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  • How to Limit Text Characters in PHP?

    - by hateMe
    I was wondering how can I limit a users input like HTML maxlength attribute but with PHP, example would be nice? Is MySQL varchar(255) one way to limit a users character input? What are the cons of just counting on MySQL to do this?

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  • A tool for finding duplicate code in PHP

    - by Toby
    Are there any tools available that can scan multiple .php files and report back duplicated lines/chunks of code? It doesn't have to be really smart but basically give me a starting point for manual scans to improve the codebase of some of my apps.

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  • seperated mysql statement query in php

    - by stone
    So, I can run the following statements from within mysql itself successfully. SET @fname = 'point1'; SELECT * FROM country WHERE name=@fname;` But when I try to pass the query through php like this and run it, I get an error on the second line $query = "SET @fname = 'point1';"; $query .= "SELECT * FROM country WHERE name=@fname;";

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  • MySQLi Insert prepared statement via PHP

    - by Jimmy
    Howdie do, This is my first time dealing with MySQLi inserts. I had always used mysql and directly ran the queries. Apparently, not as secure as MySQLi. Anywho, I'm attempting to pass two variables into the database. For some reason my prepared statement keeps erroring out. I'm not sure if it's a syntax error, but the insert just won't work. I've updated the code to make the variables easier to read Also, the error is specifically, Error preparing statement. I've updated the code, but it's not a pHP error. It's a MySQL error as the script runs but fails at the execution of: if($stmt = $mysqli - prepare("INSERT INTO subnets (id, subnet, mask, sectionId, description, vrfId, masterSubnetId, allowRequests, vlanId, showName, permissions, pingSubnet, isFolder, editDate) VALUES ('', ?, ?, '1', '', '0', '0', '0', '0', '0', '{"3":"1","2":"2"}', '0', '0', 'NULL')")) { I'm going to enable MySQL error checking. I honestly didn't know about that. <?php error_reporting(E_ALL); function InsertIPs($decimnal,$cidr) { error_reporting(E_ALL); $mysqli = new mysqli("localhost","jeremysd_ips","","jeremysd_ips"); if(mysqli_connect_errno()) { echo "Connection Failed: " . mysqli_connect_errno(); exit(); } if($stmt = $mysqli -> prepare("INSERT INTO subnets (id, subnet, mask,sectionId,description,vrfld,masterSubnetId,allowRequests,vlanId,showName,permissions,pingSubnet,isFolder,editDate) VALUES ('',?,?,'1','','0','0','0','0','0', '{'3':'1','2':'2'}', '0', '0', NULL)")) { $stmt-> bind_param('ii',$decimnal,$cidr); if($stmt-> execute()) { echo "Row added successfully\n"; } else { $stmt->error; } $stmt -> close; } } else { echo 'Error preparing statement'; } $mysqli -> close(); } $SUBNETS = array ("2915483648 | 18"); foreach($SUBNETS as $Ip) { list($TempIP,$TempMask) = explode(' | ',$Ip); echo InsertIPs($Tempip,$Tempmask); } ?> This function isn't supposed to return anything. It's just supposed to perform the Insert. Any help would be GREATLY appreciated. I'm just not sure what I'm missing here

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  • Updating an integer defined column in a MySQL DB with PHP

    - by Zloy Smiertniy
    I have a table defined like this: create table users ( id int(10), age int(3), name varchar (50) ) I want to use a query to update just age, which is an integer, that comes from an html form. When it arrives to the method that updates it, it comes as a string, so I change it to integer with PHP and try to update the table, but it doesn't work $age = intval($age); $q2 = "UPDATE users SET age='$age' where username like '$username';"; mysql_query($q2,$con);

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  • PHP : Pattern Replacement Query.

    - by Rachel
    Currently I have ‘customer_id’ . ‘+’ . ‘operator_domain’ pattern, e.g., '123456789'.'+'.'987654321' Desired Pattern: ‘customer_id.operator_domain’ pattern, e.g., '123456789987654321' How can I achieve this using in php ?

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  • PHP class function.

