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  • Html.ActionLink in a button

    - by Pomster
    I Am trying to connect to a method in my controller, with a button. I can connect though this link: @Html.ActionLink("Print", "Print", new { id = Model.SalesContractId}) But i Don't want a link, i want my button on my dialog to do it. I have tried the following: $('#btnDialogPrint').click(function () { location.href = '<%= Url.Action("Print", "Print", new { id = Model.SalesContractId}) %>'; }); But it just redirect me to a page that say bad request. namespace Contract.Controllers { public class ContractController : Controller { CompassEntities db = new CompassEntities(); public ActionResult Print(int id) { return View(""); // This can be removed and Print code may be added } Don't worry about the code inside i will get to that once i get inside this method. Could i maybe attach a link here? <input type="button" value="Print" id="btnDialogPrint" />

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  • Sorting related objects in the Django Admin form interface

    - by Carver
    I am looking to sort the related objects that show up when editing an object using the admin form. So for example, I would like to take the following object: class Person(models.Model): first_name = models.CharField( ... ) last_name = models.CharField( ... ) hero = models.ForeignKey( 'self', null=True, blank=True ) and edit the first name, last name and hero using the admin interface. I want to sort the objects as they show up in the drop down by last name, first name (ascending). How do I do that? Context I'm using Django v1.1. I started by looking for help in the django admin docs, but didn't find the solution As you can see in the example, the foreign key is pointing to itself, but I expect it would be the same as pointing to a different model object. Bonus points for being able to filter the related objects, too (eg~ only allow selecting a hero with the same first name)

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  • Add Many-to-Many Entity Framework

    - by tomcamara
    I've got a question: I have 3 tables: Users Menu UserMenu UserMenu contains IdMenu and IdUser. In My DataModel Entity Framework 4.0, I'm filling my User Model and filling User.Menu (Menu is Navigation Properties) with an existing Menu of my table Menu. I have to save User and Save each related menu item in UserMenu table. I get the following exception: The ObjectStateManager does not contain an ObjectStateEntry with a reference to an object of type 'SGGED.Model.Menu'. Code Users objUser = new Users(); objUser.name = itemUsers.name.Trim(); objUser.email = itemUsers.email.Trim(); objUser.password = Util.HashString("12345"); objUser.effdt = DateTime.Now; objData.Users.AddObject(objUser); foreach (var itemMenu in itemUsers.Menu) { objData.ObjectStateManager.ChangeObjectState(itemMenu, EntityState.Unchanged); } affRows = objData.SaveChanges(); Whats the way to handle this issue? Best Regards, Miltom Camara

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  • How do I tell Entity Framework that a column in a view is nullable?

    - by Ryan ONeill
    I have a view which has an Int column which is nullable (let's call it StackOverflowCount). When generating an EF model from the database, the EF designer does not recognise it as nullable and creates the column as an Int. The issue I have is that on the EF designer I have set the column to Nullable and the following error then kills the compilation; Error 3031: Problem in mapping fragments starting at line 2327: Non-nullable column MyView.StackOverflowCount in table MyView is mapped to a nullable entity property. I can get round this by opening the .edmx file in XML mode and manually editing the SQL column definition, but there is no way to do this using the designer and it gets overwritten the next time I refresh from the model from the DB. Is this 'by design' or an example of something that slipped through into EF 4.0? I'm using .Net 4.0 with EF 4.0 under VS 2010.

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  • What is the proper way to check the previous value of a field before saving an object? (Using Django

    - by anonymous coward
    I have a Django Model with updated_by and an approved_by fields, both are ForeignKey fields to the built-in (auth) User models. I am aware that with updated_by, it's easy enough to simply over-ride the .save() method on the Model, and shove the request.user in that field before saving. However, for approved_by, this field should only ever be filled in when a related field (date_approved) is first filled in. I'm somewhat certain that I can check this logically, and fill in the field if the previous value was empty. What is the proper way to check the previous value of a field before saving an object? I do not anticipate that date_approved will ever be changed or updated, nor should there be any reason to ever update the approved_by entry. UPDATE: Regarding forms/validation, I should have mentioned that none of the fields in question are seen by or editable by users of the site. If I have misunderstood, I'm sorry, but I'm not sure how forms and validation apply to my question.

