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  • Why use threading data race will occur, but will not use gevent

    - by onlytiancai
    My test code is as follows, using threading, count is not 5,000,000 , so there has been data race, but using gevent, count is 5,000,000, there was no data race . Is not gevent coroutine execution will atom "count + = 1", rather than split into a one CPU instruction to execute? # -*- coding: utf-8 -*- import threading use_gevent = True use_debug = False cycles_count = 100*10000 if use_gevent: from gevent import monkey monkey.patch_thread() count = 0 class Counter(threading.Thread): def __init__(self, name): self.thread_name = name super(Counter, self).__init__(name=name) def run(self): global count for i in xrange(cycles_count): if use_debug: print '%s:%s' % (self.thread_name, count) count = count + 1 counters = [Counter('thread:%s' % i) for i in range(5)] for counter in counters: counter.start() for counter in counters: counter.join() print 'count=%s' % count

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  • The return value should be a list but doesn't return as expected?! - Python newbie

    - by user1432941
    Hi this must be a very simple solution that has eluded me this last hour. I've tried to build this test function where the return value of the test_cases list should match the values in the test_case_answers list but for some reason, test case 1 and test case 2 fail. When i print the return values for the test cases they return the correct answers, but for some reason test case 1 and test case 2 return False. Thanks for your help! import math test_cases = [1, 9, -3] test_case_answers = [1, 3, 0] def custom_sqrt(num): for i in range(len(test_cases)): if test_cases[i] >= 0: return math.sqrt(test_cases[i]) else: return 0 for i in range(len(test_cases)): if custom_sqrt(test_cases[i]) != test_case_answers[i]: print "Test Case #", i, "failed!" custom_sqrt(test_cases)

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  • Iterating through a range of dates in Python

    - by ShawnMilo
    This is working fine, but I'm looking for any feedback on how to do it better. Right now I think it's better than nested loops, but it starts to get Perl-one-linerish when you have a generator in a list comprehension. Any suggestions are welcome. day_count = (end_date - start_date).days + 1 for single_date in [d for d in (start_date + timedelta(n) for n in range(day_count)) if d <= end_date]: print strftime("%Y-%m-%d", single_date.timetuple()) Notes: I'm not actually using this to print; that's just for demo purposes. The variables start_date and end_date are datetime.date objects, because I don't need the timestamps (they're going to be used to generate a report). I checked the StackOverflow questions which were similar before posting this, but none were exactly the same. Sample Output (for a start date of 2009-05-30 and an end date of 2009-06-09): 2009-05-30 2009-05-31 2009-06-01 2009-06-02 2009-06-03 2009-06-04 2009-06-05 2009-06-06 2009-06-07 2009-06-08 2009-06-09

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  • python compare time

    - by Jesse Siu
    i want to using python create filter for a log file. get recent 7 days record. but when i didn't know how to compare time. like current time is 11/9/2012, i want to get records from 04/9/2012 to now the log file like Sat Sep 2 03:32:13 2012 [pid 12461] CONNECT: Client "66.249.68.236" Sat Sep 2 03:32:13 2012 [pid 12460] [ftp] OK LOGIN: Client "66.249.68.236", anon password "[email protected]" Sat Sep 2 03:32:14 2012 [pid 12462] [ftp] OK DOWNLOAD: Client "66.249.68.236", "/pub/10.5524/100001_101000/100022/readme.txt", 451 i using this one def OnlyRecent(line): print time.strptime(line.split("[")[0].strip(),"%a %b %d %H:%M:%S %Y") print time.time() if time.strptime(line.split("[")[0].strip(),"%a %b %d %H:%M:%S %Y") < time.time(): return True return False But it shows (2012, 9, 2, 3, 32, 13, 5, 246, -1) 1347332968.08 (2012, 9, 2, 3, 32, 13, 5, 246, -1) 1347332968.08 (2012, 9, 2, 3, 32, 14, 5, 246, -1) 1347332968.08 the time format is different, and it can't compare time. So how to set this comparison in 7 days. Thanks

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  • remove the spaces...

