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• MySQL INSERT IGNORE not working

  - by gAMBOOKa

  Here's my table with some sample data a_id | b_id ------------ 1 225 2 494 3 589 When I run this query INSERT IGNORE INTO table_name (a_id, b_id) VALUES ('4', '230') ('2', '494') It inserts both those rows when it's supposed to ignore the second value pair (2, 494) No indexes defined, neither of those columns are primary. What don't I know?

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• Getting random values in mySql query

  - by Roland

  I have a query which selects 6 names in the database. eg SELECT names FROM users LIMIT 6 Now I want this query to select a random 6 names in the database table, is this possible? And how

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• MYSQL: Udate table column from subquery result

  - by Jhourlad Estrella

  On the Members table are columns "MemberID" and "PointsEarned". I want to update the PointsEarned column from the result of this query: SELECT m.MemberID, m.UserName, ( (SELECT COUNT(*) FROM EventsLog as e WHERE e.MemberID=m.MemberID AND e.EventsTypeID=2)*10 ) + ( (SELECT COUNT(*) FROM EventsLog as e WHERE e.MemberID=m.MemberID AND e.EventsTypeID=3)*3 ) + ( (SELECT COUNT(*) FROM ChatMessages as c WHERE c.MemberID=m.MemberID)*.1 ) as PointsEarned FROM Members as m Can anybody tell me how I should do it with a single query? Thanks!

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• Multidimensional Array To Mysql Codeigniter

  - by rochellecanale

  A little help how can I create an input query using this array? Or how can I pass it in the table? my table layout sample is this: sales_table id | product_name | price | qty | subtotal This is derived from the var_dump() function. Here is my code in array //array code from unserialized function $products = unserialize($this->session->userdata('product_list')); //This is the output. Array ( [2] => Array ( [id] => 2 [product_name] => NOKIA 5110 [product_desc] => Cellphone [product_price] => 500.00 [product_qty] => 1 [product_amount] => 500 [product_code] => NOKI2012-84353 ) [3] => Array ( [id] => 3 [product_name] => HP IPAQ RW6828 [product_desc] => Cellphone [product_price] => 1500.00 [product_qty] => 1 [product_amount] => 1500 [product_code] => HP I2012-08386 ) )

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• restrict duplicate rows in specific columns in mysql

  - by JPro

  I have a query like this : select testset, count(distinct results.TestCase) as runs, Sum(case when Verdict = "PASS" then 1 else 0 end) as pass, Sum(case when Verdict <> "PASS" then 1 else 0 end) as fails, Sum(case when latest_issue <> "NULL" then 1 else 0 end) as issues, Sum(case when latest_issue <> "NULL" and issue_type = "TC" then 1 else 0 end) as TC_issues from results join testcases on results.TestCase = testcases.TestCase where platform = "T1_PLATFORM" AND testcases.CaseType = "M2" and testcases.dummy <> "flag_1" group by testset order by results.TestCase The result set I get is : testset runs pass fails issues TC_issues T1 66 125 73 38 33 T2 18 19 16 16 15 T3 57 58 55 55 29 T4 52 43 12 0 0 T5 193 223 265 130 22 T6 23 12 11 0 0 My problem is, this is a result table which has testcases running multiple times. So, I am able to restrict the runs using the distinct TestCases but when I want the pass and fails, since I am using case I am unable to eliminate the duplicates. Is there any way to achieve what I want? any help please? thanks.

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• Mysql filling in missing dates

  - by bsandrabr

  I have the following query SELECT * FROM attend RIGHT OUTER JOIN noattend ON attend.date = noattend.date2 WHERE attend.date BETWEEN '2010-02-01' AND '2010-04-01' AND attend.customerid =1 ORDER BY date DESC LIMIT 0 , 30 Attend is the table with customerid noattend is the table with a row for each date (date2) I followed the advice in other questions to right outer join it to create values where there is no record in attend but it still isn't filling in the empties any help much appreciated

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• MySQL look for missing ratings

  - by Dustin

  Hopefully I can ask this without being confusing. I am a photographer and I am having some of our clients rate pictures that we have taken. We have hundreds of pictures in our portfolio that they may be rating. What I want to do is ask our clients to rate pictures again, but only show them the pictures they haven't yet rated. I currently have three tables: one that stores the actual ratings, one that stores the pictures (or location of each picture), and one that stores the information about the rater. I'm using codeigniter for my db management, if that helps at all. What I have so far is this: "SELECT * FROM ratings LEFT JOIN portfolio ON ratings.portfolioid = portfolio.portfolioid" This will give me a row for each rating, but won't show me where a rating is missing for a picture. Thanks in advance!

