Search Results

Search found 34274 results on 1371 pages for 'mysql table'.

Page 227/1371 | < Previous Page | 223 224 225 226 227 228 229 230 231 232 233 234  | Next Page >

• Lining up content in divs without table cells

  - by Mike

  Hi, I have two rows of links like: Link 1 Link 2 Link 3 Link 4 Link 5 Link 6 Link 7 LInk 8 I need the top four links to align with the top bottom links regardless of how many characters are in the link. For example, This is link 1 This is link 2 Link 3 L4 LInk 1 Link 2 that is longer Link 3 L4 I can do this with tables and td cells but how can this be accomplished just using divs? Thanks.

  Read the article

• Removing groups of similar records in MySQL query

  - by user1182155

  I'm trying to wrap my head around this... (it may be simple, been a long day!) I have a database with sometimes multiple similar records... ie. Apples 2008-09-03 Apples 2012-01-01 Apples 2013-10-24 Oranges 2012-01-04 What I need to do is do a query that will show only records that haven't been updated today... So in this case, since Apples has an entry that was updated today, none of the records for the Apples should appear in the results. Oranges should be the only record it returns. I have a query similar to this... SELECT fruit FROM fruitnames where date < CURDATE() Which works to remove the record that was updated today... But it keeps the other records for Apples (obviously)... How would I remove those results as well?

  Read the article

• MySQL - generate numbers for a group of results

  - by FreeIX

  I need a query to return this result: +---------+-----+-------+ | ref_nid | nid | delta | +---------+-----+-------+ | AA | 97 | 1 | | BB | 97 | 2 | | CC | 97 | 3 | | DD | 98 | 1 | | EE | 98 | 2 | | FF | 98 | 3 | +---------+-----+-------+ However, I do not have the delta column. I need to generate it for each nid group. In other words, I need an auto incremented number for each group of the result.

  Read the article

• Union - Same table, excluding previous results MySQL

  - by user82302124

  I'm trying to write a query that will: Run a query, give me (x) number of rows (limit 4) If that query didn't give me the 4 I need, run a second query limit 4-(x) and exclude the ids from the first query A third query that acts like the second I have this: (SELECT *, 1 as SORY_QUERY1 FROM xbamZ where state = 'Minnesota' and industry = 'Miscellaneous' and id != '229' limit 4) UNION (SELECT *, 2 FROM xbamZ where state = 'Minnesota' limit 2) UNION (SELECT *, 3 FROM xbamZ where industry = 'Miscellaneous' limit 1) How (or is?) do I do that? Am I close? This query gives me duplicates

  Read the article

• generating images by user id php + mysql

  - by jay

  function user_image($id, $increment_views = false) { $id = mysql_real_escape_string($id); $q = mysql_query("SELECT * FROM `images` WHERE `id` = '$id'"); if (mysql_num_rows($q)) { $return = mysql_fetch_assoc($q); $q = mysql_query("SELECT * FROM `sources` WHERE `source_id` = $return[id] AND `source_flagged` = 0"); while ($r = mysql_fetch_assoc($q)) { $return['sources'][] = $r; } if ($increment_views) { $q = mysql_query("UPDATE `images` SET `views` = `views` + 1 WHERE `id` = $return[id]"); } return $return; } else { return false; } }

  Read the article

• How to prevent negative number in Mysql

  - by Jerry

  Hello guys.. I have data which is starting from 0 in my database. My php will add 1 or -1 to the data depending on the user's input. My problem is that if data is 0 and a user try to subtract 1. The data become 4294967295 which is the maximum value of INT data type. Are there anyways to make the data stays in 0 even when the user asks for -1? Thanks for the reply.. my sql command is like below update board set score=score-1 where team='TeamA' //this would generate 4294967295 if the score is 0.....

