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• PHP returns invalid MySQL resource

  - by DeadMG

  $LDATE = '#' . $_REQUEST['LDateDay'] . '/' . $_REQUEST['LDateMonth'] . '/' . $_REQUEST['LDateYear'] . '#'; $RDATE = '#' . $_REQUEST['RDateDay'] . '/' . $_REQUEST['RDateMonth'] . '/' . $_REQUEST['RDateYear'] . '#'; include("../../sql.php"); $myconn2 = mysql_connect(/*removed*/, $username, $password); mysql_select_db(/*removed*/, $myconn2); $LSQLRequest = "SELECT * FROM flight WHERE DepartureDate = ".$LDATE; $LFlights = mysql_query($LSQLRequest, $myconn2); $RSQLRequest = "SELECT * FROM flight WHERE DepartureDate = ".$RDATE; $RFlights = mysql_query($RSQLRequest, $myconn2); Assuming that all the $_REQUESTs are valid numerical values for their appropriate fields in the day/month/year field, how can LFlights and RFlights be invalid? When I polled the whole database I got hundreds of results so I know that the database and connection data is fine, and the field DepartureDate exists too.

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• How to search a MySQL database for a specific string

  - by Nadia

  I am trying to set up a search feature on my site that will only return exact matches to keyword entered by the user. So if the user searches "dog" I don't want an article titled "Doggy Style" to appear in the search results (just an example I don't really have an article by that name). This of course does exactly that: SELECT * FROM articles WHERE article_title LIKE '%$searchQuery%' $searchQuery here is a PHP variable taken from the user's input form. So is there any way to return only exact matches?

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• Syntax for combining joins in mysql

  - by UltraVi01

  I seem to remember reading somewhere that there is a way to combine LEFT JOIN statements into a more simple query. I have the following query and was hoping someone could kindly take a look at it. SET @userId = 8; SELECT ug.user_id, COUNT(DISTINCT goal_id) as matches FROM user_goal ug, user u, profile p LEFT JOIN user_block ub ON @userId = ub.blocked_id LEFT JOIN user_block ub2 ON @userId = ub2.blocker_id LEFT JOIN user_user uu ON @userId = uu.user_id LEFT JOIN friend_request fr ON @userId = fr.user_id WHERE ug.user_id = u.id AND u.profile_id = p.id AND (ub.blocker_id IS NULL OR ub.blocker_id != ug.user_id) AND (ub2.blocked_id IS NULL OR ub2.blocked_id != ug.user_id) AND (uu.user_friends_id IS NULL OR uu.user_friends_id != ug.user_id) AND (fr.to_user_id IS NULL OR (fr.to_user_id != ug.user_id)) AND ug.user_id!=@userId AND p.suggestible AND goal_id IN (SELECT iug.goal_id FROM user_goal iug WHERE user_id=@userId) GROUP BY user_id ORDER BY matches DESC LIMIT 4

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• MySQL VARCHAR strange column behavior

  - by Mat

  I have the following SQL statement which returns a single record as expected: select * from geodatasource_cities C, geodatasource_countries D where C.CC_FIPS = D.CC_FIPS and D.CC_ISO='AU' and UCASE(TRIM(C.FULL_NAME_ND)) LIKE '%JAN JUE%'; However, If I use the following SQL statement, no records are returned. I have only changed the LIKE clause to an equal to clause: select * from geodatasource_cities C, geodatasource_countries D where C.CC_FIPS = D.CC_FIPS and D.CC_ISO='AU' and UCASE(TRIM(C.FULL_NAME_ND)) = 'JAN JUE'; Can anybody please help me understand why this may be happening?

