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  • Spring properties (property-placeholder) autowiring

    - by peperg
    I have in my applicationContext.xml <context:property-placeholder location="classpath*:*.properties" /> <bean id="clientPreferencesManager" class="pl.bildpresse.bildchat2.business.ClientPreferencesManager" > <property name="clientApiUrl" value="${clientapi.url}" /> </bean> Is it possible to do the same by autowire ? Something like : @Autowired @Qualifier("${clientapi.url}") public void setClientApiUrl(String clientApiUrl) { this.clientApiUrl = clientApiUrl; }

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  • django: How to make one form from multiple models containing foreignkeys

    - by Tim
    I am trying to make a form on one page that uses multiple models. The models reference each other. I am having trouble getting the form to validate because I cant figure out how to get the id of two of the models used in the form into the form to validate it. I used a hidden key in the template but I cant figure out how to make it work in the views My code is below: views: def the_view(request, a_id,): if request.method == 'POST': b_form= BForm(request.POST) c_form =CForm(request.POST) print "post" if b_form.is_valid() and c_form.is_valid(): print "valid" b_form.save() c_form.save() return HttpResponseRedirect(reverse('myproj.pro.views.this_page')) else: b_form= BForm() c_form = CForm() b_ide = B.objects.get(pk=request.b_id) id_of_a = A.objects.get(pk=a_id) return render_to_response('myproj/a/c.html', {'b_form':b_form, 'c_form':c_form, 'id_of_a':id_of_a, 'b_id':b_ide }) models class A(models.Model): name = models.CharField(max_length=256, null=True, blank=True) classe = models.CharField(max_length=256, null=True, blank=True) def __str__(self): return self.name class B(models.Model): aid = models.ForeignKey(A, null=True, blank=True) number = models.IntegerField(max_length=1000) other_number = models.IntegerField(max_length=1000) class C(models.Model): bid = models.ForeignKey(B, null=False, blank=False) field_name = models.CharField(max_length=15) field_value = models.CharField(max_length=256, null=True, blank=True) forms from mappamundi.mappa.models import A, B, C class BForm(forms.ModelForm): class Meta: model = B exclude = ('aid',) class CForm(forms.ModelForm): class Meta: model = C exclude = ('bid',) B has a foreign key reference to A, C has a foreign key reference to B. Since the models are related, I want to have the forms for them on one page, 1 submit button. Since I need to fill out fields for the forms for B and C & I dont want to select the id of B from a drop down list, I need to somehow get the id of the B form into the form so it will validate. I have a hidden field in the template, I just need to figure how to do it in the views

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  • How do I get PHP variables from this MySQL query?

    - by CT
    I am working on an Asset Database problem using PHP / MySQL. In this script I would like to search my assets by an asset id and have it return all related fields. First I query the database asset table and find the asset's type. Then depending on the type I run 1 of 3 queries. <?php //make database connect mysql_connect("localhost", "asset_db", "asset_db") or die(mysql_error()); mysql_select_db("asset_db") or die(mysql_error()); //get type of asset $type = mysql_query(" SELECT asset.type From asset WHERE asset.id = 93120 ") or die(mysql_error()); switch ($type){ case "Server": //do some stuff that involves a mysql query mysql_query(" SELECT asset.id ,asset.company ,asset.location ,asset.purchase_date ,asset.purchase_order ,asset.value ,asset.type ,asset.notes ,server.manufacturer ,server.model ,server.serial_number ,server.esc ,server.user ,server.prev_user ,server.warranty FROM asset LEFT JOIN server ON server.id = asset.id WHERE asset.id = 93120 "); break; case "Laptop": //do some stuff that involves a mysql query mysql_query(" SELECT asset.id ,asset.company ,asset.location ,asset.purchase_date ,asset.purchase_order ,asset.value ,asset.type ,asset.notes ,laptop.manufacturer ,laptop.model ,laptop.serial_number ,laptop.esc ,laptop.user ,laptop.prev_user ,laptop.warranty FROM asset LEFT JOIN laptop ON laptop.id = asset.id WHERE asset.id = 93120 "); break; case "Desktop": //do some stuff that involves a mysql query mysql_query(" SELECT asset.id ,asset.company ,asset.location ,asset.purchase_date ,asset.purchase_order ,asset.value ,asset.type ,asset.notes ,desktop.manufacturer ,desktop.model ,desktop.serial_number ,desktop.esc ,desktop.user ,desktop.prev_user ,desktop.warranty FROM asset LEFT JOIN desktop ON desktop.id = asset.id WHERE asset.id = 93120 "); break; } ?> So far I am able to get asset.type into $type. How would I go about getting the rest of the variables (laptop.model to $model, asset.notes to $notes and so on)? Thank you.

