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  • Me.Invoke in VB.NET doesn't actually "Invoke" - threads stall on Invoke statement

    - by rwmnau
    I've got the following code: Public Delegate Sub SetStatusBarTextDelegate(ByVal StatusText As String) Private Sub SetStatusBarText(ByVal StatusText As String) If Me.InvokeRequired Then Me.Invoke(New SetStatusBarTextDelegate(AddressOf SetStatusBarText), StatusText) Else Me.labelScanningProgress.Text = StatusText End If End Sub The problem is that, when I call the "SetStatusBarText" sub from another thread, InvokeRequired is True (as it should be), but then my threads stall on the Me.Invoke statement - pausing execution shows them all just sitting there, not actually invoking anything. Any thoughts about why the threads seem to be afraid of the Invoke?

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  • How do I get the ListBox from a ListBoxItem?

    - by Shimmy
    Sub FindAncestor(Of TParent, reference As DependencyObject) As TParent 'find the parent ListBox container End Sub 'Usage Sub Handle(lbi As ListBoxItem) Dim lb = GetListBox(lbi) End Sub I have a button in a ListBoxItem datatemplate, I want in the handler of the button to access the parent ListBox (this is the way I want to access it, since it's all nested in other DataTemplates, ItemsControls and stuff).

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  • Calling Class from another File ASP.NET VB.NET

    - by davemackey
    Lets say I have a class like this in class1.vb: Public Class my_class Public Sub my_sub() Dim myvar as String myvar = 10 Session("myvar") = myvar End Sub End Class Then I have a ASP.NET page with a code-behind file, default.aspx and default.aspx.vb and I want to call my_class. I'm doing the following, but it doesn't work: Imports my_app.my_class Partial Public Class _default Inherits System.Web.UI.Page Protected Sub Page_Load(ByVal sender as Object, ByVal e as System.EventArgs) Handles Me.Load my_class() End Sub End Class I get a "Reference to a non-shared member requires an object reference"

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  • Stack Trace of cross-thread exceptions with Invoke

    - by the_lotus
    When an exception happens after calling Invoke, .NET shows the stack trace as if the error happens while calling Invoke. Example below: .NET will say the error happen in UpdateStuff instead of UpdateStuff - BadFunction Is there a way to catch the "real" exception and show the correct stack trace? Private Sub UpdateStuff() If (Me.InvokeRequired) Then Me.Invoke(New UpdateStuffDelegate(AddressOf UpdateStuff)) Return End If Badfunction() End Sub Private Sub BadFunction() Dim o As Object o.ToString() End Sub

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  • VBA Excel - Workbook_SheetChange

    - by user2947014
    Hopefully this question hasn't already been asked, I tried searching for an answer and couldn't find anything. This is probably a simple question, but I am writing my first macro in excel and am having a problem that I can't find out a solution to. I wrote a couple of macros that basically sum up columns dynamically (so that the number of rows can change and the formula moves down automatically) based on a value in another column of the same row, and I call those macros from the event Workbook_SheetChange. The problem I'm having is, I change a cell's value from my macro to display the result of the sum, and this then calls Workbook_SheetChange again, which I do not want. Right now it works, but I can trace it and see that Workbook_SheetChange is being called multiple times. This is preventing me from adding other cell changes to the macros, because then it results in an infinite loop. I want the macros to run every time a change is made to the sheet, but I don't see any way around allowing the macros to change a cell's value, so I don't know what to do. I will paste my code below, in case it is helpful. Private Sub Workbook_SheetChange(ByVal Sh As Object, ByVal Target As Range) Dim Row As Long Dim Col As Long Row = Target.Row Col = Target.Column If Col <> 7 Then Range("G" & Row).Select Selection.Formula = "=IF(F" & Row & "=""Win"",E" & Row & ",IF(F" & Row & "=""Loss"",-D" & Row & ",0))" Target.Select End If Call SumRiskColumn End Sub Private Sub Workbook_SheetCalculate(ByVal Sh As Object) Call SumOutcomeColumn End Sub Sub SumOutcomeColumn() Dim N As Long N = Cells(Rows.Count, "A").End(xlUp).Row Cells(N + 1, "G").Formula = "=SUM(G2:G" & N & ")" End Sub Sub SumRiskColumn() Dim N As Long N = Cells(Rows.Count, "A").End(xlUp).Row Dim CurrTotalRisk As Long CurrTotalRisk = 0 For i = 2 To N If IsEmpty(ActiveSheet.Cells(i, 6)) And Not IsEmpty(ActiveSheet.Cells(i, 1)) And Not IsEmpty(ActiveSheet.Cells(i, 2)) And Not IsEmpty(ActiveSheet.Cells(i, 3)) Then CurrTotalRisk = CurrTotalRisk + ActiveSheet.Cells(i, 4).Value End If Next i Cells(N + 1, "D").Value = CurrTotalRisk End Sub Thank you for any help you can give me! I really appreciate it.