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• PHP, MySQL - My own version of SALT (I call salty) - Login Issue

  - by Fabio Anselmo

  Ok I wrote my own version of SALT I call it salty lol don't make fun of me.. Anyway the registration part of my script as follows is working 100% correctly. //generate SALTY my own version of SALT and I likes me salt.. lol function rand_string( $length ) { $chars = "ABCDEFGHIJKLMNOPQRSTUWXYZabcdefghijklmnopqrstuwxyz1234567890"; $size = strlen( $chars ); for( $i = 0; $i < $length; $i++ ) { $str .= $chars[ rand( 0, $size - 1 ) ]; } return $str; } $salty = rand_string( 256 ); //generate my extra salty pw $password = crypt('password'); $hash = $password . $salty; $newpass = $hash; //insert the data in the database include ('../../scripts/dbconnect.php'); //Update db record with my salty pw ;) // TESTED WITH AND WITHOUT SALTY //HENCE $password and $newpass mysql_query("UPDATE `Register` SET `Password` = '$password' WHERE `emailinput` = '$email'"); mysql_close($connect); However my LOGIN script is failing. I have it setup to TEST and echo if its login or not. It always returns FAILED. I entered the DB and changed the crypted salty pw to "TEST" and I got a SUCCESS. So my problem is somewhere in this LOGIN script I assume. Now I am not sure how to implement my $Salty in this. But also be advised that even without SALTY (just using crypt to store my pass) - I was still unable to perform a login successfully. And if you're gonna suggest i use blowfish - note that my webhost doesn't have it supported and i don't know how to install it. here's my login script: if (isset($_POST['formsubmitted'])) { include ('../../scripts/dbconnect.php'); $username = mysql_real_escape_string($_POST['username']); $password = crypt(mysql_real_escape_string($_POST['password'])); $qry = "SELECT ID FROM Register WHERE emailinput='$username' AND Password='$password'"; $result = mysql_query($qry); if(mysql_num_rows($result) > 0) { echo 'SUCCESS'; //START SESSION } else { echo 'FAILED'; //YOU ARE NOT LOGGED IN } } So what's wrong with this login? Why isn't it working just using the crypt/storing only crypt? How can i make it work storing both the crypt and randomly generated SALTY :) ? Ty advance

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• MYSQL JOIN SELECT Statment - omit duplicated

  - by mouthpiec

  Hi, I am tying to join the following 2 queries but I am having duplicated .... it is possible to remove duplacted fro this: ( SELECT bar_id, bar_name, town_name, bar_telephone, (subscription_type_id *2) AS subscription_type_id FROM bar, sportactivitybar, towns, subscriptiontype WHERE sport_activity_id_fk =14 AND bar_id = bar_id_fk AND town_id = town_id_fk AND subscription_type_id = subscription_type_id_fk ) UNION ( SELECT bar_id, bar_name, town_name, bar_telephone, subscription_type_id FROM bar, towns, subscriptiontype WHERE town_id = town_id_fk AND subscription_type_id = subscription_type_id_fk ) ORDER BY subscription_type_id DESC , RAND( ) Please note that I need to omit those duplicates that will have a lower subscription_type_id

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• Zend Framework - Database Table Singleton

  - by Sonny

  I have found myself doing this in my code to 'cache' the work done when instantiating my Zend_Db_Table models: if (Zend_Registry::isRegistered('x_table')) { $x_table = Zend_Registry::get('x_table'); } else { $x_table = new Default_Model_DbTable_X; Zend_Registry::set('x_table', $x_table); } It bothered me that this method isn't very DRY and it dawned on me today that a singleton pattern would probably be a better way to do this. Problem is, I've never written a singleton class. When I did some web searches, I found some offhand comments about Zend_Db_Table singletons, but no real examples. I already have meta-data caching configured. How do I make my Zend_Db_Table models singletons? Are there pitfalls or downsides?