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  • ASP.NET MVC2 TmplatedHelper doesn't render an ID of the HTML's markup

    - by Tony
    Hi, I have the code (snippet): The Model is the IEnumerable object of the Person's class: <% foreach (var item in Model) { %> <tr> <td><%= Html.DisplayFor(x=>item.Name) %></td> </tr> <% } %> it renders only labels like that: <td>Tommy</td> According to the link it should be rendering a HTML markup something like: but there is no the ID and the NAME property. Why ?

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  • Is there an ORM that allows a "plugin" to extend the database?

    - by IP
    So, I've been searching for the answer to this, but I can't find anything I have an Entity Framework Model (MyModel1) - for now, we'll say this contains a "Users" table It's part of a big app, that has a references to an "Addresses" project The addresses project contains an Entity Framework Model (MyModel2), this contains a Users table, and an Addresses table (pointing to the same database. The main app has a control that edits the user, and in that control it has an "addresses" control which actually exists in the "Addresses" project. To make this work, the User control passes the User object down to the addresses control, however, as the User that's been passed belongs to MyModel1 and not MyModel2, another User object has to be loaded up, then it can be used. This isn't ideal as I've had to load up the User twice. Is there a way of say, MyModel2 extending MyModel1, which effectively just adds a relationship to "User". Or is there an ORM that would handle this better? Or even a design pattern that would handle this better?

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  • is it safe to refactor my django models?

    - by Johnd
    My model is similar to this. Is this ok or should I make the common base class abstract? What are the differcenes between this or makeing it abstract and not having an extra table? It seems odd that there is only one primary key now that I have factored stuff out. class Input(models.Model): details = models.CharField(max_length=1000) user = models.ForeignKey(User) pub_date = models.DateTimeField('date published') rating = models.IntegerField() def __unicode__(self): return self.details class Case(Input): title = models.CharField(max_length=200) views = models.IntegerField() class Argument(Input): case = models.ForeignKey(Case) side = models.BooleanField() is this ok to factor stuff out intpu Input? I noticed Cases and Arguments share a primary Key. like this: CREATE TABLE "cases_input" ( "id" integer NOT NULL PRIMARY KEY, "details" varchar(1000) NOT NULL, "user_id" integer NOT NULL REFERENCES "auth_user" ("id"), "pub_date" datetime NOT NULL, "rating" integer NOT NULL ) ; CREATE TABLE "cases_case" ( "input_ptr_id" integer NOT NULL PRIMARY KEY REFERENCES "cases_input" ("id"), "title" varchar(200) NOT NULL, "views" integer NOT NULL ) ; CREATE TABLE "cases_argument" ( "input_ptr_id" integer NOT NULL PRIMARY KEY REFERENCES "cases_input" ("id"), "case_id" integer NOT NULL REFERENCES "cases_case" ("input_ptr_id"), "side" bool NOT NULL )

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  • Extending appengine's db.Property with caching

    - by Noio
    I'm looking to implement a property class for appengine, very similar to the existing db.ReferenceProperty. I am implementing my own version because I want some other default return values. My question is, how do I make the property remember its returned value, so that the datastore query is only performed the first time the property is fetched? What I had is below, and it does not work. I read that the Property classes do not belong to the instances, but to the model definition, so I guess that the return value is not cached for each instance, but overwritten on the model every time. Where should I store this _resolved variable? class PageProperty(db.Property): data_type = Page def get_value_for_datastore(self, model_instance): page = super(PageProperty, self).get_value_for_datastore(model_instance) self._resolved = page return page.key().name() def make_value_from_datastore(self, value): if not hasattr(self, '_resolved'): self._resolved = Page.get_by_name(value) return self._resolved