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  • Access Filter VBA

    - by user569709
    Hi, I'm trying to use a filter in vba like this: Private Sub Form_Load() Me.Filter = "[Alvo] = " & AlvoAtual Me.FilterOn = True Me.Requery End Sub where AlvoAtual is global variable, but nothin happens. When I change the AlvoAtual for a specifc value nothin happens too. Like this: Private Sub Form_Load() Me.Filter = "[Alvo] = 'AAAA'" Me.FilterOn = True Me.Requery End Sub Someone knows the problem? Thank you.

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  • How to get the header of the parent node of a selected TreeViewItem?

    - by Dabblernl
    I have this TreeView: Main Node Header="Main" Sub Node Header="Sub1" Final Node Header="Item1" Final Node Header="Item2" Sub Node Header="Sub 2" Final Node Header="Item1" Final Node Header="Item2" I have two textboxes that are bound to this TreeView. One has its Text property bound to the TreeView's SelectedItem property and works OK. The other TextBox I want to bind to the Header text of the Sub Node directly above the selected Item. How do I reference it?

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  • sorting nested list, allow only li to be sorted witin the same ul

    - by Y.G.J
    what i want to achive is: sorting the main ul is working but not all the time - i will try to fix that my own but if there is a problem with the code here and not the one in proccess-sortable - tell me. moving li in the main ul is ok but the sub or the sub of the sub is having problem - i can drag something from one sub to it's sub or the other way too - i don't want that to happend. i want to be able to drag li and by selecting that one that only this ul group will send to proccess-sortable to be updated - how can i catch the specific ul of li i am draging? $(document).ready(function() { $("#test-list").sortable({ items: "> li", handle : '.handle', axis: 'y', opacity: 0.6, update : function () { var order = $('#test-list').sortable('serialize'); $("#info").load("process-sortable.asp?"+order+"&id=catid&order=orderid&table=tblCats"); } }); $("#test-sub").sortable({ containment: "ul", items: "li", handle : '.handle2', axis: 'y', opacity: 0.6, update : function () { var order = $('ul').sortable('serialize'); $("#info").load("process-sortable.asp?"+order+"&id=catid&order=orderid&table=tblCats"); } }); }); this is the html part <ul id="test-list"> <li id="listItem_10">first<img align="middle" src="Themes/arrow.png" class="handle" /></li> <li id="listItem_8">second<img align="middle" src="Themes/arrow.png" class="handle" /> <ul id="test-sub"> <li id="listItem_4><img align="middle" src="Themes/arrow.png" class="handle2" /></li> <li id="listItem_3"><img align="middle" src="Themes/arrow.png" class="handle2" /></li> <ul id="test-sub"> <li id="listItem_9"><img align="middle" src="Themes/arrow.png" class="handle2" /></li> </ul> </li> </ul> </li> </ul>

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  • problem with jquery sortable of ul with childrens - how to allow li to be sorted only on the same le

    - by Y.G.J
    $(document).ready(function() { $("#test-list").sortable({ items: "> li", handle : '.handle', axis: 'y', opacity: 0.6, update : function () { var order = $('#test-list').sortable('serialize'); $("#info").load("process-sortable.asp?"+order+"&id=catid&order=orderid&table=tblCats"); } }); $("#test-sub").sortable({ containment: "ul", items: "li", handle : '.handle2', axis: 'y', opacity: 0.6, update : function () { var order = $('ul').sortable('serialize'); $("#info").load("process-sortable.asp?"+order+"&id=catid&order=orderid&table=tblCats"); } }); }); <ul id="test-list"> <li id="listItem_10">first<img align="middle" src="Themes/arrow.png" class="handle" /></li> <li id="listItem_8">second<img align="middle" src="Themes/arrow.png" class="handle" /> <ul id="test-sub"> <li id="listItem_4><img align="middle" src="Themes/arrow.png" class="handle2" /></li> <li id="listItem_3"><img align="middle" src="Themes/arrow.png" class="handle2" /></li> <ul id="test-sub"> <li id="listItem_9"><img align="middle" src="Themes/arrow.png" class="handle2" /></li> </ul> </li> </ul> </li> </ul> the problems i have: sorting the main ul is working but not all the time - i will try to fix that my own but if there is a problem with the code here and not the one in proccess-sortable - tell me. moving li in the main ul is ok but the sub or the sub of the sub is having problem - i can drag something from one sub to it's sub or the other way too - i don't want that to happend. i want to be able to drag li and by selecting that one that only this ul group will send to proccess-sortable to be updated - how can i catch the specific ul of li i am draging?