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• What JavaScript table widgets you can recommend? [2]

  - by sdespolit

  As so far i've "found" Yahoo UI library and it fully conforms to my requirements. Also there is jqGrid that i'm using right now. If there are any alternatives? UPDATE: Please suggest libraries and don't seek for matching all the requirements listed below. [i'll check it for myself] My reqs are: rows adding, deletinig rows reoder (optionally with drag and drop) rows selection inline editing json data over xhr (optional) simple integration with backbone.js disclaimer: there was almost the same question 2 years ago

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• Mysql regexp performance question

  - by Tim

  Rumour has it that this; SELECT * FROM lineage_string where lineage like '%179%' and lineage regexp '(^|/)179(/|$)' Would be faster than this; SELECT * FROM lineage_string where lineage regexp '(^|/)179(/|$)' Can anyone confirm ? Or know a decent way to test the speed of such queries. Thanks

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• mysql : Recieve data only per months

  - by Tristan

  Hello, few times ago, i asked how to do to display datas per month, i must told a bad explanation because i just figured out that it's not what i want : Here's what I got : $req1 = ... AND v.date > (DATE_SUB(CURDATE(), INTERVAL 2 MONTH)) AND v.date < (DATE_SUB(CURDATE(), INTERVAL 1 MONTH)) $req2= ... AND v.date > (DATE_SUB(CURDATE(), INTERVAL 3 MONTH)) AND v.date < (DATE_SUB(CURDATE(), INTERVAL 2 MONTH)) But the problem, imagine that today you are the 10th june, it's going to calculate ALL the data between the 10 june to the 10 may then the 10 may until the 10 april... But what i want is data : from 1st may to 1 st june, from 1st june to 1st july... do you see what i mean ? thank you ;)

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• Why does this MySQL Query hang?

  - by zzapper

  SELECT * FROM tbl_order_head AS o INNER JOIN tbl_orders_log AS c ON o.PAYMENT_TRANSACTION_LOG_ID=c.TRANSACTION_ID WHERE o.VISUAL_ID = '77783'; tbl_order_head 67,000 (30 fields) records, tbl_orders_log 17000 (5 fields) records. I don't know if it would eventually return as I am running it on a live server and fear overloading. I am doing similar queries and much more complex queries successfully.

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• php code to mysql database export

  - by kumar

  i want php code to import *.sql file to database and export db to *.sql file without going to phpmyadmin

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• Search a string to find which records in table are inside said string

  - by Improfane

  Hello, Say I have a string. Then I have a number of unique tokens or keywords, potentially a large number in a database. I want to search and find out which of these database strings are inside the string I provide (and get the IDs of them). Is there a way of using a query to search the provided string or must it be taken to application space? Am I right in thinking that this is not a 'full text search'? Would the best method be to insert it into the database to make it a full text search?

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• MySQL Query exceptions

  - by Wayne

  In one page, it should show records that has the following selected month from the drop down menu and it is set in the ?month=March So the query will do this $sql = "SELECT * FROM schedule WHERE month = '" . Clean($_GET['month']) . "' AND finished='0' ORDER BY date ASC"; But it shows records that has a value of 2 in the finished column and I don't want the query to include this. I've tried $sql = "SELECT * FROM schedule WHERE month = '" . Clean($_GET['month']) . "' AND finished='0' OR finished = '1' OR finished = '3' ORDER BY date ASC"; But it shows records on different months when it shouldn't be. So basically I want the record to exclude the records that has the value of 2 in the record that will not be shown in the page.

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• MySQL date query only returns one year, when multiple exist

  - by Bowman

  I'm a part-time designer/developer with a part-time photography business. I've got a database of photos with various bits of metadata attached. I want to query the database and return a list of the years that photos were taken, and the quantity of photos that were taken in that year. In short, I want a list that looks like this: 2010 (35 photos) 2009 (67 photos) 2008 (48 photos) Here's the query I'm using: SELECT YEAR(date) AS year, COUNT(filename) as quantity FROM photos WHERE visible='1' GROUP BY 'year' ORDER BY 'year' DESC Instead of churning out all the possible years (the database includes photos from 2010-2008), this is the sole result: 2010 (35 photos) I've tried a lot of different syntax but at this point I'm giving in and asking for help!