  Read the article

• Seeking assistance with Escaping Data for MySQL queries

  - by JM4

  Please don't send me a link to php.net referencing mysql_real_escape_string as the only response. I have read through the page and while I understand the general concepts, I am having some trouble based on how my INSERT statement is currently built. Today, I am using the following: $sql = "INSERT INTO tablename VALUES ('', '$_SESSION['Member1FirstName'], '$_SESSION['Member1LastName'], '$_SESSION['Member1ID'], '$_SESSION['Member2FirstName'], '$_SESSION['Member2LastName'], '$_SESSION['Member2ID'] .... and the list goes on for 20+ members with some other values entered. It seems most people in the examples already have all their data stored in an array. On my site, I accept form inputs, action="" is set to self, php validation takes place and if validation passes, data is stored into SESSION variables on page 2 then redirected to the next page in the process (page 3) (approximately 8-10 pages in the whole process). thanks!

  Read the article

• Multiple LIKE, OR MySql Queries Match

  - by Codex73

  Search for: 'chemist' Problem: query which will match a string like 'onechemist' but not 'chemist'. SELECT id,name FROM `records` WHERE name LIKE '%". mysql_real_escape_string($q) ."%' This alternate try won't work: SELECT id,name FROM `records` WHERE name LIKE '%". mysql_real_escape_string($q) ."%' OR name LIKE '". mysql_real_escape_string($q) ."%' OR name LIKE '%". mysql_real_escape_string($q) ."' How could I compile the above into one single query that will match any field which has the string or optimize the query into a better expression?

  Read the article

• MySQL/PHP Search Efficiency

  - by iMaster

  Hi! I'm trying to create a small search for my site. I've tried using full-text index search, but I could never get it to work. Here is what I've come up with: if(isset($_GET['search'])) { $search = str_replace('-', ' ', $_GET['search']); $result = array(); $titles = mysql_query("SELECT title FROM Entries WHERE title LIKE '%$search%'"); while($row = mysql_fetch_assoc($titles)) { $result[] = $row['title']; } $tags = mysql_query("SELECT title FROM Entries WHERE tags LIKE '%$search%'"); while($row = mysql_fetch_assoc($tags)) { $result[] = $row['title']; } $text = mysql_query("SELECT title FROM Entries WHERE entry LIKE '%$search%'"); while($row = mysql_fetch_assoc($text)) { $result[] = $row['title']; } $result = array_unique($result); } So basically, it searches through all the titles, body-text, and tags of all the entries in the DB. This works decently well, but I'm just wondering how efficient would it be? This would only be for a small blog, too. Either way I'm just wondering if this could be made any more efficient.

  Read the article

• Mysql date : 0000-00-00 00:00:00

  - by jasmine

  In my query: $cselect = mysql_real_escape_string($_POST['cselect']); --------------- --------------- $sql = sprintf("INSERT INTO content (id, catID, title, abstract, body, status, published, date, description_meta, keywords_meta) VALUES ('', '%s', '%s','%s','%s','%s','%s','%s','', '' )", $cselect,$chead, $cabst,$ctext, $cp, $cradio, 'TIMESTAMP: Auto NOW()'); ouptput for date is: 0000-00-00 00:00:00. What is wrong in my query? Thanks in advance

  Read the article

• Mysql help with view more button.

  - by WAC0020

  I am working on a widget that is a lot like twitters widget where there is a list of postings and a view more button. I can get it to work with using ID variables but I would like to sort by popular posts. Here is my mysq code: $sql = "SELECT id, title, category, icon_normal, status, description, views_monthly FROM posts WHERE views_monthly<=".$lastPost." AND status='1' ORDER BY views_monthly DESC LIMIT 9" So the problem that I am having is it shows the first 9 just fine. When it gets to the point where views_monthly = 0 then it just loads the same 9 post over again. How do it get it to switch to using ID when it reaches Views_monthly = 0 and load fresh posts?

  Read the article

• MySQL : Calculate business day difference between two dates column

  - by yokoyoko

  My sql query returns back two columns, first column is "date created" and second column is "date updated", first column has a prior timestamp with respect to second column. I need to add a third column which can display business day hrs (9:00am to 5:00pm) response i.e. if date created is 2012-01-01 09:00:20 and "dated updated" is 4:00pm same day then third column should display 7 hrs If date created is 2012-01-01 16:00:20 (4:00pm) and "date updated" is 10:00m on 2012:01:02 (2nd Jan) then third column should display 2 hrs. It should exclude Saturday and Sunday. Can you please suggest appropriate SQL query for this.