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  • Invalid cast exception

    - by user127147
    I have a simple application to store address details and edit them. I have been away from VB for a few years now and need to refreash my knowledge while working to a tight deadline. I have a general Sub responsible for displaying a form where user can add contact details (by pressing button add) and edit them (by pressing button edit). This sub is stored in a class Contact. The way it is supposed to work is that there is a list with all the contacts and when new contact is added a new entry is displayed. If user wants to edit given entry he or she selects it and presses edit button Public Sub Display() Dim C As New Contact C.Cont = InputBox("Enter a title for this contact.") C.Fname = frmAddCont.txtFName.Text C.Surname = frmAddCont.txtSName.Text C.Address = frmAddCont.txtAddress.Text frmStart.lstContact.Items.Add(C.Cont.ToString) End Sub I call it from the form responsible for adding new contacts by Dim C As New Contact C.Display() and it works just fine. However when I try to do something similar using the edit button I get errors - "Unable to cast object of type 'System.String' to type 'AddressBook.Contact'." Dim C As Contact If lstContact.SelectedItem IsNot Nothing Then C = lstContact.SelectedItem() C.Display() End If I think it may be something simple however I wasn't able to fix it and given short time I have I decided to ask for help here. I have updated my class with advice from other members and here is the final version (there are some problems however). When I click on the edit button it displays only the input box for the title of the contact and actually adds another entry in the list with previous data for first name, second name etc. Public Class Contact Public Contact As String Public Fname As String Public Surname As String Public Address As String Private myCont As String Public Property Cont() Get Return myCont End Get Set(ByVal value) myCont = Value End Set End Property Public Overrides Function ToString() As String Return Me.Cont End Function Sub NewContact() FName = frmAddCont.txtFName.ToString frmStart.lstContact.Items.Add(FName) frmAddCont.Hide() End Sub Public Sub Display() Dim C As New Contact C.Cont = InputBox("Enter a title for this contact.") C.Fname = frmAddCont.txtFName.Text C.Surname = frmAddCont.txtSName.Text C.Address = frmAddCont.txtAddress.Text 'frmStart.lstContact.Items.Add(C.Cont.ToString) frmStart.lstContact.Items.Add(C) End Sub End Class

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  • Xcode xcconfig file and build rules

    - by g-Off
    I have an Xcode project that contains many sub-projects. The main project file and all sub-projects have the same xcconfig file. Some of the sub-projects currently have a build rule set on them to use the Intel compiler for C++ files. I'm wondering if there is a way to move this build rule into the xcconfig file so that I can easily turn on or off the Intel compiler for C++ files by changing just the one xcconfig file instead of having to modify the build rule for each sub-project

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  • Weird bug on powerpoint vba

    - by asksuperuser
    I have a "mynote" textbox on a slide. If I execute: Sub test() If ActiveWindow.Selection.SlideRange.Shapes("mynote").Visible Then MsgBox "ok" End If end sub It works. But If I attach a shape with this macro: Sub test(oShape As Shape) If ActiveWindow.Selection.SlideRange.Shapes("mynote").Visible Then MsgBox "ok" End If end sub It doesn't work (no error message, no "ok" message)

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  • Application Design in Interface Builder Challenge

    - by Sheehan Alam
    I want to design an app that launches other sub-apps. Main View will contain 4 buttons. Clicking on each button respectively will launch the other sub-apps. Each sub-app will have a UITabBarController which has its own different views. At any point I want the user to be able to go back to the Main View from any of the sub-apps. I am not sure how to design this in IB.

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  • Custom Command WPF

    - by Sachin Gaur
    I have an application that contains Menu and sub menus. I have attached Appliocation Commands to some of the sub menu items such as Cut, Copy and Paste. I also have some other menu items that do not have application commands. How could I add a custom command binding to those sub menu items? I have gone through this artcile but unable to attach event to my sub menu items.

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  • VB.NET FileSystemWatcher Multiple Change Events

    - by John
    Hi. I have the following code: Imports System.IO Public Class Blah Public Sub New() InitializeComponent() Dim watcher As New FileSystemWatcher("C:\") watcher.EnableRaisingEvents = True AddHandler watcher.Changed, AddressOf watcher_Changed End Sub Private Sub watcher_Changed(ByVal sender As Object, ByVal e As FileSystemEventArgs) MsgBox(e.FullPath) End Sub End Class When I run it and save changes to a file on my C drive, the code works great, except it executes the watcher_Changed() method four times. Any idea why? The changeType is "4" every time. Thanks.

