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  • Json request with Javascript

    - by chota
    Hi, I am just beginner on java script and JSON and never had done any work in these before. My employer has just asked me to create the basic POC of these. Scenario: I have a REST API and when i call it, it returns back response in JSON format. Need to To: Create a HTML page and use javascript to call that REST API and capture JSON response and print in the same HTML page. <script type="text/javascript"> function loadMe() { loadJSON('http://myrestAPI'); } function loadJSON(url) { //Help me here to capture the response and print in html page. } </script> I would appreciate your help. This might be simple, but for me i have no idea because i never have done anything similar in java script and json. I goggled but could not find anything. Thanks, chota

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  • Why is this Python class copying another class contents?

    - by fjfnaranjo
    Hello guys. I'm trying to understand an estrange behavior in Python. I have the next python code: class IntContainer: listOfInts = [] def __init__(self, initListOfInts): for i in initListOfInts: self.listOfInts.append(i) def printInts(self): print self.listOfInts if __name__ == "__main__": intsGroup1 = [1,2,3,4] intsGroup2 = [4,5,6,7] intsGroups = [intsGroup1,intsGroup2] intsContainers = [] for ig in intsGroups: newIntContainer = IntContainer(ig) intsContainers.append(newIntContainer) for ic in intsContainers: print ic.listOfInts I expect to get something like: [1, 2, 3, 4] [4, 5, 6, 7] But i get: [1, 2, 3, 4, 4, 5, 6, 7] [1, 2, 3, 4, 4, 5, 6, 7] I have check the next question: http://stackoverflow.com/questions/1876905/why-is-python-reusing-a-class-instance-inside-in-function And a lot of Python reference, but I can not understand what is happening. I think is related with the newIntContainer identifier reutilization, but I do not understand it deeply. Why Python appears to reused the last reference for the new object, even if I have added it to a permanent list? What can I do to resolve this behavior? Thanks ;)

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  • Alternative to css3 not selector

    - by Raynos
    Are there any alternatives to the :not css3 selector that are compliant with IE8 (and quirks mode). Either in css or javascript/jquery that emulates the selector or something similar. I am using *:not as follows below. Feel free to recommend a solution that avoids the use of :not completely. @media screen { #printable { visibility: hidden; } } @media print { *:not(#printable) { visibility: hidden; } #printable { position: absolute; visibility: visible; } } Note that the use of :not is tied to the use of @media print so just using a simple jQuery solution to apply css to $(":not(#printable)") won't work without being clever. Including an entire library like ie9.js or selectivirz isn't an option as it can effect various other parts of the pages and would involve a large section of re-testing. a jsfiddle that shows it working in browsers that support :not http://jsfiddle.net/Raynos/TjKbz/

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  • How to write a list to a text file in the correct format

    - by lia1000
    I've got this piece of code that I want to write the output to a text file but with the correct format i.e. no brackets, single quotes so it appears as a formatted list. This is the code: file = open("env5.txt", "w"); for key in os.environ.keys(): env = os.environ[key]; key1 = key; list = str([key, env]).replace("'","").replace('[]', ''); list2 = list[1:-1]; print(list2); file.writelines(list2); file.close(); This is the original code: for key in os.environ.keys(): print(key, os.environ[key]); Many thanks

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  • Parse and Break: why break cannot be used for getting out of "any" or "some" rule ?

    - by Rebol Tutorial
    Let say I have to parse a hierarchical set of tags <tag> <subtag1 attr1=value1 attr2=value2> <subtag1 attr1=value1 attr2=value2> <subtag1 attr1=value1 attr2=value2> </tag> Why can't I use break inside some or any to get out of a level hierarchy ? This would allow to do that kind of parsing instead of having a headache to do so ? I'm asking this because I read here http://www.codeconscious.com/rebol/parse-tutorial.html it would create an infinite loop This case produces an infinite loop. Because the BREAK is within a sub-rule of the rule that SOME is processing. The BREAK does not affect success/failure status or the input pointer - it just exits a rule early: rule-to-break: [(print "Break") break] == [(print "Break") break] parse "X" [some [rule-to-break] "X"] Break *Break* ... Break *Break*(escape)

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  • Debugging (displaying) SQL command sent to the db by SQLAlchemy

