Search Results

Search found 58168 results on 2327 pages for 'mysql real escape string'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 217/2327 | < Previous Page | 213 214 215 216 217 218 219 220 221 222 223 224  | Next Page >

  • mySQL - How to select a date interval

    - by fabriciols
    Hello, this is my table : ------------------------------------- | user | item | date_time | | 10 | 01 | 10-10-10 20:10:05 | | 10 | 02 | 10-10-10 20:10:10 | | 10 | 03 | 10-10-10 20:10:10 | | 20 | 02 | 10-10-10 20:15:10 | | 20 | 02 | 10-10-10 20:20:10 | | 30 | 10 | 10-10-10 20:01:10 | | 30 | 20 | 10-10-10 20:01:20 | | 30 | 30 | 10-10-10 20:05:20 | ------------------------------------- i want to do a query that return a user that took multiple items in a 1min interval, like this result : ------------------------------------- | user | item | date_time | | 10 | 01 | 10-10-10 20:10:05 | | 10 | 02 | 10-10-10 20:10:10 | | 10 | 03 | 10-10-10 20:10:10 | | 30 | 10 | 10-10-10 20:01:10 | | 30 | 20 | 10-10-10 20:01:20 | ------------------------------------- how i do this ?

    Read the article

  • Mysql SELECT nested query, very complicated?

    - by smartbear
    Okay, first following are my tables: Table house: id | items_id | 1 | 1,5,10,20 | Table items: id | room_name | refer 1 | kitchen | 3 5 | room1 | 10 Table kitchen: id | detail_name | refer 3 | spoon | 4 5 | fork | 10 Table spoon: id | name | color | price | quantity_available | 4 | spoon_a | white | 50 | 100 | 5 | spoon_b | black | 30 | 200 | How to do a nested select statement, where I want to select id, name, color, price and quantity_available column, from the each value inside the 'items_id' column in 'house' table? This is very challenging!! EDIT: after read robin's answer Table house: id | items_id | house1 | 1 | house1 | 5 | house1 | 10 | house2 | 20 | If this it the house table, how to do the nested, join, or whatever select statement??

    Read the article

  • MySQL top count({column}) with a limit

    - by Josh K
    I have a table with an ip address column. I would like to find the top five addresses which are listed. Right now I'm planning it out the following: Select all distinct ip addresses Loop through them all saying count(id) where IP='{ip}' and storing the count List the top five counts. Downsides include what if I have 500 ip addresses. That's 500 queries I have to run to figure out what are the top five. I'd like to build a query like so select ip from table where 1 order by count({distinct ip}) asc limit 5

    Read the article

  • MySQL and Collation

    - by user294787
    I have a table with a column using utf8_unicode_ci character set. This table stores Japanese data and my problem is that using this character set, I'm not able to store the same word written in katakana and hiragana because it's considered to be the same word. For example ??? and ???, which mean I, me. I know that I can change the character set to utf8_general_ci to resolve this problem but is it possible to bypass this limitation ? I mean, keep utf8_unicode_ci character set and make those two words be inserted? Is it possible to make this work using CONVERT or CAST operators? Thanks.

    Read the article

  • Search Multiple Tables of a Mysql Database

    - by DogPooOnYourShoe
    I have the following code: $query = "select * from customer where Surname like \"%$trimmed%\" OR TitleName like \"%$trimmed%\" OR PostCode like \"%$trimmed%\" order by Surname"; However, I have another table which I want to search from with the same paramaters(variables) as that. I know that something like "select * from customer,othertable" might not be possible, Is there a way to do it?

    Read the article

  • MySQL MyISAM table performance... painfully, painfully slow

    - by Salman A
    I've got a table structure that can be summarized as follows: pagegroup * pagegroupid * name has 3600 rows page * pageid * pagegroupid * data references pagegroup; has 10000 rows; can have anything between 1-700 rows per pagegroup; the data column is of type mediumtext and the column contains 100k - 200kbytes data per row userdata * userdataid * pageid * column1 * column2 * column9 references page; has about 300,000 rows; can have about 1-50 rows per page The above structure is pretty straight forwad, the problem is that that a join from userdata to page group is terribly, terribly slow even though I have indexed all columns that should be indexed. The time needed to run a query for such a join (userdata inner_join page inner_join pagegroup) exceeds 3 minutes. This is terribly slow considering the fact that I am not selecting the data column at all. Example of the query that takes too long: SELECT userdata.column1, pagegroup.name FROM userdata INNER JOIN page USING( pageid ) INNER JOIN pagegroup USING( pagegroupid ) Please help by explaining why does it take so long and what can i do to make it faster. Edit #1 Explain returns following gibberish: id select_type table type possible_keys key key_len ref rows Extra 1 SIMPLE userdata ALL pageid 372420 1 SIMPLE page eq_ref PRIMARY,pagegroupid PRIMARY 4 topsecret.userdata.pageid 1 1 SIMPLE pagegroup eq_ref PRIMARY PRIMARY 4 topsecret.page.pagegroupid 1 Edit #2 SELECT u.field2, p.pageid FROM userdata u INNER JOIN page p ON u.pageid = p.pageid; /* 0.07 sec execution, 6.05 sec fecth */ id select_type table type possible_keys key key_len ref rows Extra 1 SIMPLE u ALL pageid 372420 1 SIMPLE p eq_ref PRIMARY PRIMARY 4 topsecret.u.pageid 1 Using index SELECT p.pageid, g.pagegroupid FROM page p INNER JOIN pagegroup g ON p.pagegroupid = g.pagegroupid; /* 9.37 sec execution, 60.0 sec fetch */ id select_type table type possible_keys key key_len ref rows Extra 1 SIMPLE g index PRIMARY PRIMARY 4 3646 Using index 1 SIMPLE p ref pagegroupid pagegroupid 5 topsecret.g.pagegroupid 3 Using where Moral of the story Keep medium/long text columns in a separate table if you run into performance problems such as this one.