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• How to build unlimited level of menu through PHP and mysql

  - by Starx

  Well, to build my menu my menu I use a db similar structure like this To assign another submenu for existing submenu I simply assign its parent's id as its value of parent field. parent 0 means top menu now there is not problem while creating submenu inside another submenu now this is way I fetch the submenu for the top menu <ul class="topmenu"> <? $list = $obj -> childmenu($parentid); //this list contains the array of submenu under $parendid foreach($list as $menu) { extract($menu); echo '<li><a href="#">'.$name.'</a></li>'; } ?> </ul> What I want to do is. I want to check if a new menu has other child menu and I want to keep on checking until it searches every child menu that is available and I want to display its child menu inside its particular list item like this Home ........

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• Splitting tables by field to optimize MySQL?

  - by AK

  Do splitting fields into multiple tables ever yield faster queries? Consider the following two scenarios: Table1 ----------- int PersonID text Value1 float Value2 or Table1 ----------- int PersonID text Value1 Table2 ----------- int PersonID float Value2 If Value1 and Value2 are always being displayed together, I imagine Table1 is always faster because the second schema would require two SELECT statements. But are there any situations where you would choose the second? If the number of records were expected to be really large?

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• cant get ordering mysql results by current date ASC to work

  - by Patrick

  Im trying to order results ASCENDING from the current date this is what im using now; SELECT * FROM friends JOIN bdays ON bdays.user = friends.friendname WHERE username = $userid ORDER BY DATE_FORMAT(date, '%m %d') any ideas?

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• Converting MySQL Resultset from Rows to Columns

  - by gms8994

  I have output from a select like this: 04:47:37> select * from attributes left outer join trailer_attributes on attributes.id = trailer_attributes.attribute_id; +----+--------------+----------+-----------+------------+--------------+-----------------+ | id | name | datatype | list_page | trailer_id | attribute_id | attribute_value | +----+--------------+----------+-----------+------------+--------------+-----------------+ | 1 | Make | text | 1 | 1 | 1 | Apple | | 1 | Make | text | 1 | 2 | 1 | sdfg | | 2 | Year | number | 1 | 1 | 2 | 2009 | | 2 | Year | number | 1 | 2 | 2 | sdfg | | 3 | Type | text | 0 | 1 | 3 | iPhone | | 3 | Type | text | 0 | 2 | 3 | sdfg | | 4 | Axles | text | 0 | 1 | 4 | asdf | | 4 | Axles | text | 0 | 2 | 4 | sdfg | | 7 | Size | text | 0 | 1 | 7 | asd1 | | 7 | Size | text | 0 | 2 | 7 | sdfg | | 8 | Frame | text | 0 | 1 | 8 | | | 8 | Frame | text | 0 | 2 | 8 | sdfg | | 9 | Height | text | 0 | 1 | 9 | | | 9 | Height | text | 0 | 2 | 9 | sdfg | | 10 | Dollies | text | 0 | 1 | 10 | | | 10 | Dollies | text | 0 | 2 | 10 | sdfg | | 11 | Tires/Wheels | text | 0 | 1 | 11 | | | 11 | Tires/Wheels | text | 0 | 2 | 11 | sdfg | | 12 | Condition | text | 1 | 1 | 12 | New | | 12 | Condition | text | 1 | 2 | 12 | sdfg | | 13 | Title | text | 0 | 1 | 13 | | | 13 | Title | text | 0 | 2 | 13 | sdfg | +----+--------------+----------+-----------+------------+--------------+-----------------+ I want to convert it to something more along the lines of: id, Make, Year, Type, Axles, Size, Frame (etc) 1, Apple, 2009, iPhone, ..... 2, sdfg, sdfg, sdfg, ..... Any suggestions?

