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  • zend framework version trouble

    - by sasori
    Hi, am 100% sure I downloaded and extracted version 1.8 of ZF, but then when I go to console and typed "zf show version" it says am using 1.9.6, yes I do have 1.9.6 but it is "Compressed" and untouched, how could this be possible ?, I double checked my system variables, there's no evidence of ZF there. I also checked my php.ini file, it's pointed to the location of the extracted 1.8 ZF.. please help. this is my first attempt in using ZF

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  • How should I organize my Java GUI?

    - by Spencer
    I'm creating a game in Java for fun and I'm trying to decide how to organize my classes for the GUI. So far, all the classes with only the swing components and layout (no logic) are in a package called "ui". I now need to add listeners (i.e. ActionListener) to components (i.e. button). The listeners need to communicate with the Game class. Currently I have: Game.java - creates the frame add panels to it import javax.swing.; import ui.; public class Game { private JFrame frame; Main main; Rules rules; Game() { rules = new Rules(); frame = new JFrame(); frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); main = new Main(); frame.setContentPane(main.getContentPane()); show(); } void show() { frame.pack(); frame.setLocationRelativeTo(null); frame.setVisible(true); } public static void main(String[] args) { new Game(); } } Rules.java - game logic ui package - all classes create new panels to be swapped out with the main frame's content pane Main.java (Main Menu) - creates a panel with components Where do I now place the functionality for the Main class? In the game class? Separate class? Or is the whole organization wrong? Thanks

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  • Complex orderby question (entity framework)

    - by PFranchise
    Ok, so I will start by saying that I am new to all this stuff, and doing my best to work on this project. I have an employee object, that contains a supervisor field. When someone enters a search on my page, a datagrid displays employees whose name match the search. But, I need it to display all employees that report to them and a third tier of employees that report to the original employee's underlings. I only need three tiers. To make this easier, employees only come in 3 ranks, so if rank==3, that employee is not in charge of others. I imagine the best method of retrieving all these employees from my employee table would be something like from employee in context.employees where employee.name == search || employee.boss.name == search || employee.boss.boss.name == search But I am not sure how to make the orderby appear the way I want to. I need it to display in tiers. So, it will look like: Big Boss Boss underling underling Boss underling Boss Boss Big Boss Like I said, there might be an easier way to approach this whole issue, and if there is, I am all ears. Any advice you can give would be HIGHLY appreciated.

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  • Adding text read from a file to an array list in java

    - by user1824856
    I am having trouble putting text read from a file into an array list. My text looks like this: 438;MIA;JFK;10:55;1092;447 638;JFK;MIA;19:45;1092;447 689;ATL;DFW;12:50;732;448 etc... My code looks like this: package filesexample; import java.io.*; import java.io.FileNotFoundException; import java.util.Scanner; import java.util.ArrayList; /** * * @author */ public class FilesExample { /** * @param args the command line arguments */ public static void main(String[] args) throws IOException { File file = new File ("/Schedule.txt"); try { Scanner scanner= new Scanner(file);; while (scanner.hasNextLine()) { String line = scanner.nextLine(); Scanner lineScanner= new Scanner(line); lineScanner.useDelimiter(";"); while(lineScanner.hasNext()){ String part = lineScanner.next(); System.out.print(part + " "); } System.out.println(); } }catch (FileNotFoundException e){ e.printStackTrace(); } } } Some help on getting started would be much appreciated thank you!

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  • Using OpenID with Zend Framework.

    - by user284503
    I want my website to do exactly what Stackoverflow does with openId. I'm combing through sources, and I have done this before with facebook, but not making much progress with OpenID. What I would like to do is just detect if someone has logged into Google, and if they have get some identifying information, and allow them to federate into my site. Can anyone suggest any tutorials or Code snippets, and should I use Zends Libraries ? -P

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  • Zend Framework - Deny access to folders other than public folder

