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  • Spotting similarities and patterns within a string - Python

    - by RadiantHex
    Hi folks, this is the use case I'm trying to figure this out for. I have a list of spam subscriptions to a service and they are killing conversion rate and other usability studies. The emails inserted look like the following: [email protected] [email protected] [email protected] roger[...]_surname[...]@hotmail.com What would be your suggestions on spotting these entries by using an automated script? It feels a little more complicated than it actually looks. Help would be very much appreciated!

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  • Update the rank in a MySQL Table

    - by sammichy
    I have the following table structure for a table Player Table Player { Long playerID; Long points; Long rank; } Assuming that the playerID and the points have valid values, can I update the rank for all the players based on the number of points in a single query? If two people have the same number of points, they should tie for the rank.

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  • Php, mysql selection

    - by cosy
    I have this table ATTRIBUTE id name um 12 capacity MB;GB;TB And this table2 : id id_attribute id_product name value um 1 12 40 hdd maxtor 30 GB 2 12 41 hdd maxtor 40 GB 3 12 42 hdd y 1 TB How can i select from table2 in this order : 30GB 40GB 1TB? Thanks a lot!

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  • Resuming MySQL indexing

    - by gmemon
    Hello All, I have been building index on a 200 million row table for almost 14 hours. Due to resource over-consumption on the machine (because of a separate incident), the machine cashed. Clearly, I want to avoid another 14 hours to re-construct the index. Is there a way that I can resume the construction of index from the point (or slightly back) where the machine crashed? I can see the temporary files created. Thanks

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  • Converting the value from string to integer in a nested dictionary

    - by tom smith
    I want to change the numbers in my dictionary to int values for use later in my program. So far I have import time import math x = 400 y = 300 def read_next_object(file): obj = {} for line in file: if not line.strip(): continue line = line.strip() key, val = line.split(": ") if key in obj and key == "Object": yield obj obj = {} obj[key] = val yield obj planets = {} with open( "smallsolar.txt", 'r') as f: for obj in read_next_object(f): planets[obj["Object"]] = obj print(planets) scale=250/int(max([planets[x]["Orbital Radius"] for x in planets if "Orbital Radius" in planets[x]])) print(scale) and the output is {'Sun': {'Object': 'Sun', 'Satellites': 'Mercury,Venus,Earth,Mars,Jupiter,Saturn,Uranus,Neptune,Ceres,Pluto,Haumea,Makemake,Eris', 'Orbital Radius': '0', 'RootObject': 'Sun', 'Radius': '20890260'}, 'Moon': {'Object': 'Moon', 'Orbital Radius': '18128500', 'Period': '27.321582', 'Radius': '1737000.10'}, 'Earth': {'Object': 'Earth', 'Satellites': 'Moon', 'Orbital Radius': '77098290', 'Period': '365.256363004', 'Radius': '6371000.0'}} 3.2426140709476178e-06 I want to be able to convert the numbers in the dict to ints for further use. Any help in greatly appreciated.

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  • PHP Moving mySQL Tree Node

    - by TK
    I am having trouble trying to move sub nodes or parent nodes up or down... not that good at math. CREATE TABLE IF NOT EXISTS `pages` ( page-id mediumint(8) unsigned NOT NULL AUTO_INCREMENT, page-left mediumint(8) unsigned NOT NULL, page-right smallint(8) unsigned NOT NULL, page-title text NOT NULL, page-content text NOT NULL, page-time int(11) unsigned NOT NULL, page-slug text NOT NULL, page-template text NOT NULL, page-parent mediumint(8) unsigned NOT NULL, page-type text NOT NULL, PRIMARY KEY (page-id) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 ; INSERT INTO pages (page-id, page-left, page-right, page-title, page-content, page-time, page-slug, page-template, page-parent, page-type) VALUES (17, 1, 6, '1', '', 0, 'PARENT', '', 0, ''), (18, 2, 5, '2', '', 0, 'SUB', '', 17, ''), (19, 3, 4, '3', '', 0, 'SUB-SUB', '', 18, ''), (20, 7, 8, '5', '', 0, 'TEST', '', 0, ''); As example how would I move TEST up above PARENT and say move SUB down below SUB-SUB by playing with the page-left/page-right IDs? Code is not required just help with the SQL concept or math for it, would help me understand how to move it better...

