Search Results

Search found 19155 results on 767 pages for 'url redirection'.

Page 221/767 | < Previous Page | 217 218 219 220 221 222 223 224 225 226 227 228  | Next Page >

  • need help with mvc & routes

    - by geoff
    I'm very new to MVC and I'm trying to get a new site set up using it. For SEO reasons we need to make the url of a page something like "Recruiter/4359/John_Smith" or basically {controller}/{id}/{name}. I have that working when I create the url in the code behind like so... //r is a recruiter object that is part of the results for the view r.Summary = searchResult.Summary + "... &lt;a href=\"/Recruiter/" + r.Id + "/" + r.FirstName + "_" + r.LastName + "\"&gt;Read More&lt;/a&gt;" But when I am using the collection of results from a search in my view and iterating through them I am trying to create another link to the same page doing something like <%=Html.ActionLink<RecruiterController>(x => x.Detail((int)r.Id), r.RecruiterName)%> but that doesn't work. When I use that code in the view it gives me a url in the form of /Recruiter/Detail/4359 I was told by a coworker that I should use the Html.ActionLink to create the link in both the view and the controller so that if the route changes in the future it will automatically work. Unfortunately he wasn't sure how to do that in this case. So, my problems are... How can I make the Html.ActionLink work in the view to create a url like I need (like r.Summary above)? How do I use the Html.ActionLink in a controller instead of hardcoding the link like I have above?

    Read the article

  • ASP.NET MVC twitter/myspace style routing

    - by Astrofaes
    Hi guys, This is my first post after being a long-time lurker - so please be gentle :-) I have a website similar to twitter, in that people can sign up and choose a 'friendly url', so on my site they would have something like: mydomain.com/benjones I also have root level static pages such as: mydomain.com/about and of course my homepage: mydomain.com/ I'm new to ASP.NET MVC 2 (in fact I just started today) and I've set up the following routes to try and achieve the above. public static void RegisterRoutes(RouteCollection routes) { routes.IgnoreRoute("{resource}.axd/{*pathInfo}"); routes.IgnoreRoute("content/{*pathInfo}"); routes.IgnoreRoute("images/{*pathInfo}"); routes.MapRoute("About", "about", new { controller = "Common", action = "About" } ); // User profile sits at root level so check for this before displaying the homepage routes.MapRoute("UserProfile", "{url}", new { controller = "User", action = "Profile", url = "" } ); routes.MapRoute("Home", "", new { controller = "Home", action = "Index", id = "" } ); } For the most part this works fine, however, my homepage is not being triggered! Essentially, when you browser to mydomain.com, it seems to trigger the User Profile route with an empty {url} parameter and so the homepage is never reached! Any ideas on how I can show the homepage?

    Read the article

  • JQuery SelectList Option Changed doesn't refresh

    - by Jean-Philippe
    Hi. I have this select list: <select url="/Admin/SubCategories" name="TopParentId" id="ParentList"> <option value="">Please select a parent category</option> <option value="1" selected="selected">New Store</option> <option value="2">Extensions</option> <option value="3">Remodel</option> <option value="4">Bespoke Signage</option> <option value="5">Tactical Signage</option> <option value="6">Size Chart</option> <option value="7">Contact Info</option> </select> As you can see the option 1 is marked as selected. When I change the selection, I use this code to do an ajax call to get some values to populate a new select list: $("#ParentList").unbind("change"); $("#ParentList").change(function() { var itemId = $(this).val(); var url = $(this).attr("url"); var options; $.getJSON(url, itemId, function(data) { var defaultoption = '<option value="0">Please select a sub-category</option>'; options += defaultoption; $.each(data, function(index, optionData) { var option = '<option value="' + optionData.valueOf + '">' + optionData.Text + '</option>'; options += option; }); $("#SubParentList").html(options); }); }); My problem is that whenever I change the selection, the itemId is always the id of option 1, because it is marked as selected. It doesn't pick up the value of the option it is being changed too. Can someone please enlighten me of their knowledge. Regards, Jean-Philippe

