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  • are mobile can be used as a devices to develop application

    - by Richa Media and services
    I say that we can work @ mobile using a technique and work with any IDE and use any OS without problem like work on visual studio and use Window 7 How it possible ? 1. We use Mobile like a CPU and Use a monitor to watch code. We use samsung's techniques to display on monitor. it's give signal to monitor wirelessly to display code on monitor 2 We use Wireless keyboard and Mouse (if user like USB then he also use USB keyboard and mouse) 3. We use a component inside of mobile to control all devices like internet , wi-fi bluethoth. by component user easily setup , control and use feature. 4 don't be confused. i am sure to say that we not use mobile to watch code on mobile screen and Mobile 's keyboard because it's too smaller to work so we use Monitor (LCD) to display code and a keyboard to work comfortably and freely. 5. what are you think if you see a developer who work using this way 6. it is not impossible. give me some feedback and suggestion about your thinking on this technologies.

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  • how to handle empty selection in a jface bound combobox?

    - by guido
    I am developing a search dialog in my eclipse-rcp application. In the search dialog I have a combobox as follows: comboImp = new CCombo(grpColSpet, SWT.BORDER | SWT.READ_ONLY); comboImp.setBounds(556, 46, 184, 27); comboImpViewer = new ComboViewer(comboImp); comboImpViewer.setContentProvider(new ArrayContentProvider()); comboImpViewer.setInput(ImpContentProvider.getInstance().getImps()); comboImpViewer.setLabelProvider(new LabelProvider() { @Override public String getText(Object element) { return ((Imp)element).getImpName(); } }); Imp is a database entity, ManyToOne to the main entity which is searched, and ImpContentProvider is the model class which speaks to embedded sqlite database via jpa/hibernate. This combobox is supposed to contain all instances of Imp, but to also let empty selection; it's value is bound to a service bean as follows: IObservableValue comboImpSelectionObserveWidget = ViewersObservables.observeSingleSelection(comboImpViewer); IObservableValue filterByImpObserveValue = BeansObservables.observeValue(searchPrep, "imp"); bindingContext.bindValue(comboImpSelectionObserveWidget, filterByImpObserveValue , null, null); As soon as the user clicks on the combo, a selection (first element) is made: I can see the call to a selectionlistener i added on the viewer. My question is: after a selection has been made, how do I let the user change his mind and have an empty selection in the combobox? should I add a "fake" empty instance of Imp to the List returned by the ImpContentProvider? or should I implement an alternative to ArrayContentProvider? and one additional related question is: why calling deselectAll() and clearSelection() on the combo does NOT set a null value to the bound bean?

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  • JPA: persisting object, parent is ok but child not updated

    - by James.Elsey
    Hello, I have my domain object, Client, I've got a form on my JSP that is pre-populated with its data, I can take in amended values, and persist the object. Client has an abstract entity called MarketResearch, which is then extended by one of three more concrete sub-classes. I have a form to pre-populate some MarketResearch data, but when I make changes and try to persist the Client, it doesn't get saved, can someone give me some pointers on where I've gone wrong? My 3 domain classes are as follows (removed accessors etc) public class Client extends NamedEntity { @OneToOne @JoinColumn(name = "MARKET_RESEARCH_ID") private MarketResearch marketResearch; ... } @Inheritance(strategy = InheritanceType.JOINED) public abstract class MarketResearch extends AbstractEntity { ... } @Entity(name="MARKETRESEARCHLG") public class MarketResearchLocalGovernment extends MarketResearch { @Column(name = "CURRENT_HR_SYSTEM") private String currentHRSystem; ... } This is how I'm persisting public void persistClient(Client client) { if (client.getId() != null) { getJpaTemplate().merge(client); getJpaTemplate().flush(); } else { getJpaTemplate().persist(client); } } To summarize, if I change something on the parent object, it persists, but if I change something on the child object it doesn't. Have I missed something blatantly obvious? Thanks

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  • How can I take advantage of IObservable/IObserver to get rid of my "god object"?