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• MySQL join problem

  - by David

  Table1 has u_name, Table2 has u_name, u_type and u_admin Table1.u_name is unique. But neither of the 3 fields in Table2 is unique. For any value of Table1.u_name, there are 0 to many entries in Table2 that Table2.u_name equals to that value. For any value of Table1.u_name, there are 0 to 1 entries in Table2 that Table2.u_name equals to that value AND Table2.u_type='S' What I want: Use Table1.u_name to get Table1.*, Table2.u_admin where Table1.u_name=Tabl2.u_name and Table2.u_type='S'. If there is no such entry in Table2 we still need to get Table1.* Please help give me some hints. Thank you so much!

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• PHP/mySQL - using result from 'CONCAT' and 'AS' in 'LIKE' clause

  - by Phil Jackson

  Hi I have the following code; if( ! empty( $post['search-bar'] ) ) { $search_data = preg_replace("#\s\s#is", '', preg_replace("#[^\w\d\s+]#is", '', $post['search-bar'] ) ); $data_array = explode( " ", $search_data ); $data_array = "'%" . implode( "%' OR '%", $data_array ) . "%'"; $query = "SELECT CONCAT( PROFILE_PROFFESION, FIRST_NAME, LAST_NAME, DISPLAY_NAME) AS 'STRING' FROM `" . ACCOUNT_TABLE . "` WHERE STRING LIKE ( " . $data_array . " ) AND BUSINESS_POST_CODE LIKE '" . substr(P_BUSINESS_POST_CODE, 0, 4) . "%'"; $q = mysql_query( $query, $CON ) or die( "_error_" . mysql_error() ); if( mysql_num_rows( $q ) != 0 ) { die(); } } Problem is I want to use the temp col 'STRING' in the where clause but is returning 'unknown coloumn STRING Can any one point me in the right direction, regards Phil

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• PHP/Mysql issues

  - by queryne

  Php/my sql newbie question. I have a database I've imported into my local phpmyadmin. However it seems I can't access it from my a php application. The connection string seems right and when i try to authenticate user credentials to access database information, no problems. However authenticate everyone and knows when i put in fake credentials. Still it won't pull any other information from the database. For instance, once a users login they should see something like, "Hello username"... that kind of thing. At this point I see "Hello" without the username. Any ideas what i might be missing?

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• Levenshtein: MySQL + PHP

  - by user317005

  $word = strtolower($_GET['term']); $lev = 0; $q = mysql_uqery("SELECT `term` FROM `words`"); while($r = mysql_fetch_assoc($q)) { $r['term'] = strtolower($r['term']); $lev = levenshtein($word, $r['term']); if($lev >= 0 && $lev < 5) { $word = $r['term']; } } how can I move all that into just one query? don't want to have to query through all terms and do the filtering in php.

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• MySQL parameter resource error

  - by Derek

  Here is my error: Warning: mysql_query() expects parameter 2 to be resource, null given... This refers to line 23 of my code which is: $result = mysql_query($sql, $connection) My entire query code looks like this: $query = "SELECT * from users WHERE userid='".intval( $_SESSION['SESS_USERID'] )."'"; $result = mysql_query($query, $connection) or die ("Couldn't perform query $query <br />".mysql_error()); $row = mysql_fetch_array($result); I don't have a clue what has happpened here. All I wanted to do was to have the value of the users 'fullname' displayed in the header section of my web page. So I am outputting this code immediately after to try and achieve this: echo 'Hello '; echo $row['fullname']; Before this change, I had it working perfectly, where the session variable of fullname was echoed $_SESSION['SESS_NAME']. However, because my user can update their information (including their name), I wanted the name displayed in the header to be updated accordingly, and not displaying the session value.

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• mysql query optimization

  - by vamsivanka

  I would need some help on how to optimize the query. select * from transaction where id < 7500001 order by id desc limit 16 when i do an explain plan on this - the type is "range" and rows is "7500000" According to the some online reference's this is explained as, it took the query 7,500,000 rows to scan and get the data. Is there any way i can optimize so it uses less rows to scan and get the data. Also, id is the primary key column.

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