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  • One Common View In Every ViewController

    - by l3v
    I am having a hard time wording this when searching the internet so I am just going to ask the question. I have an options view in my app that slides into view when the user clicks a button. This options view will display app information like settings. I want this options view to be displayed on every view controller in my app. I do not want to copy and paste the code for the options view into every viewcontroller file. The options view has quite a few outlets and actions and also calls many delegates. How can I reuse this options view in all my view controllers without adding all the outlets, actions, and delegate methods each time? I was going to make a new file with public methods, but I would still have to copy the outlets. Would this public methods file have to include delegate methods as well then? Let me know if my question does not make sense. I am hoping there is a standard way of implementing something like this.

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  • Setting a property from one collection to another collection

    - by ooo
    I have two colluections List<Application> myApps; List<Application> yourApps; These lists have overlapping overlapping data but they are coming from different sources and each source has some missing field data. Application object has a property called Description Both collections have a unique field called Key i want to see if there is a LINQ solution to: Loop through all applications in myApps and look at the key and see if that existing in yourApps. If it does, i want to take the description property from that application in yourApps and set the description property on the application on myApps to that same value i wanted to see if there was any slick way using lambda expressions (instead of having to have loops and a number of if statements.)

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  • Wordpress: Issues trying to display all comments in one page

    - by KeyStroke
    Hi, I'm trying to modify my wordpress theme (inove) to display all comments in the same page instead of 50 comments per page. I opened the comments.php file, commented out calls to paginate_comments_links() and and set the wp_list_comments() as follows: wp_list_comments('type=comment&callback=custom_comments&per_page=100&page=1'); The problem is, whenever someone posts a comments, the comment form appends '/comment-page-2/' to the URL after submitting the comment, even though I've specified that all comments to be displayed on the same page. Any idea what I could be missing? Appreciate your help

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  • [Django] One single page to create a Parent object and its associated child objects

    - by ahmoo
    Hi all, This is my very first post on this awesome site, from which I have been finding answers to a handful of challenging questions. Kudos to the community! I am new to the Django world, so am hoping to find help from some Django experts here. Thanks in advance. Item model: class Item(models.Model): name = models.CharField(max_length=50) ItemImage model: class ItemImage(models.Model): image = models.ImageField(upload_to=get_unique_filename) item = models.ForeignKey(Item, related_name='images') As you can tell from the model definitions above, every Item object can have many ItemImage objects. My requirements are as followings: A single web page that allows users to create a new Item while uploading the images associated with the Item. The Item and the ItemImages objects should be created in the database all together, when the "Save" button on the page is clicked. I have created a variable in a custom config file, called NUMBER_OF_IMAGES_PER_ITEM. It is based on this variable that the system generates the number of image fields per item. Questions: What should the forms and the template be like? Can ModelForm be used to achieve the requirements? For the view function, what do I need to watch out other than making sure to save Item before ItemImage objects?

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  • one-liner if statements...

    - by snickered
    Total noob here so be gentle. I've looked everywhere and can't seem to find the answer to this. How do I condense the following? if (expression) { return true; } else { return false; } I can't get it to work since it's returning something vs. setting something. I've already seen things like this: somevar = (expression) ? value1 : value2; Like I said, please be gentle :)

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  • php values of one array to key of another array

    - by mark
    I have 2 arrays $arr1 = Array ( [0] => 12 [1] => 4 [2] => 8 [3] => xx [4] => 1 [5] => 1year [6] => 7 ) $arr2 = Array ( [0] => 1 [1] => 2 [2] => 3 [3] => 4 [4] => 5 [5] => 6 [6] => 7 ) I want to create a new array with the values of a2 as keys in $arr1. My resultant array should be like this $arr3 = Array ( [1] => 12 [2] => 4 [3] => 8 [4] => xx [5] => 1 [6] => 1year [7] => 7 )

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  • displaying search results of more than one word