    - by Vincent
    All, I have the following Zend application structure: helloworld - application - configs - controllers - models - layouts - include - library - public - .htaccess - index.php - design - .htaccess The .htaccess in the root folder has the following contents: ##################################################### # CONFIGURE media caching # Header unset ETag FileETag None Header unset Last-Modified Header set Expires "Fri, 21 Dec 2012 00:00:00 GMT" Header set Cache-Control "max-age=7200, must-revalidate" SetOutputFilter DEFLATE # ##################################################### ErrorDocument 404 /custom404.php RedirectMatch permanent ^/$ /public/ The .htaccess in the public folder has the following: Options -MultiViews ErrorDocument 404 /custom404.php RewriteEngine on # The leading %{DOCUMENT_ROOT} is necessary when used in VirtualHost context RewriteCond %{DOCUMENT_ROOT}%{REQUEST_FILENAME} -s [OR] RewriteCond %{DOCUMENT_ROOT}%{REQUEST_FILENAME} -l [OR] RewriteCond %{DOCUMENT_ROOT}%{REQUEST_FILENAME} -d RewriteRule ^.*$ - [NC,L] RewriteRule ^.*$ index.php [NC,L] My vhost configuration is as under: <VirtualHost *:80> ServerAdmin [email protected] DocumentRoot "C:\\xampp\\htdocs\\xampp\\helloworld\\" ServerName helloworld ServerAlias helloworld <Directory "C:\\xampp\\htdocs\\xampp\\helloworld\\"> Options Indexes FollowSymLinks AllowOverride all Order Deny,Allow Deny from all Allow from 127.0.0.1 </Directory> </VirtualHost> Currently, if the user visits, http://localhost, my .htaccess files above make sure, the request is routed to http://localhost/public automatically. If the user visits any other folder apart from public folder from the address bar, he gets a directory listing of that folder. How can I make sure to deny the user access to every other folder except the public folder? I want the user to be redirected to the public folder if he visits any other folder. However, if the underlying code requests something from other folders, (ex: ) it should still work.. Thanks

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  • SpringMvc java.lang.NullPointerException When Posting Form To Server

    - by dev_darin
    I have a form with a user name field on it when i tab out of the field i use a RESTFUL Web Service that makes a call to a handler method in the controller. The method makes a call to a DAO class that checks the database if the user name exists. This works fine, however when the form is posted to the server i call the same exact function i would call in the handler method however i get a java.lang.NullPointerException when it accesses the class that makes a call to the DAO object. So it does not even access the DAO object the second time. I have exception handlers around the calls in all my classes that makes calls. Any ideas as to whats happening here why i would get the java.lang.NullPointerException the second time the function is called.Does this have anything to do with Spring instantiating DAO classes using a Singleton method or something to that effect? What can be done to resolve this? This is what happens the First Time The Method is called using the Web Service(this is suppose to happen): 13011 [http-8084-2] INFO com.crimetrack.jdbc.JdbcOfficersDAO - Inside jdbcOfficersDAO 13031 [http-8084-2] DEBUG org.springframework.jdbc.core.JdbcTemplate - Executing prepared SQL query 13034 [http-8084-2] DEBUG org.springframework.jdbc.core.JdbcTemplate - Executing prepared SQL statement [SELECT userName FROM crimetrack.tblofficers WHERE userName = ?] 13071 [http-8084-2] DEBUG org.springframework.jdbc.datasource.DataSourceUtils - Fetching JDBC Connection from DataSource 13496 [http-8084-2] DEBUG org.springframework.jdbc.core.StatementCreatorUtils - Setting SQL statement parameter value: column index 1, parameter value [adminz], value class [java.lang.String], SQL type unknown 13534 [http-8084-2] DEBUG org.springframework.jdbc.datasource.DataSourceUtils - Returning JDBC Connection to DataSource 13537 [http-8084-2] INFO com.crimetrack.jdbc.JdbcOfficersDAO - No username was found in exception 13537 [http-8084-2] INFO com.crimetrack.service.ValidateUserNameManager - UserName :adminz does NOT exist The Second time When The Form Is 'Post' and a validation method handles the form and calls the same method the web service would call: 17199 [http-8084-2] INFO com.crimetrack.service.OfficerRegistrationValidation - UserName is not null so going to check if its valid for :adminz 17199 [http-8084-2] INFO com.crimetrack.service.OfficerRegistrationValidation - User Name in try.....catch block is adminz 17199 [http-8084-2] INFO com.crimetrack.service.ValidateUserNameManager - Inside Do UserNameExist about to validate with username : adminz 17199 [http-8084-2] INFO com.crimetrack.service.ValidateUserNameManager - UserName :adminz EXCEPTION OCCURED java.lang.NullPointerException