    Read the article

  • Webview shouldoverrideurlloading doesn't work

    - by Zak
    I have this code in my app: public class Home extends Activity{ @Override public void onCreate(Bundle savedInstanceState){ super.onCreate(savedInstanceState); setContentView(R.layout.home); final ProgressDialog progressBar; if(isOnline()){ WebView webView = (WebView) findViewById(R.id.home_web); webView.setBackgroundColor(Color.parseColor(getString(R.color.colore_bg))); webView.getSettings().setJavaScriptEnabled(true); webView.getSettings().setBuiltInZoomControls(true); webView.getSettings().setPluginsEnabled(true); webView.setWebViewClient(new MyWebViewClient()); progressBar = ProgressDialog.show(this,getString(R.string.caricamento),getString(R.string.attendere)); webView.setWebViewClient(new WebViewClient(){ public void onPageFinished(WebView view, String url) { if (progressBar.isShowing()) { progressBar.dismiss(); } } }); webView.loadUrl("http://www.mysite.com/android.php"); }else{ Toast.makeText(this,getString(R.string.no_connessione),Toast.LENGTH_LONG).show(); } } private class MyWebViewClient extends WebViewClient { @Override public boolean shouldOverrideUrlLoading(WebView view, String url) { System.out.println("here"); if (Uri.parse(url).getHost().equals("mysite.com")) { // This is my web site, so do not override; let my WebView load the page return false; } // Otherwise, the link is not for a page on my site, so launch another Activity that handles URLs Intent intent = new Intent(Intent.ACTION_VIEW, Uri.parse(url)); startActivity(intent); return true; } } public boolean isOnline(){ ConnectivityManager cm=(ConnectivityManager)getSystemService(Context.CONNECTIVITY_SERVICE); NetworkInfo ni = cm.getActiveNetworkInfo(); if(ni==null){ return false; } return ni.isConnected(); } } The shouldOverrideUrlLoading doesn't work, neither print the system.out, it seems to be never called. How can I repair this? I need to open all the link (except the main page www.mysite.com/iphone.php) in the default browser

    Read the article

  • jQuery preventing RedirectToAction from working?

    - by DaveDev
    I'm trying to redirect the user if they login successfully but the code I have on my page seems to be preventing the redirection from working. If I remove the jQuery below the redirection works. Can somebody tell me tell me if there's something I'm doing wrong? Thanks I have the following Action: [AcceptVerbs(HttpVerbs.Post)] public ActionResult Login(User user) { var myErrors = new Dictionary<string, string>(); try { if (ModelState.IsValid) { if (userRepository.ValidUser(user)) { return RedirectToAction("Index", "Group", new {page = (int?)null}); } else { return Json("Username or password seems to be incorrect"); } } else { foreach (KeyValuePair<string, ModelState> keyValuePair in ViewData.ModelState) { if (keyValuePair.Value.Errors.Count > 0) { List<string> errors = new List<string>(); myErrors.Add(keyValuePair.Key, keyValuePair.Value.Errors[0].ErrorMessage); } } return Json(myErrors); } } catch (Exception) { return Json("Invalid"); } } and the following code on my page: <script language="javascript" type="text/javascript"> $(document).ready(function() { $("#SaveSuccess").hide(); $("#btnLogin").click(function() { $("form").submit(function(event) { var formData = $(this).serialize(); $.post($(this).attr("action"), formData, function(res) { ShowErrors(res); if (res == true) { $("#SaveSuccess").text("Saved"); } else { $("#divError").html(res); } $("#SaveSuccess").fadeIn(100); }, "json"); return false; }); }); }); </script>

    Read the article

  • Why does my Perl CGI program fail with "Software error: ..."?

    - by kiran
    When I try to run my Perl CGI program, the returned web page tells me: Software error: For help, please send mail to the webmaster (root@localhost), giving this error message and the time and date of the error. Here is my code in one of the file: #!/usr/bin/perl use lib "/home/ecoopr/ecoopr.com/CPAN"; use CGI; use CGI::FormBuilder; use CGI::Session; use CGI::Carp (fatalsToBrowser); use CGI::Session; use HTML::Template; use MIME::Base64 (); use strict; require "./db_lib.pl"; require "./config.pl"; my $query = CGI-new; my $url = $query-url(); my $hostname = $query-url(-base = 1); my $login_url = $hostname . '/login.pl'; my $redir_url = $login_url . '?d=' . $url; my $domain_name = get_domain_name(); my $helpful_msg = $query-param('m'); my $new_trusted_user_fname = $query-param('u'); my $action = $query-param('a'); $new_trusted_user_fname = MIME::Base64::decode($new_trusted_user_fname); ####### Colin: Added July 12, 2009 ####### my $view = $query-param('view'); my $offset = $query-param('offset'); ####### Colin: Added July , 2009 ####### #print $session-header; #print $new_trusted_user; my $helpful_msg_txt = qq[]; my $helpful_msg_div = qq[]; if ($helpful_msg)

