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  • simple php Dollar $ evaluation in string questions

    - by Mirage
    I have always been confused that .e,g in php i have sql statement $qry = "select * from table where id = $id"; now can i insert "$" directly inside the quotes or i have to use $qry = "select * from table where id =".$id." "; or $qry = 'select * from table where id = $id'; or $qry = 'select * from table where id = '$id''; Which is correct

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  • using javascript replace() to match the last occurance of a string

    - by Dave
    I'm building an 'add new row' function for product variations, and I'm struggling with the regex required to match the form attribute keys. So, I'm basically cloning rows, then incrementing the keys, like this (coffeescript): newrow = oldrow.find('select, input, textarea').each -> this.name = this.name.replace(/\[(\d+)\]/, (str, p1) -> "[" + (parseInt(p1, 10) + 1) + "]" ) this.id = this.id.replace(/\_(\d+)\_/, (str, p1) -> "_" + (parseInt(p1, 10) + 1) + "_" ) .end() This correctly increments a field with a name of product[variations][1][name], turning it into product[variations][2][name] BUT Each variation can have multiple options (eg, color can be red, blue, green), so I need to be able turn this product[variations][1][options][2][name] into product[variations][1][options][3][name], leaving the variation key alone. What regex do I need to match only the last occurrence of a key (the options key)?

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  • Converting string to datetime

    - by duder
    I'm trying to enter a date in a mysql table `ssdate` datetime The function that produces the date can output it in 3 formats: 1276142400000 Thu Jun 10 00:00:00 GMT-0400 2010 Fri Jun 4 2010 I'm wondering which of these would be easiest to convert to this field format? Since I'm trying to save only the date, is there a better option than datetime that would work with one of these output formats?

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  • Parsing a simple XML from string in Cocoa?

    - by Nick Brooks
    I have a simple XML and I need to get the first 'id' from puid-list. I found lots of examples but none of them quite do that because of the namespace. How do get the id out as an NSString? <genpuid songs="1" xmlns:mip="http://musicip.com/ns/mip-1.0#"> <track file="/htdocs/test.mp3" puid="0c9f2f0e-e72a-c461-9b9a-e18e8964ca20"> <puid-list> <puid id="0c9f2f0e-e72a-c461-9b9a-e18e8964ca20"/> </puid-list> </track> </genpuid>

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  • What's the logical value of "string" in python?

    - by Kamran
    I erroneously wrote this code in python: name = input("what is your name?") if name == "Kamran" or "Samaneh": print("That is a nice name") else: print("You have a boring name ;)") It always prints out "That is a nice name" even when the input is neither "Kamran" nor "Samaneh". Am I correct in saying that it considers "Samaneh" as a true? why? By the way, I already noticed my mistake. The correct form is: if name == "Kamran" or name == "Samaneh":

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  • How to return string name of calling method?

    - by keruilin
    Right now my code works as such: def method_a self.method_b ==> 'method_b' end def method_b puts self.name_of_calling_method end def name_of_calling_method if /`(.*)'/.match(caller.first) return $1 else return nil end end Instead of method_b printing 'method_b', how can I print the name of the calling method - 'method_a'?

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  • Get String Instead of Source - Xcode Cocoa

    - by Kevin
    Hello everyone, I have a program that will scan the contents of a website, and display it in a textbox. The problem is that it shows the html source. For example if my html code was: <html> <body> <p>Hello</p> </body> </html> instead of just showing hello, it'll show the code above... How can I get my objective c program to just read the hello, and not the html source.. I was assuming that it was the encoding when reading the website, but I might be possibly wrong.. I would greatly appreciate it if someone could give me a reasonable answer.. Best Regards, Kevin

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  • SQL Server Concatinate string column value to 5 char long

    - by mrp
    Scenario: I have a table1(col1 char(5)); A value in table1 may '001' or '01' or '1'. Requirement: Whatever value in col1, I need to retrive it in 5 char length concatenate with leading '0' to make it 5 char long. Technique I applied: select right(('00000' + col1),5) from table1; I didn't see any reason, why it doesn't work? but it didn't. Can anyone help me, how I can achieve the desired result?

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  • How can I convert a timestamp to a user-friendly time string

    - by Steve Neal
    I want to be able to present "today" and "yesterday" for recent dates in my application. I've got a date formatter in use currently to show dates (retrieved from data records) and will keep using this for anything more than a couple of days old. I just really like the way the SMS app in the iPhone shows dates for recent messages and would like to emulate this. The time-stamps that I have to work with are generated on a server that the phone downloads the data records from. All times are therefore generated at UTC (i.e. GMT) time. I've been fiddling about with this for a while the solutions I've devised just seem horribly long-winded. Can anyone suggest how to implement a method that could do this? Cheers - Steve.

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  • Does string concatenation use StringBuilder internally?

    - by JamesBrownIsDead
    Three of my coworkers just told me that there's no reason to use a StringBuilder in place of concatenation using the + operator. In other words, this is fine to do with a bunch of strings: myString1 + myString2 + myString3 + myString4 + mySt... The rationale that they used was that since .NET 2, the C# compiler will build the same IL if you use the + operator as if you used a StringBuilder. This is news to me. Are they correct?

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  • Processing an Integer Retrieved from a String in XSL

    - by justkt
    I have a stored time value which is of the format H:mm:ss. The hours may be any value from 0 up through several days. This data is sent in an XML tag and processed by XSL to be displayed. The display that I want is of the format: D days, HH:mm:ss (hours/minutes) Where the last tag shows hours if HH is greater than 0, minutes if it is 0. Given the original HH, which may be more than 24, I know I need the floor of HH / 24 to get the days value. Then the original HH % 24 gives me the leftover hours. I have also handled the minutes and hours question using xsl:when and xsl:if. It's getting days and hours from the hours value that has me stumped.