    - by Will
    In a system I'm currently working on, I have many components which are defined as interfaces and base classes. Each part of the system has some specific points where they interact with other parts of the system. For example, the data readying component readies some data which eventually needs to go to the data processing portion, the communications component needs to query different components for their status for relaying to the outside, etc. Currently, I glue these parts of the system together using a "god object", or an object with intimate knowledge of different parts of the system. It registers with events over here and shuttles the results to methods over there, creates a callback method here and returns the result of that method over there, and passes many requests through a multi-threaded queue for processing because it "knows" certain actions have to run on STA threads, etc. While its convenient, it concerns me that this one type knows so much about how everybody else in the system is designed. I'd much prefer a more generic hub that can be given instances which can expose events or methods or callbacks or that can consume these. I've been seeing more about the IObservable/IObserver features of the reactive framework and that are being rolled into .NET 4.0 (I believe). Can I leverage this pattern to help replace my "god object"? How should I go about doing this? Are there any resources for using this pattern for this specific purpose?

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  • Playframework sends 2 queries for fetched query

    - by MRu
    I currently have problems with the JPA at the play framework 1.2.4. I need to have a UserOptions model in a separate database and want to join it lazyly cause its only needed in one query. In this query I want to load the options eagerly and by searching I found out that can only be done by using a join query. If I use eager instead oder lazy, everything would be fine by using User.findById() and the options and the user is found in one query. But play sends two queries when I use a 'left join fetch' query. So heres the query: User.find(" SELECT user FROM User user LEFT JOIN FETCH user.options options WHERE user.id = ? ", Long.parseLong(id)).first(); And here the models: @Entity public class User extends Model { @OneToOne(mappedBy = "user", fetch = FetchType.LAZY) public UserOptions options; // ... } @Entity public class UserOptions extends Model { @OneToOne(fetch = FetchType.LAZY) public User user; } The question is why play sends two query for the fetch query? Thanks in advance

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  • How to refer to enum values inside nhibernate formula mapping specification?

    - by mark
    Dear ladies and sirs. I have two entities types: RunContainer parent entity type Run child entity type Run has a property Status, which is of type RunStatus, like so: public enum RunStatus { Created, Starting, // ... } public class Run { public int ContainerId { get; private set; } // ... public RunStatus Status { get; private set; } } RunContainer has a calculated property ActiveRunCount, like so: public class RunContainer { public int Id { get; private set; } // ... public int ActiveRunCount { get; private set; } } In the mapping for the RunContainer.ActiveRunCount property, I use the formula specification like so: <property name="ActiveRunCount" formula="(select count(r.Id) from Run r where r.ContainerId = Id and r.Status = 1)"/> My problem is that I refer to the RunStatus enum values in the formula by their respective numeric value, rather than the appropriate symbolic name. Can anyone tell me how can I use the symbolic name instead? Thanks.

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  • MVC design for archived data view

    - by Hemant Tank
    Implementation of a standard archive process in ASP.Net MVC. Backend SQL Server 2005 We've an existing web app built in MVC. We've an Entity "Claim" and it has some child entities like ClaimDetails, Files, etc... A pretty standard setup in DB. Each entity has its own table and are linked via FK. Now, we need to have an "Archive" feature in web app which will allow admin to archive a Claim and its child entities. An archived Claim shud become readonly when visited again. Here're some points on which I need your valued opinion - To keep it simple and scalable (for a few million records) for now we plan to simply add a bit field "Archived" to the Claim table in db. And change the behavior accordingly in the web app. We've a 'Manage claim' page which renders a bunch of diff views for Claim and its child entities. Now, for a readonly view we can either use the same views or have a separate set of views. What do you suggest? At controller level, we can identify archived claim and select which view to render. At model level, though it'd be great to be able to use the same model used for Manage Claim - but it might not get us the "text" of some lookup fields. For example, Claim.BrandId is rendered as a dropdown in Manage claim (requires only BrandId) but for readonly view we need 'BrandText'. Any existing ref or architecture level example would be great. Here's my prev SO post but its more about db level changes: Design a process to archive data (SQL Server 2005) Thank you.