    Read the article

  • Android: Problems downloading images and converting to bitmaps

    - by Mike
    Hi all, I am working on an application that downloads images from a url. The problem is that only some images are being correctly downloaded and others are not. First off, here is the problem code: public Bitmap downloadImage(String url) { HttpClient client = new DefaultHttpClient(); HttpResponse response = null; try { response = client.execute(new HttpGet(url)); } catch (ClientProtocolException cpe) { Log.i(LOG_FILE, "client protocol exception"); return null; } catch (IOException ioe) { Log.i(LOG_FILE, "IOE downloading image"); return null; } catch (Exception e) { Log.i(LOG_FILE, "Other exception downloading image"); return null; } // Convert images from stream to bitmap object try { Bitmap image = BitmapFactory.decodeStream(response.getEntity().getContent()); if(image==null) Log.i(LOG_FILE, "image conversion failed"); return image; } catch (Exception e) { Log.i(LOG_FILE, "Other exception while converting image"); return null; } } So what I have is a method that takes the url as a string argument and then downloads the image, converts the HttpResponse stream to a bitmap by means of the BitmapFactory.decodeStream method, and returns it. The problem is that when I am on a slow network connection (almost always 3G rather than Wi-Fi) some images are converted to null--not all of them, only some of them. Using a Wi-Fi connection works perfectly; all the images are downloaded and converted properly. Does anyone know why this is happening? Or better, how can I fix this? How would I even go about testing to determine the problem? Any help is awesome; thank you!

    Read the article

  • PHP Form - Edit & Delete via Text File Db

    - by Jax
    hi, I pieced together the script below from various tutorials, examples, etc... Right now the script currently: Saves Id, Name, Url with a "|" delimiter to a text file Db like: 1|John|http://www.john.com| 2|Mark|http://www.mark.com| 3|Fred|http://www.fred.com| But I'm having a hard time trying to make the "UPDATE" and "DELETE" buttons work. Can someone please post code which will: let me update/save any changed data for that row (for UPDATE button) let me delete that row (for DELETE button) PLEASE copy n paste the code below and try for yourself. I would like to keep the output format of the script below too. thanks D- $file = "data.txt"; $name = $_POST['name']; $url = $_POST['url']; $data = file('data.txt'); $i = 1; foreach ($data as $line) { $line = explode('|', $line); $i++; } if (isset($_POST['submits'])) { $fp = fopen($file, "a+"); fwrite($fp, $i."|".$name."|".$url."|\n"); fclose($fp); } ? '); } ?

    Read the article

  • If attacker has original data, and encrypted data, can they determine the passphrase?

    - by Brad Cupit
    If an attacker has several distinct items (for example: e-mail addresses) and knows the encrypted value of each item, can the attacker more easily determine the secret passphrase used to encrypt those items? Meaning, can they determine the passphrase without resorting to brute force? This question may sound strange, so let me provide a use-case: User signs up to a site with their e-mail address Server sends that e-mail address a confirmation URL (for example: https://my.app.com/confirmEmailAddress/bill%40yahoo.com) Attacker can guess the confirmation URL and therefore can sign up with someone else's e-mail address, and 'confirm' it without ever having to sign in to that person's e-mail account and see the confirmation URL. This is a problem. Instead of sending the e-mail address plain text in the URL, we'll send it encrypted by a secret passphrase. (I know the attacker could still intercept the e-mail sent by the server, since e-mail are plain text, but bear with me here.) If an attacker then signs up with multiple free e-mail accounts and sees multiple URLs, each with the corresponding encrypted e-mail address, could the attacker more easily determine the passphrase used for encryption? Alternative Solution I could instead send a random number or one-way hash of their e-mail address (plus random salt). This eliminates storing the secret passphrase, but it means I need to store that random number/hash in the database. The original approach above does not require this extra table. I'm leaning towards the the one-way hash + extra table solution, but I still would like to know the answer: does having multiple unencrypted e-mail addresses and their encrypted counterparts make it easier to determine the passphrase used?