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  • sorting nested list, allow only li to be sorted witin the same ul

    - by Y.G.J
    $(document).ready(function() { $("#test-list").sortable({ items: "> li", handle : '.handle', axis: 'y', opacity: 0.6, update : function () { var order = $('#test-list').sortable('serialize'); $("#info").load("process-sortable.asp?"+order+"&id=catid&order=orderid&table=tblCats"); } }); $("#test-sub").sortable({ containment: "ul", items: "li", handle : '.handle2', axis: 'y', opacity: 0.6, update : function () { var order = $('ul').sortable('serialize'); $("#info").load("process-sortable.asp?"+order+"&id=catid&order=orderid&table=tblCats"); } }); }); <ul id="test-list"> <li id="listItem_10">first<img align="middle" src="Themes/arrow.png" class="handle" /></li> <li id="listItem_8">second<img align="middle" src="Themes/arrow.png" class="handle" /> <ul id="test-sub"> <li id="listItem_4"><img align="middle" src="Themes/arrow.png" class="handle2" /></li> <li id="listItem_3"><img align="middle" src="Themes/arrow.png" class="handle2" /></li> <ul id="test-sub"> <li id="listItem_9"><img align="middle" src="Themes/arrow.png" class="handle2" /></li> </ul> </li> </ul> </li> </ul> the problems i have: sorting the main ul is working but not all the time - i will try to fix that my own but if there is a problem with the code here and not the one in proccess-sortable - tell me. moving li in the main ul is ok but the sub or the sub of the sub is having problem - i can drag something from one sub to it's sub or the other way too - i don't want that to happend. i want to be able to drag li and by selecting that one that only this ul group will send to proccess-sortable to be updated - how can i catch the specific ul of li i am draging?

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  • how to find out which textbox is currenlty selected.

    - by abcdefghijklmnopqrstuvwxyz
    I have 3 text-boxes, how do I find out which text-box is currently selected (has focus). I am unable to come up with anything. Public Class Form1 Public activeTextBox As TextBox = CType(Me.ActiveControl, TextBox) Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click activeTextBox.Text = activeTextBox.Text & "This is text 1" End Sub Private Sub Button2_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button2.Click activeTextBox.Text = activeTextBox.Text & "This is the text 2" End Sub End Class

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  • DNS Forwarding using CNAME

    - by user569698
    Hi. I have a domain named "domain.com" and subdomain "sub.domain.com" I want users be redirected to "sub.domain.com" when entering "domain.com" This is my DNS configurations right now: domain.com points to a.a.a.a sub points to a.a.a.a direct points to a.a.a.a ftp points to a.a.a.b www points to a.a.a.a www.sub points to a.a.a.a What should I do to achieve the redirection and what is my misconfiguration right now?

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  • REST web service keeps first POST parametrs

    - by Diego
    I have a web service in REST, designed with Java and deployed on Tomcat. This is the web service structure: @Path("Personas") public class Personas { @Context private UriInfo context; /** * Creates a new instance of ServiceResource */ public Personas() { } @GET @Produces("text/html") public String consultarEdad (@QueryParam("nombre") String nombre) { ConectorCliente c = new ConectorCliente("root", "cafe.sql", "test"); int edad = c.consultarEdad(nombre); if (edad == Integer.MIN_VALUE) return "-1"; return String.valueOf(edad); } @POST @Produces("text/html") public String insertarPersona(@QueryParam("nombre") String msg, @QueryParam("edad") int edad) { ConectorCliente c = new ConectorCliente("usr", "passwd", "dbname"); c.agregar(msg, edad); return "listo"; } } Where ConectorCliente class is MySQL connector and querying class. So, I had tested this with the @GET actually doing POST work, any user inputed data and information from ma Java FX app and it went direct to webservice's database. However, I changed so the CREATE operation was performed through a webservice responding to an actual POST HTTP request. However, when I run the client and add some info, parameters go OK, but in next time I input different parameters it'll input the same. I run this several times and I can't get the reason of it. This is the clients code: public class WebServicePersonasConsumer { private WebTarget webTarget; private Client client; private static final String BASE_URI = "http://localhost:8080/GetSomeRest/serviciosweb/"; public WebServicePersonasConsumer() { client = javax.ws.rs.client.ClientBuilder.newClient(); webTarget = client.target(BASE_URI).path("Personas"); } public <T> T insertarPersona(Class<T> responseType, String nombre, String edad) throws ClientErrorException { String[] queryParamNames = new String[]{"nombre", "edad"}; String[] queryParamValues = new String[]{nombre, edad}; ; javax.ws.rs.core.Form form = getQueryOrFormParams(queryParamNames, queryParamValues); javax.ws.rs.core.MultivaluedMap<String, String> map = form.asMap(); for (java.util.Map.Entry<String, java.util.List<String>> entry : map.entrySet()) { java.util.List<String> list = entry.getValue(); String[] values = list.toArray(new String[list.size()]); webTarget = webTarget.queryParam(entry.getKey(), (Object[]) values); } return webTarget.request().post(null, responseType); } public <T> T consultarEdad(Class<T> responseType, String nombre) throws ClientErrorException { String[] queryParamNames = new String[]{"nombre"}; String[] queryParamValues = new String[]{nombre}; ; javax.ws.rs.core.Form form = getQueryOrFormParams(queryParamNames, queryParamValues); javax.ws.rs.core.MultivaluedMap<String, String> map = form.asMap(); for (java.util.Map.Entry<String, java.util.List<String>> entry : map.entrySet()) { java.util.List<String> list = entry.getValue(); String[] values = list.toArray(new String[list.size()]); webTarget = webTarget.queryParam(entry.getKey(), (Object[]) values); } return webTarget.request(javax.ws.rs.core.MediaType.TEXT_HTML).get(responseType); } private Form getQueryOrFormParams(String[] paramNames, String[] paramValues) { Form form = new javax.ws.rs.core.Form(); for (int i = 0; i < paramNames.length; i++) { if (paramValues[i] != null) { form = form.param(paramNames[i], paramValues[i]); } } return form; } public void close() { client.close(); } } And this this the code when I perform the operations in a Java FX app: String nombre = nombreTextField.getText(); String edad = edadTextField.getText(); String insertToDatabase = consumidor.insertarPersona(String.class, nombre, edad); So, as parameters are taken from TextFields, is quite odd why second, third, fourth and so on POSTS post the SAME.