    - by Jordan Pagaduan
    What is wrong with this code? <?php class users { var $user_id, $f_name, $l_name, $db_host, $db_user, $db_name, $db_table; function user_input() { $this->$db_host = 'localhost'; $this->$db_user = 'root'; $this->$db_name = 'input_oop'; $this->$db_table = 'users'; } function userInput($f_name, $l_name) { $dbc = mysql_connect($this->db_host , $this->db_user, "") or die ("Cannot connect to database : " .mysql_error()); mysql_select_db($this->db_name) or die (mysql_error()); $query = "insert into $this->db_table values (NULL, \"$f_name\", \"$l_name\")"; $result = mysql_query($query); if(!$result) die (mysql_error()); $this->userID = mysql_insert_id(); mysql_close($dbc); $this->first_name = $f_name; $this->last_name = $l_name; } function userUpdate($new_f_name, $new_l_name) { $dbc = mysql_connect($this->db_host, $this->db_user, "") or die (mysql_error()); mysql_select_db($this->db_name) or die (mysql_error()); $query = "UPDATE $this->db_table set = \"$new_f_name\" , \"$new_l_name\" WHERE user_id = \"$this->user_id\""; $result = mysql_query($query); $this->f_name = $new_f_name; $this->l_name = $new_l_name; $this->user_id = $user_id; mysql_close($dbc); } function userDelete() { $dbc = mysql_connect($this->db_host, $this->db_user, "") or die (mysql_error()); mysql_select_db($this->db_name) or die (mysql_error()); $query = "DELETE FROM $this->db_table WHERE $user_id = \"$this->user_id\""; mysql_close($dbc); } } ?> The error is: Warning: mysql_connect() [function.mysql-connect]: Access denied for user 'ODBC'@'localhost' (using password: NO) in C:\xampp\htdocs\jordan_pagaduan\class.php on line 21 Cannot connect to database : Access denied for user 'ODBC'@'localhost' (using password: NO) The code cannot define this "$this->db_host" as "localhost".

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  • Is there a simple PHP development server?

    - by pinchyfingers
    When writing web apps in Python, it brain dead easy to run a development server. Django and Google App Engine both ship with simple servers. The main feature I'm looking for is no configuration. I want something like the GAE dev server where you just pass the directory of the app as a parameter when the server is started. Is there a reason that this is more difficult with PHP?

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  • Do compiled PHP scripts exist?

    - by dabito
    Hi, I am wondering if anyone has used or read about PHP scripts compiled as a .so extension for Apache... Thing is I think I remember reading about it somewhere but dont know if such a thing exists. This looks promising, but incomplete and abandoned: http://phpcompiler.org/ Im interested because i think it could improve performance... Perhaps someone could point out a framework or apache extension that does this. Thanks!!

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  • PHP & JQuery Question?

    - by characters
    Is there a way to hide a form from my users until they click a link and then the form drops down for the user to fill out, by using PHP or JQuery if so how? Is there a tutorial that will teach me how to do this?

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  • redirect images to php script

    - by Jonathan
    I want to be able to redirect all requests to navigate to an image to a php script which will then show the image but with a nav bar at the top. However using rewrite (im using IIS btw) means that I can't embed those images. Any help will be greatly appreciated.

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  • Set php file permissions so only my server's curl can run

    - by robr
    I have a PHP script that I don't want anyone to be able to run through their browser. It sends emails and is called via curl by my server's cron, yet needs to be in the public www directory. What permissions or owner do I need to set the file to to allow only my server's curl to execute (or do I mean read) the file? I'm on centos. Thanks!

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  • [php] call_user_func_array problems

    - by Knarf
    I have a class with this in self::$DB = new PDO("mysql:dbname=$dbname;host:=127.0.0.1" , 'root' , ''); and then this public static function __callStatic($name, $arguments) { return call_user_func_array(array('self::$DB', $name), $arguments); } How does I make it right/work? Warning: call_user_func_array() expects parameter 1 to be a valid callback, class 'self::$DB' not found in D:\Mine Dokumenter\My Dropbox\www\Framework 3\database.class.php on line 19

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