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  • Good real-world uses of metaclasses (e.g. in Python)

    - by Carles Barrobés
    I'm learning about metaclasses in Python. I think it is a very powerful technique, and I'm looking for good uses for them. I'd like some feedback of good useful real-world examples of using metaclasses. I'm not looking for example code on how to write a metaclass (there are plenty examples of useless metaclasses out there), but real examples where you have applied the technique and it was really the appropriate solution. The rule is: no theoretical possibilities, but metaclasses at work in a real application. I'll start with the one example I know: Django models, for declarative programming, where the base class Model uses a metaclass to fill the model objects of useful ORM functionality from the attribute definitions. Looking forward to your contributions.

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  • I can't delete record in Codeigniter

    - by jomblo
    I'm learning CRUD in codeigniter. I have table name "posting" and the coloumns are like this (id, title, post). I successed to create a new post (both insert into database and display in the view). But I have problem when I delete my post in the front-end. Here is my code: Model Class Post_Model extends CI_Model{ function index(){ //Here is my homepage code } function delete_post($id) { $this->db->where('id', $id); $this->db->delete('posting'); } } Controller Class Post extends CI_Controller{ function delete() { $this->load->model('Post_Model'); $this->Post_Model->delete_post("id"); redirect('Post/index/', 'refresh'); } } After click "delete" in the homepage, there was nothing happens. While I'm looking into my database, my records still available. Note: (1) to delete record, I'm following the codeigniter manual / user guide, (2) I found a message error (Undefined variable: id) after hiting the "delete" button in the front-end Any help or suggestion, please

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  • Rails Authlogic authentication method

    - by Rabbott
    Within Authlogic, is there a way that I can add conditions to the authentication method? I know by using the find_by_login_method I can specify another method to use, but when I use this I need to pass another parameter since the find_by_login_method method only passes the parameter that is deemed the 'login_field'. What I need to do is check something that is an association of the authentic model.. Here is the method I want to use # make sure that the user has access to the subdomain that they are # attempting to login to, subdomains are company names def self.find_by_email_and_company(email, company) user = User.find_by_email(email) companies = [] user.brands.each do |b| companies << b.company.id end user && companies.include?(company) end But this fails due to the fact that only one parameter is sent to the find_by_email_and_company method. The company is actually the subdomain, so in order to get it here I am just placing it in a hidden field in the form (only way I could think to get it to the model) Is there a method I can override somehow..?

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  • Rails: Modeling an optional relation in ActiveRecord

    - by Hassinus
    I would like to map a relation between two Rails models, where one side can be optionnal. Let's me be more precise... I have two models: Profile that stores user profile information (name, age,...) and User model that stores user access to the application (email, password,...). To give you more information, User model is handled by Devise gem for signup/signin. Here is the scenario of my app: 1/ When a user register, a new row is created in User table and there is an equivalent in Profile table. This leads to the following script: class User < ActiveRecord::Base belongs_to :profile end 2/ A user can create it's profile without registering (kind of public profile with public information), so a row in Profile doesn't have necessarily a User row equivalent (here is the optional relation, the 0..1 relation in UML). Question: What is the corresponding script to put in class Profile < AR::Base to map optionally with User? Thanks in advance.

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  • Why does the check for an interface fail?