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  • Joining different models in Django

    - by Andrew Roberts
    Let's say I have this data model: class Workflow(models.Model): ... class Command(models.Model): workflow = models.ForeignKey(Workflow) ... class Job(models.Model): command = models.ForeignKey(Command) ... Suppose somewhere I want to loop through all the Workflow objects, and for each workflow I want to loop through its Commands, and for each Command I want to loop through each Job. Is there a way to structure this with a single query? That is, I'd like Workflow.objects.all() to join in its dependent models, so I get a collection that has dependent objects already cached, so workflows[0].command_set.get() doesn't produce an additional query. Is this possible?

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  • Monitor database table for external changes from within Rails application

    - by jhwist
    I'm integrating some non-rails-model tables in my Rails application. Everything works out very nicely, the way I set up the model is: class Change < ActiveRecord::Base establish_connection(ActiveRecord::Base.configurations["otherdb_#{RAILS_ENV}"]) set_table_name "change" end This way I can use the Change model for all existing records with find etc. Now I'd like to run some sort of notification, when a record is added to the table. Since the model never gets created via Change.new and Change.save using ActiveRecord::Observer is not an option. Is there any way I can get some of my Rails code to be executed, whenever a new record is added? I looked at delayed_job but can't quite get my head around, how to set that up. I imagine it evolves around a cron-job, that selects all rows that where created since the job last ran and then calls the respective Rails code for each row.

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  • ASP.NET MVC - separating large app

    - by marc_s
    I've been puzzled by what I consider a contradiction in terms: ASP.NET MVC claims to be furthering and supporting the "separation of concern" motto, which I find a great idea. However, it seems there's no way of separating out controllers, model or views into their own assembly, or separating areas into assemblies. With the fixed Controller, Model and View folders in your ASP.NET MVC, you're actually creating a huge hodge podge of things. Is that the separation of concerns, really?? Seems like quite the contrary to me. So what I'm wondering: how can I create an ASP.NET MVC solution that will either separate out controllers, the model, and the folders full of views, into separate assemblies? how can I put areas of ASP.NET MVC 2 into separate assemblies? or how else do you manage a large ASP.NET MVC app - which has several dozen or even over a hundred controllers, lots of model and viewmodel classes, and several hundred views?

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  • django left join with null

    - by SledgehammerPL
    The model: class Product(models.Model): name = models.CharField(max_length = 128) def __unicode__(self): return self.name class Receipt(models.Model): name = models.CharField(max_length=128) components = models.ManyToManyField(Product, through='ReceiptComponent') class Admin: pass def __unicode__(self): return self.name class ReceiptComponent(models.Model): product = models.ForeignKey(Product) receipt = models.ForeignKey(Receipt) quantity = models.FloatField(max_length=9) unit = models.ForeignKey(Unit) def __unicode__(self): return unicode(self.quantity!=0 and self.quantity or '') + ' ' + unicode(self.unit) + ' ' + self.product.genitive The idea: there are a components on stock. I'd like to find out which recipes I can made with components which I have. It's not easy - but possible - I made a SQL view, which gets the solution. But I'm learning python and Django so I'd like to make it Django-style ;D The concept of solution: get the set of recipes which has at last one component: list_of_available_components = ReceiptComponent.objects.filter(product__in=list_of_available_products).distinct() list_of_related_receipts = Receipt.objects.filter(receiptcomponent__in = list_of_available_components).distinct() get recipes (from list_of_related_receipts) which has not at last one component list_of_incomplete_recipes = (SELECT * FROM drinkbook_receiptcomponent LEFT JOIN drinkstore_stock_products USING(product_id) WHERE drinkstore_stock_products.stock_id IS NULL AND receipt_id IN (SELECT receipt_id FROM drinkbook_receiptcomponent JOIN drinkstore_stock_products USING(product_id))) get recipes (from list_of_related_receipts) which are not in "list_of_incomplete_recipes"