    - by fusion
    in my search form, if the user types 'good', it displays all the results which contain the keyword 'good'. however if the user types in 'good sweetest', it displays no results because there is no record with the two words appearing together; BUT appearing in an entry at different places. for example, the record says: A good action is an ever-remaining store and a pure yield the user types in 'good', it will show up this record, but if the user types in 'good' + 'pure', it will not show anything. or if the record contains the keyword 'good-deeds' and if the user types in 'good deeds' without the hyphen, it will not show anything. what i would like is that if the user types in 'good' + 'pure' or 'good deeds' it should records containing these keywords highlighting them. search.php code: $search_result = ""; $search_result = $_POST["q"]; $search_result = trim($search_result); //Check if the string is empty if ($search_result == "") { echo "<p class='error'>Search Error. Please Enter Your Search Query.</p>" ; exit(); } if ($search_result == "%" || $search_result == "_" || $search_result == "+" ) { echo "<p class='error1'>Search Error. Please Enter a Valid Search Query.</p>" ; exit(); } $result = mysql_query('SELECT cQuotes, vAuthor, cArabic, vReference FROM thquotes WHERE cQuotes LIKE "%' . mysql_real_escape_string($search_result) .'%" ORDER BY idQuotes DESC', $conn) or die ('Error: '.mysql_error()); function h($s) { echo htmlspecialchars($s, ENT_QUOTES); } function highlightWords($string, $word) { $string = preg_replace("/".preg_quote($word, "/")."/i", "<span class='highlight'>$0</span>", $string); /*** return the highlighted string ***/ return $string; } ?> <div class="caption">Search Results</div> <div class="center_div"> <table> <?php while ($row= mysql_fetch_array($result, MYSQL_ASSOC)) { $cQuote = highlightWords(htmlspecialchars($row['cQuotes']), $search_result); ?> <tr> <td style="text-align:right; font-size:18px;"><?php h($row['cArabic']); ?></td> <td style="font-size:16px;"><?php echo $cQuote; ?></td> <td style="font-size:12px;"><?php h($row['vAuthor']); ?></td> <td style="font-size:12px; font-style:italic; text-align:right;"><?php h($row['vReference']); ?></td> </tr> <?php } ?> </table> </div> search.html: <form name="myform" class="wrapper"> <input type="text" name="q" onkeyup="showUser()" class="txt_search"/> <input type="button" name="button" onclick="showUser()" class="button"/> <p> <div id="txtHint"></div> </form>

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  • C++: How to require that one template type is derived from the other

    - by Will
    In a comparison operator: template<class R1, class R2> bool operator==(Manager<R1> m1, Manager<R2> m2) { return m1.internal_field == m2.internal_field; } Is there any way I could enforce that R1 and R2 must have a supertype or subtype relation? That is, I'd like to allow either R1 to be derived from R2, or R2 to be derived from R1, but disallow the comparison if R1 and R2 are unrelated types.

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  • Getting changes in one column of an historical table

    - by Javi
    Hello, I have a table which stores historical data. It's mapped to an Entity with the following fields (I use JPA with Hibernate implementation): @Entity @Table(name="items_historical") public class ItemHistory{ private Integer id; private Date date; @Enumerated(EnumType.ORDINAL) private StatusEnum status @ManyToOne(optional=false) private User user; @ManyToOne(optional=false) private Item item; } public enum StatusEnum { OK, BAD,...//my status } In every row I store historical data of another table. I need to get the list of the changes on "status" column: the status, the date and the previous status on a specified item (It would be good as well getting the status and date when status was changed). I don't know if this is possible by using HQL. Thanks.

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  • One UI for two business objects

    - by JC
    I have an order edit and quote edit screen that are very similar. I want to try to avoid code like this: if (order is Order) SetupScreenForOrder(); if (order is Quote) SetupScreenForQuote(); But maintaining two screens is not good either. If I create some common interface between a Quote and Order then how do you deal with fields like OrderNumber or QuoteDate? What's the best way to handle this?

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  • Copy data from a table to another one has different structure

    - by Kernel
    I have two tables with different structure: TableSource: intId(not null), txtSummary, strDetail TableDesc: guidId(not null), guidFK(not null), Name, Detail I want to migrate data from two fields of tableSource(txtSummary, strDetail) to two fields of tableDesc(Name, Detail). For simply,suppose that guidId and guidFK are auto generation. I'v tried but not success. Could anyone help me?

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  • Left Join only returning one row

    - by Adam
    I am trying to join two tables. I would like all the columns from the product_category table (there are a total of 6 now) and count the number of products, CatCount, that are in each category from the products_has_product_category table. My query result is 1 row with the first category and a total count of 68, when I am looking for 6 rows with each individual category's count. <?php $result = mysql_query(" SELECT a.*, COUNT(b.category_id) AS CatCount FROM `product_category` a LEFT JOIN `products_has_product_category` b ON a.product_category_id = b.category_id "); while($row = mysql_fetch_array($result)) { echo ' <li class="ui-shadow" data-count-theme="d"> <a href="' . $row['product_category_ref_page'] . '.php" data-icon="arrow-r" data-iconpos="right">' . $row['product_category_name'] . '</a><span class="ui-li-count">' . $row['CatCount'] . '</span></li>'; } ?> I have been working on this for a couple of hours and would really appreciate any help on what I am doing wrong.