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  • Is it possible to import specific class from project propreties

    - by Alex
    I have 2 projects. First project need to include second. When I copy sources from second project to first I need to modify manually import path to R.java file. The problem is that I need to use SVN external link connection between this 2 projects, that is mean, one project (the bigger one) will take sources from another through svn and should be able to use it without any modifications. If I would be able to specify R.java file path anywhere in project properties it will resolve my problem by changing manually that path. Need to specify that package name of these 2 projects are different. Another solution to resolve this problem also would be accepted. Thank you.

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  • How to set the session timeout in Zend Framework 2

    - by user2261761
    I don't have much Zend experience and want to change someone's login code in Zend to make the session not expire. It seems the code is basic behavior: $adapter = $this->getAuthService()->getAdapter(); $adapter->setIdentity($email)->setCredential($password); $result = $this->getAuthService()->authenticate(); What do I have to do to make the session not expire or to at least set the session for a specific time? Right now the user doesn't stay logged in for long, I think perhaps it is just relying on default php settings behavior like the standard 24 minutes for the gc_maxlifetime. What is the connection between Zend_Session and AuthService?

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  • How to create relationship mapping via Entity framework

    - by James
    I have following domain model: User { int Id; } City { int Id; } UserCity { int UserId, int CityId, dateTime StartDate } In the function where I have to attach a user to a city, the following code is working for me: UserCity uc = new UserCity(); //This is a db hit uc.User = MyEntityFrameworkDBContext.User.FirstOrDefault(u => u.ID == currentUserId); //this is a db hit uc.City = MyEntityFrameworkDBContext.City.FirstOrDefault(c => c.ID == currentCityId); uc.StartDate = userCityStartDate; //this is a db hit MyEntityFrameworkDBContext.SaveChanges(); Is there any way I can create relationships with just one single DB hit? The first two db hits are not required, actually.

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  • How to load a resource bundle from a file resource in Java?

    - by user143794
    I have a file called mybundle.txt in c:/temp - c:/temp/mybundle.txt how do I load this file into a java.util.resource bundle? The file is a valid resource bundle. This does not seem to work: java.net.URL resourceURL = null; String path = "c:/temp/mybundle.txt"; java.io.File fl = new java.io.File(path); try { resourceURL = fl.toURI().toURL(); } catch (MalformedURLException e) { } URLClassLoader urlLoader = new URLClassLoader(new java.net.URL[]{resourceURL}); java.util.ResourceBundle bundle = java.util.ResourceBundle.getBundle( path , java.util.Locale.getDefault(), urlLoader ); What is the best way to do this?

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  • Entity Framework model and foreign key property

    - by verror
    I have 2 tables that I import to EF model. First table has a property [section] that acts as foreign key to the second table. When I map this property in model to the table and try to compile I get this error: Problem in Mapping Fragments starting at lines 158, 174: Non-Primary-Key column(s) [Section] are being mapped in both fragments to different conceptual side properties - data inconsistency is possible because the corresponding conceptual side properties can be independently modified. If i remove this property from the model it passes, but when I query the data I don't have the section field. I know that I can get it by using the navigation field and reading this property from the second table, but to make it work I must include the other table in my query. var res = from name in Context.Table1.Include("Table2")... Why do I need to include the association just for one field?

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  • How does a java compiler resolve a non-imported name

    - by gexicide
    Consider I use a type X in my java compilation unit from package foo.bar and X is not defined in the compilation unit itself nor is it directly imported. How does a java compiler resolve X now efficiently? There are a few possibilities where X could reside: X might be imported via a star import a.b.* X might reside in the same package as the compilation unit X might be a language type, i.e. reside in java.lang The problem I see is especially (2.). Since X might be a package-private type, it is not even required that X resides in a compilation unit that is named X.java. Thus, the compiler must look into all entries of the class path and search for any classes in a package foo.bar, it then must read every class that is in package foo.bar to check whether X is included. That sounds very expensive. Especially when I compile only a single file, the compiler has to read dozens of class files only to find a type X. If I use a lot of star imports, this procedure has to be repeated for a lot of types (although class files won't be read twice, of course). So is it advisable to import also types from the same package to speed up the compilation process? Or is there a faster method for resolving an unimported type X which I was not able to find?