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  • NSEntityDescription entityForName returning nil

    - by Kamchatka
    Hi, I did some changes to my model (but I don't want migration yet, so I just remove the application, built clean etc.) so my application works in the simulator. However, when I run it on the iPhone, I get the following error: *** Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: 'executeFetchRequest:error: A fetch request must have an entity.' I set the entity like this: NSEntityDescription *entity = [NSEntityDescription entityForName:@"Document" inManagedObjectContext:managedObjectContext]; My managedObjectContext is not nil. But I suspect that it doesn't load the object model correctly or something similar because If I display the entities in the model, the list is empty. How can I make sure the model is loaded? Thanks,

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  • Ruby on Rails: Unit Testing non activerecord models and still load fixtures

    - by Vaibhav Gumashta
    I may be missing something but I am stuck in this scenario: I have a non activerecord model, which I want to test. I have derived its test case class from: Test::Unit::TestCase. However, the test case class for the model, uses within itself, other activerecord model classes and I want to load fixtures for them. My problem is that the fixtures class method is available only when I subclass the test case class from ActiveSupport::TestCase (it is defined within ActiveRecord::TestFixtures which gets included in ActiveSupport::TestCase). Any help, coz running the tests gives me the error: undefined method "fixtures" (which is understandable) and in case I derive my test case class from ActiveSupport::TestCase it complains that there is no corresponding DB table. Also, I don't want to create a dummy table for backing my model class. Thanks a ton!

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  • Ember nested route. Load more models

    - by user3568719
    JsBin http://jsbin.com/EveQOke/153/ I know how to load more then one model to a route, using Ember.RSVP.hash. (see Jsbin Children menu). I use dynamic part to access one elem from a collection children/1. But i cant load more models to a nested resource. In my example i want to populate all the toys for a select, not just list the toys of the child. I have tried to access the model of the route children App.ChildRoute = Ember.Route.extend({ model: function(param){ return Ember.RSVP.hash({ allToys: this.modelFor("children"), child:this.store.find('child', param.child_id) }); } }); and use its model's toy property (since there have already loaded all of the toys) child.hbs <h4>All avaiable toys</h4> <table> {{#each toy in model.allToys.toys}} <tr> <td>{{toy.name}}</td> </tr> {{/each}} </table>

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  • Why does my JSF + Spring web application output JSF source code instead of interpreted HTML page?

    - by Corvus
    I'm new to both JSF and Spring Framework and I'm trying to figure out how to make them work together. My current problem is that application outputs my JSF files without interpreting them. Here are some snippets of my code which I believe might be relevant: dispatcher-servlet.xml <bean id="urlMapping" class="org.springframework.web.servlet.handler.SimpleUrlHandlerMapping"> <property name="mappings"> <props> <prop key="login.htm">loginController</prop> </props> </property> </bean> <bean id="viewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver" p:prefix="/WEB-INF/pages/" p:suffix=".xhtml" /> <bean name="loginController" class="controller.LoginController" /> loginController public class LoginController extends MultiActionController { public ModelAndView login(HttpServletRequest request, HttpServletResponse response) throws Exception { System.out.println("LOGIN"); return new ModelAndView("login"); } WEB-INF/pages/login.xhtml <?xml version='1.0' encoding='UTF-8' ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xmlns:h="http://java.sun.com/jsf/html"> <h:head> <title>#{message.log}</title> </h:head> <h:body> <h:form> <h:outputLabel value="#{message.username}" for="userName"> <h:inputText id="userName" value="#{User.name}" /> </h:outputLabel> <h:commandButton value="#{message.loggin}" action="#{User.login}" /> </h:form> </h:body> </html> Any ideas where the problem might be? Does this code make any sense at all? I'm well aware of fact, that probably completely sucks and I'll be glad to here WHY it sucks and how to make it better. Thanks :)

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  • How can I create XSD files from M documents?

    - by Andrew Matthews
    Does anyone know of a nice way to: produce XSD documents from an OSLO model consume conformant XML documents using that model and add directly into the DB created from the model? I can't see any obvious way from the current documentation, but I'm a newcomer, so I may have missed something. Thanks.