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  • Problem updating collection using JPA

    - by FarmBoy
    I have an entity class Foo foo that contains Collection<Bar> bars. I've tried a variety of ways, but I'm unable to successfully update my collection. One attempt: foo = em.find(key); foo.getBars().clear(); foo.setBars(bars); em.flush; \\ commit, etc. This appends the new collection to the old one. Another attempt: foo = em.find(key); bars = foo.getBars(); for (Bar bar : bars) { em.remove(bar); } em.flush; At this point, I thought I could add the new collection, but I find that the entity foo has been wiped out. Here are some annotations. In Foo: @OneToMany(cascade = { CascadeType.ALL }, mappedBy = "foo") private List<Bar> bars; In Bar: @ManyToOne(optional = false, cascade = { CascadeType.ALL }) @JoinColumn(name = "FOO_ID") private Foo foo; Has anyone else had trouble with this? Any ideas?

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  • How do I pass dependency to object with Castle Windsor and MS Test?

    - by Nick
    I am trying to use Castle Windsor with MS Test. The test class only seems to use the default constructor. How do I configure Castle to resolve the service in the constructor? Here is the Test Class' constructors: private readonly IWebBrowser _browser; public DepressionSummaryTests() { } public DepressionSummaryTests(IWebBrowser browser) { _browser = browser; } My component in the app config looks like so: <castle> <components> <component id="browser" service="ConversationSummary.IWebBrowser, ConversationSummary" type="ConversationSummary.Browser" /> </components> </castle> Here is my application container: public class ApplicationContainer : WindsorContainer { private static IWindsorContainer container; static ApplicationContainer() { container = new WindsorContainer(new XmlInterpreter(new ConfigResource("castle"))); } private static IWindsorContainer Container { get { return container; } } public static IWebBrowser Browser { get { return (IWebBrowser) Container.Resolve("browser"); } } } MS test requires the default constructor. What am I missing? Thanks!

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  • How to deal with a Java serialized object whose package changed?

    - by Alex
    I have a Java class that is stored in an HttpSession object that's serialized and transfered between servers in a cluster environment. For the purpose of this explanation, lets call this class "Person". While in the process of improving the code, this class was moved from "com.acme.Person" to "com.acme.entity.Person". Internally, the class remains exactly the same (same fields, same methods, same everything). The problem is that we have two sets of servers running the old code and the new code at the same time. The servers with the old code have serialized HttpSession object and when the new code unserializes it, it throws a ClassNotFoundException because it can't find the old reference to com.acme.Person. At this point, it's easy to deal with this because we can just recreate the object using the new package. The problem then becomes that the HttpSession in the new servers, will serialize the object with the new reference to com.acme.entity.Person, and when this is unserialized in the servers running the old code, another exception will be thrown. At this point, we can't deal with this exception anymore. What's the best strategy to follow for this kind of cases? Is there a way to tell the new servers to serialize the object with the reference to the old package and unserialize references to the old package to the new one? How would we transition to using the new package and forgetting about the old one once all servers run the new code?

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  • Can't delete record via the datacontext it was retrieved from

    - by Antilogic
    I just upgraded one of my application's methods to use compiled queries (not sure if this is relevant). Now I'm getting contradicting error messages when I run the code. This is my method: MyClass existing = Queries.MyStaticCompiledQuery(MyRequestScopedDataContext, param1, param2).SingleOrDefault(); if (existing != null) { MyRequestScopedDataContext.MyClasses.DeleteOnSubmit(existing); } When I run it I get this message: Cannot remove an entity that has not been attached. Note that the compiled query and the DeleteOnSubmit reference the same DataContext. Still I figured I'd humor the application and add an attach command before the DeleteOnSubmit, like so: MyClass existing = Queries.MyStaticCompiledQuery(MyRequestScopedDataContext, param1, param2).SingleOrDefault(); if (existing != null) { MyRequestScopedDataContext.MyClasses.Attach(existing); MyRequestScopedDataContext.MyClasses.DeleteOnSubmit(existing); } BUT... When I run this code, I get a completely different contradictory error message: An attempt has been made to Attach or Add an entity that is not new, perhaps having been loaded from another DataContext. This is not supported. I'm at a complete loss... Does anyone else have some insight as to why I can't delete a record via the same DataContext I retrieved it from?