  Read the article

• MYSQL Query using subquery

  - by Michael Quiles

  Cant get this to work can any one help. List the part number, part description, and on_hand value of each part whose number of units on hand is more than the average number of units onhand for all parts use a subquery? SELECT PART_NUM, DESCRIPTION, SUM(ON_HAND * PRICE) ON_HAND_VALUE FROM PART; WHERE MAX(ON_HAND); (AVG(ON_HAND) > ON_HAND);

  Read the article

• PHP/MySQL - an array filter for bots

  - by Mike

  Hello, I'm making a hit counter. I have a database and I store the IP and $_SERVER['HTTP_USER_AGENT']; of the visitors. Now I need to add a filter, so I can put away the hits, that are made by bots. I found out, that many bots usually keep some common words in the $_SERVER['HTTP_USER_AGENT']; , so I's like to make and array of words, that would keep the bot from displaying in the results. Here is what I have now: while($row = mysql_fetch_array($yesterday, MYSQL_ASSOC)) { <-- Here I need a code, that would run through an array and check, if it containts the keywords and if it doesn't ... just count++; -- } Also if you know any other way of detecting and removing the bots from the results, I'd be verry thankful. Cheers

  Read the article

• Group mysql query by 15 min intervals

  - by gsiener

  I've got a monitoring system that is collecting data every n seconds (n ~=10 but varies). I'd like to aggregate the collected data by 15 minute intervals. Is there a way to corral the timestamp column into 15 minute chunks to allow for grouping to work?

  Read the article

• MySQL - accessing a table sum and compare to another table?

  - by assignment_operator

  This is for a homework assignment. I just plain don't understand how to do it. The instructions for this particular question is: List the branch name for all branches that have at least one book that has at least 4 copies on hand. Where the tables in question are: Branch: BranchName | BranchId Henry Downtown | 1 16 Riverview | 2 Henry On The Hill | 3 Inventory: BookId | BranchId | OnHand 1 | 1 | 2 2 | 3 | 4 3 | 1 | 8 4 | 3 | 1 5 | 1 | 2 6 | 2 | 3 From what I understand, I can get the number of OnHand per branch name with: SELECT BranchName, SUM(OnHand) FROM Branch B, Inventory I WHERE B.BranchId = I.BranchId GROUP BY BranchName; but I don't get how I'd do the comparison between the sum of OnHand per branch and 4. Any help would be appreciated, guys!

  Read the article

• mysql query results sorting

  - by user329094

  I am calling the results form a query to a list on my site based on if the item is "downtown_hosted". This works fine but I would now like to sort that list DESC, but can't seem to get the syntax correct. Below is what I have: $result_events = mysql_query("SELECT * FROM events WHERE downtown='downtown_hosted' ORDER BY date DESC LIMIT 5 ");

  Read the article

• MYSQL: COUNT with GROUP BY, LEFT JOIN and WHERE clause doesn't return zero values

  - by Paul Norman

  Hi guys, thanks in advance for any help on this topic! I'm sure this has a very simply answer, but I can't seem to find it (not sure what to search on!). A standard count / group by query may look like this: SELECT COUNT(`t2`.`name`) FROM `table_1` `t1` LEFT JOIN `table_2` `t2` ON `t1`.`key_id` = `t2`.`key_id` GROUP BY `t1`.`any_col` and this works as expected, returning 0 if no rows are found. So does: SELECT COUNT(`t2`.`name`) FROM `table_1` `t1` LEFT JOIN `table_2` `t2` ON `t1`.`key_id` = `t2`.`key_id` WHERE `t1`.`another_column` = 123 However: SELECT COUNT(`t2`.`name`) FROM `table_1` `t1` LEFT JOIN `table_2` `t2` ON `t1`.`key_id` = `t2`.`key_id` WHERE `t1`.`another_column` = 123 GROUP BY `t1`.`any_col` only works if there is at least one row in table_1 and fails miserably returning an empty result set if there are zero rows. I would really like this to return 0! Anyone enlighten me on this? Beer can be provided in exchange if you are in London ;-)

