11: // using Take() on array because it was failing against the provider 12: var recentTweets = list.ToArray().Take(numTweets).ToArray(); 13: return recentTweets; 14: } 15: catch 16: { 17: return new Status[0]; 18: } 19: } Once they have been retrieved, they would be placed inside an MVC model. Next, the tweets need to be formatted for display. I've defined an extension method to aid with date formatting: .csharpcode, .csharpcode pre { font-size: small; color: black; font-family: Consolas, "Courier New", Courier, Monospace; background-color: #ffffff; /*white-space: pre;*/ } .csharpcode pre { margin: 0em; } .csharpcode .rem { color: #008000; } .csharpcode .kwrd { color: #0000ff; } .csharpcode .str { color: #006080; } .csharpcode .op { color: #0000c0; } .csharpcode .preproc { color: #cc6633; } .csharpcode .asp { background-color: #ffff00; } .csharpcode .html { color: #800000; } .csharpcode .attr { color: #ff0000; } .csharpcode .alt { background-color: #f4f4f4; width: 100%; margin: 0em; } .csharpcode .lnum { color: #606060; } 1: public static class DateTimeExtension 2: { 3: public static string ToAgo(this DateTime date2) 4: { 5: DateTime date1 = DateTime.Now; 6: if (DateTime.Compare(date1, date2) >= 0) 7: { 8: TimeSpan ts = date1.Subtract(date2); 9: if (ts.TotalDays >= 1) 10: return string.Format("{0} days", (int)ts.TotalDays); 11: else if (ts.Hours > 2) 12: return string.Format("{0} hours", ts.Hours); 13: else if (ts.Hours > 0) 14: return string.Format("{0} hours, {1} minutes", 15: ts.Hours, ts.Minutes); 16: else if (ts.Minutes > 5) 17: return string.Format("{0} minutes", ts.Minutes); 18: else if (ts.Minutes > 0) 19: return string.Format("{0} mintutes, {1} seconds", 20: ts.Minutes, ts.Seconds); 21: else 22: return string.Format("{0} seconds", ts.Seconds); 23: } 24: else 25: return "Not valid"; 26: } 27: } Finally, here is the piece of the view used to render the tweets. .csharpcode, .csharpcode pre { font-size: small; color: black; font-family: Consolas, "Courier New", Courier, Monospace; background-color: #ffffff; /*white-space: pre;*/ } .csharpcode pre { margin: 0em; } .csharpcode .rem { color: #008000; } .csharpcode .kwrd { color: #0000ff; } .csharpcode .str { color: #006080; } .csharpcode .op { color: #0000c0; } .csharpcode .preproc { color: #cc6633; } .csharpcode .asp { background-color: #ffff00; } .csharpcode .html { color: #800000; } .csharpcode .attr { color: #ff0000; } .csharpcode .alt { background-color: #f4f4f4; width: 100%; margin: 0em; } .csharpcode .lnum { color: #606060; } 1: <ul class="tweets"> 2: <% 3: foreach (var tweet in Model.Tweets) 4: { 5: %> 6: <li class="tweets"> 7: <span class="tweetTime"><%=tweet.CreatedAt.ToAgo() %> ago</span>: 8: <%=tweet.Text%> 9: </li> 10: <%} %> 11: </ul>  

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  • Linq to Xml to Datagridview

    - by David Archer
    Right, starting to go crazy here. I have the following code: var query = (from c in db.Descendants("Customer") select c.Elements()); dgvEditCusts.DataSource = query.ToList(); In this, db relates to an XDocument.Load call. How can I get the data into the DataGridView? Just thought I should mention: it returns a completely blank dgv

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  • How to select all the attributes that contain certain String in an XML Document using LINQ

    - by jaircazarin
    Similar to XPath: How to match attributes that contain a certain string but without using XPath. Is it possible? <c BarFoo="val1"> <d Foo="val2" someAttribute=""> <e FooBar="val3" /> </d> </c> Basically I want to select all the attribute values in the document that their attribute name contains "Foo", so it should return the values of "BarFoo", "FooBar", "Foo" (va1, val2, val3)

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  • c# Deserializing an element based on it's parent node's name

    - by daveharnett
    The XML I'm working with has the following structure: <fixture_statistics> <home_player_1 id="2306143" teamid="2"> <element_1>Some Data</element_1> <element_2>Some Data</element_2> </home_player_1> <home_player_2 id="2306144" teamid="2"> <element_1>Some Data</element_1> <element_2>Some Data</element_2> </home_player_2> </fixture_statistics> Now the code to deserialize it would normally look like this: [XmlRootAttribute("fixture_statistics", Namespace = "", IsNullable = false)] public class FixtureRoot { [XmlElement("home_player_1")] [XmlElement("home_player_2")] public List<FixtureStats> fixtures { get; set; } } public class FixtureStats { public string element_1; [XMLElement("element_2")] public string elementTwo; } Here's the question: I'd like the FixtureStats class to have a 'position' property which corrosponds to it's parent's element name (so the FixtureStat object corrosponding to home_player_1 would have position=1). Can this be done with the built-in serialization atrributes? If it's not possible, what's the cleanest workaround? Bear in mind that each document will have about 50 player elements, each with about 50 'child' data elements.