    - by tekknolagi
    !/usr/bin/python import random lower_a = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z'] upper_a = ['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'] num = ['0', '1', '2', '3', '4', '5', '6', '7', '8', '9'] all = [] all = " ".join("".join(lower_a) + "".join(upper_a) + "".join(num)) all = all.split() x = 0 while x < 10: for i in range(7): a = random.choice(all) print a, print x += 1 what i want to do is remove the spaces from the output what it gives now is Z 3 a A I K R G B i N 9 c E v g E r A N 8 e B 6 d v H O c a V 8 c x y b g 2 W a T T f 8 H T r 6 E p D K l 5 p u x q 8 P Z 9 T n I W X n B Q

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  • Regular Expression Program

    - by david robers
    Hi I have the following text: SMWABCCA ABCCAEZZRHM NABCCAYJG XABCCA ABCCADK ABCCASKIYRH ABCCAKY PQABCCAK ABCCAKQ This method takes a regex in out by the user and SHOULD print out the Strings it applies to but seems to print out something completely different: private void matchIt(String regex) { Pattern p = Pattern.compile(regex); Matcher m = null; boolean found = false; for(int i = 0; i < data.length; i++){ m = p.matcher(data[i]); if(m.find()){ out.println(data[i]); found = true; } } if(!found){ out.println("Pattern Not Found"); } } When inputting "[C]" It outputs: SMWABCCA ABCCAEZZRHM NABCCAYJG XABCCA ABCCADK ABCCASKIYRH ABCCAKY PQABCCAK ABCCAKQ Any ideas why? I think I'm using m.find() improperly...

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  • Alternative to css3 not selector

    - by Raynos
    Are there any alternatives to the :not css3 selector that are compliant with IE8 (and quirks mode). Either in css or javascript/jquery that emulates the selector or something similar. I am using *:not as follows below. Feel free to recommend a solution that avoids the use of :not completely. @media screen { #printable { visibility: hidden; } } @media print { *:not(#printable) { visibility: hidden; } #printable { position: absolute; visibility: visible; } } Note that the use of :not is tied to the use of @media print so just using a simple jQuery solution to apply css to $(":not(#printable)") won't work without being clever. Including an entire library like ie9.js or selectivirz isn't an option as it can effect various other parts of the pages and would involve a large section of re-testing. a jsfiddle that shows it working in browsers that support :not http://jsfiddle.net/Raynos/TjKbz/

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  • Json request with Javascript

    - by chota
    Hi, I am just beginner on java script and JSON and never had done any work in these before. My employer has just asked me to create the basic POC of these. Scenario: I have a REST API and when i call it, it returns back response in JSON format. Need to To: Create a HTML page and use javascript to call that REST API and capture JSON response and print in the same HTML page. <script type="text/javascript"> function loadMe() { loadJSON('http://myrestAPI'); } function loadJSON(url) { //Help me here to capture the response and print in html page. } </script> I would appreciate your help. This might be simple, but for me i have no idea because i never have done anything similar in java script and json. I goggled but could not find anything. Thanks, chota

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  • Why is Python 3.1 throwing a SyntaxError when printing after loop?

    - by bubersson
    Hi, I'm trying to run this snippet in Python 3.1 console and I'm getting SyntaxError: >>> while True: ... a=5 ... if a<6: ... break ... print("hello") File "<stdin>", line 5 print("hello") ^ SyntaxError: invalid syntax >>> (This is just shortened code to make a point.) Am I missing something? Is there some other Magic I don't know about? Thanks for your help (since this is my first StackOverflow question and I'm not a native English speaker)

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  • My cookies won't stay (PHP).

    - by RemiX
    I'm building an autologin system using cookies, but one fundamental part of the functionality of the cookies fails: they are non-persistent over different sessions - or even pages! In my login script, I set the cookies like this: setcookie('userID', $userID, time()+86400); // (edited after replies) $userID has a value. Then I print the $_COOKIE variable and it says array(['base_usid'] = 1); So that's good, but when I click the home page and print the $_COOKIE variable there, it says NULL. Does anyone see the problem?

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  • Why does Visual Studio 2008 try to open a project from the wrong folder?

    - by Rising Star
    I'm having a bizarre problem with Visual Studio 2008. I wanted to debug one of the libraries that my web application references. Therefore, I decide to add the project containing the library to my solution so that I can debug them together. The project containing my library sits at c:\webLibs\myproj.vbproj. However, when I try to add the project to my solution, Visual Studio throws the following error: "The project file 'c:\someOtherFolder\myproj.vbproj'. has been moved, renamed, or is not on your computer." As you can see, VS appears to be trying to open a different file than the one I clicked on. I used to have the file in that other location, but not anymore. I've tried restarting VS several times. What could cause this bizarre behavior? Why would Visual Studio try to open my project from the wrong folder?