    Read the article

  • How to display data in spinner from json

    - by user1605913
    I am retrieving values from a json url and then storing it in a string variable. Now I want to display that value in a spinner. I have created an array list in my strings.xml file. The xml file contains following code: <string name="credit_card_title">Card Type</string> <string-array name="credit_card"> <item >Select</item> <item >Visa</item> <item >MC</item> <item >Amex</item> <item >Discover</item> my spinner code is: <Spinner android:id="@+id/crdtcrd_crdtype" android:layout_width="match_parent" android:layout_height="wrap_content" android:entries="@array/credit_card" android:prompt="@string/credit_card_title" /> After retriving the value from the json url I am storing it in variable name String cardtype Now how can I display the value of cardtype in the Spinner crtdcrd_crdtype.... the json url is: http://mygogolfteetime.com/iphone/login/[email protected]/123456 From this URL I have to retrieve the value of cardtype and after retrieving the value i have to display it in the spinner.. There are different values for cardype like visa, mc, amex and discover All these values are in my strings.xml file and after retrieving the value I have to display it in Spinner.. Help needed still not able to find the solution.. Thanks in advance...

    Read the article

  • Calling a jQuery plugin inside itself

    - by Real Tuty
    I am trying to create a comet like thing. I have a plugin that collects data from a php page. The problem is that i dont know how to call the plugin inside itself. If it were a function i could go like this: function j () {setTimeout(j(), 1000);}, but i am using a jQuery plugin. Here is my plugin code: (function($) { $.fn.watch = function(ops) { var $this_ = this, setngs = $.extend({ 'type' : 'JSON', 'query' : 'GET', 'url' : '', 'data' : '', 'wait' : 1000 }, ops); if (setngs.type === '') { return false; } else if (setngs.query === '') { return false; } else if (setngs.url === '') { return false; } else if (setngs.wait === '') { return false; } else if (setngs.wait === 0) { setngs.wait = 1000; } var xhr = $.ajax({ type : setngs.query, dataType : setngs.type, url : setngs.url, success : function(data) { var i = 0; for (i = 0; i < data.length; i++) { var html = $this_.html(), str = '<li class="post" id="post-' + data[i].id + '"><div class="inner"><div class="user">' + data[i].user + '</div><div class="body">' + data[i].body + '</div></div></li>'; $this_.html(str + html); } setTimeout($this_, 1000); } }); }; })(jQuery); where it says setTimeout($this_, 1000); this is where im having trouble. I don't know what to call the plugin as. $this_ is what I thought might work but I am wrong. That is what i need to replace. Thanks for your help.

    Read the article

  • Any one point me how to customize facebook share

    - by Venkat
    I am trying to share my own custom url, image, title and description using Facebook and twitter. I am having lot of images and videos in my website. So i want to make my content viral on social websites. I am trying to keep share options for both facebook and twitter for everything individually. If some one share one image i want that image in the sharing thumbnail and url will be the page url with my own title, description. Based on the url i will point the user to that pic in my website. I tried in the below way. Facebook share: <a href="javascript:;" onclick="window.open('http://www.facebook.com/share.php?u=your_page_url','facebook share','resizable=yes,width=700,height=500,scrollbars=yes,status=yes')"><img alt="facebook" src="yourimage.jpg" /></a> Twitter share: <a href="javascript:;" onclick="window.open('https://twitter.com/share','twitter share','resizable=yes,width=700,height=500,scrollbars=yes,status=yes')"><img alt="twitter" src="yourimage.jpg" /></a>

    Read the article

  • Android - BitmapFactory.decodeByteArray - OutOfMemoryError (OOM)