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  • C# LINQ XML Query with duplicate element names that have attributes

    - by ncain187
    <Party id="Party_1"> <PartyTypeCode tc="1">Person</PartyTypeCode> <FullName>John Doe</FullName> <GovtID>123456789</GovtID> <GovtIDTC tc="1">Social Security Number US</GovtIDTC> <ResidenceState tc="35">New Jersey</ResidenceState> <Person> <FirstName>Frank</FirstName> <MiddleName>Roberts</MiddleName> <LastName>Madison</LastName> <Prefix>Dr.</Prefix> <Suffix>III</Suffix> <Gender tc="1">Male</Gender> <BirthDate>1974-01-01</BirthDate> <Age>35</Age> <Citizenship tc="1">United States of America</Citizenship> </Person> <Address> <AddressTypeCode tc="26">Bill Mailing</AddressTypeCode> <Line1>2400 Meadow Lane</Line1> <Line2></Line2> <Line3></Line3> <Line4></Line4> <City>Somerset</City> <AddressStateTC tc="35">New Jersey</AddressStateTC> <Zip>07457</Zip> <AddressCountryTC tc="1">United States of America</AddressCountryTC> </Address> </Party> <!-- *********************** --> <!-- Insured Information --> <!-- *********************** --> <Party id="Party_2"> <PartyTypeCode tc="1">Person</PartyTypeCode> <FullName>Dollie Robert Madison</FullName> <GovtID>123956239</GovtID> <GovtIDTC tc="1">Social Security Number US</GovtIDTC> <Person> <FirstName>Dollie</FirstName> <MiddleName>R</MiddleName> <LastName>Madison</LastName> <Suffix>III</Suffix> <Gender tc="2">Female</Gender> <BirthDate>1996-10-12</BirthDate> <Citizenship tc="1">United States of America</Citizenship> </Person> <!-- Insured Address --> <Address> <AddressTypeCode tc="26">Bill Mailing</AddressTypeCode> <Line1>2400 Meadow Lane</Line1> <City>Somerset</City> <AddressStateTC tc="35">New Jersey</AddressStateTC> <Zip>07457</Zip> <AddressCountryTC tc="1">United States of America</AddressCountryTC> </Address> <Risk> <!-- Disability Begin Effective Date --> <DisabilityEffectiveStartDate>2006-01-01</DisabilityEffectiveStartDate> <!-- Disability End Effective Date --> <DisabilityEffectiveStopDate>2008-01-01</DisabilityEffectiveStopDate> </Risk> </Party> <!-- ******************************* --> <!-- Company Information --> <!-- ****************************** --> <Party id="Party_3"> <PartyTypeCode tc="2">Organization</PartyTypeCode> <Organization> <DTCCMemberCode>1234</DTCCMemberCode> </Organization> <Carrier> <CarrierCode>105</CarrierCode> </Carrier> </Party> Here is my code which doesn't work because party 3 doesn't contain FullName, I know that partyelements contains 3 parties if I only return the name attribute. Is there a way to loop through each tag seperate? var partyElements = from party in xmlDoc.Descendants("Party") select new { Name = party.Attribute("id").Value, PartyTypeCode = party.Element("PartyTypeCode").Value, FullName = party.Element("FullName").Value, GovtID = party.Element("GovtID").Value, };

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  • Adding integer value to a list from XML file

    - by Pramodh
    I've an Xml file like <SampleFile> <Data> <Element Val="8" /> <Element Val="10" /> <Element Val="12" /> <Element Val="14" /> <Element Val="16" /> <Element Val="9" /> <Element Val="11" /> <Element Val="13" /> <Element Val="15" /> <Element Val="17" /> </Data> </SampleFile> i need to read the attribute value of" Val" and convert it to Int32 , then sort and then add to the list now i'm using like: List<Int32> lst = (XDocument.Load("\\Sample.xml").Descendants("Element").Select(l_Temp => l_Temp.Attribute("Val").Value.ToString()).Cast<Int32>().OrderBy(nTemp => nTemp)).ToList(); but its not working properly please give me a better solution

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