    - by chobo
    I have a class that implements an interface. In another area of the code I check if that class instance contains that interface, but it doesn't work. The check to see if the class contains the interface always fails (false) when it should be true. Below is a simple representation of what I am trying to accomplish. Example public interface IModel { bool validate(); } public class SomeModel : IModel { public SomeModel { } public bool Validate() { return true; } } // Dummy method public void Run() { SomeModel model = new SomeModel(); if (model is IModel) { string message = "It worked"; } else { string message = "It failed"; } }

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  • @ExceptionHandler doesn't handle the thrown exceptions

    - by Javi
    Hello, I have a method in my controller which will handle the exceptions thrown by the application. So I have a method like this one. @Controller public class ExceptionController { @RequestMapping(value="/error") @ExceptionHandler(value={Exception.class, NullPointerException.class}) public String showError(Exception e, Model model){ return "tiles:error"; } } And to try I if it works I throw a NullPointerException in another method in other method controller: boolean a = true; if(a){ throw new NullPointerException(); } After the exception is thrown it is printed in the JSP, but it doesn't go throw my showError() method (I've set a breakpoint there and it never enters). showError() method will catch the exception and will show different error pages depending on the exception type (though now it always shows the same error page). If I go to the url /error it shows the error page so the showError() method is OK. I'm using Spring 3. What can be the problem? Thanks.

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  • defaults for to_json in Rails with :include

    - by prateekdayal
    Let us say I have a model Post which belongs to a User. To convert to json, I do something like this @reply.to_json(:include => {:user => {:only => [:email, :id]}, :only => [:title, :id]) However, I want to set some defaults for this so I don't have to specify :only everytime. I am trying to override as_json to accomplish this. When I add as_json in User model, it is called when I do @user.to_json but when user is included in @reply.to_json, my overriden as_json for User is ignored. How do I make this work? Thanks

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  • filter queryset based on list, including None

    - by jujule
    Hi all I dont know if its a django bug or a feature but i have a strange ORM behaviour with MySQL. class Status(models.Model): name = models.CharField(max_length = 50) class Article(models.Model) status = models.ForeignKey(status, blank = True, null=True) filters = Q(status__in =[0, 1,2] ) | Q(status=None) items = Article.objects.filter(filters) this returns Article items but some have other status than requested [0,1,2,None] looking at the sql query : SELECT [..] FROM `app_article` LEFT OUTER JOIN `app_status` ON (`app_article`.`status_id` = `app_status`.`id`) WHERE (`app_article`.`status_id` IN (1, 2) OR `app_status`.`id` IS NULL) ORDER BY [...] the OR app_status.id IS NULL part seems to be the cause. if i change it to OR app_article.status_id IS NULL it works correctly. How to deal with this ? Thanx.

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  • how to avoid storing several times a repeated field of a Symfony form?

    - by user454760
    Hello everybody, I am working with Symfony 1.4 and Doctrine. I have a model A with an email field. The form of A displays an input in which the user should insert the email correctly. But as everybody knows, sometimes they don't do it. To fix this I have inserted an extra field in the model (and in the form), called *repeat_email* to prevent the misspellings. Then, in the validation process, after validating all the fields, i use a global validator to compare the data of the two fields. This works, but I don't want to have the email stored two times in the database (I don't want the *repeat_email*). Is there any mechanism to use it in the validation process, but not to store it in the database? Thanks,

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  • Paperclip generating wrong URLs in Heroku

    - by Tony
    Paperclip is generating wrong URLs in Heroku. I have an Audio model which has a mp3 field as follows: class Audio < ActiveRecord::Base has_attached_file :mp3, :storage => :s3, :s3_credentials => S3_CREDENTIALS, :bucket => S3_CREDENTIALS[:bucket], :path => ":rails_root/public/system/:attachment/:id/:style/:filename", :url => "/system/:attachment/:id/:style/:filename" I am calling audio.mp3.url from a controller, and it returns http://s3.amazonaws.com/MyApp/audios/mp3s//original/96a9ae89302fdf8462ee05eb829f2e17578b144e20120908-2-11f61zr.mp3?1347135050 instead of http://s3.amazonaws.com/MyApp/audios/mp3s/000/000/004/original/96a9ae89302fdf8462ee05eb829f2e17578b144e20120908-2-11f61zr.mp3?1347135050 (which works) Why is it missing the '000/000/004' part of the route? The same model is generating the right URL when used in a view. Any help? I am using paperclip 3.2.0 and Rails 3.1.8. Any help?

