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  • LookAndFeel not changing in Ubuntu

    - by Tom Brito
    Anyone knows Why the laf is not changing in the following code? (running in Ubuntu) import java.awt.Dialog; import java.awt.event.ActionEvent; import java.awt.event.ActionListener; import javax.swing.JComboBox; import javax.swing.JDialog; import javax.swing.JPanel; import javax.swing.UIManager; import javax.swing.UIManager.LookAndFeelInfo; public class TEST extends JPanel { public TEST() { final LookAndFeelInfo[] lafArray = UIManager.getInstalledLookAndFeels(); String[] names = new String[lafArray.length]; for (int i = 0; i < names.length; i++) { names[i] = lafArray[i].getName(); } final JComboBox cb = new JComboBox(names); cb.addActionListener(new ActionListener() { public void actionPerformed(ActionEvent ev) { try { int index = cb.getSelectedIndex(); LookAndFeelInfo lafInfo = lafArray[index]; String lafClassName = lafInfo.getClassName(); System.out.println(lafClassName); UIManager.setLookAndFeel(lafClassName); } catch (Exception e) { e.printStackTrace(); } } }); add(cb); } public static void main(String[] args) throws Exception { System.out.println("start"); JDialog dialog = new JDialog(null, Dialog.ModalityType.APPLICATION_MODAL); dialog.setContentPane(new TEST()); dialog.pack(); dialog.setLocationRelativeTo(null); dialog.setVisible(true); dialog.dispose(); System.out.println("end"); } }

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  • Problem installing mod_jk on Ubuntu karmic apache httpd 2.2.12 and tomcat 6

    - by Deny Prasetyo
    I have a problem when configuring mod_jk on ubuntu i use apache httpd 2.2.12 and tomcat 6 I installed apache httpd and lib mod_jk from synaptic and use default configuration. Here my mod_jk.conf Load mod_jk module Update this path to match your modules location LoadModule jk_module /usr/lib/apache2/modules/mod_jk.so Where to find workers.properties Update this path to match your conf directory location JkWorkersFile /etc/apache2/workers.properties Where to put jk logs Update this path to match your logs directory location JkLogFile /etc/apache2/logs/mod_jk.log Set the jk log level [debug/error/info] JkLogLevel info Select the log format JkLogStampFormat "[%a %b %d %H:%M:%S %Y]" JkOptions indicate to send SSL KEY SIZE, JkOptions +ForwardKeySize +ForwardURICompat -ForwardDirectories JkRequestLogFormat set the request format JkRequestLogFormat "%w %V %T" Send everything for context /ws to worker ajp13 JkMount /themark ajp13 JkMount /themark/* ajp13 Send everything for context /jsp-examples to worker ajp13 JkMount /static ajp13 JkMount /static/* ajp13 Send everything for context /servelts-examples to worker ajp13 JkMount /servlets-examples ajp13 JkMount /servlets-examples/* ajp13 and this my workers.properties Define 1 real worker named ajp13 worker.list=ajp13 Set properties for worker named ajp13 to use ajp13 protocol, and run on port 8009 worker.ajp13.type=ajp13 worker.ajp13.host=localhost worker.ajp13.port=8009 worker.ajp13.lbfactor=50 worker.ajp13.cachesize=10 worker.ajp13.cache_timeout=600 worker.ajp13.socket_keepalive=1 worker.ajp13.socket_timeout=300 when i start apache httpd and tomcat 6. it seem that mod_jk load successfully and tomcat 6 recognized the ajp connector. here my tomcat 6 log INFO: Starting Coyote HTTP/1.1 on http-8080 Mar 29, 2010 11:48:34 AM org.apache.jk.common.ChannelSocket init INFO: JK: ajp13 listening on /0.0.0.0:8009 Mar 29, 2010 11:48:34 AM org.apache.jk.server.JkMain start INFO: Jk running ID=0 time=0/16 config=null here my mod_jk.log [Mon Mar 29 11:06:53 2010][6688:3499775792] [info] init_jk::mod_jk.c (2830): mod_jk/1.2.26 initialized [Mon Mar 29 11:16:59 2010][18277:1983043376] [info] init_jk::mod_jk.c (2830): mod_jk/1.2.26 initialized [Mon Mar 29 11:16:59 2010][18278:1983043376] [info] init_jk::mod_jk.c (2830): mod_jk/1.2.26 initialized but when i access http://localhost/themark it won't work. it seems that apache httpd can load the mod_jk module but it can listen the ajp. is there somebody ever had same problem? nb: i use the same config in windows using xampplite and it works well