    - by morpheous
    I have an ORM class called Person, which wraps around a person table: After setting up the connection to the db etc, I run the ff statement. people = session.query(Person).all() The person table does not contain any data (as yet), so when I print the variable people, I get an empty list. I renamed the table referred to in my ORM class People, to people_foo (which does not exist). I then run the script again. I was surprised that no exception was thrown when attempting to access a table that does not exist. I therefore have the following 2 questions: How may I setup SQLAlchemy so that it propagates db errors back to the script? How may I view (i.e. print) the SQL that is being sent to the db engine If it helps, I am using PostgreSQL as the db

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  • C++ new line not translating

    - by m3n
    First off, I'm a complete beginner at C++. I'm coding something using an API, and would like to pass text containing new lines to it, and have it print out the new lines at the other end. If I hardcode whatever I want it to print out, like so printInApp("Hello\nWorld"); it does come out as separate lines in the other end, but if I retrieve the text from the app using a method that returns a const char then pass it straight to printInApp (which takes const char as argument), it comes out as a single line. Why's this and how would I go about to fix it?

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  • Resetting a while loop

    - by Patrick Beardmore
    I have found a confusing thing in a php script I am writing to generate some javascript. Here it is below, slightly simplified. The second while loop won't run unless I comment out the entire first while loop. Can anyone explain why? Many thanks. <?php $listid = 2; //DEMO ONLY $result1 = mysql_query("SELECT words.wid,words.wordmd5,words.word FROM words,instances WHERE words.wid = instances.wid AND instances.lid = \"$listid\""); $result1copy = $result1; $count1 = 1; while( $row = mysql_fetch_object( $result1 ) ) { print "words_left[$count1] = \"".$row->word."\";\n"; //Increment the array counter (starts at 1) $count1++; } ?> //Some javascript <?php $count2 = 1; while( $row = mysql_fetch_object( $result1copy ) ) { print " $count2 then $row->wordmd5 "; $count2++; } ?>

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  • Second largest number in list python

    - by Manu Lakaster
    So I have to find THE SECOND LARGEST NUMBER IN A LIST. I am doing it through simple loops.My approach is I am going to divide a list into two parts and then find the largest number into two parts and then compare two nuumbers. I will choose the smaller number from two of them. I can not use ready functions or different approaches. Basically, this is my code....But it does not run correctly....Help me please to fix it because I spent a lot of time on it :( Thanks....P.S. Can we use indices to "divide" a list ??? #!/usr/local/bin/python2.7 alist=[-45,0,3,10,90,5,-2,4,18,45,100,1,-266,706] largest=alist[0] h=len(alist)/2 m=len(alist)-h print(alist) for i in alist: if alist[h]>largest: largest=alist[h] i=i+1 print(largest)

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  • Why is Python 3.1 throwing a SyntaxError when printing after loop?

    - by bubersson
    Hi, I'm trying to run this snippet in Python 3.1 console and I'm getting SyntaxError: >>> while True: ... a=5 ... if a<6: ... break ... print("hello") File "<stdin>", line 5 print("hello") ^ SyntaxError: invalid syntax >>> (This is just shortened code to make a point.) Am I missing something? Is there some other Magic I don't know about? Thanks for your help (since this is my first StackOverflow question and I'm not a native English speaker)

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  • TCP Scanner Python MultiThreaded

    - by user1473508
    I'm trying to build a small tcp scanner for a netmask. The code is as follow: import socket,sys,re,struct from socket import * host = sys.argv[1] def RunScanner(host): s = socket(AF_INET, SOCK_STREAM) s.connect((host,80)) s.settimeout(0.1) String = "GET / HTTP/1.0" s.send(String) data = s.recv(1024) if data: print "host: %s have port 80 open"%(host) Slash = re.search("/", str(host)) if Slash : netR,_,Wholemask = host.partition('/') Wholemask = int(Wholemask) netR = struct.unpack("!L",inet_aton(netR))[0] for host in (inet_ntoa(struct.pack("!L", netR+n)) for n in range(0, 1<<32-Wholemask)): try: print "Doing host",host RunScanner(host) except: pass else: RunScanner(host) To launch : python script.py 10.50.23.0/24 The problem I'm having is that even with a ridiculous low settimeout value set, it takes ages to cover the 255 ip addresses since most of them are not assigned to a machine. How can i make a way faster scanner that wont get stuck if the port is close.MultiThreading ? Thanks !