    - by Bob Keathley
    I have read 100s of article about the OOM problem. Most are in regard to large bitmaps. I am doing a mapping application where we download 256x256 weather overlay tiles. Most are totally transparent and very small. I just got a crash on a bitmap stream that was 442 Bytes long while calling BitmapFactory.decodeByteArray(....). The Exception states: java.lang.OutOfMemoryError: bitmap size exceeds VM budget(Heap Size=9415KB, Allocated=5192KB, Bitmap Size=23671KB) The code is: protected Bitmap retrieveImageData() throws IOException { URL url = new URL(imageUrl); InputStream in = null; OutputStream out = null; HttpURLConnection connection = (HttpURLConnection) url.openConnection(); // determine the image size and allocate a buffer int fileSize = connection.getContentLength(); if (fileSize < 0) { return null; } byte[] imageData = new byte[fileSize]; // download the file //Log.d(LOG_TAG, "fetching image " + imageUrl + " (" + fileSize + ")"); BufferedInputStream istream = new BufferedInputStream(connection.getInputStream()); int bytesRead = 0; int offset = 0; while (bytesRead != -1 && offset < fileSize) { bytesRead = istream.read(imageData, offset, fileSize - offset); offset += bytesRead; } // clean up istream.close(); connection.disconnect(); Bitmap bitmap = null; try { bitmap = BitmapFactory.decodeByteArray(imageData, 0, bytesRead); } catch (OutOfMemoryError e) { Log.e("Map", "Tile Loader (241) Out Of Memory Error " + e.getLocalizedMessage()); System.gc(); } return bitmap; } Here is what I see in the debugger: bytesRead = 442 So the Bitmap data is 442 Bytes. Why would it be trying to create a 23671KB Bitmap and running out of memory?

    Read the article

  • UIAlertView Will not show

    - by John
    I have a program that is requesting a JSON string. I have created a class that contains the connect method below. When the root view is coming up, it does a request to this class and method to load up some data for the root view. When I test the error code (by changing the URL host to 127.0.0.1), I expect the Alert to show. Behavior is that the root view just goes black, and the app aborts with no alert. No errors in debug mode on the console, either. Any thoughts as to this behavior? I've been looking around for hints to this for hours to no avail. Thanks in advance for your help. Note: the conditional for (error) is called, as well as the UIAlertView code. - (NSString *)connect:(NSString *)urlString { NSString *jsonString; UIApplication *app = [UIApplication sharedApplication]; app.networkActivityIndicatorVisible = YES; NSError *error = nil; NSURLResponse *response = nil; NSURL *url = [[NSURL alloc] initWithString:urlString]; NSURLRequest *req = [NSURLRequest requestWithURL:url cachePolicy:NSURLRequestReloadIgnoringCacheData timeoutInterval:10]; NSData *_response = [NSURLConnection sendSynchronousRequest: req returningResponse: &response error: &error]; if (error) { /* inform the user that the connection failed */ //AlertWithMessage(@"Connection Failed!", message); UIAlertView *alert = [[UIAlertView alloc] initWithTitle:@"Oopsie!" message:@"Unable to connect! Try later, thanks." delegate:nil cancelButtonTitle:@"OK" otherButtonTitles: nil]; [alert show]; [alert release]; } else { jsonString = [[[NSString alloc] initWithData:_response encoding:NSUTF8StringEncoding] autorelease]; } app.networkActivityIndicatorVisible = NO; [url release]; return jsonString; }

    Read the article

  • Java Applet 411 Content Length

    - by user1903006
    I am new to Java. I wrote an applet with a gui that sends results (int w and int p) to a server, and I get the "411 Length Required" error. What am I doing wrong? How do you set a Content-Length? This is the method that communicates with the server: public void sendPoints1(int w, int p){ try { String url = "http://somename.com:309/api/Results"; String charset = "UTF-8"; String query = String.format("?key=%s&value=%s", URLEncoder.encode(String.valueOf(w), charset), URLEncoder.encode(String.valueOf(p), charset)); String length = String.valueOf((url + query).getBytes("UTF-8").length); HttpURLConnection connection = (HttpURLConnection) new URL(url + query).openConnection(); connection.setRequestMethod("POST"); connection.setRequestProperty("Content-Length", length); connection.connect(); System.out.println("Responce Code: " + connection.getResponseCode()); System.out.println("Responce Message: " + connection.getResponseMessage()); } catch (Exception e) { System.err.println(e.getMessage()); } }