    Read the article

  • using joins or multiple queries in php/mysql

    - by askkirati
    Here i need help with joins. I have two tables say articles and users. while displaying articles i need to display also the user info like username, etc. So will it be better if i just use joins to join the articles and user tables to fetch the user info while displaying articles like below. SELECT a.*,u.username,u.id FROM articles a JOIN users u ON u.id=a.user_id OR can this one in php. First i get the articles with below sql SELECT * FROM articles Then after i get the articles array i loop though it and get the user info inside each loop like below SELECT username, id FROM users WHERE id='".$articles->user_id."'; Which is better can i have explanation on why too. Thank you for any reply or views

    Read the article

  • Deferring frequent updates in MySQL

    - by cdecker
    I have frequent updates to a user table that simply sets the last seen time of a user, and I was wondering whether there is a simple way to defer them and group them into a single query after a short timeout (5 minutes or so). This would reduce queries on my user database quite a lot.

    Read the article

  • Simple javascript string problem in ie6 and ie7

    - by Jeff Lamb
    I have a very simple function that takes a list of comma separated (x,y) points and imports them into a graph. I have FF, Chrome and IE8 installed. I use IETester to test for IE6 and IE7. // Import Data this.Import = function(data) { alert("Data in: "+data); var d; // Make sure the first and the last are start/ending parenthesis if ( (data[0] != '(') || (data[data.length-1] != ')') ) { alert("After if: "+data[0]+" "+data[data.length-1]); return false; } ... In Chrome, FF and IE8, I don't see the "After if:" alert. In IE6 and IE7, I see the following two alerts: Data in: (52,16),(100,90) After if: undefined undefined The "Data in" alert matches in all browsers. Any ideas?

    Read the article

  • Simple MySQL Query taking 45 seconds (Gets a record and its "latest" child record)

    - by Brian Lacy
    I have a query which gets a customer and the latest transaction for that customer. Currently this query takes over 45 seconds for 1000 records. This is especially problematic because the script itself may need to be executed as frequently as once per minute! I believe using subqueries may be the answer, but I've had trouble constructing it to actually give me the results I need. SELECT customer.CustID, customer.leadid, customer.Email, customer.FirstName, customer.LastName, transaction.*, MAX(transaction.TransDate) AS LastTransDate FROM customer INNER JOIN transaction ON transaction.CustID = customer.CustID WHERE customer.Email = '".$email."' GROUP BY customer.CustID ORDER BY LastTransDate LIMIT 1000 I really need to get this figured out ASAP. Any help would be greatly appreciated!

    Read the article

  • MySQL optimized sentence

    - by Ivan
    I have a simple table where I have to extract some records. The problem is that the evaluation function is a very time-consuming stored procedure so I shouldn't to call it twice like in this sentence: SELECT *, slow_sp(row) FROM table WHERE slow_sp(row)>0 ORDER BY dist DESC LIMIT 10 First I thought in optimize like this: SELECT *, slow_sp(row) AS value FROM table WHERE value>0 ORDER BY dist DESC LIMIT 10 But it doesn't works due "value" is not processed when the WHERE clause is evaluated. Any idea to optimize this sentence? Thanks.

    Read the article

  • Getting mysql row that doesn't conflict with another row

    - by user939951
    I have two tables that link together through an id one is "submit_moderate" and one is "submit_post" The "submit_moderate" table looks like this id moderated_by post 1 James 60 2 Alice 32 3 Tim 18 4 Michael 60 Im using a simple query to get data from the "submit_post" table according to the "submit_moderate" table. $get_posts = mysql_query("SELECT * FROM submit_moderate WHERE moderated_by!='$user'"); $user is the person who is signed in. Now my problem is when I run this query, with the user 'Michael' it will retrieve this 1 James 60 2 Alice 32 3 Tim 18 Now technically this is correct however I don't want to retrieve the first row because 60 is associated with Michael as well as James. Basically I don't want to retrieve that value '60'. I know why this is happening however I can't figure out how to do this. I appreciate any hints or advice I can get.

    Read the article

  • Are default mysql parameters in RDS sane?

    - by taw
    RDS uses the same set of parameters for all instance sizes and they don't seem to be that far from defaults (max_packet_size being too small etc.) Has anyone looked at them and reviewed them for how sensible they are, especially on relatively bigger instances?