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  • Rails paginate array items one-by-one instead of page-by-page

    - by hnovick
    Hi Guys, I have a group of assets, let's call them "practitioners". I'm displaying these practitioners in the header of a calendar interface. There are 7 columns to the calendar. 7 columns = 7 practitioners per view/page. Right now: if the first page shows you practitioners 1-7, when you go the next page you will see practitioners 8-15, next page 16-23, etc. etc. i am wondering how to page the practitioners so that if the first page shows you practitioners 1-7, the next page will show you practitioners 2-8, then 3-9, etc. etc. i would greatly appreciate any help you can offer. here is the rails code i am working with. best regards, harris novick # get the default sort order sort_order = RESOURCE_SORT_ORDER # if we've been given asset ids, start our list with them unless params[:asset_ids].blank? params[:asset_ids] = params[:asset_ids].values unless params[:asset_ids].is_a?(Array) sort_order = "#{params[:asset_ids].collect{|id| "service_provider_resources.id = #{id} DESC"}.join(",")}, #{sort_order}" end @asset_set = @provider.active_resources(:include => {:active_services => :latest_approved_version}).paginate( :per_page => RESOURCES_IN_DAY_VIEW, :page => params[:page], :order => sort_order )

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  • Ubuntu: pip not working with python3.4

    - by val_
    Trying to get pip working on my Ubuntu pc. pip seems to be working for python2.7, but not for others. Here's the problem: $ pip Traceback (most recent call last): File "/usr/local/bin/pip", line 9, in <module> load_entry_point('pip==1.4.1', 'console_scripts', 'pip')() File "/usr/local/lib/python3.4/dist-packages/setuptools-1.1.5-py3.4.egg /pkg_resources.py", line 357, in load_entry_point def get_entry_info(dist, group, name): File "/usr/local/lib/python3.4/dist-packages/setuptools-1.1.5-py3.4.egg/pkg_resources.py", line 2394, in load_entry_point break File "/usr/local/lib/python3.4/dist-packages/setuptools-1.1.5-py3.4.egg/pkg_resources.py", line 2108, in load name = some.module:some.attr [extra1,extra2] ImportError: No module named 'pip' $ which pip /usr/local/bin/pip $ python2.7 -m pip //here can be just python, btw Usage: /usr/bin/python2.7 -m pip <command> [options] //and so on... $ python3.4 -m pip /usr/bin/python3.4: No module named pip From the home/user/.pip/pip.log : Exception: Traceback (most recent call last): File "/usr/lib/python2.7/dist-packages/pip/basecommand.py", line 122, in main status = self.run(options, args) File "/usr/lib/python2.7/dist-packages/pip/commands/install.py", line 283, in run requirement_set.install(install_options, global_options, root=options.root_path) File "/usr/lib/python2.7/dist-packages/pip/req.py", line 1431, in install requirement.uninstall(auto_confirm=True) File "/usr/lib/python2.7/dist-packages/pip/req.py", line 598, in uninstall paths_to_remove.remove(auto_confirm) File "/usr/lib/python2.7/dist-packages/pip/req.py", line 1836, in remove renames(path, new_path) File "/usr/lib/python2.7/dist-packages/pip/util.py", line 295, in renames shutil.move(old, new) File "/usr/lib/python2.7/shutil.py", line 303, in move os.unlink(src) OSError: [Errno 13] Permission denied: '/usr/bin/pip' There's no /usr/bin/pip btw. How can I fix this issue to work with pip and python 3.4 normally? I am trying to use pycharm, but it's package manager also stucks in this problem. Thanks for attention!

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  • If I exchange the CPU, must I reinstall the OSes? (swapping cpus from one *nix-like to another)

    - by dag729
    Hi, as suggested by the title, I want to change CPU: actually I have two computers, one with Ubuntu running on an AMD Athlon 64 dual core 5200+ and the other with FreeBSD running on an AMD Sempron single core LE-1250. I would like to swap (I am not sure that this is the correct term...) the CPUs from one computer to the other one, that is take the dual core from the ubuntu pc and put it inside the freebsd pc and viceversa. The mobo is the same. Do you think I will encounter problems?

