char[] and char* compatibility?
- by Aerovistae
In essence, will this code work? And before you say "Run it and see!", I just realized my cygwin didn't come with gcc and it's currently 40 minutes away from completing reinstallation. That being said:
char* words[1000];
for(int i = 0; i<1000; i++)
words[i] = NULL;
char buffer[ 1024 ];
//omit code that places "ADD splash\0" into the buffer
if(strncmp (buffer, "ADD ", 4){
char* temp = buffer + 4;
printf("Adding: %s", temp);
int i = 0;
while(words[i] != NULL) i++;
words[i] = temp;
}
I'm mostly uncertain about the line char* temp = buffer + 4, and also whether I can assign words[i] in the manner that I am. Am I going to get type errors when I eventually try to compile this in 40 minutes?
Also-- if this works, why don't I need to use malloc() on each element of words[]? Why can I say words[i] = temp, instead of needing to allocate memory for words[i] the length of temp?