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  • MySQL: Complex Join Statement involving two tables and a third correlation table

    - by Stephen
    I have two tables that were built for two disparate systems. I have records in one table (called "leads") that represent customers, and records in another table (called "manager") that are the exact same customers but "manager" uses different fields (For example, "leads" contains an email address, and "manager" contains two fields for two different emails--either of which might be the email from "leads"). So, I've created a correlation table that contains the lead_id and manager_id. currently this correlation table is empty. I'm trying to query the "leads" table to give me records that match either "manager" email field with the single "leads" email field, while at the same time ignoring fields that have already been added to the "correlated" table. (this way I can see how many leads that match have not yet been correlated.) Here's my current, invalid SQL attempt: SELECT leads.id, manager.id FROM leads, manager LEFT OUTER JOIN correlation ON correlation.lead_id = leads.id WHERE correlation.id IS NULL AND leads.project != "someproject" AND (manager.orig_email = leads.email OR manager.dest_email = leads.email) AND leads.created BETWEEN '1999-01-01 00:00:00' AND '2010-05-10 23:59:59' ORDER BY leads.created ASC; I get the error: Unknown column 'leads.id' in 'on clause' Before you wonder: there are records in the "leads" table where leads.project != "someproject" and leads.created falls between those dates. I've included those additional parameters for completeness.

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  • MYSQL get the name from another table that is associated with the first table

    - by Juan Gonzales
    I can't figure out why this statement is not working SELECT myChurches.id AS id, myChurches.church_name AS church_name FROM myChurches INNER JOIN church_staff ON church_staff.church_id=myChurches.id WHERE church_staff.mem_id='$logOptions_id' ORDER BY myChurches.church_name ASC Basically I need to find the person's that are staff members of a church from one table and want to get the 'name' of that church FROM the 'myChurches' table. Hopefully that makes sense. Thanks in advance

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  • MySQL GROUP_CONCAT + IN() = missing data :-(

    - by Andrew Heath
    Example: Table: box boxID color 01 red 02 blue 03 green Table: boxHas boxID has 01 apple 01 pear 01 grapes 01 banana 02 lime 02 apple 02 pear 03 chihuahua 03 nachos 03 baby crocodile I want to query on the contents of each box, and return a table with each ID, color, and a column that concatenates the contents of each box, so I use: SELECT box.boxID, box.color, GROUP_CONCAT(DISTINCT boxHas.has SEPARATOR ", ") AS contents FROM box LEFT JOIN boxHas ON box.boxID=boxHas.boxID WHERE boxHas.has IN ('apple','pear') GROUP BY box.boxID ORDER BY box.boxID and I get the following table of results: boxID color contents 01 red apple, pear 02 blue apple, pear My question to you is: why isn't it listing ALL the has values in the contents column? Why is my WHERE statement also cropping my GROUP_CONCAT? The table I thought I was going to get is: boxID color contents 01 red apple, banana, grapes, pear 02 blue apple, lime, pear Although I want to limit my boxID results based upon the WHERE statement, I do not want to limit the contents field for valid boxes. :-/ Help?

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  • Retrieve part of a MySQL column with PHP

    - by Gerardo Marset
    For instance, if I have the following table: +----+---+----------+ | id | a | position | +----+---+----------+ | 0 | 0 | 0 | | 1 | 0 | 1 | | 2 | 1 | 4 | | 3 | 1 | 9 | | 4 | 1 | 6 | | 5 | 1 | 1 | +----+---+----------+ and I want to get an array that contains the first 100 values from position where a is 1 in ascending order, what would I do? Im guessing something like this: $col = mysql_fetch_array( mysql_query(' SELECT `position` FROM `table` WHERE `a`="1" ORDER BY `position` ASC LIMIT 100 ')); I'd expect to get the following array: +-------+-------+ | index | value | +-------+-------+ | 0 | 1 | | 1 | 4 | | 2 | 6 | | 3 | 9 | +-------+-------+ but it doesn't work. ¿What should I do to make it work? Thanks

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  • MySQL JDBC date issues with database server in different timezone