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  • How to find full module path of a class to import in other file

    - by Pooya
    I have method that returns module path of given class name def findModulePath(path, className): attributes = [] for root, dirs, files in os.walk(path): for source in (s for s in files if s.endswith(".py")): name = os.path.splitext(os.path.basename(source))[0] full_name = os.path.splitext(source)[0].replace(os.path.sep, '.') m = imp.load_module(full_name, *imp.find_module(name, [root])) try: attr = getattr(m, className) attributes.append(attr) except: pass if len(attributes) <= 0: raise Exception, "Class %s not found" % className for element in attributes: print "%s.%s" % (element.__module__, className) but it does not return the full path of the module, For example I have a python file named "objectmodel" in objects package,and it contains a Model class, So I call findModulePath(MyProjectPath,"Model"). it prints objectmodel.Model but I need objects.objectmodel.Model

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  • How to extend models of other applications in Django?

    - by culebrón
    I have a small app with Category model and want to make a required foreign key referencing it from Photologue Gallery model. What's the right approach? I can make many-to-many field in Category, but this way it will not be required in Gallery. Use "register" and modify the Gallery model? Inherit it in my app?

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  • JSF 2.0: Preserving component state across multiple views

    - by tlind
    The web application I am developing using MyFaces 2.0.3 / PrimeFaces 2.2RC2 is divided into a content and a navigation area. In the navigation area, which is included into multiple pages using templating (i.e. <ui:define>), there are some widgets (e.g. a navigation tree, collapsible panels etc.) of which I want to preserve the component state across views. For example, let's say I am on the home page. When I navigate to a product details page by clicking on a product in the navigation tree, my Java code triggers a redirect using navigationHandler.handleNavigation(context, null, "/detailspage.jsf?faces-redirect=true") Another way of getting to that details page would be by directly clicking on a product teaser that is shown on the home page. The corresponding <h:link> would lead us to the details page. In both cases, the expansion state of my navigation tree (a PrimeFaces tree component) and my collapsible panels is lost. I understand this is because the redirect / h:link results in the creation of a new view. What is the best way of dealing with this? I am already using MyFaces Orchestra in my project along with its conversation scope, but I am not sure if this is of any help here (since I'd have to bind the expansion/collapsed state of the widgets to a backing bean... but as far as I know, this is not possible). Is there a way of telling JSF which component states to propagate to the next view, assuming that the same component exists in that view? I guess I could need a pointer into the right direction here. Thanks! Update 1: I just tried binding the panels and the tree to a session-scoped bean, but this seems to have no effect. Also, I guess I would have to bind all child components (if any) manually, so this doesn't seem like the way to go. Update 2: Binding UI components to non-request scoped beans is not a good idea (see link I posted in a comment below). If there is no easier approach, I might have to proceed as follows: When a panel is collapsed or the tree is expanded, save the current state in a session-scoped backing bean (!= the UI component itself) The components' states are stored in a map. The map key is the component's (hopefully) unique, relative ID. I cannot use the whole absolute component path here, since the IDs of the parent naming containers might change if the view changes, assuming these IDs are generated programmatically. As soon as a new view gets constructed, retrieve the components' states from the map and apply them to the components. For example, in case of the panels, I can set the collapsed attribute to a value retrieved from my session-scoped backing bean.

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  • Session is Closed! NHibernate shouldn't be trying to grab data

    - by Jeremy Holovacs
    I have a UnitOfWork/Service pattern where I populate my model using NHibernate before sending it to the view. For some reason I still get the YSOD, and I don't understand why the object collection is not already populated. My controller method looks like this: public ActionResult PendingRegistrations() { var model = new PendingRegistrationsModel(); using (var u = GetUnitOfWork()) { model.Registrations = u.UserRegistrations.GetRegistrationsPendingAdminApproval(); } return View(model); } The service/unit of work looks like this: public partial class NHUserRegistrationRepository : IUserRegistrationRepository { public IEnumerable<UserRegistration> GetRegistrationsPendingAdminApproval() { var r = from UserRegistration ur in _Session.Query<UserRegistration>() where ur.Status == AccountRegistrationStatus.PendingAdminReview select ur; NHibernateUtil.Initialize(r); return r; } } What am I doing wrong?