    Read the article

  • Simple search form passing the searched string through GET

    - by Brian Roisentul
    Hi, I'd like my Search form to return the following url after submit: /anuncios/buscar/the_text_I_searched My form is the following: <% form_for :announcement, :url => search_path(:txtSearch) do |f| %> <div class="searchBox" id="basic"> <%= text_field_tag :txtSearch, params[:str_search].blank? ? "Busc&aacute; tu curso r&aacute;pido y f&aacute;cil." : params[:str_search], :maxlength=> 100, :class => "basicSearch_inputField", :onfocus => "if (this.value=='Busc&aacute; tu curso r&aacute;pido y f&aacute;cil.') this.value=''", :onblur => "if(this.value=='') { this.value='Busc&aacute; tu curso r&aacute;pido y f&aacute;cil.'; return false; }" %> <div class="basicSearch_button"> <input type="submit" value="BUSCAR" class="basicSearch_buttonButton" /> <br /><a href="#" onclick="javascript:jQuery('#advance').modal({opacity:60});">Busqueda avanzada</a> </div> </div> <% end %> My routes' line for search_path is this: map.search '/anuncios/buscar/:str_search', :controller => 'announcements', :action => 'search' Well, this will work if I manually type the url I want in the brower, but definitely, if you look at the form's url, you'll find a ":txtSearch" parameter, which is not giving me the actual value of the text field when the form is submitted. And that's what I'd like to get! Could anybody help me on this?

    Read the article

  • Catch hibernate exceptions with errorpage handler?

    - by membersound
    I'm catching all exceptions within: java.lang.Throwable /page.xhtml java.lang.Error /page.xhtml But what If I get eg a hibernate ex: org.hibernate.exception.ConstraintViolationException Do I have to define error-pages for EVERY maybe occuring exception? Can't I just say "catch every exception"? Update Redirect on a 404 works. But on a throwable does not! <servlet> <servlet-name>Faces Servlet</servlet-name> <servlet-class>javax.faces.webapp.FacesServlet</servlet-class> <load-on-startup>1</load-on-startup> </servlet> <servlet-mapping> <servlet-name>Faces Servlet</servlet-name> <url-pattern>*.jsf</url-pattern> <url-pattern>*.xhtml</url-pattern> </servlet-mapping> <error-page> <exception-type>java.lang.Throwable</exception-type> <location>/error.xhtml</location> </error-page> <error-page> <error-code>404</error-code> <location>/error.xhtml</location> </error-page>

    Read the article

  • A question on webpage representation in Java

    - by Gemma
    Hello there. I've followed a tutorial and came up with the following method to read the webpage content into a CharSequence public static CharSequence getURLContent(URL url) throws IOException { URLConnection conn = url.openConnection(); String encoding = conn.getContentEncoding(); if (encoding == null) { encoding = "ISO-8859-1"; } BufferedReader br = new BufferedReader(new InputStreamReader(conn.getInputStream(),encoding)); StringBuilder sb = new StringBuilder(16384); try { String line; while ((line = br.readLine()) != null) { sb.append(line); sb.append('\n'); } } finally { br.close(); } return sb; } It will return a representation of the webpage specified by the url. However,this representation is hugely different from what I use "view page source" in my Firefox,and since I need to scrape data from the original webpage(some data segement in the original "view page source" file),it will always fail to find required text on this Java representation. Did I go wrong somewhere?I need your advice guys,thanks a lot for helping!

    Read the article

  • how to connect to MSSQL using activerecord, JDBC, JTDS and Integrated Security

    - by Rob
    As per the above, I've tried: establish_connection(:adapter => "jdbcmssql", :url => "jdbc:jtds:sqlserver://myserver:1433/mydatabase;domain='mynetwork';", :username => 'user', :password=>'pass' ) establish_connection(:adapter => "jdbcmssql", :url => 'jdbc:jtds:sqlserver://myserver:1433/mydatabase;domain="mynetwork";user="mynetwork\user"' ) establish_connection(:adapter => "jdbcmssql", :url => "jdbc:jtds:sqlserver://myserver:1433/mydatabase;domain='mynetwork';", :username=>'user' ) establish_connection(:adapter => "jdbcmssql", :url => "jdbc:jtds:sqlserver://myserver:1433/mydatabase;domain='mynetwork';integratedSecurity='true'", :username=>'user' ) .. and various other combinations. Each time I get: net/sourceforge/jtds/jdbc/SQLDiagnostic.java:368:in `addDiagnostic': java.sql.SQLException: Login failed for user ''. The user is not associated with a trusted SQL Server connection. (NativeException) Any tips? Thanks, activerecord (2.3.5) activerecord-jdbc-adapter (0.9.6) activerecord-jdbcmssql-adapter (0.9.6) jdbc-jtds (1.2.5) jruby 1.4.0 (ruby 1.8.7 patchlevel 174) (2009-11-02 69fbfa3) (Java HotSpot(TM) Client VM 1.6.0_18) [x86-java]