    - by Somatik
    I have a database server in "Europe/London" time zone and my web server in "Europe/Brussels". Since it is summer time now my application server has a 2 hour difference. I created a test to reproduce my issue: Query q = JPA.em().createNativeQuery("SELECT UNIX_TIMESTAMP(startDateTime) FROM `Event` WHERE `id` =574"); BigInteger unix = (BigInteger) q.getSingleResult(); System.out.println(unix + "000 UNIX_TIMESTAMP to BigInteger"); Query q2 = JPA.em().createNativeQuery("SELECT startDateTime FROM `Event` WHERE `id` =574"); Timestamp o = (Timestamp) q2.getSingleResult(); System.out.println(o.getTime() + " Timestamp"); The startDateTime column is defined as 'datetime' (but same issue with 'timestamp') The output I am getting is this: 1340291591000 UNIX_TIMESTAMP to BigInteger 1340284391000 Timestamp Reading java date objects results in a shift in time zone, how do I fix this? I would expect the jdbc driver to just set the "unix time" value it gets from the server in the Date object. (a proper solution should work with any timezone combination, not only for db in GMT)

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  • Modify MySQL INSERT statement to omit the insertion of certain rows

    - by dave
    I'm trying to expand a little on a statement that I received help with last week. As you can see, I'm setting up a temporary table and inserting rows of student data from a recently administered test for a few dozen schools. When the rows are inserted, they are sorted by the score (totpct_stu, high to low) and the row_number is added, with 1 representing the highest score, etc. I've learned that there were some problems at school #9999 in SMITH's class (every student made a perfect score and they were the only students in the district to do so). So, I do not want to import SMITH's class. As you can see, I DELETED SMITH's class, but this messed up the row numbering for the remainder of student at the school (e.g., high score row_number is now 20, not 1). How can I modify the INSERT statement so as to not insert this class? Thanks! DROP TEMPORARY TABLE IF EXISTS avgpct ; CREATE TEMPORARY TABLE avgpct_1 ( sch_code VARCHAR(3), schabbrev VARCHAR(75), teachername VARCHAR(75), totpct_stu DECIMAL(5,1), row_number SMALLINT, dummy VARCHAR(75) ); -- ---------------------------------------- INSERT INTO avgpct SELECT sch_code , schabbrev , teachername , totpct_stu , @num := IF( @GROUP = schabbrev, @num + 1, 1 ) AS row_number , @GROUP := schabbrev AS dummy FROM sci_rpt WHERE grade = '05' AND totpct_stu >= 1 -- has a valid score ORDER BY sch_code, totpct_stu DESC ; -- --------------------------------------- -- select * from avgpct ; -- --------------------------------------- DELETE FROM avgpct_1 WHERE sch_code = '9999' AND teachername = 'SMITH' ;

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  • MySql Query lag time?

    - by Click Upvote
    When there are multiple PHP scripts running in parallel, each making an UPDATE query to the same record in the same table repeatedly, is it possible for there to be a 'lag time' before the table is updated with each query? I have basically 5-6 instances of a PHP script running in parallel, having been launched via cron. Each script gets all the records in the items table, and then loops through them and processes them. However, to avoid processing the same item more than once, I store the id of the last item being processed in a seperate table. So this is how my code works: function getCurrentItem() { $sql = "SELECT currentItemId from settings"; $result = $this->db->query($sql); return $result->get('currentItemId'); } function setCurrentItem($id) { $sql = "UPDATE settings SET currentItemId='$id'"; $this->db->query($sql); } $currentItem = $this->getCurrentItem(); $sql = "SELECT * FROM items WHERE status='pending' AND id > $currentItem'"; $result = $this->db->query($sql); $items = $result->getAll(); foreach ($items as $i) { //Check if $i has been processed by a different instance of the script, and if so, //leave it untouched. if ($this->getCurrentItem() > $i->id) continue; $this->setCurrentItem($i->id); // Process the item here } But despite of all the precautions, most items are being processed more than once. Which makes me think that there is some lag time between the update queries being run by the PHP script, and when the database actually updates the record. Is it true? And if so, what other mechanism should I use to ensure that the PHP scripts always get only the latest currentItemId even when there are multiple scripts running in parrallel? Would using a text file instead of the db help?