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  • Regular Expression Program

    - by david robers
    Hi I have the following text: SMWABCCA ABCCAEZZRHM NABCCAYJG XABCCA ABCCADK ABCCASKIYRH ABCCAKY PQABCCAK ABCCAKQ This method takes a regex in out by the user and SHOULD print out the Strings it applies to but seems to print out something completely different: private void matchIt(String regex) { Pattern p = Pattern.compile(regex); Matcher m = null; boolean found = false; for(int i = 0; i < data.length; i++){ m = p.matcher(data[i]); if(m.find()){ out.println(data[i]); found = true; } } if(!found){ out.println("Pattern Not Found"); } } When inputting "[C]" It outputs: SMWABCCA ABCCAEZZRHM NABCCAYJG XABCCA ABCCADK ABCCASKIYRH ABCCAKY PQABCCAK ABCCAKQ Any ideas why? I think I'm using m.find() improperly...

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  • remove the spaces...

    - by tekknolagi
    !/usr/bin/python import random lower_a = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z'] upper_a = ['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'] num = ['0', '1', '2', '3', '4', '5', '6', '7', '8', '9'] all = [] all = " ".join("".join(lower_a) + "".join(upper_a) + "".join(num)) all = all.split() x = 0 while x < 10: for i in range(7): a = random.choice(all) print a, print x += 1 what i want to do is remove the spaces from the output what it gives now is Z 3 a A I K R G B i N 9 c E v g E r A N 8 e B 6 d v H O c a V 8 c x y b g 2 W a T T f 8 H T r 6 E p D K l 5 p u x q 8 P Z 9 T n I W X n B Q

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  • Python: Give a class its own `self` at instantiation time

    - by SuperDisk
    I've got a button class that you can instantiate like so: engine.createElement((0, 0), Button(code=print, args=("Stuff!",))) And when it is clicked it will print "Stuff!". However, I need the button to destroy itself whenever it is clicked. Something like this: engine.createElement((0, 0), Button(code=engine.killElement, args=(self,))) However, that would just kill the caller, because self refers to the caller at that moment. What I need to do is give the class its own 'self' in advance... I thought of just making the string 'self' refer to the self variable upon click, but what if I wanted to use the string 'self' in the arguments? What is the way to do this? Is my architecture all wrong or something? Thanks.

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  • Check and avoid if a char is being entered in a int

    - by John
    Hi.... This is a exremely stupid question but i need help with this.... I'm trying to make a small program that i made robust and needed some help with tht.... int num1; int num2 = 0; System.out.print("Enter number 1: "); num1 = kb.nextInt(); while(num2<num1) { System.out.print("Enter number 2: "); num2 = kb.nextInt(); } Number 2 has to be greater than number 1 Also i want the program to automatically check and ignore if the user enters a char instead of an int... Cause right now when a user enters lets say "r" instead of a number the program just exists....

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  • Why does Visual Studio 2008 try to open a project from the wrong folder?

    - by Rising Star
    I'm having a bizarre problem with Visual Studio 2008. I wanted to debug one of the libraries that my web application references. Therefore, I decide to add the project containing the library to my solution so that I can debug them together. The project containing my library sits at c:\webLibs\myproj.vbproj. However, when I try to add the project to my solution, Visual Studio throws the following error: "The project file 'c:\someOtherFolder\myproj.vbproj'. has been moved, renamed, or is not on your computer." As you can see, VS appears to be trying to open a different file than the one I clicked on. I used to have the file in that other location, but not anymore. I've tried restarting VS several times. What could cause this bizarre behavior? Why would Visual Studio try to open my project from the wrong folder?

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  • My cookies won't stay (PHP).

    - by RemiX
    I'm building an autologin system using cookies, but one fundamental part of the functionality of the cookies fails: they are non-persistent over different sessions - or even pages! In my login script, I set the cookies like this: setcookie('userID', $userID, time()+86400); // (edited after replies) $userID has a value. Then I print the $_COOKIE variable and it says array(['base_usid'] = 1); So that's good, but when I click the home page and print the $_COOKIE variable there, it says NULL. Does anyone see the problem?

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  • In Python, is it better to use list comprehensions or for-each loops?

