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  • How to fit the paper-size to the content in LaTeX

    - by mef
    Hi, I'd like to create a pdf/ps/eps that contains only one single formula. I thought the easiest way would be to use latex. Unfortunately, I found no option to specify, that the paper-size should automatically be set to fit the contents. I found that dvipng has a "-T tight" option, that actually does the trick, but... I want it in vector-graphics format. Any suggestions? Thanks.

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  • Compute data between record of SQL database within Visual Studio

    - by Carl
    Hello, I am attempting to calculate the miles per gallon for logged fuel full-ups. My table consists of the flowing: FillUp(CarID, Date, ODReading, Gallons, StopGo, Highway, FillupID, MPG) I want to subtract the ODReading from the previous record and divide gallons by this computed value. How do I work between records to achieve this within Visual Studio 2008's column properties (formula) section? Thanks much, Carl

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  • Good Package for Fitting Polynomial Trend Lines

    - by Rev316
    Given a simple data set, I would like to be able to calculate a trending formula given it's a second order polynomial regression. In fact, it would be great if one could even forecast X periods during calculation (similar to what Excel does). I'm looking for a portable C/C++ package that's relatively easy to use, and allows it to spit out the "best-fit" (highest R^2 value) curve. Any suggestions? Thanks!

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  • Sharepoint calculated Date field shows incorrectly in non-US region

    - by Proforce
    If a SharePoint user (with Regional Settings set to UK) views a calculated date field in a View details form, the field shows incorrectly showing the date is in US format, thus 01-Apr-2010 for 03-Jan-2010, and doesnt show unresolvalble dates such as 31-Dec-2010. This applies even with a simnple =[Modified] formula The Server is set up in the US for that locale. Does anyone know of a workaround for this or if there is a patch available ? Thanks in advance..

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  • Scientific notation in Excel

    - by Vojtech R.
    Hi, I need make Number Format like scientific notation, but without E nor e. Just classic like this: (In latex its 2.3\times10^3) Maybe excel doesn't support this format. (I have on mind Number Format - for hundreds numbers - not in math formula)

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  • Have you been stuck with the math in a Flash project?

    - by VideoDnd
    Have you been stuck with the math in a Flash project? It's a loose design pattern my director formulated. My goal is to keep the project object oriented, and get 'non Flash obstacles' off my plate. XML values going to AS3, updating a changing acceleration formula. I don't hate math, but it just doesn't seem OOP or good project planning to have the math stuck in Flash. Your comments are welcome.

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  • How can i estimate memory usage of stl::map?

    - by Drakosha
    For example, I have a std::map with known sizeof(A) and sizefo(B), while map has N entries inside. How would you estimate its memory usage? I'd say it's something like (sizeof(A) + sizeof(B)) * N * factor But what is the factor? Different formula maybe? Update: Maybe it's easier to ask for upper bound?

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  • Simple caesar cipher in java

    - by Max Canlas
    Hey I'm making a simple caesar cipher in Java using the formula [x- (x+shift-1) mod 127 + 1] I want to have my encrypted text to have the ASCII characters except the control characters(i.e from 32-127). How can I avoid the control characters from 0-31 applying in the encrypted text. Thank you.

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  • MAC address need to add colons

    - by nan
    Kevin your response was helpful with the MAC address question. I wanted to ask you if you have like 2600 MAC address the formula you provided =LEFT(A2,2)&":"&MID(A2,3,2)&":"&MID(A2,5,2)&":"&MID(A2,7,2)&":"&MID(A2,9,2)&":"&RIGHT(A2,2) how do I replace A1 with blank so all of column A gets converted

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  • I've got my 2D/3D conversion working perfectly, how to do perspective

    - by user346992
    Although the context of this question is about making a 2d/3d game, the problem i have boils down to some math. Although its a 2.5D world, lets pretend its just 2d for this question. // xa: x-accent, the x coordinate of the projection // mapP: a coordinate on a map which need to be projected // _Dist_ values are constants for the projection, choosing them correctly will result in i.e. an isometric projection xa = mapP.x * xDistX + mapP.y * xDistY; ya = mapP.x * yDistX + mapP.y * yDistY; xDistX and yDistX determine the angle of the x-axis, and xDistY and yDistY determine the angle of the y-axis on the projection (and also the size of the grid, but lets assume this is 1-pixel for simplicity). x-axis-angle = atan(yDistX/xDistX) y-axis-angle = atan(yDistY/yDistY) a "normal" coordinate system like this --------------- x | | | | | y has values like this: xDistX = 1; yDistX = 0; xDistY = 0; YDistY = 1; So every step in x direction will result on the projection to 1 pixel to the right end 0 pixels down. Every step in the y direction of the projection will result in 0 steps to the right and 1 pixel down. When choosing the correct xDistX, yDistX, xDistY, yDistY, you can project any trimetric or dimetric system (which is why i chose this). So far so good, when this is drawn everything turns out okay. If "my system" and mindset are clear, lets move on to perspective. I wanted to add some perspective to this grid so i added some extra's like this: camera = new MapPoint(60, 60); dx = mapP.x - camera.x; // delta x dy = mapP.y - camera.y; // delta y dist = Math.sqrt(dx * dx + dy * dy); // dist is the distance to the camera, Pythagoras etc.. all objects must be in front of the camera fac = 1 - dist / 100; // this formula determines the amount of perspective xa = fac * (mapP.x * xDistX + mapP.y * xDistY) ; ya = fac * (mapP.x * yDistX + mapP.y * yDistY ); Now the real hard part... what if you got a (xa,ya) point on the projection and want to calculate the original point (x,y). For the first case (without perspective) i did find the inverse function, but how can this be done for the formula with the perspective. May math skills are not quite up to the challenge to solve this. ( I vaguely remember from a long time ago mathematica could create inverse function for some special cases... could it solve this problem? Could someone maybe try?)