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  • JPA / Hibernate checks conditions in merge()

    - by bert
    Working with JPA / Hibernate in an OSIV Web environment is driving me mad ;) Following scenario: I have an entity A that is loaded via JPA and has a collection of B entities. Those B entities have a required field. When the user adds a new B to A by pressing a link in the webapp, that required field is not set (since there is no sensible default value). Upon the next http request, the OSIV filter tries to merge the A entity, but this fails as Hibernate complains that the new B has a required field is not set. javax.persistence.PersistenceException: org.hibernate.PropertyValueException: not-null property references a null or transient value Reading the JPA spec, i see no sign that those checks are required in the merge phase (i have no transaction active) I can't keep the collection of B's outside of A and only add them to A when the user presses 'save' (aka entitymanager.persist()) as the place where the save button is does not know about the B's, only about A. Also A and B are only examples, i have similar stuff all over the place .. Any ideas? Do other JPA implementaions behave the same here? Thanks in advance.

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  • flex positioning a button within a panel

    - by pfunc
    All I'm trying to do is place a button inside of a panel, rotate that button (so it is vertical) and place it on the edge of the panel. I can;t seem to do this correctly. Here is my code: <mx:Panel id="weekList" width="260" height="100%" x="-500" title="Weeks" > <mx:List id="weekButtonList" width="260" borderVisible="false" contentBackgroundAlpha="0" dataProvider="{_data.mappoints.week.@number}" itemClick="onWeekClick(event);" > <mx:itemRenderer> <mx:Component> <mx:Button buttonMode="true" right="20" width="260" height="50" label="Week {data}" /> </mx:Component> </mx:itemRenderer> </mx:List> <mx:HBox id="closeButtonHolder" rotation="90" width="100" > <mx:Button label="OPEN" click="weekListToggle()" /> </mx:HBox> </mx:Panel> If you look at the part of the script you will see I am trying to rotate it and move it to the left. I am just trying to move it somewhere, and nothing is working. Also, the text seems to dissapear when I rotate it on a 90% axis. Anyone know what I can do for this?

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  • Setting Image.Source doesn't update when loading from a resource.

    - by ChrisF
    I've got this definition in my XAML: <Image Name="AlbumArt" Source="/AlbumChooser2;component/Resources/help.png" /> The image is display OK on startup. In my code I'm looking for mp3's to play and I display the associated album art in this Image. Now if there's no associated image I want to display a "no image" image. So I've got one defined and I load it using: BitmapImage noImage = new BitmapImage( new Uri("/AlbumChooser2;component/Resources/no_image.png", UriKind.Relative)); I've got a helper class that finds the image if there is one (returning it as a BitmapImage), or returns null if there isn't one: if (findImage.Image != null) { this.AlbumArt.Source = findImage.Image; // This works } else { this.AlbumArt.Source = noImage; // This doesn't work } In the case where an image is found the source is updated and the album art gets displayed. In the case where an image isn't found I don't get anything displayed - just a blank. I don't think that it's the setting of AlbumArt.Source that's wrong, but the loading of the BitmapImage. If I use a different image it works, but if I recreate the image it doesn't work. What could be wrong with the image?

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  • JPA + EJB + JSF: how can design complicated query

    - by Harry Pham
    I am using netbean 6.8 btw. Let say that I have 4 different tables: Company, Facility, Project, and Document. So the relationship is this. A company can have multiple facilities. A facility can have multiple projects, and a project can have multiple documents. Company: +companyNum: PK +facilityNum: FK Facility: +facilityNum: PK +projectNum: FK Project: +projectNum: PK +drawingNum: FK So when I create Entity Class From Database in netbean 6.8, I have 4 entity classes that named after the above 4 tables. So if I want to see all the Document in the database, then it is easy. In my SessionBean, I would do this: @PersistenceContext private EntityManager em; List<Document> documents = em.createNamedQuery("Document.findAll").getResultList(); However, that is not all what I need. Let say that I want to know all the Document from a particular Company, or all the Document from a particular Project from a particular Facility from a particular Company. I am very new to JPA + EJB + JSF as a whole. Please help me out.