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  • .NET port with Java's Map, Set, HashMap

    - by Nikos Baxevanis
    I am porting Java code in .NET and I am stuck in the following lines that (behave unexpectedly in .NET). Java: Map<Set<State>, Set<State>> sets = new HashMap<Set<State>, Set<State>>(); Set<State> p = new HashSet<State>(); if (!sets.containsKey(p)) { ... } The equivalent .NET code could possibly be: IDictionary<HashSet<State>, HashSet<State>> sets = new Dictionary<HashSet<State>, HashSet<State>>(); HashSet<State> p = new HashSet<State>(); if (!sets.containsKey(p)) { /* (Add to a list). Always get here in .NET (??) */ } However the code comparison fails, the program think that "sets" never contain Key "p" and eventually results in OutOfMemoryException. Perhaps I am missing something, object equality and identity might be different between Java and .NET. I tried implementing IComparable and IEquatable in class State but the results were the same. Edit: What the code does is: If the sets does not contain key "p" (which is a HashSet) it is going to add "p" at the end of a LinkedList. The State class (Java) is a simple class defined as: public class State implements Comparable<State> { boolean accept; Set<Transition> transitions; int number; int id; static int next_id; public State() { resetTransitions(); id = next_id++; } // ... public int compareTo(State s) { return s.id - id; } public boolean equals(Object obj) { return super.equals(obj); } public int hashCode() { return super.hashCode(); }

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  • Java Newbie can't do simple Math, operator error

    - by elguapo-85
    Trying to do some really basic math here, but my lack of understanding of Java is causing some problems for me. double[][] handProbability = new double[][] {{0,0,0},{0,0,0},{0,0,0}}; double[] handProbabilityTotal = new double[] {0,0,0}; double positivePot = 0; double negativePot = 0; int localAhead = 0; int localTied = 1; int localBehind = 2; //do some stuff that adds values to handProbability and handProbabilityTotal positivePot = (handProbability[localBehind][localAhead] + (handProbability[localBehind][localTied] / 2.0) + (handProbability[localTied][localAhead] / 2.0) ) / (handProbabilityTotal[localBehind] + (handProbability[localTied] / 2.0)); negativePot = (handProbability[localAhead][localBehind] + (handProbability[localAhead][localTied] / 2.0) + (handProbability[localTied][localBehind] / 2.0) ) / (handProbabilityTotal[localAhead] + (handProbabilityTotal[localTied] / 2.0)); The last two lines are giving me problems (sorry for their lengthiness). Compiler Errors: src/MyPokerClient/MyPokerClient.java:180: operator / cannot be applied to double[],double positivePot = ( handProbability[localBehind][localAhead] + (handProbability[localBehind][localTied] / 2.0) + (handProbability[localTied][localAhead] / 2.0) ) / (handProbabilityTotal[localBehind] + (handProbability[localTied] / 2.0) ); ^ src/MyPokerClient/MyPokerClient.java:180: operator + cannot be applied to double, positivePot = ( handProbability[localBehind][localAhead] + (handProbability[localBehind][localTied] / 2.0) + (handProbability[localTied][localAhead] / 2.0) ) / (handProbabilityTotal[localBehind] + (handProbability[localTied] / 2.0) ); ^ src/MyPokerClient/MyPokerClient.java:180: operator / cannot be applied to double, positivePot = ( handProbability[localBehind][localAhead] + (handProbability[localBehind][localTied] / 2.0) + (handProbability[localTied][localAhead] / 2.0) ) / (handProbabilityTotal[localBehind] + (handProbability[localTied] / 2.0) ); Not really sure what the problem is. You shouldn't need anything special for basic math, right?

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  • Zend Framework Db Select Join table help

    - by tester2001
    I have this query: SELECT g.title, g.asin, g.platform_id, r.rank FROM games g INNER JOIN ranks r ON ( g.id = r.game_id ) ORDER BY r.rank DESC LIMIT 5` Now, this is my JOIN using Zend_Db_Select but it gives me array error $query = $this-select(); $query-from(array('g' = 'games'), array()); $query-join(array('r' = 'ranks'), 'g.id = r.game_id', array('g.title', 'g.asin', 'g.platform_id', 'r.rank')); $query-order('r.rank DESC'); $query-limit($top); $resultRows = $this-fetchAll($query); return $resultRows; Anyone know what I could be doing wrong? I want to get all the columns in 'games' to show and the 'rank' column in the ranks table.