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  • NHibernate Query

    - by Nathan Roe
    Is it possible to get NHibernate to generate a query similar to the following with HQL or Criteria API? select * from ( select row_number() over ( partition by Column1 order by Column2 ) as RowNumber, T.* from MyTable T ) where RowNumber = 1 I can get it to execute the inner select using the formula attribute, but I can't figure out a way to write a HQL or Criteria query that lets me wrap the inner select in the outer one.

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  • How to convert <font size="10"> to px?

    - by marknt15
    Hi, I need to convert <font size="10"> to px. Example only(not correct): <font size="10"> is equivalent to 12px. Is there any formula or table conversion out there to convert <font size="10"> to px? Thanks :) Kind Regards, Mark PHP Developer from Philippines

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  • Sharepoint 2007 calculated Date field shows incorrectly in non-US region

    - by Proforce
    If a SharePoint user (with Regional Settings set to UK) views a calculated date field in a View details form, the field shows incorrectly. I am using: ddwrt:FormatDateTime(string(@RenewalDate), 1033, 'dd MMMM yyyy') Which shows 04 January 2010 for 01/04/2010 and, doesnt show unresolvable dates such as 31-Dec-2010. This applies even with a simnple =[Modified] formula The Server is set up in the US for that locale.

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  • LINQ to XML, a problem conceptualizing how the tree should look.

    - by snark
    Have you ever had one of those days when you've dug a hole but your so deep in now that the only option is to keep on digging and see where you come out? I thought just for giggles in the latest component I'm writing to use LINQ to XML because it was about time I saw what all the hooplah was about. The problem: I am making a graph component that contains series of data that get graphed and then you can apply a formula to that series and graph another series then apply a formula to that series and so on. So I figured that I would do so in 2 steps, create (and manage) an XML representaion of the series and how they relate to each other, then pass this xml to a draw engine which draws. Conceptually its a tree, with the exception of the root all child series being based upon a parent (1 parent can have many children. So I should always be adding child nodes to their parent and if I delete a node(series) then I can simply delete the series and its descendants (then draw) and voila all the messy iterating through each node finding parents and children is unneccessary. Trouble is I dont know how to represent this tree in XML i.e. the structure. My first attempt saw me programatically adding each series as siblings, which worked like a treat because I ended up with an ordered list and thus my order of rendering was maintained. I had this <Chart> <Series id="1">seriesText1</Series> <Series id="2">seriesText2</Series> <Series id="3">seriesText3</Series> <Series id="4">seriesText4</Series> </Chart> I'm in a muddle now ... how can I represent a series and a series that has children series. If some-one can give me a hint to how my tree should look (perhaps with a snippet on how to programatically add nodes to their parents) All the examples I have read usually have some container elements such as <ContactS> or <BookS> but my head says I have <series> some of them parent some of them children. Would appreciate a nudge in the right direction.

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  • Information Gain and Entropy

    - by dhorn
    I recently read this question regarding information gain and entropy. I think I have a semi-decent grasp on the main idea, but I'm curious as what to do with situations such as follows: If we have a bag of 7 coins, 1 of which is heavier than the others, and 1 of which is lighter than the others, and we know the heavier coin + the lighter coin is the same as 2 normal coins, what is the information gain associated with picking two random coins and weighing them against each other? Our goal here is to identify the two odd coins. I've been thinking this problem over for a while, and can't frame it correctly in a decision tree, or any other way for that matter. Any help? EDIT: I understand the formula for entropy and the formula for information gain. What I don't understand is how to frame this problem in a decision tree format. EDIT 2: Here is where I'm at so far: Assuming we pick two coins and they both end up weighing the same, we can assume our new chances of picking H+L come out to 1/5 * 1/4 = 1/20 , easy enough. Assuming we pick two coins and the left side is heavier. There are three different cases where this can occur: HM: Which gives us 1/2 chance of picking H and a 1/4 chance of picking L: 1/8 HL: 1/2 chance of picking high, 1/1 chance of picking low: 1/1 ML: 1/2 chance of picking low, 1/4 chance of picking high: 1/8 However, the odds of us picking HM are 1/7 * 5/6 which is 5/42 The odds of us picking HL are 1/7 * 1/6 which is 1/42 And the odds of us picking ML are 1/7 * 5/6 which is 5/42 If we weight the overall probabilities with these odds, we are given: (1/8) * (5/42) + (1/1) * (1/42) + (1/8) * (5/42) = 3/56. The same holds true for option B. option A = 3/56 option B = 3/56 option C = 1/20 However, option C should be weighted heavier because there is a 5/7 * 4/6 chance to pick two mediums. So I'm assuming from here I weight THOSE odds. I am pretty sure I've messed up somewhere along the way, but I think I'm on the right path! EDIT 3: More stuff. Assuming the scale is unbalanced, the odds are (10/11) that only one of the coins is the H or L coin, and (1/11) that both coins are H/L Therefore we can conclude: (10 / 11) * (1/2 * 1/5) and (1 / 11) * (1/2) EDIT 4: Going to go ahead and say that it is a total 4/42 increase.

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