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  • How to get the value of a ComboBox within a DataGrid

    - by Jason Towne
    While this may be a simple problem, I'm having a heck of a time coming up with a solution. I have a DataGrid with a ComboBox as an ItemRenderer for one of my columns. When the user selects a row, I want to get the ComboBox's selected value for the selected row. Any suggestions? Some sample code: <mx:DataGrid id="myGrid" dataProvider="{myData}"> <mx:columns> <mx:DataGridColumn headerText="Column 1" dataField="dataField1" /> <mx:DataGridColumn headerText="Column 2" dataField="dataField2_Array"> <mx:itemRenderer> <mx:Component> <mx:HBox paddingLeft="5"> <mx:ComboBox id="myComboBox" dataProvider="{data.dataField2_Array}" /> </mx:HBox> </mx:Component> </mx:itemRenderer> </mx:DataGridColumn> </mx:columns> </mx:DataGrid>

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  • PHP / Zend custom date input formats

    - by mld
    Hi, I'm creating a library component for other developers on my team using PHP and Zend. This component needs to be able to take as input a date (string) and another string telling it the format of that date. Looking through the Zend documentation and examples, I thought I found the solution - $dateObject = Zend_Date('13.04.2006', array('date_format' => 'dd.MM.yyyy')); this line, however, throws an error - call to undefined function. So instead I tried this - $dt = Zend_Locale_Format::getDate('13.04.2006', array('date_format' => 'dd.MM.yyyy')); This gets the job done, but throws an error if a date that is entered isn't valid. The docs make it look like you can use the isDate() function to check validity - Zend_Date::isDate('13.04.2006', array('date_format' => 'dd.MM.yyyy')) but this line always returns false. So my questions - Am I going about this the right way? If not, is there a better way to handle this via Zend or straight PHP? If I do use Zend_Locale_Format::getDate(), do I need to worry about a locale being set elsewhere and changing the results of the call? I'm locked into PHP 5.2.6 on windows, btw... so 5.3+ functions & strptime() are out.

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  • JPA - Can an @JoinColumn be an @Id as well? SerializationException occurs.

    - by Shivago
    Hi everyone, I am trying to use an @JoinColumn as an @Id using JPA and I am getting SerializationExceptions, "Could not serialize." UserRole.java: @Entity @Table(name = "authorities") public class UserRole implements Serializable { @Column(name = "authority") private String role; @Id @ManyToOne @JoinColumn(name = "username") private User owner; ... } User.java: @Entity @Table(name = "users") public class User implements Serializable { @Id @GeneratedValue protected Long id; @Column(name = "username") protected String email; @OneToMany(mappedBy = "owner", fetch = FetchType.LAZY, cascade = CascadeType.ALL) protected Set<UserRole> roles = new HashSet<UserRole>(); .... } "username" is set up as a unique index in my Users table but not as the primary key. Is there any way to make "username" act as the ID for UserRole? I don't want to introduce a numeric key in UserRole. Have I totally lost the plot here? I am using MySQL and Hibernate under the hood.

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  • Fluent NHibernate Mappings ClassMap<Entities>....

    - by Pandiya Chendur
    I was going through fluent hibernate getting started tutorial.... In my asp.net mvc web application i have created Entities and Mapping folder as they stated... I created an entity class and i tried to map it my mapping class using this, using System; using System.Collections.Generic; using System.Linq; using System.Web; using FluentNhibernateMVC.Entities; namespace FluentNhibernateMVC.Mappings { public class ClientMap : ClassMap<Client> { } } I cant able to find a ClassMap keyword in my autosuggest list why? This is my entity class using System; using System.Collections.Generic; using System.Linq; using System.Web; namespace FluentNhibernateMVC.Entities { public class Client { public int ClientId { get; set; } public string ClientName { get; set; } public string ClientMobNo { get; set; } public string ClientAddress { get; set; } public DateTime CreatedDate { get; set; } public byte IsDeleted { get; set; } public int CreatedBy { get; set; } } } I have added all references to my project...Am i missing some thing...

