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  • need help on php require

    - by user225269
    What do I need to put in a php code so that the user cannot access it even if he specified the correct url for the page they are trying to access. And redirect it to the logon page. I'm really having difficulty in this matter, everytime I click back button on the browser the user can still access the page

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  • PHP $array[0] in $string for JSON

    - by user1907696
    I am trying to use PHP to make a JSON file. Part of the code is as follow $array = array("hello", "world"); $string='{"person": [ { "name":'$array[0];', "age":'$array[1];' } ] }'; The file created. However, $array[0] and $array[1] doesn't return the values "hello" and "world" but as $array[0] and $array[1] Any idea? Thanks

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  • php fetch user data from mysql

    - by milodinosaur
    hi, currently i have 2 table in mysql structure: messages id | content | user_id | time submessages id | subcontent | msg_id | user_id | time submessages msg_id is FK for messages id. Now i need to query from php $cur_user = $user->current; // current user id. SELECT * FROM messages WHERE id > '{$_GET['id']}' // problem here how do i query submessages that posted by others not include current user? thank you.

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  • Obtaining standard port for arbitrary protocols in PHP

    - by Trott
    I'm looking for a function that will accept a string representing the scheme portion of a URL (e.g., "http", "https", "ftp", etc.) and return the standard port. It might be used like this: echo get_port_from_protocol("http"); // 80 As a last resort, I suppose I could write something to parse through /etc/services (assuming I only need to run under UNIX-like operating systems). But surely there must be something built-in to PHP, no?

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  • Problem with PHP & SQL Query

    - by Shahd
    Hi .... i have a problem in php code (inserting values in database) i use PHPMyAdmin my DATABASE has 3 tables: 1) Member with this fields: MemberID, MemberName 2) Room with this fields: RoomID, RoomName 3) Join with this fields: MemberID, RoomID the idea is to join the member in the room. My query was mysql_query("INSERT INTO join (RoomID, MemberID) VALUES ('121', '131')"); but unfortunately it is not work

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  • Lower CPU % used by FFMPEG Process via PHP (FLV Video Conversion)

    - by BoRo
    Hi, Okay, so I currently execute an ffmpeg command via PHP to run a video conversion. The Problem I'm Having is during the conversion, the ffmpeg process(es) use up so much CPU/Processing Power (near 100%), which slows down the response of my webserver. Is there a Way (crontab or script) I can limit the ffmpeg processes to a certain CPU percentage? Thanks,

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  • Deeper Integration with phpBB

    - by The Official Microsoft IIS Site
    More good news on the Interoperability front: the new phpBB release is now available for installation from the Windows Web Application Gallery and Web Platform Installer (Web PI) for Windows, IIS and SQL Server. Version 3.0.7-PL1 of phpBB takes advantage of a number of features for PHP applications on the Microsoft Web Platform with Windows, IIS and SQL Server, including SQL Server Driver for PHP 1.1 , which provides key interoperability for PHP applications to use SQL Server or SQL Azure for data...(read more)

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  • Can't add repository due to 'missing' fingerprint

    - by cubsink
    I am trying to install nginx with php but when I am following a guide, like this one: http://www.justincarmony.com/blog/2011/10/24/setting-up-nginx-php-fpm-on-ubuntu-10-04/ I am always told to add that repository (sudo add-apt-repository ppa:brianmercer/php) but I can't. I'll just get "Error: can't find signing_key_fingerprint at https://launchpad.net/api/1.0/~nginx/+archive/php5" and when I go to that website I find that there is a fingerprint specified but still I get that error message. Is there anyway to specify it myself? And for the last thing, how I can fix this so I can continue my installation towards a working nginx enviroment with php. Thanks for your advice and better wisdom.

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  • SQL SERVER – Puzzle to Win Print Book – Explain Value of PERCENTILE_CONT() Using Simple Example

    - by pinaldave
    From last several days I am working on various Denali Analytical functions and it is indeed really fun to refresh the concept which I studied in the school. Earlier I wrote article where I explained how we can use PERCENTILE_CONT() to find median over here SQL SERVER – Introduction to PERCENTILE_CONT() – Analytic Functions Introduced in SQL Server 2012. Today I am going to ask question based on the same blog post. Again just like last time the intention of this puzzle is as following: Learn new concept of SQL Server 2012 Learn new concept of SQL Server 2012 even if you are on earlier version of SQL Server. On another note, SQL Server 2012 RC0 has been announced and available to download SQL SERVER – 2012 RC0 Various Resources and Downloads. Now let’s have fun following query: USE AdventureWorks GO SELECT SalesOrderID, OrderQty, ProductID, PERCENTILE_CONT(0.5) WITHIN GROUP (ORDER BY ProductID) OVER (PARTITION BY SalesOrderID) AS MedianCont FROM Sales.SalesOrderDetail WHERE SalesOrderID IN (43670, 43669, 43667, 43663) ORDER BY SalesOrderID DESC GO The above query will give us the following result: The reason we get median is because we are passing value .05 to PERCENTILE_COUNT() function. Now run read the puzzle. Puzzle: Run following T-SQL code: USE AdventureWorks GO SELECT SalesOrderID, OrderQty, ProductID, PERCENTILE_CONT(0.9) WITHIN GROUP (ORDER BY ProductID) OVER (PARTITION BY SalesOrderID) AS MedianCont FROM Sales.SalesOrderDetail WHERE SalesOrderID IN (43670, 43669, 43667, 43663) ORDER BY SalesOrderID DESC GO Observe the result and you will notice that MidianCont has different value than before, the reason is PERCENTILE_CONT function has 0.9 value passed. For first four value the value is 775.1. Now run following T-SQL code: USE AdventureWorks GO SELECT SalesOrderID, OrderQty, ProductID, PERCENTILE_CONT(0.1) WITHIN GROUP (ORDER BY ProductID) OVER (PARTITION BY SalesOrderID) AS MedianCont FROM Sales.SalesOrderDetail WHERE SalesOrderID IN (43670, 43669, 43667, 43663) ORDER BY SalesOrderID DESC GO Observe the result and you will notice that MidianCont has different value than before, the reason is PERCENTILE_CONT function has 0.1 value passed. For first four value the value is 709.3. Now in my example I have explained how the median is found using this function. You have to explain using mathematics and explain (in easy words) why the value in last columns are 709.3 and 775.1 Hint: SQL SERVER – Introduction to PERCENTILE_CONT() – Analytic Functions Introduced in SQL Server 2012 Rules Leave a comment with your detailed answer by Nov 25's blog post. Open world-wide (where Amazon ships books) If you blog about puzzle’s solution and if you win, you win additional surprise gift as well. Prizes Print copy of my new book SQL Server Interview Questions Amazon|Flipkart If you already have this book, you can opt for any of my other books SQL Wait Stats [Amazon|Flipkart|Kindle] and SQL Programming [Amazon|Flipkart|Kindle]. Reference: Pinal Dave (http://blog.SQLAuthority.com) Filed under: Pinal Dave, PostADay, SQL, SQL Authority, SQL Function, SQL Puzzle, SQL Query, SQL Scripts, SQL Server, SQL Tips and Tricks, T SQL, Technology

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