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  • Fast CGI, Lighttpd, Ubuntu

    - by Gosh
    Is this log file familiar to someone of UBUNTU users? Lighttpd log file: > 2009-08-30 21:37:45: (log.c.75) server started > 2009-08-30 21:37:45: (mod_fastcgi.c.1029) the fastcgi-backend php5-cgi *failed* to start: > 2009-08-30 21:37:45: (mod_fastcgi.c.1033) *child exited with status 9 php5-cgi* > 2009-08-30 21:37:45: (mod_fastcgi.c.1036) If you're trying to run PHP as a FastCGI backend, make sure you're using the FastCGI-enabled version. > You can find out if it is the right one by executing 'php -v' and it should display '(cgi-fcgi)' in the output, NOT '(cgi)' NOR '(cli)'. > For more information, check http://trac.lighttpd.net/trac/wiki/Docs%3AModFastCGI#preparing-php-as-a-fastcgi-programIf this is PHP on Gentoo, add 'fastcgi' to the USE flags. > 2009-08-30 21:37:45: (mod_fastcgi.c.1340) [ERROR]: *spawning fcgi failed*. > 2009-08-30 21:37:45: (server.c.908) Configuration of plugins failed. Going down. Please open a secret how did you solved fcgi problem and made lighttpd to start, if you did. Thx, Gosh.

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  • MYSQL not running on Ubuntu OS - Error 2002.

    - by mgj
    Hi, I am a novice to mysql DB. I am trying to run the MYSQL Server on Ubuntu 10.04. Through Synaptic Package Manager I am have installed the mysql version: mysql-client-5.1 I wonder that how was the database password set for the mysql-client software that I installed through the above way.It would be nice if you could enlighten me on this. When I tried running this database, I encountered the error given below: mohnish@mohnish-laptop:/var/lib$ mysql ERROR 2002 (HY000): Can't connect to local MySQL server through socket '/var/run/mysqld/mysqld.sock' (2) mohnish@mohnish-laptop:/var/lib$ I referred to a similar question posted by another user. I didn't find a solution through the proposed answers. For instance when I tried the solutions posted for the similar question I got the following: mohnish@mohnish-laptop:/var/lib$ service start mysqld start: unrecognized service mohnish@mohnish-laptop:/var/lib$ ps -u mysql ERROR: User name does not exist. ********* simple selection ********* ********* selection by list ********* -A all processes -C by command name -N negate selection -G by real group ID (supports names) -a all w/ tty except session leaders -U by real user ID (supports names) -d all except session leaders -g by session OR by effective group name -e all processes -p by process ID T all processes on this terminal -s processes in the sessions given a all w/ tty, including other users -t by tty g OBSOLETE -- DO NOT USE -u by effective user ID (supports names) r only running processes U processes for specified users x processes w/o controlling ttys t by tty *********** output format ********** *********** long options *********** -o,o user-defined -f full --Group --User --pid --cols --ppid -j,j job control s signal --group --user --sid --rows --info -O,O preloaded -o v virtual memory --cumulative --format --deselect -l,l long u user-oriented --sort --tty --forest --version -F extra full X registers --heading --no-heading --context ********* misc options ********* -V,V show version L list format codes f ASCII art forest -m,m,-L,-T,H threads S children in sum -y change -l format -M,Z security data c true command name -c scheduling class -w,w wide output n numeric WCHAN,UID -H process hierarchy mohnish@mohnish-laptop:/var/lib$ which mysql /usr/bin/mysql mohnish@mohnish-laptop:/var/lib$ mysql ERROR 2002 (HY000): Can't connect to local MySQL server through socket '/var/run/mysqld/mysqld.sock' (2) I even tried referring to http://forums.mysql.com/read.php?11,27769,84713#msg-84713 but couldn't find anything useful. Please let me know how I could tackle this error. Thank you very much..

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  • Using CURL within a loop to download a file, 1st one works, 2nd one times out