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  • Using Enum in Hibernate causes select followed by an update statement

    - by Leonardo
    Hi all, I have a mapped entity wich has an enum property. By loking at log file, whenever I run a select statement on such entity, the result is an immediately following update. For example if my result set contains 100 records, then I have: [INFO org... select...] [INFO org... update... where id=?] [INFO org... update... where id=?] .... repeated 100 times If I mark the property as update=false the problem disappear. The enum is assigned trough an enum converter class, which I copied from a well known book. So I don't know if I just copy and paste the code. Here it is how is declared on hbm file. <typedef class="mypackage.HbnEnumConverter" name="the_type"> <param name="enumClassname">mypackage.TheType</param> </typedef> Can you point out a direction to investigate this ? Beside, what are the consequences of having update=false on hibernate field ? thanks

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  • Struts2 Hibernate Login with User table and group table

    - by J2ME NewBiew
    My problem is, i have a table User and Table Group (this table use to authorization for user - it mean when user belong to a group like admin, they can login into admincp and other user belong to group member, they just only read and write and can not login into admincp) each user maybe belong to many groups and each group has been contain many users and they have relationship are many to many I use hibernate for persistence storage. and struts 2 to handle business logic. When i want to implement login action from Struts2 how can i get value of group member belong to ? to compare with value i want to know? Example I get user from username and password then get group from user class but i dont know how to get value of group user belong to it mean if user belong to Groupid is 1 and in group table , at column adminpermission is 1, that user can login into admincp, otherwise he can't my code: User.java /* * To change this template, choose Tools | Templates * and open the template in the editor. */ package org.dejavu.software.model; import java.io.Serializable; import java.util.Date; import java.util.HashSet; import java.util.Set; import javax.persistence.CascadeType; import javax.persistence.Column; import javax.persistence.Entity; import javax.persistence.FetchType; import javax.persistence.GeneratedValue; import javax.persistence.Id; import javax.persistence.JoinColumn; import javax.persistence.JoinTable; import javax.persistence.ManyToMany; import javax.persistence.Table; import javax.persistence.Temporal; /** * * @author Administrator */ @Entity @Table(name="User") public class User implements Serializable{ private static final long serialVersionUID = 2575677114183358003L; private Long userId; private String username; private String password; private String email; private Date DOB; private String address; private String city; private String country; private String avatar; private Set<Group> groups = new HashSet<Group>(0); @Column(name="dob") @Temporal(javax.persistence.TemporalType.DATE) public Date getDOB() { return DOB; } public void setDOB(Date DOB) { this.DOB = DOB; } @Column(name="address") public String getAddress() { return address; } public void setAddress(String address) { this.address = address; } @Column(name="city") public String getCity() { return city; } public void setCity(String city) { this.city = city; } @Column(name="country") public String getCountry() { return country; } public void setCountry(String country) { this.country = country; } @Column(name="email") public String getEmail() { return email; } public void setEmail(String email) { this.email = email; } @ManyToMany(fetch = FetchType.LAZY, cascade = CascadeType.ALL) @JoinTable(name="usergroup",joinColumns={@JoinColumn(name="userid")},inverseJoinColumns={@JoinColumn( name="groupid")}) public Set<Group> getGroups() { return groups; } public void setGroups(Set<Group> groups) { this.groups = groups; } @Column(name="password") public String getPassword() { return password; } public void setPassword(String password) { this.password = password; } @Id @GeneratedValue @Column(name="iduser") public Long getUserId() { return userId; } public void setUserId(Long userId) { this.userId = userId; } @Column(name="username") public String getUsername() { return username; } public void setUsername(String username) { this.username = username; } @Column(name="avatar") public String getAvatar() { return avatar; } public void setAvatar(String avatar) { this.avatar = avatar; } } Group.java /* * To change this template, choose Tools | Templates * and open the template in the editor. */ package org.dejavu.software.model; import java.io.Serializable; import javax.persistence.Column; import javax.persistence.Entity; import javax.persistence.GeneratedValue; import javax.persistence.Id; import javax.persistence.Table; /** * * @author Administrator */ @Entity @Table(name="Group") public class Group implements Serializable{ private static final long serialVersionUID = -2722005617166945195L; private Long idgroup; private String groupname; private String adminpermission; private String editpermission; private String modpermission; @Column(name="adminpermission") public String getAdminpermission() { return adminpermission; } public void setAdminpermission(String adminpermission) { this.adminpermission = adminpermission; } @Column(name="editpermission") public String getEditpermission() { return editpermission; } public void setEditpermission(String editpermission) { this.editpermission = editpermission; } @Column(name="groupname") public String getGroupname() { return groupname; } public void setGroupname(String groupname) { this.groupname = groupname; } @Id @GeneratedValue @Column (name="idgroup") public Long getIdgroup() { return idgroup; } public void setIdgroup(Long idgroup) { this.idgroup = idgroup; } @Column(name="modpermission") public String getModpermission() { return modpermission; } public void setModpermission(String modpermission) { this.modpermission = modpermission; } } UserDAO /* * To change this template, choose Tools | Templates * and open the template in the editor. */ package org.dejavu.software.dao; import java.util.List; import org.dejavu.software.model.User; import org.dejavu.software.util.HibernateUtil; import org.hibernate.Query; import org.hibernate.Session; /** * * @author Administrator */ public class UserDAO extends HibernateUtil{ public User addUser(User user){ Session session = HibernateUtil.getSessionFactory().getCurrentSession(); session.beginTransaction(); session.save(user); session.getTransaction().commit(); return user; } public List<User> getAllUser(){ Session session = HibernateUtil.getSessionFactory().getCurrentSession(); session.beginTransaction(); List<User> user = null; try { user = session.createQuery("from User").list(); } catch (Exception e) { e.printStackTrace(); session.getTransaction().rollback(); } session.getTransaction().commit(); return user; } public User checkUsernamePassword(String username, String password){ Session session = HibernateUtil.getSessionFactory().getCurrentSession(); session.beginTransaction(); User user = null; try { Query query = session.createQuery("from User where username = :name and password = :password"); query.setString("username", username); query.setString("password", password); user = (User) query.uniqueResult(); } catch (Exception e) { e.printStackTrace(); session.getTransaction().rollback(); } session.getTransaction().commit(); return user; } } AdminLoginAction /* * To change this template, choose Tools | Templates * and open the template in the editor. */ package org.dejavu.software.view; import com.opensymphony.xwork2.ActionSupport; import org.dejavu.software.dao.UserDAO; import org.dejavu.software.model.User; /** * * @author Administrator */ public class AdminLoginAction extends ActionSupport{ private User user; private String username,password; private String role; private UserDAO userDAO; public AdminLoginAction(){ userDAO = new UserDAO(); } @Override public String execute(){ return SUCCESS; } @Override public void validate(){ if(getUsername().length() == 0){ addFieldError("username", "Username is required"); }if(getPassword().length()==0){ addFieldError("password", getText("Password is required")); } } public String getPassword() { return password; } public void setPassword(String password) { this.password = password; } public String getRole() { return role; } public void setRole(String role) { this.role = role; } public User getUser() { return user; } public void setUser(User user) { this.user = user; } public String getUsername() { return username; } public void setUsername(String username) { this.username = username; } } other question. i saw some example about Login, i saw some developers use interceptor, im cant understand why they use it, and what benefit "Interceptor" will be taken for us? Thank You Very Much!

