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• help with query in access

  - by Gold

  hi i have 2 tables Table A - code|name Table B - barcode|name table B has full barcode and name, Table A has only code i need to run update query that fill name in Table A i try somthing like: update A set name = (select top 1 Name from B where B.Code = mid(A.Barcode,1,8)) but it dos't work

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• Mysql timestamp query

  - by Hulk

  In mysql a result of a query is say select timestamp from newbie; | 2010-03-12 14:50:46 | | 2010-03-12 14:50:46 | | 2010-03-12 14:50:51 | | 2010-03-12 14:50:52 | | 2010-03-12 14:50:54 | | 2010-03-12 14:51:04 | | 2010-03-12 14:51:07 | | 2010-03-12 14:51:08 | Is there a way to subquery the above and sum up the i.e, the final result should be the delta of each row in hh:mm:ss format

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• Timeout on Large mySQL Query

  - by Bob Stewart

  I have this query: $theQuery = mysql_query("SELECT phrase, date from wordList WHERE group='nouns'"); while($getWords=mysql_fetch_array($theQuery)) { echo "$getWords[phrase] created on $getWords[date]<br>"; } The data table "wordList" contains 75,000 records in the group "nouns" and every time I load the code I am returned an error. Help!

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• complex Subtract in sql server query

  - by AmRoSH

  Hello, I have table like following PK num1 num2 numsdiff 1 10 15 ? 2 20 25 ? 3 30 35 ? 4 40 45 ? i need to get Subtract of 20 - 15 and 30 - 25 and 40 - 35 and so on by select query from this table. any ideas?. thanks

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• Sql-server Database query help

  - by menacheb

  Hi, I have a project in C# with a Sql-server Database. In that database I have a table named 'Process' and columns named 'process_name', 'Full_Name' and 'Version' (all of the type:nvarchar(50)). I want to write a query wich will add the new process, only if it doesn't exist in the table yet. How can I do that? Many thanks,

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• SQLite Query to Insert a record If not exists

  - by Tharindu Madushanka

  I want to insert a record into a sqlite table if its actually not inserted. Let's say it has three fields pk, name, address I want to INSERT new record with name if that name not added preveously. Can we do with this in a single Query. Seems like its slightly different from SQL Queries sometimes. Thanks you, Tharindu Madushanka

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• CakePHP - Paginate / Query: find lowest of multiple fields & order by it

  - by Atea

  I am using CakePHP for a price-comparison website. I have a table products with fields: id, pride_regular, price_action. I would like to combine the fields price_regular and price_action into a dynamic field: price. The lowest value of these two fields should be the value of the new price field. Also I want to order on it Ascending. Should I use a custom MySQL-query?

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• What is the fastest findByName query with hibernate?

  - by Karussell

  I am sure I can improve the performance of the following findByName query of hibernate: public List<User> findByName(String name) { session.createCriteria(User.class).add(Restrictions.eq("name", name)).list(); } In which way should I improve it or even more important: in which ways should I improve it first? I will need the full object with all the collections (layz or not) and deps of this class.

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• How do I execute this query in MYSQL?

  - by alex

  Suppose I have a column with words: orange grape orange orange apple orange grape banana How do I execute a query to get the top 10 words, as well as their count?

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• inserting array into database table in single query

  - by Praveen Prasad

  iam having an array of items like [item1,itmem2,item3]; i have to insert these items at a particular userId: final results look like this UserId ItemId 2 || item1 2 || item2 2 || item3 currently iam looping through the array in php code and inserting each item one by one eg foreach($items as $item) { insert into items (UserId,ItemId) value (2,$item); } is it possible i can insert all entries in single query.

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• need an sql query

  - by CKeven

  I currently have two tables: 1. car(plate_number, brand, cid) 2. borrow(StartDate, endDate, brand, id) I want to write a query to get all available brand and count of available cars for each brand

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• SQL concatenate rows query

  - by bobobobo

  Say we have a table table posts +---------+-----------+--------------------------------+ | postId | title | status | bodyText | +---------+-----------+--------------------------------+ | 1 | Hello! | deleted | A deleted post! | | 2 | Hello 2! | deleted | Another one! | Can we, in SQL, retrieve a concatenation of a field across rows, by issuing a single query, not having to do the join up in a loop in our back-end code? Something like select title from posts group by status ; Should give "Hello!, Hello 2!"

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• how to optimize this query?

  - by jest

  hi! the query is: select employee_id, last_name, salary, round((salary+(salary*0.15)), 0) as NewSalary, (round((salary+(salary*0.15)), 0) - salary) as “IncreaseAmount” from employees; can i optimize this round((salary+(salary*0.15)), 0) part in anyway, so that it doesn't appear twice..i tried giving it an alias but didn't work :(

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• pgSQL query error

  - by running4surival

  i tried using this query: "SELECT * FROM guests WHERE event_id=".$id." GROUP BY member_id;" and I'm getting this error: ERROR: column "guests.id" must appear in the GROUP BY clause or be used in an aggregate function can anyone explain how i can work around this?