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  • mysql display each day in a month

    - by Jason
    during a month, display the infor each date, order by date, but this infor is empty in some day. how can i still display each day as a row? Product date ----------------- 20 2008-01-01 10 2008-01-02 20 2008-01-03 10 2008-01-05 09 2008-01-08 30 2008-01-09 result: Product date ----------------- 20 2008-01-01 10 2008-01-02 20 2008-01-03 0 2008-01-04 10 2008-01-05 0 2008-01-06 0 2008-01-07 09 2008-01-08 30 2008-01-09

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  • MySQL Subquery LIMIT

    - by atif089
    As the title says, I wanted a workaround for this... SELECT comments.comment_id, comments.content_id, comments.user_id, comments.`comment`, comments.comment_time, NULL FROM comments WHERE (comments.content_id IN (SELECT content.content_id FROM content WHERE content.user_id = 1 LIMIT 0, 10)) Cheers

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  • Mysql Select 1:n

    - by clinisbut
    Hello, I have two tables that relates 1:n content --------- - id - title - text content_meta ------------- - id - content_id - meta_key - meta_value A content can have multiple content_meta registers associated to it. Typically content_meta will contain the category, tags, descriptions and all that stuff, so I really don't know the number of registers a content will have. What I want to accomplish is to take the content register and also all the related registers in content_meta in a single query. I've tried the subselect approachment but seems that I can only get one register/column (¿?) SELECT content.*, ( SELECT * FROM content_meta WHERE content_id = content.id ) FROM content This query complains that "Operand should contain 1 column(s)", so changing the '*' by for example meta_key clears the error, but returns a NULL for this subselect... SELECT content.*, ( SELECT meta_key FROM content_meta WHERE content_id = content.id ) FROM content Can anybody show me where to go from here please?

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  • Mysql Query problem ?

    - by deep
    ID NAME AMT 1 Name1 1000 2 Name2 500 3 Name3 3000 4 Name1 5000 5 Name2 2000 6 Name1 3000 consider above table as sample. am having a problem in my sql query, Am using like this. Select name,amt from sample where amt between 1000 and 5000 it returns all the values in the table between 1000 and 5000, instead I want to get maximum amount record for each name i.e., 3 name3 3000 4 name1 5000 5 name2 2000

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  • mysql left outer join

    - by tirso
    hi to all I have two tables employee and timecard, employee table has fields employee_id,firstname,middlename,lastname and timecard table has fields employee_id,time-in,time-out,tc_date_transaction. I want to select all employee records which have the same employee_id with timecard and date is equal with the current date. If there are no records equal with the current date then return also the records of employee even without time-in,timeout and tc_date_transaction. I have query like this SELECT * FROM employee LEFT OUTER JOIN timecard ON employee.employee_id = timecard.employee_id WHERE tc_date_transaction = "17/06/2010"; result should like this: employee_id,firstname, middlename, lastname,time-in,time-out,tc_date_transaction 1,john,t,cruz,08:00,05:00,17/06/2010 2,mary,j,von,null,null,null any help would greatly appreciated Thanks in advance

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  • Single Large v/s Multiple Small MySQL tables for storing Options

    - by Prasad
    Hi there, I'm aware of several question on this forum relating to this. But I'm not talking about splitting tables for the same entity (like user for example) Suppose I have a huge options table that stores list options like Gender, Marital Status, and many more domain specific groups with same structure. I plan to capture in a OPTIONS table. Another simple option is to have the field set as ENUM, but there are disadvantages of that as well. http://www.brandonsavage.net/why-you-should-replace-enum-with-something-else/ OPTIONS Table: option_id <will be referred instead of the name> name value group Query: select .. from options where group = '15' - Since this table is expected to be multi-tenant, the no of rows could grow drastically. - I believe splitting the tables instead of finding by the group would be easier to write & faster to execute. - or perhaps partitioning by the group or tenant? Pl suggest. Thanks

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  • Why is str_replace not replacing this string?