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  • How add loading image using jquery?

    - by user244394
    I'm working on a form, <form id="myform" class="form"> </form> that gets submitted to the server using jquery ajax. How can I refresh the form on success to show the updated form information and add a spinner until the form loads? here is my html and jquery snippet <div class="container"> <div class="page-header"> <div class="span2"> <!--Sidebar content--> <img src="img/emc_logo.png" title="EMC" > </div> <div class="span6"> <h2 class="form-wizard-heading">Configuration</h2> </div> </div> <form id="myform" class="form"> </form> </div> <!-- /container --> <!-- Modal --> <div id="myModal" class="modal hide fade" tabindex="-1" role="dialog" aria-labelledby="myModalLabel" aria-hidden="true"> <div class="modal-header"> <button type="button" class="close" data-dismiss="modal" aria-hidden="true">&times;</button> <h3 id="myModalLabel">Configuration Changes</h3> <p><span class="label label-important">Please review your changes before submitting. Submitting the changes will result in rebooting the cluster</span></p> </div> <div class="modal-body"> <table class="table table-condensed table-striped" id="display"></table> </div> <div class="modal-footer"> <button id="cancel" class="btn" data-dismiss="modal" aria-hidden="true">Close</button> <button id="save" class="btn btn-primary">Save changes</button> </div> </div> //Jquery part $(document).ready(function () { $('input').hover(function () { $(this).popover('show') }); // On mouseout destroy popout $('input').mouseout(function () { $(this).popover('destroy') }); $('#myform').on('submit', function (ev) { ev.preventDefault(); var data = $(this).serializeObject(); json_data = JSON.stringify(data); $('#myModal').modal('show'); $.each(data, function (key, val) { var tablefeed = $('<tr><td>' + key + '</td><td id="' + key + '">' + val + '</td><tr>').appendTo('#display'); }); $(".modal-body").html(tablefeed); }); $("#cancel").click(function () { $("#display").empty(); }); $(function () { $("#save").click(function () { // validate and process form here alert("button submitted" + json_data); $.ajax({ type: "POST", url: "somefile.json.", data: json_data, contentType: 'application/json', success: function (data, textStatus, xhr) { console.log(arguments); console.log(xhr.status); alert("Your form has been submitted: " + textStatus + xhr.status); }, error: function (jqXHR, textStatus, errorThrown) { alert(jqXHR.responseText + " - " + errorThrown + " : " + jqXHR.status); } }); }); }); });

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  • Why ((Integer) weightModel.getObject()).intValue(); throws exception

    - by yakup
    I am learning Wicket by "Enjoying Web Development with Wicket" book. And in an example: int weight = ((Integer) weightModel.getObject()).intValue(); is used. When I click Submit button it throws exception. But after changed the code to: int weight=Integer.parseInt( (String) weightModel.getObject()); It works fine. What is the reason for throwing the exception? The full code: GetRequest.java package myapp.postage; import java.util.HashMap; import java.util.Map; import org.apache.wicket.markup.html.WebPage; import org.apache.wicket.markup.html.form.Form; import org.apache.wicket.markup.html.form.TextField; import org.apache.wicket.model.Model; @SuppressWarnings("unchecked") public class GetRequest extends WebPage { private Model weightModel=new Model(); private Model patronCodeModel=new Model(); private Map patronCodeToDiscount; public GetRequest(){ patronCodeToDiscount=new HashMap(); patronCodeToDiscount.put("p1", new Integer(90)); patronCodeToDiscount.put("p2", new Integer(95)); Form form=new Form("form"){ @Override protected void onSubmit(){ int weight = ((Integer) weightModel.getObject()).intValue(); Integer discount=(Integer)patronCodeToDiscount.get(patronCodeModel.getObject()); int postagePerKg=10; int postage=weight*postagePerKg; if(discount!=null){ postage=postage*discount.intValue()/100; } ShowPostage showPostage=new ShowPostage(postage); setResponsePage(showPostage); } }; TextField weight=new TextField("weight",weightModel); form.add(weight); TextField patronCode=new TextField("patronCode",patronCodeModel); form.add(patronCode); add(form); } } The html file GetRequest.html: <!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"> <html> <form wicket:id="form"> <table> <tr> <td>Weight</td> <td><input type="text" wicket:id="weight"/></td> </tr> <tr> <td>Patron code:</td> <td><input type="text" wicket:id="patronCode"/></td> </tr> <tr> <td></td> <td><input type="submit"/></td> </tr> </table> </form> </html>

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  • Submiting a Form without Refreshing the page with jQuery and Ajax Not updating MySQL database.