    Read the article

  • how to get contents of site use HTTPS

    - by cashmoney
    ex of site using ssl ( HTTPs ) : https://www.eb2a.com 1 - i tried to get its content using file_get_contents, but not work and give error ex : <?php $contents = file_get_contents("https://www.eb2a.com/"); echo $contents; ?> 2 - i tried to use fopen, but not work and give error ex: <?php $url = 'https://www.eb2a.com/'; $contents = fopen($url, 'r'); echo "$contents"; ?> 3 - i tried to use CURL, but not work and give BLANK PAGE ex : function cURL($url, $ref, $header, $cookie, $p){ $ch = curl_init(); curl_setopt($ch, CURLOPT_URL, $url); curl_setopt($ch, CURLOPT_SSL_VERIFYHOST, 0); curl_setopt($ch, CURLOPT_USERAGENT, $_SERVER['HTTP_USER_AGENT']); curl_setopt($ch, CURLOPT_REFERER, $ref); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, 0); if ($p) { curl_setopt($ch, CURLOPT_CUSTOMREQUEST, "POST"); curl_setopt($ch, CURLOPT_POST, 1); curl_setopt($ch, CURLOPT_POSTFIELDS, $p); } $result = curl_exec($ch); curl_close($ch); if ($result){ return $result; }else{ return ''; } } $file = cURL('https://www.eb2a.com/','https://www.eb2a.com/',0,0,null); echo $file any one have any idea ??

    Read the article

  • initWithContentsOfURL seems to have issues with "long" URLs

    - by samsam
    Hi there I'm facing a rather strange Issue when trying to load data from an XML-Webservice. The webservice allows me to pass separated identifiers within the URL-Request. It is therefore possible for the URL to become rather long (240 characters). If I open said URL in firefox the response arrives as planned, if I execute the following code xmlData remains empty. NSString *baseUrl = [[NSString alloc] initWithString:[[[[kSearchDateTimeRequestTV stringByReplacingOccurrencesOfString:@"{LANG}" withString:appLanguageCode] stringByReplacingOccurrencesOfString:@"{IDENTIFIERS}" withString:myIdentifiers] stringByReplacingOccurrencesOfString:@"{STARTTICKS}" withString:[NSString stringWithFormat:@"%@", [[startTime getTicks] descriptionWithLocale:nil]]] stringByReplacingOccurrencesOfString:@"{ENDTICKS}" withString:[NSString stringWithFormat:@"%@", [[endTime getTicks] descriptionWithLocale:nil]]]]; NSLog(baseUrl); //looks good, if openend in browser, returnvalue is ok urlRequest = [NSURL URLWithString:baseUrl]; NSString *xmlData = [NSString stringWithContentsOfURL:urlRequest encoding:NSUTF8StringEncoding error:&err]; //err is nil, therefore i guess everything must be ok... :( NSLog(xmlData); //nothing... is there any sort of URL-Length restriction, does the same problem happened to anyone of you as well? whats a good workaround? thanks for your help sam

    Read the article

  • How to parse XML string value using jQuery ?

    - by Vijay
    Hi All, I am new to jquery. I am trying to parse xml string using jquery. I have found one sample code; $(function() { $.get('data.xml', function(d) { var data = ""; var startTag = "<table border='1' id='mainTable'><tbody><tr><td style=\"width: 120px\">Name</td><td style=\"width: 120px\">Link</td></tr>"; var endTag = "</tbody></table>"; $(d).find('url').each(function() { var $url = $(this); var link = $url.find('link').text(); var name = $url.find('name').text(); data += '<tr><td>' + name + '</td>'; data += '<td>' + link + '</td></tr>'; }) $("#content").html(startTag + data + endTag); ; }); }); In this case, I am able to parse and fetch the values from xml file. but now what I am looking for is instead of reading file from desk, I want to read the xml from string. Say, instead of data.xml I want to parse string which consists of well formed xml. does anyone have any idea about this ? Thanks in advance

    Read the article

  • How to get a checkout-able revision info from subversion?