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• How to rearrange Mysql columns?

  - by Lost_in_code

  I need to move the position of existing columns (for better visibility). How can this be done without affecting the data?

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• Error with characters in a html iframe

  - by dinero beta

  excuse my English I speak Spanish I'm trying to display multiple php and mysql registration, after that the show in an iframe the problem is that apparently in the iframe shows me errors accents and other characters for example: for example (?D?nde cuesta menos y se consume m?s?") this is what shows (?) In the original query or first does not show me that, but in the iframe shows me that error and probe with http-equiv = "content-type" and I worked What else I can do? What should I do? regards

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• How to prevent negative number in Mysql

  - by Jerry

  Hello guys.. I have data which is starting from 0 in my database. My php will add 1 or -1 to the data depending on the user's input. My problem is that if data is 0 and a user try to subtract 1. The data become 4294967295 which is the maximum value of INT data type. Are there anyways to make the data stays in 0 even when the user asks for -1? Thanks for the reply.. my sql command is like below update board set score=score-1 where team='TeamA' //this would generate 4294967295 if the score is 0.....

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• PHP/MySQL - an array filter for bots

  - by Mike

  Hello, I'm making a hit counter. I have a database and I store the IP and $_SERVER['HTTP_USER_AGENT']; of the visitors. Now I need to add a filter, so I can put away the hits, that are made by bots. I found out, that many bots usually keep some common words in the $_SERVER['HTTP_USER_AGENT']; , so I's like to make and array of words, that would keep the bot from displaying in the results. Here is what I have now: while($row = mysql_fetch_array($yesterday, MYSQL_ASSOC)) { <-- Here I need a code, that would run through an array and check, if it containts the keywords and if it doesn't ... just count++; -- } Also if you know any other way of detecting and removing the bots from the results, I'd be verry thankful. Cheers

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• delete row from mysql through generated table with records

  - by HennySmafter

  I am using 2 pages. On one page it generates a table with the records and a delete button. After pressing delete it goes to the second page which should delete the record. But it doesn't. Below is the code that I am using. PS: The code is adapted from a tutorial I found through Google a while ago. delete_overzicht.php <?php // Load Joomla! configuration file require_once('../../../configuration.php'); // Create a JConfig object $config = new JConfig(); // Get the required codes from the configuration file $server = $config->host; $username = $config->user; $password = $config->password; $database = $config->db; // Connect to db $con = mysqli_connect($server,$username,$password,$database); if (!$con){ die('Could not connect: ' . mysqli_error($con)); } mysqli_select_db($con,$database); // Get results $result = mysqli_query($con,"SELECT * FROM cypg8_overzicht"); echo "<table border='1' id='example' class='tablesorter'><thead><tr><th>Formulier Id</th><th>Domeinnaam</th><th>Bedrijfsnaam</th><th>Datum</th><th>Periode</th><th>Subtotaal</th><th>Dealernaam</th><th>Verwijderen</th></tr></thead><tbody>"; while($row = mysqli_fetch_array($result)) { echo "<tr>"; echo "<td>" . $row['formuliernummer'] . "</td>"; echo "<td>" . $row['domeinnaam'] . "</td>"; echo "<td>" . $row['bedrijfsnaam'] . "</td>"; echo "<td>" . $row['datum'] . "</td>"; echo "<td>" . $row['periode'] . "</td>"; echo "<td> &euro; " . $row['subtotaal'] . "</td>"; echo "<td>" . $row['dealercontactpersoon'] . "</td>"; echo "<td><a href='delete.php?id=" . $row['id'] . "'>Verwijderen </a></td>"; echo "</tr>"; } echo "</tbody></table>"; mysqli_close($con); ?> delete.php <?php // Load Joomla! configuration file require_once('../../../configuration.php'); // Create a JConfig object $config = new JConfig(); // Get the required codes from the configuration file $server = $config->host; $username = $config->user; $password = $config->password; $database = $config->db; // Connect to db $con = mysqli_connect($server,$username,$password,$database); if (!$con){ die('Could not connect: ' . mysqli_error($con)); } mysqli_select_db($con,$database); // Check whether the value for id is transmitted if (isset($_GET['id'])) { // Put the value in a separate variable $id = $_GET['id']; // Query the database for the details of the chosen id $result = mysqli_query($con,"DELETE * FROM cypg8_overzicht WHERE id = $id"); } else { die("No valid id specified!"); } ?> Thanks to everyone who is willing to help!