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  • In Python, is it better to use list comprehensions or for-each loops?

    - by froadie
    Which of the following is better to use and why? Method 1: for k, v in os.environ.items() print "%s=%s" % (k, v) Method 2: print "\n".join(["%s=%s" % (k, v) for k,v in os.environ.items()]) I tend to lead towards the first as more understandable, but that might just be because I'm new to Python and list comprehensions are still somewhat foreign to me. Is the second way considered more Pythonic? I'm assuming there's no performance difference, but I may be wrong. What would be the advantages and disadvantages of these 2 techniques? (Code taken from Dive into Python)

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  • Check and avoid if a char is being entered in a int

    - by John
    Hi.... This is a exremely stupid question but i need help with this.... I'm trying to make a small program that i made robust and needed some help with tht.... int num1; int num2 = 0; System.out.print("Enter number 1: "); num1 = kb.nextInt(); while(num2<num1) { System.out.print("Enter number 2: "); num2 = kb.nextInt(); } Number 2 has to be greater than number 1 Also i want the program to automatically check and ignore if the user enters a char instead of an int... Cause right now when a user enters lets say "r" instead of a number the program just exists....

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  • Ruby: Streaming large AWS S3 object freezes

    - by Peter
    Hi, I am using the ruby aws/s3 library to retrieve files from Amazon S3. I stream an object and write it to file as per the documentation (with debug every 100 chunks to confirm progress) This works for small files, but randomly freezes downloading large (150MB) files on VPS Ubuntu. Fetching the same files (150MB) from my mac on a much slower connection works just fine. When it hangs there is no error thrown and the last line of debug output is the 'Finished chunk'. I've seen it write between 100 and 10,000 chunks before freezing. Anyone come across this or have ideas on what the cause might be? Thanks The code that hangs: i=1 open(local_file, 'w') do |f| AWS::S3::S3Object.value(key, @s3_bucket) do |chunk| puts("Writing chunk #{i}") f.write chunk.read_body puts("Finished chunk #{i}") i=i+1 end end

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  • In rails whats the best way to get the site that a user came from? I am getting conflicting info.

    - by kidbrax
    If i enter a url directly into the address bar of the browser, i get the following results: logger.debug ENV['HTTP_REFERER'] // => logger.debug request.referrer // => / So the first one gives me a blank result which is what I expected but the second gives me the root? Is this correct? It seems from the docs (http://api.rubyonrails.org/classes/ActionController/AbstractRequest.html#M000478) that they should return the same thing. And secondly, why does it return the root, if there was no referrer.

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  • How to view the GDTR's value ?

    - by Mehdi Asgari
    Hi In the book "Rootkit Arsenal" page 84 (Chapter 3) mentions: ..., we can view the contents of the target machine's descriptor registers using the command with the 0x100 mask: kd rM 0x100 and a paragraph below: Note that the same task can be accomplished by specifying the GDTR components explicitly: kd r gdtr .... I run Windbg on my Win XP (inside VMWare) and choose the Kernel Debug - Local. My problem is in case of first command, windbg errors with: lkd rM 0x100 ^ Operation not supported in current debug session 'rM 0x100' and in the second command: lkd r gdtr ^ Bad register error in 'r gdtr' Can anyone guide me ?

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  • sIFR 3 - sifr-config.js possibly not running? Not sure what's wrong.

    - by nukegara
    Hi, I've been messing with this for a few hours, and I just can't get the text to be replaced at all. I really can't believe it's taking so long, especially because I did this a few months ago and got it to work in minutes. Anyway, here is my site I'm working on: http://www.moreheadplanetarium.org/regeneration/test/vision.php and I want to replace the h1 tag (Morehead's Vision). I don't know what's wrong, since I've done everything I know to do. I'm jumping back into web design and using Firebug, and when I check the scripts it only has sifr.js and sifr-debug.js in the list, so I'm assuming the config isn't loading but I have no idea what could be the hold up... How do you get the debug to work btw? thanks!

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  • In Python what's the best way to emulate Perl's __END__?