    - by HEEEEEEELP
    I'm a newbie to JQuery and have a problem, when I click submit button on the form everything says registration was successful but my MYSQL database was not updated everything worked fine until I tried to add the JQuery to the picture. Can someone help me fix this problem so my database is updated? Thanks Here is the JQuery code. $(function() { $(".save-button").click(function() { var address = $("#address").val(); var address_two = $("#address_two").val(); var city_town = $("#city_town").val(); var state_province = $("#state_province").val(); var zipcode = $("#zipcode").val(); var country = $("#country").val(); var email = $("#email").val(); var dataString = 'address='+ address + '&address_two=' + address_two + '&city_town=' + city_town + '&state_province=' + state_province + '&zipcode=' + zipcode + '&country=' + country + '$email=' + email; if(address=='' || address_two=='' || city_town=='' || state_province=='' || zipcode=='' || country=='' || email=='') { $('.success').fadeOut(200).hide(); $('.error').fadeOut(200).show(); } else { $.ajax({ type: "POST", url: "http://localhost/New%20Project/home/index.php", data: dataString, success: function(){ $('.success').fadeIn(200).show(); $('.error').fadeOut(200).hide(); } }); } return false; }); }); Here is the PHP code. if (isset($_POST['contact_info_submitted'])) { // Handle the form. // Query member data from the database and ready it for display $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT users.*, contact_info.* FROM users INNER JOIN contact_info ON contact_info.user_id = users.user_id WHERE users.user_id=3"); $user_id = mysqli_real_escape_string($mysqli, htmlentities('3')); $address = mysqli_real_escape_string($mysqli, htmlentities($_POST['address'])); $address_two = mysqli_real_escape_string($mysqli, htmlentities($_POST['address_two'])); $city_town = mysqli_real_escape_string($mysqli, htmlentities($_POST['city_town'])); $state_province = mysqli_real_escape_string($mysqli, htmlentities($_POST['state_province'])); $zipcode = mysqli_real_escape_string($mysqli, htmlentities($_POST['zipcode'])); $country = mysqli_real_escape_string($mysqli, htmlentities($_POST['country'])); $email = mysqli_real_escape_string($mysqli, strip_tags($_POST['email'])); //If the table is not found add it to the database if (mysqli_num_rows($dbc) == 0) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"INSERT INTO contact_info (user_id, address, address_two, city_town, state_province, zipcode, country, email) VALUES ('$user_id', '$address', '$address_two', '$city_town', '$state_province', '$zipcode', '$country', '$email')"); } //If the table is in the database update each field when needed if ($dbc == TRUE) { $dbc = mysqli_query($mysqli,"UPDATE contact_info SET address = '$address', address_two = '$address_two', city_town = '$city_town', state_province = '$state_province', zipcode = '$zipcode', country = '$country', email = '$email' WHERE user_id = '$user_id'"); } if (!$dbc) { // There was an error...do something about it here... print mysqli_error($mysqli); return; } } Here is the XHTML code. <form method="post" action="index.php"> <fieldset> <ul> <li><label for="address">Address 1: </label><input type="text" name="address" id="address" size="25" class="input-size" value="<?php if (isset($_POST['address'])) { echo $_POST['address']; } else if(!empty($address)) { echo $address; } ?>" /></li> <li><label for="address_two">Address 2: </label><input type="text" name="address_two" id="address_two" size="25" class="input-size" value="<?php if (isset($_POST['address_two'])) { echo $_POST['address_two']; } else if(!empty($address_two)) { echo $address_two; } ?>" /></li> <li><label for="city_town">City/Town: </label><input type="text" name="city_town" id="city_town" size="25" class="input-size" value="<?php if (isset($_POST['city_town'])) { echo $_POST['city_town']; } else if(!empty($city_town)) { echo $city_town; } ?>" /></li> <li><label for="state_province">State/Province: </label> <?php echo '<select name="state_province" id="state_province">' . "\n"; foreach($state_options as $option) { if ($option == $state_province) { echo '<option value="' . $option . '" selected="selected">' . $option . '</option>' . "\n"; } else { echo '<option value="'. $option . '">' . $option . '</option>'."\n"; } } echo '</select>'; ?> </li> <li><label for="zipcode">Zip/Post Code: </label><input type="text" name="zipcode" id="zipcode" size="5" class="input-size" value="<?php if (isset($_POST['zipcode'])) { echo $_POST['zipcode']; } else if(!empty($zipcode)) { echo $zipcode; } ?>" /></li> <li><label for="country">Country: </label> <?php echo '<select name="country" id="country">' . "\n"; foreach($countries as $option) { if ($option == $country) { echo '<option value="' . $option . '" selected="selected">' . $option . '</option>' . "\n"; } else if($option == "-------------") { echo '<option value="' . $option . '" disabled="disabled">' . $option . '</option>'; } else { echo '<option value="'. $option . '">' . $option . '</option>'."\n"; } } echo '</select>'; ?> </li> <li><label for="email">Email Address: </label><input type="text" name="email" id="email" size="25" class="input-size" value="<?php if (isset($_POST['email'])) { echo $_POST['email']; } else if(!empty($email)) { echo $email; } ?>" /><br /><span>We don't spam or share your email with third parties. We respect your privacy.</span></li> <li><input type="submit" name="submit" value="Save Changes" class="save-button" /> <input type="hidden" name="contact_info_submitted" value="true" /> <input type="submit" name="submit" value="Preview Changes" class="preview-changes-button" /></li> </ul> </fieldset> </form>