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• changing existing duplicate entries in mysql

  - by Mladen

  sorry for the (probably) noob question, but I', new at this stuff. i have a table that has column 'position', and I want to, when inserting a new row, change positions of every row that has position lower than row that is inserted. for example, if I add row with position 4, if there is a duplicate, it should become 5, 5 should shift to 6 and so on... also, is there a way to get highest value for column besides testing it in every row via php?

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• Mysql query problem

  - by Lost_in_code

  Below is a sample table: fruits +-------+---------+ | id | type | +-------+---------+ | 1 | apple | | 2 | orange | | 3 | banana | | 4 | apple | | 5 | apple | | 6 | apple | | 7 | orange | | 8 | apple | | 9 | apple | | 10 | banana | +-------+---------+ Following are the two queries of interest: SELECT * FROM fruits WHERE type='apple' LIMIT 2; SELECT COUNT(*) AS total FROM fruits WHERE type='apple'; // output 6 I want to combine these two queries so that the results looks like this: +-------+---------+---------+ | id | type | total | +-------+---------+---------+ | 1 | apple | 6 | | 4 | apple | 6 | +-------+---------+---------+ The output has to be limited to 2 records but it should also contain the total number of records of the type apple. How can this be done with 1 query?

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• MySql Not Like Regexp?

  - by KnockKnockWhosThere

  I'm trying to find rows where the first character is not a digit. I have this: SELECT DISTINCT(action) FROM actions WHERE qkey = 140 AND action NOT REGEXP '^[:digit:]$'; But, I'm not sure how to make sure it checks just the first character...

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• PHP mySQL query's and PHP Variables

  - by jon

  I'm trying to make an OO Login system for a project I'm working on, and am having trouble with inserting variables into the query strings. In the code below, if I replace "$TBL_NAME" with the actual table name it works. Why isn't $TBL_NAME translating to the value of $TBL_NAME? class UserDB { private $TBL_NAME = "users"; public static function CheckLogin($username, $password) { Database::Connect(); $username = stripslashes($username); $password = stripslashes($password); $username = mysql_real_escape_string($username); $password = mysql_real_escape_string($password); $sql="SELECT uid FROM $TBL_NAME WHERE username='$username' AND password='$password' "; $result =mysql_query($sql); $count=mysql_num_rows($result); if ($count==1) return true; else return false; } The Query is returning false.

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• Mysql Left join with condition on column

  - by skicster

  Hi, can you help me with sql query? I have this problem: I have two tables "Join" table: Reservation_has_meal +----------------+ | id_reservation | | id_meal | | pieces | +----------------+ and table with data: Meal +-------------+ | id_meal | | name | +-------------+ Sample data for Meal: 1 | carrot 2 | potatoe 3 | cucumber Reservation_has_meal 1 | 2 | 5230 1 | 3 | 1203 How can I get this result for reservation with id_reservation=1: id_meal | id_Reservation | name | pcs | -------------------------------------------- 1 | 1 | carrot | null| 2 | 1 | potatoe | 5230| 3 | 1 | cucumber | 1203| -------------------------------------------- And result for id_reservation = 2: id_meal | id_Reservation | name | pcs | -------------------------------------------- 1 | 2 | carrot | null| 2 | 2 | potatoe | null| 3 | 2 | cucumber | null| -------------------------------------------- Thanks for advice.

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• Seeking assistance with Escaping Data for MySQL queries

  - by JM4

  Please don't send me a link to php.net referencing mysql_real_escape_string as the only response. I have read through the page and while I understand the general concepts, I am having some trouble based on how my INSERT statement is currently built. Today, I am using the following: $sql = "INSERT INTO tablename VALUES ('', '$_SESSION['Member1FirstName'], '$_SESSION['Member1LastName'], '$_SESSION['Member1ID'], '$_SESSION['Member2FirstName'], '$_SESSION['Member2LastName'], '$_SESSION['Member2ID'] .... and the list goes on for 20+ members with some other values entered. It seems most people in the examples already have all their data stored in an array. On my site, I accept form inputs, action="" is set to self, php validation takes place and if validation passes, data is stored into SESSION variables on page 2 then redirected to the next page in the process (page 3) (approximately 8-10 pages in the whole process). thanks!