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  • How can I create a sample SQLLite DB for my iPhone app?

    - by Dr Dork
    I'm diving in to iPhone development and I'm building an iPhone app that uses the Core Data framework and my first task will be to get the model setup with a few that will display it. Thus far, I have the model defined and my Managed Object Files created, but I don't have a database with any sample data. What's a quick way to create a DB that conforms to my schema? Are there any tools that can generate a sample DB using my schemas? Is there a good tool I can use to directly manipulate the data in DB for testing purposes? Thanks in advance for your help! I'm going to continue researching this question right now.

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  • DB fields not showing up in association custom queries?

    - by Kevin
    I have a notification list that the user can select different show options for different kinds of notifications along with how many results are returned. I'm keeping them in the user model because I want the custom sort to stay with the user between sessions. Here is the association in my user model: has_many :notifications, :class_name => "Notification", :foreign_key => "user_id", :conditions => ["won = ? and lost = ? and paid = ?", self.prefs_won, self.prefs_lost, self.prefs_paid], :limit => self.prefs_results.to_s But when I use the above code, Rails throws me an "unknown method" error for self.prefs_won. It is definitely a field in my database and set as a boolean value, but Rails can't find it... what's the problem?

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  • Why I should use an N-Tier Approach When using an SqlDatasource is ALOT EASIER ?

    - by The_AlienCoder
    When it comes to web development I have always tried to work SMART not HARD. So for along time My Aproach to interacting with databases in my AspNet projects has been this : 1) Create my stored procedures 2) Drag an SQLDatasource control on my aspx page 3) Bind a DataList Control to my SQLDatasource 4) Insert, Update & Delete by using my Datalist or programmatically using built in SQLDatasource methods e.g MySqlDataSource.InsertParameters["author"].DefaultValue = TextBox1.Text; MySqlDataSource.Insert(); Recently however I got a relatively easy web project. So I decided to employ a 3-tier Model...But I got exhausted halfway and just didnt seem worth it ! It seemed like I was working too HARD for a project that could have been easily accomplished by a couple of SqlDataSource Controls. So Why Is the N-Tier Model better than my Approach? Has it anything to do with performance? What are the advantages of the ObjectDataSource control over the SqlDataSource Control?

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  • MVC: Structuring Feed Output

    - by Brian Wigginton
    The framework I'm using on my project follows the MVC Pattern. I"M building JSON feeds and need to structure them in a different way then what the system gives me by default from the ORM. Where should I be handling the task of mangling and shaping my data that I'll serve up, in the model, view or controller? Right now I'm doing it in my controller, then passing that data to the view. I can see this fitting better under the Model or the View but not sure which one.

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  • What is an instance of a field called?

    - by waxwing
    This might be an odd question, but it has actually caused me some headache. In Object oriented programming, there are accepted names for key concepts. In our model, we have classes with methods and fields. Now, going to the data world: An instance of a class is called an object. An instance of a field is called... what? A value? Isn't the term value a little broad for this? I have been offered "property" as well, but isn't property also part of the model and not the data? (This is not purely academic, I am actually coding these concepts.)

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  • how to don't store a repeated field of a Symfony form?

    - by user454760
    Hello everybody, I am working with Symfony 1.4 and Doctrine. I have a model A with a email field. The form of A, display an input in which the user should insert the email correctly. But as everybody know sometiemes they don't do it. To fix this i have insert an extra field in the model (and in the form), called *repeat_email* to prevent the misspellings. Then, in the validation process, after validates all the fields, i use a global validator to compare the data of the two fields. This works, but i don't want to have the email stored two times in the database (i don't want the *repeat_email*). Is there any mechanism to use it in the validation process, but not to store it in the database? Thanks,

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