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  • Rails: generating URLs for actions in JSON response

    - by Chris Butler
    In a view I am generating an HTML canvas of figures based on model data in an app. In the view I am preloading JSON model data in the page like this (to avoid an initial request back): <script type="text/javascript" charset="utf-8"> <% ActiveRecord::Base.include_root_in_json = false -%> var objects = <%= @objects.to_json(:include => :other_objects) %>; ... Based on mouse (or touch) interaction I want to redirect to other parts of my app that are model specific (such as view, edit, delete, etc.). Rather than hard code the URLs in my JavaScript I want to generate them from Rails (which means it always adapts the latest routes). It seems like I have one of three options: Add an empty attr to the model that the controller fills in with the appropriate URL (we don't want to use routes in the model) before the JSON is generated Generate custom JSON where I add the different URLs manually Generate the URL as a template from Rails and replace the IDs in JavaScript as appropriate I am starting to lean towards #1 for ease of implementation and maintainability. Are there any other options that I am missing? Is #1 not the best? Thanks! Chris

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  • Dropdown sorting in django-admin

    - by Andrey
    I'd like to know how can I sort values in the Django admin dropdowns. For example, I have a model called Article with a foreign key pointing to the Users model, smth like: class Article(models.Model): title = models.CharField(_('Title'), max_length=200) slug = models.SlugField(_('Slug'), unique_for_date='publish') author = models.ForeignKey(User) body = models.TextField(_('Body')) status = models.IntegerField(_('Status')) categories = models.ManyToManyField(Category, blank=True) publish = models.DateTimeField(_('Publish date')) I edit this model in django admin: class ArticleAdmin(admin.ModelAdmin): list_display = ('title', 'publish', 'status') list_filter = ('publish', 'categories', 'status') search_fields = ('title', 'body') prepopulated_fields = {'slug': ('title',)} admin.site.register(Article, ArticleAdmin) and of course it makes the nice user select dropdown for me, but it's not sorted and it takes a lot of time to find a user by username.

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  • ASP.NET MVC Patterns

    - by Sam Striano
    Hello, I am fairly new to MVC, but after playing with it (MVC 3/Razor), I am hooked. I have a few questions: 1) What is the best, or most widely used pattern to develop MVC apps in? Repository, DDD, UOW? 2) I am using the Entity Framework 4, so could some please explain to me or point me to a good source that will explain the Repository Pattern w/EF4? Doesn't EF4 take place as the business layer and the data access layer? Does the Repository Pattern even provide a benefit? 3) Also, one last question, could someone explain the whole relationship between the Controller, the Model and the View? I get the basics, but maybe a little more in depth of the correct way to use it. View Models - Say I have a view that displays customer info, and one that edits it, should I have a view model and an edit model, or can the be passed around? 4) Examples?? Thanks for the help up front, $("Sam") ** EDIT ** Am I on the right track here: Public Class HomeController Inherits System.Web.Mvc.Controller Function Index(ByVal id As Integer) As ActionResult Return View(New HomeModel) End Function <HttpPost()> _ Function Index(ByVal Model As HomeModel) As ActionResult Return View(Model) End Function End Class Public Class HomeModel Private _Repository As IRepository(Of Customer) Public Property Customer As Customer Public Sub New() End Sub Public Sub New(ByVal ID As Integer) _Repository = New CustomerRepository Customer = _Repository.GetByID(ID) End Sub End Class Public Interface IRepository(Of T) Function GetByID(ByVal ID As Integer) As T Sub Add(ByVal Entity As T) Sub Delete(ByVal Entity As T) End Interface Public Class CustomerRepository Implements IRepository(Of Customer) Public Sub Add(ByVal Entity As Customer) Implements IRepository(Of Customer).Add End Sub Public Sub Delete(ByVal Entity As Customer) Implements IRepository(Of Customer).Delete End Sub Public Function GetByID(ByVal ID As Integer) As Customer Implements IRepository(Of Customer).GetByID Return New Customer With {.ID = ID, .FirstName = "Sam", .LastName = "Striano"} End Function End Class Public Class Customer Public Property ID As Integer Public Property FirstName As String Public Property LastName As String End Class

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  • test is null in the controller upon post