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  • How can I cache a Subversion password on a server, without storing it in unencrypted form?

    - by Zilk
    My Subversion server only provides access via HTTPS; support for svn+ssh has been dropped because we wanted to avoid creating system users on that machine just for SVN access. Now I'm trying to provide a way for users to cache their passwords for a while, without leaving them stored on the filesystem in unencrypted form. This is no problem for Gnome or KDE users, because they can use gnome-keyring and kwallet, respectively. IIRC, TortoiseSVN has a similar caching mechanism, too. But what about users on a non-GUI system? Some context: in this case, we have a development/testing server where one project has been checked out into the Apache htdocs directory. Development for this project is almost complete, and only minor text/layout changes are performed directly on this server. Nevertheless, the changes should be checked into the repository. There's no kwallet and no gnome-keyring on this system, and the ssh-agent can't help because the repository is accessed via https instead of svn+ssh. As far as I know, that leaves them the choice of entering the password every time they talk to the SVN server, or storing it in an insecure way. Is there any way to get something like what gnome-keyring and kwallet provide in a non-GUI environment?

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  • Apache restart does not load new php.ini

    - by Tiffany Walker
    Never had this problem till updated CPanel today? Maybe that is part the problem? I only have the one php.ini file # /usr/local/bin/php --info | grep php.ini Configure Command => './configure' '--disable-cgi' '--disable-fileinfo' '--enable-bcmath' '--enable-calendar' '--enable-exif' '--enable-ftp' '--enable-gd-native-ttf' '--enable-libxml' '--enable-magic-quotes' '--enable-mbstring' '--enable-pdo=shared' '--enable-soap' '--enable-sockets' '--enable-zip' '--prefix=/usr/local' '--with-bz2' '--with-config-file-path=/usr/local/lib' '--with-config-file-scan-dir=/usr/local/lib/php.ini.d' '--with-curl=/opt/curlssl/' '--with-curlwrappers' '--with-freetype-dir=/usr' '--with-gd' '--with-imap=/opt/php_with_imap_client/' '--with-imap-ssl=/usr' '--with-jpeg-dir=/usr' '--with-kerberos' '--with-libdir=lib64' '--with-libexpat-dir=/usr' '--with-libxml-dir=/opt/xml2' '--with-libxml-dir=/opt/xml2/' '--with-mcrypt=/opt/libmcrypt/' '--with-mysql=/usr' '--with-mysql-sock=/var/lib/mysql/mysql.sock' '--with-mysqli=/usr/bin/mysql_config' '--with-openssl=/usr' '--with-openssl-dir=/usr' '--with-pcre-regex=/opt/pcre' '--with-pdo-mysql=shared' '--with-pdo-sqlite=shared' '--with-pic' '--with-png-dir=/usr' '--with-pspell' '--with-sqlite=shared' '--with-tidy=/opt/tidy/' '--with-xmlrpc' '--with-xpm-dir=/usr' '--with-xsl=/opt/xslt/' '--with-zlib' '--with-zlib-dir=/usr' '--with-gettext' Configuration File (php.ini) Path => /usr/local/lib Loaded Configuration File => /usr/local/lib/php.ini Scan this dir for additional .ini files => /usr/local/lib/php.ini.d # /usr/bin/php --info | grep php.ini <tr><td class="e">Configure Command </td><td