    - by kitenski
    Morning all, I am using CURL to download an image file within a loop. The first time it runs fine and I see the image appear in the directory. The second time it fails with a timeout, despite it being a valid URL. Can anyone suggest why it always fails on the 2nd time and how to fix it? The snippet of code is: // download image $extension = "gif"; $ch = curl_init(); curl_setopt($ch, CURLOPT_TIMEOUT, 90); curl_setopt($ch, CURLOPT_URL, $imgurl); curl_setopt($ch, CURLOPT_RETURNTRANSFER, true); curl_setopt($ch, CURLOPT_FOLLOWLOCATION, true); echo $imgurl . " attempting to open URL "; $i = curl_exec($ch); if ( $i==false ) { echo curl_errno($ch).' '.curl_error($ch); } $image_name=time().'.'.$extension; $f = fopen('/fulldirectorypath/' . $image_name ,'w+'); fwrite($f,$i); fclose($f); I have put an echo in there to display the $IMGURL, to check it is valid, and upped the timeout to 90 secs, but it still fails. This is what I see on screen: http://images.eu-xmedia.de/thumbnails/34555861/5676051/pt=pic,lang=2,origfile=yes/image.gif attempting to open URL 28 Operation timed out after 90 seconds with 0 bytes received an empty file is created in my directory. thanks alot, Greg

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  • One to One XSLT map with namespace manipulations

    - by ohadinho
    I have the following xml: <ns0:Root xmlns:ns0="http://root" xmlns:nm="http://notroot"> <nm:MSH> <content>bla</content> </nm:MSH> <ns0:Second> <ns0:item>aaa</ns0:item> </ns0:Second> <ns0:Third> <ns0:itemb>vv</ns0:itemb> </ns0:Third> </ns0:Root> That is my expected result: <Root xmlns="http://root" xmlns:nm="http://notroot"> <nm:MSH> <content>bla</content> </nm:MSH> <Second> <item>aaa</item> </Second> <Third> <itemb>vv</itemb> </Third> </Root> I need to write an xslt 1.0 that perform that map. I really doesn't have a clue how to do it, thus it seems pretty simple. Can anyone please help ?

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  • Opening port 80 with Java application on Ubuntu

    - by Featheast
    What I need to do is running a Java application which is a RESTful service server side writtern by Restlet. And this service will be called by another app running on Google App Engine. Because of the restriction of GAE, every http call is limited to port 80 and 443 (http and https) with HttpUrlConnection class. As a result, I have to deploy my server side application on port 80 or 443. However, because the app is running on Ubuntu, and those ports under 1024 cannot be accessed by non-root user, then a Access Denied exception will be thrown when I run my app. The solutions that have come into my mind includs: Changing the security policy of JRE, which is the files resides in /lib/security/java.policy, to grantjava.net.SocketPermission "*.80" "listen, connect, accept, resolve" permission?However, neither using command line to include this file or overrides the content in JRE's java.policy file, the same exception keeps coming out. try to login as a root user, however because my unfamiliarity with Unix, I don't know how to do it. another solution I haven't try is to map all calls to 80 to a higher port like 1234, then I can deploy my app on 1234 without problem, and GAE call send request to port 80. But how to connect the missing gap is still a problem. Currently I am using a "hacking" method, which is to package the application into a jar file, and sudo running the jar file with root privilege. It works now, but definitely not appropriate in the real deployment environment. So if anyone have any idea about the solution, thanks very much!

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  • Compiling Objective-C project on Linux (Ubuntu)

    - by Alex
    How to make an Objective-C project work on Ubuntu? My files are: Fraction.h #import <Foundation/NSObject.h> @interface Fraction: NSObject { int numerator; int denominator; } -(void) print; -(void) setNumerator: (int) n; -(void) setDenominator: (int) d; -(int) numerator; -(int) denominator; @end Fraction.m #import "Fraction.h" #import <stdio.h> @implementation Fraction -(void) print { printf( "%i/%i", numerator, denominator ); } -(void) setNumerator: (int) n { numerator = n; } -(void) setDenominator: (int) d { denominator = d; } -(int) denominator { return denominator; } -(int) numerator { return numerator; } @end main.m #import <stdio.h> #import "Fraction.h" int main( int argc, const char *argv[] ) { // create a new instance Fraction *frac = [[Fraction alloc] init]; // set the values [frac setNumerator: 1]; [frac setDenominator: 3]; // print it printf( "The fraction is: " ); [frac print]; printf( "\n" ); // free memory [frac release]; return 0; } I've tried two approaches to compile it: Pure gcc: $ sudo apt-get install gobjc gnustep gnustep-devel $ gcc `gnustep-config --objc-flags` -o main main.m -lobjc -lgnustep-base /tmp/ccIQKhfH.o:(.data.rel+0x0): undefined reference to `__objc_class_name_Fraction' I created a GNUmakefile Makefile: include ${GNUSTEP_MAKEFILES}/common.make TOOL_NAME = main main_OBJC_FILES = main.m include ${GNUSTEP_MAKEFILES}/tool.make ... and ran: $ source /usr/share/GNUstep/Makefiles/GNUstep.sh $ make Making all for tool main... Linking tool main ... ./obj/main.o:(.data.rel+0x0): undefined reference to `__objc_class_name_Fraction' So in both cases compiler gets stuck at undefined reference to `__objc_class_name_Fraction' Do you have and idea how to resolve this issue?