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• After 30 seconds, update MYSQL databse

  - by Sam

  Hello everyone! I've been looking around here on SO and Googling, however I can't find anything that fits my description. What I want to do is update the database if the page has not been refreshed after 30 seconds. I want to email a person with the contents of a form {submitted by a different user} (I can do that) IF the person has NOT visited the page (I can do that) within the last 30 seconds. What I've tried to do is make the page that should be visited refresh every 30 seconds, and so I figured if I did something like after 31 seconds, edit the database (so if the refreshed page was not refreshed, the database editing would run). I'm sorry if this sounds complicated, there's probably a better way to do this, but I'm not sure how. The bigger picture is I'm trying to make a 'on-duty' sort of thing, so that if the person is not actively looking at the page, they will get emailed with whatever the contents of the form is. The page will contain a table of all the entered form results.

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• MYSQL Query using subquery

  - by Michael Quiles

  Cant get this to work can any one help. List the part number, part description, and on_hand value of each part whose number of units on hand is more than the average number of units onhand for all parts use a subquery? SELECT PART_NUM, DESCRIPTION, SUM(ON_HAND * PRICE) ON_HAND_VALUE FROM PART; WHERE MAX(ON_HAND); (AVG(ON_HAND) > ON_HAND);

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• MySQL Search (Sort by Relevance)

  - by atif089

  Hi guys, Can any one help me how to sort rows by relevance for the following criterion ? tbluser First Name Last Name tbleduc School College University On the search form the user has following fields Name School College University Where School College and University are Optional.. And Name is split into 2 words (other words in middle are omitted), first word is taken as first anme and last word as last name.. Now I would like to implement search based on relevance. Thanks for the help :)

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• mysql - How select a akin records?

  - by zeroonea

  I have a table with name varchar address varchar country varchar city varchar ..... to store address of location example: name|address|country HaLong hotel|156 blahblah street|Vietnam Hotel Ha Long|156 blah blah|Vietnam Two rows above is duplicate data. I have a form, when user submit new location. The code need to find akin records to give a message (ex: This location already in db, use it or create new?) How to make a query to get akin record like this?

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• retrive data from mysql using php and jquery

  - by user313835

  i have a menu, it contains multiple items, each menu item will retrieve data from the database. i want to do it without the page refresh, i want like an area that will change when the user clicks on the menu link. How should i send data to the php script and how should i get it from there and preview it on the page. if you can send me any information, references or examples that will be great Thanks in advance.

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• generating images by user id php + mysql

  - by jay

  function user_image($id, $increment_views = false) { $id = mysql_real_escape_string($id); $q = mysql_query("SELECT * FROM `images` WHERE `id` = '$id'"); if (mysql_num_rows($q)) { $return = mysql_fetch_assoc($q); $q = mysql_query("SELECT * FROM `sources` WHERE `source_id` = $return[id] AND `source_flagged` = 0"); while ($r = mysql_fetch_assoc($q)) { $return['sources'][] = $r; } if ($increment_views) { $q = mysql_query("UPDATE `images` SET `views` = `views` + 1 WHERE `id` = $return[id]"); } return $return; } else { return false; } }

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• MySQL/PHP Search Efficiency

  - by iMaster

  Hi! I'm trying to create a small search for my site. I've tried using full-text index search, but I could never get it to work. Here is what I've come up with: if(isset($_GET['search'])) { $search = str_replace('-', ' ', $_GET['search']); $result = array(); $titles = mysql_query("SELECT title FROM Entries WHERE title LIKE '%$search%'"); while($row = mysql_fetch_assoc($titles)) { $result[] = $row['title']; } $tags = mysql_query("SELECT title FROM Entries WHERE tags LIKE '%$search%'"); while($row = mysql_fetch_assoc($tags)) { $result[] = $row['title']; } $text = mysql_query("SELECT title FROM Entries WHERE entry LIKE '%$search%'"); while($row = mysql_fetch_assoc($text)) { $result[] = $row['title']; } $result = array_unique($result); } So basically, it searches through all the titles, body-text, and tags of all the entries in the DB. This works decently well, but I'm just wondering how efficient would it be? This would only be for a small blog, too. Either way I'm just wondering if this could be made any more efficient.

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