    - by Niall
    I have the following PHP code which should load the data from a CSS file into a variable, search for the old body background colour, replace it with the colour from a submitted form, resave the CSS file and finally update the colour in the database. The problem is, str_replace does not appear to be replacing anything. Here is my PHP code (stored in "processors/save_program_settings.php"): <?php require("../security.php"); $institution_name = mysql_real_escape_string($_POST['institution_name']); $staff_role_title = mysql_real_escape_string($_POST['staff_role_title']); $program_location = mysql_real_escape_string($_POST['program_location']); $background_colour = mysql_real_escape_string($_POST['background_colour']); $bar_border_colour = mysql_real_escape_string($_POST['bar_border_colour']); $title_colour = mysql_real_escape_string($_POST['title_colour']); $url = $global_variables['program_location']; $data_background = mysql_query("SELECT * FROM sents_global_variables WHERE name='background_colour'") or die(mysql_error()); $background_output = mysql_fetch_array($data_background); $css = file_get_contents($url.'/default.css'); $str = "body { background-color: #".$background_output['data']."; }"; $str2 = "body { background-color: #".$background_colour."; }"; $css2 = str_replace($str, $str2, $css); unlink('../default.css'); file_put_contents('../default.css', $css2); mysql_query("UPDATE sents_global_variables SET data='{$institution_name}' WHERE name='institution_name'") or die(mysql_error()); mysql_query("UPDATE sents_global_variables SET data='{$staff_role_title}' WHERE name='role_title'") or die(mysql_error()); mysql_query("UPDATE sents_global_variables SET data='{$program_location}' WHERE name='program_location'") or die(mysql_error()); mysql_query("UPDATE sents_global_variables SET data='{$background_colour}' WHERE name='background_colour'") or die(mysql_error()); mysql_query("UPDATE sents_global_variables SET data='{$bar_border_colour}' WHERE name='bar_border_colour'") or die(mysql_error()); mysql_query("UPDATE sents_global_variables SET data='{$title_colour}' WHERE name='title_colour'") or die(mysql_error()); header('Location: '.$url.'/pages/start.php?message=program_settings_saved'); ?> Here is my CSS (stored in "default.css"): @charset "utf-8"; /* CSS Document */ body,td,th { font-family: Arial, Helvetica, sans-serif; font-size: 14px; color: #000; } body { background-color: #CCCCFF; } .main_table th { background:#003399; font-size:24px; color:#FFFFFF; } .main_table { background:#FFF; border:#003399 solid 1px; } .subtitle { font-size:20px; } input#login_username, input#login_password { height:30px; width:300px; font-size:24px; } input#login_submit { height:30px; width:150px; font-size:16px; } .timetable_cell_lesson { width:100px; font-size:10px; } .timetable_cell_tutorial_a, .timetable_cell_tutorial_b, .timetable_cell_break, .timetable_cell_lunch { width:100px; background:#999; font-size:10px; } I've run some checks using the following code in the PHP file: echo $css . "<br><br>" . $str . "<br><br>" . $str2 . "<br><br>" . $css2; exit; And it outputs (as you can see it's not changing anything in the CSS): @charset "utf-8"; /* CSS Document */ body,td,th { font-family: Arial, Helvetica, sans-serif; font-size: 14px; color: #000; } body { background-color: #CCCCFF; } .main_table th { background:#003399; font-size:24px; color:#FFFFFF; } .main_table { background:#FFF; border:#003399 solid 1px; } .subtitle { font-size:20px; } input#login_username, input#login_password { height:30px; width:300px; font-size:24px; } input#login_submit { height:30px; width:150px; font-size:16px; } .timetable_cell_lesson { width:100px; font-size:10px; } .timetable_cell_tutorial_a, .timetable_cell_tutorial_b, .timetable_cell_break, .timetable_cell_lunch { width:100px; background:#999; font-size:10px; } body { background-color: #CCCCFF; } body { background-color: #FF5719; } @charset "utf-8"; /* CSS Document */ body,td,th { font-family: Arial, Helvetica, sans-serif; font-size: 14px; color: #000; } body { background-color: #CCCCFF; } .main_table th { background:#003399; font-size:24px; color:#FFFFFF; } .main_table { background:#FFF; border:#003399 solid 1px; } .subtitle { font-size:20px; } input#login_username, input#login_password { height:30px; width:300px; font-size:24px; } input#login_submit { height:30px; width:150px; font-size:16px; } .timetable_cell_lesson { width:100px; font-size:10px; } .timetable_cell_tutorial_a, .timetable_cell_tutorial_b, .timetable_cell_break, .timetable_cell_lunch { width:100px; background:#999; font-size:10px; }

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