    Read the article

  • mysql view performance

    - by vamsivanka
    I have a table for about 100,000 users in it. First Case: explain select * from users where state = 'ca' when i do an explain plan for the above query i got the cost as 5200 Second Case: Create or replace view vw_users as select * from users Explain select * from vw_users where state = 'ca' when i do an explain plan on the second query i got the cost as 100,000. How does the where clause in the view work ?? Is the where clause applied after the view retrieves all the rows. Please let know, how can i fix this issue. Thanks

    Read the article

  • Single specific string replace method Objective C

    - by Sam
    Hi guys, I wanted to know if theres a single method or way that will help me replace strings for specific characters. like MALE - M FEMALE - F CHILD - P The longer way out is this.. [str stringByreplacingOccurencesOfString:@"MALE" withString:@"M"]; [str stringByreplacingOccurencesOfString:@"FEMALE" withString:@"F"]; [str stringByreplacingOccurencesOfString:@"CHILD" withString:@"P"]; I was wondering if theres another way in which i can reduce lines of code here, specially when there are alots of things to replace. thanks. this is for iPhone OS.

    Read the article

  • Seeting up MySQL database

    - by mathew
    I do have single database and near about 11 tables. while my web page is opening informations from these 11 tables will be accessed same time. according to my current settings what I did now is for each table database is opening and closing. say I had given username and password to open databse for each table and close after retrieving information from that table. Is this the right way to do it?? I feel because of this the database is opeing and closing 11 times!!!! Am I right?? is this the right way to do that?? THanks Mathew

    Read the article

  • Many-to-Many Relationships in MySQL

    - by Kaji
    I've been reading up on foreign keys and joins recently, and have been pleasantly surprised that many of the basic concepts are things I'm already putting into practice. For example, with one project I'm currently working on, I'm organizing word lists, and have a table for the sets, like so: `words` Table `word_id` `headword` `category_id` `categories` Table `category_id` `category_name` Now, generally speaking this would be a one-to-many relationship, with several words being placed under a single category with the foreign key category_id. Let's assume for a moment, however, that a user chooses to add another category to a word, making it many-to-many—Is there a way to set up my words table to handle additional categories for words without creating extra columns like category_2, category_3, etc.?

    Read the article

  • mysql table marked as crashed

    - by Phil Jackson
    I recently created a ajax based instant messaging application and after running for a while I got an error [table] is marked as crashed and should be repaired. How could this have happened and how do I go about preventing it happening again?

    Read the article

  • Trim function in C, to trim in place (without returning the string)

    - by user364100
    I can't figure out what to do to make this work. Here's my code: char* testStr = " trim this "; char** pTestStr = &testStr; trim(pTestStr); int trim(char** pStr) { char* str = *pStr; while(isspace(*str)) { (*pStr)++; str++; } if(*str == 0) { return 0; } char *end = str + strlen(str) - 1; while(end > str && isspace(*end)) end--; *(end+1) = 0; return 0; } I get an access violation on *(end+1) = 0;, but I can't declare my testStr[] as such to avoid that, because I can't pass the pointers that way. Any ideas?

    Read the article

  • How to join mysql tables

    - by Ivan
    I've an old table like this: user> id | name | address | comments And now I've to create an "alias" table to allow some users to have an alias name for some reasons. I've created a new table 'user_alias' like this: user_alias> name | user But now I have a problem due my poor SQL level... How to join both tables to generate something like this: 1 | my_name | my_address | my_comments 1 | my_alias | my_address | my_comments 2 | other_name | other_address | other_comments I mean, I want to make a "SELECT..." query that returns in the same format as the "user" table ALL users and ALL alias.. Something like this: SELECT user.* FROM user LEFT JOIN user_alias ON `user`=`id` but it doesn't work for me..

    Read the article

  • MySQL DUMP as CSV

    - by swt83
    I've looked around and nothing seems to work: $file = '/path/to/file.csv'; $cmd = 'mysqldump DATABASE TABLE > '.$file.' --host=localhost --user=USER --password=PASS'; $cmd .= ' --lock-tables=false --no-create-info --tab=/tmp --fields-terminated-by=\',\''; exec($cmd); Everything I try creates an empty CSV file. Any ideas? Thanks much.

    Read the article

  • Ruby delete method (string manipulation)

    - by brianheys
    I'm new to Ruby, and have been working my way through Mr Neighborly's Humble Little Ruby Guide. There have been a few typos in the code examples along the way, but I've always managed to work out what's wrong and subsequently fix it - until now! This is really basic, but I can't get the following example to work on Mac OS X (Snow Leopard): gone = "Got gone fool!" puts "Original: " + gone gone.delete!("o", "r-v") puts "deleted: " + gone Output I'm expecting is: Original: Got gone fool! deleted: G gne fl! Output I actually get is: Original: Got gone fool! deleted: Got gone fool! The delete! method doesn't seem to have had any effect. Can anyone shed any light on what's going wrong here? :-\

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 213 214 215 216 217 218 219 220 221 222 223 224  | Next Page >