    - by zhongshu
    I want to check a svn url and to get the latest revision, then checkout it, I don't want to use HEAD because I will compare the latest revision to others. so I use "svn info" to get the "Last Changed Rev" for the url like this: D:\Project>svn info svn://.../branches/.../path Path: ... URL: svn://.../branches/.../path Repository Root: svn://yt-file-srv/ Repository UUID: 9ed5ffd7-7585-a14e-96b2-4aab7121bb21 Revision: 2400 Node Kind: directory Last Changed Author: xxx Last Changed Rev: 2396 Last Changed Date: 2010-03-12 09:31:52 +0800 but, I found the 2396 revision is not checkout-able, because this path is in a branch copied from trunk, and the 2396 is the revision modified in the trunk. so when I use svn checkout -r 2396, I will get a workcopy for the path in the trunk, then I can not do checkin for the branch. D:\Project>svn checkout svn://.../branches/.../path -r 2396 workcopy ..... ..... D:\Project>svn info workcopy Path: workcopy URL: svn://.../trunk/.../path Repository Root: svn://yt-file-srv/ Repository UUID: 9ed5ffd7-7585-a14e-96b2-4aab7121bb21 Revision: 2396 Node Kind: directory Schedule: normal Last Changed Author: xxx Last Changed Rev: 2396 Last Changed Date: 2010-03-12 09:31:52 +0800 So, my question is how to get a checkout-able revision for the branch path, for this example, I want to get 2397 (because 2397 is the revision which copy occur). And I know "svn log" can get the info, but "svn log" output maybe very long and parse it will be difficult than "svn info". I just want know which revision is the latest checkout-able revision for the path.

    Read the article

  • CSS Sprite for images which have vertical as well as horizontal repeats

    - by Rachel
    I have four images, one of which has background repeat property in horizontal direction and three of which have background repeat in vertical direction. I have different CSS classes which currently uses this images as under: .sb_header_dropdown { background: url(images/shopping_dropdown_bg.gif) repeat-y top left; padding: 8px 3px 8px 15px; } .shopping_basket_dropdown .sb_body { background: url(images/shopping_dropdown_body_bg.png) repeat-y top left; margin: 0; padding: 5px 9px 5px 8px; position: relative; z-index: 99999; } .checkout_cart .co_header_left { background: url(images/bg.gif) repeat-x 0 -150px; overflow: hidden; padding-left: 3px; } .sb_dropdown_footer { background: url(images/shopping_dropdown_footer_bg.png) repeat-y top left; clear: both; height: 7px; font-size: 0; } So here am making 4 HTTP Request and I want to implement CSS Sprite for all 4 images such that I can reduce the number of HTTP Request from 4 to 1, also thing to keep in mind is that here we have background repeat for all 4 images, either on x-direction or on y-direction and so how should sprite be created and how it can be used in the CSS to reduce the number of HTTP request. I hope this question is clear.

    Read the article

  • Post valuse and upload Image to php server in android

    - by lawat
    I am trying to upload image from android phone to php server with additional values,the method is post my php file look like this if($_POST['val1']){ if($_POST['val2']){ if($_FILE['image']){ ...... } } }else{ echo "Value not found"; } I am doing is URL url=new URL("http://www/......../myfile.php"); HttpURLConnection con=(HttpURLConnection) url.openConnection(); con.setDoInput(true); con.setDoOutput(true); con.setUseCaches(false); con.setRequestMethod("POST");//Enable http POST con.setRequestProperty("Connection", "Keep-Alive"); con.setRequestProperty("Content-Type", "multipart/form-data;boundary="+"****"); connection.setRequestProperty("uploaded_file", imagefilePath); DataOutputStream ostream = new DataOutputStream( con.getOutputStream()); String res=("Content-Disposition: form-data; name=\"val1\""+val1+"****"+ "Content-Disposition: form-data; name=\"val2\""+val2+"****" "Content-Disposition: form-data; name=\"image\";filename=\"" + imagefilePath +"\""+"****"); outputStream.writeBytes(res); my actual problem is values are not posting so first if condition get false and else section is executed that is it give value not found please help me

    Read the article

< Previous Page | 217 218 219 220 221 222 223 224 225 226 227 228  | Next Page >