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  • Handling large (object) datasets with PHP

    - by Aron Rotteveel
    I am currently working on a project that extensively relies on the EAV model. Both entities as their attributes are individually represented by a model, sometimes extending other models (or at least, base models). This has worked quite well so far since most areas of the application only rely on filtered sets of entities, and not the entire dataset. Now, however, I need to parse the entire dataset (IE: all entities and all their attributes) in order to provide a sorting/filtering algorithm based on the attributes. The application currently consists of aproximately 2200 entities, each with aproximately 100 attributes. Every entity is represented by a single model (for example Client_Model_Entity) and has a protected property called $_attributes, which is an array of Attribute objects. Each entity object is about 500KB, which results in an incredible load on the server. With 2000 entities, this means a single task would take 1GB of RAM (and a lot of CPU time) in order to work, which is unacceptable. Are there any patterns or common approaches to iterating over such large datasets? Paging is not really an option, since everything has to be taken into account in order to provide the sorting algorithm.

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  • Persist data when the table was not mapped (JPA EclipseLink)

    - by enrique
    Hi everybody I need some help in persisting data into a table that has not been mapped... The issue is that the database we have has a table which all of its columns are foreign keys so by mapping the whole database all of the tables are correctly mapped. However that table called "category" is not mapped. The way in which we can browse the data is by passing for the table I mentioned using the @jointable annotation which was set by the system in the other tables with which "category" has a relation. So we can go ahead and using the collections and perform a query. But the issue comes when I want to persist data into that table because there´s no any entity. We tried to persist through the collections but no luck. Then I have just tried by creating the entity with its PK and Facade all by hand. However when I try to persist using the Merge method the system tries to perform an Insert when it is supposed to perform an Update. So obviously it returns an error. Does anybody have an idea on this situation? Thanks.-

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  • Ruby - Nokogiri - Parsing XML from memory and putting all same name node values into an array.

    - by r3nrut
    I have an XML I'm trying to parse from memory and get the status of each of my heart beat tests using Nokogiri. Here is the solution I have... xml = <a:HBeat> <a:ElapsedTime>3 ms</a:ElapsedTime> <a:Name>Service 1</a:Name> <a:Status>true</a:Status> </a:HBeat> <a:HBeat> <a:ElapsedTime>4 ms</a:ElapsedTime> <a:Name>Service 2</a:Name> <a:Status>true</a:Status> </a:HBeat> <a:HBeat> I have tried using both css and xpath to pull back the value for each Status and put it into an array. Code is below: doc = Nokogiri::XML.parse(xml) #service_state = doc.css("a:HBeat, a:Status", 'a' => 'http://schemas.datacontract.org/2004/07/OpenAPI.Entity').map {|node| node.children.text} service_state = doc.xpath("//*[@a:Status]", 'a' => 'http://schemas.datacontract.org/2004/07/OpenAPI.Entity').map(&:text) Both will return service_state = []. Any thoughts or recommendations? Also, consider that I have almost identical xml for another test and I used the following snippet of code which does exactly what I wanted but for some reason isn't working with the xml that contains namespaces. service_state = doc.css("HBeat Status").map(&:text) Thanks!

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  • issue with vhdl structural coding

    - by user3699982
    The code below is a simple vhdl structural architecture, however, the concurrent assignment to the signal, comb1, is upsetting the simulation with the outputs (tb_lfsr_out) and comb1 becoming undefined. Please, please help, thank you, Louise. library IEEE; use IEEE.STD_LOGIC_1164.all; entity testbench is end testbench; architecture behavioural of testbench is CONSTANT clock_frequency : REAL := 1.0e9; CONSTANT clock_period : REAL := (1.0/clock_frequency)/2.0; signal tb_master_clk, comb1: STD_LOGIC := '0'; signal tb_lfsr_out : std_logic_vector(2 DOWNTO 0) := "111"; component dff port ( q: out STD_LOGIC; d, clk: in STD_LOGIC ); end component; begin -- Clock/Start Conversion Generator tb_master_clk <= (NOT tb_master_clk) AFTER (1 SEC * clock_period); comb1 <= tb_lfsr_out(0) xor tb_lfsr_out(2); dff6: dff port map (tb_lfsr_out(2), tb_lfsr_out(1), tb_master_clk); dff7: dff port map (tb_lfsr_out(1), tb_lfsr_out(0), tb_master_clk); dff8: dff port map (tb_lfsr_out(0), comb1, tb_master_clk); end behavioural;

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