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  • Spring Framework HttpRequestHandler failure

    - by sharadva
    We have an application which communicates via REST requests made by clients. The REST requests contain "region name" and a "ID" as parameters So, a request would look something like this (for a DELETE) http://host:port/regionnameID These REST requests between regions in a federation are properly URL encoded I find that these request fail if the region name has a slash ("/") in it. Then, the request would look like so http://host:port/region/nameID This is due to incorrect interpretation of the Rest URL by HttpRequesthandler when there is a '/' in the region name. Now, we have no control over clients sending REST request with "/" in the Region name. Is there any method / configuration / workaround that can be done to prevent the HttpRequestHandler from returning 404

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  • Comparison of Java and .NET technologies/frameworks

    - by Paul Sasik
    I work in a shop that is a mix of mostly Java and .NET technologists. When discussing new solutions and architectures we often encounter impedance in trying to compare the various technologies, frameworks, APIs etc. in use between the two camps. It seems that each camp knows little about the other and we end up comparing apples to oranges and forgetting about the bushels. While researching the topic I found this: Java -- .Net rough equivalents It's a nice list but it's not quite exhaustive and is missing the key .NET 3.0 technologies and a few other tidbits. To complete that list: what are the near/rough equivalents (or a combination of technologies) in Java to the following in .NET? WCF WPF Silverlight = JavaFx WF = jBMP (Java Business Process Management) Generics Lambda expressions = lambdaJ project or Closures Linq (not Linq-to-SQL) ...have i missed anything else? Note that I omitted technologies that are already covered in the linked article. I would also like to hear feedback on whether the linked article is accurate. Thanks. (Will CW if requested.)

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  • How can I execute a Java program within a php script?

    - by user450775
    I am writing a simple web upload script. The goal is to upload a file using php, and then calling a java program to process this file. I have done the work for uploading the file, but I cannot get a java program to be successfully run from within the php script. I have tried exec(), shell_exec(), and system() with no results. For the command, I have used "java Test", "java < directory /Test", "/usr/bin/java < directory /Test", I have even set up the application as a jar file with no results. The actual line of code I have used is: echo shell_exec("java Test"); Usually there is no output. However, if I have just shell_exec("java"), then the last line of the help from java ("show splash screen with specified image") is displayed, which shows that the command has been executed. If I use, for example, shell_exec("whoami") I get "nobody" returned, which is correct. The only thing the java file does is create a file so that I can see that the application has been successfully run (the application runs successfully if I run it on the command line). I have set the permissions for the java file to 777 to rule out any possibility of permission errors. I have been struggling with this for a while trying all sorts of options with no results - the file is never created (the file is created with an absolute path so it's not being created and I just can't find the file). Does anyone have any ideas? Thanks.

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  • Delete database. Entity Framework

    - by Idotz
    I have a very annoying issue and I would love a solution. The problem: I followed the MDSN tutorial- http://www.asp.net/mvc/tutorials/mvc-4/getting-started-with-aspnet-mvc4/adding-a-model Then I tried this guide according to my needs and I set up a database GAMES.MDF.   Then, I deleted the database and set it up again, is supposedly work (I can write and read data), but There is no such database in the APP_DATA folder. Like it keeps it somewhere in my PC and reuse it.   I even tried a new project and it did not work, works but not in the library, and it even uses the data I created before. I even deleted the DB from SQL Server Management Studio 2008. Does anyone know what the hell? How do I delete it permanently, not to remain any trace of him?   Thank you.  Ido

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  • peoblem with download file on zend framework

    - by user1400
    hello all i am using upload files to server in my application, it works fine , i want other users could download these file ,but i get error i created a upload folder in public folder and i upload my files in upload folder now when i create a link (<a href="http://mytest/public/1.jpg">download image</a>) to these files i get error "The requested URL /public/upload/1.jpg was not found on this server." how should i use routing for download these files? someone may help please thanks

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