    - by user281180
    I have the following codes and the test value is always null in the controller after the post. What is wrong with the following code: Model: public class Suitcase { public string Color { get; set; } public string[] Size { get; set; } public List<string> Clothes { get; set; } public List<Test> test { get; set; } } public class Test { public string Name { get; set; } public int ID { get; set; } } The view: <fieldset> <legend>All about my baggage</legend> <div class="editor-label"> <%: Html.LabelFor(model => model.Color) %> </div> <div class="editor-field"> <%: Html.TextBoxFor(model => model.Color) %> </div> <br /> <div class="editor-label"> Width, Height, Depth: </div> <div class="editor-field"> ml.TextBoxFor(model => model.Depth, new { style = "width:50px;" })%> </div> <br /> <div class="editor-label">Suitcase Contents</div> <div class="editor-field"> <div id="clothes-editor"> Clothing Item: <input type="text" id="new-clothes-item" style="width:150px" /> <button id="add-clothes">Add to suitcase</button> </div> <b>Items currently in suitcase:</b> <ul id="clothes-list"> </ul> </div> <p> <button id="pack-it">Put on Baggage Carosel</button> </p> </fieldset> <script type="text/javascript" language="javascript"> $(function () { $("button").button(); // allow users to add items to the suitcase $("#add-clothes").click(function () { var clothesText = $("#new-clothes-item"); $("#clothes-list").append("<li>" + clothesText.val() + "</li>"); clothesText.val("").focus(); }); // pack the suitcase up and send it to the baggage carosel...erm...controller $("#pack-it").click(function () { var clothesList = []; $("#clothes-list li").each(function () { clothesList.push($(this).text()) }); var SizeList = []; SizeList[0] = "Medium"; SizeList[1] = "Large"; SizeList[2] = "small"; var Data = new Object(); Data.test = []; var reading = {}; reading.Name = "Micheal" reading.ID = 123; Data.test[0] = reading; reading.Name = "Rowen" reading.ID = 1234; Data.test[1] = reading; $.ajax({ type: 'POST', traditional: true, data: { Color: $("#Color").val(), Size: SizeList, Clothes: clothesList, test: Data.test } }); }); }); </script> Controller: [HttpPost] public EmptyResult Suitcase(Suitcase lookWhatIPacked) { return new EmptyResult(); }

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  • WCF Multiple Services

    - by David
    Hi, im brand spanking new to WCF and Im trying to understand how to correctly expose my BLL to it. I created my first Resource.svc and IResource.svc Resource.svc [ServiceBehavior] public class Resources : IResources { #region IResources Members public List<Model.Resource> GetAll() { return Repository.Inventory.Resource.GetAll(true); } public List<Model.Resource> GetAllEnabled() { return Repository.Inventory.Resource.GetAllEnabled(true); } #endregion } IResource.cs [ServiceContract] public interface IResources { [OperationContract] List<Model.Resource> GetAll(); [OperationContract] List<Model.Resource> GetAllEnabled(); } So this all works, My windows app can talk to the service and all is great. So I now need to access some information, I have created another .svc file called Project.svc and IProject.cs, this contains the same info as resource (apart from the type is Project) But this now means I have another webservice, surley this is not right!?

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  • How can I inherit an ASP.NET MVC controller and change only the view?

    - by AlexWalker
    I have a controller that's inheriting from a base controller, and I'm wondering how I can utilize all of the logic from the base controller, but return a different view than the base controller uses. The base controller populates a model object and passes that model object to its view, but I'm not sure how I can access that model object in the child controller so that I can pass it to the child controller's view.

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  • ASP.MVC 1.0 complex ViewModel not populating on Action