class="v"> &#039;./configure&#039; &#039;--disable-fileinfo&#039; &#039;--enable-bcmath&#039; &#039;--enable-calendar&#039; &#039;--enable-exif&#039; &#039;--enable-ftp&#039; &#039;--enable-gd-native-ttf&#039; &#039;--enable-libxml&#039; &#039;--enable-magic-quotes&#039; &#039;--enable-mbstring&#039; &#039;--enable-pdo=shared&#039; &#039;--enable-soap&#039; &#039;--enable-sockets&#039; &#039;--enable-zip&#039; &#039;--prefix=/usr&#039; &#039;--with-bz2&#039; &#039;--with-config-file-path=/usr/local/lib&#039; &#039;--with-config-file-scan-dir=/usr/local/lib/php.ini.d&#039; &#039;--with-curl=/opt/curlssl/&#039; &#039;--with-curlwrappers&#039; &#039;--with-freetype-dir=/usr&#039; &#039;--with-gd&#039; &#039;--with-imap=/opt/php_with_imap_client/&#039; &#039;--with-imap-ssl=/usr&#039; &#039;--with-jpeg-dir=/usr&#039; &#039;--with-kerberos&#039; &#039;--with-libdir=lib64&#039; &#039;--with-libexpat-dir=/usr&#039; &#039;--with-libxml-dir=/opt/xml2&#039; &#039;--with-libxml-dir=/opt/xml2/&#039; &#039;--with-mcrypt=/opt/libmcrypt/&#039; &#039;--with-mysql=/usr&#039; &#039;--with-mysql-sock=/var/lib/mysql/mysql.sock&#039; &#039;--with-mysqli=/usr/bin/mysql_config&#039; &#039;--with-openssl=/usr&#039; &#039;--with-openssl-dir=/usr&#039; &#039;--with-pcre-regex=/opt/pcre&#039; &#039;--with-pdo-mysql=shared&#039; &#039;--with-pdo-sqlite=shared&#039; &#039;--with-pic&#039; &#039;--with-png-dir=/usr&#039; &#039;--with-pspell&#039; &#039;--with-sqlite=shared&#039; &#039;--with-tidy=/opt/tidy/&#039; &#039;--with-xmlrpc&#039; &#039;--with-xpm-dir=/usr&#039; &#039;--with-xsl=/opt/xslt/&#039; &#039;--with-zlib&#039; &#039;--with-zlib-dir=/usr&#039; </td></tr> <tr><td class="e">Configuration File (php.ini) Path </td><td class="v">/usr/local/lib </td></tr> <tr><td class="e">Loaded Configuration File </td><td class="v">/usr/local/lib/php.ini </td></tr> <tr><td class="e">Scan this dir for additional .ini files </td><td class="v">/usr/local/lib/php.ini.d </td></tr> everytime I restart apache I still seem to be running the old one. Nothing changes. I removed phpinfo() and ini_set() from the php.ini but I still can't use them. # service httpd -k restart [Fri Oct 26 15:27:10 2012] [warn] module hostinglimits_module is already loaded, skipping [Fri Oct 26 15:27:10 2012] [warn] NameVirtualHost 127.0.0.1:8081 has no VirtualHosts There is also no php.ini files under the vhosts or .htaccess. # /usr/bin/php -v PHP 5.3.15 (cgi-fcgi) (built: Aug 4 2012 21:33:58) Copyright (c) 1997-2012 The PHP Group Zend Engine v2.3.0, Copyright (c) 1998-2012 Zend Technologies with eAccelerator v0.9.6.1, Copyright (c) 2004-2010 eAccelerator, by eAccelerator with the ionCube PHP Loader v4.2.2, Copyright (c) 2002-2012, by ionCube Ltd., and with Zend Guard Loader v3.3, Copyright (c) 1998-2010, by Zend Technologies with Suhosin v0.9.33, Copyright (c) 2007-2012, by SektionEins GmbH and # /usr/local/bin/php -v PHP 5.3.15 (cli) (built: Aug 4 2012 21:34:27) Copyright (c) 1997-2012 The PHP Group Zend Engine v2.3.0, Copyright (c) 1998-2012 Zend Technologies with eAccelerator v0.9.6.1, Copyright (c) 2004-2010 eAccelerator, by eAccelerator with the ionCube PHP Loader v4.2.2, Copyright (c) 2002-2012, by ionCube Ltd., and with Zend Guard Loader v3.3, Copyright (c) 1998-2010, by Zend Technologies with Suhosin v0.9.33, Copyright (c) 2007-2012, by SektionEins GmbH Nothing shows up in the error logs either. The only errors we get are under the vhost's with error_log saying phpinfo and ini_set are disabled. EDIT: Both php binaries use the same php.ini file EDIT: Running php as mod_fgcid.so with suexec EDIT: From SSH I see the correct values for PHP from the php.ini file being loaded from both binaries When using php from apache [26-Oct-2012 20:25:34 UTC] PHP Warning: phpinfo() has been disabled for security reasons in /home/jake/public_html/phpinfo.php on line 1 EDIT: /usr/bin/php is the correct PHP file. Forgot to mention. It is the one in the wrapper script.

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