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  • mix together cck imageField and videoField in one ordered list

    - by Patrick
    hi, I'm using imageField and videoField into each node of my website and I'm using multiple files option, so that I have 2 ordered lists. This works great, however I would like to have only 1 ordered list instead of 2, so that my customer can arrange video and images in the same list and ordered them i.e. video1 image1 video2 video3 image2 ... etc thanks

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  • which one is a faster/better sql practice?

    - by artsince
    Suppose I have a 2 column table (id, flag) and id is sequential. I expect this table to contain a lot of records. I want to periodically select the first row not flagged and update it. Some of the records on the way may have already been flagged, so I want to skip them. Does it make more sense if I store the last id I flagged and use it in my select statement, like select * from mytable where id > my_last_id order by id asc limit 1 or simply get the first unflagged row, like: select * from mytable where flagged = 'F' order by id asc limit 1 Thank you!

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  • Item of one combobox should not come into the other

    - by syedsaleemss
    Im using c# .net windows form application. I have a database with some tables.I have two comboboxes (A & B). I have populated a combo box A with column names of a table using sys.columns. Now when i select an item in combo box A ,combo box B should be populated with the same items except the selected item which was selected in combobox A .

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  • MySQL: List rows who have one but not another many-to-many relationship

    - by Svish
    Not quite sure how to ask or define this, but can't figure it out. I have three tables like this: persons person_id, first_name, last_name hobbies hobby_id, name persons_hobbies person_id, hobby_id I need to make two lists. Persons that have both hobby A and B, and persons that have hobby A but not B. How can I write these two queries? Can't figure out how to do this with joining and all...

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  • Multiple certs with one private key on apache?

    - by tenbatsu
    Really fundamental question here, but nothing a quick google search is lending itself to. Do I need to generate a separate private key for each cert I use in apache? Server details: % /usr/sbin/httpd -v Server version: Apache/2.2.8 (Unix) Server built: Jan 24 2008 10:44:19 % uname -a Linux *.com 2.6.23.15-80.fc7 #1 SMP Sun Feb 10 17:29:10 EST 2008 i686 i686 i386 GNU/Linux % cat /proc/versionversion 2.6.23.15-80.fc7 ([email protected]) (gcc version 4.1.2 20070925 (Red Hat 4.1.2-27)) #1 SMP Sun Feb 10 17:29:10 EST 2008

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  • Merging hashes into one hash in perl

    - by Nick
    how do I get this: $VAR1 = { '999' => { '998' => [ '908', '906', '0', '998', '907' ] } }; $VAR1 = { '999' => { '991' => [ '913', '920', '918', '998', '916', '919', '917', '915', '912', '914' ] } }; $VAR1 = { '999' => { '996' => [] } }; $VAR1 = { '999' => { '995' => [] } }; $VAR1 = { '999' => { '994' => [] } }; $VAR1 = { '999' => { '993' => [] } }; $VAR1 = { '999' => { '997' => [ '986', '987', '990', '984', '989', '988' ] } }; $VAR1 = { '995' => { '101' => [] } }; $VAR1 = { '995' => { '102' => [] } }; $VAR1 = { '995' => { '103' => [] } }; $VAR1 = { '995' => { '104' => [] } }; $VAR1 = { '995' => { '105' => [] } }; $VAR1 = { '995' => { '106' => [] } }; $VAR1 = { '995' => { '107' => [] } }; $VAR1 = { '994' => { '910' => [] } }; $VAR1 = { '993' => { '909' => [] } }; $VAR1 = { '993' => { '904' => [] } }; $VAR1 = { '994' => { '985' => [] } }; $VAR1 = { '994' => { '983' => [] } }; $VAR1 = { '993' => { '902' => [] } }; $VAR1 = { '999' => { '992' => [ '905' ] } }; to this: $VAR1 = { '999:' => [ { '992' => [ '905' ] }, { '993' => [ { '909' => [] }, { '904' => [] }, { '902' => [] } ] }, { '994' => [ { '910' => [] }, { '985' => [] }, { '983' => [] } ] }, { '995' => [ { '101' => [] }, { '102' => [] }, { '103' => [] }, { '104' => [] }, { '105' => [] }, { '106' => [] }, { '107' => [] } ] }, { '996' => [] }, { '997' => [ '986', '987', '990', '984', '989', '988' ] }, { '998' => [ '908', '906', '0', '998', '907' ] }, { '991' => [ '913', '920', '918', '998', '916', '919', '917', '915', '912', '914' ] } ]}; in Perl?

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