  Read the article

• mysql_num_rows(): supplied argument is not a valid MySQL result resource

  - by php-b-grader

  I am getting this error when I pass an invalid SQL string... I spent the last hour trying to find the problem assuming - It's not my SQL it must be the db handle... ANyway, I've now figured out that it was bad SQL... What I want to do is test the result of the mysql_query() for a valid resultset. I am simply using empty($result)... Is this the most effective test? Is there a more widely accepted method of testing a resultset for a valid result?

  Read the article

• MySql Not Like Regexp?

  - by KnockKnockWhosThere

  I'm trying to find rows where the first character is not a digit. I have this: SELECT DISTINCT(action) FROM actions WHERE qkey = 140 AND action NOT REGEXP '^[:digit:]$'; But, I'm not sure how to make sure it checks just the first character...

  Read the article

• convert mysql code to codeigniter

  - by Jethro Tamares Doble

  How can i convert this code into an acceptable codeigniter code: mysql_select_db($database_connection_ched, $connection_ched); $query_Institutions = "SELECT * FROM tb_institutional_profile ORDER BY tb_institutional_profile.institution_name ASC"; $Institutions = mysql_query($query_Institutions, $connection_ched) or die(mysql_error()); $row_Institutions = mysql_fetch_assoc($Institutions); $totalRows_Institutions = mysql_num_rows($Institutions); <td width="192"><select name="institution_id"> <?php do { <option value="<?php echo $row_Institutions['institution_id']?>" ><?php echo $row_Institutions['institution_name']?></option> <?php } while ($row_Institutions = mysql_fetch_assoc($Institutions)); ?> </select></td>

  Read the article

• How do I mirror a MySQL database?

  - by user366133

  I'm running two load balanced servers for one website, and I'd like the databases to be synchronized. Queries may be run on either of the two servers because they are both production sites, so the replication can't just work one way. It doesn't have to be in real-time, just fairly accurate so people don't notice a difference when they get switched to a different server.

  Read the article

• Sum of a summation in mysql

  - by dames

  I have the following query, in the top select statement (sum(l.app_ln_amnt)/count(l.app_ln_amnt)) works well but in the union I want to find the total of (sum(l.app_ln_amnt)/count(l.app_ln_amnt)) query from the top select statement However my solution seems to be off I need some help please select (sum(l.app_ln_amnt)/count(l.app_ln_amnt)), from receipt_history l UNION select SUM(sum(l.app_ln_amnt)/count(l.app_ln_amnt)), from receipt_history l

  Read the article

• restrict users from changing rows inserted 3 hours ago in mysql

  - by htaikthegreat

  Hi, I inserted a number of rows 3 hours ago and I don't want these rows from changing. How can I write sql statement that compare current time with the timstamp in the row and restrict users from changing it if abouve creteria is met. Thanks

  Read the article

• Mysql question about UPDATE

  - by Beck

  UPDATE counter_reports SET `counter`=`counter`+1,`date`=? WHERE report_id IN( (SELECT report_id FROM counter_reports WHERE report_name="emails_sent" AND `year`=1 ORDER BY report_id DESC LIMIT 1), (SELECT report_id FROM counter_reports WHERE report_name="emails_sent" AND `month`=1 ORDER BY report_id DESC LIMIT 1), (SELECT report_id FROM counter_reports WHERE report_name="emails_sent" AND `week`=1 ORDER BY report_id DESC LIMIT 1), (SELECT report_id FROM counter_reports WHERE report_name="emails_sent" AND `day`=1 ORDER BY report_id DESC LIMIT 1) ) Is there any alternative for such sql? I need to update(increment by 1) last counter reports for day,week,month and year. If I'm adding manually, sql works fine, but with subqueries it fails to launch. Thanks. :)

  Read the article

< Previous Page | 223 224 225 226 227 228 229 230 231 232 233 234  | Next Page >