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  • echo -e acts differently when run in a script by root on ubuntu

    - by ekrub
    When running a bash script on ubuntu 9.10, I get different behavior from bash echo's "-e" option depending on whether or not I'm running as root. Consider this script: $ cat echo-test if [ "`whoami`" = "root" ]; then echo "Running as root" fi echo Testing /bin/echo -e /bin/echo -e "foo\nbar" echo Testing bash echo -e echo -e "foo\nbar" When run as non-root user, I see this output: $ ./echo-test Testing /bin/echo -e foo bar Testing bash echo -e foo bar When run as root, I see this output: $ sudo ./echo-test Running as root Testing /bin/echo -e foo bar Testing bash echo -e -e foo bar Notice the "-e" being echoed in the last case ("-e foo" instead of "foo" on the second-to-last line). When running a script as root, the echo command runs as if "-e" was given and, if -e is given, the option itself is echoed. I can understand some subtle differences in behavior between /bin/echo and bash echo, but I would expect bash echo to behave the same no matter which user invokes it. Anyone know why this is the case? Is this a bug in bash echo? FYI -- I'm running GNU bash, version 4.0.33(1)-release (x86_64-pc-linux-gnu)

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  • 32/64 bit problems with Eclipse CDT on Ubuntu

    - by waffleShirt
    I have just recently started running Linux on my PC and I am trying to start learning OpenGL. I am using the latest version of Eclipse CDT as my IDE, and my system is Ubuntu 10.10, 64 bit version. The problem I am having is that whenever I try to run a build from within the IDE I get the error message "Launch Failed. Binary Not Found." Ive done a lot of looking around on the internet but I still cant solve the problem. I know for a fact that the binary is built, it can be run from a terminal window. According to posts I have seen the problem is that Eclipse tries to run a 32 bit binary, but GCC 4.4.5 defaults to 64 bit binaries on a 64 bit system. Ive seen a lot of information about using the -m32 flag in makefiles, but then I still get the following output in Eclipse: make all g++ -o HelloWorld2 main.o /usr/bin/ld: i386 architecture of input file `main.o' is incompatible with i386:x86-64 output /usr/bin/ld: final link failed: Invalid operation collect2: ld returned 1 exit status make: *** [HelloWorld2] Error 1 What I would like to know is how to either get Eclipse to launch the 64 bit binaries, or have Eclipse correctly compile 32 bit binaries.

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  • UDP sockets in ad hoc network (Ubuntu 9.10)

    - by Ekhiotz
    Hi! I am using BSD sockets in Ubuntu 9.10 to send UDP packets in broadcast with the following code: sock_fd = socket(PF_INET,SOCK_DGRAM,IPPROTO_UDP); //sock_fd=socket(AF_INET,SOCK_DGRAM,0); receiver_addr.sin_family = PF_INET; //does not send with broadcast in ad hoc receiver_addr.sin_addr.s_addr = htonl(INADDR_BROADCAST); inet_aton("169.254.255.255",&receiver_addr.sin_addr); receiver_addr.sin_port = htons(port); int broadcast = 1; // this call is what allows broadcast packets to be sent: if (setsockopt(sock_fd, SOL_SOCKET, SO_BROADCAST, &broadcast, sizeof broadcast) == -1) { perror("setsockopt (SO_BROADCAST)"); exit(1); } ret=sendto(sock_fd, packet, size, 0,(struct sockaddr*)&receiver_addr,sizeof(receiver_addr)); Note that is not all the code, it is only to have an idea. The program sends all the data with INADDR_BROADCAST if I am connected to an infrastructure wireless network. However, if my laptop is connected to an ad-hoc network, it is able to receive all the data, but not to send it. I have solved the problem using the 169.254.255.255 broadcast address, but I would like to know what is going on. Thank you in advance!

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  • How to split Chinese characters one by one?

    - by Nano HE
    Hi If there is no special character(such as white space, : etc) between firstname and lastname. Then how to split the Chinese characters below. use strict; use warnings; use Data::Dumper; my $fh = \*DATA; my $fname; # ? ; my $lname; # ??; while(my $name = <$fh>) { $name =~ ??? ; print $fname"/n"; print $lname; } __DATA__ ??? Output ? ??