    - by froadie
    Which of the following is better to use and why? Method 1: for k, v in os.environ.items() print "%s=%s" % (k, v) Method 2: print "\n".join(["%s=%s" % (k, v) for k,v in os.environ.items()]) I tend to lead towards the first as more understandable, but that might just be because I'm new to Python and list comprehensions are still somewhat foreign to me. Is the second way considered more Pythonic? I'm assuming there's no performance difference, but I may be wrong. What would be the advantages and disadvantages of these 2 techniques? (Code taken from Dive into Python)

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  • Why doesn't list.get(0).equals(null) work?

    - by Jessy
    The first index is set to null (empty), but it doesn't print the right output, why? //set the first index as null and the rest as "High" String a []= {null,"High","High","High","High","High"}; //add array to arraylist ArrayList<Object> choice = new ArrayList<Object>(Arrays.asList(a)); for(int i=0; i<choice.size(); i++){ if(i==0){ if(choice.get(0).equals(null)) System.out.println("I am empty"); //it doesn't print this output } }

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  • Ruby: Streaming large AWS S3 object freezes

    - by Peter
    Hi, I am using the ruby aws/s3 library to retrieve files from Amazon S3. I stream an object and write it to file as per the documentation (with debug every 100 chunks to confirm progress) This works for small files, but randomly freezes downloading large (150MB) files on VPS Ubuntu. Fetching the same files (150MB) from my mac on a much slower connection works just fine. When it hangs there is no error thrown and the last line of debug output is the 'Finished chunk'. I've seen it write between 100 and 10,000 chunks before freezing. Anyone come across this or have ideas on what the cause might be? Thanks The code that hangs: i=1 open(local_file, 'w') do |f| AWS::S3::S3Object.value(key, @s3_bucket) do |chunk| puts("Writing chunk #{i}") f.write chunk.read_body puts("Finished chunk #{i}") i=i+1 end end

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  • PHP variable question

    - by Kyle Parisi
    This works: $customerBox = mysql_query("MY SQL STATEMENT HERE"); $boxRow = mysql_fetch_array($customerBox); $customerBox = mysql_query("MY SQL STATEMENT AGAIN"); while($item = mysql_fetch_assoc($customerBox)) { foreach ($item as $columnName = $value) { if (empty($value)) { print $columnName; } } } This does not: $customerBox = mysql_query("MY SQL STATEMENT HERE"); $boxRow = mysql_fetch_array($customerBox); while($item = mysql_fetch_assoc($customerBox)) { foreach ($item as $columnName = $value) { if (empty($value)) { print $columnName; } } } Why? I guess I don't understand how variables work yet.

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  • In rails whats the best way to get the site that a user came from? I am getting conflicting info.

    - by kidbrax
    If i enter a url directly into the address bar of the browser, i get the following results: logger.debug ENV['HTTP_REFERER'] // => logger.debug request.referrer // => / So the first one gives me a blank result which is what I expected but the second gives me the root? Is this correct? It seems from the docs (http://api.rubyonrails.org/classes/ActionController/AbstractRequest.html#M000478) that they should return the same thing. And secondly, why does it return the root, if there was no referrer.

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  • Subtype polymorphism and arrays

    - by user133466
    Computer[] labComputers = new Computer[10]; with public class Computer { ... void toString(){ // print computer specs } } public class Notebook extends Computer{ ... void toString(){ // print computer specs + laptop color } } each subscripted variable labComputers[i] can reference either a Computer object or a Notebook object because Notebook is a subclass of Computer. For the method call labComputers[i].toString(), polymorphism ensures that the correct toString method is called. I wonder what if we do Notebook[] labComputers = new Notebook[10]; what kind or error would I get if I reference with Computer object and a Notebook object

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  • can list be converted into string

    - by PARIJAT
    Actually i have extracted some data from the file and want to write it in the file 2 but the program says 'sequence item 1: expected string, list found', I want to know how i can convert buffer[] ie string into sequence, so that it could be saved in file 2...I am new to the python please help* file = open('/ddfs/user/data/k/ktrip_01/hmm.txt','r') file2 = open('/ddfs/user/data/k/ktrip_01/hmm_write.txt','w') buffer = [] rec = file.readlines() for line in rec : field = line.split() print '>',field[0] term = field[0] buffer.append(term) print field[1], field[2], field[6], field[12] term1 = field [1] buffer.append(term1) term2 = field[2] buffer.append[term2] term3 = field[6] buffer.append[term3] term4 = field[12] buffer.append[term4] file2.write(buffer) file.close() file2.close()

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