    - by Graham
    Hi, I'm 3 days into learning MVC for a new project and i've managed to stumble my way over the multitude of issues I've come across - mainly about something as simple as moving data to a view and back into the controller in a type-safe (and manageable) manner. This is the latest. I've seen this reported before but nothing advised has seemed to work. I have a complex view model: public class IndexViewModel : ApplicationViewModel { public SearchFragment Search { get; private set; } public IndexViewModel() { this.Search = new SearchFragment(); } } public class SearchFragment { public string ItemId { get; set; } public string Identifier { get; set; } } This maps to (the main Index page): %@ Page Title="" Language="C#" MasterPageFile="~/Views/Shared/Site.Master" Inherits="System.Web.Mvc.ViewPage<IndexViewModel>" %> <asp:Content ID="Content1" ContentPlaceHolderID="MainContent" runat="server"> <% Html.BeginForm("Search", AvailableControllers.Search, FormMethod.Post); %> <div id="search"> <% Html.RenderPartial("SearchControl", Model.Search); %> </div> <% Html.EndForm(); %> </asp:Content> and a UserControl: <%@ Control Language="C#" Inherits="System.Web.Mvc.ViewUserControl<SearchFragment>" %> <p> <label for="itemId"> <%= Html.Resource("ItemId") %></label> <%= Html.TextBox("itemId", Model.ItemId)%> </p> <p> <label for="title"> <%= Html.Resource("Title") %></label> <%= Html.TextBox("identifier", Model.Identifier)%> </p> <p> <input type="submit" value="<%= Html.Resource("Search") %>" name="search" /> </p> This is returned to the following method: [AcceptVerbs(HttpVerbs.Post)] public ActionResult Search(IndexViewModel viewModel) { .... } My problem is that when the view model is rehydrated from the View into the ViewModel, the SearchFragment elements are null. I suspect this is because the default model binder doesn't realise the HTML ItemId and Identifier elements rendered inline in the View map to the SearchFragment class. When I have two extra properties (ItemId and Identifier) in the IndexViewModel, the values are bound correctly. Unfortunately, as far as I can tell, I must use the SearchFragment as I need this to strongly type the Search UserControl... as the control can be used anywhere it can operate under any parent view. I really don't want to make it use "magic strings". There's too much of that going on already IMO. I've tried prefixing the HTML with "Search." in the hope that the model binder would recognise "Search.ItemId" and match to the IndexViewModel "Search" property and the ItemId within it, but this doesn't work. I fear I'm going to have to write my own ModelBinder to do this, but surely this must be something you can do out-of-the-box?? Failing that is there any other suggestions (or link to someone who has already done this?) Here's hoping....

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  • SpringBatch Jaxb2Marshaller: different name of class and xml attribute

    - by user588961
    I try to read an xml file as input for spring batch: Java Class: package de.example.schema.processes.standardprocess; @XmlAccessorType(XmlAccessType.FIELD) @XmlType(name = "Process", namespace = "http://schema.example.de/processes/process", propOrder = { "input" }) public class Process implements Serializable { @XmlElement(namespace = "http://schema.example.de/processes/process") protected ProcessInput input; public ProcessInput getInput() { return input; } public void setInput(ProcessInput value) { this.input = value; } } SpringBatch dev-job.xml: <bean id="exampleReader" class="org.springframework.batch.item.xml.StaxEventItemReader" scope="step"> <property name="fragmentRootElementName" value="input" /> <property name="resource" value="file:#{jobParameters['dateiname']}" /> <property name="unmarshaller" ref="jaxb2Marshaller" /> </bean> <bean id="jaxb2Marshaller" class="org.springframework.oxm.jaxb.Jaxb2Marshaller"> <property name="classesToBeBound"> <list> <value>de.example.schema.processes.standardprocess.Process</value> <value>de.example.schema.processes.standardprocess.ProcessInput</value> ... </list> </property> </bean> Input file: <?xml version="1.0" encoding="UTF-8"?> <process:process xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:process="http://schema.example.de/processes/process"> <process:input> ... </process:input> </process:process> It fires the following exception: [javax.xml.bind.UnmarshalException: unexpected element (uri:"http://schema.example.de/processes/process", local:"input"). Expected elements are <<{http://schema.example.de/processes/process}processInput] at org.springframework.oxm.jaxb.JaxbUtils.convertJaxbException(JaxbUtils.java:92) at org.springframework.oxm.jaxb.AbstractJaxbMarshaller.convertJaxbException(AbstractJaxbMarshaller.java:143) at org.springframework.oxm.jaxb.Jaxb2Marshaller.unmarshal(Jaxb2Marshaller.java:428) If I change to in xml it work's fine. Unfortunately I can change neither the xml nor the java class. Is there a possibility to make Jaxb2Marshaller map the element 'input' to the class 'ProcessInput'?

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  • nHibernate: limit the result set of a mapped collection

    - by HeavyWave
    How do you limit the result set of a mapped collection in nHibernate? For instance: Model.Items; will always return all the Items for the given Model. Is there any way to force it to return only, say, 20 Items without creating a specific query ? Something like Model.Items.SetMaxResults(20); In other words, I would like nHibernate to return IQueryable instead of a simple IList, when I access a collection.

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