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  • YUI vs jQuery, for css style layouts

    - by tony
    Hi Complete novice question. I've used jQuery a bit, YUI not at all and know very little about it. I work on a website thats IE specific, we're now looking at making it cross browser. jQuery seems great at hiding the differences between browsers from a javascript point of view. However in terms of css layout is it YUI that I should really be looking at? thanks

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  • MYSQL - Query to check against other table (hard to explain...)

    - by Sam
    I have a query that gets a list of emails who have subscribed for a newsletter trial which lasts 30 days.. $thirty = time() - 3024000; SELECT c.email FROM tbl_clients AS c JOIN tbl_clientoptions AS o ON o.client = c.id WHERE o.option = 'newsletter' AND c.datecreated $thirty What I want to do is do a check in that same query so it also returns clients OVER 30 days old if they have the tbl_clientoptions.option = 'trialoverride' (ie; a row in the client options table with the value "trialoverride") basic columns are: TBL_CLIENTS id,name,email,datecreated TBL_CLIENTOPTIONS id,client,option

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  • Selecting count(*) while checking for a value in the results

    - by Rob
    SELECT COUNT(*) as Count, IF(sch.HomeTeamID = 34,true,false) AS Hawaii FROM schedule sch JOIN schools s ON s.ID = 83 WHERE (sch.HomeTeamID = 83 OR sch.AwayTeamID = 83) AND sch.SeasonID = 4 I'm trying to use count() to simplify my result but also include a field that represents wether any of the results' specific column contained a certain value. Is this possible? I'd basically like a row response with all the info I need.

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  • PHP MySQL query help

    - by user547794
    Hello, I am trying to use this query to return every instance where the variable $d['userID'] is equal to the User ID in a separate table, and then echo the username tied to that user ID. Here's what I have so far: $uid = $d['userID']; $result = mysql_query("SELECT u.username FROM users u LEFT JOIN comments c ON c.userID = u.id WHERE u.id = $uid;")$row = mysql_fetch_assoc($result); echo $row['username'];

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  • Why closed contours are guaranteed here?

    - by user198729
    Quoted from here: BW = edge(I,'zerocross',thresh,h) specifies the zero-cross method, using the filter h. thresh is the sensitivity threshold; if the argument is empty ([]), edge chooses the sensitivity threshold automatically. If you specify a threshold of 0, the output image has closed contours, because it includes all the zero crossings in the input image. I don't understand it,can someone elaborate?

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  • Website Design Templates

    - by user347834
    I am looking fr someone to make me two website templates for my site for free. Here is a quick design of what I want:(Took me 2 minutes in Paint) http:/ /i50.tinypic.com/33p9aut.jpg (You have to push backspace on the first link to join up the http:/ and the other /)and http://i50.tinypic.com/2qmogoo.jpg Email me at [email protected] or [email protected] for more information

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  • Get top rated item using AVG mysql

    - by user1876234
    I want to find top rated item using AVG function in mysql, right now my query looks like this: SELECT a.title, AVG(d.rating) as rating FROM in8ku_content a JOIN in8ku_content_ratings d ON a.id = d.article_id ORDER BY rating DESC Problem is that it takes AVG of all items and the result is not accurate, what should be changed here to get correct result ? Tables: in8ku_content [id, title] in8ku_content_ratings [id, article_id, rating]

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  • What is the best way to find the period of a (repeating) list in Mathematica?

    - by Arnoud Buzing
    What is the best way to find the period in a repeating list? For example: a = {4, 5, 1, 2, 3, 4, 5, 1, 2, 3, 4, 5, 1, 2} has repeat {4, 5, 1, 2, 3} with the remainder {4, 5, 1, 2} matching, but being incomplete. The algorithm should be fast enough to handle longer cases, like so: b = RandomInteger[10000, {100}]; a = Join[b, b, b, b, Take[b, 27]] The algorithm should return $Failed if there is no repeating pattern like above.

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  • MySQL 'user_id' in where clause is ambiguous problem

    - by HoMe
    How can I correct the problem I keep getting from the code below which states 'user_id' in where clause is ambiguous. Thanks for the help in advance. Here is the mysql table. SELECT user.*, user_info.* FROM user INNER JOIN user_info ON user.user_id = user_info.user_id WHERE user_id='$user_id'

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  • Change a link's href value based on time

    - by justSteve
    I'm coding a 'Connect to Meeting' page where i would like the link that allows attendees to join our GoToMeeting event to 'become active' 15 minutes prior to the start time. So the page users visit to see the connection info (meetingID, password) includes the start time of the meeting. I need a button ('Connect To Meeting') to change from inactive to Active when [Now() < (StartTime()-15minutes)].

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  • Margin totals in xtabs

    - by James
    If you have 2 cross classifying variables you can use rowSums and colSums to produce margin totals on an xtabs output. But how can it be done if you have 3 classifying variables (ie margin totals in each sub table)?

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  • Return all users from group(s) specified as comma delimited value

    - by todor
    I have the following two table scenario: users id groups 1 1,2,3 2 2,3 3 1,3 4 3 and groups id 1 2 3 How do I return the IDs of all users that belong to group 2 and 1 for example? Should I look into join, a helper group_membership table or function to separate the comma delimited group IDs to get something like this: group_membership user_id group_id 1 1 1 2 1 3 2 2 2 3 ... ...

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  • Is there anyway that we can get a label value to a Sql

    - by Pradeep
    SELECT COUNT(*) AS Expr1 FROM Book INNER JOIN Temp_Order ON Book.Book_ID = Temp_Order.Book_ID WHERE (Temp_Order.User_ID = 25) AND (CONVERT (nvarchar, Temp_Order.OrderDate, 111) = CONVERT (nvarchar, GETDATE(), 111)) In here i want to change my User_ID to get from a label.Text this Sql Statement is in a DataView. so in the Wizard it not accepting a text box values or anything. can someone please help me to solve this

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  • delete taking really long time! mysql

    - by every_answer_gets_a_point
    i am doing this: delete calibration_2009 from calibration_2009 join batchinfo_2009 on calibration_2009.rowid = batchinfo_2009.rowid where batchinfo_2009.reporttime like '%2010%'; both tables have about 500k lines of data i suspect that 250k match the criteria to be deleted so far it has been running for 2 hours!!! is there something wrong?

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  • XML XQUERY Problem with NTEXT data type

    - by johnfa
    Hello I want to use XQuery on a column of data type NTEXT (I have no choice!). I have tried converting the column to XML using CONVERT but it gives the error: Incorrect syntax near the keyword 'CONVERT'. Here's the query SELECT y.item.value('@UserID', 'varchar(50)') AS UnitID, y.item.value('@ListingID', 'varchar(100)') AS @ListingID FROM dbo.KB_XMod_Modules CROSS APPLY CONVERT(xml, instancedata).nodes('//instance') AS y(item) (instancedata is my column) Can anyone think of a work around for this ? Thanks

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