    - by FM
    Am I correct in thinking that that Python doesn't have a direct equivalent for Perl's __END__? print "Perl...\n"; __END__ End of code. I can put anything I want here. One thought that occurred to me was to use a triple-quoted string. Is there a better way to achieve this in Python? print "Python..." """ End of code. I can put anything I want here. """

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  • TCP Scanner Python MultiThreaded

    - by user1473508
    I'm trying to build a small tcp scanner for a netmask. The code is as follow: import socket,sys,re,struct from socket import * host = sys.argv[1] def RunScanner(host): s = socket(AF_INET, SOCK_STREAM) s.connect((host,80)) s.settimeout(0.1) String = "GET / HTTP/1.0" s.send(String) data = s.recv(1024) if data: print "host: %s have port 80 open"%(host) Slash = re.search("/", str(host)) if Slash : netR,_,Wholemask = host.partition('/') Wholemask = int(Wholemask) netR = struct.unpack("!L",inet_aton(netR))[0] for host in (inet_ntoa(struct.pack("!L", netR+n)) for n in range(0, 1<<32-Wholemask)): try: print "Doing host",host RunScanner(host) except: pass else: RunScanner(host) To launch : python script.py 10.50.23.0/24 The problem I'm having is that even with a ridiculous low settimeout value set, it takes ages to cover the 255 ip addresses since most of them are not assigned to a machine. How can i make a way faster scanner that wont get stuck if the port is close.MultiThreading ? Thanks !

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  • can list be converted into string

    - by PARIJAT
    Actually i have extracted some data from the file and want to write it in the file 2 but the program says 'sequence item 1: expected string, list found', I want to know how i can convert buffer[] ie string into sequence, so that it could be saved in file 2...I am new to the python please help* file = open('/ddfs/user/data/k/ktrip_01/hmm.txt','r') file2 = open('/ddfs/user/data/k/ktrip_01/hmm_write.txt','w') buffer = [] rec = file.readlines() for line in rec : field = line.split() print '>',field[0] term = field[0] buffer.append(term) print field[1], field[2], field[6], field[12] term1 = field [1] buffer.append(term1) term2 = field[2] buffer.append[term2] term3 = field[6] buffer.append[term3] term4 = field[12] buffer.append[term4] file2.write(buffer) file.close() file2.close()

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  • Message box does not work in release mode

    - by Bi
    I have the following code in a C# windows form application. if (myGrid.Rows.Count != 0) { // do something } else { MessageBox.Show("Test"); } The message box shows up in Debug mode but not in release mode. Any idea why? I am having similar issues with other code as well For instance if (!myParameter) this.mycheckBox.Enabled = false; else this.mycheckBox.Enabled = true; The above code works in debug mode not in release. Not sure why. Thanks

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  • Python: Give a class its own `self` at instantiation time

    - by SuperDisk
    I've got a button class that you can instantiate like so: engine.createElement((0, 0), Button(code=print, args=("Stuff!",))) And when it is clicked it will print "Stuff!". However, I need the button to destroy itself whenever it is clicked. Something like this: engine.createElement((0, 0), Button(code=engine.killElement, args=(self,))) However, that would just kill the caller, because self refers to the caller at that moment. What I need to do is give the class its own 'self' in advance... I thought of just making the string 'self' refer to the self variable upon click, but what if I wanted to use the string 'self' in the arguments? What is the way to do this? Is my architecture all wrong or something? Thanks.

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  • Resetting a while loop

    - by Patrick Beardmore
    I have found a confusing thing in a php script I am writing to generate some javascript. Here it is below, slightly simplified. The second while loop won't run unless I comment out the entire first while loop. Can anyone explain why? Many thanks. <?php $listid = 2; //DEMO ONLY $result1 = mysql_query("SELECT words.wid,words.wordmd5,words.word FROM words,instances WHERE words.wid = instances.wid AND instances.lid = \"$listid\""); $result1copy = $result1; $count1 = 1; while( $row = mysql_fetch_object( $result1 ) ) { print "words_left[$count1] = \"".$row->word."\";\n"; //Increment the array counter (starts at 1) $count1++; } ?> //Some javascript <?php $count2 = 1; while( $row = mysql_fetch_object( $result1copy ) ) { print " $count2 then $row->wordmd5 "; $count2++; } ?>

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  • Why doesn't list.get(0).equals(null) work?

    - by Jessy
    The first index is set to null (empty), but it doesn't print the right output, why? //set the first index as null and the rest as "High" String a []= {null,"High","High","High","High","High"}; //add array to arraylist ArrayList<Object> choice = new ArrayList<Object>(Arrays.asList(a)); for(int i=0; i<choice.size(); i++){ if(i==0){ if(choice.get(0).equals(null)) System.out.println("I am empty"); //it doesn't print this output } }

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