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  • String or binary data would be truncated -- Heisenberg problem

    - by harpo
    When you get this error, the first thing you ask is, which column? Unfortunately, SQL Server is no help here. So you start doing trial and error. Well, right now I have a statement like: INSERT tbl (A, B, C, D, E, F, G) SELECT A, B * 2, C, D, E, q.F, G FROM tbl ,othertable q WHERE etc etc Note that Some values are modified or linked in from another table, but most values are coming from the original table, so they can't really cause truncation going back to the same field (that I know of). Eliminating fields one at a time eventually makes the error go away, if I do it cumulatively, but — and here's the kicker — it doesn't matter which fields I eliminate. It's as if SQL Server is objecting to the total length of the row, which I doubt, since there are only about 40 fields in all, and nothing large. Anyone ever seen this before? Thanks. UPDATE: I have also done "horizontal" testing, by filtering out the SELECT, with much the same result. In other words, if I say WHERE id BETWEEN 1 AND 100: Error WHERE id BETWEEN 1 AND 50: No error WHERE id BETWEEN 50 AND 100: No error I tried many combinations, and it cannot be limited to a single row.

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  • Smiley Replace within CDATA of an HTML-String

    - by michaelm
    Hello, i have got a simple problem :( I need to replace text smilies with the according smiley-image. ok.. thats not really complex, but now i have to replace only smilie appereances outside of HTML Tags. short examplae: Text: Thats a good example :/ .. with a <a href="http://www.foobar.com">link</a> inside. i want to replace ":/" with the image of this smiley... ok, how to do that the best way?

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  • SQL Server Concatenate string column value to 5 char long

    - by mrp
    Scenario: I have a table1(col1 char(5)); A value in table1 may '001' or '01' or '1'. Requirement: Whatever value in col1, I need to retrive it in 5 char length concatenate with leading '0' to make it 5 char long. Technique I applied: select right(('00000' + col1),5) from table1; I didn't see any reason, why it doesn't work? but it didn't. Can anyone help me, how I can achieve the desired result?

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  • how to parse string into a date pattern using dojo

    - by Dojouser
    Hi, I have a value as '05/17/2010' I would like to get it as May 17, 2010 by using dojo.date.locale.I have tried using the dojo.date.locale.parse as follows : x = '05/17/2010' var x= dojo.date.locale.parse(x, {datePattern: "MM/dd/yyyy", selector: "date"}); alert(x) This doesnt give me the desired date pattern I also tried replacing the pattern as datePattern : "MMMM d, yyyy" but it returns me null. Any help highly appreciated. Thanks

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  • Compressing a hex string in Ruby/Rails

    - by PreciousBodilyFluids
    I'm using MongoDB as a backend for a Rails app I'm building. Mongo, by default, generates 24-character hexadecimal ids for its records to make sharding easier, so my URLs wind up looking like: example.com/companies/4b3fc1400de0690bf2000001/employees/4b3ea6e30de0691552000001 Which is not very pretty. I'd like to stick to the Rails url conventions, but also leave these ids as they are in the database. I think a happy compromise would be to compress these hex ids to shorter collections using more characters, so they'd look something like: example.com/companies/3ewqkvr5nj/employees/9srbsjlb2r Then in my controller I'd reverse the compression, get the original hex id and use that to look up the record. My question is, what's the best way to convert these ids back and forth? I'd of course want them to be as short as possible, but also url-safe and simple to convert. Thanks!

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  • Escape doube and single backslashes in a string in Ruby

    - by Nick Gorbikoff
    Hello. I'm trying to access a network path in my ruby script on a windows platform in a format like this. \\servername\some windows share\folder 1\folder2\ Now If I try to use this as a path, it won't work. Single backslashes are not properly escaped for this script. path = "\\servername\some windows share\folder 1\folder2\" d = Dir.new(path) I tried everything I could think of to properly escape slashes in the path. However I can't escape that single backslash - because of it's special meaning. I tried single quotes, double quotes, escaping backslash itself, using alternate quotes such as %Q{} or %q{}, using ascii to char conversion. Nothing works in a sense that I'm not doing it right. :-) Right now the temp solution is to Map a network drive N:\ pointing to that path and access it that way, but that not a solution. Does anyone have any idea how to properly escape single backslashes? Thank you

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  • string auto splitting in each loop - jquery

    - by sluggerdog
    I have the following jquery code that is looping through the returned json data, for some reason is it splitting the suburb by a space when being assigned as the value but not as the text, I cannot work out why this is happening. MY CODE $.each(data , function( index, obj ) { $.each(obj, function( key, value ) { var suburb = $.trim(value['mcdl01']); var number = $.trim(value['mcmcu']); $("#FeedbackBranchName").append("<option value=" + suburb + ">" + suburb + " (" + number + ")</option>"); }); }); SAMPLE RETURNED RESULTS <option **value="AIRLIE" beach=""**>AIRLIE BEACH (4440)</option> <option value="ASHMORE">ASHMORE (4431)</option> <option **value="BANYO" commercial=""**>BANYO COMMERCIAL (4432)</option> <option value="BEENLEIGH">BEENLEIGH (4413)</option> <option value="BERRIMAH">BERRIMAH (4453)</option> <option **value="BOWEN" hills=""**>BOWEN HILLS (4433)</option> Notice how for AIRLEE BEACH, BANYO COMMERICAL AND BOWN HILLS the second word has been separated out from the value attribute but it's fine at the text level. Anyone have any idea why this might happen? Thanks

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