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  • Adding single row one by one in tableview from core data of iPhone

    - by user336685
    I am working on RSS reader code where articles get downloaded and are viewable offline. The problem is only after all articles are downlaoded the tableview containing headlines gets updated. Core data is used. So everytime NSobjectcontext is saved , [self tableview updatebegins ] is called.The table is getting updated via fetchcontroller core data. I tried saving NSobjectcontext everytime an article is saved but that is not updating the tableview. I want a mechanism similar to instapaper tableview where articles get saved and tableview gets updated immediately. Please help if you know the solution. Thanks in advance.

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  • Deploying a Rails app on an Ubuntu server using Git

    - by NudeCanalTroll
    I'm completely new to Linux, but today I find myself setting up a server (Ubuntu 10.04 LTS lucid) from scratch to host a Rails application. Anyway, I managed to get a Rails app up and running on the server itself, but I had to scrap that because I want to use Git. So I setup a git repository on the server, then pushed all the code from my local machine to the repository. Buuuut, of course Git doesn't actually store the files themselves in the repository -- all the code for my Rails app is now only on my local machine. How am I supposed to tell the server to host that? Right now my solution is to have the server use git to pull the code from its own repository. That's the code I'll host for all the world to see. In order to update the code, I guess I'll have to do something like this: Update the code on my local machine. Do some git adds, git commits, and a git push. On the server, do a git pull to update the code. So my question is, am I doing this the right way? enter code here

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  • retrive file line one by one using C#?

    - by riad
    Dear all, I have a file name abc.txt.On that file have some lines like this: jani 50,south carolina,USA karim 16,roam,Italy fara 52,sydny,Australia first line is name and second line is address.Now i need the info name on a string let say nameString and address is let say addressString.How can i do it using C#? I write a code in PHP its working smoothly.I need the same thing in C#.For yours clarification here is the php code: $file=file_get_contents('abc.txt'); $arr=explode("\n",$file); for ($i=0;$i<count($arr);$i=$i+2) { $name=$arr[$i]; $address=$arr[$i+1]; echo $name ."<br/>"; echo $address. "<br/>"; } How can i do the same thing in C#???? Another question: IS their any function in C# as like as explode in php? thanks in advance riad

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  • Why One-to-one relationship dosen't work?

    - by eugenn
    I'm trying to create a very simple relationship between two objects. Can anybody explain me why I can't find the Company object via findBy method? class Company { String name String desc City city static constraints = { city(unique: true) } } class City { String name static constraints = { } } class BootStrap { def init = { servletContext -> new City(name: 'Tokyo').save() new City(name: 'New York').save() new Company(name: 'company', city: City.findByName('New York')).save() def c = Company.findByName('company') // Why c=null????! } def destroy = { } }

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  • Copying Android source code directory from one computer to an other one

    - by Walidix
    I have downloaded the Android source code on my computer using the repo sync command. Since I have no experience with git and repo , I would like to know if it is possible to copy the mydroid directory (which contains Android source code) to an other computer by just burning it on a DVD and then processing the build without problems. Thanks in advance and sorry if my question is stupid

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  • How to regularly merge two git repositories, one with submodules into one without

    - by smoothify
    I maintain a Drupal project in a git repository containing submodules. This works well for me overall, and I like the submodule approach. However, I would like to move my site to a hosting provider that offers deployment via git push but doesn't work with submodules. I would like to keep my current repository intact, and then when I'm ready to deploy, I would like to merge the changes from my repository into the deployment repository, but any submodules need to be exported into the tree. So, it needs to be (semi) automated, so I can just run a command or two and initiate the merge, and then push to the server. Ideally it would keep track of individual commits, but I wouldn't mind if it squashed them into a single commit. How would be the most effective way to achieve this?

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  • Hibernate one to one with multiple columns

    - by Erdem Emekligil
    How can i bind two columns, using @OneToOne annotation? Lets say I've 2 tables A and B. Table A: id1 (primary key) id2 (pk) other columns Table B: id1 (pk) id2 (pk) other columns In class A i want to write something like this: @OneToOne(fetch = FetchType.EAGER, targetEntity = B.class) @JoinColumn(name = "id1 and id2", referencedColumnName = "id1 and id2") private B b; Is it possible to do this using annotations? Thanks.

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