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• writting an sql query

  - by Praveen Prasad

  iam having 2 tables table Items Table (this table holds all items iam having) itemId --------- Item1 Item2 Item3 Item4 Item5 table 2 users_item relation UserId || ItemId 1 || Item1 1 || Item2 userId one has stored 2 items Item1,Item2. Now i want to write a query on table1 (Items table) so that it displays all items which user1 has NOT chosen.

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• how to reverse the order of words in query or c#

  - by Ranjana

  i have stored in the database as location India,Tamilnadu,Chennai,Annanagar while i bind in the grid view it ll be displaying as 'India,Tamilnadu,Chennai,Annanagar' this format. but i need to be displayed as 'Annanagar,Chennai,Tamilnadu,India' in this format. how to perform this reverse order in query or in c#

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• SQL query, select from 2 tables random

  - by klaus

  Hello all i have a problem that i just CANT get to work like i what it.. i want to show news and reviews (2 tables) and i want to have random output and not the same output here is my query i really hope some one can explain me what i do wrong SELECT anmeldelser.billed_sti , anmeldelser.overskrift , anmeldelser.indhold , anmeldelser.id , anmeldelser.godkendt FROM anmeldelser LIMIT 0,6 UNION ALL SELECT nyheder.id , nyheder.billed_sti , nyheder.overskrift , nyheder.indhold , nyheder.godkendt FROM nyheder ORDER BY rand() LIMIT 0,6

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• Solr OR query for different combination of facets

  - by Ritesh M Nayak

  I have a sample Solr schema as follows isPublic = boolean source = facebook| twitter | wordpress I want to write a query which returns all documents from the index which matches either the isPublic = true or isPublic is false and source= facebook. Something like this solrUrl/?q=blah&fq=(isPublic:true OR (isPublic:false AND source:facebook)) Is such a thing possible or should I search the index two times with each of these conditions and then combine + de-duplicate the results?

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• criticle join query mysql

  - by Bharanikumar

  i have table country and having country name and country code, i have customer table having countomer mobile number like customer_mobile field values like 0044-123456798 , 0024-582654753 , 012-52686145 , i want to populate my country oce into combo, that country name should in customer table which country code count is high that country name should come in the dropdown list top , How to write the join query... Thanks

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• select query related problem

  - by user222585

  i have interest rate and amount in a table where interest rate are ranged in different values like 4.5,4.6,5.2,5.6 etc. i want to get sum of amounts classified by interest rate where interest rate will be separated by .25. for example all amount having interest rate 1.25,1.3,1.4 will be in one group and 1.5,1.67,1.9 will be in another group how can i write the query?

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• MySQL Query to Count Unique Domains from Email Address field

  - by Ian

  I'd like to get a better idea of what domains my customers are using. I could easily do this in PHP by explodeing each address and counting the domain that way. But I'm wondering if there's a way to get this information with just a plain MySQL query?

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• Mysql query for within a specific date

  - by Ajith

  I need to retrieve data from within a specific date range.Anybody can help me to create a query to getting the information within date range 12-12-2009 to 12-15-2009 from a mysql table.(including 12 and 15)

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• Why does this properly escaped SQL query fail?

  - by Jason Rhodes

  Here's the query: INSERT INTO jobemails (jobid, to, subject, message, headers, datesent) VALUES ('340', '[email protected]', 'We\'ve received your request for a photo shoot called \'another\'.', 'message', 'headers', '2010-04-22 15:55:06') The datatypes are all correct, it always fails at the subject, so it must be how I'm escaping the values, I assume. I'm sure one of you will see my idiot mistake right away. A little help?

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• Need some help with a NHibernate Query

  - by cwap

  Hi all Say I got 3 entities: Business, Employee and Payment. A payment has a foreign key to an Employee, while the Employee has an foreign key to a business. Now, I want to create a query which gives me all payments for a given business. I really don't have a clue about how to do this - I guess I want something like: mySession.CreateCriteria<Payment>() .Add(Criterion.Expression.Eq(/* Employee_FK => Employee.Business_FK == BusinessID */); Any help would be greatly appreciated :)

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• how to do this in MySql Query??

  - by deep

  ID NAME AMT 1 Name1 1000 2 Name2 500 3 Name3 3000 4 Name1 5000 5 Name2 2000 6 Name1 3000 consider above table as sample. am having a problem in my sql query, Am using like this. Select name,amt from sample where amt between 1000 and 5000 it returns all the values in the table between 1000 and 5000, instead I want to get maximum amount record for each name i.e., 3 name3 3000 4 name1 5000 5 name2 2000

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